How many centimeters are in 7 feet given that 1 inch is 2.5 cm

Answer:

-1.5, -1

Step-by-step explanation:

midpoint formula

(x1 + x2 / 2) , (y1 + y2/ 2)

-6 + 3 / 2 ,   -8  + 6 / 2

Answer:

Distance

=

\( \sqrt{(a {}^{2} - a {}^{1}) {}^{2} +(b{}^{2} - b {}^{1}) {}^{2} } \)

=

\( = \sqrt{( - 8 + 6) {}^{2} + (6 - 3) {}^{2} } \)

\( \sqrt{4 + 9} \)

\( = \sqrt{13} \)

=3.61/2

=1.8

Answer:

5.5, 5¼, 5 1/5 and 5.1.

Explanation:

To list the height from greatest to least, we convert each of them to a decimal.

Therefore, the weights are: 5.1, 5.2, 5.5 and 5.25

Arranging them from greatest to least gives:

5.5, 5.25, 5.2 and 5.1 which is equivalent to: 5.5, 5¼, 5 1/5 and 5.1.

Answer:

Step-by-step explanation:

Volume of a pyramid can be found by using the formula

\(v = \frac{1}{3} \times a \times h \\ \)

a is the area of the base

h is the height

Since the base is a square we have

\(v = \frac{1}{3} \times {15.3}^{2} \times 19.6 \\ = 78.03 \times 19.6 \\ = 1529.388\)

We have the final answer as

Hope this helps you

Answer:

(0,1.5)

Step-by-step explanation:

The probability that there will be at least 4 typos on page 301 is 0.847

To solve this problem, we need to make some assumptions. Let's assume that the number of typos on each page follows a Poisson distribution with a mean of 6 typos per page, and that the number of typos on one page is independent of the number of typos on any other page.

Under these assumptions, we can use the Poisson distribution to calculate the probability of observing a certain number of typos on a given page.

Let X be the number of typos on page 301. Then X follows a Poisson distribution with a mean of 6 typos per page. The probability of observing at least 4 typos on page 301 can be calculated as follows

P(X ≥ 4) = 1 - P(X < 4)

= 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

Using the Poisson distribution formula, we can calculate the probabilities of each of these events

P(X = k) = (e^-λ × λ^k) / k!

where λ = 6 and k is the number of typos. Thus,

P(X = 0) = (e^-6 × 6^0) / 0! = e^-6 ≈ 0.0025

P(X = 1) = (e^-6 × 6^1) / 1! = 6e^-6 ≈ 0.015

P(X = 2) = (e^-6 × 6^2) / 2! = 18e^-6 ≈ 0.045

P(X = 3) = (e^-6 × 6^3) / 3! = 36e^-6 ≈ 0.091

Plugging these values into the equation above, we get

P(X ≥ 4) = 1 - (e^-6 + 6e^-6 + 18e^-6 + 36e^-6)

≈ 0.847

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Answer:

okay, but with what should i help?

Answer:

6.2 and 6.4

Step-by-step explanation:

I am right please like

Answer:

40% of 2500=

100

40

×2500

=1000

Step-by-step explanation:

Write the calculation exactly as you say it:

Answer:

3^6

Step-by-step explanation:

3^8 ÷ 3^2

= 3^ (8-2)

= 3^6

I don't really understand the question. Do u have a picture?

Slope intercept form formula: Y = mx + b

M represents the slope and B represents the y-intercept.

The type of model that best fits the given situation is; A linear equation  Model

Right inside the local reservoir we will have an initial amount of water A.

Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.

Thus, after t hours, the amount of water in the reservoir is expressed as:

W = A - 500gal * t

This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.

The domain of this model is restricted because we can't have a negative amount of water in the reservoir,  and as such the maximum value of t accepted is: W = 0 = A - 500gal*t

t = A/500 hours

Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }

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Answer:

150%

Step-by-step explanation:

15 / 10 =

1.5 =

150%

Answer:

(x+2)^2 - 6

Step-by-step explanation:

Answer:

ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok

Answer:

step by step

Step-by-step explanation:

y = 3x - 4

Root (x-intercept): y=0     3x-4=0       x=4/3 (or 1 1/3, 1.33333)

y-intercept: x=0   y=4

Answer: 473

Step-by-step explanation: 946 Divided by 2

Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the 3 sides , then

2x - 6 + x + 4 + 10 > 50

3x + 8 > 50 ( subtract 8 from both sides )

3x > 42 ( divide both sides by 3 )

x > 14

(4)

The area is calculated by multiplying length and breadth , then

3(4x - 2) < 138 ( divide both sides by 3 )

4x - 2 < 46 ( add 2 to both sides )

4x < 48 ( divide both sides by 4 )

x < 12

The maximum height reached by the projectile is 12 feet, and it hits the ground approximately 1.228 seconds and 3.772 seconds after being launched.

To find the maximum height reached by the projectile and the time it takes to hit the ground, we can analyze the given quadratic function H(t) = -16t^2 + 72t + 12.

The function H(t) represents the height of the projectile at time t seconds after its launch. The coefficient of t^2, which is -16, indicates that the path of the projectile is a downward-facing parabola due to the negative sign.

To determine the maximum height, we look for the vertex of the parabola. The x-coordinate of the vertex can be found using the formula x = -b / (2a), where a and b are the coefficients of t^2 and t, respectively. In this case, a = -16 and b = 72. Substituting these values, we get x = -72 / (2 * -16) = 9/2.

To find the corresponding y-coordinate (the maximum height), we substitute the x-coordinate into the function: H(9/2) = -16(9/2)^2 + 72(9/2) + 12. Simplifying this expression gives H(9/2) = -324 + 324 + 12 = 12 feet.

Hence, the maximum height reached by the projectile is 12 feet.

Next, to determine the time it takes for the projectile to hit the ground, we set H(t) equal to zero and solve for t. The equation -16t^2 + 72t + 12 = 0 can be simplified by dividing all terms by -4, resulting in 4t^2 - 18t - 3 = 0.

This quadratic equation can be solved using the quadratic formula: t = (-b ± √(b^2 - 4ac)) / (2a), where a = 4, b = -18, and c = -3. Substituting these values, we get t = (18 ± √(18^2 - 4 * 4 * -3)) / (2 * 4).

Simplifying further, we have t = (18 ± √(324 + 48)) / 8 = (18 ± √372) / 8.

Using a calculator, we find that the solutions are t ≈ 1.228 seconds and t ≈ 3.772 seconds.

Therefore, the projectile hits the ground approximately 1.228 seconds and 3.772 seconds after its launch.

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To find the series solution for the differential equation y'' + 2xy' + 2y = 0, we can assume a power series solution of the form:

Now, substitute y(x), y'(x), and y''(x) into the differential equation:

∑(n=0 to ∞) aₙn(n-1) xⁿ⁻² + 2x ∑(n=0 to ∞) aₙn xⁿ⁻¹ + 2 ∑(n=0 to ∞) aₙxⁿ = 0

We can simplify this equation by combining the terms with the same powers of x. Let's manipulate the equation step by step:

We can combine the three summations into a single summation:

∑(n=0 to ∞) (aₙ₊₂(n+1)n + 2aₙ₊₁ + 2aₙ) xⁿ = 0

Since this equation holds for all values of x, the coefficients of the terms must be zero. Therefore, we have:

This is the recurrence relation that determines the coefficients of the power series solution To find the series solution, we can start with initial conditions. Let's assume that y(0) = y₀ and y'(0) = y'₀. This gives us the following initial terms:

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Answer:

5+23+18+8+4,=100

Step-by-step explanation:

plus

The expression is written with parentheses and the signs will be 5 + 23 + 18 x (8 - 4) = 100.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

5 + 23 + 18 x (8 - 4) = 100

Simplify the expression, then we have

5 + 23 + 18 x (8 - 4) = 100

5 + 23 + 18 x 4 = 100

28 + 72 = 100

100 = 100

The expression is written with parentheses and the signs will be 5 + 23 + 18 x (8 - 4) = 100.

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Answer:

202 cm^2

Step-by-step explanation:

SA = 2LW + 2LH + 2WH

SA = 2(4 cm)(5 cm) + 2(4 cm)(9 cm) + 2(5 cm)(9 cm)

SA = 40 cm^2 + 72 cm^2 + 90 cm^2

SA = 202 cm^2

Answer:

im pretty sure its 26

Step-by-step explanation:

.

Answer:

31.304951685

Step-by-step explanation:

Answer:

10.7

Step-by-step explanation:

Answer:

x=3 sorry if I am wrong.

Step-by-step explanation:

(5x-2)=(3x+4)

-3       -3

2x-2=4

   +2  +2

2x=6/2

x=3

Answer:

Step-by-step explanation:

5x +3x +4-2

8x +2

Answer: Andre subtracted 3x from both sides

The area of the surface generated by rotating the parametric curve about the x-axis is π/8.

To find the area of the surface generated by rotating the parametric curve about the x-axis, we can use the formula for the surface area of revolution:

\(A = \int\limits^a_b {2\pi y} \sqrt{(\frac{dx}{d\theta})^2+ (\frac{dy}{d\theta})^2} \, dx\)

In this case, the given parametric equations are:

\(x = cos^3\theta\\\\y = sin^3\theta\)

Let's calculate the derivatives of x and y with respect to θ:

\(\frac{dx}{d\theta} = -3cos^2\theta sin\theta\\\\\frac{dy}{d\theta} = 3sin^2\theta cos\theta\\\)

Now we can substitute these values into the surface area formula:

\(A = \int_{0}^{\pi /2} {2\pi sin^3\theta} \sqrt{(-3cos^2\theta sin\theta)^2+ (3sin^2\theta cos\theta)^2} \, d\theta\)

Simplifying the expression inside the square root:

\(A = \int_{0}^{\pi /2} {2\pi sin^3\theta} \sqrt{9cos^4\theta sin^2\theta+ 9sin^4\theta cos^2\theta} \, d\theta\)

\(A = \int_{0}^{\pi /2} {2\pi sin^3\theta} \sqrt{9cos^2\theta sin^2\theta(cos^2\theta +sin^2\theta)} \, d\theta\)

\(A = \int_{0}^{\pi /2} {2\pi sin^3\theta} \sqrt{9cos^2\theta sin^2\theta} \, d\theta\)

\(A = \int_{0}^{\pi /2} {2\pi sin^3\theta} \quad 3cos^2\theta sin^2\theta \, d\theta\)

\(A = 6\pi \int_{0}^{\pi /2} {sin^4\theta} \quad cos^2\theta d\theta\)

Now, we can use a trigonometric identity to simplify the integral. The identity is:

\(Sin^2\theta = \frac{1-cos2\theta}{2}\)

Using this identity, we can rewrite the integral as:

\(A = 6\pi \int_{0}^{\pi /2} {(\frac{1-cos2\theta}{2})^2 } \quad cos^2\theta d\theta\)

Simplifying further:

\(A = 6\pi \int_{0}^{\pi /2} {(\frac{1+cos^22\theta-2cos2\theta}{4}) } \quad cos^2\theta d\theta\)

\(A = 3\pi /2\int_{0}^{\pi /2} {cos\theta-2cos2\theta cos\theta+\frac{1}{4} cos^3\theta} d\theta\)

Evaluating the limits of integration:

\(A = 3\pi /2[\frac{1}{2} sin\theta-\frac{1}{3} cos^3\theta+\frac{1}{12} cos^32\theta]^{\pi /2}_0\)

Evaluating =

A = π/8

Therefore, the area of the surface generated by rotating the parametric curve about the x-axis is π/8.

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Answer:

By distributing the parenthesis

Step-by-step explanation:

Given

5(3x - 6) ← multiply each term in the parenthesis by 5

= 15x - 30 ← as required

Answer:

c

Step-by-step explanation: