How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant figures in all numbers. Be sure to include the zero before the decimal if the number is less than one.

Answers

Answer 1
Answer:

0.0253 mol H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 0.456 g H₂O (water)

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

[DA] Set up:                                                                                                     \(\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})\)[DA] Multiply/Divide [Cancel out units]:                                                          \(\displaystyle 0.025305 \ mol \ H_2O\)

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.025305 mol H₂O ≈ 0.0253 mol H₂O


Related Questions

what effect does a catalyst have on a reaccion rate an the products formed in a reaccion

Answers

A catalyst will speed up the activation energy and therefore speed up the reaction. The products will form fast because of this.

What is the correct mole to mole ratio for Aluminum to Aluminum chloride in the following reaction: 2Al + 3Cl2 --> 2AlCl3
2 ;2

3 ; 2

2 ; 3

6 ; 2

Answers

Answer:

3;2

Explanation:

What problems might there be if oxygen was very soluble in water?​

Answers

There is a lot of water on earth. If oxygen was very soluble in water, the oceans would absorb and hold the oxygen of the atmosphere and there would be none left for plants and animals.

Hope this help you!!

Water can dissolve oxygen gas. The oxygen that is dissolved in water is used for respiration by plants and animals that dwell in water. Therefore, oxygen gas that has been dissolved in water is crucial for the survival of aquatic creatures and plants.

What is respiration ?

During respiration, carbon dioxide is expelled in the opposite direction, back into the environment, while oxygen is moved from the outside environment to the cells within tissues.

The oxygen molecules become trapped between the open spaces between the water molecules as a result of the creation of hydrogen bonds. Water is a polar solvent, as is well known.

Additionally, the oxygen molecules have pi-electrons, which give them a certain amount of polarity because they are sensitive to polar environments.

The majority of aquatic creatures need oxygen for respiration, and our aquatic ecosystems are at risk if there is an oxygen shortage in the water.

Thus, The oxygen that is dissolved in water is used for respiration by plants and animals that dwell in water.

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if ethanol is replaced by acetic acid would you expect the same change?

Answers

Explanation:

no because they have different functional group

Guysss how to explain nuclear chemistry? And define nuclear chemistry ?

Answers

Answer:

How do amoeba respire.

Define Diffusion.

Which element has the LARGEST atomic radius?
Be
Ca
Ba
Sr

Answers

Answer:

none

Explanation:

it's Fr. which is francium.

Explanation:

An atomic radius is defined to be one-half the distance between the nuclei of two atoms, assuming a spherical atom since, according to the quantum mechanical model of the atom, electrons are located within a probability cloud surrounding the nucleus which has no sharp boundary.

Notice that, in general, there are two main trends of atomic radii in the Periodic Table of Elements.

The first trend illustrates that atomic radii increase when going down a group in the periodic table. This is because when moving downwards in a group, every subsequent atom gains an additional principal energy level, which leads to electron shielding. Electron shielding refers to the decreased attraction between the electrons that occupy the higher principal energy level and the nucleus of the atom due to the shielding of electrons in the lower principal energy level.

The second trend outlines that atomic radii decrease when going across the period from left to right. For elements within a period, individual electrons occupy the same principal energy level. Likewise, when an electron is added, a new proton is also added to the nucleus, providing the nucleus with a stronger positive charge and hence leading to a higher effective nuclear charge. This increase in nuclear attraction pulls the electrons closer towards the nucleus, leading to a decrease in atomic radius.

Therefore, given the option between beryllium, calcium, barium, and strontium, the element with the largest atomic radius is barium since all the elements given are in Group II, however, barium is the element furthest down the group and therefore have electrons occupying the highest principal energy level compared to other elements.

Lithium reacts with chlorine to form a new substance.What other element will also with chlorine to form a new substance with similar properties?
a) Flourine
b) Argon
c) Potassium
d) Carbon
HELP ILL NAME YOU THE BRAINLIEST!!!

Answers

Answer:

Flourine

Explanation:

Chlorine is a member of the halogen family. Halogens are the elements that make up Group 17 (VIIA) of the periodic table, a chart that shows how elements are related to one another. They include fluorine, bromine, iodine, and astatine.

Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y , respectively?

Answers

From the solution that we have in the question;

The concentration of X and Y is 0.28 MThe concentration of XY is  0.32 MWhat is the equilibrium constant?

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

A 0.28 M concentration of X and Y exists at equilibriumXY's concentration at equilibrium is 0.32 M.

The equilibrium constant

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY,

what is chemistry...
jab-njko-rzv​

Answers

Answer:

Chemistry is the science of matter, its properties, structure, changes or reactions and the energy that accompanies these changes.

Acrylonitrile, C3H₂N, is a molecule used to produce a plastic called Orlon. How many grams of acrylonitrile
could be produced by reacting 583 g of propene, C3H, with excess ammonia, NH, and oxygen?
2C3H6+ 2NH3 + 30₂ → 2C,H₂N + 6H₂O

a. 368 g
b. 1470 g
C. 462 g
d. 735 g
e. 583 g

Answers

d. 735 g of acrylonitrile could be produced by reacting 583 g of propene, \(C_{3}H\), with excess ammonia, NH, and oxygen

To determine the grams of acrylonitrile that could be produced, we need to find the limiting reactant in the given chemical equation. The limiting reactant is the one that is completely consumed and determines the amount of product formed.

First, we need to calculate the molar masses of propene (\(C_{3}H_{6}\)) and acrylonitrile (\(C_{3}H_{2}N\)).

Molar mass of propene (\(C_{3}H_{6}\)):

3(C) + 6(H) = 3(12.01 g/mol) + 6(1.01 g/mol) = 42.09 g/mol

Molar mass of acrylonitrile (\(C_{3}H_{2}N\)):

3(C) + 2(H) + 1(N) = 3(12.01 g/mol) + 2(1.01 g/mol) + 1(14.01 g/mol) = 53.06 g/mol

Next, we calculate the number of moles of propene:

583 g / 42.09 g/mol = 13.86 mol

According to the balanced equation, the stoichiometric ratio between propene and acrylonitrile is 2:2. Therefore, for every 2 moles of propene, 2 moles of acrylonitrile are produced.

Since the stoichiometric ratio is 1:1, the number of moles of acrylonitrile produced is also 13.86 mol.

Finally, we calculate the mass of acrylonitrile:

Mass = moles × molar mass = 13.86 mol × 53.06 g/mol = 735 g

Therefore, Option D is correct.

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What is an example of microorganisms acting in a harmful way?

Answers

Answer:

Mark me as brainlest

Explanation:

Microorganisms present in our body Re viruses, bacteria, fungi, algae, and protozoa among which most of them cause immense benefits to the body. There are some harmful microorganisms too known as pathogens which cause disease and cause a threat to all existing life forms of the earth which can result in death at times.

Answer:

An example of microorganisms acting in a harmful way is a bacteria spoiling food.

How many grams of a 12.5 % sugar solution contain 56.0 g of sugar?

Answers

Considering the definition of percentage by mass, 448 grams of a 12.5 % sugar solution contain 56.0 g of sugar

Percentage by mass

The percentage by mass expresses the concentration and is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage:

percent by mass= (mass of solute÷ mass of solution)×100%

Mass of sugar solution

In this case, you know:

percent by mass= 12.5%mass of sugar= 56 gmass of solution= ?

Replacing in the definition of percent by mass:

12.5%= (56 g÷ mass of solution)×100%

Solving:

12.5%÷ 100%= 56 g÷ mass of solution

12.5%÷ 100%= 56 g÷ mass of solution

0.125= 56 g÷ mass of solution

0.125× mass of solution= 56 g

mass of solution= 56 g÷ 0.125

mass of solution= 448 g

Finally, the mass of solution is 448 grams.

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sample gas has a pressure of 6.8 kPa at 539K. If the temperature decreases to 211K, then what will be the new pressure?

Answers

Gay-Lussac's Law-

\( \:\:\:\:\:\:\star\longrightarrow \underline{\sf \boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}}\)

\( \:\:\:\:\:\:\star\longrightarrow \sf \underline{P_2=\dfrac{P_1 \:T_2}{T_1}}\)

Where-

P₁ is the initial pressure.T₁ is the initial temperatureP₂ is the final pressure.T₂ is the final temperature  

As per question, we are given -

P₁ = 6.8 KPaT₁ =539 KT₂= 211K

Now that we are given all the required values, so we can put them into the formula and solve for P₂:-

\( \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{P_1 \:T_2}{T_1}\\\)

\( \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{6.8\times 211}{539}\\\)

\(\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf P_2 = \dfrac{1434.8}{539}\\\)

\( \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2 = 2.661966.........\\\)

\(\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf\underline{ P_2 = 2.7 \:KPa}\\\)

Therefore, If the temperature decreases to 211K, then the new pressure will become 2.7 KPa.

Pewter is a solidified solution of tin and lead or tin and zinc. In both cases, tin is the main component. Which metal would you classify as the solute in each type of pewter?

Answers

Low quality pewter is tin, lead and a small amount of copper. In higher quality pewter, antimony or bismuth is used instead of lead. Pewter alloyed with antimony and bismuth can be polished to a bright, tarnish free finish. The alloying metals lower the melting temperature of tin, making it possible to cast molten alloy into detailed shapes.

why must you replace the lids of chemicals immediately​

Answers

All bottles/containers need to be closed immediately to avoid any degradation of the chemicals or reactions.

An analytical chemist is titrating 60.5mL of a 0.8700M solution of benzoic acid HC6H5CO2 with a 0.3600M solution of KOH . The pKa of benzoic acid is 4.20 . Calculate the pH of the acid solution after the chemist has added 172.mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places.

Answers

Answer:

The correct answer is 12.6.

Explanation:

The formation of benzoate takes place when potassium hydroxide reacts with benzoic acid, due to the presence of a weak acid and its conjugated base the solution will act as a buffer. In the given question, the molarity of benzoic acid given is 0.8700 M and its volume is 60.5 ml. Therefore, the moles of benzoic acid will be,  

Moles = molarity * volume of solution  

= 0.8700 M * 60.5 ml = 52.365 m mol or 0.052365 moles

On the other hand, the molarity of KOH given is 0.3600 M and the volume given is 172 ml. Therefore, the moles of KOH added will be,  

Moles = 0.3600 * 172 = 61.92 m moles or 0.06192 moles

Out of this 61.92 m mol, only 52.365 m mol of KOH will react with the benzoic acid. The moles of KOH, which remain unreactive is,  

61.92 m moles - 52.365 m moles = 9.285 m moles or 0.009285 moles

The formula for calculating molarity is number of moles / volume of solution in liters

The total volume of the solution is 172 ml + 60.5 ml = 232.5 ml or 0.2325 L

The molarity of KOH will be,  

Molarity = 0.009285 moles / 0.2325 L = 0.0395 M

The dissociation of KOH takes place completely to produce hydroxide ion.  

pOH = -log[0.0395] = 1.4

pH + pOH = 14

pH = 14 - 1.4 = 12.6

give an example of coupling reaction​

Answers

Answer:

An example is the formation of ATP, which is an endergonic process and is coupled to the dissipation of a proton gradient.

Explanation:

Hope this helped!

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Calcium nitrate- make an evidence based argument for why acid rain would cause the calcium carbonate in the marble to slowly break down and wash away over time when calcium nitrate is produced

Answers

Following are the effects of acid rain.

What is Acid Rain?

Acid rain is caused by the accumulation of nitric and sulfuric acids in the atmosphere. These compounds are strong acids and are very soluble in water, dissolving in droplets in clouds.

Limestone effect:

Calcium carbonate, [Ca][CO3], is a very common mineral. A limestone is a well-known form of calcium carbonate. The acid contained in acid rain reacts with carbonate ions and promotes the dissolution of calcium carbonate.

This will create a bicarbonate solution. The presence of limestone and other calcium carbonates in lakes and streams helps maintain a constant pH as the mineral reacts with excess acidity. However, acid rain can eventually exceed the buffering capacity of surface waters.

How does acid rain affect buildings made of marble and limestone?

It is mainly affected in 2 ways: dissolution and alteration. Calcite dissolves when sulfuric, sulfuric and nitric acids in polluted air react with calcite in marble and limestone. Exposed areas of buildings and statues show rough surfaces, worn materials, and loss of sculptural detail. Stoneface material can be lost anywhere or only in more reactive areas.

Hence, this is how acid rain affects.

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What is the pH of 6.00 M H2CO3 if it has 7% dissociation? SHOW YOUR WORK!!!

Answers

From the calculation, the pH of the solution can be obtained as 0.39.

What is the pH of the solution?

We first have to obtain the dissociation constant of the solution;

α = √Ka/C

Ka = Cα^2

Ka = 4.9 * 10^-3 * 6

Ka = 0.0294

Then we have that;

0.0294 = [x]^2/[6 - x]

0.0294 * [6 - x] = x^2

0.1764 - 0.0294 x = x^2

x^2 +  0.0294 x - 0.1764 =0

x = 0.41 M

Thus the pH of the solution is;

pH = -log[0.41]

= 0.39

pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.

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Which soil horizon contains the most organic matter?

A horizon
B horizon
C horizon
D horizon

Answers

Answer:

I- It says horizon so.....what....wth ._.

Explanation:

The gas tank of car hold 22.3 gallons.If the density of gasoline is 0.8206g/mL,determine the massin kilograms and pounds of the fuelin a full truck

Answers

Density = mass/Volume    or    D = m/V  

Given:  V = 22.3 gal

           D = 0.8206 g/mL

1)  Rearrange the equation to solve for m

2)  Find conversion factor(s) and convert V from gal to mL (by dimensional analysis) so the units cancel

3)  Solve for m in g

4)  Find conversion factor(s) and convert m from g → lbs

1)  D = m/V  rearranges to  m = D ∗ V

2)  1 gal = 3.785 L  and  1 L = 1000 mL;     22.3 gal  ∗  3.785  L/1 gal  ∗  1000 mL/1 L   =  84 406 mL

3)  m =  0.8206 g/mL  ∗  84 406 mL    =  69 260 g

4)  1 lb = 453.6 g;   69 260  g  ∗  1 lb/453.6 g   =  153 lbs

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Calculate (a) the pH of a 0.0250 M solution of phenylacetic acid, and (b) the pH of a 0.0500 M solution of sodium phenylacetate. The pKa of phenylacetic acid is 4.31, and its structure is shown below.

Calculate (a) the pH of a 0.0250 M solution of phenylacetic acid, and (b) the pH of a 0.0500 M solution

Answers

Answer:

Explanation:cool thre answer is 009000000000.1 because you have to add them so ye

1. Write the IUPAC names for the following 1.1 1.2 N 1.3 O NO2 x Y ·0 OH 5​

Answers

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

The bright coloring of the skin of this poison dart frog announces, "Don't eat me! My
skin is poisonous."
This is an example of an adaptation that meets the challenge of...
maintaining structure
reproduction.
getting and using energy

The bright coloring of the skin of this poison dart frog announces, "Don't eat me! Myskin is poisonous."This

Answers

Getting and using energy

If 765 mL of a gas at 2.78 atm, has the volume Change to 2.47 L , What is the pressure of the
gas in atm?

Answers

Answer:

0.87 atm

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the new pressure

\(P_2 = \frac{P_1V_1}{V_2} \\\)

From the question

2.47 L = 2470 mL

We have

\(P_2 = \frac{765 \times 2.78}{2470} = \frac{2142}{2470} \\ = 0.867206...\)

We have the final answer as

0.87 atm

Hope this helps you

you are given a 1.50 g mixture of sodium nitrate and sodium chloride. you dissolve this mixture into 100ml of water and then add excess of 0.500M silver nitrate solution. you produce a white solid, which you then collect, dry and measure. of u had am extremely magnified view of the solution ( to the atomic molecular level) list the species you would see(include changes, if any). write tje balanced net ionic equation for the reaction that produces the solid. include phases and charge. calculate the percent sodium chloride in the original unknown mixture.

Answers

When the 0.500 M silver nitrate solution is added to the 1.50 g mixture of sodium nitrate and sodium chloride in water, a reaction occurs.

What is the balanced ionic equation and percent sodium chloride in the mixture?

When the 0.500 M silver nitrate solution is added to the mixture of sodium nitrate and sodium chloride, the following reaction takes place:

NaNO₃(aq) + AgNO₃(aq) → AgNO₃(s) + NaNO₃(aq)

NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)

The solid produced is silver chloride (AgCl), which is a white precipitate.

At the atomic/molecular level, the following species would be seen:

   Sodium ions (Na⁺) and nitrate ions (NO₃⁻) from sodium nitrate (NaNO₃)    Sodium ions (Na⁺) and chloride ions (Cl⁻) from sodium chloride (NaCl)    Silver ions (Ag⁺) and nitrate ions (NO₃⁻) from silver nitrate (AgNO₃)    Solid silver chloride (AgCl)

To calculate the percent sodium chloride in the original unknown mixture, we need to know how much of the white solid we collected. Let's assume we collected 2.00 g of silver chloride.

We need to compute the number of moles of silver chloride produced:

2.00 g AgCl x (1 mol AgCl/143.32 g AgCl) = 0.01395 mol AgCl

Since silver nitrate is in excess, all the chloride ions in the original mixture will react with silver ions to form silver chloride. The number of moles of chloride ions in the original mixture is therefore equal to the number of moles of silver chloride produced:

0.01395 mol Cl- = 0.01395 mol NaCl

To calculate the percent sodium chloride in the original mixture, we need to know the total mass of the mixture:

1.50 g NaNO₃ + NaCl = 1.50 g

The percent sodium chloride is:

(0.01395 mol NaCl x 58.44 g/mol NaCl) / 1.50 g x 100% = 54.4% NaCl

Therefore, the original mixture was 54.4% sodium chloride and 45.6% sodium nitrate.

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DDT, an insecticide harmful to fish, birds and humans, is produced by the following

reaction

2C6H5Cl + C2HOCl3 → C14H9Cl5 + H2O

Chlorobenzene Chloral DDT

In a government lab, 1142 g chlorobenzene is reacted with 485 g of chloral.

a) What mass of DDT is formed?

b) Which reactant is limiting? Which is in excess?

c) What mass of the excess reactant is left over?

d) If the actual yield of DDT is 200 g, what is the percent yield?

2. An element consists of 1.40% of an isotope with mass 203.973 amu, 24.10% of an

isotope with mass 205.9745 amu, 22.10% of an isotope with mass 207.9766 amu.

Calculate the average atomic mass and identify the element

3. Calculate the concentration of all ions present in each of the following solutions of

strong electrolytes

a) 0.100 mol of Ca(NO3)2 in 100 mL of solution

b) 2.5 mol Na2SO4 in 1.28 M of solution

c) 4.00 g K3PO4 in 150.0 mL of solution

4. A balloon is filled to a volume of 6.00 x 102 mL at a temperature of 19.0oC . The

balloon is then cooled at constant pressure to a temperature of 100 K. What is the

final volume of the balloon?

5. If 14.0 g AgNO3 is available, what volume of 0.27 M AgNO3 can be prepared?

6. Maleic acid is an organic compound composed of 41.39% C, 3.47% H, and the rest

oxygen. If 0.129 mol maleic acid has a mass of 15.0 g, what are the empirical and

molecular formulas of maleic acid?

7. An 13.6 L sample of gas is determined to contain 0.80 mol Ar. At the same

temperature and pressure, how many moles of gas would there be in a 45L sample?

8. Write the balanced formula, complete ionic, and net ionic equations for each of the

following acid-base reactions.

a) HNO3(aq) + Al(OH)3(S) →

b) HC2H3O2 (aq) + KOH(aq) →

9. Balance each of the following oxidation-reduction reactions in acid solution

a) Cl2(g) + Al (s) → Al3+

(aq) + Cl-

(aq)

b) MnO-

4(aq) + Pb2+

(aq) → Mn2+(aq) + Pb4+(aq)

10. Balance the oxidation-reduction reaction in basic solution

Br2(g) + Sn (s) → Sn2+ (aq) + Br-

(aq)​

Answers

Answer:

answer is letter B I did it

4.) What % of the original atoms remained after 8 trials?

Answers

The remaining percentage of the original radioactive atoms is 321100=3. 125%.

What percentage of radioactive substance remains after ten half-lives?We have 12.5 percent left after another six hours. Only 0.1% of the radioactivity is left after ten half-lives. Three different half-lives are available.More than 99 percent of an atom's volume is actually empty space when protons, neutrons, and electrons are taken into account.According to current estimates, hydrogen makes up 90% of all atoms in the universe and is crucial to the existence of the material world.Therefore, 50% of the original parent nuclei are still there after one half-life; 25% are still present after two half-lives; and so on. A radioactive source's half-life and the initial quantity of radioactive atoms present affect the radiation's intensity.

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Do you feel that products containing organic solvents should be more tightly regulated and controlled than they are now ? Why or why not?

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When handling solvents, the following precautions should be carried out:Store solvents in strong, sealed containers.Clearly identify and labels the containers.Establish procedures and evacuation routes in case of a fire or a solvent spill.Wear protective clothing.Use a respirator.

Yes, I think that it should be more tightly packed than now and it should be made with tight and strong substance which can't be torn easily.

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