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In young's double silt experiment if the distance between the silts is 0.5 and the distance between the silts and screen is 2 times.Then what will be the width of bands
Answer: The width of bands will be 2λ
Explanation: Please see the attachments below
Which property of waves is possessed by both mechanical and electromagnetic wave A,Energy transport B,interference C,Reflection D,All
Answer:
D All
Explanation:
Mechanical and electromagnetic waves both carry energy. The mechanical wave via the motion/vibration of particles, and the electromagnetic via vibration of the electric and magnetic fields.
We know of interference patterns of light (electromagnetic interference), as well as interference of mechanical waves of water generating typical patterns.
Both, electromagnetic and mechanical waves go through the process of reflection when hitting a barrier (mirror for example in the case of light, and a solid wall for example in the case of water waves.
So the correct answer is "All of the above"
A 10 kg cart with a momentum of 10 kg• m/s hits a 20 kg cart at rest. Momentum is calculated by using
the formula p = mv, where m is the mass of an object and vis the velocity of an object.
Change in momentum formula
The change in momentum resulting from an external force is called the impulse (I=mv-mvo) and is related to the force applied through the Impulse-Momentum Theorem: I = F tc = mv - mvo . Here F is the external force applied and tc is the amount of time the force is in contact with the object.
The final velocity ( Vf ) of the cart at rest is : 0.5 m/s
Determine the final velocity of cart at restChange in momentum of the objects = m₁ * ΔV = m₂ * ΔV --- ( 1 )
Given that momentum ( p ) = m * v
where ; m₁ = 10 kg , p = 10 kg.m/s , v = ?
calculate for v
v = p/m = 10 kg.m/s / 10 kg
= 1 m/s
Back to equation ( 1 )
= 10 * ( 1 m/s ) = 20 * ( Vf - )
= 10 = -20 Vf
therefore Vf ( final velocity of cart at rest ) = 10 / 20
= 0.5 m/s
Hence we can conclude that The final velocity ( Vf ) of the cart at rest is : 0.5 m/s
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A girl walks 0.3 m/s. She moves 0.8 m/s 5 s later.
What is the girl’s acceleration?
0.8 m/s
0.5 m/s, 2
0.3 m/s
0.1 m/s2
Answer:
a = 0.1 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f}=v_{o}+a*t\)
Vf = final velocity = 0.8 [m/s]
Vo = initial velocity = 0.3 [m/s]
a = acceleration [m/s²]
t = time = 5 [s]
\(0.8=0.3+a*t\\0.5 = 5*a\\a = 0.1 [m/s^{2}]\)
an amusement park ride has two identical carriages that revolve around the center of the ride’s axle, as shown in the figure. both carts travel at a constant tangential speed at all points along the circular path. at what position is the total mechanical energy of the cart-cart-earth system at its maximum value?
The principle of conservation of energy allows to find the result for the mechanical energy of the system is:
Mechanical energy is conserved at all points, therefore at all points it has the same value.
Mechanical energy is defined by the sum of the kinetic energy and the potential energies.
Em = K + U
In the principle of energy conservation, it establishes that energy cannot be created or destroyed, it is only transformed, in the case of no friction, mechanized energy is conserved at all points.
They indicate that the system is rotating, which is why it is subjected to a force that expends its energy in changing the direction of the speed to keep the system in rotation, so the speed of the system remains constant.
Em = K = ½ I w²
Consequently, using the principle of conservation of energy we can find the result for the mechanical energy of the system is:
Mechanical energy is conserved at all points, therefore at all points it has the same value.
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Covalent bonding occurs when:
A. two atoms share electrons in their outer valence shells.
B. positive metallic ions are bonded with delocalized free electrons.
C. the negative side of one molecule bonds with the positive side of
a neighboring molecule.
O D. a negative ion is drawn to a positive ion through electrostatic
attraction.
Answer:
I guess A option is correct
AP PHYSICS 1 HELP PLEASE!! The pendulum illustrated above has a length of 2m and a bob of mass of 0.04 kg. It is held at an angle theta shown, where cos theta= 0.9. The frequency of oscillation is most nearly
A.) 4π hz
B.) 2π√.2 hz
C.) (0.25)/(π) hz
D.) (√.2)/2π hz
E.) (√5)/(2π) hz
The correct answer is E, but I have no clue why. Please help!
If the pendulum illustrated above has a length of 2m and a bob of mass of 0.04 kg. The frequency of oscillation is most nearly is: E.) (√5)/(2π) hz.
What is the frequency of oscillation ?The frequency of a simple pendulum is given by:
f = 1/(2π) √(g/L)
where g is the acceleration due to gravity, and L is the length of the pendulum.
In this case, L = 2m and the mass of the bob is 0.04kg. We are given cos(theta) = 0.9, so sin(theta) = √(1 - cos^2(theta)) = 0.4359.
The force of gravity on the bob is given by F = mg, where m is the mass of the bob and g is the acceleration due to gravity. The component of this force acting along the direction of motion is F sin(theta) = mg sin(theta) = 0.04 x 9.8 x 0.4359 = 0.170 N.
Using this force and the length of the pendulum, we can find the acceleration of the bob along the direction of motion:
a = F sin(theta)/m = 0.170/0.04 = 4.25 m/s^2
Substituting this acceleration and the length of the pendulum into the formula for frequency, we get:
f = 1/(2π) √(g/L) = 1/(2π) √(4.25/2) = (√5)/(2π) Hz
Therefore, the answer is E.
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Respostas
2 M
3 M
5 M
7 M
8 M
A force of F= 45 N is used to drag a crate 3 m across a floor.
ANSWER:
(a) 108 J
(b) 0 J
(c) 108 J
STEP-BY-STEP EXPLANATION:
(a)
Express the relation between horizontal component of work done and force on the crate:
\(W_h=F_h\cdot d\)Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}\)(b)
Express the relation between vertical component of work done and force on the crate:
\(W_v=F_v\cdot d\)Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.
Replacing:
\(\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}\)(c)
Express the relation for total work done by the 45 N force:
\(\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}\)what would happen to the temperature on mercury during the day if a sunspot was directly in line with it's surface?
Answer:
mind-bogglingly hot
Explanation:
If a sunspot were pointed right at Mercury in this way, the planet would become even more mind-bogglingly hot. Sunspots look dark in our visual spectrum, so we might suspect that they are colder (or at least less hot) than the rest of the Sun; but in fact, they are hotter.
When discussing newton™s laws of motion, which terms do people most likely use when talking about newton™s third law of motion? a. force and œacceleration b. inertia and œforce c. action and œreaction d. mass and œinertia
When discussing Newton's laws of motion, people most likely use the terms "action" and "reaction" when talking about Newton's third law of motion.
Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that whenever one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.
In other words, if object A pushes or pulls on object B with a certain force, then object B will push or pull back on object A with an equal and opposite force. This law applies to all types of forces, whether they are contact forces or non-contact forces, such as gravitational or electromagnetic forces.
This law is important in understanding how forces work in the physical world. It helps explain why things don't just keep accelerating indefinitely when a force is applied, and why forces always come in pairs. It also plays a crucial role in understanding the behavior of systems like rockets, airplanes, and cars.
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A few years ago I supervised a third year student who designed a water rocket. The first principle for the design was that it would be made out of recycled or readily available material. Consequently, the first choice was that the body of the rocket was to be a two litre plastic bottle. In the rest of this question you are free to make your own choices on the design but they must fit with the components being readily available or easily created within the engineering department. Note that this is a topic that is frequently discussed on the internet. You are free to use any resources you can find but you must acknowledge the use of pages through referencing. There is a link at the top of page 2 of this document that explains referencing, which you should already be aware of having written the paper for EG-194. a. The first stage of a design process is to develop a conceptual design. In this exercise a conceptual design is where you decide the main components of your design and what they look like. At this stage you should discuss the possibilities for the design of the water rocket. What are the options? What are the advantages and disadvantages of the options? Why did you choose the route you have chosen? In addition to answering the previous questions you should include an annotated diagram of your design. This is normally a sketch rather than a CAD drawing b. Complete a failure mode and effects analysis (FMEA) of the chosen design. Note the team exercise at the start of the module went through a form of FMEA that is suitable for this question. I expect you to cover five aspects of the design. You should focus on items that can be influenced by the design stage of the exercise, in this exercise we will not do the build and test phases. c. In order to optimise the height the rocket can attain it is necessary to develop a computational model. Using the knowledge that you have gained from year 1 of your degree and elsewhere to identify what will affect the height the rocket can reach. What physics will affect the flight of the rocket? What data will the physics require? How would you suggest the data is obtained?
When designing a water rocket made from recycled or readily available materials, the main component is typically a two-liter plastic bottle. The conceptual design options for the water rocket include variations in fins, nose cones, and deployment mechanisms.
The options for the design of a water rocket include variations in fins, nose cones, and deployment mechanisms. Fins are essential for providing stability during flight. Different fin shapes and sizes can affect the rocket's stability and control.
Larger fins generally provide better stability but may increase drag, while smaller fins can reduce stability but improve aerodynamic performance. The choice of fin design depends on the desired trade-off between stability and aerodynamics.
The nose cone design is another important consideration. A pointed nose cone reduces drag and improves aerodynamics, allowing the rocket to reach higher altitudes.
However, a pointed nose cone can be challenging to construct using readily available materials. An alternative option is a rounded nose cone, which is easier to construct but may result in slightly higher drag.
The deployment mechanism refers to the method of releasing a parachute or recovery system to slow down the rocket's descent and ensure a safe landing. The options include a simple nose cone ejection system or a more complex deployment mechanism triggered by pressure, altitude, or time. The choice of deployment mechanism depends on factors such as reliability, simplicity, and the availability of materials for construction.
In the chosen design route, the emphasis is on simplicity, stability, and ease of construction. The rocket design incorporates moderately sized fins for stability and control, a rounded nose cone for ease of construction, and a simple nose cone ejection system for parachute deployment.
This design strikes a balance between stability and aerodynamic performance while utilizing readily available or recycled materials.
To complete a failure mode and effects analysis (FMEA), five aspects of the design should be considered. These aspects can include potential failure points such as fin detachment, parachute failure to deploy, structural integrity of the bottle, leakage of water, and ejection mechanism malfunction.
By identifying these potential failure modes, appropriate design improvements and safety measures can be implemented to mitigate risks.
The height a water rocket can reach is influenced by various physics principles. Factors that affect the flight of the rocket include thrust generated by water expulsion, drag caused by air resistance, weight of the rocket, and the angle of launch.
To optimize the height, the physics data required would include the mass of the rocket, the volume and pressure of the water, the drag coefficient, and the launch angle.
Experimental data can be obtained through launch tests where the rocket's flight parameters are measured using appropriate instruments such as altimeters, accelerometers, and cameras.
By analyzing and correlating the data, the computational model can be refined to predict and optimize the rocket's maximum height.
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A vehicle travels for 20 minutes at a speed of 60 km/h. It then travels for 10 minutes at 90 km/h. At
the end of 30 minutes, it covers a distance of Select... v km.
Answer:
120km
Explanation:
it will covered 120km
Measure the speed of the fourth car of the train when it is at the highest point on the loop.
Show your process and results below.
We have that the speed of the the fourth car of the train when it is at the highest point is
v=12.12From the question we are told
Measure the speed of the fourth car of the train when it is at the highest point on the loop.Speed of the fourth carGenerally the equation for the Conversation of energy is mathematically given as
\(0.5mv^2+mgR=0.5mv^2\\\\Therefore\\\\v_1^2=v^2-2gR\\\\V_1^2=21^2-2*9.8*15\\\\\)
v=12.12
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A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 l to 15 l. the final pressure is ________ atm. group of answer choices
A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is 0.67 atm.
A physics principle states that a gas's volume changes inversely with applied pressure while the gas is kept at a constant temperature. Boyle's law states that in constant temperature the variation volume of gas is inversely proportional to the applied pressure. According to Boyle's law, a gas's pressure is inversely proportional to its volume while the gas is at constant temperature. To put it another way, we can argue that volume and pressure are inversely proportional to one another, but only for gases with constant mass and temperature.
The formula is,
P₁ X V₁ = P₂ X V₂
Where,
P₁ is initial pressure = 1 atm
P₂ is final pressure = ? (Not Known)
V₁ is initial volume = 10 L
V₂ is final volume = 15 L
Now put the values in the formula,
1 x 10 = P₂ x 15
10 = 15 P₂
P₂ = 0.67
Therefore, the final pressure is 0.67 atm.
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lighting converts ... energy, into ... energy.
Explanation:
lighting converts heat energy.
hope you like this .
Help Plsss
Which of the following objects are subject to the law of universal gravitation? (circle all that apply)
a. Satellites
b. Water
c. Frogs
d. Stars
Neha and Reha are playing see-saw.Neha is sitting 60cm away from the fulcrum and Reha is sitting 40cm away from the fulcrum.Calculate the effort that Reha should apply to lift Neha.The weight of Neha is 360N.
Answer:
Effort = 540 Newton
Explanation:
Given the following data;
Load arm = 60 cm
Effort arm = 40 cm
Load = 360 N
Conversion:
100 cm = 1 meters
40 cm = 40/100 = 0.4 meters
60 cm = 60/100 = 0.6 meters
To calculate the effort that Reha should apply to lift Neha, we would use the expression;
Effort * effort arm = load * load arm
Substituting into the expression, we have;
Effort * 0.4 = 360 * 0.6
Effort * 0.4 = 216
Effort = 216/0.4
Effort = 540 Newton
the two light bulbs are now connected in parallel across the 120- v line. find the current through each bulb.
The current through each bulb is 0.15A.
D)
V = Voltage across each bulb = 120 Volts
i400 = current in 400 ohm resistor = V/R = 120/400 = 0.3 A
i800 = current in 800 ohm resistor = V/R = 120/800 = 0.15 A
E)
P400 = V2/R400 = 1202/400 = 36 Watt
P800 = V2/R800 = 1202/800 = 18 Watt
F)
Ptotal = 36 + 18 = 54 Watt
Current refers to the flow of electric charge through a conducting medium. It is defined as the amount of charge that passes through a given cross-sectional area per unit of time. The SI unit of current is the ampere (A), which is defined as the flow of one coulomb of electric charge per second.
In an electric circuit, the current flows from a higher potential to a lower potential, and the direction of the current is taken as the direction in which positive charges would flow. In DC, the current flows in one direction only, while in AC, the current changes direction periodically. The magnitude of the current depends on the potential difference across the circuit and the resistance of the circuit.
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Complete Question:
Two light bulbs have resistances of 400 Ω and 800 Ω.
D). the two light bulbs are now connected in parallel across the 120- v line. find the current through each bulb.
E). Find the power dissipated in each bulb.
F). Find the total power dissipated in both bulbs.
Considering the physics of sunlight being received by the Earth's surface at a location that has a fairly typical 24-hour day cycle, as a given day progresses from morning to noon, what statement best describes the key phenomena that occur?
Select one:
a. As the sun climbs to its noontime position, the solar zenith angle decreases and in response the solar flux decreases.
b. As the sun climbs to its noontime position, the solar zenith angle decreases and in response the solar flux increases.
c. As the sun climbs to its noontime position, the solar zenith angle increases and in response the solar flux decreases.
d. As the sun climbs to its noontime position, the solar zenith angle increases and in response the solar flux only changes slightly.
e. As the sun climbs to its noontime position, the solar zenith angle increases and in response the solar flux increases.
As the sun climbs to its noontime position, the solar zenith angle decreases and in response the solar flux increases.
Option a is correct.
This phenomenon occurs due to the fact that the angle of incidence between the sun's rays and the Earth's surface becomes more perpendicular as the sun climbs higher in the sky towards its noontime position. This increases the amount of solar radiation that is absorbed by the Earth's surface, resulting in an increase in solar flux. However, it is important to note that this increase in solar flux is not constant throughout the day and can be affected by factors such as cloud cover and atmospheric conditions.
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A pendulum is measured to have a max velocity of 2.1 m/s. Determine the height that the pendulum is released
from.
Answer:
the height that the pendulum is released is 0.2305 m
Explanation:
The total mechanical energy of the pendulum is the sum of its potential energy and kinetic energy.
At the maximum velocity (2.1 m/s), the pendulum's kinetic energy is at its maximum, while the potential energy is at its minimum. This occurs when all the potential energy is converted to kinetic energy.
The equation for the conservation of mechanical energy is: E = KE + PE
Where E is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.
At the highest point (when the pendulum is released), all the energy is in the form of potential energy, and the kinetic energy is zero. Therefore, we have:
E = KE + PE
0.5 * m * v² + m * g * h = 0
Where m is the mass of the pendulum, v is the maximum velocity (2.1 m/s), g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height.
h = -(0.5 * (2.1 m/s)²) / (9.8 m/s²)
h ≈ -0.2305 m
Since height cannot be negative, we disregard the negative sign and take the absolute value:
h ≈ 0.2305 m
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What happens to the gravitational force between two objects when the distance between them is reduced by 50%?
A the gravitational force decreases by 50%
B the gravitational force increases by 50%
Cthe gravitational force decreases by 25%
the gravitational force increases by 400%
Question 8
Answer:
B
Explanation:
What words experiences in Niels Bohrs life That led to his interest in science and the study of the atom
The words experiences in Niels Bohr's life that led to his interest in science and the study of the atom is he disliked writing essays and talented in mathematics.
What is atom?Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.
Neil Bohr loved talking, he had a disliking of writing essays. He was talented in mathematics. He then attracted to the sciences. Physics interested Neil and when he was a teenager, he started correcting the mistakes in his school's textbooks.
The contributions are present in the modern atomic model. They are: All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.
Thus, Physics interested him to further study for atom.
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i need help with this one 2 if you guys don’t mind
A plastic ball is tied to 1 end of a long string and is swung in a horizontal circle. If it takes to complete 1 circle, what is the acceleration of the ball
Explanation:
Assuming the ball is swung with a constant velocity V and radius of circle R. Therefore, The tangential acceleration of the ball would be zero.
Considering the centripetal acceleration to be a_c . we get,
\(a_c= \frac{V^2}{R}\)
Identify 3 parts of your body what are formed from specialized cells or tissues. What makes those cells unique?
Answer:
Cells make up tissues, tissues make up organs, and organs make up organ systems. ... organisms have specialized systems that maintain the internal environment, ... the different organ systems as though they were distinct, parts of one system
Explanation:
Point P is located 1.7 m from fixed point charge q. The electric field Ē at point P is 8.6 x
10-2 N/C, directed away from the point charge. What is the magnitude of q? Let the
electrostatic constant k = 8.99 x 10°N • m²/C2.
O
A. 2.8 10-11 C
0
B. 4.8 * 10-11 C
O.C. -4.8 x 10-11 C
D. 1.5 x 10-10
Answer:
2.8 × 10^-11 C
Explanation:
The computation of the magnitude of q is shown below;
The electric field at point P because of point charge Q is provided by,
E = 8.6 × 10^-2 N/C
And, the separation between charge Q and P is r = 1.7m
Now According to the Coulomb's law,
E = kQ ÷ r²
8.6 × 10^-2 = 9 × 10^9 × Q ÷ (1.7)²
8.6 × 10^-2 × 2.89 ÷ 9 × 10^9 = Q
Q = (8.6 × 2.89 ÷ 9) × 10^-11
Q = 2.76 × 10^-11 C
= 2.8 × 10^-11 C
g a bird has a mass of 26 g and perches in the middle of a stretched telephone line. determine the tension when
The bird with a mass of 26 g perches in the middle of a stretched telephone line. The tension in the wire is 0.12753 N.
To determine the tension when the bird is perching:
Tension is the force that stretches a string or a telephone line. The bird's weight will cause the wire to stretch by a certain amount. The weight of the bird can be calculated as follows:
Weight = mass × gravity
The weight of the bird is:
Weight = 26 g × 9.81 m/s2 = 255.06 g · m/s2 = 0.25506 N
This force will be evenly distributed across the wire, causing it to stretch evenly in all directions.
As a result, the tension in the telephone wire will be the weight of the bird divided by two. This is due to the fact that the weight of the bird is evenly distributed over the length of the wire. The tension formula is given as:
Tension = weight of the bird/2
Tension = 0.25506 N / 2 = 0.12753 N
Therefore, when the bird is perching in the middle of a stretched telephone line, the tension in the wire is 0.12753 N.
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the velocity components of u and v of a two-dimensional flow are given by = 2 2 bxu ax x y and = 2 2 byv ay x y , where a and b are constants. calculate the acceleration
The acceleration components in the two-dimensional flow are given by ax = 2a + 4b(dy/dt)x + 2b(dy/dt)y and ay = 2a + 4b(dx/dt)y + 2b(dx/dt)x.
To calculate the acceleration of the two-dimensional flow, we need to compute the time derivatives of the velocity components.
The velocity components are:
u = 2ax + 2bxy
v = 2ay + 2byx
Taking the time derivatives of these equations:
du/dt = 2a(dx/dt) + 2b(dy/dt)x + 2b(x(dy/dt) + y(dx/dt))
dv/dt = 2a(dy/dt) + 2b(dx/dt)y + 2b(y(dx/dt) + x(dy/dt))
Simplifying these expressions:
du/dt = 2a(dx/dt) + 4b(dy/dt)x + 2b(dy/dt)y
dv/dt = 2a(dy/dt) + 4b(dx/dt)y + 2b(dx/dt)x
Therefore, the acceleration components are:
ax = 2a + 4b(dy/dt)x + 2b(dy/dt)y
ay = 2a + 4b(dx/dt)y + 2b(dx/dt)x
The acceleration is given by the vector (ax, ay), where ax and ay depend on the constants a and b, as well as the time derivatives of x and y.
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Two force vectors, F1=(3.0N)x^−(4.0N)y^ and F2=(−6.0N)x^+(4.5N)y^, are applied to a particle.What third force F3 would make the net, or resultant, force on the particle zero?
To make the net force on the particle zero, the third force vector, F3, must be equal and opposite to the vector sum of F1 and F2.
To find the vector sum of F1 and F2, we add their respective x and y components:
Fx = F1x + F2x = (3.0N) - (6.0N) = -3.0N
Fy = F1y + F2y = (-4.0N) + (4.5N) = 0.5N
Therefore, the vector sum of F1 and F2 is F1+F2 = (-3.0N)x^ + (0.5N)y^.
To make the net force zero, the third force vector, F3, must be equal and opposite to F1+F2:
F3 = -(F1+F2)
F3 = -(-3.0N)x^ - (0.5N)y^
F3 = (3.0N)x^ + (0.5N)y^
Therefore, a third force of (3.0N)x^ + (0.5N)y^ would make the net force on the particle zero.
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