how many water (h2o) molecules are in a block of ice that has a mass of 59.5 g? how many atoms of hydrogen are present in this block?

Answers

Answer 1

Block of ice of mass 59.5g contains 19.87 ×10²³molecules and 39.75×10²³ atoms.

Molecular mass of Water is 18g/mol

No. of moles = Given mass /Molecular mass

No. of moles of water = 59.5/18 (Given, mass of block of ice is 59.5g)

                                    = 3.3moles.

1mol of water contains 6.023×10²³ molecules of water.

Then,3.3 moles of water contains ,

3.3×  6.023×10²³= 19.87 ×10²³molecules.

1mol of water (H₂O) contains,2×  6.023×10²³ atoms of hydrogen

Then, 3.3 moles of water contains,

2×3.3×  6.023×10²³ = 39.75×10²³ atoms of hydrogen.

Thus, the molecules and atoms present in the block of ice of mass 59.5g is 19.87 ×10²³molecules and 39.75×10²³ atoms respectively.

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Related Questions

Light has both magnetic and electric fields. Scientists call this *

Answers

Answer:

I think is electromagnetic radiation (light)

Explanation:

If i get it wrong i am sorry

Convert each measurement from scientific notation

Convert each measurement from scientific notation

Answers

Answer:

no each of them i will do but a single for your understanding so you can do by your own

here first one 8.1755×10^4 so 81755 the answer

Caption for this picture asap.

Caption for this picture asap.

Answers

Answer:

1.conical flask

2.beaker

3 graduated cylinder

4.receiver

5.distillation flask

Explanation:

the name of material is this!

2H2S + 3O2 → 2SO2 + 2H2O


1. For every 10.0 g of H2S how many moles of SO2 are formed?

Answers

Answer:10

Explanation:

A man works in an aluminum smelter for 12years. the drinking water in the smelter contains0.075mg/l arsenic and 0.580mg/l methylene chloride. his only exposure to these chemicals in water is at work.
a. What is the hazard index (HI) associated with this exposure?
b. Does the HI indicate this is a safe level of exposure?
C. What is the incremental lifetime cancer risk for the man due solely to the water he drinks at work? Does it seem to be an acceptable risk according to EPA?

Answers

a. The hazard index is the sum of the individual hazard quotients for each chemical.

b. The HI indicates a potential health risk.

c. The incremental lifetime cancer risk is a measure of the additional risk of developing cancer over a lifetime due to exposure to a chemical.

a. Assuming the man weighs 70 kg and drinks 2 L of water per day, the HQs are 0.015 for arsenic and 0.405 for methylene chloride, giving an HI of 0.42.

b. The HI indicates a potential health risk, as an HI greater than 1 indicates a potential for adverse health effects.

c. The ILCR for methylene chloride is \(5.6 * 10^{-5}\), which is also above the acceptable risk level, indicating a potentially increased risk of cancer from methylene chloride exposure.

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The system below was at equilibrium in a
9.0 L container. What change will occur
for the system when the container is
shrunk to 3.0 L?
51.8 kJ + H₂(g) + 1₂(g) = 2HI(g)

The system below was at equilibrium in a9.0 L container. What change will occurfor the system when the

Answers

The change that wilL occur is that the the reaction shifts to the right (products) to produce fewer moles of gas.

option C is correct.

How do we determine?

The balanced equation is:

\(51.8 kJ + H_2(g) + 12(g) = 2HI(g)\)

From the left, there are 1 mole of H2 gas and 1 mole of I2 gas, which gives a total of 2 moles of gas.

In the right,  there are 2 moles of HI gas.

We can tell that there are more moles of gas on the left side than on the right side by comparing the amount of moles on each side.

According to Le Chatelier's principle, a decrease in volume will favor the side with fewer moles of gas.

In our scenario, the reaction will shift to the right  to produce fewer moles of gas.

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Answer:

there is no change

Explanation:

acellus correct

Which formulas represent one ionic compound and one covalent compound?
b. Cl₂ and H₂S
a. N₂ and SO₂
c. BaCl and N₂O₂
d. Na₂O and CaO

Answers

i,ii&iii only the alkanes forms 3-bromo-3-methylpentane as the major product when it's react with hbr.

What is alkanes forms?

Alkanes are the series of a  compounds that is contain carbon and hydrogen atoms of the  with single covalently bonds. Theses are knowns as saturated if  hydrocarbons. This group of the  compounds consists of a  carbon and hydrogen and  atoms with single covalent bonds. Also it is comprises a homologous series of  having a molecular formula of CnH2n+2.

Sol- Which of the following is the issue this? After adding HBR, Elkins produces three bromo three metal paintings as the main output. So allow me to simply write an equation, okay? I'm writing right here. What will this compound be when HBR is reacted? We'll be receiving a substance similar to this. Okay, my name is B. R. Once more, we are processing with H to the right.

That's it. Thus, organic compounds will now be observed. It's a beard. Right? Therefore, you can add B. R. as a further point here. We will arrive soon. Yes, once more, the beard is what makes this strange. So once more, we will be able to return home in this manner. The fact that we are getting the same compound means that the main component of this is three Bromo three metal. The fact that they all have the same product and option is therefore true. Right? No further inquiry is made regarding which of the following cardboard signs will experience Metal shift at 1 and 2. Right? Therefore, none of them have ever been the right response because none of them will experience a 12 m shift.

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nitrogen gas escapes through a pinhole in 83.8 seconds. under the same conditions, a gaseous compound with the empirical formula ch2 escapes in 68.4 seconds. what is its molecular formula?

Answers

The molecular formula of the compound is \(C_2H_3\).

To determine the molecular formula of the gaseous compound, we need to use the information given about its empirical formula and the time it takes to escape through a pinhole and apply the concept of the Ideal Gas Law.

The empirical formula of the compound tells us the simplest whole-number ratio of the atoms present in the molecule. In this case, the empirical formula is \(CH_2\), which means that the molecule contains one carbon atom and two hydrogen atoms.

The time it takes for gas to escape through a pinhole is related to its molar mass and the size of the hole. The lighter the gas, the faster it will escape. Therefore, we can compare the escape times of nitrogen gas and the compound to determine their relative molar masses.

Using the Ideal Gas Law, we can relate the molar mass of the compound to the time it takes to escape through the pinhole. Assuming the same conditions of temperature and pressure, the Ideal Gas Law states that PV=nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. Rearranging this equation gives us n=m/M, where m is the mass of the gas and M is the molar mass.

We can use this equation to find the molar mass of the compound:

n = m/M

n = m/ (Empirical formula mass of \(CH_2\))

n = m/ (12.01 + 2*1.01)

n = m/ 14.03

We know that the time it takes for nitrogen gas to escape through the pinhole is 83.8 seconds, and the time for the compound is 68.4 seconds. Therefore, the ratio of their molar masses is:

(Molar mass of nitrogen gas) / (Molar mass of the compound) = (Time for the compound to escape) / (Time for nitrogen gas to escape)

(Molar mass of nitrogen gas) / (Molar mass of the compound) = 83.8 / 68.4

(Molar mass of nitrogen gas) / (Molar mass of the compound) = 1.2246

We know the molar mass of nitrogen gas is 28.01 g/mol, so we can solve for the molar mass of the compound:

28.01 / (Molar mass of the compound) = 1.2246

The molar mass of the compound = 22.87 g/mol

Now we can use the molar mass of the compound to find its molecular formula. The empirical formula mass of \(CH_2\) is 14.03 g/mol, so the molecular formula mass must be a multiple of this value that is close to 22.87 g/mol. Dividing 22.87 by 14.03 gives a value of 1.63, which suggests that the molecular formula contains approximately 1.63 times as many atoms as the empirical formula.

To find the molecular formula, we can multiply the empirical formula by this factor:

(\(CH_2\)) x 1.63 = C1.63H3.26

Rounding to the nearest whole number, we get the molecular formula \(C_2H_3\).

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What happens to the state of liquid water if enough heat is added?

Answers

The molecules would move faster and start to float and it would start to boil and turn into a gas
HEAT

==============================

\( \large \sf \underline{Question:}\)

What happens to the state of liquid water if enough heat is added?

==============================

\( \large \sf \underline{Answer:}\)

What happens to the state of liquid water if enough heat is added?

The liquid will turn into gas due to the heat and if heat has been remove it will go back to being liquid.

==============================

What happens to the state of liquid water if enough heat is added?

Consider the equation:S+3O2 → SO3
Is this equation balanced? Why or why not?

I will give brainlyiest to whoever writes the most detailed answer.!!!

Answers

No, this equation is not balanced because the number of atoms of each element is not equal on both sides of the equation.

On the left side of the equation, there is 1 atom of S and 6 atoms of O (3 O$_2$ molecules).

On the right side of the equation, there is 1 atom of S and 3 atoms of O (1 SO$_3$ molecule).

Therefore, to balance the equation, we need to add a coefficient of 2 in front of SO$_3$ to get:

S + 3O$_2$ $\rightarrow$ 2SO$_3$

Now, there are 2 atoms of S and 6 atoms of O on both sides of the equation.

__________________________________

S + 3O2 → SO3 = S + 3O2 → 2SO3= 2S + 302 → 2SO3= uS + v302 → wSO3= u = w = 6v = 3w= 6v/6 = 3w/6= v = w/2 = u = w= 2S + 3O2 → 3SO2No, The Equation Is Not Balanced.

___________________________________

what is the bond order for al2

Answers

Answer:

The bond order is 1.091

Explanation:

there really is no explanation.

what is the name of the covalent compound N5Cl8

Answers

Answer:

Did you put that in right because i've never heard of a compound called that nor is there a compound called that on the internet

Explanation:

You must of put that in wrong

A ball has a mass of 33.6 grams and a volume of 14.0 cubic centimeters (cc). What is its density?

Answers

Answer: 2400kg/m3

Explanation:  p=m/3   m over 3

                       33.6g/14cm3

                       2.4g/cm3

                       2400kg/m3                        

Of the following solutions, which has the greatest buffering capacity?
a. 0.543 M NH3 and 0.555 M NH4Cl b. 0.087 M NH3 and 0.088 M NH4Cl c. 0.234 M NH3 and 0.100 M NH4Cl d. 0.100 M NH3 and 0.455 M NH4Cl e. They are all buffer solutions and would all have the same capacity.

Answers

The solution with the greatest buffering capacity is 0.543 M NH₃ and 0.555 M NH₄Cl since it has the highest concentrations of both NH₃ and NH₄+. option (a).

The buffer capacity is determined by the concentrations of both the weak acid and its conjugate base. The higher the concentrations of these species, the greater the buffering capacity. Thus, the solution with the greatest buffering capacity is option (a) 0.543 M NH₃ and 0.555 M NH₄Cl since it has the highest concentrations of both NH₃ and NH₄+.

A conjugate base is the particle formed when an acid loses a proton. It carries a negative charge and is capable of accepting a proton to reform the original acid. It is related to the acid through the transfer of a single proton.

Buffering capacity refers to the ability of a buffer solution to resist changes in pH upon addition of an acid or a base, by neutralizing them through the buffer components.

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B) Express the answer to this multistep calculation using the appropriate number of significant figures: 87. 95 feet x 0. 277 feet +5. 02 feet - 1. 348 feet + 10. 0 feet.

Answers

The answer to the multistep calculation, expressed using the appropriate number of significant figures, is 24.3 feet.

In order to determine the appropriate number of significant figures in the answer, we need to follow the rules of significant figures for addition and subtraction.

When adding or subtracting numbers, the answer should be rounded to the same number of decimal places as the measurement with the least number of decimal places.

Here, the measurement with the least number of decimal places is 10.0 feet, which has one decimal place. Therefore, we should round the final answer to one decimal place as well.

Now, let's perform the calculation:

87.95 feet x 0.277 feet + 5.02 feet - 1.348 feet + 10.0 feet = 24.3108725 feet

Rounding to one decimal place, the final answer is:

24.3 feet

Therefore, the answer to the multistep calculation, expressed using the appropriate number of significant figures, is 24.3 feet.

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Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?.

Answers

Answer:

212 000 yrs

Explanation:

15/16 decay means 1/16 is left

 how many halflives is this?

                    (1/2)^n = 1/16

                       n = 4   half lives

4 half lives * 53 000 yr/ half life = 212 000 yrs

Answer:

c. 212,000 years

Explanation:

got it right on edge:3

23. Record the volume of water for each of the following beakers to the correct number of sig figs.
24. Using your recorded measurements from #20, calculate the total volume of water with correct sig figs and units

23. Record the volume of water for each of the following beakers to the correct number of sig figs.24.

Answers

The volume of water for each of the following beakers to the correct number of sig figs are A= 26.4, B=24 and C = 26.44

The total volume of water in the beakers is = 76.84

Calculation of total volume

The volume of water is beaker A = 26.4

The volume of water is beaker B = 24

The volume of water is beaker C = 26.44

Therefore thet total volume of the whole beakers =

Beaker A + Beaker B + Beaker C

= 26.4 + 24+ 26.44

= 76.84

Therefore, the total volume of the whole beakers = 76.84.

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what is the poster child for complex ion formation?

Answers

A complex ion is a species shaped among a primary steel ion and one or greater surrounding ligands, molecules or ions that comprise at the least one lone pair of electrons.

Small, quite charged metal ions have the finest tendency to behave as Lewis acids and shape complicated ions. When a steel ion reacts with a Lewis base in answer a complicated ion is shaped. This response may be defined in phrases of chemical equilibria. A complicated ion is an ion that incorporates one or greater ligands which are connected to a primary steel cation via a dative covalent bond. A ligand is a species that may shape a dative covalent bond with a transition steel the usage of its lone pair of electrons.

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I'm just looking for someone to check my answers on this and correct me if I'm wrong :)This is the question:You have three elements, A, B, and C, with the following electronegativity values:A = 0.9B = 3.0C = 3.5You react the elements to form the substances AB, AC, and BC. Answer the following questions:What type of substance is AB? What types of bonds are present? Explain your answer.What type of substance is AC? What types of bonds are present? Explain your answer.What type of substance is BC? What types of bonds are present? Explain your answer.If any of the substances are ionic compounds, which element is the cation and which is the anion? Explain your answer.And these are my answers:AB is a compound. It'd be an ionic compound because the electronegativity is different in each.AC is a compound. It'd be an ionic compound because the electronegativity is different in each.BC is a compound, but the bond between them is covalent.AB is an ionic compound. A is the cation and B is the anion because the element with lower electronegativity is the cation and the element with the higher electronegativity is the anion.

Answers

Answer:

Explanations:

Given the following electronegativity of three elements as:

You have an object with a mass of 14 g and a volume of 20 mL. Calculate the density and identify which material you have from the list.

Answers

Answer:

0.7 g/ml. Whichever material matches that closest is the right one.



31. A mixture with sand, pink sugar and water would be best separated using

Answers

Answer:

Filtration and evaporation

Explanation:

A mixture of sand, pink sugar and water can be separated by filtration and evaporation.

The pink sugar is already dissolved in the water but the sand remains undissolved in the water hence it can be filtered off. The filtrate now contains the sugar.

The sugar is obtained from the filtrate by evaporation of the solution to yield the solid pink sugar and steam which can be condensed again to give liquid water.

why is longitudinal diffusion a more serious problem in gas chromatography than in liquid chromatography?

Answers

The longitudinal diffusion a more serious problem in gas chromatography than in liquid chromatography because the diffusion coefficient is much more larger in gas than the liquid.

What is Chromatography?

Chromatography is a type of laboratory technique which is performed for the separation of the mixture of different elements into its components. The mixture firstly dissolved in a fluid solvent which is known as the mobile phase, that carries it through a system at which the material called the stationary phase is fixed.

Not all molecules present in the same solute show same behavior. Different molecules show different behaviour. This is due to mainly three reason which arr given as below:

Resistance to the transfer of matter. Longitudinal diffusionSwirl diffusion

The molecules of solute moves in different direction in the stationary phase, it is due to porosity of the particle that form it.

Thus, we concluded that the longitudinal diffusion a more serious problem in gas chromatography than in liquid chromatography because the diffusion coefficient is much more larger in gas than the liquid.

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Which element is this.Its shiny,Is solid at room temperature, has atoms with two valence electrons?A:Lithium B:Strontium C:Aluminium D:Silicon

Answers

Answer:

Strontium

Explanation:

STRONTIUM

Strontium is a chemical element that is non radioactive and its occur naturally. It is a shiny and silvery white metal that have atomic number of 38 and it belong to group 2 member of the periodic table which is why it have two valence electrons. It is a solid metal at room temperature.

About 99% of Strontium is found in bones. It help to make new bones in humans by replacing the old bones.

Therefore, it is strontium.

Strontium is the element which is shiny, solid at room temperature and has two electrons in its outermost shell.

The atomic number of Strontium is 38. In the first shell, there are two electrons, in the second and fourth shell has space for 8 electrons so these shells are filled with electron whereas third shell has 18 electrons and the fifth shell has 2 electrons. Strontium belongs to second group i.e. alkaline earth metals due to which it has two valance electrons in its outermost shell.

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You have been asked to draw a Bohr model of the element carbon. How would you arrange the dots that represent electrons?

Answers

Answer:

You have been asked to draw a Bohr model of the element carbon. How would you arrange the dots that represent electrons? They would be embedded in a solid core. They would be in rings around the nucleus

What are magnetic field lines and what do they do? Explain likes and opposites in this

Answers

Answer:

Attract Field lines that curve toward each other show attraction.

Explanation:

Your science teacher asks you to find an Erlenmeyer flask. Your teacher says it has a flat bottom, a narrow opening, and a cone-shaped base. Based on this description, which is the correct flask?

Answers

Based on the description provided by the science teacher, the correct flask is an Erlenmeyer flask. Erlenmeyer flasks have a flat bottom, a narrow opening, and a cone-shaped base.

The cone-shaped base helps in swirling the contents of the flask and prevents spills during the mixing of liquids. The narrow opening helps in controlling the rate of gas exchange and minimizes the risk of contamination. Erlenmeyer flasks are commonly used in chemistry laboratories for mixing, heating, and storing liquids. They are also used in the preparation of solutions and in titration experiments. Their design makes them easy to handle and they are also stackable, which saves flask space in the laboratory. Based on the description provided by the science teacher, the correct flask is an Erlenmeyer flask. Erlenmeyer flasks have a flat bottom, a narrow opening, and a cone-shaped base.

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What key features should be present in the ir spectrum of your product if you successfully made the desired bromohydrin? what key features should be absent from the ir spectrum if the starting material was completely reacted?.

Answers

The key features that should be present in the IR spectrum of your product if you successfully made the desired bromohydrin and the key features that should be absent from the IR spectrum if the starting material was completely reacted are the spectra of the other alcohols.

The spectra of the other alcohols utilized in the synthesis indicate the presence of bromohydrin. The presence of Bromohydrin with the Hydroxyl stretch characteristic demonstrates the presence of alcohol

What is bromohydrin?

Bromonydrin is formed by the addition of Br and OH across an alkene, and the result is known as a bromohydrin (bromo=bromine, hydrin=hydro, water/H₂O).

The synthesis of bromohydrins includes extremely regioselective ring expansion of epoxides to halohydrins using hydrogen and lithium halides in the presence of -cyclodextrin in water as a solvent.

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Raw sulfur containing 88% S and 12% inerts was burned in dry air supplied in 54% in excess (S to SO2). The cinder contained 6% S and the rest inerts. It was found that 79% of the S that was gasified burned to SO2 and the rest to SO3. Calculate the following
Percent excess air based on the complete conversion of S to SO3
Weight of cinder in kg
Amount of sulfur gasified in kmol
Percent of SO2 in the burner gas based on complete analysis

Answers

The sulfur in raw sulfur, which has an 88% S and 12% inerts composition, was burned in dry air supplied with 54% in excess. The cinder contained 6% S and the remaining inerts. It was discovered that 79% of the S that was gasified burned to SO2, and the remaining to SO3. The following are the calculations.

Percent excess air based on complete conversion of S to SO3S + 3O2 → SO3The equation shows that there is no excess air in the case of complete conversion of sulfur to SO3. The balanced equation indicates that 1 kmol of sulfur reacts with 3 kmol of oxygen to produce 1 kmol of SO3. This implies that 1.5 kmol of oxygen are necessary per kmol of S.

Given the air-supplying 54% in excess of S to SO2, the oxygen supply was 1.54(1.5 kmol O2/kmol S) = 2.31 kmol O2/kmol S.

The excess air required for the complete conversion of S to SO3 was thus (2.31 - 1.5)/1.5 × 100 = 54%.

The weight of cinder in kg

Cinder composition includes 6% sulfur. The amount of sulfur in the cinder is calculated as follows:

100 kg of cinder contains 6 kg of sulfur.

Mass of sulfur = Mass fraction × Total mass

= 6/100 × Total mass= 0.06

Total mass = Mass of sulfur/Mass fraction= 0.06/0.06= 1 kg

Amount of sulfur gasified in kmol

The weight of the sulfur present in the raw sulfur is calculated first: 100 kg of raw sulfur contains 88 kg of sulfur

Mass of sulfur = Mass fraction × Total mass= 88/100 × Total mass= 0.88

Total mass = Mass of sulfur/Mass fraction= 0.88/0.88= 1 kmol

SO2 percent in the burner gas based on complete analysis

The air needed to completely burn 1 kmol of sulfur to SO2 is 1 kmol S + 1.5 kmol O2 → 1 kmol SO2.

54% excess air was used in this situation, therefore, oxygen supply was 1.54(1.5 kmol O2/kmol S) = 2.31 kmol O2/kmol S. This implies that the air/fuel ratio was 2.31 kmol O2/kmol S. Since oxygen accounts for around 23 percent of the air, this equates to an air-fuel ratio of approximately 10 kmol air/kmol S. SO2 accounts for 20 percent of the dry products by volume. This equates to an SO2 concentration of 20/(20 + 80) = 20 percent by volume.

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The abiotic components of an
ecosystem are
B. the animals and plants.
A. not important.
D. invisible.
C. nonliving.

Answers

Answer:

C. nonliving.

Explanation:

Will mark brainliest for who is right
Which properties change the composition of a substance?

chemical and physical properties


neither chemical nor physical properties


physical properties


chemical properties

Answers

Chemical properties
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