how many liters are in 3 moles of oxygen gas?
please explain ​

Answer:

1 mole is equal to 6.022x10²³

Answer:

2.979 mol

Explanation:

mass of NaF=14+19

                    =33g

33g of NaF is the mass of 1 mol

98.3g of NaF is the mass of (98.3/33)*1=2.979 mol

No, the statement a solid substance dissolves in water, releasing heat as it does so is not always true.

A solid substance does not always release heat as it dissolves in water. The enthalpy change of the dissolution process can be endothermic or exothermic depending on the specific solid and solvent used.In an exothermic reaction, the reaction releases heat as it occurs.

Dissolving solid substances in water is an example of an exothermic reaction. The heat that is generated when salt is dissolved in water, for example, is due to the negative and positive ions interacting with one another. Conversely, an endothermic reaction is a reaction that absorbs heat during the process. This is the reverse of exothermic.

For example, dissolving ammonium nitrate in water requires heat because it is endothermic. Therefore, the dissolution of a solid substance in water does not always release heat; it can either be exothermic or endothermic. Hence, the statement is not always true.

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Answer:

0.600 is yourr answer and if wrong sorry  

Explanation:

0.600 mol of potassium contain \(3.6 * 10^{23}\) atoms of potassium.

C. 0.600 mol

A mole is the amount (10) of material containing  \(6.022*10^{23}\) particles . This number is also called Avogadro's number.

Given:

Atoms of potassium = \(3.3*10^{23} atoms\)

To find:

Moles of potassium =?

As we know,

\(1 mole = 6.022*10^{23} atoms\\\\1 atom = 1 / 6.022*10^{23} mole\\\\3.3*10^{23} atoms = 1 / 6.022*10^{23} mole * 3.3*10^{23} atoms\\\\3.3*10^{23} atoms=0.600 mol\\\\\)

Thus, 0.600 mol of potassium contain  \(3.6 * 10^{23}\) atoms of potassium.

Therefore, option C is correct.

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Answer:

0.456

Explanation:

Carbon Dioxide, CO2 0.456

456÷1000=0.456

The resulting volume of the gas is approximately 2.14 m^3.

According to Boyle's Law, when the temperature of a gas remains constant, the product of its pressure and volume is constant. Mathematically, P1 * V1 = P2 * V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Given:

Initial volume (V1) = 5 m^3

Initial pressure (P1) = 300 kPa

Final pressure (P2) = 700 kPa

Rearranging the Boyle's Law equation to solve for the final volume (V2), we get:

V2 = (P1 * V1) / P2

Substituting the given values into the equation, we find:

V2 = (300 kPa * 5 \(m^3\)) / 700 kPa

Evaluating the expression, the resulting volume of the gas is approximately 2.14 \(m^3\).

Therefore, when the temperature remains unchanged, the resulting volume of the gas is approximately 2.14\(m^3\).

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a. A sample of water is very cloudy or shows high turbidity - Unhealthy.

b. A hydroelectric dam has heated a nearby body of water - Unhealthy.

c. A water sample is tested to have 10 ppm of dissolved oxygen- Healthy.

Healthy is a state of well-being where an individual is physically, mentally, emotionally, and spiritually balanced and functioning at their optimal level. This means having a balanced diet, exercising regularly, getting enough rest, engaging in positive relationships, managing stress, and having positive mental and emotional health.

A healthy lifestyle also includes avoiding harmful substances such as alcohol, tobacco, and drugs. Making healthy choices, such as eating the right foods, exercising regularly, and engaging in positive relationships, can help individuals reach and maintain a healthy state. It is important to remember that health is not just the absence of disease, but a state of overall well-being.

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The theoretical yield of H2O from 68.75 g of C4H10 is 106.6 g.

We now know that the theoretical yield of CO2 C O 2 is 2.56 mol since the limiting reactant dictates it.

For the combustion of C4H10, the balanced equation is:

2C4H10 + 13O2 → 8CO2 + 10H2O

First, let's calculate the number of moles of C4H10:

molar mass of C4H10 = 4(12.01) + 10(1.01) = 58.12 g/mol

C4H10 mass is equal to its molar mass in C4H10 moles.

moles of C4H10 = 68.75 g / 58.12 g/mol

moles of C4H10 = 1.183 mol

According to the balanced equation, 2 moles of C4H10 produce 10 moles of H2O. As a result, the amount of water generated is:

moles of H2O = (moles of C4H10) x (10 moles H2O / 2 moles C4H10)

moles of H2O = 1.183 mol x 5

moles of H2O = 5.915 mol

The amount of moles of water can finally be converted to grams:

molar mass of H2O = moles of H2O x

mass of H2O = 5.915 mol x 18.02 g/mol

mass of H2O = 106.6 g.

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Answer:

122g/63.5

1.92 mol

According to the balanced equation, 31.7 grams of nitrogen gas (N₂) reacting with excess hydrogen gas (H₂) will produce a 2.264 moles of ammonia gas (NH₃).

To determine the moles of ammonia formed, we need to convert the given mass of nitrogen gas to moles using its molar mass and the stoichiometric ratio of the balanced equation.

The molar mass of nitrogen gas (N₂) is 28.02 g/mol. To calculate the number of moles of nitrogen gas, we divide the given mass by its molar mass:

31.7 g / 28.02 g/mol = 1.132 mol

According to the stoichiometry of the balanced equation, the ratio between nitrogen gas and ammonia gas is 1:2. This means that for every 1 mole of nitrogen gas, 2 moles of ammonia gas are produced.

Therefore, using the stoichiometric ratio, we can determine the moles of ammonia formed:

1.132 mol N₂ * (2 mol NH₃ / 1 mol N₂) = 2.264 mol NH₃

Thus, upon the complete reaction of 31.7 grams of nitrogen gas with excess hydrogen gas, 2.264 moles of ammonia gas will be formed.

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Answer:

d

Explanation:

because nuclear charge ( no. of protons) increases

On a Space shuttle, LiOH Is used to absorb CO2 to produce LiHCO3

LiOH + CO2 === LiHCO3

Now

58g of CO2 produces 79.3g of LiHCO3

This is the Actual Yield.

Recall

% Yield = Actual yield/Theoretical yield x100

NOW

We have to find the theoretical yield

From the equation of reaction

Now 58g of CO2 reacted

Converting to Moles

mole = Mass/Molar Mass

Molar mass of CO2=44g/mol

Mole = 58/44

=1.318moles of CO2

From the equation Of Reaction.

1 mole of CO2 reacts and Produces 1 mole of LiHCO3

Since their Mole ratio is 1:1

An Equal amount of LiHCO3 will be produced.

So 1.318moles of LiHCO3 will be produced.

Convert this mole to Mass

Mole =Mass/Molar Mass

Mass = Mole x Molar Mas

Molar Mass of LiHCO3 =68g/mol

Mass = 1.318 x 68

Mass = 89.62g.

This is the theoretical Yield.

% yield = 79.3/89.62 x 100

= 88.48%.

Answer:

A geologist visits an environment to make observations. The scientist predicts that the environment will undergo secondary succession. What did the geologist likely observe in the environment to draw this conclusion? Check all that apply a

The geologist saw rocks and gravel.

b

The geologist saw cooled lava flows.

c

The geologist saw remaining soil.

d

The geologist saw a few plant species.

e

The geologist saw a few small insects.

Answer:

1.92

Explanation:

The temperature of the system in equilibrium is 301.96 K.

The equilibrium temperature of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m1 = 62.5 g = 0.0625 kg

T1 = 650 K

m2 = 165 g = 0.165 kg

T2 = 298 K

c1 = 126 J/kgK

c2 = 4200 J/kgK

Lets assume that the value of equilibrium temperature is T. Hence,

Q released = Q received

m1 . c1 . ΔT1 = m2 . c2 . ΔT

0.0625 . 126 . (T1 - T) = 0.165 . 4200 . (T - T2)

0.0625 . 126 . (650 - T) = 0.165 . 4200 . (T - 298)

5118.75 - 7.875T = 693T - 206514

700.875T = 211632.75

T = 301.96 K

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Answer:

–253.5 °C

Explanation:

We'll begin by calculating the number of mole in 6 g of CO₂. This can be obtained as follow:

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ = 6 g

Mole of CO₂ =.?

Mole = mass / molar mass

Mole of CO₂ = 6 / 44

Mole of CO₂ = 0.136 mole

Next, we shall convert 225 mL to L.

1000 mL = 1 L

Therefore,

225 mL = 225 mL × 1 L / 1000

225 mL = 0.225 L

Next, we shall determine the temperature of the gas. This can be obtained as follow:

Pressure (P) = 0.855 atm

Volume (V) = 0.225 L

Number of mole (n) = 0.136 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =?

PV =nRT

0.855 × 0.255 = 0.136 × 0.0821 × T

0.218025 = 0.0111656 × T

Divide both side by 0.0111656

T = 0.218025 / 0.0111656

T = 19.5 K

Finally, we shall convert 19.5 K to degree celsius (°C). This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 19.5 K

T(°C) = 19.5 – 273

T(°C) = –253.5 °C

Therefore, the temperature of the gas is –253.5 °C

Answer:

Oxidized: Hydrogen

Reduced: Chlorine

Oxidizing agent: Chlorine

Reducing agent: Hydrogen

Explanation:

To determine which atom is oxidized and which is reduced, we need to compare the oxidation numbers of the atoms in the reactants and products.

In the reaction H2 + Cl2 → 2 HCl, the oxidation state of hydrogen in H2 is 0, while the oxidation state of chlorine in Cl2 is also 0. In the product HCl, the oxidation state of hydrogen is +1, while the oxidation state of chlorine is -1.

So, in this reaction, hydrogen is oxidized (its oxidation state increases from 0 to +1), while chlorine is reduced (its oxidation state decreases from 0 to -1).

To determine which reactant is the oxidizing agent and which is the reducing agent, we need to look at which reactant caused the oxidation and which caused the reduction.

In this case, chlorine caused the oxidation of hydrogen and is therefore the oxidizing agent. Hydrogen caused the reduction of chlorine and is therefore the reducing agent.

Heat : 12 kJ,  to maintain hydrogen bonds

Given

A 2.00mole sample ⇒ n = 2 mol

H₂O(s) at 0°C melted, producing H₂O(l) at 0°C

Required

the amount of heat required

the changes that took place

Analysis

Conversion of mol to mass

Use formula of Heat  :

Q = mLf (melting/freezing)  

Lf=latent heat of fusion  (for water=334 J/g)

Solution

mass H₂O(MW=18 g/mol) :

\(\tt mass=2\times 18=36~g\)

Heat required :

\(\tt Q=36\times 334=12024~J\approx 12~kJ\)

The absorbed heat is used to maintain hydrogen bonds in water molecules (there are two hydrogen bonds per molecule)

Paraphrase

The amount of heat required : 12 kJ, and to maintain hydrogen bonds

If an oil film (n = 1.46) floats on a water puddle (n = 1.33), the minimum (non-zero) thickness of the oil film is 150.41 nm.

The minimum (non-zero) thickness of the oil film can be calculated using the equation for thin film interference:

2nt = mλ/√(n² - sin²θ)

Where:
n = refractive index of the medium (in this case, air)
t = thickness of the oil film
m = order of the interference (m = 1 for the first minimum)
λ = wavelength of light (480 nm for blue light)
θ = angle of incidence (assumed to be 0°)

Substituting the values given in the problem, we get:

2(1.46)t = 1(480 nm)/√(1.46² - sin²0°)

Simplifying the equation, we get:

2.92t = 480 nm/1.092

2.92t = 439.56 nm

t = 150.41 nm

Therefore, the minimum (non-zero) thickness of the oil film is 150.41 nm.

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When investigating whether or not the substance dibromoethane (ethylene dibromide) is carcinogenic, we follow the survival history of 161 white employees of 2 factories who were exposed to dibromoethane.

Among them, we observe 7 cancer deaths in the period 1940-1975. On the other hand, the mean number of cases over that period in that general population is expected to be 5.8. Do those 7 cases provide a reason to consider the substance as .Yes, the seven cases provide a reason to consider the substance dibromoethane as carcinogenic.

Since the number of cancer deaths observed in the 161 white employees exposed to dibromoethane is 7 which is greater than the expected cancer deaths in the general population, which is 5.8. Therefore, the excess cases may suggest that dibromoethane has some carcinogenic potential.

Hence, we can consider dibromoethane as carcinogenic.

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Answer:

missin a diagram buddy

Explanation:

The number of carbon atoms present in any compound is equal to seven.

Number of carbon atoms present in any compound will be calculated by using the following equation:

No. of Carbon atoms = Relative intensity of M+1 peak / Natural abundance of C13

Intensity of molecular peak = 34.76%

Intensity of M+1 peak = 2.632%

Relative intensity of M+1 peak = (100/34.76)×2.632 = 7.57%

Given that natural abundance of M+1 = 1.07%

On putting values on above equation, we get

No. of C atoms = 7.57 / 1.07 = 7.07 = 7 (approx)

Hence number of carbon atoms is 7.

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0.54 g of K2SO4 will crystallize when the solution is cooled to 0 degree celsius.

Weight of KNO3= 51 g

Weight of K2SO4= 9 g

Weight of Water= 130 g

When the mixture is added to water, we get a solution.

Now, the solution is cooled to 0 °C.

Therefore, the solubility of KNO3 and K2SO4 decreases at this temperature, and they start to crystallize.

In other words, KNO3 and K2SO4 will start to crystallize at 0 °C, and the solubility of these salts at this temperature is given in the table below;

Substance Solubility at 0°C (g/100 g H2O)

KNO3 10.6

K2SO 41.8

Let's calculate the mass of K2SO4 that will crystallize.

The mass of the remaining K2SO4 in the solution will be the initial mass minus the mass of K2SO4 that crystallizes.

mass of K2SO4 = initial mass - mass of K2SO4 that crystallizes

mass of K2SO4 = 9 - mass of K2SO4 that crystallizes

We know that the mass of KNO3 in the solution is 51 g, and its solubility at 0 °C is 10.6 g/100 g of water.

Therefore, the amount of KNO3 that crystallizes will be;

KNO3 that crystallizes = 51 - (130/100) × 10.6

KNO3 that crystallizes = 51 - 13.78

KNO3 that crystallizes = 37.22 g

The mass of the remaining solution after crystallization of KNO3 is;

mass of the remaining solution = 130 - 100

mass of the remaining solution = 30 g

Now, using the amount of solution that is left, we can calculate the mass of K2SO4 that will crystallize.

Mass of K2SO4 that crystallizes = solubility of K2SO4 x Mass of water

Mass of K2SO4 that crystallizes = 1.8 g/100 g x 30 g

Mass of K2SO4 that crystallizes = 0.54 g

Therefore, 0.54 g of K2SO4 will crystallize.

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Answer

b. It produces carbon dioxide when burned in pure oxygen.

Explanation

The reaction between diamond and oxygen, producing carbon dioxide is not a physical property of diamond, it is a chemical property because breaking and synthesis of chemical bonds occur.

Answer:

the heat wants to travel up. Heat rises

Explanation:

Answer:

Explanation:

Hence,

The above statement is true for, the gas particles moves faster in high temperature.

Answer:

You are right, it's D

A chemical Reaction causes atoms to react with each other. Hence Option (D) is correct.

A process that involves rearrangement of the molecular or ionic structure of a substance, as distinct from a change in physical form or a nuclear reaction.

Therefore, A chemical Reaction causes atoms to react with each other. Hence Option (D) is correct.

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The purpose of aluminum filtration in the x-ray tube head is to remove low-energy, less penetrating x-rays from the x-ray beam.

Aluminum filtration is an essential component of the x-ray tube head in medical imaging. It involves the insertion of aluminum sheets or filters into the path of the x-ray beam. The primary purpose of this filtration is to selectively absorb or attenuate low-energy x-rays, which are less penetrating and can contribute to unnecessary patient radiation dose without providing significant diagnostic information.

When the x-ray beam passes through the aluminum filter, it preferentially absorbs the lower-energy x-ray photons. This filtration process helps to "harden" the x-ray beam by removing the less energetic x-rays. As a result, the remaining x-ray beam that reaches the patient or the image receptor consists mainly of higher-energy photons, which are more penetrating and can pass through the body to create clearer images.

Aluminum is commonly used as the material for filtration because it has the appropriate attenuation properties to absorb the lower-energy x-rays effectively while allowing higher-energy x-rays to pass through. The thickness or composition of the aluminum filter can be adjusted to achieve the desired level of beam hardening, depending on the imaging requirements and the energy spectrum of the x-ray tube.

Aluminum filtration in the x-ray tube head serves the purpose of removing low-energy x-rays from the beam, reducing patient radiation dose while improving image quality by allowing mainly higher-energy, more penetrating x-rays to reach the patient or the image receptor.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} = 0.5 \\ \)

We have the final answer as

Hope this helps you