How do the grids you made while launching red particles compare to the grids you made while

launching blue particles? Explain why this makes sense

The wavelength of these radio waves are 2.88 m

In the electromagnetic spectrum, radio waves have the longest wavelengths. These waves, which fall under the category of electromagnetic radiation, range in frequency from 300 GHz to 3 kHz, though they are sometimes classified as microwaves above 3 GHz.

The given frequency is 104 mhz

Any radiation in the electromagnetic spectrum, including radio waves, travels at a speed of 3.00 x 10^8 m/s in vacuum.

Consequently, the following equation can be used to determine the wavelength:

c = wavelength × frequency

frequency is given in mHz thus we convert it into Hz

and get 104 × 10 ^6

this implies

wavelength = \(\frac{3 X 10^8}{104 X 10^6}\)

wavelength = 0.0288× \(10^{2}\) m

= 2.88 m

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Answer:

d. are easily compressible.

Explanation:

Solids and liquids are not easily compressible while gas is.

According to the question the rotational velocity during the two second time interval is 5 radians per second (rad/s).

Velocity is a quantity that measures both the speed and direction of an object's motion. Velocity is a vector, meaning it has both direction and magnitude. Speed is the rate at which an object moves, while velocity is the rate and direction of an object's motion. Velocity is typically expressed in terms of meters per second (m/s). Velocity is different from acceleration, which is the rate of change in velocity over time.

The rotational velocity during the two second time interval is 5 radians per second (rad/s). This is calculated by dividing the total rotation of 10 radians by the two second time interval. Mathematically, this is expressed as:

Velocity = (Rotation / Time) = (10 rad / 2 s) = 5 rad/s

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Complete Question:
A disk displaces 10 radians (rads) over an 2 second interval. The rotational velocity during that 2 second time interval was rad/s.

Answer:The energy of nuclear fission is released as kinetic energy of the fission products and fragments, and as electromagnetic radiation in the form of gamma rays; in a nuclear reactor, the energy is converted to heat as the particles and gamma rays collide with the atoms that make up the reactor and its working fluid.

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Answer:

yea what the other guy said

Answer:

a

 \(a = 21.7 \ m/s^2\)

b

\(F = 108.5 \ N\)  

Explanation:

From the question we told that

   The mass is  m  =  5 kg

    The initial speed \(u = 5 m/s\)

    The time taken to attain \(v = 70 \ m/s\) is  t =  3 s

Generally from kinematic equation we have that

     \(v = u + at\)

=> \(70 = 5 + a * 3\)

=>  \(a = 21.7 \ m/s^2\)

Generally  the force acting is mathematically represented

        \(F = m * a\)

=>      \(F = 5 * 21.7\)  

=>      \(F = 108.5 \ N\)  

Answer:

When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.

Explanation:

Hope it will help u

Answer:  Make the frequency higher for number 1 and have the same amplitude.

Explanation: Wavelength and frequency are directly related so if you change one of those then you can't keep the other one the same. You would need to raise the frequency which would make 1 louder and keep amplitude the same for both so that 1 is louder.

To make the sounds match in pitch while making sound wave 1 louder than sound wave 2 : Increase the frequency for wave #1 while setting their amplitudes at the same value

The wavelength of a sound wave is inversely proportional to its frequency therefore when the frequency of wave 1 is increased its wavelength decreases with equal proportion.

Since the increase in frequency results to a decrease in wavelength. therefore to make wave 1 louder, both waves we will have to set the amplitude values of the waves at the same amplitude.

Hence we can conclude that to make the sounds match in pitch while making sound wave 1 louder than sound wave 2 ; Increase the frequency for wave #1 while setting their amplitudes at the same value.

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The area of each plate of an empty parallel-plate capacitor can be calculated using the given capacitance and the distance between the plates.

The capacitance (C) of a parallel-plate capacitor is determined by the formula C = (ε₀ * A) / d, where ε₀ is the permittivity of free space, A is the area of each plate, and d is the distance between the plates.

In this case, we are given the capacitance (C) as 1.5 pF (picofarads) and the distance (d) as 3.5 mm (millimeters). We need to find the area (A) of each plate.

Rearranging the formula, we have A = (C * d) / ε₀.

The permittivity of free space (ε₀) is a constant value of approximately 8.854 x 10^(-12) F/m (farads per meter).

Converting the distance from millimeters to meters, we have d = 3.5 mm = 3.5 x 10^(-3) m.

Plugging in the values, we can calculate the area as A = (1.5 x 10^(-12) F * 3.5 x 10^(-3) m) / (8.854 x 10^(-12) F/m).

Performing the calculation, we find the area of each plate to be approximately 5.936 x 10^(-6) square meters or 5.936 mm².

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While conducting a flight test of a new aircraft, the pilot radios to the ground that she is in level flight at a standard altitude of 35,000 feet. 45.14 kPa is the ambient air pressure far ahead of the airplane.

The ambient air pressure far ahead of the airplane is approximately equal to the standard atmospheric pressure at an altitude of 35,000 ft. The standard atmospheric pressure decreases with increasing altitude, according to the formula:

P = P0*(1 - Lh/T0)^(gM/(R*L))

P = ambient pressure on altitude h,

P0 = standard atmospheric pressure at sea level,

T0 = standard temperature at sea level,

L = temperature lapse rate,

g = gravitational acceleration,

M = molar mass of Earth's air, and

R = universal gas constant.

For an altitude of 35,000 ft, the ambient pressure can be calculated by substituting the appropriate values into the formula:

= P

= 101325 Pa * (1 - 6.5 K/km * 35000 m / 288 K)^(9.80665 m/s^2 * 0.0289644 kg/mol / 8.3144621 J/mol*K)

This gives an ambient pressure of approximately 45,140 Pa, or 45.14 kPa.

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if the particle velocity is perpendicular to the magnetic field lines, the force experienced by the particle will be the largest.

The force experienced by a moving charged particle in a magnetic field is given by the formula:

F = q v B sin(theta)

where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and theta is the angle between the velocity of the particle and the magnetic field.

The force experienced by the particle is maximum when sin(theta) is equal to 1, i.e., when the angle theta between the velocity of the particle and the magnetic field is 90 degrees. This means that the velocity vector of the particle is perpendicular to the magnetic field lines.

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The correct answer is Option(C). The proper time between two events is measured by clocks at rest in a reference frame in which the two events are separated by the distance a light signal can travel during the time interval.

The concept of proper time is a fundamental concept in special relativity. It refers to the time interval measured by an observer who is at rest relative to the events being measured. According to special relativity, the passage of time can be affected by relative motion and gravitational fields.

The proper time between two events is independent of the reference frame from which it is measured. It is a fundamental property of the events themselves. In order to measure the proper time between two events, one must use clocks that are at rest relative to the events being measured.

Option (C)  states that the two events are separated by the distance a light signal can travel during the time interval. This is the correct choice because the speed of light is a fundamental constant in special relativity and is the maximum speed at which information can propagate. Using the distance traveled by light during a time interval ensures that the measurement of proper time is consistent with the principles of special relativity.

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--The question is incomplete, the complete question is:

"The proper time between two events is measured by clocks at rest in a reference frame in which the two events:  (A). occur at the same time  (B). occur at the same coordinates  (C). are separated by the distance a light signal can travel during the time interval  (D). occur in Boston  E. satisfy none of the above"--

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

The mass of the lighter construction worker, m₁ = 90 kg

The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.

when this combination of capacitors is attached to a 9.00 V battery, 45.0 μC of charge will be stored on the plates.

To determine how much charge will be stored on the plates of the capacitors in the image, we need to use the formula Q = CV, where Q is the charge stored on the plates, C is the capacitance of the capacitor, and V is the voltage across the plates.
We can start by finding the total capacitance of the combination of capacitors. The two capacitors in the image are in parallel, so their capacitances add together:
C_total = C1 + C2 = 3.00 μF + 2.00 μF = 5.00 μF
Next, we can use Ohm's Law to find the current (I) flowing from the battery:
I = V/R = 9.00 V / 20.0 Ω = 0.450 A
Finally, we can use the formula Q = CV to find the charge stored on the plates:
Q = C_total * V = 5.00 μF * 9.00 V = 45.0 μC

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They We'll find the speed and frequency of the Wavelength using the given tension, mass, length, and wavelength. a) To find the speed of the wave, first we need to determine the linear mass density (µ) of the wire.

The calculated using the formula µ = Mass / Length Plug in the values µ = 50 kg / 10 m = 5 kg/m Now, we can use the formula for wave speed (v): v = sqrt (Tension / µ) v = sqrt (1500 N / 5 kg/m) = sqrt (300 m²/s²) = 17.32 m/s So, the speed of the wave is 17.32 m/s. b) To find the frequency of the wave, we can use the formula that relates wave speed, frequency, and wavelength Wave speed (v) = Frequency (f) * Wavelength (λ) We know the wave speed and the wavelength, so we can solve for the frequency (f) = Wave speed (v) / Wavelength (λ) f = 17.32 m/s / 0.15 m = 115.47 Hz The frequency of the wave is 115.47 Hz.

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Therefore, the eccentricity of the orbit is 0, and the radii at perigee and apogee are both 6,871 km.

The given problem describes a scenario where an earth satellite is planned to be launched into a circular orbit with an altitude of 500 km. However, due to a guidance and control error, the launch vehicle reaches the planned burnout velocity at an altitude of only 300 km.
To determine whether or not the satellite will remain in orbit, we need to consider the minimum altitude required for a satellite to remain in orbit around the Earth. This minimum altitude is known as the "minimum circular orbit altitude." If the actual altitude of the satellite is above this minimum altitude, it will remain in orbit. If it is below this minimum altitude, it will not be able to maintain a stable orbit.
The minimum circular orbit altitude can be calculated using the following formula:
minimum circular orbit altitude = Earth's radius + satellite's altitude
The Earth's radius is approximately 6,371 km.
Using this formula, we can calculate the minimum circular orbit altitude:
minimum circular orbit altitude = 6,371 km + 500 km
minimum circular orbit altitude = 6,871 km
Since the actual altitude of the satellite is 300 km, which is below the minimum circular orbit altitude of 6,871 km, the satellite will not remain in orbit.
Now, let's calculate the orbit's eccentricity and the radii at perigee and apogee.
Eccentricity is a measure of how elliptical an orbit is. For a circular orbit, the eccentricity is 0.
Since the given problem states that the satellite was planned to be launched into a circular orbit, the eccentricity remains 0.
The radii at perigee and apogee can be calculated using the following formulas:
radius at perigee = Earth's radius + altitude at perigee
radius at apogee = Earth's radius + altitude at apogee
In this case, since the satellite was planned to be launched into a circular orbit with an altitude of 500 km, the altitude at perigee and apogee will be the same.
Let's calculate the radii at perigee and apogee:
radius at perigee = 6,371 km + 500 km
radius at perigee = 6,871 km
radius at apogee = 6,371 km + 500 km
radius at apogee = 6,871 km
Therefore, the eccentricity of the orbit is 0, and the radii at perigee and apogee are both 6,871 km.

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Answer: 14

Explanation: 35•0.40

The minimum force to start this block moving is 14N,formula to be used to find  minimum force(F= μ N

those minimal steps, including the use of force, required to defuse a crisis or protect oneself from an aggressive act or hostile intent. Once the target obeys orders or stops taking hostile action, all actions must stop.

To solve such problems, you must find the second derivative: The force is at its minimum if the second derivative is positive; at its maximum if the second derivative is negative.

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Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

The binding energy of electrons to caesium metal is found to be approximately \(1.3\times 10^{-19} J\).

The binding energy of electrons to a metal refers to the energy required to remove an electron from the metal's surface. It can be determined by considering the energy of the incident light and the maximum kinetic energy of the ejected electrons.

The binding energy of electrons to caesium metal can be calculated using the equation

\(E=hf-KE\)

where E is the binding energy, hf is the energy of the incident light, and KE is the maximum kinetic energy of the ejected electrons. Here, h is Planck's constant, which is approximately \(6.626 \times 10^{-34} J.s\).

Given the frequency of the incident light as \(1.30 \times 10^{15} s^{-1}\) and the maximum kinetic energy of the ejected electrons as \(5.2 \times 10^{-19} J\), we can calculate the energy of the incident light using the equation

\(E=hf\)

By rearranging the equation, we get

\(hf = E + KE\)

Substituting the given values, we have

\(hf = (5.2 \times 10^{-19 }J )+ (1.30 \times 10^{15} s^{-1})\)

Now, we can calculate the binding energy by subtracting the maximum kinetic energy from the energy of the incident light:

\(E = hf - KE = (5.2 \times 10^{-19} J + 1.30 \times 10^{15} s^{-1}) - (5.2 \times 10^{-19} J)\)

Simplifying the expression, we find that the binding energy of electrons to caesium metal is approximately \(1.3 \times 10^{-19} J\).

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Answer:

what grade are you dude

Answer:

Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.

Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).

Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).

Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:

\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).

With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:

\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).

Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).

All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.

It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:

\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).

Solve for the displacement of the spring, \(x\):

\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).

The force of friction acting on him is 122 N. The correct answer is option C

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  \(F_{r}\) = μN

\(F_{r}\) = 0.15 x 813.4

\(F_{r}\) = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

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Formula for force:

\(F=ma\)

force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)

Formula for work:

\(w=Fd\)

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

__________________________________________________________

Given:

\(m=3.4kg\)

\(d=1613m\)

\(a=9.8m/s\) (due to gravity)

\(w=?\)

__________________________________________________________

Finding force:

\(F=ma\)

\(F=3.4\times9.8\)

\(F=33.32N\)

__________________________________________________________

Finding work:

\(W=Fd\)

\(W=33.32\times1613\)

__________________________________________________________

Answer:

\(\fbox{w = 53745.16 Joules}\)

There are approximately 3.52x10²¹ air molecules in the spherical balloon.

The number of air molecules in a spherical balloon can be calculated using the ideal gas law, which relates the number of molecules to the pressure, volume, temperature, and gas constant.

PV = nRT

where P is the pressure, V is the volume, n is the number of molecules, R is the gas constant, and T is the absolute temperature.

Assuming that the balloon is at atmospheric pressure, we can use the ideal gas law to solve for the number of molecules:

n = PV/RT

The volume of the balloon can be calculated as:

V = (4/3)πr³

where r is the radius of the balloon.

Substituting the values given, we have:

V = (4/3)π(0.15m)³ = 0.0141 m³

n = (1.01x10⁵ Pa)(0.0141 m³)/(8.31 J/mol K)(273 K)(1.29 kg/m³)(1 u/1.66x10⁻²⁷ kg) = 3.52x10²¹ molecules

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A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery. The correct answer is D

The potential difference between any two point in a circuit is the work done when one coulomb of charge moves from one point to the other. Potential difference is a kind of electrical pressure difference between two point.

The difference in electric potential in a 12 Volt battery is greater than the difference in electric potential in a 1.5 Volt battery.

According to Ohm's law, Voltage supplied is proportional to current produced. That is, V = lR. Where R = resistance.

A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery.

Therefore, the correct answer is the option D

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Answer:

The gravitational potential energy is 150J

Explanation:

P. E=mgh

=5*10*3

ANSWER

EXPLANATION

We want to find the angle of reflection of the ray of light.

According to the law of reflection, the angle of reflection must be equal to the angle of incidence of a ray of light:

Therefore, the angle of reflection of the ray of light is:

That is the answer.

Collected data plays a crucial role in evaluating whether the criteria for success have been met. By analyzing the collected data, one can assess the progress made towards achieving the desired goals and determine if the criteria have been fulfilled.

Data provides an objective measure of performance or outcomes, allowing for an evidence-based assessment of success. It helps to quantify and track key metrics or indicators related to the criteria for success. By comparing the actual data with the predetermined benchmarks or targets, one can determine if the criteria have been met or if further improvements are required.

Data analysis also enables the identification of trends, patterns, and correlations, providing insights into the factors influencing success. It helps in identifying areas of strength and areas that need improvement. Additionally, data can be used for comparative analysis, benchmarking against previous periods or similar projects, to gain a broader perspective on success.

In summary, collected data provides an objective basis for evaluating progress and success by comparing actual performance against predetermined criteria, identifying areas of improvement, and gaining insights for future decision-making.

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The gauge pressure in the higher part will be 136 kph. The pressure is found with the help of the Bernoulli equation.

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

From the continuity equation;

\(\rm A_1v_1=A_2v_2 \\\\ \rm \frac{\pi}{4}(6)^2 \times 5 = \frac{\pi}{4}(3)^2 v_2 \\\\ v_1 = 20 \ m/sec\)

The gauges pressure in the higher part is found as;

From the Bernoullis equation;

\(\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{80 \times 10^3 }{\rho g} + \frac{(5)^2}{2g} +0= \frac{p_2}{\rho g} + \frac{(20)^2}{2g} +3 \\\\ \frac{80 \times 10^3 - P_2 }{1000 \times 9.81 } = \frac{20^2-5^2}{2 \times 9.81 } +3 \\\\ P_2 = 136 \ kpa\)

Hence the gauge pressure in the higher part will be 136 kpa.

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The frequency of the sound is 68 Hz, which is found by dividing the speed of sound by the wavelength, where the wavelength is determined by the path difference between the two speakers.

To find the frequency of the sound, we need to consider the path difference and the speed of the sound. When you hear maximum intensity, the path difference is a whole number multiple of the wavelength (constructive interference). When you hear minimum intensity, the path difference is a half-integer multiple of the wavelength (destructive interference).
In this case, when you're in front of one speaker, the path difference is half the distance between the speakers (5.0 m / 2 = 2.5 m). This corresponds to a half-integer multiple of the wavelength, meaning (2n + 1) * (wavelength / 2) = 2.5 m, where n is an integer.
Let's consider the smallest value of n, which is 0. Then, the wavelength is 5.0 m.
To find the frequency, we can use the equation:
frequency = speed of sound/wavelength
frequency = 340 m/s / 5.0 m
frequency = 68 Hz
So, the frequency of the sound is 68 Hz.

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