how much (grams) hydrogen is required to react completely with 33.00 grams of nitrogen according to the following chemical reaction? do not type units into your answer. n2(g) 3 h2(g) 2 nh3(g)

The pH of an aqueous solution with a [H3O+] concentration of 2.5 x 10^-4 M can be calculated using the formula pH = -log[H3O+]. In this case, the pH of the solution is 3.60.

The pH of a solution is a measure of its acidity or basicity and is determined by the concentration of hydrogen ions ([H+]) or hydronium ions ([H3O+]) present in the solution. The relationship between pH and [H3O+] is given by the equation pH = -log[H3O+].

In this case, the concentration of [H3O+] is given as 2.5 x 10^-4 M. Plugging this value into the pH equation, we have pH = -log(2.5 x 10^-4) = 3.60.

Therefore, the pH of the given aqueous solution is 3.60.

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The pH of the given aqueous solution  is approximately 3.60.

What is PH?

The pH stands for potential of hydrogen and  is a measure of the acidity or alkalinity of a solution. It is a logarithmic scale used to express the concentration of hydrogen ions ([H+]) in a solution. The lower the pH value, the more acidic the solution, and the higher the pH value, the more alkaline or basic the solution.

The pH of a solution is defined  of hydronium ions ([\(H_3O+\)]) concentration in the solution.

Given [\(H_3O+\)] = 2.5 x \(10^{-4}\) M, we can determine the pH using the formula:

pH = -log10([\(H_3O+\)])

pH = -log10(2.5 x \(10^{-4}\))

Therefore:

pH = -log10(2.5) - (-4)

= -log10(2.5) + 4

pH ≈ 3.60

Therefore, the pH of the given aqueous solution for which [\(H_3O+\)] = 2.5 x \(10^{-4}\) M is approximately 3.60.

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Answer:

a chemical equation is balanced when the number of each type of atom is the same on both sides of the equation.

Explanation:

A chemical equation is considered to be properly balanced when the number of each type of atom is the same on both sides of the chemical equation.

What is a chemical equation?

A chemical equation is typically used in chemistry to represent the chemical reaction between two (2) or more chemical elements.

What is a balanced equation?

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, the following must be in place for a balanced chemical equation:

Ideally, the first step in balancing a chemical equation is to count the number of atoms in the reactant and product side of the chemical equation.

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From the balanced equation below the mole ratio of PCl3 to PCl5 is 1:1

\(PCl_{5} + PCl_{5}\) -------------------> \(PCl_{5}\)

Number of moles of \(PCl_{3}\) can be expressed as  1 mole

Number of moles of  \(Cl_{2}\) can be expressed as 1 mole

Number of moles of  \(PCl_{5}\) can be expressed as 1 mole

Mole ratio of \(PCl_{5}\) can be expressed as 1:1

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

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There could be several reasons why a student produced less magnesium oxide than expected. Here are two possibilities: Incomplete reaction,  Loss of product

Incomplete reaction: Magnesium oxide is produced when magnesium metal is heated in the presence of oxygen. However, if the reaction is incomplete, then less magnesium oxide will be produced. One reason for incomplete reaction could be that the temperature was not high enough to provide the necessary activation energy.

Loss of product: It is possible that some of the magnesium oxide that was produced was lost during the experiment. For example, if the magnesium oxide was not handled carefully after it was produced, it may have been spilled or blown away.

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0.10 M will be the concentration of A after 80 min.

We need to use the equation for first order reactions, which is: ln[A]t = -kt + ln[A]0, where [A]t is the concentration of A at time t, k is the rate constant, and [A]0 is the initial concentration of A.
We are given that the half-life of the reaction is 20 minutes, which means that k = ln2/20 = 0.03465 min^-1.
We can now use this value of k to find the concentration of A after 80 minutes:
ln[A]80 = -0.03465 x 80 + ln(1.6)
ln[A]80 = -2.772 + 0.470
ln[A]80 = -2.302
To get the concentration of A, we need to take the antilog of this value:
[A]80 = e^-2.302
[A]80 = 0.099 M
Therefore, the answer is (C) 0.10 M.
Substance A undergoes a first-order reaction A → B with a half-life of 20 minutes at 25 °C. The initial concentration of A is 1.6 M. To determine the concentration of A after 80 minutes, we can use the half-life concept. Since 80 minutes is equivalent to 4 half-lives (80 minutes / 20 minutes per half-life), we can calculate the concentration as follows:
1st half-life (20 min): 1.6 M / 2 = 0.8 M
2nd half-life (40 min): 0.8 M / 2 = 0.4 M
3rd half-life (60 min): 0.4 M / 2 = 0.2 M
4th half-life (80 min): 0.2 M / 2 = 0.1 M
Therefore, the concentration of A after 80 minutes will be 0.1 M (Option C).

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A body-centered cubic (BCC) unit cell contains two identical atoms. The unit cell consists of one atom located at each of the eight corners and one atom at the center of the cube.

In a body-centered cubic (BCC) unit cell, the atoms are arranged in a specific pattern. The unit cell consists of eight corner atoms and one atom located at the center of the cube. Each corner atom is shared between eight neighboring unit cells, contributing 1/8th of its presence to the unit cell. The central atom is contained entirely within the unit cell. Therefore, the total number of atoms in a BCC unit cell is 1 + 1/8 = 2 atoms.

Hence, a body-centered cubic unit cell contains two identical atoms.

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In total, a body-centred cubic (bcc) unit cell contains 1 + 1 = 2 identical atoms.

In a body-centred cubic (bcc) unit cell, there are two types of atoms: one atom located at each of the eight corners and one atom positioned at the centre of the unit cell. To determine the total number of atoms in a bcc unit cell, we need to count the atoms at each of these positions.

The eight corner atoms are shared among eight adjacent unit cells, meaning that each corner atom contributes only 1/8th of its presence to the unit cell it belongs to. Therefore, the eight corner atoms collectively contribute 8 × (1/8) = 1 atom to the unit cell.

Additionally, there is one atom located at the centre of the unit cell, which is not shared with any other unit cells.

Therefore, in total, a body-centred cubic (bcc) unit cell contains 1 + 1 = 2 identical atoms.

Please note that this answer assumes that all atoms in the bcc unit cell are identical.

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NaOH.

Na = Sodium which is in group 1 of periodic table which are alkaline metals. all the others are alkaline earths as they are all in group 2.

The mass of oxygen is 76.32 g

Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It refers to the mole ratios of the reactants and products involved in a reaction.

We know that;

Number of moles of  maleic acid anhydride = 52.1 grams /98 g/mol

= 0.53 moles

If 9 moles of oxygen produces 2 moles of  maleic acid anhydride

x moles of oxygen will produce 0.53 moles  of  maleic acid anhydride

x = 2.385 moles

Mass of oxygen =  2.385 moles * 32 g/mol

= 76.32 g

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Answer:

Temperature affects the kinetic energy in a gas the most, followed by a comparable liquid, and then a comparable solid. The higher the temperature, the higher the average kinetic energy, but the magnitude of this difference depends on the amount of motion intrinsically present within these phases

Explanation:

I just know lol

Answer:

The correct answer is Water boiling. Examples of physical change are freezing of water, boiling of water, melting of wax, etc. Examples of chemical change are digestion of food, burning of paper, rusting of metal, silver tarnishing, etc.

The density of the substance is 0.77 g/cm³.

The density of a substance is calculated by dividing its mass by its volume. In this case, the mass of the substance is 85g and the volume is 110cm³.

Density = Mass / Volume

Density = 85g / 110cm³

To obtain the answer, we divide 85g by 110cm³.

Calculating the division, we find that the density of the substance is approximately 0.77 g/cm³.

Therefore, the density of the substance is 0.77 g/cm³.

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Answer:

R = 8.314 pKa*L/mol*K

The value for the ideal gas constant (R) is approximately 8.314 kPa·L/(mol·K).

To determine the value for the ideal gas constant (R) when pressure (P) is in kilopascals (kPa), temperature (T) is in kelvins (K), volume (V) is in liters (L), and amount of gas (n) is in moles, we need to use the appropriate units for R based on these measurements.

The ideal gas constant, R, can be expressed in various units. The most common units for R are:

R = 0.0821 L·atm/(mol·K) (atmospheres, liters, moles, and kelvins)

However, since you provided the measurements in kilopascals, liters, moles, and kelvins, we need to use a different value for R that is consistent with these units:

R = 8.314 kPa·L/(mol·K)

Therefore, when pressure is in kilopascals, volume is in liters, amount of gas is in moles, and temperature is in kelvins, the value for the ideal gas constant (R) is approximately 8.314 kPa·L/(mol·K).

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Answer: Assuming the reaction between Cu2+ and NH3 goes to completion, we can use stoichiometry to determine the amount of complex formed and the amount of excess reagent remaining.

The balanced equation for the complexation reaction is:

Cu2+ + 4 NH3 → [Cu(NH3)4]2+

First, we need to calculate the moles of Cu2+ and NH3 used:

moles of Cu2+ = (0.010 M) x (5.00 mL/1000 mL) = 5.00 x 10^-5 mol

moles of NH3 = (3.0 M) x (1.00 mL/1000 mL) = 3.00 x 10^-3 mol

Next, we determine which reactant is limiting. Since there are fewer moles of Cu2+ than NH3, Cu2+ is the limiting reactant. The reaction will go to completion with all of the Cu2+ reacting to form [Cu(NH3)4]2+.

The amount of complex formed will be equal to the moles of Cu2+ used, which is 5.00 x 10^-5 mol. The amount of excess NH3 remaining will be equal to the initial moles of NH3 minus the moles of NH3 used, which is:

3.00 x 10^-3 mol - 4 x 5.00 x 10^-5 mol = 2.80 x 10^-3 mol

Now, let's consider the reverse reaction:

[Cu(NH3)4]2+ → Cu2+ + 4 NH3

The equilibrium constant for this reaction, K, is equal to the reciprocal of the equilibrium constant for the forward reaction, Kf:

K = 1/Kf = 1/(4.8 x 10^12) = 2.08 x 10^-13

Therefore, the equilibrium constant for the reverse reaction is 2.08 x 10^-13.

The compound in each pair is more soluble in water are strontium sulfate, copper (II) carbonate, calcium carbonate, barium chromate, silver chromate and barium iodate.

Strontium sulfate or BaSO4, these two are very insoluble in water because of the high lattice enthalpy of the compounds. Copper (II) carbonate or CuCO3, this salt is also insoluble in water and thus, cannot exist in water without breaking down into its ions. Calcium carbonate or CaCO3, this salt is soluble in water to some extent, but it does not dissolve completely in water.

Barium chromate or BaCrO4, this salt is very insoluble in water as the hydration energy is lower than the lattice enthalpy. Silver chromate or Ag2CrO4, silver chromate is more soluble than barium chromate because the Ag+ ion has a greater affinity for water than Ba2+ ion. Barium iodate or Ba(IO3)2, this compound is moderately soluble in water. The solubility increases with an increase in temperature. If we compare the compounds, then silver chromate is more soluble in water than barium chromate.

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Answer:

It's water.

Explanation:

Water is also called as universal solvent, because it's literally almost the only one we use.

Sorry if I spelled something wrong. I'm Dominican so yeah . I hope this helps you :)

Answer:Chemical energies,elastic energy,kinetic energy,Light energy :)

Explanation:

A BCC unit cell with a lattice constant, a, of 2.4 Å. The volume atomic concentration of the unit cell is 0.0722 atoms/ų.

To determine the volume atomic concentration of a Body-Centered Cubic (BCC) unit cell, we need to consider the number of atoms present in the unit cell and the volume occupied by the unit cell.

In a BCC unit cell, there is one atom located at the center of the cube and eight atoms at the corners, but each corner atom is shared among eight adjacent unit cells. Therefore, the total number of atoms present in the unit cell is 1.

The volume of a BCC unit cell can be calculated using the formula:

Volume = a³

where "a" is the lattice constant.

Given that the lattice constant, a, is 2.4 Å, we can calculate the volume of the unit cell as follows:

Volume = (2.4 Å)³

Converting the units to cubic angstroms:

Volume = 13.824 ų

Now, to determine the volume atomic concentration, we need to divide the number of atoms (1) by the volume of the unit cell:

Volume Atomic Concentration = Number of Atoms / Volume

Volume Atomic Concentration = 1 / 13.824 ų

The volume atomic concentration of the BCC unit cell is approximately 0.0722 atoms/ų.

Therefore, the volume atomic concentration of the unit cell in a BCC crystal with a lattice constant of 2.4 Šis approximately 0.0722 atoms/ų.

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The complete question is:

A BCC unit cell with a lattice constant, a, of 2.4 Å. Determine the volume atomic concentration of the unit cell.

When two substances are brought in contact with each other, heat energy is exchanged between them until they reach thermal equilibrium.

At thermal equilibrium, the temperature of the two substances becomes equal. This means that the statement that is true of the temperature of the two substances when they reach thermal equilibrium is that their temperatures are equal. The temperature of the warmer substance decreases while the temperature of the colder substance increases until they both reach the same temperature. This is because heat energy flows from the warmer substance to the colder substance until they reach a state of balance.
It's important to note that thermal equilibrium is an important concept in thermodynamics and is used in many practical applications. For example, in HVAC systems, it is important to ensure that the air inside the building is in thermal equilibrium to maintain a comfortable temperature for occupants. In cooking, thermal equilibrium is used to ensure that food is cooked evenly throughout. Therefore, understanding thermal equilibrium and the principles behind it is crucial in many fields.

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The vital clues that were provided by Franklin's work to Watson and Crick about the molecular structure of DNA:Rosalind Franklin's research played an important role in understanding the structure of DNA. X-ray crystallography was used by Franklin to study the arrangement of atoms in DNA molecules.

When Franklin's photos were studied by Watson and Crick, they discovered that the DNA molecule had a double helix shape. This discovery allowed them to make a model of the DNA structure that was later confirmed.2. It was not ethical for Wilkins to show Franklin's unpublished photo to Watson and Crick without Franklin's consent. Even though Wilkins was Franklin's co-worker, the photo was Franklin's intellectual property, and he had no right to share it with others. Watson and Crick should have acknowledged Franklin's contribution in their research.

Franklin's work was crucial to the discovery of the DNA structure, and she should have been given credit. Watson and Crick should have offered her co-authorship on the paper.3. Gender may have played a role in the fact that Rosalind Franklin did not receive credit for her X-ray diffraction work. Women in science were not treated equally to men in the 1950s. Franklin was not offered the same opportunities as Watson and Crick, despite her important contributions to their research. It is likely that her gender was a factor in her treatment. Today, the scientific community recognizes the importance of diversity in science, and steps are being taken to ensure that all scientists are treated equally.

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To make a buffer with pH 4.76 from 500 mL of 0.1 M solution of sodium acetate, you can add 25 mL of the 1 M solution of HCl to it.

According to the Henderson-Hasselbalch equation used for the calculation of buffer pH:

\(pH = pK_{a} + log\frac{[base]}{[acid]}\)
when the pH = pKa (as is here) then:

\(log\frac{[base]}{[acid]} = 0\)
so:
\(\frac{[base]}{[acid]}=1\)

This means that [base]=[acid]. The easiest way to generate acid here (because sodium acetate is the basic component), is to add strong acid to the solution, which will effectively transform sodium acetate into acetic acid.

The amount of acid needed is equal to half of the starting amount of sodium acetate:

c = n/V, so n = c * V = 0.1 M * 0.5 L = 0.05 mol of NaOAc

0.05 mol / 2 = 0.025 mol of HCl

In order to add the smallest volume of acid possible (so as to not reduce buffer capacity), we can use 1 M solution of HCl.

c = n/V, so V = n/c = 0.025 mol / 1 M = 0.025 L = 25 mL of 1 M HCl

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Taking into account the definition of ionization energy and electronegativity, you can say that the significance of the similarity of these trends  is that while electrons are more attracted to the nucleus (electronegativity), more energy is needed to extract an electron from a neutral atom (ionization energy).

Electrons are held in atoms by their attraction to the nucleus, which means that energy is needed to remove an electron from the atom.

Ionization energy, also called ionization potential, is the necessary energy that must be supplied to a neutral, gaseous, ground-state atom to remove an electron from an atom. When an electron is removed from a neutral atom, a cation with a charge equal to +1 is formed.

The further away the electron is from the nucleus, the easier it is to remove it, that is, the less energy is needed.

In a group the atoms have the same electronic structure in the outermost shell. But when going down in the same group, the electrons find themselves in shells that are farther and farther away from the nucleus, being less and less attracted. The size of the atom increases as the number of electronic shells increases, increasing the atomic radius when descending in a group. But the electrons are farther from the nucleus, and the easier it will be to expel them. That is, its extraction from the atom is facilitated. So the ionization energy decreases when descending in a group. In other words, ionization energy is a function of atomic radius; the larger the radius, the less energy is required to remove the electron from the outermost orbital.

By increasing the atomic number of the elements of the same period, the nuclear attraction on the outermost electron increases, since the atomic radius decreases and the effective nuclear charge on it increases.

For this reason, in a period, as the atomic number increases, the ionization energy becomes greater.

The electronegativity of an element is defined as the relative ability of an atom to attract electrons from another atom to chemically bond and form a compound.

In other words, electronegativity is a measure of the attractive force that one atom exerts on the electrons of another when a chemical bond forms.

In the groups, the electronegativity decreases from top to bottom because the valence shell moves away from the nucleus and with this the attraction that the nucleus exerts on the valence electrons decreases.

In the periods, the electronegativity increases from left to right, because the number of electrons in the valence shell increases, so the attraction of other electrons increases to complete the valence shell and reach a stable state.

The significance of the similarity of these trends  is that while electrons are more attracted to the nucleus (electronegativity), more energy is needed to extract an electron from a neutral atom (ionization energy).

Then, electronegativity is related to ionization energy in the following way: an atom with a high ionization potential has a high electronegativity. On the contrary, atoms with low ionization potential have small electronegativity.

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Answer:
Answer 1: The mass of magnesium contained in the compound is 0.57g, which can be determined by subtracting the mass of the crucible and lid (31.064g) from the mass of the crucible, lid, and magnesium ribbon (31.634g).

Answer 2: The mass of oxygen contained in the compound is 1.39g, which can be determined by subtracting the mass of the crucible, lid, and magnesium oxide (31.970g) from the mass of the crucible and lid (31.064g).

Answer 3: The change in mass between the two can be accounted for by the reaction of the magnesium with oxygen to form magnesium oxide.

Answer 4: The number of moles of magnesium is 0.0995 (2.39/24) and the number of moles of oxygen is 0.0868 (1.39/16). Dividing the moles of each element by the smallest amount of moles (0.0868) results in a simplest ratio of 1:1. Therefore, the empirical formula of magnesium oxide is MgO.

Answer 5: The known formula for magnesium oxide is MgO, which is the same as the empirical formula determined in question 4.

The correct answer is Uranium. The fissionable fuel used in most nuclear reactors in the United States is uranium. Specifically, the fuel used is usually enriched uranium, which means that the concentration of uranium-235 (the fissile isotope of uranium) has increased above its natural abundance in uranium ore.

When a uranium atom undergoes nuclear fission, it releases a large amount of energy in the form of heat, which can be used to generate electricity in a nuclear power plant. The fission process also releases neutrons, which can go on to cause additional fissions in nearby uranium atoms, creating a self-sustaining chain reaction.

While plutonium and thorium can also be used as nuclear fuels, they are not as commonly used as uranium in the United States. Tritium is not a fissionable fuel; it is a radioactive isotope of hydrogen that is sometimes used in nuclear weapons and as a tracer in scientific experiments.

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The following chemical equations have been balanced using the appropriate coefficients.

Mg(OH)2 + NaCl → MgCl2 + 2NaOH

H2SO4 + BaCl2 → BaSO4↓ + 2HCl

AgNO3 + Fe(NO3)2 → AgFeO2↓ + 2NO3

Balancing chemical equations in chemistry involves adjusting the coefficients of the reactants and products in a chemical reaction so that the number of atoms of each element is equal on both sides of the equation.

Note: Never change the subscripts in a chemical formula to balance an equation. Only coefficients can be changed.

Mg(OH)2 + NaCl → MgCl2 + 2NaOH

H2SO4 + BaCl2 → BaSO4↓ + 2HCl

AgNO3 + Fe(NO3)2 → AgFeO2↓ + 2NO3

MgCl2 + 2NaOH → Mg(OH)2↓ + 2NaCl

3NaOH + Fe2(SO4)3 → Fe(OH)3↓ + 3Na2SO4

Pb(NO3)2 + 2KCl → PbCl2↓ + 2KNO3

MgSO4 + BaCl2 → MgCl2 + BaSO4↓

Cu(NO3)2 + 2KOH → Cu(OH)2↓ + 2KNO3

Al(OH)3 + NaOH → NaAlO2 + 2H2O

BaCO3 + H2SO4 → BaSO4↓ + CO2↑ + H2O

ZnCl2 + 2AgNO3 → 2AgCl↓ + Zn(NO3)2

BaSO4 + 2KOH → Ba(OH)2↓ + K2SO4

Fe(NO3)3 + 3KOH → Fe(OH)3↓ + 3KNO3

NaHCO3 + KHCO3 → NaKHCO3 + H2O + CO2↑

Ba(OH)2 + Na2CO3 → BaCO3↓ + 2NaOH

Al + H2SO4 → Al2(SO4)3 + H2↑

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Answer:

Bases and Acids are chemically opposite from each other,and there are multiple ways to distinguish how they react when dissolved in water.

Explanation:

In the reaction SO2(g) + ½O2(g) → SO3(g), the hybridization of the sulfur atom changes from sp2 to sp3.

This is because the sulfur atom in SO2 has a trigonal planar geometry with three bonding pairs and one lone pair, which corresponds to sp2 hybridization. In SO3, the sulfur atom has a tetrahedral geometry with four bonding pairs, which corresponds to sp3 hybridization.

In the reaction SO2(g) + ½O2(g) → SO3(g), the hybridization change for the sulfur atom can be explained as follows:

1. Determine the hybridization of the sulfur atom in SO2: In SO2, the sulfur atom forms two sigma bonds with two oxygen atoms and has one lone pair. According to the valence bond theory, its hybridization is sp2.

2. Determine the hybridization of the sulfur atom in SO3: In SO3, the sulfur atom forms three sigma bonds with three oxygen atoms and has no lone pairs. According to the valence bond theory, its hybridization is sp2.

As we can see, the hybridization of the sulfur atom does not change in this reaction. It remains sp2 in both SO2 and SO3.

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Answer:

the 2nd choice, nervous and muscular

Mass of sucrose : = 41.076 g

Given

50 ml sample of a  2.4 M sucrose solution(C₁₂H₂₂O₁₁)

Required

Mass of sugar

Solution

Mol sucrose :

= M(molarity) x V(volume)

= 2.4 x 50

= 120 mlmol

= 0.12 mol

Mass of sugar :

= mol x MW

= 0.12 x 342,3 g/mol

= 41.076 g