Answer:
4.0s
Explanation:
v = v_0 + a*t -> t = (v - v_0) / a
v = 20.0m/s, v_0 = 8.0 m/s, a = 3.0 m/s^2
t = (20.0 - 8.0) / 3.0 = 4.0s
Answer:
t = 4.0 s
Explanation:
Given:
V₁ = 8.0 m/s
V₂ = 20.0 m/s
a =3.0 m/c²
______________
t - ?
a = ( V₂ - V₁ ) / t
t = ( V₂ - V₁ ) / a
t = ( 20.0 - 8.0 )/ 3.0 = 12.0 /3.0 = 4.0 s
A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?
Answer:
A) E / B = 2.99 10⁸ V/ mT, B) B = 2.50 10⁻⁶ T
Explanation:
A) the expressions for the energy densities are:
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
indicate that the two densities are equal
½ ε₀ E² = ½ B² /μ₀
E / B = 1 /\(\sqrt{\epsilon_o \ \mu_o }\)
we calculate
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹9
E / B = 2.99 10⁸ V/ mT
B) for this case E = 750 V / m, ask the magnetic field
E / B = 1 /\(\sqrt{\epsilon_o \ \mu_o}\)
B = E \(\sqrt{\epsilon_o \ \mu_o}\)
we calculate
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
Energy densities can be expressed as
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
When the two densities are equal we use the formula
½ ε₀ E² = ½ B² /μ₀
E / B = 1 / μ₀
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹
E / B = 2.99 10⁸ V/ mT
If the magnetic field and electric-field energy densities are equal and E = 750 V / m, we can deduce thatE / B = 1 / √ ξ₀ μ₀
B = E √ ξ₀ μ₀
We substitute the values into the equation
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
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In recent years, assistive technologies have been developed to give people with disabilities equal access to resources. Examples include wheelchair ramps, voice-recognition software, and screen readers. Which statement best explains how societal demand guided the development of these technologies?
The statement which best explains how market forces supply and demand guided the development of the new technologies is the statement: Engineers recognized the disparity in access to resources and decided to develop systems that would address the issue; option D.
What is technology?Technology is the application of knowledge to reach practical goals.
Technology has affected our society and its surroundings in a number of ways which include:
technology has helped develop more advanced economiesTechnology has improved the medical fieldIn recent years, assistive technologies have been developed to give people with disabilities equal access to resources. Examples include wheelchair ramps, voice-recognition software, and screen readers.
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Complete question:
In recent years, assistive technologies have been developed to give people
with disabilities equal access to resources. Examples include wheelchair
ramps, voice-recognition software, and screen readers. Which statement best
explains how the market forces of supply and demand guided the
development of these technologies?
O A. As businesses became aware of the demand for equal access,
they began to invest in research and development to meet the
desires of their customers.
O B. As businesses developed assistive technologies, they began to
advertise their ability to provide equal access to consumers.
C. When assistive technologies became widely available, the public
demand for their universal adoption increased.
D. Engineers recognized the disparity in access to resources and
decided to develop systems that would address the issue.
At a certain distance from a point charge, the potential and electric-field magnitude due to that charge are 4. 98 v and 16. 2 v/m , respectively. (take v = 0 at infinity. ).
The distance r or the charge Q from the given information as there is only one equation for two unknowns. We need another equation to solve for r and Q.
Using the formula for the electric potential due to a point charge Q at a distance r:
\(V = k Q / r\)
where k is the Coulomb constant \((k = 8.99 \times 10^9 Nm^2/C^2)\)
We can find the charge Q of the point charge by rearranging the formula as:
\(Q = V r / k\)
Substituting the given values, we get:
\(Q = (4.98 V) (r) / (8.99 \times 10^9 Nm^2/C^2)\)
Similarly, we can find the electric field magnitude E due to the point charge using the formula:
\(E = k Q / r^2\)
Substituting the given values, we get:
\(E = (8.99 \times 10^9 Nm^2/C^2) (Q) / r^2 = (8.99 \times 10^9 Nm^2/C^2) [(4.98 V)\)(r) / \((8.99 \times\)\(10^9 Nm^2/C^2)] / r^2\)
Simplifying, we get:
\(E = (4.98 V) / r\)
and
\(Q = (4.98 V) (r) / (8.99 \times 10^9 Nm^2/C^2)\)
Note that we cannot determine the distance r or the charge Q from the given information as there is only one equation for two unknowns. We need another equation to solve for r and Q.
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A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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500000000 in standard form
Answer:
5.0 x 10^8
Explanation:
because u moved it 8 times to it places
A car is traveling north with a velocity of 18.1 m/s. Find the velocity of the car after 7.50 seconds if the acceleration is 2.4 m/s^2. *
In scientific terms, anything that represents something else is called a
O theory
O model
O hypotnesis
O chemical bond
The two objects shown are both positively charged. Which position could possibly have zero electric field?
- A
- B
- C
- D
- They could all have zero electric field
The position they could possibly have zero electric field is C.
What is electric field?An electric field is a physical field that exists in the space surrounding electrically charged particles or objects. It is a vector field, meaning that it has both magnitude and direction.
When a charged particle is present in a space, it creates an electric field that exerts a force on any other charged particles in the vicinity.
The strength of the electric field at any given point is defined as the force per unit charge that a small test charge would experience if placed at that point.
The magnitude and direction of the electric field depend on the distance between the charges and their magnitudes. The electric field is stronger when the charges are closer together and weaker when they are farther apart.
So position they could experience zero electric field is C, assuming point C if very far from the two charges.
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What does the phrase “constant velocity” indicate?
a. zero distance
b. zero acceleration
c. constant acceleration
d. deceleration
A 2[kg] rock and a 4[kg] rock are lifted to a height of 10[m].
How much PE does each rock have?
Answer:
See below
Explanation:
Potential Energy = mgh
for 2 rock = 2 * 9.81 * 10 = 196.2 j
for 4 rock = 4 * 9.81 * 10 = 392.4 j
A ball is rolling with a constant acceleration of 13 m/s starting from rest. How long will it take to increase its velocity to a final speed of 62 m/s?
Time taken : 4.77 s
Further explanationGiven
a = 13 m/s²
vf = final velocity = 62 m/s
Required
time taken
Solution
An equation of uniformly accelerated motion
\(\large {\boxed {\bold {x=xo+vo.t+\frac {1} {2} at ^ 2}}}\)
vf = vo + at
vf² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
Input the value :
vo =0 ⇒from rest
vf=at
62 m/s = 13 m/s².t
t = 62 : 13
t = 4.77 s
A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?
The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.
The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.
emf = N(dФ/dt)
where;
N is number of turns of the wireФ is magnetic fluxФ = BA
where;
B is magnetic field strengthA is the area of the loopemf = NBA/t
A = πr²
A = π x (0.13)²
A = 0.053 m²
emf = NBA/t
emf = (1 x 3.746 x 0.053)/(1.16)
emf = 0.171 V
Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.
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You spaceship has a snazzy lounge called Ten-Forward that needs a new spacecouch. Sadly the couch you bought is too long and won't fit into your car when it is stationary. The couch has a length Lc = 14.0 m and mass m = 49 kg, and your shuttlecraft has a length of L = 9.0 m How fast would you need to run, in terms of the speed of light c, in order to get the couch to fit inside the length of the shuttlecraft?
Answer:
v = speed
c = speed of light
using the equation
L = Lc Sqrt( 1 - (v/c)2)
9 = 14 Sqrt( 1 - (v/c)2)
v/c = 0.765
v = 0.765 c
Mark walked 2 miles east than 1 mile north how would you determine his total displacement
They could determine it by counting their total amount of miles mark went by the directions he went to walk those miles.
10. Explain why a power plant doesn’t make electricity.
Answer: The power station converts stored chemical energy in the fuel to kinetic energy in the raised temperature of the steam that pushed a turbine to rotate the generator that makes electricity.
So chemical to thermal (kinetic) to thermal to kinetic to electrical. Then mostly to heat or movement.
Loads of losses, thermal, mostly.
Explanation: hopes this helps
In all of the power plants, electricity is generated by rotating turbine inside a magnetic field. That is why, power plant transfers mechanical energy into electric energy. That is why, it doesn’t make electricity.
What is power plants?
An industrial facility for the production of electricity is referred to as a power plant. In most cases, power plants are wired into a grid.
A revolving device called a generator, which transforms mechanical power into three-phase electric power, is found in many power plants. An electric current is produced by the movement of a conductor in relation to a magnetic field.
The majority of power plants throughout the world produce electricity by burning fossil fuels including coal, oil, and natural gas. Nuclear energy and the usage of renewable energy sources including solar, wind, geothermal, and hydroelectricity are examples of low-carbon power sources.
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definition of momentum
Answer:
Momentum is a term used in physics to describe an object's resistance to change its motion. It is a measure of an object's mass and velocity and can be mathematically represented by the equation p = mv, where p is momentum, m is mass, and v is velocity.
Momentum is a vector quantity, meaning it has both magnitude and direction. It can be thought of as the amount of motion an object possesses in a particular direction. For example, a large truck traveling at a high speed has more momentum than a small car traveling at a slower speed, even though they both may have the same mass.
In physics, momentum plays a crucial role in determining how objects will react when they collide. If two objects collide and have equal and opposite momentum, they will typically bounce off each other. However, if one object has much more momentum than the other, it is likely to push the other object aside and continue on its original path.
It is also important to note that momentum is conserved in isolated systems. This means that if two or more objects collide or interact with each other, the total momentum before the collision is equal to the total momentum after the collision.
In conclusion, momentum is a fundamental concept in physics that helps to describe and understand the motion of objects. It is a combination of an object's mass and velocity, and it determines how objects will interact when they collide.
Please mark me brainliest if I helped.
Find the magnitude of the Sun's gravitational force on the Earth when the Earth is at perihelion and at aphelion. The perihelion and aphelion distances are 1.48 ✕ 1011 m and 1.52 ✕ 1011 m, respectively.
Answer:
Explanation:
Force F = GMm / R²
mass of the sun M = 1.99 x 10³⁰ kg
mass of the earth = 5.97 x 10²⁴ kg
value of G = 6.67 x 10⁻¹¹
for perihelion point R = 1.48 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.48 x 10¹¹ )²
= 36.17 x 10²¹ N
for aphelion point R = 1.52 x 10¹¹ m
Force = 6.67 x 10⁻¹¹ x 1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.52 x 10¹¹ )²
= 34.29 x 10²¹ N
(17%) Problem 2: The drawing shows a small sphere of mass m=0.26 g that carries a charge of q = 85 x 10-10 C. The sphere is attached to one end of a very thin silk string of length L = 6.25 cm. The other end of the string is attached to a large vertical conducting plate that has a charge density of o = 30 x 10-6C/m². + + + + + + L m, A 25% Part (a) Write an expression for the magnitude of the electric field due to the charge distribution on the conductive plate. E = 0 Grade Summary Deductions 0% Potential 100% €0 B 0 Y b 0 Submissions Attempts remaining: 20 (% per attempt) detailed view d h ( 789 HOME 1456 1 23 + 0 END VO BACKSPACE GEL CLEAR g k j m n P S Submit Hline Feedback I give up! Hints: for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Date Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work. Time Answer Hints Feedback 24 25% Part (b) Write an expression for the horizontal component of the net force acting on the charged sphere in terms of the tension T in the string, the electric field, and the given variables. A 25% Part (c) Write an expression for the vertical component of the net force acting on the charged sphere in terms of the tension T in the string and the given variables. 425% Part (d) What is the angle in degrees that the string makes with respect to the vertical?
θ = 39.7º is the angle in degrees that the string makes with respect to the vertical using Newtons law.
In each exercise, we construct the equations at the equilibrium point using Newton's second law for the sphere. We'll assume that plate 1 is on the left for this exercise.
Y Axis
Y= -W = 0 = W
X axis
X= - F_{e2} + Tₓ = 0
Let's utilize trigonometry to determine the tension's component parts. We gauge the angle in relation to the vertical
sin θ = Tₓ / T
cos θ = T_{y} / t
Tₓ = T sin θ
T_{y} = T cos θ
Gauss's law can be used to determine the electric field of each leaf. Since a cylinder forms a Gaussian surface, the component of the field perpendicular to the cylinder's base is the one containing electric flow.
F = ∫ E. dA
The flow is towards both sides of the plate in this instance, and the scalar product is reduced to the algebraic product.
F = 2E A = q_{int} / ε₀
let's use the concept of surface charge density
σ = q_{int} / A
we substitute
2E A = σ A /ε₀
E = σ / 2ε₀
T cos θ = mg
- q σ₁ / 2ε₀ - q σ₂ /2ε₀ + T sinθ = 0
we introduce t in the second equations
- q /2 ε₀ (σ₁ + σ₂) + (mg / cos θ) sin θ = 0
mg tan θ = q /2ε₀ (σ₁ + σ₂)
θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)
data indicates the mass of 0.26 g = 0.26 10⁻³ kg
give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²
let's calculate
θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2 (6.25 10⁻¹² *0.26 10⁻³ 9.8))
θ = tan⁻¹ 8.3 10⁻¹)
θ = 39.7º
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An Aluminum cube with size L is immersed in a box containing water and Mercury. Assuming that the cube is in equilibrium in the horizontal position, compute the height of the centre of mass of the cube with respect to the surface separating water and Mercury.
density of water ρw = 1gcm−3
density of Mercury ρHg = 13.6gcm−3
density of Aluminum ρAl = 2.7gcm−3
L = 10cm.
Answer:
B = (dm v1 + dw v2) g where B = buoyant force and d the density
B = da ( v1 + v2) g where v1 is volume of Hg displaced and v2 the water
(dm v1 + dw v2) = da ( v1 + v2)
v1 ( dm - da) = v2 ( da - dw)
v1 / v2 = (2.7 - 1) / (13.6 - 2.7) = .156
L1 = .156 L2 where L1 is length of side in Hg and L2 length of side in water
Since the center of mass is at L / 2 and L1 + L2 = L
L1 = .156 (L - L1)
L1 = .156 L / 1.156 = .135 L
L / 2 - .135 L = .365 L above the interface of the liquids
What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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Patrick walks 6 meters to the south, 3 meters west, 2 meters to the north, and 5 meters to the east. Which of the following is true?
A. His displacement was 4 meters.
B. His distance traveled was 6 meters.
C. His distance traveled was 16 meters.
D.His displacement was 17 meters.
Hector stretches a spring with a spring constant of 3 N/m until it is extended by 50 cm. What is the elastic potential energy stored by the spring?
The elastic potential energy stored in the spring is 0.375 J.
The formula for elastic potential energy is:
E = 1/2 * k * x^2
where:
* E is the elastic potential energy in Joules
* k is the spring constant in N/m
* x is the distance the spring is stretched or compressed from its equilibrium position in meters
In this problem, we have:
* k = 3 N/m
* x = 0.5 m (50 cm)
Substituting these values into the formula, we get:
E = 1/2 * 3 * 0.5^2 = 0.375 J
Therefore, the elastic potential energy stored in the spring is 0.375 J.
Four different insect mouthparts are shown which is best adapted for chewing leaves YXWZ
Answer:
i think its W, in the picture it looks like a cricket
Explanation:
i got it right on edg 2020
Answer:
w
Explanation:
edg 2921
A 2,600 kg SUV traveling west at 15 m/s collides head on with a 1,300 kg four door sedan traveling east at 20 m/s. Determine the speed and direction of the two cars immediately after impact if they lock together.
Answer:
Explanation:
From Law of conservation of momentum,
m1u1+m2u2 = m1v1+m2v2 [Law of conservation of momentum]
m1 = 2600kg
u1 = 15m/s
m2 = 1300kg
u2 = -20m/s [as it is moving in opposite direction]
here, after impact, cars lock with each other so v (final velocity) is the same for both cars, i.e., v1 = v2
(2600)(15)+(1300)(-20) = (2600)v1+(1300)v2
39000-26000 = (2600+1300)v1 [as v1 = v2]
v1 = 13000/3900
v1 = 3.33 m/s
Here, m1v1 = 2600x3.33 = 8658kgm/s
m2v2 = 1300x3.33 = 4329kgm/s
As final momentum of car 1 is higher than that of car 2, both cars will move in direction of car1, that is, west direction.
Energy Transformation
A car with a mass of 2000 kg is traveling down the highway at a constant 20 m/s. How much kinetic energy does it have?
100 J
50 J
400.000 J
40.000 J
Answer:
K =400000 J
Explanation:
Kinetic Energy
Is the energy an object has due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
\(\displaystyle K=\frac{1}{2}mv^2\)
Where:
m = mass of the object
v = speed at which the object moves
The kinetic energy is expressed in Joules (J)
The car has a mass of m=2000 Kg and travels at v=20 m/s. Calculating the kinetic energy:
\(\displaystyle K=\frac{1}{2}2000*20^2\)
Calculating:
K =400000 J
Answer #49 please and thank you
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit
Answer:
1.74
Explanation:
right on acellus
Answer:
1.74
Explanation:
acellus
5 points
Which is "NOT“ a Top 10 Reason for Being Physical Active *
Gives you a feelings of well-being: Relieves your stress: Helps you develop social skills
Helps you learn how to compete: Helps you manage your weight: Strengthens your
heart and lungs
Keeps your blood vessels healthy. Strengthens your bones; Tones your muscles
Makes it hard to go to sleep at night
Answer:
Makes it hard to go to sleep at night
Explanation:
In a pipe of 90mm diameter, water is flowing with a mean velocity of 2m/s at a gauge pressure of 350KN/M². Determine the total head, if the pipe is 8m above the datum.
The total head of the pipe is 430,400 Pa.
What is the total head of the pipe?
The total head of the pipe is the total pressure of the pipe and it is calculated as follows;
Pt = Pi + ¹/₂ρv² + ρgh
where;
Pi is the gauge pressure ρ is density of waterv is the speed of the waterh is the height of the water above the groundPt = ( 350,000) + ¹/₂(1000)(2)² + (1000 x 9.8 x 8)
Pt = 430,400 Pa
Thus, the total head or total pressure of the pipe depends on the density of water, speed of water and height above datum.
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Which of the following gases is the major byproduct of fossil fuel combustion?
methane
water vapor
sulfuric acid
carbon dioxide
Answer:
Carbon dioxide and water vapour
Explanation:
So the products of a combustion reaction are primarily:
carbon dioxide + water vapour, however other gases such as nitrogen, methane, and sulphur dioxide are also produced in smaller concentrations.
Carbon dioxide and water vapour are the main byproducts
Answer:
Carbon dioxide
Explanation:
The major byproduct of fossil fuel combustion is carbon dioxide. When fossil fuels such as coal, oil, and natural gas are burned, they release carbon dioxide into the atmosphere. This is because fossil fuels are made up of hydrocarbons, which are compounds made up of carbon and hydrogen. When these compounds are burned, they react with oxygen in the air to produce carbon dioxide \(\rm (CO_2)\) and water vapor \(\rm (H_2O)\).
Methane is also produced during fossil fuel combustion, but in smaller amounts compared to carbon dioxide. Sulfuric acid is not a byproduct of fossil fuel combustion, but rather a product of the reaction between sulfur dioxide \(\rm (SO_2)\) and water vapor in the atmosphere. While water vapor is also produced during fossil fuel combustion, it is not considered a major byproduct, as it is a natural component of the air and atmosphere.