Scientists determine the composition and temperature of stars through spectroscopy, spectral classification, stellar models, color-temperature relationships, and photometry
Techniques to determine composition and temperature of starsSpectroscopy: Spectroscopy is a key method used to analyze the composition of stars. By splitting the starlight into its component wavelengths, scientists can identify the absorption or emission lines produced by different elements. These spectral lines provide information about the types and abundances of elements present in the star. Comparing observed spectra to known spectra helps determine the composition.Learn more about star composition here:
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what does the scientific unit named for sir isaac newton measure?
The scientific unit named for Sir Isaac Newton measures force.
What is the quantity measured by the scientific unit named after Sir Isaac Newton?The scientific unit named after Sir Isaac Newton is the newton (N), and it is used to measure force. Force is a fundamental concept in physics that describes the interaction between objects and their ability to cause acceleration or deformation.
The newton is defined as the amount of force required to accelerate a one-kilogram mass at a rate of one meter per second squared (1 N = 1 kg·m/s²). It represents the strength or magnitude of a force and is widely used in various fields, including mechanics, engineering, and everyday life.
Whether it's the force exerted by gravity, the push or pull of objects, or the tension in a spring, the newton provides a quantitative measure for these physical interactions.
The newton is the unit of measurement for force in the International System of Units (SI). It is named after Sir Isaac Newton, a renowned physicist and mathematician who made significant contributions to the understanding of classical mechanics and the laws of motion.
Newton's second law of motion, F = ma (force equals mass times acceleration), is a foundational equation in physics and relates force to the mass and acceleration of an object.
The newton is defined based on this relationship and is used to quantify the effect of forces on objects. Understanding the newton and its application in measuring force is essential in various scientific and engineering disciplines.
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A soapbox derby is to be held on a frictionless hill with a 28 m vertical drop. The track is 300 m long. What is
the change in potential energy of a racecar from start to finish if it and the driver have a combined mass of 113
kg?
Round your answer to a whole number and include correct Sl unit abbreviation.
Answer: -31039 J
Explanation:
a)What is the current I 1 through the resistor R 2?
b) What is the the potential difference across each of the two resistors R2,R3?
In this given circuit, there are two resistors, R2 and R3 connected in series with a battery of 12 V as shown below;\(\Delta V = V = 12 V\)Let us first find the total resistance of the circuit.
Using the formula, resistances in series add up to give the total resistance of the circuit\(R_T = R_2 + R_3 = 8\ \Omega + 12\ \Omega = 20\ \Omega\)
Using Ohm's Law; the current through the circuit can be calculated as follows;
\(I_T = \frac{V}{R_T} = \frac{12\ V}{20\ \Omega} = 0.6\ A\)
Thus, the current through each of the resistors, R2 and R3 is the same and it is equal to the total current of the circuit;\(I_1 = I_2 = 0.6\ A\)
The potential difference across each of the two resistors, R2 and R3 is different because of the difference in resistance. Using Ohm's Law, the potential difference across each resistor can be calculated as follows;
\(\Delta V_2 = V_{R_2} = I_2 \cdot R_2 = 0.6\ A \cdot 8\ \Omega = 4.8\ V\)
\(\Delta V_3 = V_{R_3} = I_2 \cdot R_3 = 0.6\ A \cdot 12\ \Omega = 7.2\ V\)
Thus, the potential difference across resistor R2 is 4.8 V and across resistor R3 is 7.2 V.
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a 60-kg crate is lowered from a loading dock to the floor using a top passing over fixed support. The rope exerts a constant upward force on the crate of 500 N.
A. Will the crate accelerate? Explain.
B. What are the magnitude and direction of the acceleration of the crate?
C. How long will it take for the crate to reach the floor of the height of the loading dock is 1.4m above the floor?
D. How fast is the crate traveling when it hits the floor?
Explanation:
a) What is the weight of the crate?
W = m*g = 60 kg *9.81 m/s^2 = 588.6 N
Sum of the forces in the vertical direction on the box (up is +) = F - W = 500 N - 588.6 N = -88.6 N
Since the forces do not add up to 0, then there is a net force on the crate which will cause the crate to accelerate.
b) F = m*a ==> a = F/m
a = -88.6 N / 60 kg = -1.48 m/s^2 (- means down since above we declared up as +)
c) Assume it starts from rest, vi = 0 m/s
Equation of motion in the vertical direction
h = h0 + v0*t + 1/2*a*t^2
h0 = 1.4 m
h = 0 m
v0 = 0 m/s
a = -1.48 m/s^2
0 = 1.4 m + 0 - 1/2* 1.48 m/s^2 * t^2
1.4 m = 1/2 * 1.48 m/s^2 * t^2
t = 1.38 s
d) vf = vi + a*t
vi = 0 m/s
vf = a*t = -1.48 m/s^2 * 1.38 s = -2.04 m/s
William Herschel thought he had found a comet when he spotted the green disk of: Neptune. Oberon. Uranus. Titania. Triton.
William Herschel thought he had found a comet when he spotted the green disk of Uranus.
Uranus is the seventh planet located far away from the Sun. It is a gaseous planet which was discovered in 1781, mistaken by a comet but after two years it was accepted as a planet. After decades of observations and only one close visit by a spacecraft, which shows us that Uranus has unique atmosphere.
Atmosphere of Uranus is mostly made up of hydrogen and helium as well as a small amount of methane and traces of water and ammonia. The presence of methane gas gives blue colour to Uranus so we can conclude that Uranus is the planet which was thought first a comet by William Herschel.
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An object starts at the 100 m mark and ends up at the -100 m mark, 50
seconds later. What was the velocity? *
The Sun constantly undergoes explosions called solar eruptions. When a solar eruption happens, satellites capture images of bright flashes of light called solar flares. Solar eruptions emit more energy than millions of megaton hydrogen bombs. Space is a vacuum and void of any matter.
The sound of solar eruptions cannot be heard on earth, because they cannot travel through space, as there is no medium.
The colliding, crossing, or reorganisation of magnetic field lines close to sunspots results in solar eruptions, which are rapid explosions of energy.
It is very dense on the Sun's surface. It contains electrically charged gases, which produce magnetic fields with strong magnetic forces in certain regions.
As there is no physical medium in space, where the sound of explosions is meant to travel. However, we are aware that sound cannot travel in a vacuum and needs a medium for propagation.
As a result, we cannot hear the explosions that are taking place in the Sun.
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Your question was incomplete, but most probably your question would be:
The Sun constantly undergoes explosions called solar eruptions. When a solar eruption happens, satellites capture images of bright flashes of light called solar flares. Solar eruptions emit more energy than millions of megaton hydrogen bombs. Space is a vacuum and void of any matter. Write a scientific explanation on why we don't hear solar eruptions on Earth.
. How does the intensity of sunlight received affect Earth’s temperatures?
PLS HELP MEEEE (NO LINKS PLEASE)
The difference between visible light and gamma rays is that
a.
the amplitude of visible light is greater.
c.
they travel through a different medium.
b.
the speed of gamma rays is greater.
d.
the frequency of gamma rays is greater.
Answer:
Gamma rays occupy the short-wavelength end of the spectrum; they can have wavelengths smaller than the nucleus of an atom. Visible light wavesare one-thousandths the width of human hair--about a million times longer than gamma rays. Radio waves, at the long-wavelength end of the spectrum, can be many meters long.
Answer:D "the frequency of gamma rays is greater."
Explanation:Trust
Whenever an electrically charged particle is accelerated, it radiates energy in the form of?.
Answer:
electromagnetic radiation
Explanation:
The student notices that the electronic balance has a zero error, so it shows
mass readings that are all slightly too small.
This means that the density value is
A)incorrect and slightly too large
B)incorrect and slightly too small
C)correct because the student used three significant figures
D)correct because the mass of the block is more than zero
The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small. This means that the density value is incorrect and slightly too small. The correct option is B.
The density is the ratio of the mass and the volume of the object. It is denoted by ρ.
ρ = mass/Volume = m/V
The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small.
As mass is directly proportional to density. The density will also be slight small when mass reading are all slightly small.
Thus, the correct option is B.
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Think about a neutral magnesium atom. Then think of a magnesium ion with a 2+ charge.
How are these two alike? same number of __________
How are they different? different number of ________
Group of answer choices:
A. protons, neutrons
B: protons, electron
C: electrons, neutrons
D: electrons, protons
1. Find the Work and the Power done to increase the velocity of a 9 kg ball from 14
m/s to 30 m/s in 4 s.
Answer:
65
Explanation:
because everyday my birthday
The moon's diameter is 3.48 106 m, and its mean distance from the earth is 3.85 108 m. The moon is being photographed by a camera whose lens has a focal length of 53.0 mm.
(a) Find the diameter of the moon's image on the slide film.
(b) When the slide is projected onto a screen that is 16.1 m from the lens of the projector (f = 103.4 mm), what is the diameter of the moon's image on the screen?
(a). The object distance (do) is essentially at infinity, the image formed on the slide film is at the focal point of the lens, which means the diameter of the moon's image on the slide film will be equal to the diameter of the lens. Thus, the diameter of the moon's image on the slide film is 53.0 mm.
(b). The diameter of the moon's image on the screen is approximately 44.92 mm.
To solve this problem, we can use the thin lens formula:
1/f = 1/di + 1/do,
where f is the focal length of the lens, di is the image distance, and do is the object distance.
(a) Finding the diameter of the moon's image on the slide film:
Given:
Focal length of the lens (f) = 53.0 mm = 0.053 m
Object distance (do) = Mean distance from the Earth to the Moon = 3.85 × \(10^8\) m
Since the camera forms a real image on the slide film, the image distance (di) is equal to the focal length of the lens (f). Therefore, di = f.
Using the thin lens formula, we can solve for the object distance (do):
1/f = 1/di + 1/do
1/0.053 = 1/0.053 + 1/do
1/do = 1/0.053 - 1/0.053
1/do = 0
do = infinity
(b) Finding the diameter of the moon's image on the screen:
Given:
Focal length of the projector lens (f) = 103.4 mm = 0.1034 m
Image distance (di) = Distance from the lens to the screen = 16.1 m
Using the thin lens formula, we can solve for the object distance (do):
1/f = 1/di + 1/do
1/0.1034 = 1/16.1 + 1/do
1/do = 1/0.1034 - 1/16.1
1/do = 0.0096704 - 0.0621118
1/do = -0.0524414
do = -1/0.0524414 ≈ -19.07 m
Since the object distance (do) is negative, it means the object (moon's image) is located on the same side as the lens. In this case, the diameter of the moon's image on the screen will be given by the formula:
diameter = (di/do) × diameter of the moon's image on the slide film
Plugging in the values:
diameter = (16.1 m) / (-19.07 m) × 53.0 mm
diameter = -0.845 × 53.0 mm
diameter ≈ -44.92 mm
The negative sign indicates an inverted image. However, the magnitude of the diameter is what matters, so the diameter of the moon's image on the screen is approximately 44.92 mm.
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A massless spring with force constant
580 N/m is fastened at its left end to a vertical
wall, as shown below.
The acceleration of gravity is 9.8 m/s
2
.
7 kg 5 kg
580 N/m
Initially, the 7 kg block and 5 kg block rest
on a horizontal surface with the 7 kg block in
contact with the spring (but not compressing
it) and with the 5 kg block in contact with the
7 kg block. The 7 kg block is then moved to
the left, compressing the spring a distance of
0.2 m, and held in place while the 5 kg block
remains at rest as shown below.
7 kg 5 kg
k 0.2 m
Determine the elastic energy U stored in
the compressed spring.
Answer in units of J.
The elastic potential energy stored in the compressed spring is determined as 11.6 J.
What is the elastic potential energy of the spring?
The elastic potential energy of the spring is the energy stored in the spring and the magnitude is calculated as follows;
U = ( ¹/₂kx² )
where;
k is the spring constantx is the extension of the springThe given parameters include the following;
the spring constant, k = 580 N/m
the extension of the spring, x = 0.2 m
Substitute the given parameters and solve for the elastic potential energy stored in the spring based on the compression produced by the two blocks.
U = ( ¹/₂kx² )
U = ( ¹/₂ ( 580 N/m ) ( 0.2 m )² )
U = 11.6 J
Thus, the elastic potential energy stored in the compressed spring is a function of the spring constant and extension of the spring.
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A bus travels to proviso east high school from oprfhs. it takes the bus 0.1 hrs to get there when it is travelling 30 miles per hour. if the bus traveled from phs all the way back to oprfhs in 0.15 hrs then what is the bus's displacement?
the bus traveled from all the way back to in 0.15 hrs then
is the bus's displacement-
Displacement of bus is 3 miles.
Given that
A bus travels to proviso east high school from oprfhs.It takes the bus 0.1 hrs to get there when it is travelling 30 miles per hour.the bus traveled from phs all the way back to oprfhs in 0.15 hrs.To find
We have to find the displacement of bus when this traveled from phs all the way back to oprfhs in 0.15 hrs.So according the question
We have
velocity of bus travels to proviso east high school from oprfhsu = 30 mile/hour.
Time taken by bus travels to proviso east high school from oprfhst₁ = 0.1 hour.
Time of bus when this traveled from phs all the way back to oprfhs from proviso east high schoolt₂ = 0.15 hour.
Now, We have to find the total distance travelled by bus
We know that,
\(velocity = \frac{distance}{time}\)
So,
\(u = \frac{distance}{t_1}\)
\(distance d = {u}\times {t_1}\)
d = 30 × 0.1
d = 3 miles
The total distance from oprfhs to phs is 3 miles.
This bus firstly travels from oprfhs to phs and come back from phs to oprfhs so the distance travelled by bus will be same i.e 3 miles.
Now, we can say that when bus traveled from phs all the way back to oprfhs in 0.15 hrs then the displacement of the bus is 3 miles.
Displacement of bus is 3 miles.
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Overgrazing occurs when farm animals, like cows, sheep, and horses, eat all the plants on an area of land. When all of the plants have been eaten, the soil is left bare as is shown in the picture below.
Since overgrazing removes the plants that help hold the soil in place, overgrazing can cause increased _______.
A.
rainfall
B.
erosion
C.
snow
D.
wind
Answer:
erosion
Explanation:
because i just got it right on study island
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I think least electricity is used between probably 7-8a.m. and 4-5p.m.
This is because, around those times, the suns already out. Depending on how sunny it is, it may not be as cold as all the other times of the day. And by then, buildings are typically already warmed all up. Everybody's body heat also may play a factor in buildings. ( if there is a ton of people )
6. Given cost=0 € (2): a) Determine sin28 b) Which quadrant does sin20 lie and what is the angle to the nearest tenth of a degree? Q
Since cost = 0 €, the value of sinθ will be 1. Recall that the Pythagorean identity for sine and cosine states that sin²θ + cos²θ = 1. So, sin²θ = 1 - cos²θ. Given cost=0 €,cosθ=0. Substituting cosθ = 0, we get;sin²θ = 1 - cos²θ. sin²θ = 1 - 0² = 1Therefore,sinθ = √1 = 1
This means that sin28 = 1 Since sin20 lies in the first quadrant (0° to 90°), it will have a positive value. To determine sin20, we can use a calculator or reference a trigonometric table. To the nearest tenth of a degree, sin20 is 0.3 and it lies in the first quadrant.
An identity that expresses the Pythagorean theorem in terms of trigonometric functions is known as the Pythagorean trigonometric identity, or simply the Pythagorean identity. It is one of the fundamental relations between the sine and cosine functions, along with the sum-of-angles formulas. The angle can be any real value, and the equation is s i n 2 + c o s 2 = 1. Given both the sine value and the quadrant in which the angle is located, we can use the Pythagorean identity to determine the angle of cosine.
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By the 2nd century BCE the ____ democratized astrology
A. Greeks
B. Egyptians
C. Romans
Answer:
A
Explanation:
4) Two people are pulling on a chain in opposite directions with forces of 500 N and 600 N. The
forces would best be described as ____.
A) balanced forces
B) unbalanced forces
C) action-reaction forces
D) gravitational forces
Answer: B) unbalanced forces
Explanation:
500 N and 600 N are not equal to each other. The two people are also pulling on the chain in opposite directions. Using these given pieces of information, we can decide that the answer is unbalanced forces acting upon the chain.
500 N ≠ 600 N
Determine whether the series is convergent or divergent. 1 + 7n Σ 57 n = 1 convergent divergent If it is convergent, find its sum. (If the quantity diverges, enter DIVERGES.) 7 4
The given series, 1 + 7n Σ 57 n = 1, is divergent because the terms in the series continue to increase without bounds, the sum of the series also increases indefinitely.
To determine the convergence or divergence of the series, we can analyze its behaviour as n approaches infinity. The series can be written as Σ(1 + 7n*57) for n = 1 to infinity. By simplifying the expression, we have Σ(399n + 1) for n = 1 to infinity.
As n increases, the summand of the series grows linearly with a coefficient of 399. Since the coefficient is nonzero and positive, the series will diverge. This means that the sum of the series will not approach a finite value as n tends to infinity.
Therefore, the given series is divergent, and we cannot find its sum. It is important to note that a divergent series does not have a finite sum. Therefore, the sum of the given series is "DIVERGES."
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Another switch allows one to adjust the magnetic field so that it is either nearly uniform at the center or has a strong gradient. The latter means that the magnitude of the field changes rapidly along the vertical direction near the center. How does this switoh change the current in the two coils?
The switch that adjusts the magnetic field to be either nearly uniform or have a strong gradient will affect the current in the two coils differently.
When the magnetic field is nearly uniform at the center, the current in both coils will remain relatively unchanged. The uniform field will not induce any significant voltage in the coils, so the current will flow through them as usual.
However, when the magnetic field has a strong gradient, the current in the two coils will be affected differently. The rapidly changing field will induce a voltage in the coils according to Faraday's law of electromagnetic induction. This induced voltage will result in a change in the current flowing through the coils. The magnitude and direction of the induced current will depend on the specific characteristics of the coils and the magnetic field gradient.
In summary, the switch that changes the magnetic field from uniform to having a strong gradient will induce a change in the current flowing through the coils due to the induced voltage.
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overall, a p-wave increases in velocity with depth. this implies that ______.
Overall, a p-wave increases in velocity with depth. This implies that the density and/or rigidity of the material that the p-wave is passing through is increasing with depth.
This is because p-waves are compressional waves that propagate through the solid material of the Earth, and the speed at which they travel is influenced by the density and rigidity of that material. As the density and/or rigidity increase with depth, the p-wave encounters a greater resistance and travels at a faster velocity.
This is important for geophysicists who use seismic data to determine the structure and composition of the Earth's interior, as they can use the velocity of p-waves to infer properties of the materials they are passing through. Overall, the increasing velocity of p-waves with depth provides valuable information about the Earth's internal structure.
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Ferris wheel has a diameter of 76 m and completed one revolution every 20 min.
a)Calculate the tangential speed the car
b) Calculate the magnitude to the centripetal acceleration of one of the car
The tangential speed of a point on the Ferris wheel is approximately 2.01 m/s. the magnitude of the centripetal acceleration of a point on the Ferris wheel is approximately 0.106 m/s².
The tangential speed of a point on the Ferris wheel is given by the formula:
v = (2πr) / T
where v is the tangential speed, r is the radius of the Ferris wheel (half the diameter), and T is the time taken to complete one revolution.
In this case, the diameter of the Ferris wheel is 76 m, so its radius is 38 m. It completes one revolution every 20 min, so the time taken is T = 20 min = 1200 s. Substituting these values in the formula, we get:
v = (2π × 38 m) / 1200 s
≈ 2.01 m/s
The centripetal acceleration of a point on the Ferris wheel is given by the formula:
a = v² / r
where a is the magnitude of the centripetal acceleration, v is the tangential speed, and r is the radius of the Ferris wheel.
In this case, we have already calculated the tangential speed to be approximately 2.01 m/s, and the radius of the Ferris wheel is 38 m. Substituting these values in the formula, we get:
a = (2.01 m/s)² / 38 m
≈ 0.106 m/s²
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What is the relationship between an object’s mass and the amount of inertia that it has?.
1According to the passage, where is “the most expensive house” located?
A) on the surface of Mars
B) Hollywood, CA
C) circling above Earth
D) New York City
Answer:
C) circling above earth
What work is done when we apply a force of 5N and move in the direction of the force 2m?
Answer:
10 J
Explanation:
work = force x distance
work = 5x2
work = 10 J
Joule is the unit for work
Please help!!!!!!!!!
What help do you want? If you tell, I may help you.
A satellite is orbiting around a planet in a circular orbit. The radius of the orbit, measured from the center of the planet is R = 2.1×10^7 m. The mass of the planet is M = 1.6 × 10^24 kg.
a) Express the magnitude of the gravitational force F in terms of M, R, the gravitational constant G, and the mass m of the satellite.
b) Express the magnitude of the centripetal acceleration ac of the satellite in terms of the speed of the satellite v and R.
c) Express the speed v in terms of G, M, and R.
d) Calculate the numerical value of v, in m/s.
The magnitude of the gravitational force between the planet and the satellite, F = G * (M * m) / R².
The magnitude of the centripetal acceleration of the satellite, ac = v² / R
What is the gravitational force?The magnitude of the gravitational force F between the planet and the satellite is given by the formula:
F = G * (M * m) / R²where;
G is the gravitational constant (6.6743 × 10⁻¹¹ Nm²/kg²),M is the mass of the planet,m is the mass of the satellite, andR is the radius of the orbit.b) The magnitude of the centripetal acceleration ac of the satellite is given by the formula:
ac = v² / R
where v is the speed of the satellite.
c) We can equate the gravitational force to the centripetal force, which gives:
G * (M * m) / R² = m * v² / R
Solving for v, we get:
v = √(G * M / R)
d) Substituting the given values, we get:
v = √((6.6743 × 10⁻¹¹ Nm²/kg²) * (1.6 × 10²⁴ kg) / (2.1 × 10⁷ m))
v ≈ 2.41 × 10³ m/s
Therefore, the speed of the satellite is approximately 2.41 × 10^3 m/s.
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