How do spectroscopes help with studying of distance stars?

It measures the distance of faraway stars.
It collects sound waves from distant stars.
It breaks apart lights that comes from stars faraway.
It gives a clear image of the shape of stars.

projectile's vertical speed v yv y v, start , y,  drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward

.

At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.

In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.

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A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student cannot tell that if the elevator is moving upward or downward. The correct answer is option C.

The reason for this is that the scale reading depends not only on the weight of the student but also on the acceleration of the elevator. If the elevator is accelerating upwards, the scale will read more than the actual weight of the student.

Similarly, if the elevator is accelerating downwards, the scale will read less than the actual weight of the student.

In this case, we know that the scale reads 645 N, which is 30 N more than the actual weight of the student (615 N).

However, we don't know whether the elevator is accelerating upwards or downwards. It could be accelerating upwards with an acceleration of 3 m/s^2 (in which case the apparent weight would be 645 N), or it could be accelerating downwards with an acceleration of 3 m/s^2 (in which case the apparent weight would be 585 N).

Therefore, based on the information given, we cannot determine whether the elevator is moving upwards or downwards. The correct option is c.

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Answer:

E = - 500 V / m,  v = 30.95 10⁴ m / s   and    t = 6.46 10⁻⁶ s

Explanation:

For this problem we use the relation

           ΔU = - E s

           E = -ΔU / s

           E = - 500/1

           E = - 500 V / m

Now we can look for the proton approach

           F = q E

let's use Newton's second law

           F = m a

           a = F / m

           a = q E / m

Now let's use kinematics relations, where the proton starts from the rest

v₀ = 0

           v² = v₀² + 2 a x

           v = √2 q E / m x

           v = √ (2 1.6 10⁻¹⁹ 500 / 1.67 10⁻²⁷  1)

           v = √ (958.08 108)

           v = 30.95 10⁴ m / s

for time let's use the equation

          x = v₀ t + ½ to t2

          t = √2x / a

          t = √ (2x m / qE)

          t = √ (2 1 1.67 10⁻²⁷ / (1.6 10⁻¹⁹ 500))

          t = √ (0.004175 10⁻⁸)

          t = 0.0646 10⁻⁴ s

          t = 6.46 10⁻⁶ s

The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.

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earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.

Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.

The term earth's energy budget is also described as the  balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.

The earth's energy budget was mainly three types as shown:

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The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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Answer:

an acceleration of the boy as it passes through the board and be the total time the boy is in contact with the board solution

Answer:

1)   α = 2.2 rad / s² , 2)   t = 7.068 s , 3) in this interval   s = 23.096 m

total distance    s = 57.4 m

Explanation:

For this exercise we use the angular kinematic relations, before starting the problem we reduce all the magnitude to the SI system

        v₀ = 88 km / h (1000 m / 1km) 1h / 3600s) = 24.44 m / s

        v = 56.0 km / h = 15.55 m / s

        θ = 90 rev (2pi rad / 1 rev) = 565,487 rad

        d = 0.84 m

          r = d / 2

         r = 0.84 / 2

         r = 0.42 m

1) ask for angular acceleration

        w² = w₀² - 2 α Δθ

        α = (w₀² -w²) / 2 Δθ

To find the angular velocities we use the acceleration between the linear and angular velocity

         v = w r

         w = v / r

         w₀ = 24.44 / 0.42

         w₀ = 58.20 rad / s

         w = 15.55 / 0.42

         w = 30.037 rad / s

we calculate

        α = (58.20² - 30.037²) / (2   565.487)

        α = 2.2 rad / s²

2) how much longer does it take to stop

         w₂ = 15.55 rad / s

         w = 0

         w = w₂ - α t

         t = (w₂ -0) / α

         t = 15.55 / 2.2

         t = 7.068 s

3) the distance that the car travels from the beginning of the movement, we can find it by looking for the number of revolutions until it stops and then using the relationship between the angular and linear variable

         w² = w₀² - 2 α θ

at the end of the movement speed is zero

         0 = w₀² - 2 α θ

         θ = w₀² / 2 α

         θ = 24.44² / (2 2.2)

          θ = 135.80 rad

If the angles are measured in radians, we can apply the relation

         θ = s / R

         s = R ttea

         s = 0.42 135

         s = 57.4 m

this is the distance from when the movement starts

the distance for the final part of the movement is

          w = 15.55 rad / s

          θ = w² / 2 α

          θ = 15.55 2 / (2 2.2)

          θ = 54.99 rad

the distance in this interval is

          s = 0.42 54.99

          s = 23.096 m

Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Energy parallel is a type of energy efficiency strategy that seeks to reduce the amount of energy used in a building or facility by utilizing multiple energy sources instead of relying solely on one. This type of energy efficiency strategy works by drawing energy from multiple sources, such as solar, geothermal, wind, and water energy, and combining them to power a single building or facility. By utilizing multiple energy sources, energy parallel helps to reduce the overall amount of energy used in a building or facility, thus improving its overall energy efficiency. Additionally, this type of energy efficiency strategy helps to reduce the amount of energy that is wasted or lost by utilizing energy sources that are renewable and more sustainable.

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The 99% confidence interval for the average maximum HP for the experimental engine is (610.12, 689.88).

To calculate the confidence interval for the experimental engines' average maximum HP, we can use the following formula:

To find the z-score for α=0.01, we can refer to a standard normal distribution table or use a calculator. The z-score is approximately 2.58.

Substituting the given values into the formula, we get:

CI = 650 ± 2.58*(60/√25) CI = 650 ± 30.96

Rounding to two decimal places, the confidence interval for the experimental engines' average maximum HP is:

CI = [619.04 HP, 680.96 HP]

Therefore, we can say with 99% confidence that the true average maximum HP for the experimental engines falls between 619.04 HP and 680.96 HP. Thus, we can conclude that the experimental engines' average maximum HP is likely to be within this range. However, note that this range does not include the manufacturer's claimed maximum HP of 630 HP, which may indicate that the engines are performing below expectations.

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B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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A. When we convert 37.4 mL to ML, the result obtained is 3.74×10¯⁸ ML

B. When we convert 689 km/hr to m/s, the result obtained is 191.39 m/s

C. When we convert 34.5 m² to mm², the result obtained is 3.45×10⁷ mm²

1 mL = 1×10¯⁹ ML

Therefore,

37.4 mL = 37.4 × 1×10¯⁹

37.4 mL = 3.74×10¯⁸ ML

Thus, 37.4 mLis equivalent to 3.74×10¯⁸ ML

Conversion scale

3.6 Km/hr = 1 m/s

Therefore,

689 km/hr = 689 / 3.6

689 km/hr = 191.39 m/s

Thus, 689 km/hr is equivalent to 191.39 m/s

Conversion scale

1 m² = 1×10⁶ mm²

Therefore,

34.5 m² = 34.5 × 1×10⁶

34.5 m² = 3.45×10⁷ mm²

Thus, 34.5 m² is equivalent to 3.45×10⁷ mm²

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l will help and if you get it correctly I will say you are welcome

Answer:

85.4 N

Explanation:

Weight of the ball, W = 60 N

W = mg, m is mass

m = W/g

m = 60/9.8 = 6.12 kg

Length of a rope, r = 6 m

Speed, v = 5 m/s

We need to find the tension in the rope at this point. Tension is equal to the centripetal force It is given by :

\(F=\dfrac{mv^2}{r}+mg\\\\F=\dfrac{6.12\times (5)^2}{6}+60\\\\=85.5\ N\)

So, the correct option is (b) " 85.4 N".

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

The magnitude of the normal force: 75.1 N

Explanation:

The free-body diagram showing all forces acting on the box is:

Here is a little explanation of the diagram. What we are doing is we are refinding our coordinate system such that the y axis is along the normal force Fn and the x-axis is along with the tangential force Ft. Remember that in this coordinate system, we have to decompose the gravitation force Fg into normal and tangential components.

Now the Normal force acting on the box is Fn. What is its magnitude? We can easily find it using some trigonometry.

which evaluates to give

Hence, the normal force on the box is 75.1 newtons.

Answer:

The third one.

Explanation:

Atmospheric molecules releasing photons (light) in response to collisions with Solar Wind particles because when auroras are produced what actually happens is that the ions of the solar wind collide with atoms of oxygen and nitrogen from the Earth's atmosphere. The energy released during these collisions causes a colorful glowing halo around the poles which is the aurora.

Given,

The mass of Francine McFly, m=50 kg

The distance from the center of the seesaw to Francine, d=2 m

The mass of the jumpers, M=80 kg

The maximum height reached by the jumpers, h=1 m

From the law of conservation of energy, energy can neither be created nor be destroyed but can be converted from one form to another.

The jumpers transfer their potential energy to Francine through the seesaw. The energy gained by Francine from jumpers and a stomper gives her the velocity. She shots off with the kinetic energy equal to the total energy transferred input of two jumpers and a stomper. As Francine rises, she slowly loses kinetic energy. This lost kinetic energy will be converted into her potential energy. When she reaches the top, her potential energy will be equal to the energy input from the two jumpers and a stomper.

The energy applied by two jumpers is equal to their potential energy at the maximum height, That is,

Where g is the acceleration due to gravity.

Given that the stomper stomps with an energy equal to 1/4 of applied by one of the jumpers.

Thus the total energy applied to the seesaw is given by,

On substituting the known values,

a)

This total energy will be equal to the kinetic energy of Francine when she is shot off.

Thus,

Where E_K is the kinetic energy of Francine when she is shot off and v is her velocity when she is shot off.

On substituting the known values,

Thus Francine's velocity when she is shot off is 8.4 m/s

b)

The potential energy of Francine when she is at the maximum height is equal to the energy applied to the seesaw. Thus,

Where E_P is the potential energy of Francine and H is the height reached by Francine.

On substituting the known values,

Thus the maximum height reached by Francine is 3.6 m

The primary means by which heat is transferred through fluids is convection currents (option D).

Convection is the transmission of heat in a fluid by the circulation of currents.

Heat can be transferred by different methods depending on the medium. Fluids like gases and liquids transfer heat through the process of convection.

Therefore, the primary means by which heat is transferred through fluids is convection currents.

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Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.

High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.

Neutral atoms or molecules often make up gaseous substances like air.

The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.

It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.

Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.

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Answer:

We can use the formula:

q = mcΔT

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

The heat transferred from the gold bar to the water is equal to the heat transferred from the water to the gold bar, since they reach thermal equilibrium. Therefore:

q_gold = q_water

We can solve for the temperature change of the gold bar:

q_gold = mcΔT_gold

q_water = mcΔT_water

Since the heat transferred is equal:

mcΔT_gold = mcΔT_water

Rearranging and solving for ΔT_gold:

ΔT_gold = ΔT_water(m_water/m_gold)

ΔT_water is the temperature change of the water, which is 17°C. m_water is 0.220 kg, and m_gold is 3 kg. c_gold is given as 129 J/kg K.

ΔT_gold = 17°C(0.220 kg/3 kg)(1/129 J/kg K) = 0.025°C

Therefore, the temperature change of the gold bar is 0.025°C when it is placed into 0.220 kg of water and thermal equilibrium is reached.

The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound.

Answer:

The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.

Explanation:

The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:

2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k

We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:

|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49

The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.

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We have that for the Question, it can be said that

From the question we are told

From,

\(tan\theta = \frac{h}{2}\)

differentiate with respect to h

\(sec^2\theta * \frac{do}{dz} = \frac{1}{2} * \frac{dh}{dz}\\\\\frac{dh}{dz} = 2 sec^\theta * \frac{d\theta}{dz}\\\\\theta = \frac{\pi}{6} and \frac{d\theta}{dz} = 0.1rad/min\\\\\frac{dh}{dz} = 2sec^2 (\frac{\pi}{6}) * (0.1)\\\\= 0.266miles/min\)

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The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.

Mass of the yoyo = 0.001 kg

Initial value of the spindle radius, R = 4 cm

Initial length of the radius of the yo–yo, r = 0.8 cm

The final values are;

R2 = 4.1 cm, r2 = 0.9 cm

Which gives;

\(T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} \)

Which gives;

\(T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} \)

\(T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} \)

Therefore;

\( \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} \)

Given that difference between the final and the initial states is negative, the the value of the tension decreases

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The options that would be a part of a force diagram for the attached image are:

A; A dot that represents the box

B; A vector labeled Fg, pointing straight down

E; A vector labeled Fs, pointing parallel to and up the ramp.

This is a simple force diagram of an item lying on an inclined plane.

The first step is to draw a dot in the center of the box, as here is where we will draw the other forces operating on the box.

Second, we must recognize the force of gravity (F_g), which is a vertical vector line drawn from that dot and whose perpendicular component assures that the box is pressing against the inclined plane.

Third, we can see that the box is moving down the slope, but it will face some friction in the other direction. As a result, we will draw a vector line parallel to the inclined plane from the dot to the left of the box. Frictional force (F_fs) will be shown by this line.

Fourth, there would be a normal force attempting to counteract the perpendicular component of gravity (F_g). This normal force is perpendicular to the perpendicular component of F_g. This is referred to as F_g•sin. We will draw a vector line perpendicular to the inclined plane starting from the dot to represent this normal force. F_n represents this normal force.

Looking at the possibilities, only Options A, B, and E correlate to the forces stated above.

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Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.