The total number of photons with a wavelength of 710 nm and a total energy of 0.001 J is approximately 1.41 x 10^15.
The energy of a single photon is given by the equation E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength.
To find the number of photons, we can divide the total energy by the energy of a single photon:
Number of photons = Total energy / Energy of a single photon
Number of photons = 0.001 J / (hc/λ)
Number of photons = 0.001 J / [(6.626 x 10^-34 J·s) * (3.00 x 10^8 m/s) / (710 x 10^-9 m)]
Number of photons ≈ 1.41 x 10^15
Therefore, approximately 1.41 x 10^15 photons of wavelength 710 nm carry a total energy of 0.001 J.
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The force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What is the coefficient of kinetic friction?
Answer: 0.6
Explanation: I don't know the explanation and i don't know how to find the answer but i promise the answer is 0.6
The coefficient of kinetic friction between the object and the surface is 0.6
The formula for calculating the force of friction is expressed as:
\(F = \mu R\)
F is the frictional force
\(\mu\) is the coefficient of friction
R is the normal reaction
For the object on the surface, its weight is equal to the normal reaction and the frictional force is equal to the moving force;
W = R = 20N
F = Fm = 12N
From the equation above:
\(\mu =\frac{F}{R} \\\mu = \frac{12}{20}\\\mu = 0.6\)
Hence the coefficient of kinetic friction between the object and the surface is 0.6
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0.40N
weight
apple
50 cm
mark
25 cm
45 cm
pivot
Fig. 3.1 (not to scale)
The centre of mass of the apple is 25 cm from the pivot and the centre of mass of the weight
is 45 cm from the pivot.
Calculate
(i) the weight of the apple,
IO
.. [2]
weight =
(11) the mass of the apple.
[1
mass =
Answer:
Explanation:
dwadad
One component of a magnetic field has a magnitude of 0. 0404 T and points along the x axis while the other component has a magnitude of 0. 0739 T and points along the y axis A particle carrying a charge of 2. 80 10 5 C is moving along the z axis at a speed of 4. 46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis
a) The magnitude of the net magnetic force that acts on the particle is 2.18 x 10-6 N.
b) The angle that the net force makes with respect to the x axis is 63.8°.
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
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7. An object's mass refers to___ and an object's weight refers to___. Fill in each bland.
Answer:
An Object's mass refers to THE AMOUNT OF MATTER/STUFF IN AN OBJECT and an object's weight refers to THE FORCE OF GRAVITATIONAL ATTRACTION TO THE EARTH.
Explanation:
-Hope this helped
An Object's mass refers to The amount of Matter in the Object and an object's weight refers to THE FORCE OF GRAVITATIONAL ATTRACTION TO THE EARTH.
What is Gravitational attraction ?Greater gravitational forces will pull more massive objects toward one another because gravitational force is directly proportional to the mass of both interacting objects.
Therefore, the gravitational attraction between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two.
The force of gravity between two objects is multiplied by two when their masses are each doubled, and so on. Increased separation distance will lead to more gravitational force because it is inversely proportional to the square of the distance between the two interacting objects.
Therefore, An Object's mass refers to The amount of Matter in the Object and an object's weight refers to THE FORCE OF GRAVITATIONAL ATTRACTION TO THE EARTH.
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Compared to visible radiation, does infrared radiation have longer or shorter wavelengths and higher or lower energy per photon?
Infrared radiation has longer wavelengths compared to visible radiation, and lower energy per photon.
What are infrared radiation?Infrared radiation (IR) is a type of electromagnetic radiation that is not visible to the human eye. It has a longer wavelength and lower frequency than visible light, and it is part of the electromagnetic spectrum that also includes radio waves, microwaves, visible light, ultraviolet radiation, X-rays, and gamma rays.
Infrared radiation is often associated with thermal radiation, which is the emission of electromagnetic waves from objects that are at a temperature above absolute zero. This is because infrared radiation is often emitted by objects that are warm, and it is this type of infrared radiation that is responsible for our ability to feel heat.
Infrared radiation has a wide range of applications, including in remote sensing, thermal imaging, and heating. For example, in remote sensing, infrared radiation can be used to observe and study the Earth and other celestial objects, as well as to detect and monitor changes in temperature, vegetation, and other physical properties. In thermal imaging, infrared cameras are used to detect heat signatures and create images based on temperature differences. In heating, infrared heaters use infrared radiation to heat objects and materials directly, rather than heating the air around them.
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Define 1 kg of mass as international standard
Answer:
1 kg is defined as the mass of a cylindrical Platinum iridium alloy whose height is equal to its diameter
A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.
Answer:
Density= 2.78 g/cm³
Relative density=2.8
Explanation:
To calculate the density of the cube we have to use the formula ρ=mass/volume
ρ stands for density.
So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³
3³= 9 cm³
Now plug in the values. ρ= 25 g/9 cm³
ρ= 2.78 g/cm³
To find the relative density, we have to use the formula ρsample/ρH20
The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.
Now we have to make the units same so you change the unit of the density of cube to kg/m³
So, 25/1000= 0.025 kg
9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)
=0.000009 m³
The new density= 0.025 kg/ 0.000009 m³
= 2777.78 kg/m³
Now plug the values into the formula:
relative density= 2.777.78 kg/m³ / 997 kg/m³
=2.8
There is no unit since kg/m³ and kg/m³ cancels
What are the 3 main approaches to the identification of unknown bacteria?
The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification
What is Phenotypic, Molecular and Biochemical identification?1. Phenotypic identification
Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.
2. Biochemical identification
Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.
3. Molecular identification
Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.
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If the change of variables ux2 is used to evaluate the definite integral , what are the new limits of integration?
If the change of variables \(\(u = x^2\)\)is used to evaluate the definite integral, the new limits can be seen as \(\(u = a^2\)\) for the lower limit and \(\(u = b^2\)\) for the upper limit.
To determine the new limits of integration when using the change of variables \(\(u = x^2\)\), we need to express the original limits of integration in terms of the new variable \(\(u\)\).
Let's consider the definite integral:
\(\[I = \int_{a}^{b} f(x) \, dx.\]\)
Using the change of variables \(\(u = x^2\),\) we need to find the values of \(\(u\)\) corresponding to the original limits \(\(x = a\)\) and \(\(x = b\).\)
For the lower limit, \(\(x = a\)\), we substitute into the equation \(\(u = x^2\)\):
\(\[u = a^2.\]\)
For the upper limit, \(x = b\), we substitute into the equation \(\(u = x^2\)\):
\(\[u = b^2.\]\)
Therefore, the new limits of integration, expressed in terms of the variable \(\(u\)\), are \(\(u = a^2\)\) for the lower limit and \(\(u = b^2\)\) for the upper limit.
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____________ is the rate at which the electric charges move through a given area.
Magnetism
Current
Induction
Flux
Answer:
current is the rate at which the electric charges move through a given areawhich of the following geographic features sits on a divergent plate boundary? a) the andes mountains b) iceland c) los angeles d) the himalayan mountains
b) Iceland sits on a divergent plate boundary.
Correct answer is b) iceland
A divergent plate boundary, also known as a constructive boundary, is a boundary where two tectonic plates are moving away from one another. As the two plates separate, molten rock, or magma, rises from the mantle to fill the gap, forming a new crust on each plate.
This process creates new oceanic crust, resulting in the creation of mid-oceanic ridges. A new divergent boundary is created when plates shift away from each other, and the resulting crack fills with molten magma. Iceland is located on a divergent plate boundary.
It is situated over the Mid-Atlantic Ridge, which separates the North American and Eurasian Plates. Iceland is still expanding due to the divergent boundary's movement, and it is one of the few places on the planet where this phenomenon can be observed on land. The Andes, Los Angeles, and the Himalayas are not located on divergent plate boundaries.
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what can the radial velocity method determine about an exoplanet that the transit detection method cannot?
A transiting exoplanet in relation to the star that it is orbiting. The photometric approach can figure out a planet's radius whereas the radial velocity technique can tell you how much mass a planet has.
How can you find extrasolar planets using the radial velocity method?Utilizing the Doppler changes in the wavelength of the planet's star, the radial velocity approach finds extrasolar planets. A star would show a bluish change as it approached the earth. The radial velocity technique detects the redshift of the spectrum of a star that is travelling away from Earth.
Why is it that low mass stars benefit from the radial velocity method?Because of the fact that planets' gravitational pull on low mass stars is stronger and also because these stars often spin slower rate.
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The radial velocity method can determine the mass of an exoplanet, while the transit detection method cannot.
The radial velocity method, also known as the Doppler spectroscopy method, measures the slight shifts in the wavelength of light emitted by a star due to the gravitational tug of an orbiting exoplanet. This method allows scientists to determine the mass of the exoplanet. When an exoplanet orbits its host star, it induces a small wobble in the star's motion. By measuring these periodic changes in the star's radial velocity (motion along the line of sight), scientists can infer the mass of the exoplanet.
On the other hand, the transit detection method involves observing the periodic dimming of a star's brightness as an exoplanet passes in front of it, blocking a fraction of the star's light. This method provides information about the exoplanet's size, orbital period, and distance from its host star. However, it cannot directly determine the exoplanet's mass.
By combining the radial velocity method with the transit detection method, scientists can gather more comprehensive information about exoplanets. The combination of these two techniques enables the determination of an exoplanet's density, which provides insights into its composition and potential characteristics such as whether it is rocky or gaseous.
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Jack and jill travel up a hill at a speed of 2 mi/h. they travel back down the hill at a speed of 4 mi/h. what is their average speed for the entire trip? express your answer as a mixed number.
Jack and jill travel up a hill at a speed of 2 mi/h. They travel back down the hill at a speed of 4 mi/h. Their average speed for the entire trip is 8/3 mi/h
The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity
Let x be the distance of hill from one side.
⇒ Distance for round trip = 2x
Let t1 and t2 be the time taken by them when going and returning back respectively.
Total time taken for round trip = t1+ t2
we have,
speed = distance/ time
⇒time = distance/speed
so, t1 = x/2
t2= x/4
Average speed for round trip = total distance/ total time
\(average speed = \frac{2x}{ \frac{x}{2} + \frac{x}{4} } \)
= 8/3 mi/h
therefore, Their average speed for the entire trip is 8/3 mi/h.
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What is the resistance of resistor R3?
Answer: 2.0
Explanation: I KNOW !
an electromagnet is the most powerful type of magnet there is. it is a magnet with a current running through it that can be turned on and off. why might it be useful to be able to turn the electromagnet on and off?(1 point)
An electromagnet is a very powerful type of magnet that can be turned on and off, making it incredibly useful in a variety of settings. Electromagnets can be used to sort and manipulate metallic materials, and they can be controlled with precision. However, there are also some drawbacks to using electromagnets, including the need for an electrical power source and the potential for heat generation.
An electromagnet is an incredibly powerful type of magnet that can be turned on and off, making it incredibly useful in a variety of settings.
The ability to turn an electromagnet on and off is particularly useful in situations where there are a large number of metallic materials that need to be manipulated or sorted.
One of the primary benefits of using an electromagnet is that it is incredibly powerful, particularly when compared to other types of magnets. This is because an electromagnet is a magnet with a current running through it. This current produces a magnetic field, which is much stronger than the magnetic fields produced by permanent magnets.
Another benefit of using an electromagnet is that it can be controlled with precision. Because the current running through the electromagnet can be adjusted, it is possible to control the strength of the magnetic field. This makes it possible to use electromagnets in a wide range of applications, from lifting heavy loads to separating metallic materials.
Finally, it is worth noting that there are some drawbacks to using electromagnets.
Additionally, electromagnets can generate heat when they are turned on, which can be a problem in some applications.
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1. Gravity depends on two things. What two things does gravity depend on? 10pts
SCI
Gravity depends on the mass of objects and distance.
The more mass the more gravitational force, the more distance between two objects the less gravitational force.
Fluorescence occurs when an object absorbs ____________________ and immediately releases the energy as visible light.
Answer:
The answer should be light or other electromagnetic radiation
Explanation:
Such as x-rays or other things like that.
-Hope This Helps!
-Justin:)
what force much be applied to stop a 1400kg car that is initially traveling at 13 m/s over a 5 second time period
Answer:
As per Provided Information
Mass of car m is 1400KgInitial velocity u is 13m/sTime taken to stop t is 5 second .Final velocity v is 0m/swe have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.
\( \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}\)
Substituting the value and let's solve it
\( \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} \)
Now, let's calculate the force applied to stop the car .
\( \pink{\boxed{\bf \: F = ma}}\)
Substituting the value we get
\( \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N\)
Here , negative sign show that the " Force is acting in opposite direction of the motion"
Therefore,
3640 Newton force is required to stop the car .How can i get the distance of echo equals to 17m?
To get the distance of an echo that equals 17m, you need to know the speed of sound and the time it takes for the echo to bounce back.
The speed of sound in air is approximately 343 meters per second. So, to calculate the time it takes for the sound to travel to the object and back, you need to divide the distance by the speed of sound.
Here's the formula:
Time = Distance / Speed of Sound
So, if you want to find the time it takes for sound to travel to the object and back and reach your ears as an echo, you can use this formula.
Time = 17m / 343 m/s
Time = 0.0496 seconds
This means that it takes approximately 0.0496 seconds for the sound to travel to the object and back, and for the echo to reach your ears. Keep in mind that this calculation assumes that the sound waves travel directly to and from the object, without any obstructions or other factors that could affect the speed or distance of the sound.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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Please help!
The Moon itself does not produce light. It appears to be lit because it is _____________ light from the Sun. *
A)absorbing
B)Reflecting
C)capturing
D)stealing
Answer:
it's b the moon reflect light from the sun
I quoted a theorem on the multiplicity of any system with only quadratic degrees of freedom: In the high- temperature limit where the number of units of energy is much larger than the number of degrees of freedom, the multiplicity of any such system is proportional to U^N f/2, where N f is the total number of degrees of freedom. Find an expressionfor the energy of such a system in terms of its temperature, and comment on the result. How can you tell that this formula for ohm cannot be valid when the total energy is very small?
The expression for the energy of the system in terms of temperature is E = -kT ln(U).
The given theorem states that in the high-temperature limit, where the number of units of energy is much larger than the number of degrees of freedom, the multiplicity of the system is proportional to U^(Nf/2), where Nf is the total number of degrees of freedom. Here, U represents the energy of the system.
To express the energy of the system in terms of its temperature, we can utilize the relationship between energy and temperature derived from statistical mechanics.
According to statistical mechanics, the energy of a system is related to its temperature through the Boltzmann distribution, given by:
U ∝ exp(-E/kT)
In this equation, E represents the energy of a particular state, k is the Boltzmann constant, and T is the temperature. Taking the logarithm of both sides of the equation, we have:
ln(U) ∝ -E/kT
Rewriting the equation, we get:
E = -kT ln(U)
Therefore, the expression for the energy of the system in terms of temperature is E = -kT ln(U).
Now, let's comment on the result. The negative sign in the expression indicates that as the multiplicity (U) increases, the energy (E) decreases. This is consistent with the concept that in the high-temperature limit, systems tend to occupy states with higher multiplicity (more available configurations) and lower energy.
The equation also shows that as temperature (T) increases, the energy of the system also increases. This aligns with our intuitive understanding that raising the temperature of a system adds energy to it.
Regarding the validity of the formula for systems with very small total energy, we need to consider the assumptions made in the theorem. The theorem assumes that the number of units of energy is much larger than the number of degrees of freedom.
When the total energy is very small, it may violate this assumption, and the high-temperature limit might not be applicable. In such cases, other factors and effects, such as quantum mechanical considerations and discrete energy levels, become significant, and the behavior of the system may deviate from the predictions based on the high-temperature limit.
Therefore, the formula for the multiplicity (and consequently the energy) derived from the high-temperature limit may not be valid for systems with very small total energy.
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calculate the net force needed to accelerate a 70.0 kg refrigerator 5.0 m/s^2
Answer:
350 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 70 kg
acceleration = 5 m/s²
We have
force = 70 × 5 = 350
We have the final answer as
350 NHope this helps you
. ASSERTION: WHEN ASTRONAUTS THROW SOMETHING IN SPACE, THAT OBJECT WOULD CONTINUE MOVING IN THE SAME DIRECTION AND WITH THE SAME SPEED. REASON: THE ACCELERATION OF AN OBJECT PRODUCED BY A NET APPLIED FORCE IS DIRECTLY RELATED TO THE MAGNITUDE OF THE FORCE, AND INVERSELY RELATED TO THE MASS OF THE OBJECT.
Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.
The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.
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Sound travels through air at 343 m/s at 20 °C. A bat emits an ultrasonic squeak and hears the echo 0.05 second later . How far away was the object that reflected it?
Answer:
8.575 m
Explanation:
speed = distance/time
distance -- 2d
343 = 2d/0.05
2d = 17.15
d = 17.15/2
d = 8.575
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i need to write an abstract for a science project, 250 words minimum. the project is regarding the frequency of guitar strings. here is other information if needed:
There are many components that make up a guitar. At the top, is the head and the peghead. Below that is the nut which leads into the neck and the fretboard of the instrument. The frequency of a guitar string depends on the length, the tension, and the mass of the string.The longer, looser, or heavier the string, the lower the lower the frequency. Ultimately, the slower the string vibrates and the longer it takes the sound to carry through the string, the lower the pitch will be and vice versa. You can increase the frequency of a string on guitar by shortening, tightening or reducing the weight of it. The strings of a guitar are supported at two points when they are not being played. The nut, at the top, and the saddle, which rests on the bridge. When you fret on a guitar, that fret starts to act as the nut, becoming the starting point of the string and therefore raising the frequency. You can raise the pitch an octave by fretting between the 11th and 12th frets.
Question: What is the relationship between the length of a string and the wavelength of the fundamental tone it produces when plucked?
Hypothesis: If the string is shorter, then it will produce a fundamentally higher tone.
Materials:
guitar (acoustic or electric)
guitar pick
electronic tuner to tell you what note you’ve played
sewing tape measure
lab notebook
pen or pencil
Procedure:
Measure the length of the string and the distance between the saddle and each fret using a sewing tape measure.
Tune your guitar and set up a tuner software or chromatic tuner to record the notes.
Play the open high E string and write down the frequency.
Fret the string just behind the first fret and play it again. Write down the frequency.
Repeat step 4 for frets 2-5 and all the other strings.
Organize your data in a table.
conclusion:
The fundamental tone produced by each string was higher when the string became shorter and thinner.
The abstract for a science project regarding the frequency of guitar strings is given below
What is the abstract?This science project is one that seeks to explores the relationship between the length of a guitar string and the wavelength of the elemental tone it produces when culled.
The recurrence of a guitar string is seen as part on its length, pressure, and mass. This extend tells that shorter strings will create a on a very basic level higher tone.
Hence An electronic tuner was said to be utilized to record the recurrence of each note played. The comes about appeared that the elemental tone delivered by each string was higher when the string got to be shorter and more slender.
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A 20 kω resistor is connected in series with an initially uncharged 100 μf capacitor and a 5 v battery. What is the charge on the capacitor when the circuit has reached steady state?
Hi there!
We can use the equation for the charge of a charging capacitor:
\(q(t) = C\epsilon( 1 - e^{-\frac{t}{RC}})\)
Using Capacitor equations:
\(C = \frac{Q}{V}}\\\\Q = CV\)
Therefore, Cε equals the steady-state charge of the capacitor (the function approaches this value as t ⇒ ∞.
We can plug in the givens and solve.
\(\epsilon = 5 V\\\\C = 100\mu F = 0.0001 F\)
\(Q = C \epsilon = (0.0001)(5) = \boxed{0.0005 C}\)
The charge on the capacitor when the circuit has reached a steady-state is 0.0005C.
What is capacitance?The capacitance of a conductor is defined as the ratio of the quantity of electric charge stored on it to the difference in electric potential.
Given that the resistance of the resistor is 20 kω, while the capacitance of the capacitor is 100 μf, and the voltage of the battery is 5V.
Now, the charge on the capacitor when the circuit has reached a steady-state can be written as,
\(Q=CV\\\\Q = 100\mu F \times 5V\\\\Q = \dfrac{100}{1,000,000}F \times 5V\\\\Q = 0.0005C\)
Hence, the charge on the capacitor when the circuit has reached a steady state is 0.0005C.
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A mover is trying to lift a piano (slowly) up to a second-story apartment. He use a pulley and ropes to decrease the force needed to raise a heavy load (Figure 1) Figure 1 of 1 B mg Part A But for every meter the load is raised, how much rope must be pulled up? Account for this, using energy concepts O For each meter of the load is raised, 2 m of rope must be pulled up. O For each meter of the load is raised, 2.5 m of rope must be pulled up For each meter of the load is raised, 1.5 m of rope must be pulled up. O For each meter of the load is raised, 0.5 m of rope must be pulled up. Submit Request Answer Provide Feedback
Two metres of rope must be raised in order to move the burden every metre.
Explain why two metres of rope should be raised.
Assuming no dissipative forces are at work over the rope.
The effort is used to draw upward on the rope's free end while the load is hung from the pulley block. The effort required is just half the amount of the load because the load is now suspended from two ropes, each of which is bearing half of the weight.
Hence, two metres of rope must be raised in order to move the burden every metre.
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The density of iron is 14.0 g/cm³. A worker in a science lab calculates the density of iron as 4.5
g/cm³. What is the percent error of the worker's measurement?
Answer:
Percent Error = 67.86%
Explanation:
The percent error can be calculated using the following equation:
| measured value - true value |
Percent Error = ------------------------------------------------- x 100%
true value
In this equation,
---> The "measured value" is the value found after performing an experiment.
---> The "true value" is the value you expect to find after performing an experiment.
In this case,
---> measured value = 4.5 g/cm³
---> true value = 14.0 g/cm³
| 4.5 g/cm³ - 14.0 g/cm³ |
Percent Error = ---------------------------------------- x 100% <----- Insert values
14.0 g/cm³
| -9.5 g/cm³ |
Percent Error = ------------------------ x 100% <----- Subtract
14.0 g/cm³
9.5 g/cm³
Percent Error = ------------------------ x 100% <----- Take absolute value
14.0 g/cm³
Percent Error = 0.6786 x 100% <----- Divide
Percent Error = 67.86% <----- Multiply
A girl is travelling on her bike at a speed 2.54 m/s. If the girl and her bike have a kinetic energy of 193 J, what is the combined mass of the girl and her bike? Show all your work.
Answer:
About 59.83 kg
Explanation:
The formula for kinetic energy is \(KE = \frac{1}{2}mV^2\), where KE = Kinetic Energy in Joules (J), m = mass in kilograms (kg), and V = Velocity in meters per second (m/s).
In this problem, we are given the Kinetic Energy amount as 193 Joules and the Velocity as 2.54 m/s. Let's plug it into our equation
\(193 = \frac{1}{2} * 2.54^2m\)Now, let's solve this equation.
Step 1: Simplify both sides of the equation.
\(193 = 0.5 * 2.54 * 2.54 * m\) \(193=3.2258m\)Step 2: Divide both sides by 3.2258.
\(193/3.2258 = 3.2258m/3.2258\) m ≈ 59.830 kilograms