how does electic motor and generator work?​

Answer:

See the answer below

Explanation:

The weight of a body is defined as the product of mass by the acceleration gravitation of space or place.

1)

\(W=m*g\)

where:

m = mass [kg]

g = gravity acceleration = 9.8 [m/s²]

Therefore:

\(m=W/g\\m=62/9.8\\m=6.32[kg]\)

2)

The mass remains the same regardless of where the object or body is located. That is, the mass will be equal on Mars and on Earth.

3)

We used the same equation to determine the weight, using the Mars gravity constant.

\(W=6.32*3.7\\W=23.4[N]\)

These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).

In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.

Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.

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A 24 V potential difference is applied across a parallel combination of four 6 Ω resistors. The current in each resistor is 16 A. Therefore, option C is correct.

Use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).

A parallel combination of four 6 Ω resistors, which means the total resistance (\(R_{total}\)) is given by the reciprocal of the sum of the reciprocals of each resistor's resistance:

\(1/R_{total}\) = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄

= 1/6 Ω + 1/6 Ω + 1/6 Ω + 1/6 Ω

= 4/6 Ω

\(R_{total}\)= 6/4 Ω

= 3/2 Ω

Use Ohm's Law to find the current in each resistor:

I = V/R_total

I = 24 V / (3/2 Ω)

I = 24 V × (2/3 Ω)

I = 16 A

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Answer:

the units are joule and foot pound

one joule is defined as the amount of work done when a force of one Newton is exerted through a distance of one meter

Answer: The answer is Statistic.

Explanation:

The branch of physics that deals with newton’s laws of motion, the law of gravitation, Maxwell’s kinetic theory, and thermodynamics. Classical physics is mostly related to energy and matter which are considered as different entities. The main branches of classical physics are Acoustics, optics, classical mechanics, and electromagnetic.

Answer:

Statistic.

Explanation:

Answer:use 1/2 x M x V^2

Explanation:

to calculate the kinetic energy, observe the velocity from the graph at 8.0 seconds. and use the formula!

When the particles are very far apart, their potential energy approaches zero, and their kinetic energy becomes maximum. At this point, all the initial potential energy has been converted into kinetic energy, and the total mechanical energy is conserved.

When two particles are released from rest and allowed to move freely, the conservation of mechanical energy can be applied to determine their speeds when they are very far apart. Assuming no external forces act on the particles and neglect any potential energy differences, their total mechanical energy remains constant throughout the motion.

Initially, both particles are at rest, so their kinetic energy is zero. As they move apart, their potential energy decreases due to the increasing distance between them. This decrease in potential energy is converted into kinetic energy, resulting in an increase in their speeds.

When the particles are very far apart, their potential energy approaches zero, and their kinetic energy becomes maximum. At this point, all the initial potential energy has been converted into kinetic energy. According to the law of conservation of energy, the total mechanical energy is conserved.

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The mass of the cube is found to be to 218.7 grams with a density of 8.1g/cm³.

The density of any substance is calculated by dividing the mass of the substance by the volume of that substance.

Hayat is given that there is a cube which is 3 cm from each side and the density of the cube is given to be 8.1g/cm³.

Calculating the volume of the cube by using the formula,

V = a³

a is the side of the cube,

V = 3³

V = 27cm³.

Now, for finding the mass,

Density = mass/volume

Mass = density x volume

Putting values,

Mass of the cube = 8.1 x 27

Mass of the cube = 218.7 grams.

So, the mass of the cube is found to be 218.7 grams.

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Answer:

K. E= 1/2MV²

125 = 1/2M5²

multiply both side by 2

250 = 25M

M= 10kg

The angle between the electric field lines and the equipotential lines should be 90 degrees because: electric field lines always point in the direction of the electric force.

This is because electric field lines always point in the direction of the electric force, and equipotential lines represent locations of equal potential energy. If there were no electric field, then the equipotential lines would form concentric circles around the charge.

When the electric field is present, however, the equipotential lines will form perpendicular to the electric field lines. This is because, at any given point, the electric force is perpendicular to the equipotential line. Mathematically, this is represented by the equation E = -grad(V), where E is the electric field and V is the potential energy.

The electric field points in the direction of the negative gradient of V, which means that it is always perpendicular to V. Since V is a measure of potential energy, its contours (the equipotential lines) will be perpendicular to the electric field lines.

To summarize, the angle between the electric field lines and the equipotential lines should be 90 degrees because the electric field points in the direction of the negative gradient of potential energy, and the equipotential lines represent locations of equal potential energy.

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Answer:

\(\boxed {\boxed {\sf D. \ -11 \ m/s^2}}\)

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

\(a=\frac{v_f-v_i}{t}\)

where Vf is the final velocity, Vi is the initial velocity, and t is the time.

Since the car came to a complete stop, it's final velocity was 0 meters per second.

The initial velocity was 22 meters per second.

The time was 2.0 seconds.

\(v_f=0 \ m/s\\v_i=22 \ m/s\\t= 2.0 \ s\)

Substitute the values into the formula.

\(a=\frac{0 \ m/s-22 \ m/s}{ 2.0 \s }\)

Subtract in the numerator first.

\(a=\frac{-22 \ m/s}{2.0 \ s}\)

Divide.

\(a= -11 \ m/s^2\)

The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.

According to special relativity, time dilation occurs when an object moves at high speeds relative to an observer. In this scenario, the students on Spacecraft I are moving at 0.600 times the speed of light (c) relative to the Earth, while Spacecraft II, carrying the professors, moves at 0.280 c towards the students.

To determine the time interval as measured by the students, we need to take into account the time dilation effect. Time dilation states that time appears to run slower for objects moving at high speeds. The time dilation factor (γ) is given by γ = 1/√(1 - v^2/c^2), where v is the velocity of the object and c is the speed of light.

For Spacecraft I, γ = 1/√(1 - 0.600^2) = 1.25, and for Spacecraft II, γ = 1/√(1 - 0.280^2) = 1.04. This means that time on Spacecraft I appears to run 1.25 times slower than on Earth, while time on Spacecraft II appears to run 1.04 times slower than on Earth.

The professors stop the exam after 50.0 min on their clock. So, as measured by the students, the exam lasts for 50.0 min * (1.25/1.04) = 60.1 min.

Therefore, the exam lasts for approximately 60.1 minutes as measured by the students on Spacecraft I.

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SinФ = w/l

SinФ = 4.33 / 5.0

Ф = arcsin 4.33/5.0

Ф = 59.99 degrees

Round to 60 degrees

According to special relativity, one can travel at increased rates. However, this is only possible when moving at very high speeds approaching the speed of light. When an object moves at high speeds, the time slows down, and the length of the object appears to be shortened.

These observations are known as time dilation and length contraction. Time dilation refers to the difference in the elapsed time measured by two observers, where one is stationary, and the other is moving at a constant velocity relative to each other. The faster the moving observer, the slower time appears to be for them. Length contraction, on the other hand, refers to the phenomenon where an object appears to be shorter in length when it's moving at high

This effect is more noticeable as the speed of the object approaches the speed of light. As a result, traveling at very high speeds can allow one to cover great distances in less time, which can be used for space exploration and other scientific research. However, it's worth noting that the effects of relativity are only noticeable at very high speeds, which are currently impossible to achieve with our current technology.

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Graphite is a common form of carbon that is used in a variety of applications, including pencils, lubricants, and batteries. However, like any other material, graphite can contain defects that affect its properties. Some common defects in graphite include edge dislocations, screw dislocations, interstitials, and vacancies. Each of these defects has a unique set of directions for the Burgess and line vectors.
The Burgess vector is a mathematical representation of the direction and magnitude of a dislocation in a crystal lattice. It is defined as the Burgers vector is a vector that shows the magnitude and direction of the lattice distortion caused by a dislocation. The line vector is a vector that represents the direction of the dislocation line. The Burgers and line vectors are related to each other by a cross product. For edge dislocations, the Burgess vector is perpendicular to the dislocation line and points in the direction of the lattice distortion. The line vector is parallel to the dislocation line and points in the direction of the edge of the crystal. For screw dislocations, the Burgess vector is parallel to the dislocation line and points in the direction of the lattice distortion. The line vector is also parallel to the dislocation line and points in the direction of the screw axis. For interstitials, the Burgess vector is in the direction of the extra atom and points away from the defect. The line vector is parallel to the interstitial site and points in the direction of the defect. For vacancies, the Burgess vector is in the direction of the missing atom and points towards the defect. The line vector is parallel to the vacancy site and points in the direction of the defect. In conclusion, the directions of the Burgess and line vectors depend on the type of defect in graphite. For edge and screw dislocations, the Burgess vector is perpendicular and parallel to the dislocation line, respectively, while the line vector points in the direction of the crystal edge and screw axis, respectively. For interstitials and vacancies, the Burgess vector points away from and towards the defect, respectively, while the line vector points in the direction of the defect site.

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Answer:

6.0 m/s vertical and 9.0 m/s horizontal

Explanation:

For the vertical component, we use the formula:

Then we solve for y:

And for the horizontal component, we use the formula:

Then we solve for x:

So the answer is " 6.0 m/s vertical and 9.0 m/s horizontal".

When coherent monochromatic light passes through two slits in an opaque barrier, it diffracts and produces an interference pattern on a screen. The number of interference maxima within the central diffraction maximum depends on the distance between the slits and the wavelength of the light used. In this case, the two slits have a width of 0.020 mm and are separated by 0.050 mm. To find the number of interference maxima within the central diffraction maximum, we can use the formula:

n = (2d/λ) * sinθ

where n is the number of interference maxima, d is the distance between the slits, λ is the wavelength of the light, and θ is the angle between the central maximum and the first-order maximum.

Assuming the wavelength of the light is 500 nm (typical for green light), we can calculate the value of θ using:

sinθ = λ/d

sinθ = 500 nm / 0.050 mm

sinθ = 0.01

θ = 0.576 degrees

Substituting the values into the formula gives:

n = (2 * 0.050 mm / 500 nm) * sin(0.576 degrees)

n = 2.3

Therefore, there are approximately 2 interference maxima within the central diffraction maximum for this setup.


Step 1: Determine the angles for the first-order minima of the single-slit diffraction pattern
To find the angle, we use the formula:
θ = arcsin(mλ / b)
where m is the order number, λ is the wavelength of the light, and b is the width of each slit.

Step 2: Calculate the angular separation between the two first-order minima
θ_1st minima = arcsin(λ / b) - (-arcsin(λ / b)) = 2 * arcsin(λ / b)

Step 3: Determine the angular separation between consecutive interference maxima in the double-slit interference pattern
Using the formula for double-slit interference:
Δθ = λ / d
where d is the separation between the two slits.

Step 4: Calculate the number of interference maxima within the central diffraction maximum
Divide the angular separation between the two first-order minima (from step 2) by the angular separation between consecutive interference maxima (from step 3):
N = (2 * arcsin(λ / b)) / (λ / d)

Now we can use the given values (b = 0.020 mm and d = 0.050 mm) and the wavelength of the light to calculate the number of interference maxima within the central diffraction maximum using the formula in step 4.

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The number of moles of gas present is 0.0850 mol

Given

initial volume of the gas \(v_{i}\)= 0.80 L

final volume of the gas \(v_{f}\) = 3.0L

work done by the gas, W = 280 J

constant temperature, T = 300 K

gas constant, R = 8.31 J/mol.K

work done by gas at constant temperature is given as;

\(W= \int\limits^a_b {P} \, dv\)

where a =final volume of the gas

and b = initial volume of the gas

W=nRT*ln\((\frac{v_{f} }{v_{i} } )\)

\(n=\frac{W}{RT*ln\frac{v_{f} }{v_{i} } }\)

\(n=\frac{280}{8.31*300*ln\frac{3}{0.80 } }\)

n=0.0850 mol

Therefore, the number of moles of gas present is 0.0850 mol

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Answer:

it's always relative because it's measured or observed with respect to another thing

Explanation:

do you understand?

Answer:

Sleeping

Explanation:

Driving in traffic is stressful because you may be late for wherever you are going,

Opening a birthday present is stressful because you don't know what is inside until you open it.

Watching a soap opera is stressful because you do not know what will happen next,

Sleeping is not stressful as long as you don't bring stressful topics to bed.

In corrosion fatigue is: "d) the surface remains bright after fracture."

Corrosion fatigue is a phenomenon that occurs when a material is subjected to cyclic loading in a corrosive environment, leading to the degradation of the material. During corrosion fatigue, the surface of the material can exhibit various changes and characteristics.

Option d) states that "the surface remains bright after fracture." This statement is incorrect. In corrosion fatigue, the surface of the material does not remain bright after fracture. Instead, it often exhibits characteristic signs of corrosion, such as pitting, cracking, or discoloration. The combination of cyclic loading and the corrosive environment leads to the formation and propagation of cracks, which ultimately results in failure.

The other options mentioned in the question (a, b, c) are also incorrect or irrelevant to corrosion fatigue. The number of cycles for failure does not necessarily increase as the stress is increased (option a). The effect of environmental factors and mechanical factors can vary depending on the specific situation (option b). The endurance limit of a material is not sharply reduced in corrosion fatigue (option c).

Therefore, the correct statement is option - d.

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Answer: yes

Explanation:

Animals of different species typically compete with each other only for food, water and shelter. But they often compete with members of their own species for mates and territory as well.

Answer:

a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars

Explanation:

Answer:

2ms-2

Explanation:

F = ma

a = F/m

= 0.5 / 0.25

= 2ms-2

Answer 2m/s^2

Explanation:

mass=0.25kg

Force =0.5N

Acceleration=force/ mass

Acceleration=0.5/0.25

Acceleration=2

Acceleration =2m/s^2

Adding water vapor into the air through evaporation will increase the dew point and increase the relative humidity.

The dew point is the temperature at which the air becomes saturated with water vapor. When water vapor is added to the air through evaporation, it increases the amount of moisture in the air. As a result, the dew point, which represents the temperature at which the air would become saturated, increases.

The relative humidity is a measure of how much moisture is in the air compared to the maximum amount it can hold at a given temperature. As water vapor is added to the air through evaporation, the amount of moisture in the air increases.

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Explanation:

uasjwwbwjwbwia GJ wkwkjwnwnwjwjjwjwd7beba s

Answer:

because all the energy is directly depend on solar .. like light energy .. wind energy.. heat energy.. etc..

Explanation:

Answer:

False

Explanation:

The softball is bigger, but it is lighter, which means it has a better chance of getting farther way faster with a lighter amount of force. On the other hand, the golfball is heavier, which would take more force to move it a certain distance.

Answer: false

Explanation:

• Defines what the “natural” states of motion are, either at rest and constant

velocity. In essence, the first law sets up the basis to define what accelerated

motion is, which we address with Newton’s 2nd law.

• Defines the type of coordinate systems so that Newton’s laws are valid. These

coordinate systems are called inertial reference frames.

The cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

The given parameters;

The effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;

\(a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2\)

The distance traveled by the cyclist at the give speed and acceleration is calculated as;

\(v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m\)

Thus, we can conclude that the cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

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