How many serving of cookies does this recipe make? How many serving are in 1 dozen cookies? How many servings are in 4 dozen cookies?

Answers

Answer 1

Answer:

one dozen: 12 servings

four dozens: 12x4 so 48 servings

Step-by-step explanation:

Assuming one cookie is one serving a dozen would be 12 so 12 servings per dozen.

Answer 2

Answer:

48 cookies

Step-by-step explanation: so a dozen cookies would be 12 cookies and 4*a dozen which would be 12 is 48 so 48 cookies= 4 dozens


Related Questions

Kraig deposited money into a money market account. It has an interest of 12% and is compounded annually. Kraig thought 3% would be the equivalent quarterly interest rate. Is Kraig correct? If he is, explain why. If he is not correct, state what the equivalent quarterly interest rate. Explain.

Answers

Answer:

If the amount is P, with the interest rate of 12%, the interest over the year is:

P*(1.12) - P = 0.12P

In this case the quarterly interest rate is:

0.12P/4 = 0.03P

With the same amount and 3% quarterly rate, the yearly interest would be:

P*(1.03)^4 - P = 0.1255P

The quarterly interest rate in this case is:

0.1255P/4 = 0.031375P

If the quarterly interest rate is r, it should be little less than 3% to yield a 12% yearly rate.

So Kraig is wrong.

The following data show the frequency of rainy days in a year less than 0.01 inch 165 days 0.01 -1 inch 90 days 1.01 - 5 inches 60 days 5.01 -10 inches 40 days more than 10 inches 10 days Find the mode.

Answers

The mode of a dataset is the value that appears most frequently. In this case, we need to find the interval of rainfall that occurs most frequently.

From the given data, we can see that the interval "less than 0.01 inch" has the highest frequency with 165 days. Therefore, the mode of this dataset is "less than 0.01 inch"

Effective communication is crucial in all aspects of life, including personal relationships, business, education, and social interactions. Good communication skills allow individuals to express their thoughts and feelings clearly, listen actively, and respond appropriately. In personal relationships, effective communication fosters mutual understanding, trust, and respect.

In the business world, it is essential for building strong relationships with clients, customers, and colleagues, and for achieving goals and objectives. Good communication also plays a vital role in education, where it facilitates the transfer of knowledge and information from teachers to students.

Moreover, effective communication skills enable individuals to engage in social interactions and build meaningful connections with others. Therefore, it is essential to develop good communication skills to succeed in all aspects of life.

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Kuta Software Infinite Algebra 1. Solving Systems of Equations by Substitution. Solve each system by substitution. 1) y=6x-11. -2x-3y=-7. -2x-3(60x-11)=-7

Answers

the solution to the system of equations is x = 2 and y = 1.

To solve the system of equations by substitution, we will solve one equation for one variable and substitute it into the other equation.

Given the system of equations:

1) y = 6x - 11

2) -2x - 3y = -7

Step 1: Solve equation (1) for y.

  y = 6x - 11

Step 2: Substitute the value of y from equation (1) into equation (2).

  -2x - 3(6x - 11) = -7

Step 3: Simplify and solve for x.

  -2x - 18x + 33 = -7

  -20x + 33 = -7

  -20x = -7 - 33

  -20x = -40

  x = (-40)/(-20)

  x = 2

Step 4: Substitute the value of x into equation (1) to find y.

  y = 6(2) - 11

  y = 12 - 11

  y = 1

Therefore, the solution to the system of equations is x = 2 and y = 1.

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Final answer:

The solution to the system of equations y = 6x - 11 and -2x - 3y = -7 is x = 2 and y = 1. This is achieved by substituting y into the second equation, simplifying, and solving for x, then substituting x back into the first equation to solve for y.

Explanation:

To solve the system of equations y = 6x - 11 and -2x - 3y = -7 by substitution, we start by substituting the equation y = 6x - 11 into the second equation in place of y, giving us -2x - 3(6x - 11) = -7. Next, simplify the equation by distributing the -3 inside the parentheses to get -2x - 18x + 33 = -7. Combine like terms to get -20x + 33 = -7. Subtract 33 from both sides to obtain -20x = -40, and finally, divide by -20 to find x = 2.

Once we find the solution for x, we substitute it back into the first equation y = 6x - 11. Substituting 2 in place of x gives y = 6*2 - 11, which simplifies to y = 1.

Therefore, the solution to the system of equations is x = 2 and y = 1.

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How much would Zion earn on a deposit of 10,000 one year at 5.12% compounded daily

Answers

Zion earn $5025 on a deposit of 10,000 for one year at 5.12% compounded daily.

Explain about the daily compounding?Compounding is the method through which interest is added to both the principle balance already in place and the interest that has already been paid.The interest generated on the savings account balance each day after the interest as from previous day has been applied is known as daily compound interest.

The formula for daily compounding is :

A = P * \((1 + r/n)^{nt}\)

Principal P =  10,000

Rate of interest r = 5.12%

Time t = 1 years.

number of times compounded n = 365 days.

So,

A = 10,000 * \((1 + 0.0512/365)^{365*1}\)

A = 10,000 * 1.5025

A = 15,025

Interest = A - P

Interest = 15,025 - 10,000

Interest = 5025

Thus, the Zion earn $5025 on a deposit of 10,000 for one year at 5.12% compounded daily.

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eight hundred 35 thousandths as a decimal

Answers

Answer:

0.835

Step-by-step explanation:

Hope this helps and have a great day!!!

Answer:

800.035

Step-by-step explanation:

Find the third side in simplest radical form: √92 6

Answers

8 is the answer just had this

y > -3x + 5
how do i graph this

Answers

The graph of the inequality ­y > -3x + 5 is added as an attachment

How to determine the graph of the inequality

From the question, we have the following parameters that can be used in our computation:

­y > -3x + 5

The above expression is a linear inequality that implies that

Slope = -3y-intercept = 5

Next, we plot the graph

See attachment for the graph of the inequality

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y > -3x + 5how do i graph this

Graph the system of equations. y = 2x y = –x + 6 Two lines on a coordinate plane that intersect at the point 2 comma 4. One line has y intercept 0 and the other has y intercept 6. Two lines on a coordinate plane that intersect at the point negative 2 comma negative 4. One line has y intercept 0 and the other has y intercept negative 6. Two lines on a coordinate plane that intersect at the point 1 comma 2. One line has y intercept 0 and the other has y intercept 3. Two lines on a coordinate plane that intersect at the point 3 comma 3. One line has y intercept 0 and the other has y intercept 6.

Answers

The solution to the systems of equations graphically is (2, 4)

Solving the systems of equations graphically

From the question, we have the following parameters that can be used in our computation:

y = 2x

y = -x + 6

Next, we plot the graph of the system of the equations

See attachment for the graph

From the graph, we have solution to the system to be the point of intersection of the lines

This points are located at (2, 4)

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Graph the system of equations. y = 2x y = x + 6 Two lines on a coordinate plane that intersect at the

A certain radioactive substance decays by 3.3% each year. Find the half-life of the substance, to 2 decimal places.

Answers

The half-life of the substance is approximately 20.48 years.

The half-life of a radioactive substance is the amount of time it takes for half of the initial quantity of the substance to decay.

In this case, we are given that the substance decays by 3.3% each year.

To find the half-life, we can use the following formula:

Half-life = (ln(2)) / (decay constant)

The decay constant can be calculated using the percentage decay per year.

Since the substance decays by 3.3% each year, the decay constant can be expressed as:

decay constant = -ln(1 - 0.033)

Now we can substitute the value of the decay constant into the half-life formula:

Half-life = (ln(2)) / (-ln(1 - 0.033))

Using a calculator to perform the calculations:

decay constant ≈ -ln(0.967) ≈ 0.0338

Half-life ≈ (ln(2)) / 0.0338 ≈ 20.48 years (rounded to 2 decimal places)

Therefore, the half-life of the substance is approximately 20.48 years.

In summary, with a decay rate of 3.3% per year, the half-life of the radioactive substance is approximately 20.48 years.

This means that it takes approximately 20.48 years for half of the initial quantity of the substance to decay.

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Mr Larson is planning a pizza party for 273 peoples he plans on 3 slices of pizza for each person. How many slices of pizza is this in all

Answers

Answer: 819

Step-by-step explanation:

273 x 3= 819

a) Give an example of discrete data that might consist of some decimal numbers.
b) Give an example of continuous data that might not have any numbers with fractional parts

Answers

Step-by-step explanation:

discretion data is something that will never change

continous data is data that will continue to become either larger or smaller

discret = ticket sales, number of employees

continuous = age,height

what is the value of 2^-3 as a fraction

Answers

Answer:

1/8

Step-by-step explanation:

2⁻³ = 1 / 2³ = 1 / (2*2*2) = 1/8

so the minus sign in the exponent means you can put that factor in the denominator without the minus sign.

You are shopping for single-use cameras to hand out at a party. The daylight cameras cost $2.75 and the flash cameras cost$4.25. You must buy exactly 20 cameras and you want to spend between $65 and$75, inclusive. Write and solve a compound inequality for this situation. Then list all the solutions that involve whole numbers of cameras.

Answers

The compound inequality for the given situation is $2.75x + $4.25y ≥ $65 and $2.75x + $4.25y ≤ $75, where x represents the number of daylight cameras and y represents the number of flash cameras.

To solve this compound inequality, we need to find the values of x and y that satisfy both conditions. The inequality $2.75x + $4.25y ≥ $65 represents the lower bound, ensuring that the total cost of the cameras is at least $65. The inequality $2.75x + $4.25y ≤ $75 represents the upper bound, making sure that the total cost does not exceed $75.

To list the solutions involving whole numbers of cameras, we need to consider integer values for x and y. We can start by finding the values of x and y that satisfy the lower bound inequality and then check if they also satisfy the upper bound inequality. By trying different combinations, we can determine the possible solutions that meet these criteria.

After solving the compound inequality, we find that the solutions involving whole numbers of cameras are as follows:

(x, y) = (10, 10), (11, 8), (12, 6), (13, 4), (14, 2), (15, 0), (16, 0), (17, 0), (18, 0), (19, 0), (20, 0).

These solutions represent the combinations of daylight and flash cameras that fulfill the requirements of buying exactly 20 cameras and spending between $65 and $75.

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Find the solution of the following differential equation by Laplace transforms with initial conditions for each equation: a) y" – y = t y(0) = 1, y'(0) = 1 b) y" + y' = t² + 2t y(0) = 4, y'(0) = -2 c) d²y/dt⁴ + d³y/dt³ = cost y(0) = y'(0) = y"' (0) = 0, y" (0) = 1

Answers

Laplace transforms are an essential mathematical tool used to solve differential equations. These transforms transform differential equations to algebraic equations that can be solved easily.

To solve the differential equations given in the question, we will use Laplace transforms. So let's start:Solution:a) y" – y = t y(0) = 1, y'(0) = 1First, we take the Laplace transform of the given differential equation.L{y" - y} = L{ty}

Taking the Laplace transform of both sides gives:L{y"} - L{y} = L{ty}Using the formula, L{y"} = s²Y(s) - s*y(0) - y'(0), and L{y} = Y(s) then we get:s²Y(s) - s - 1 = (1/s²) + (1/s³)Rearranging the above equation, we get:Y(s) = [1/(s²*(s² + 1))] + [1/(s³*(s² + 1))]Now, we apply the inverse Laplace transform to find the solution.y(t) = (t/2)sin(t) + (cos(t)/2)

The solution of the differential equation y" – y = t, with initial conditions y(0) = 1, y'(0) = 1 is y(t) = (t/2)sin(t) + (cos(t)/2).

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Choose the graph of the inequality x > -4

Choose the graph of the inequality x > -4

Answers

Answer:

d

Step-by-step explanation:

because it is any number greater than-4

Answer:

A

Step-by-step explanation:

Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18

Answers

Answer:

2y - 3x = -15

Step-by-step explanation:

Slope of the line 4x + 6y = 1 is as shown below;

Rewrite in slope intercept form;

6y = -4x+1

y = -4x/6 + 1/6

y = -2x/3 + 1/6

mx = -2/3x

m = -2/3

The slope of the line perpendicular M = -1/(-2/3)

M = 3/2

Get the x and y intercept of 2x+3y = 18

x intercept occurs when y  = 0

2x + 0 = 18

x= 18/2

x = 9

y intercept occurs when x  = 0

0 + 3y = 18

3y= 18

y = 18/3

y = 6

The line passes through the point (9,6)

Write the equation in point slope form

y - y0 = m(x-x0)

y - 6  = 3/2(x-9)

2(y-6) = 3(x-9)

2y - 12 = 3x - 27

2y - 3x = -27 + 12

2y - 3x = -15

This gives the required equation

Whats an EQUATION that shows a population of 10,000 is growing at the rate of 5% per year??

Answers

The equation that shows a population of 10,000 is growing at the rate of 5% per year is:P = 10,000(1 + 0.05)twhere P represents the population and t represents the number of years.

The above equation is a type of exponential growth formula that predicts how a population will change over time, based on a constant growth rate. In this case, the population is growing at a rate of 5% per year.

In order to determine the population at a specific time, we substitute the value of t (the number of years) into the equation.

For example, if we want to know the population after 10 years, we would substitute t = 10 into the equation:P = 10,000(1 + 0.05)10P = 10,000(1.05)10P = 10,000(1.6289)P = 16,289So after 10 years, the population would be 16,289.

To find out when the population would double, we set P = 20,000 (double the initial population) and solve for t:P = 10,000(1 + 0.05)t20,000 = 10,000(1 + 0.05)t2 = (1 + 0.05)tln(2) = t ln(1.05)t = ln(2) / ln(1.05)t ≈ 14.21So the population would double in approximately 14 years and 2 months.

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I don’t know the answer helppp

I dont know the answer helppp

Answers

Answer:

(1, -2)

Step-by-step explanation:

equate the two answers (make them equal to each other). Then solve.

7x + 11 = -3x + 1

7x + 3x = 1 - 11

10x = -10

x = 1

Plug "x" in to one of the equations to find "y" (I'm using equation 2)

y = -3(1) + 1

y = -3 + 1

y = -2

final answer: (1, -2)

PLEASSEE HELP ASAP HURRRY!!!!!!!!!!!

Which of the following statements is TRUE based on the information given?

PLEASSEE HELP ASAP HURRRY!!!!!!!!!!!Which of the following statements is TRUE based on the information

Answers

Answer:

it is d

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

hi plz answer image below may god less you no bot answers plz

hi plz answer image below may god less you no bot answers plz

Answers

Answer:42.875 feet3

Step-by-step explanation:

Answer:

Step-by-step explanation:

V=a³

=\((3\frac{1}{2})^3=42\frac{7}{8}\)in³

When comparing three or more populations means within a set of quantitative data that is categorized according to one​ factor/treatment, a​ one-way ANOVA is appropriate.a. It is also appropriate in this​ situation, however, to compare two means at a time using multiple independent two sample​ t-tests. True or​ False?b. True. It is appropriate to compare two means at a time with independent two sample​ t-tests but it might be​ time-consuming.c. False. It is not appropriate to compare two means at a time in the way described. This would inflate the overall Type I Error and is a​ 'Multiple Testing' problem. The​ one-way ANOVA controls for the Type I Error and should be used instead.

Answers

c. False. It is not appropriate to compare two means at a same time with the way described above. This would remove the overall Type I Error is a 'Multiple Testing' problem.

Why it is not appropriate to compare two means at a time in the way described?

The one-way ANOVA controls for the Type I Error and should be used instead. When comparing multiple means, conducting multiple independent two-sample t-tests is not recommended because the probability of committing a Type I error increases with each additional test, leading to an inflated overall Type I error rate.

ANOVA is a better method for comparing means when there are more than two groups as it compares all means simultaneously and controls for Type I error.

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Which component is missing from the process of photosynthesis?

Carbon Dioxide + ________ + Sunlight → Glucose + Oxygen

Light Energy
Sugar
Plants
Water

Answers

Answer:

Water i hope it is correct

the answer is water .

Suppose that each of two investments has a 4% chance of a loss of R15 million, a 1% chance of a loss of R1.5 million and a 95% chance of a profit of $1.5 million. They are independent of each other. Calculate the expected shortfall (ES) when the confidence level is 95%?

Answers

The expected shortfall (ES) at a 95% confidence level for these two independent investments is R0.615 million.

To calculate the expected shortfall (ES) at a 95% confidence level, we need to determine the average loss that exceeds the value at risk (VaR) at this confidence level. The VaR is the threshold at which the specified confidence level is met or exceeded.

In this scenario, each investment has a 4% chance of a loss of R15 million, a 1% chance of a loss of R1.5 million, and a 95% chance of a profit of R1.5 million. We can calculate the probabilities of each outcome and their corresponding losses:

For the R15 million loss: Probability = 0.04, Loss = R15 million

For the R1.5 million loss: Probability = 0.01, Loss = R1.5 million

For the R1.5 million profit: Probability = 0.95, Loss = 0

To calculate the expected shortfall, we consider the losses that exceed the VaR at the 95% confidence level. In this case, the VaR is R1.5 million, which is the highest loss with a 95% probability of not being exceeded. Therefore, the expected shortfall is the weighted average of the losses that exceed the VaR, considering their respective probabilities:

Expected Shortfall = (0.04 * R15 million) + (0.01 * R1.5 million) = R0.6 million + R0.015 million = R0.615 million.

Therefore, the expected shortfall (ES) at a 95% confidence level for these two independent investments is R0.615 million.

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A.
B.
C.
D.

Help me please!!

A.B.C.D.Help me please!!

Answers

It's B!!!           ik cuz i ggogled it lol

Answer:

I think the answer is B. $92

Step-by-step explanation:

$80 time (115 on calculator will give you 9200

Solve
P =
Check
P-2w
2
= 1 for P.

SolveP =CheckP-2w2= 1 for P.

Answers

Answer:

P= 2l + 2W

Step-by-step explanation:

(P-2W)/2= l

(P-2W)= 2l

P-2W= 2l

P= 2l + 2W

Which box plot matches the data set?
10, 14, 20, 24, 30, 40, 43, 45, 46, 48
For this data set, the first quartile is 20, the median is 35, and the third
quartile is 45.

Which box plot matches the data set?10, 14, 20, 24, 30, 40, 43, 45, 46, 48For this data set, the first

Answers

Answer: C

Step-by-step explanation:

Variables y and x have a proportional relationship wher y=18 when x=2 what is the value of x when y=36

Answers

Answer:

4

Step-by-step explanation:

18 + 18 = 36

So you got 36 cuz you times by two so you times the same for x

which is

2 x 2 = 4

Answer:

4

Step-by-step explanation:

We can set up a proportion.

18:2 = 36: x

If we multiply 18 by 2, and multiply 2 by 2, we can get 18:2 = 36:4, so x is equal to 4

for the simple harmonic motion equation d=2 sin(pi/3t) what is the period

Answers

For the simple harmonic motion equation d=2 sin(pi/3t), the period is 6 seconds.

The period of a simple harmonic motion is the time taken for one complete cycle of the motion. In this equation, d represents the displacement or position of the object at time t. The equation is in the form of sin function with the argument (pi/3)t. The general form of the equation for simple harmonic motion is d=A sin(ωt+φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle. To determine the period of this motion, we can use the formula T=2π/ω, where T is the period and ω is the angular frequency. In this case, ω=pi/3, so the period is T=2π/(pi/3)=6 seconds (rounded to the nearest second). Therefore, the object completes one full cycle of motion every 6 seconds.

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the weights of oranges growing in an orchard are normally distributed with a mean weight of 8 oz. and a standard deviation of 2 oz. from a batch of 1400 oranges, how many would be expected to weigh more than 4 oz. to the nearest whole number? 1) 970 2) 32 3) 1368 4) 1295

Answers

The number of oranges that are expected to weigh more than 4 oz is:

1400 - (1400 × 0.0228)≈ 1368.

The mean weight of the oranges growing in an orchard is 8 oz and standard deviation is 2 oz, the distribution of the weight of oranges can be represented as normal distribution.

From the batch of 1400 oranges, the number of oranges is expected to weigh more than 4 oz can be found using the formula for the Z-score of a given data point.

\(z = (x - μ) / σ\)

Wherez is the Z-score of the given data point x is the data point

μ is the mean weight of the oranges

σ is the standard deviation

Now, let's plug in the given values.

\(z = (4 - 8) / 2= -2\)

The area under the standard normal distribution curve to the left of a Z-score of -2 can be found using the standard normal distribution table. It is 0.0228. This means that 0.0228 of the oranges in the batch are expected to weigh less than 4 oz.

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please help with this one

please help with this one

Answers

Answer:

13 meters

Step-by-step explanation:

The radius is half of the circumference. Please gift me brainliest

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