(1) SEP Construct an Explanation A common mistake when balancing
equations is to change the subscripts instead of the coefficients. For
example, a person might try to balance the reaction H₂ + O₂ → H₂O by
changing one subscript in the products: H₂ + O₂ → H₂O₂. Explain how
changing the subscript makes the equation incorrect.
Answer:
Changing the subscripts in a chemical equation changes the identity and number of atoms in the molecules involved, which makes the equation incorrect. In the example given, changing the subscript in the product side of the equation from 1 to 2 results in the formation of hydrogen peroxide (H2O2) instead of water (H2O).
The equation H₂ + O₂ → H₂O₂ represents the reaction between hydrogen gas and oxygen gas to form hydrogen peroxide. However, this reaction is not balanced because the number of oxygen atoms on the product side is not equal to the number of oxygen atoms on the reactant side. In the reactant side, there are two oxygen atoms, while in the product side, there are two hydrogen atoms and two oxygen atoms. Therefore, this equation is incorrect and cannot be balanced by simply changing the subscripts.
To balance the equation correctly, coefficients should be added to the molecules to represent the number of atoms involved. For example, the balanced equation for the reaction between hydrogen gas and oxygen gas to form water would be:
2H₂ + O₂ → 2H₂O
This equation represents the balanced reaction where two molecules of hydrogen gas (H2) react with one molecule of oxygen gas (O2) to form two molecules of water (H2O), with equal numbers of atoms of each element on both sides of the equation.
1. Consider the reaction: 5 A + 3 B → 2 C The rate of the reaction is found to be 0.0486 M/s. What is the rate of change of B? Be sure to consider whether the substance is disappearing or appearing in your answer.
2. For the following zero order reaction, the rate constant is 0.0311. If [A]0 = 8.68, calculate [A] at 2.9 seconds.
2 A →→ 3 B
1. Consider the reaction: 5 A + 3 B → 2 C The rate of the reaction is found to be 0.0486 M/s. Then, The rate of change of B is 0.01215 M/min.
2. For the following zero order reaction, the rate constant is 0.0311.
If [A₀] = 8.68, calculate [A] at 2.9 seconds. Then, [A] = 8.66445 ≈ 8.7.
(1) For Reaction : 5A + 3B → 2C
R₁ : 0.080486 M/s = K[A][B]² ---------------------- (1)
When half of the B has reacted, then,
⇒ R₂ = k[A][B/2] -------------------------- (2)
Dividing (2) and (1), we get:
R₂÷ R₁ = K[A] [B/2] ÷ K[A] /[B]
⇒ R₂÷ R₁ = B²/4 ÷ B²
⇒ R₂÷ R₁ = 1/4
Therefore,
R₁ /4 = 0.0486/ 4
= 0.01215 M/minute.
Therefore,
Consider the reaction: 5 A + 3 B → 2 C The rate of the reaction is found to be 0.0486 M/s. Then, The rate of change of B is 0.01215 M/min.
(2) For a Zero Order reaction:
t = K[A₀] [A] ÷ K ------------------------- (1)
Given that:
t = 2.9 Second
and, k = 0.0311
Converting Seconds into minutes:
t = 2.9 second = 0.048 Minutes ≈ 0.5 Minutes.
Putting the values in equation (1)
⇒ 0.5 = 8.68 - [A] ÷ 0.0311
⇒ 0.5 × 0.0311 = 8.68 - [A]
⇒ 0.01565 - 8.68 = - [A]
⇒ [A] = 8.66445
Therefore, [A] = 8.66445 ≈ 8.7
Based on the zero order reaction, the rate constant is 0.0311. If [A]0 = 8.68, calculate [A] at 2.9 seconds. Then, [A] = 8.7
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For SCl4, the electron domain geometry is _______(i)________ and the molecular geometry is ______(ii)________.
The electron domain geometry is trigonal bipyramidal while the molecular geometry of the compound is seesaw.
The shapes of molecules is determined by the number of electron pairs on the valence shell of the central atom in the molecule. These electron domains include lone pairs and bond pairs.
The lone pairs only contribute towards the electron domain geometry and not the molecular geometry. SCl4 has five electron domains hence its electron domain geometry is trigonal bipyramidal. The molecular geometry of the compound is seesaw.
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Which one of these is the odd one out? Iron, tin lithium or golf
The odd one among the options listed is golf because it is not an element (option D).
What are chemical elements?Chemical elements in chemistry are one of the simplest chemical substances that cannot be decomposed in a chemical reaction.
Chemical elements consist of atoms which have the same number of protons. The chemical elements are arranged on the periodic table in accordance with their atomic numbers.
There are a total number of 118 chemical elements in nature. The periodic table uses abbreviated chemical symbols in place of full element names, for example, Copper is symbolized using Cu while pottasium is symbolized using K.
Golf is a ball game played by individuals competing against one another in which the object is to hit a ball into each of a series of (usually 18 or nine) holes in the minimum number of strokes.
Golf is a sport, hence, is the odd one among the other options which are chemical elements.
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Which of these statements accurately describes monomers?
Monomers are macromolecules.
Monomers contain double bonds.
Monomers are made of repeating units.
Monomers contain bonds between metals.
Answer:
Monomers contain bonds between metals
Answer:
B: Monomers contain double bonds
Explanation:
I got it right on Edge
in 3.50 mol of iron, Fe, there are ___ atoms of iron
3.50 mol of iron contains roughly 2.11 x 10²⁴ iron (Fe) atoms.
To determine the number of atoms of iron (Fe) in 3.50 mol, we can use Avogadro's number, which is defined as the number of particles (atoms, molecules, or ions) in one mole of a substance. Avogadro's number is approximately 6.022 x 10²³ particles per mole.
To calculate the number of atoms of iron in 3.50 mol, we can use the following equation:
number of atoms = number of moles x Avogadro's number
Plugging in the given values, we get:
number of atoms = 3.50 mol x 6.022 x 10²³ atoms/mol
Simplifying this expression, we get:
number of atoms = 2.11 x 10²⁴ atoms
Therefore, there are approximately 2.11 x 10²⁴ atoms of iron (Fe) in 3.50 mol of iron.
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PLS HELP I NEED ASAP
what is the slowest speed for an object to escape the gravitational attraction of a celestial body (planet, moon, etc.)?
Answer:
the escape velocity
Explanation:
To do this, your rock has to go very fast – more than 11 kilometers per second. This velocity is called the escape velocity, the speed an object must achieve in order to overcome the gravitational attraction of a celestial body (be it a planet, a star, or a galaxy) and escape into space
found it online, lol better then nothing
ischemic strokes are the most common type of stroke and account for about ____ of all strokes.
Ischemic strokes are the most common type of stroke and account for about 87% of all strokes.
An ischemic stroke occurs when there is a blockage in the blood vessels supplying blood to the brain. This blockage is usually caused by a blood clot or a build-up of fatty deposits (atherosclerosis) inside the blood vessels, which restricts blood flow to the brain.
When blood flow to the brain is reduced or stopped, the brain cells in the affected area do not receive the oxygen and nutrients they need to function properly, resulting in damage or death of these cells. The severity of an ischemic stroke depends on the size and location of the blockage, as well as the duration of the blood flow interruption.
There are two main types of ischemic strokes: thrombotic and embolic. Thrombotic strokes are caused by a blood clot (thrombus) that forms within a blood vessel in the brain, while embolic strokes are caused by a blood clot or other debris (embolus) that forms elsewhere in the body and travels to the brain.
Immediate treatment for ischemic strokes typically involves medications to break up or remove the clot and restore blood flow to the brain. Early intervention is crucial to minimize brain damage and improve the chances of a full recovery.
Preventing ischemic strokes involves managing risk factors, such as high blood pressure, high cholesterol, smoking, obesity, and diabetes, through lifestyle modifications and medical management as needed.
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What mass of Cl2, in grams is contained in a 10.0L tank at 27oC and 3.50 atm pressure ? a. 1.42 grams b. 142 grams c. 1.01 kg d. 101 grams
Answer:
the correct answer is A
Explanation:
if 3 moles of solid nah2po4 is added to 1 l of 2 m phosphoric acid, what will be resulting value of ph? the pkas of phosphoric acid are 2.1, 7.2, 12.4, and ka1
The resulting pH value is 2.276.
To calculate the resulting pH value, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
In this case, we are using the first dissociation of phosphoric acid (H3PO4 → H+ + H2PO4-), so we will use the first pKa value (2.1) and the concentrations of H2PO4- ([A-]) and H3PO4 ([HA]).
First, we need to calculate the concentration of H2PO4- and H3PO4. The concentration of H2PO4- is equal to the number of moles of NaH2PO4 divided by the volume of the solution:
[H2PO4-] = 3 mol / 1 L = 3 M
The concentration of H3PO4 is equal to the initial concentration of phosphoric acid:
[HA] = 2 M
Now we can plug these values into the Henderson-Hasselbalch equation:
pH = 2.1 + log(3/2)
pH = 2.1 + 0.176
pH = 2.276
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How many moles are in 5.12 × 10³ F atoms?
Answer in units of mole
The number of moles in 5.12 × 10³ Fluorine(F) atoms is 8.45 × 10 ‐ ²³ moles.
The moles is defined as the measurement of the amount of any substance. Its is the measure of the amount of elementary particles in a substance. One mole is numerically equal to 6.023 × 10²³ which is called Avogadro's number.
From Periodic Table, we can find that Molecular Weight of Fluorine(F) is 19. We know the Molar Weight of any element is numerically equal to its Molecular Weight i.e. numerically, Molecular Weight = Molar Weight of any matter.
The number of moles in 5.12 × 10³ Fluorine(F) atoms will be calculated as: (5.12 × 10³) / (6.023 × 10²³) = 8.45 × 10 ‐ ²³ moles
So, there are approximately 8.45 x 10^-23 moles in 5.12 × 10³ atoms of Fluorine.
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The resistance of a thermometer is 5 ohm at 25 degree Celsius and 6 2 at 50 degree Celsius. Using linear approximation, calculate the value of resistance temperature coefficient at 45 degree Celsius.
The approximate resistance value at 45 degrees Celsius is around 5.8 ohms.
To calculate the value of the resistance temperature coefficient at 45 degrees Celsius using linear approximation, we can use the formula:
R(T) = R0 + α(T - T0),
where R(T) is the resistance at temperature T, R0 is the resistance at a reference temperature T0, α is the resistance temperature coefficient, and (T - T0) is the temperature difference.
Given that the resistance at 25 degrees Celsius is 5 ohms (R0 = 5) and the resistance at 50 degrees Celsius is 6 ohms (R(T) = 6), we can calculate the value of α.
6 = 5 + α(50 - 25),
Simplifying the equation:
1 = 25α,
Therefore, α = 1/25 = 0.04 ohm/degree Celsius.
Using the linear approximation, we can approximate the value of the resistance at 45 degrees Celsius:
R(45) = 5 + 0.04(45 - 25) = 5 + 0.04(20) = 5 + 0.8 = 5.8 ohms.
Therefore, the value of the resistance at 45 degrees Celsius is approximately 5.8 ohms.
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What electrical charges do these parts have ?
Answer:
which parts electrical charges you are asking ??
how do forces between particles affect the properties of materials
Answer:
force is you can force it in how it do
199." one mola of any gas at
STP equals 22.4 L of
that
gas. It is also true the different Elements have
different atomic volumes, or diamatws. How can you
reconcile these two Statements
Answer:
all statements are true but scientifically depending on some assumptions
Explanation:
Each element has it's own atomic number that determine how electrons are distributed in shells. the more the shells of electrons, the bigger the atomic radius. Therefore the actual space occupied by an atom of an element fully depends on its atomic number
From the findings of Van Der Waal, the actual space occupied by a gas is less than the volume of the container. Reasons being the magnitude of the intermolecular forces between the gas molecules and volume of the molecules being almost negligible to the volume of the container
Please help me with this! I’ll mark you brainiest if it’s correct.
I do know it’s either A or C
Answer:
the correct answer is A
Explanation:
For a light with a wavelength of 680 nm, how much is the energy contained in one mole photons of the same light
The energy contained in one mole of photons of light with a wavelength of 680 nm is 1.76 x 10^5 J/mol.
To calculate the energy contained in one mole photons of light with a wavelength of 680 nm, we need to use the following formula:
E = hc/λ
where E is the energy of one photon, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of the light (680 nm or 6.8 x 10^-7 m).
First, let's calculate the energy of one photon:
E = hc/λ
E = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (6.8 x 10^-7 m)
E = 2.93 x 10^-19 J
This means that one photon of light with a wavelength of 680 nm contains 2.93 x 10^-19 J of energy.
Now, let's calculate the energy contained in one mole of photons:
To convert from energy per photon to energy per mole of photons, we need to multiply by Avogadro's number (6.022 x 10^23 photons/mol):
Energy per mole = (2.93 x 10^-19 J/photon) x (6.022 x 10^23 photons/mol)
Energy per mole = 1.76 x 10^5 J/mol
Therefore, the energy contained in one mole of photons of light with a wavelength of 680 nm is 1.76 x 10^5 J/mol.
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which of the following are essential components of a bomb calorimeter? all of these answers are correct. a thermometer a heavy, fine threaded system container a mechanical stirrer
A bomb calorimeter whose components have a heat capacity of 6.66 kJ/°C is filled with 986 g of water. (The amount of water is not constant from experiment to experiment. The heat capacity of the calorimeter is broken down into two parts: the water and the calorimeter components.) The initial temperature of the calorimeter contents is 21.48°C. A 1.104 g sample of benzoic acid (?Ecomb = -26.42 kJ/g) is combusted in the calorimeter. What is the final temperature of the calorimeter contents?
°C
The final temperature of the calorimeter contents is approximately 42.9824°C.
To calculate the final temperature of the calorimeter contents, we consider the heat absorbed by the water and the calorimeter components.
First, let's calculate the heat absorbed by the water:
q_water = m_water * C_water * ΔT_water
q_water = 986 g * 4.18 J/g°C * (T_final - 21.48°C)
Next, let's calculate the heat absorbed by the calorimeter components:
q_calorimeter = C_calorimeter * ΔT_calorimeter
q_calorimeter = 6.66 kJ/°C * (T_final - 21.48°C)
Since the total heat absorbed is the sum of the heat absorbed by the water and the calorimeter components:
q_total = q_water + q_calorimeter
Now we can equate the total heat absorbed to the heat released by the combustion of benzoic acid:
q_total = -26.42 kJ/g * 1.104 g
By setting these two equations equal to each other, we can solve for the final temperature (T_final). We have:
986 g * 4.18 J/g°C * (T_final - 21.48°C) + 6.66 kJ/°C * (T_final - 21.48°C) = -26.42 kJ/g * 1.104 g
Simplifying and solving the equation will give us the value of T_final, which represents the final temperature of the calorimeter contents.
986 g * 4.18 J/g°C * (T_final - 21.48°C) + 6.66 kJ/°C * (T_final - 21.48°C) = -26.42 kJ/g * 1.104 g
Simplifying the equation:
4122.68 * (T_final - 21.48) + 6.66 * (T_final - 21.48) = -29.15568
4122.68T_final - 88721.58 + 6.66T_final - 143.5028 = -29.15568
4133.34T_final - 88865.0828 = -29.15568
4133.34T_final = 88835.92712
T_final ≈ 21.48 + (88835.92712 / 4133.34)
T_final ≈ 21.48 + 21.5024
T_final ≈ 42.9824
Therefore, the final temperature of the calorimeter contents is approximately 42.9824°C.
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draw structur of 2 methyl 2 butane?
The structural formula for 2-methyl-2-butane is as follows(See Picture): The methyl groups are joined to the second carbon atom from either end of the main chain, which is numbered from left to right.
2-methyl-2-Butane, often known as butane or n-Butane, has the following chemical formula: \(C_4H_{10}\). It is a regularly used fuel that is a highly combustible gas that has no colour or smell. 2-Butane is a straight-chain alkane with a carbon atom count of four and a hydrogen atom count of ten. Its boiling point is -0.5°C, whereas its melting point is -138°C. Many organic solvents can dissolve it even if it is insoluble in water. 2-Butane is frequently used in household and commercial refrigeration systems, stoves, and lighters. It serves as a feedstock for the synthesis of several substances, including butadiene and methyl ethyl ketone.
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What is the [HF] in a solution with a pOH of 12.5?
The concentration of the HF solution is 0.03.
What is the concentration?We know that the concentration has to do with the amount of the substance that is present in the system. We know that what we have is an acid hence we can only talk about the concentration of the acid if we can obtain the amount of the hydrogen ion.
We know that the acid is defined as any substance in which there is the presence of the hydrogen ion is what we call and acid. Since the hydrogen fluoride does have the hydrogen, we can say that the substance that we are dealing with here is an acid.
Thus;
pH = 14 - pOH
pOH = hydroxide ion concentration
pH = hydrogen ion concentration
pH = 14 - 12.5
= 1.5
[HF] = Antilog (-1.5)
= 0.03
The acid would have a concentration of 0.03.
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What are practical solutions to reduce air and water
pollution?
Just a simple 150 or so word answer, nothing fancy. Thanks in
advance.
Air and water pollution are serious environmental issues that have a negative impact on human health and the environment. Practical solutions can be implemented to reduce pollution levels and improve the overall quality of life.
To reduce air pollution, steps such as increasing public transportation usage, promoting renewable energy sources, enforcing stricter emission standards on vehicles and factories, and reducing waste production can be taken.
Planting trees and creating green spaces can also help reduce air pollution by absorbing carbon dioxide and other pollutants from the air.
To reduce water pollution, implementing proper waste disposal and treatment methods, reducing the usage of chemicals in households and industries, and enforcing stricter regulations on agricultural practices can be effective.
Regularly maintaining septic tanks and limiting the usage of pesticides and fertilizers can also help reduce water pollution.
Education and awareness campaigns can be launched to educate individuals on the importance of environmental conservation and pollution reduction.
These campaigns can promote environmentally friendly practices and encourage individuals to take action to reduce pollution levels. By implementing these practical solutions, we can take steps towards a cleaner and healthier environment.
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A tank contains 200 gallons of water in which 300 grams of salt is dissolved. A brine solution containing 0.4 kilograms of salt per gallon of water is pumped into the tank at the rate of 5 gallons per minute, and the well-stirred mixture is pumped out at the same rate. Let LaTeX: A\left(t\right)A(t)[Math Processing Error] represent the amount of salt (measured in kilograms) in the tank at time LaTeX: t[Math Processing Error].
Answer:
Therefore, after long period of time 80kg of salt will remain in tankExplanation:
given amount of salt at time t is A(t)
initial amount of salt =300 gm =0.3kg
=>A(0)=0.3
rate of salt inflow =5*0.4= 2 kg/min
rate of salt out flow =5*A/(200)=A/40
rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow
\(dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt\)
integrating factor
\(=e^{\int\limits (1/40) \, dt}\)
integrating factor \(=e^{(1/40)t}\)
multiply on both sides by \(=e^{(1/40)t}\)
\(dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t\)
integrate on both sides
\(\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})\)
b)
after long period of time means t - > ∞
\({t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80\)
Therefore, after long period of time 80kg of salt will remain in tankIdentify the limiting: and excess reactant in each reaction. a. Wood burns in a campfire. b. Airborne sulfur reacts with the silver plating on a teapot to produce tarnish (silver sulfide) c. Baking powder in batter decomposes to produce carbon dioxide.
a. In a campfire, wood is the limiting reactant and oxygen is the excess reactant
b. In the formation of tarnish (silver sulfide) on a silver-plated teapot, airborne sulfur is the limiting reactant, and silver is the excess reactant.
c. In the decomposition of baking powder in batter to produce carbon dioxide, the limiting reactant is the baking powder, while the excess reactant could be any other ingredient in the batter.
In each of these reactions, the limiting reactant is the substance that determines the amount of products formed, while the excess reactant is the one that remains unreacted after the reaction is complete.
a. Wood is composed mainly of cellulose and lignin, which react with oxygen in the air to produce carbon dioxide, water, and heat. The amount of wood determines the extent of the reaction, while there is usually an abundance of oxygen in the atmosphere to sustain the fire.
b. Sulfur in the atmosphere, often from pollution, reacts with silver to form silver sulfide. Since sulfur is present in relatively small quantities, it determines the amount of tarnish formed. The silver in the plating remains in excess.
c. Baking powder contains sodium bicarbonate, which decomposes upon heating to produce carbon dioxide, water, and a byproduct. The amount of carbon dioxide released depends on the amount of baking powder used, while other ingredients in the batter are in excess and do not affect the reaction.
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Carbon cycle – What are the main reservoirs
of the carbon cycle? Where do the inorganic and organic carbon
cycles interact? What are the major differences and similarities
between the inorganic and organic carbon?
The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.
The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.
Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.
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for the titration of 50.0 ml of 0.020 m aqueous salicylic acid with 0.020 m koh(aq), calculate the ph after the addition of 55.0 ml of koh(aq). for salycylic acid, pka = 2.97.
In the titration of 50.0 ml of 0.020 M aqueous salicylic acid with 0.020 M KOH(aq), the pH after the addition of 55.0 ml of KOH(aq) can be calculated.
Salicylic acid is a weak acid with a pKa value of 2.97. After the addition of 55.0 ml of KOH(aq), the solution will contain an excess of OH- ions due to the neutralization reaction between salicylic acid and KOH. The OH- ions will react with the weak acid, converting it to its conjugate base, salicylate. The pH of the resulting solution will depend on the relative concentrations of the acid and its conjugate base, as well as the pKa value.
To calculate the pH, we need to determine the concentrations of the acid and its conjugate base. The initial moles of salicylic acid can be calculated using the given volume and concentration. Since the acid and base react in a 1:1 ratio, the moles of KOH added will be equal to the moles of salicylic acid at the equivalence point.
Next, we calculate the moles of salicylic acid remaining after the reaction. Since 55.0 ml of KOH(aq) is added to the initial 50.0 ml of salicylic acid, the total volume becomes 105.0 ml. We subtract the moles of KOH added from the initial moles of salicylic acid to find the moles of salicylic acid left.
Using the moles of salicylic acid and its conjugate base, we can determine their concentrations. The concentration of the acid is obtained by dividing the moles of acid remaining by the final volume of the solution. The concentration of the conjugate base is determined in a similar manner.
Finally, we can calculate the pH using the Henderson-Hasselbalch equation:
pH = pKa + log10([conjugate base]/[acid])
Substituting the calculated values, we can find the pH of the solution after the addition of 55.0 ml of KOH(aq) to the titration of salicylic acid.
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What would the concentration of sodium formate (NaCOOH) be in 0.00750 M formate buffer at pH 4.358?
The concentration of sodium formate in the buffer solution is 2.93 x \(10^{-3}\) M.
To find the concentration of sodium formate in the buffer solution, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([NaCOOH] / [HCOOH])
Substituting the given values:
4.358 = 3.77 + log([NaCOOH] / 0.00750)
0.588 = log([NaCOOH] / 0.00750)
[NaCOOH] / 0.00750 = 3.91 x \(10^{-1}\)
[NaCOOH] = 0.00750 x 3.91 x \(10^{-1}\) = 2.93 x \(10^{-3}\) M
Therefore, the concentration of sodium formate in the buffer solution is 2.93 x \(10^{-3}\) M.
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Explain why volume is an example of an extensive property and density an intensive property.
Extensive property is dependent on mass. Intensive property is property that depends only on the type of matter rather than the amount. Hense, Volume is an example of Extensive property and Density is an example of Intensive property.
Hope this helps :)
What is the percent of O in
Cr203?
(Cr = 52.00 amu, O = 16.00 amu)
[?]%
Answer:
31.6%
Explanation:
find the molecular formular
(52×2)+(16×3)=152
since the %of oxygen is required
MF of o in Cr2O3 =16×3=48
%O= 48/152×100= 31.6%
How to do this question plz answer me
Answer:
dissolved
Explanation:
The figure shows sodium chloride is in solution. It gets that way by being dissolved.
DUE TODAY PLS HELPPPPPPPPP MEEEEEEEE
Answer:
Explanation:
Cold air masses tend to move toward the Equator. Warm air masses tend to move toward the poles. The Coriolis effect causes them to move on a diagonal. Many air masses move toward the northeast over the U.S. This is the same direction that global winds blow.