How many molecules are in 8.78 moles of oxygen gas

The number of mole present in the aluminum foil, given that the foil has a thickness of 1.0 mm is 0.7 mole

We'll begin by obtaining the mass of the aluminum foil. Details below:

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of aluminum = 2.702 × 7

Mass of aluminum = 18.914 g

Finally, we shall determine the number of mole present. Details below:

Mole = mass / molar mass

Number of mole of aluminum = 18.914 / 27

Number of mole of aluminum = 0.7 mole

Thus, the number of mole is 0.7 mole

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All the statements given above are correct.

Atoms within resonance structures are the same. The species' structure is not accurately reflected by a single resonance structure.

A representation of a molecule or an ion called a resonance structure depicts several electron combinations that are not conceivable in a single, static structure.

Resonance hybrid refers to the actual structure of the molecule or ion, which is an average of the potential resonance structures.

Resonance structures are not different in terms of atoms, but rather in the arrangement of electrons.

Resonance structures vary, and no single resonance structure can fully capture the structure of an entire species.

The species that make up resonance structures have isomers.

The species could have any of these structures at any time since resonance forms quickly interconvert.

It is not real to have individual resonance shapes.

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Therefore, 111.6 g of lead(IV) phosphate are produced when 150.0 g of ammonium phosphate and 250 g of lead(IV) nitrate are available.

The balanced chemical equation for the reaction is:

(NH4)3PO4 + 3Pb(NO3)4 → Pb3(PO4)4 + 12NH4NO3

First, we need to calculate the limiting reagent to determine which reactant will be consumed completely and therefore will limit the amount of product formed.

The moles of ammonium phosphate available is:

n(NH4)3PO4 = m/M = 150.0 g / 149.09 g/mol = 1.005 mol

The moles of lead(IV) nitrate available is:

nPb(NO3)4 = m/M = 250 g / 783.32 g/mol = 0.319 mol

To determine the limiting reagent, we compare the mole ratio of ammonium phosphate to lead(IV) nitrate in the balanced equation. For every one mole of ammonium phosphate, three moles of lead(IV) nitrate are required. Therefore, the amount of lead(IV) nitrate required to react with 1.005 mol of ammonium phosphate is:

nPb(NO3)4 required = 1.005 mol / 3 mol Pb(NO3)4/mol NH4)3PO4 = 0.335 mol

Since we only have 0.319 mol of lead(IV) nitrate available, it is the limiting reagent.

The amount of lead(IV) phosphate produced can be calculated using the mole ratio from the balanced equation:

nPb3(PO4)4 = 0.319 mol Pb(NO3)4 × (1 mol Pb3(PO4)4/3 mol Pb(NO3)4) × (1032.72 g Pb3(PO4)4/mol) = 111.6 g

Therefore, 111.6 g of lead(IV) phosphate are produced when 150.0 g of ammonium phosphate and 250 g of lead(IV) nitrate are available.

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Answer:

36 eggs

Explanation:

12 eggs in each carton

12 + 12 + 12 = 36 eggs

or 3 * 12 = 36 eggs

Hope this helps, have a nice day/night! :D

Answer: it definitely did help me a lot but sometimes it doesn’t make me happy like i will get stressed but it passes.

Explanation:

A liquid is allowed to evaporate and leaves no residue. It can not be determined whether it was an element, a compound, or a mixture.

A water vapor molecule stays roughly 10 days in the atmosphere after it has evaporated. Water vapor starts to cool back down as it ascends higher in the atmosphere. The water vapor condenses when it becomes cold enough, turning it back into liquid water. Eventually, individual water droplets will condense to create clouds and precipitation.

It is not possible to determined whether it would be an element, a compound and mixture because the size of the particle will be too less.

A method for separating homogenous mixtures with one or even more dissolved salts is called evaporation. The procedure separates the liquid from the solid components. Usually, the procedure entails heating the combination until there is no more liquid is present.

Therefore, it can not be possible to determined whether it was an element, a compound, or a mixture by evaporation.

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Answer:

The patient requires a dose of 107.2 mg of gentamicin

Explanation:

A dosage of 1.75 mg per Kilogram body weight results in blood serum levels of 4.5 mcg/mL

This means that; 1.75 mg/ kg = 4.0 mcg/mL

Therefore, dosage of gentamicin in  mg/kg that will result in 4.5 mcg/mL blood serum level = (1.75 mg/Kg * 4.5 mcg/mL) / 4.0 mcg/mL

Dosageof gentamicin = 1.97 mg/Kg

1-lb = 0.453592 Kg

Weight of 120-lb patient in Kg = 120 * 0.453592 = 54.43 Kg

Dose in mg required by patient = 1.97 mg/Kg * 54.43 Kg = 107.2 mg

Therefore, the 120-lb patient requires a dose of 107.2 mg of gentamicin to result in a blood serum level of 4.5 mcg/mL

Answer:

9, 10, 12

Explanation:

anything greater than pH 7 is basic

Answer:

4200

Explanation:

4,000 * .8 + 5,000 * .2

The weighted average of lemonas with 80% GX model and 20 % GXL model is calculated using their mass percent and it is 4200.

What is  weighted average?

The weighted average is different from the normal average we use in maths. Let's X and Y be two number and their average be x+ y/2. That is the arithmetic mean.

The weighted average of lemonas is similar to the atomic weight of an element calculated from ist two isotopes where, the percentage abundance in earth and the mass of isotopes if given the weighted average is calculated as follows:

weighted average =  % abundance / 100 × mass of isotope 1 + % abundance / 100 × mass of isotope 2

In a similar way, the weighted average of lemonas of GX and GXL model is calculated as follows:

weighted average = ( 4000 lbs ×80/100 ) + ( 5000 lbs ×20/100)

                               = 4200 lbs.

Hence, the weighted average of lemonas if 80% are the GX model (4,000 lbs) and 20% are the GXL model is 4200 lbs.

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Answer:

EtOH stands for ethyl alcohol, which is the type of alcohol found in alcoholic beverages such as beer, wine, and spirits. It is a central nervous system depressant that can cause a range of effects, from mild relaxation to severe impairment of cognitive and motor functions. EtOH is often used in the medical and research fields as a short notation for Ethanol.

EtOH is the chemical label or acronym for ethyl alcohol (ethanol). EtOH refers to the kind of alcohol that can be found in alcoholic beverages like wine, beer, and spirits.

It is a depressant of the central nervous system that can have a variety of effects, ranging from mild relaxation to severe cognitive and motor impairment. In the medical and research industries, EtOH is frequently used as a short notation for ethanol.

It is used in the production of other chemicals, as a solvent, and in alcoholic beverages. Ethanol is a colorless, somewhat toxic substance. Solutions of ethanol and water that contain more than 50% ethanol are extremely flammable. The most well-known use of ethanol is as alcohol in alcoholic beverages.

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Answer:

Each molecule of liquid water is involved in approximately four hydrogen bonds with strengths significantly lower than covalent bonds but significantly greater than natural thermal energy. ... Even a very small reinforcement of hydrogen bonds can have a major impact on normal metabolism.

Explanation:

Answer:

There would be no new island formations.

Explanation:

the plates simply dont move so nothing happens

when they do  mountains, volcanoes, trenches, exct. form

Answer:

There would be no new island formations.

Explanation:

Hope it helps!!

Answer:

ZnBr2

Explanation:

KNO3 + LiOH -------> no reaction

This is because KNO3 and LiOH completely ionize.in water and form neutral solutions.Since both are neutral no reaction occurs

NH4Cl + LiOH -----> NH3 (aq) + H2O (l) + LiCl(aq)

None of the above products are precipitates

Ca(C2H3O2)2 + 2LiOH -----> Ca(OH)2 (aq) + 2LiC2H3O2 (aq)

ZnBr2 + 2LiOH -----> Zn(OH)2 (s) + LiBr2 ( aq)

Zn(OH)2 thus formed is a white precipitate

However when excess LiOH is added Zn(OH)2 precipitate will dissolve to give a clear solution of Li2ZnO2 .

You can remember this by the fact that Na,K,Rb,Cs,Ca,Sr,Ba hydroxides are soluble in water and all other hydroxide are precipitated in water

Zn(OH)2 (s) + 2 LiOH ------> Li2ZnO2(aq) + 2 H2O ( l)

The only compound that will form a precipitate with LiOH would be ZnBr2

These are double displacement reactions in which precipitates are produced. Precipitates are insoluble solids formed from the combination of ions in aqueous solutions.

In this case, a reaction between LiOH and ZnBr2 would be as follows;

2LiOH + ZnBr2 ----------> 2LiBr + Zn(OH)2 (s)

Zn(OH)2 is an insoluble salt and will precipitate out in the solution.

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Answer:

because the water brings a cool breeze when the wind blows

Explanation:

Answer: D

Explanation:

D - Decomposition of carbonates into oxide and carbon dioxide

A - Combustion reaction. Combustion of methane to form Carbon dioxide and water.

C - Reaction of reactive metal (Na) and water to form hydroxide.

B - No particular name of the reaction. Usually denoted as a synthesis redox reaction.

Answer:CaCO3  CaO + CO2

Explanation: just took it

Approximately 17 metric tons of chlorine gas should be dissolved in 5 million liters of water to achieve a concentration of 3.4 ppm.

To determine the amount of chlorine gas that should be dissolved in 5 million liters of water to achieve a concentration of 3.4 ppm (parts per million), we need to convert the volume of water into the corresponding mass.

1 liter of water has a mass of approximately 1 kilogram, so 5 million liters of water would have a mass of 5 million kilograms (5 × 10^6 kg).

The concentration of 3.4 ppm means that there are 3.4 parts of chlorine gas for every million parts of water. Therefore, to find the amount of chlorine gas needed, we multiply the concentration by the mass of water:

Amount of chlorine gas = (3.4 ppm) × (5 × 10^6 kg) = 17 × 10^6 g = 17 metric tons.

Thus, to obtain a concentration of 3.4 ppm in 5 million liters of water, approximately 17 metric tons of chlorine gas would need to be dissolved.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

952.2g SO3

Explanation:

Molar mass of C4H8S2 is 120.2363 g/mol

Mol in 750.0g = 750.0/120.2363 = 6.238 mol

1mol C4H8S2 produces 2 mol SO3

6.238 mol will produce 2×6.238 = 12.476 mol SO3

Molar mass SO3 = 32+3×16 = 80.0g/mol

Theoretical yield = 12.476×80.0 = 998.08g

The actual yield is 95.4%

Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced

Hope it will help you.

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

\(PV=nRT\)

The given gas has standard pressure, \(P=1\rm atm\)

The volume of the gas has been, \(V= 0. 500 \;\rm L\)

The temperature of the gas has been, \(T=15^\circ \text C\\ T=288\;\rm K\)

Substituting the values for the moles of gas, n:

\(\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\ \textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\ \textit n=0.021\;mol\)

The moles of gas in the bottle has been 0.021 mol.

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C. physical change

Explanation:

That's the answer

The item that would most likely end up in the waste stream soonest is a single-use plastic item, such as a plastic bag or disposable plastic utensil. These items are designed for short-term use and are typically discarded shortly after use.

The item that would most likely end up in the waste stream soonest would be a disposable plastic water bottle. These bottles are commonly used and quickly disposed of after a single use, contributing to the waste stream more quickly than other durable or reusable items. In general, reducing waste generation, practicing responsible consumption, and promoting recycling and other sustainable waste management practices can help minimize the impact of waste on the environment.

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Answer:

The nucleus has an overall positive charge as it contains the protons.

Explanation:

Every atom has no overall charge (neutral). This is because they contain equal numbers of positive protons and negative electrons. These opposite charges cancel each other out making the atom neutral.

Answer:

cm^3 —> dm^3

divide by 1000

159.5 — Mr of CuSO4

n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)

0.100 mol of CuSO4 dissolved in 0.5dm^3 of water

calculate for mass of CuSO4 dissolved in 0.03dm^3  (30cm^3) of the solution

n = m/Mr

m = n*Mr

if 0.1 mol is dissolved in 0.5 dm^3 of water

0.5/0.03 ≈ 16.66666667

0.1 = 0.05

0.1 / 16.66666667 = 0.006

0.5 / 16.66666667 = 0.03

0.006 (mol of CuSO4) = 0.03 (dm^3 solution)

0.006 * 159.5 = 0.957 g

I think this is the answer

The mass copper sulphate CuSO₄ in 30ml solution is 957.6g.

To determine the mass of copper sulphate in the given solution, compare both the molarity given  

M₁V₁=M₂V₂

n₁/V1=n₂/V2

0.1/0.5=n₂/30         cm³=ml

n₂=6 moles

6×159.5=957.6g

Multiply the calculated moles with the relative mass/molecular mass to get the mass of CuSO₄.

hence, the mass of CuSO₄ is 957.6g

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The value of Y in the formula when 2.8g of silicon react with 3.2g of oxygen, is 2

The numbers in the formula of a compound determine the ratio of moles of each element in the compound.

Given:

2.8g of silicon

3.2g of oxygen

[relative atomic mass of silicon is 28 and of oxygen is 16]

For silicon, n = 2.8 ÷ 28 = 0.1    (n= moles)

For oxygen, n = 3.2 ÷ 016 = 0.2

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.1 moles.

For Silicon = 0.1/0.1 = 1

For Oxygen = 0.2/0.1 = 2

Taking the mole ratio as their subscripts.

The ratio of Si:O is 1:2

SiO\(_{2}\) is the formula of silicon dioxide.

The value of y in the formula SiO\(_{Y}\) is 2 when 2.8g of silicon react with 3.2g of oxygen.

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Answer:

Me too.  What is this for? A Lab. You are missing some kind of key info bud.

Explanation:

NaCl is correct answer of your question

Answer:

NH4OH

Explanation:

BCOZ IT IS PRESENT IN 15th GROUO WHICH NON METAL

Prediction 1 best shows what the population could look like after many generations. Because, the long beak traits is having more life time.

Each characteristics in a living thing is created by a respective genetic coding in its body. The genetic code which is responsible for a particular behavior or appearance is called a genetic trait.

Here, the prediction 1 is best . It already saying that long-beak hummingbirds are more likely to survive, that baby survived long enough to pass on its mutation, so the long-beak trait became more common over generations.

Prediction 2 says abut a  genetic trait which is less fit to survive. Hence, cannot affect the next generation population. Therefore, prediction 1 is best.

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Your question is incomplete. But your complete question probably was:

Prediction 1 :Two hummingbirds with short or medium beaks had a baby with a mutation in its genes for the long-beak trait.

Prediction 2 is best. A hummingbird could have been born with a mutation in its genes for the long-beak trait and lived for a little while.