How many nodal lines are created by two point sources emitting at the same wavelength λλ that are separated by a distance equal to 4.5λ4.5λ? Express your answer as an integer.

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

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Answer:

As the load increases the motor generally reduces rpm, as the happens the counter emf generated in the armature decreases, causing more current to flow to

Explanation:

Answer:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest. These types of waves are found globally across the open ocean and along the coast.

Explanation:

Answer:

False

Explanation:

The 3 important steps to a perfect forehand in tennis are Preparation,Backswing and Swing and contact.

(1) The total pressure of the pipe at point 1 is 1.85 x 10⁵ Pa.

(2) The total pressure of the pipe at point 2 is  146,950 Pa.

The total pressure at position 1 and 2 is calculated by applying Bernoulli's equation as shown below.

P (t) = P₀ + ρgh

where;

The total pressure of the pipe at point 1 is calculated as follows;

P (t) = ( 1.85 x 10⁵ )  +   ( 1000 x 9.8 x 0 )

P (t) = 1.85 x 10⁵ Pa

The total pressure of the pipe at point 2 is calculated as follows;

P (t) = ( 1.2 x 10⁵ ) + ( 1000 x 9.8 x 2.75 )

P (t) = 146,950 Pa

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The complete question is below:

Water flows through a pipe as shown in the figure. The pressure at points 1 and 2 respectively is 1.85 x 10ª Pa and 1.20 x105 Pa. The

radius of the pipe at points 1 and 2 respectively is 3.30 cm and 1.40 cm. If the vertical distance between points 1 and 2 is 2.75 m, determine

the following.

(1) the total pressure at point 1

(2) the total pressure at point 2

Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.

Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.

To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.

The work done by the air can be calculated using the equation:

Work = Force * Distance * cos(θ)

Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.

In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:

Work = Force * Distance * 0

Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.

However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.

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Answer:

Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.

Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.

Example of conductor is copper

Example of insulator is plastic

Answer:

The light wave could be reflected by the object

Light is refracted and spread out by a concave lens.

Refraction refers to a phenomenon which describes a change (bend) in the path taken by light when it comes in contact with surfaces between different transparent materials. The refraction of light is inversely proportional to its wavelength.

When parallel rays of light enter into a concave lens, the light waves refract outward (spread out). The light rays refract twice: first when entering the lens and second when leaving the lens. Only the light rays passing through the center of the lens remain straight.

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Answer:

True;   ar = v^2 / R      Radial acceleration because it moves in a circular path

    at = α R = tangential acceleration because its speed changes

a = at + ar    total acceleration equals sum of radial and tangential

Answer:

a) 5.5×10^17 Hz

b) visible light

Explanation:

Since the wavelength of the electromagnetic radiation must be about the size of the about itself, this implies that;

λ= 5.5 × 10^-10 m

Since;

c= λ f and c= 3×10^8 ms-1

f= c/λ

f= 3×10^8/5.5 × 10^-10

f= 5.5×10^17 Hz

The electromagnetic wave is visible light

Answer:

1. Atomic number

2. element symbol

3. element name

4. atomic mass

5 and 6 are the same as the diagram above... just rewrite using data

Answer:

10000

Explanation:

10 to the 5th power

Answer: E = 11.8 N/C

Explanation: Electric field is electric force per unit of charge or

\(E=\frac{F}{q}\)

F is electric force calculated as:

\(F=\frac{kQq}{r^{2}}\)

Electric field will be:

\(E=\frac{kQq}{qr^{2}}\)

\(E=\frac{kQ}{r^{2}}\)

where k is coulomb constant and is approximately \(9.10^{9}\frac{Nm^{2}}{C^{2}}\)

Changing units to match the constant:

38pC = \(38.10^{-12}\)C

17cm = \(17.10^{-2}\)m

So, electric field for bees in the given conditions is:

\(E=\frac{9.10^{9}.38.10^{-12}}{(17.10^{-2})^{2}}\)

\(E=\frac{342.10^{-3}}{289.10^{-4}}\)

E = 11.8N/C

The smallest external electric field to which bees nay be sensitive is 11.8N/C

Answer:

\(g=274\ m/s^2\)

Explanation:

Mass of the Sun, \(M=1.99\times 10^{30}\ kg\)

The radius of the Sun, \(r=6.96\times 10^8\ m\)

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

\(g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2\)

So, the value of acceleration due to gravity on the Sun is \(274\ m/s^2\).

The acceleration due to gravity, in meters per second squared, on the surface of the Sun is \(296.88 \;m/s^2\).

Given the following data:

Gravitational constant = \(6.67 \times 10^{-11}\)

To calculate the acceleration due to gravity, in meters per second squared, on the surface of the Sun:

From the law of gravitational force, we have the formula:

\(g = \frac{Gm}{r^2}\)

Where:

Substituting the given parameters into the formula, we have;

\(g = \frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30}}{(6.69 \times 10^8)^2} \\\\g= \frac{1.33 \times 10^{20} }{4.48 \times 10^{17}} \\\\g=296.88 \;m/s^2\)

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Answer:

4417

i think because

mv^2/r is centripetal force

Answer:

false

Explanation:

Because the sun has ultraviolet rays

Answer:

False.

Explanation: The sun is mainly composed of hydrogen, it's 92% composed of hydrogen.

Answer:

Explanation:

a. The compact car going 70 MPH has more kinetic energy than the tractor trailer going 15 MPH. Kinetic energy is proportional to the square of the velocity, so even though the tractor trailer may have more mass, the higher velocity of the compact car results in greater kinetic energy.

b. The SUV and the pickup truck have the same kinetic energy since they have the same mass and velocity.

c. The compact car going 45 MPH has the most kinetic energy since it has the highest velocity out of the three vehicles. The SUV going 35 MPH has less kinetic energy, and the school bus going 15 MPH has the least kinetic energy.

The flux through the circle loop of wire is determined as 7.96 N/C.m².

The flux through the circle loop of wire is calculated by applying the following formula.

Ф = EA cosθ

where;

The area of the wire is calculated as follows;

A = πr²

A = π (2 m)²

A = 12.57 m²

The flux through the circle loop of wire is calculated as;

Ф = EA cosθ

Ф = 1.5 x 12.57 x cos (65)

Ф = 7.96 N/C.m²

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Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.

The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.

In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.

By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.

By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.

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Answer:

n = 1.31

Explanation:

        \(n_{i} * sin( \theta_{i}) = n_{r} * sin( \theta_{r}) (1)\)

       \(n_{r} =\frac{n_{i} * sin \theta_{i} }{sin \theta_{r} } = \frac{sin (45)*1.52}{sin (55)} = 1.31 (2)\)

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

  I = 0.160 A

Explanation:

For this exercise we must calculate the power supplied to the motor

power is the work done between the time interval

      P = W / t

      W = F x

      P = \(\frac{F \ x}{t}\)

the force is

       F = ma

let's use kinematics

       v = v₀ + a t

as part of rest v₀ = 0

       a = v / t

       a = 1.81 / 7.15

       a = 0.253 m / s

therefore the applied force is

       F = m a

       F = 0.836 0.253

       F = 0.212 N

to calculate the work, let's find the distance traveled

       x = v₀ t + ½ a t²

       x = 0+ ½ a t²

       x = ½ 0.253 7.15²

       x = 6.457 m

therefore The power developed in this movement by the motor

       P = 0.212  6.457/7.15

       P = 0.19145 W

Let's use a direct proportion rule. If the for a supplied power of Ps = 1W to use 0.471W, what power is united when the effective is 0.19145 W

       P_s = 0.19145 W (0.471W/1W)

       P_s = 0.4786 W

       P_s = 0.479 W

how electrical power is

       P = I V

we assume that the batteries are not discharged during the experiment

        I = P / V

electrical power equals supplied power

        P = Ps

calulate

        I = 0.479 / 3.00

        I = 0.1597 A

        I = 0.160 A

The ratio of power delivered to the electric potential is equal to the average current flow.

The required magnitude of the average current supplied to the car's motor is 0.064 A.

The amount of electric charges passing through a specific point in a certain period of time is known as an average current.

Given data -

The mass of the toy car is, m = 0.836 kg.

The combined electric potential of two cells is, V' = 3.00 V.

The energy conversion efficiency is, \(\eta =47.1 \%\).

The time interval is, t = 7.15 s.

The final speed of car is, v = 1.81 m/s.

The power produced by the two cell is,

P = W / t

P = (F × d)/t

Here,

F is the force exerted on the toy car.

d is the distance traveled by car in the given time interval.

The magnitude of the force is given as,

F = ma

here, a is the magnitude of acceleration.

Now, using the first kinematic equation of motion as,

v = v₀ + a t

As part of rest v₀ = 0

a = v / t

a = 1.81 / 7.15

a = 0.253 m / s²

Therefore the applied force is

F = m a

F = 0.836 × 0.253

F = 0.212 N

To calculate the work, let's find the distance traveled from the second kinematic equation of motion,

d = v₀ t + ½ at²

d = 0+ ½ a t²

d = ½ 0.253 7.15²

d = 6.457 m

Finally, the power developed in this movement by the motor is,

P = (0.212 × 6.457)/7.15

P = 0.19145 W

Now, the expression for the power developed is also given as,

P = V × I

Here,

I is the magnitude of the average current.

Solving as,

I = P / V

I = 0.19145/3.00

I = 0.064 A

Thus, we can conclude that the required magnitude of the average current supplied to the car's motor is 0.064 A.

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When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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