Answers
Answer:
The more mass the more kinetic energy it has
Explanation:
like a plastic ball and a metal one the metal one will fall faster.
hope this helps
Related Questions
item13 time remaining 25 minutes 46 seconds00:25:46 item 13 time remaining 25 minutes 46 seconds00:25:46 a pump consumes 10 hp of power to raise water in a building. if the mechanical efficiency of the pump is 85 percent, determine the rate of mechanical energy increase of the water. multiple choice 5.3 kj 5.3 kw 6.3 kj 6.3 kw
Answers
Rate of mechanical energy increase of water is 6.3 kW (option D).
What is Mechanical efficiency of the pump?Mechanical efficiency of a pump is the ratio of the actual mechanical energy output delivered by the pump to the input energy supplied to the pump. It is a measure of how effectively the pump converts the input power into useful mechanical work.
In other words, it is the ratio of the power output of the pump to the power input, expressed as a percentage. Mathematically,
Mechanical efficiency = (Power output / Power input) x 100%
The rate of mechanical energy increase of the water can be calculated by multiplying the power consumed by the pump with its mechanical efficiency.
Given,
Power consumed by the pump = 10 hp
Mechanical efficiency of the pump = 85% = 0.85
Rate of mechanical energy increase of water = Power consumed x Mechanical efficiency
Rate of mechanical energy increase of water = 10 hp x 0.85 = 8.5 hp
To convert hp to kW, we can use the conversion factor 1 hp = 0.746 kW
Rate of mechanical energy increase of water = 8.5 hp x 0.746 kW/hp = 6.329 kW
The answer is 6.3 kW (option D).
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QUESTIONS
An ant walks eastward for 11.1 cm, then northward for 4,4 cm and finally westward for 11.1 cm. What is the magnitude of the displacement in cm Do
not include the units in your answer.
Answers
Answer:
4.4.
Explanation:
Hello,
In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.
In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.
Regards-
6 A test of a driver's perception/reaction time is being conducted on a special testing track with level, wet pavement and a driving speed of 50 mi/h. When the driver is sober, a stop can be made just in time to avoid hitting an object that is first visible 385 ft ahead. After a few drinks under exactly the same conditions, the driver fails to stop in time and strikes the object at a speed of 30 mi/h. Determine the driver's perception/reaction time before and after drinking. (Assume practical stopping distance.)
Answers
Answer:
a. 10.5 s b. 6.6 s
Explanation:
a. The driver's perception/reaction time before drinking.
To find the driver's perception time before drinking, we first find his deceleration from
v² = u² + 2as where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 0 m/s (since he stops), a = deceleration of driver and s = distance moved by driver = 385 ft = 385 × 0.3048 m = 117.35 m
So, a = v² - u²/2s
substituting the values of the variables into the equation, we have
a = v² - u²/2s
a = (0 m/s)² - (22.35 m/s)²/2(117.35 m)
a = - 499.52 m²/s²/234.7 m
a = -2.13 m/s²
Using a = (v - u)/t where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 0 m/s (since he stops), a = deceleration of driver = -2.13 m/s² and t = reaction time
So, t = (v - u)/a
Substituting the values of the variables into the equation, we have
t = (0 m/s - 22.35 m/s)/-2.13 m/s²
t = - 22.35 m/s/-2.13 m/s²
t = 10.5 s
b. The driver's perception/reaction time after drinking.
To find the driver's perception time after drinking, we first find his deceleration from
v² = u² + 2as where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 30 mi/h = 30 × 1609 m/3600 s = 13.41 m/s, a = deceleration of driver and s = distance moved by driver = 385 ft = 385 × 0.3048 m = 117.35 m
So, a = v² - u²/2s
substituting the values of the variables into the equation, we have
a = v² - u²/2s
a = (13.41 m/s)² - (22.35 m/s)²/2(117.35 m)
a = 179.83 m²/s² - 499.52 m²/s²/234.7 m
a = -319.69 m²/s² ÷ 234.7 m
a = -1.36 m/s²
Using a = (v - u)/t where u = initial speed of driver = 50 mi/h = 50 × 1609 m/3600 s = 22.35 m/s, v = final speed of driver = 30 mi/h = 30 × 1609 m/3600 s = 13.41 m/s, a = deceleration of driver = -1.36 m/s² and t = reaction time
So, t = (v - u)/a
Substituting the values of the variables into the equation, we have
t = (13.41 m/s - 22.35 m/s)/-1.36 m/s²
t = - 8.94 m/s/-1.36 m/s²
t = 6.6 s
What can happen when the Earth, Moon, and Sun are lined up in the order shown below?(study island)
Answers
When the Earth, Moon, and Sun are lined up, it can result in either a solar eclipse or a lunar eclipse, depending on the phase of the Moon.
What happens when the Earth, Moon, and Sun are lined up in the order shown?When the Earth, Moon, and Sun are lined up in the order shown below, it can result in a syzygy, which is a straight-line configuration of three celestial bodies.
The order is as follows: Sun --- Moon --- Earth
The specific effects of this configuration depend on whether it occurs during a new moon or full moon.
During a new moon, the Moon is between the Earth and Sun, and the side of the Moon facing the Earth is not illuminated by sunlight. This is also known as a solar eclipse, as the Moon's shadow falls on a portion of the Earth. This can only occur during a narrow region of the Earth's surface, and those in that region will see the Sun completely blocked by the Moon.
During a full moon, the Earth is between the Sun and Moon, and the side of the Moon facing the Earth is fully illuminated by sunlight. This is also known as a lunar eclipse, as the Earth's shadow falls on the Moon. This can be seen from anywhere on the night side of the Earth, as long as the Moon is above the horizon.
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The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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Using the following information to determine the young's modulus for the unknown material, the radius of the material is 4 cm. while gravitational
acceleration g=10m/s?
initial length (cm) 25
final length (cm)25.7
mass (gm) 200
Answers
Answer:
14285.71N/m2
Explanation:
Young modulus known as modulus of elasticity is defined as;
E = σ/ε
Where E is young modulus
ε is strain defined as extention / length
σ is stress defined as force /area
Let's calculate σ;
Force = mass× gravity =200/1000. × 10 =0.2kg× 10 = 2N
The area impacted by the force is raduis surface of the wire and it's calculated thus;
πr^2 = 22/7 × (0.04)^2 ; 4cm in m = 0.04m=0.005m2
Hence σ = 2/0.005=400N/M2
Let's calculate ε;
ε= extension/ original length
extension = final length - original length
extension=25.7-25=0.7cm= 0.007m
ε= 0.7/25
Hence E = 400/ 0.7/25
E = 400 × 25/ 0.7= 14285.71N/m2
Famed stunt pilot, Cleonvia Thread, pulls out rapidly from a dive. He is traveling at 222 mi/h at the bottom of his trajectory, and at that instant is traveling on a curve of radius 820 ft. r v What acceleration does he
Answers
Answer:
0.39 m/s²
Explanation:
From the question,
a = v²/r.................... Equation 1
Where v = velocity, r = radius.
Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.
Substitute thses values into equation 1
a = 9.83²/249.94
a = 96.63/249.94
a = 0.39 m/s²
Hence the acceleration is 0.39 m/s²
The value of the centripetal acceleration is equal to 4g.
Data Given;
v = 222mi/hdistance (r) = 820ftCentripetal AccelerationUsing formula of centripetal acceleration,
\(a_c = \frac{v^2}{r}\\ \)
v = (222 * 1.467) ft/s
v = 325.6 ft/s
substitute the values into the formula
\(a_c = v^2/r\\ a_c = \frac{325.6^2}{820}\\ a_c = 129.28 ft/s^2\\ \)
But the value of g = 32.174 ft/s62
This makes a = 4g.
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A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. What is the mass of this volume of water in kilograms
Answers
A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. The mass of this volume of water in kilograms is 60.4 kilograms (kg).
To calculate the mass of water in the rectangular container, we need to multiply the volume of water by the density of water.
1. Volume of water:
The volume of the rectangular container is given as:
Length (L) = 19 cm
Width (W) = 51 cm
Height (H) = 62 cm
The volume of water (V) is calculated as:
V = L × W × H
Converting the dimensions to meters:
L = 19 cm = 0.19 m
W = 51 cm = 0.51 m
H = 62 cm = 0.62 m
V = 0.19 m × 0.51 m × 0.62 m
V ≈ 0.0604 cubic meters (\(m^3\))
2. Density of water:
The density of water (ρ) is approximately 1000 kilograms per cubic meter (kg/\(m^3\)).
3. Mass of water:
Mass (m) = Volume × Density
m = 0.0604 m^3 × 1000 kg/\(m^3\)
m = 60.4 kilograms (kg)
Therefore, the mass of the volume of water in the rectangular container is approximately 60.4 kilograms (kg).
It's important to note that the density of water can vary slightly depending on temperature and impurities, but for most practical purposes, a density of 1000 kg/\(m^3\)is commonly used.
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A ball is moving up a hill at 20 meters per second, and is decelerating at a uniform rate of 2 meters per second squared. What is its velocity after 5 seconds? Assume the direction up the hill is positive.
Answers
Answer:
-12meters per secondExplanation:
2^5=32-20=-12 meters per sec (going backwards).
If this is correct pls mark me. brainly to let me know, tyy C:
Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answers
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km
Why did these observations persuade Galileo that the geocentric view of Ptolemy
Answers
Answer:
Such phases could only be explained if the planet Venus orbited the Sun. Ptolemy's Geocentric Model could not explain Venus's phases. Galileo was well aware that Ptolemy was mistaken.
Explanation:
Hope it helps:)
PLEASE ANSWER 50 points
A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consider making to the design?
O increase the force that the engine provides
O decrease the force that the engine provides
O increase the mass of the car
O decrease the mass of the car
O increase the top velocity the car can travel
O decrease the top velocity the car can travel
Answers
a. 2.00kg object is subject to three force that gives acceleration a =8m/s^2 i +6m/s j if two of three forces are f1 =(30.0N)+(16N )and f2 =-(12.0N)+(8.0N) find the third force
Answers
By Newton's second law, the net force on the object is
∑ F = m a
∑ F = (2.00 kg) (8 i + 6 j ) m/s^2 = (16.0 i + 12.0 j ) N
Let f be the unknown force. Then
∑ F = (30.0 i + 16 j ) N + (-12.0 i + 8.0 j ) N + f
=> f = (-2.0 i - 12.0 j ) N
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer distance
Please show working
Answers
Distance = (speed) x (time)
Car A: Distance = (8 m/s) x (43 s) = 344 meters
Car B: Distance = (7 m/s) x (50 s) = 350 meters
350 meters is a longer distance than 344 meters.
Car-B traveled a longer distance than Car-A did.
Answer:
\(\boxed {\boxed {\sf Car \ B : 350 \ meters }}\)
Explanation:
Distance is equal to the product of speed and time.
\(d=s*t\)
1. Car A
Car A has a speed of 8 meters per second and travels for 43 seconds.
\(s= 8 \ m/s \\t= 43 \ s\)
Substitute the values into the formula.
\(d= 8 \ m/s *43 \ s\)
Multiply and note that the seconds will cancel out.
\(d= 8 \ m*43= 344 \ m\)
2. Car B
Car B has a speed of 7 meters per second and travels for 50 seconds.
\(s= 7 \ m/s \\t= 50 \ s\)
Substitute the values in and multiply.
\(d= 7 \ m/s * 50 \ s\)
\(d= 7 \ m * 50 = 350 \ m\)
350 meters is a longer distance than 344 meters, so Car B traveled the longer distance.
You want to average 90 km/h on a car trip. You cover the first half of the distance at an
average speed of 48 km/h.
a) What average speed must you have for the second half of the trip to meet your goal?
b) Is this reasonable? Note that the velocities are based on half the distance, not half the
time.
Answers
(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.
(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
What is average velocity?
Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
average velocity = total distance / total time
v = (d)/(0.5d/v₁ + 0.5d/v₂)
where;
v is the average velocityv₁ is the average velocity during the first halfv₂ is the average velocity during the second half90 km/h = (d) / (0.5d/48 + 0.5d/v₂)
90(0.5d/48 + 0.5d/v₂) = d
0.9375d + 0.5d/v₂ = d
d(0.9375 + 0.5/v₂) = d
0.9375 + 0.5/v₂ = 1
0.5/v₂ = 0.0625
v₂ = 0.5/0.0625
v₂ = 8 km/h
Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.
The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
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A slanted surface used to raise an object is a(n)
Answers
Answer:
Inclined Plane
Explanation:
a stone is tied to a string and whirled in a vertical circle at a radius. which of the following cannot be true?
Answers
The stone is travelling in a straight line can not be true in a vertical circle at a radius.
What is vertical circle?
A vertical circle is a path that follows a vertical line in a three-dimensional space. It is a type of circular trajectory, with the center point of the circle vertically above or below the starting and ending points of the path. Vertical circles are used in mathematics and engineering to describe the motion of objects in space. The path of a vertical circle is a helix, which is a spiral with a constant radius, and can be defined by a parametric equation. Vertical circles can be used to define the motion of a satellite, or an aircraft in a corkscrew maneuver. In terms of physics, a vertical circle is an example of a non-uniform circular motion, as the speed of the object changes throughout the path.
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Complete Question
a stone is tied to a string and whirled in a vertical circle at a radius. which of the following cannot be true?
A) The stone is travelling in a straight line
B) The stone is travelling in a circular path
C) The stone is travelling at a constant speed
D) The stone is travelling in an elliptical path
4.) A hydroelectric dam runs water thru turbines that are connected to
generators to create electricity. What energy does the dam transfer to electrical
energy?
Answers
Answer:
Explanation:
A turbine and generator produce the electricity
"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.
When an automobile moves towards a listener, the sound of its horn seems relatively
a. Low pitched (low frequency) b. High Pitched (high frequency)
c. Normal (no change in frequency)
Answers
Answer:
Higher Pitched! (b)
Explanation:
The Doppler effect makes it seem high pitched, as the sound waves are mushed together at a higher frequency, while moving away, the sound waves spread out like a lower frequency wave!
a sound wave traveling through a certain freshwater lake has a frequency of 257.2hz and a wavelength of 3.25m. if the water conditions are held constant, all sound waves will travel at the save speed through water. use this fact to calculate the wavelength of a sound wave with a frequency of 415.3hz. (show work pls<3)
Answers
The wavelength of the sound wave with a frequency of 415.3 Hz is approximately 3.565 m.
How to determine wavelength?The speed of sound in water is approximately 1482 m/s. Use the formula v = f × λ, where v = velocity (speed of sound), f = frequency, and λ = wavelength.
Given:
Frequency of the first sound wave (f₁) = 257.2 Hz
Wavelength of the first sound wave (λ₁) = 3.25 m
Velocity of sound in water (v) = 1482 m/s
Rearrange the formula to solve for λ₂ (wavelength of the second sound wave):
v = f × λ
λ = v / f
Substituting the values:
λ₂ = v / f₂
= 1482 m/s / 415.3 Hz
Calculating:
λ₂ ≈ 3.565 m
Therefore, the wavelength of the sound wave with a frequency of 415.3 Hz is approximately 3.565 m.
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A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?
Answers
The waves produced by a vibrating tuning fork are longitudinal waves, also known as compression waves.
What are Longitudinal Waves?Longitudinal waves are waves that oscillate along the direction of propagation, meaning they create alternating regions of compression and rarefaction in the medium through which they travel.
In the case of a vibrating tuning fork, the tines of the fork move back and forth, causing the surrounding air to alternately compress and expand. These pressure changes propagate through the air as longitudinal waves.
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Interactive Solution 8.29 offers a model for this problem. The drive propeller of a ship starts from rest and accelerates at 2.38 x 10-3 rad/s2 for 2.04 x 103 s. For the next 1.48 x 103 s the propeller rotates at a constant angular speed. Then it decelerates at 2.63 x 10-3 rad/s2 until it slows (without reversing direction) to an angular speed of 2.42 rad/s. Find the total angular displacement of the propeller.
Answers
Answer:
Δθ = 15747.37 rad.
Explanation:
The total angular displacement is the sum of three partial displacements: one while accelerating from rest to a certain angular speed, a second one rotating at this same angular speed, and a third one while decelerating to a final angular speed.Applying the definition of angular acceleration, we can find the final angular speed for this first part as follows:\(\omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)\)
Since the angular acceleration is constant, and the propeller starts from rest, we can use the following kinematic equation in order to find the first angular displacement θ₁:\(\omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)\)
Solving for Δθ in (2):\(\theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)\)
The second displacement θ₂, (since along it the propeller rotates at a constant angular speed equal to (1), can be found just applying the definition of average angular velocity, as follows:\(\theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)\)
Finally we can find the third displacement θ₃, applying the same kinematic equation as in (2), taking into account that the angular initial speed is not zero anymore:\(\omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)\)
Replacing by the givens (α, ωf₂) and ω₀₂ from (1) we can solve for Δθ as follows:\(\theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)\)
The total angular displacement is just the sum of (3), (4) and (6):Δθ = θ₁ + θ₂ + θ₃ = 5044.12 rad + 7252 rad + 3451.25 rad ⇒ Δθ = 15747.37 rad.imagine that you have an electric car and all of the recaptured energy is put back into the battery that powers your car what speed could your car cheat from rest by using only the recaptured energy from part B
Answers
Answer:
Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.
Explanation:
a defender running away from a goalkeeper at 5m/s is hit in the back by the goal kick. the ball stops dead and the players speed increases to 5.5m/s if the ball had a mass of 500g and the player mass is 70k how fast was the ball moving?
Answers
The goal kick strikes a defender racing at 5 m/s away from a goalkeeper in the back. The ball was moving at a speed of 70 m/s if it weighed 500g and the player's mass was 70k.
Why does the goalie in a football game pull his hands back after holding the ball that has been shot towards the goal?The goalkeeper extends the amount of time he has to hold the ball by pulling his hands back. He lessens the force (rate of change of momentum) the football exerts on him by lengthening the time.
Write the formula for momentum and define it.A vector quantity, momentum. A body's momentum is equal to P=m.v if it is travelling at a speed of v while having mass m. P=mv describes the magnitude of the momentum. Because momentum is a function of mass and velocity, its unit is the product of those two quantities.
By using conservation of momentum,
Initial momentum = Final momentum
(5 x 70) + (v x 0.5) = (5.5 x 70) + (0 x 0.5)
350 + 0.5v = 385 + 0
0.5v = 35
v = 70 m/s
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how to calculate the end point on a wave when x is greater than zero
Answers
Answer:
get good
Explanation:
get good
djhdhdhdjdusigxig 9gc
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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How much work is done when a 40 N force is applied to slide a box 5 meters?
Answers
Answer:
200j
Explanation:
see in the figure
the answer is in the figure and above
A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be
Answers
A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².
When a constant force acts on a wagon, it causes the wagon to accelerate We can calculate the wagon's acceleration using Newton's second law, which states that the force acting on an object is directly proportional to its acceleration, and the acceleration is inversely proportional to the mass of the object.A = F/mHere,A = AccelerationF = Force acting on the wagon m = mass of the wagon Substituting the given values, we getA = 380 N/50.0 kgA = 7.6 m/s²Therefore, the acceleration of the wagon is 7.6 m/s² when it is pulled with a constant force of 380 N, neglecting friction.For such more question on Newton's second law
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The answer to the investigative question,_____1______, is___2_____. A piece of data from the results that supports this is_____3______. For example, when ____4____happens, then _____5____happens. The data does/does not support the hypothesis because_____6____ and the data shows____7____. The evidence to support this conclusion is_____8_____. Compared to the data, this proves___9___. Based on___10___, one can conclude that __11__. The hypothesis of______12______ was correct/incorrect because____13____.
Answers
Answer:
:)
Explanation:
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The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music
Answers
Answer:
c
Explanation: