Answer:
The answer is D. fusion
Consider the following chemical reaction:
C(s)+H2O(g)→CO(g)+H2(g)
How many liters of hydrogen gas are formed from the complete reaction of 1.07 mol of C? Assume that the hydrogen gas is collected at a pressure of 1.0 atm
and a temperature of 317 K.
Express your answer using two significant figures.
Answer: 27.85 L
Explanation:
Ideal gas law
V = nRT/P
V = 1.07 X 0.0821 X 317 / 1= 27.85 L
The enthalpy change for the reaction between two molecules of carbon oxysulfide (COS) to form one molecule of CO2 and one molecule of CS2, as shown below, is –3.2 × 10–24 kJ per molecule of COS. The bond energy for the C=S bond in CS2 has been determined to be 552 kJ/mol
What is the apparent bond energy of a carbon–sulfur bond in COS? Use the bond energies below
____ kJ
C=S 552 Kj/mole
C=O 799 KJ/mole
To calculate the apparent bond energy of a carbon-sulfur bond in COS, we need to use the bond energies of the individual bonds that make up the molecule. The apparent bond energy of a carbon-sulfur bond in COS is approximately 1092 kJ/mol.
The apparent bond energy is the difference between the energy required to break the bonds in the reactants and the energy released when new bonds form in the products.
The enthalpy change of two (2) moles of COS is:
ΔH = –3.2 × 10⁻²⁴ × 2 × 6.02 × 10²³ = -3.85 kJ / mol
ΔH = ∑bond energy of reactants - ∑bond energy of products
2×C=O + 2 × C=S -[2 × C=O] + [2×C=S)
-3.85 = 2 × C=S -(2 × 552)
2 × C=S = 1104 - 3.85 = 1100.15
C=S = 1100.15 /2 = 550.08 kJ / mol
So apparent energy is 550.08 kJ / mol.
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Calculate the enthalpy change for the reaction C2H4(g) + H2(g) -> C2H6(g) from the following data: Show your work.
The enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) is -137.15 kJ/mol.
Given:C2H4(g) + H2(g) → C2H6(g)The enthalpy of formation of C2H6(g) is -84.68 kJ mol-1The enthalpy of formation of C2H4(g) is 52.47 kJ mol-1The enthalpy of formation of H2(g) is 0 kJ mol-1Hence, using Hess's Law, the enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) can be calculated by considering the formation of reactants and products from their respective elements. It can be given as:
\($$C_2H_4 + H_2 → C_2H_6$$$$\Delta H = H_f(C_2H_6) - [H_f(C_2H_4) + H_f(H_2)]$$$$\Delta H = -84.68 - [52.47 + 0]$$$$\Delta H = -84.68 - 52.47$$$$\Delta H = -137.15 kJ/mol$$.\)
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(a) Describe the process by which Nitrogen is obtained from air on a large scale
The element nitrogen exists as a gas and is obtained from air on a large scale by fractional distillation of air.
What is an element?An element is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.
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How moles of Cl' are in a 45 mL of 1,4 M solution of NaCl?
Answer:
.063 moles Cl-
Explanation:
To find moles multiply molarity by volume.
1.4*.045=.063 moles Cl-
how many grams of water are needed to react with 71.0g CaN2?
Answer:
1
Explanation:
Mass of
C
a
C
N
2
= 75.0 g
From the equation,
C
a
C
N
2
(
s
)
+
3
H
2
O
(
l
)
→
C
a
C
O
3
(
s
)
+
2
N
H
3
(
g
)
1 mol of
C
a
C
N
2
reacts with 3 moles of water to give calcium carbonate and ammonia.
Number of moles of
C
a
C
N
2
,
n
=
G
i
v
e
n
m
a
s
s
M
o
l
a
r
m
a
s
s
Molar mass of
C
a
C
N
2
= 92.11 g/mol
Therefore,
n
C
a
C
N
2
=
75
g
92
.11
g
/
m
o
l
=
0
.814
m
o
l
Moles of water =Therefore,
n
C
a
C
N
2
=
75
g
92
.11
g
/
m
o
l
=
0
.814
m
o
l
Moles of water =
3
×
0
.814
m
o
l
e
s
=
2
.442
m
o
l
e
s
Mass of water needed;
=
m
o
l
e
s
o
f
w
a
t
e
r
×
m
o
l
a
r
m
a
s
s
o
f
w
a
t
e
r
=
2
.442
m
o
l
×
18
g
/
m
o
l
=
43
.956
g
Thus, 43.96 g of water is needed to react with 75 g of
C
a
C
N
2
.
Which of the following represents a beta decay?
OA. NiNi+ y
28
B. 23 Np
→>>>
231Pa + c
C. 220Rn 214Po + He
OD. 21Bi-2Po+ e
→>>
²¹Bi → ²¹²Po + e⁻, represents a beta decay, as it involves the emission of a beta particle (e⁻) from the nucleus of bismuth-21 (²¹Bi). Option D
Beta decay is a type of radioactive decay in which a beta particle (either an electron, represented as e⁻, or a positron, represented as e⁺) is emitted from the nucleus of an atom. The emission of a beta particle is accompanied by a change in the atomic number of the nucleus.
Looking at option D: ²¹Bi → ²¹²Po + e⁻, we can see that a beta particle (e⁻) is emitted from the nucleus of bismuth-21 (²¹Bi), resulting in the formation of polonium-212 (²¹²Po). The atomic number of the nucleus changes from 83 to 84, indicating a beta decay process.
Let's analyze the other options:
Option A: Ni → Ni+ y: This does not represent a beta decay. The symbol "y" typically represents the emission of gamma radiation, which is a high-energy photon. It does not involve a change in atomic number or the emission of a beta particle.
Option B: ²³Np → ²³¹Pa + c: This equation does not represent beta decay either. The symbol "c" does not correspond to any known particle emitted during radioactive decay.
Option C: ²²⁰Rn → ²¹⁴Po + He: This equation represents alpha decay, not beta decay. The emission of an alpha particle (⁴He) from the nucleus of radon-220 (²²⁰Rn) is observed, resulting in the formation of polonium-214 (²¹⁴Po). option D
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For the reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many grams of lead(II) iodide, PbI2, are produced from 81.1 g of potassium iodide, KI?
Taking into account the reaction stoichiometry, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.
Reaction stoichiometryIn first place, the balanced reaction is:
2 KI + Pb(NO₃)₂ → PbI₂+ 2 KNO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
KI: 2 molesPb(NO₃)₂: 1 molePbI₂: 1 moleKNO₃: 2 molesThe molar mass of the compounds is:
KI: 166 g/molePb(NO₃)₂: 331.2 g/molePbI₂: 461 g/moleKNO₃: 101.1 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
KI: 2 moles ×166 g/mole= 332 gramsPb(NO₃)₂: 1 mole ×331.2 g/mole= 331.2 gramsPbI₂: 1 mole ×461 g/mole= 461 gramsKNO₃: 2 moles ×101.1 g/mole= 202.2 gramsRule of threeRule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
That is, what is intended with it is to find the fourth term of a proportion knowing the other three.
If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, being a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So: x= (c×b)÷a
Mass of PbI₂ formedThe following rule of three can be applied: if by reaction stoichiometry 332 grams of KI form 461 grams of PbI₂, 81.1 grams of KI form how much mass of PbI₂?
mass of PbI₂= (81.1 grams of KI× 461 grams of PbI₂)÷ 332 grams of KI
mass of PbI₂= 112.61 grams
Then, 112.61 grams of lead(II) iodide, PbI₂, are produced from 81.1 g of potassium iodide, KI.
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Micheal has a substints that he puts in container 1 the substance has a volume of 5 cubic meters
Answer: Solids and liquids don't suddenly change their volumes.
But gases do...they expand to fill whatever container you
put them in.
Michael's mystery substance is in the gaseous phase.
Explanation:
under what circumstances do you think credit cards should NOT be used ?
It's never a good idea to use your credit card when experiencing strong emotions, especially if you tend to steer toward 'retail therapy.
The displacement by CH3CO2- on (a) bromoethane or (b) bromocyclohexane. ___ Submit AnswerTry Another Version
Answer:
The displacement by \(CH_{3}CO_{2}^{-}\) on bromoethane.
Explanation:
Given that,
The displacement by \(CH_{3}CO_{2}^{-}\) on bromoethane or bromocyclohexane.
We know that,
Bromoethane is not stable. It can easily break. But bromocyclohexane is more stable obstruct and very strong to displace.
Bromocyclohexane is a ring and we can not break easily of a ring.
So, bromocyclohexane does not displace by \(CH_{3}CO_{2}^{-}\).
Hence, The displacement by \(CH_{3}CO_{2}^{-}\) on bromoethane.
what's the summary of matter
matter is anything that has mass and volume...it has three state thus solid, liquid and gas.. It possess chemical and physical changes.
Complete the equation for the equilibrium present in the region bc X(s)=?
The following equality statistic is available for the BC X (s) region states:
The following data is obtained using the equilibrium diagram:
shows the various categories that can be found in various temperatures and shapes.
It demonstrates how one object can solidly melt over another.
Describes the amount of the temperature at which the material system solidifies or solidifies.
The rate of reaction is equal to the rate of reaction in an equilibrium situation.
Examples of equilibrium include a book on the table, liquid in a tightly sealed container, full solution, ionic compounds in polar solvents, and the synthesis of ammonia.
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What types of geological events can the following interactions produce?
Divergent boundaries:
Convergent boundaries:
Transform boundaries
Answer:
divergent boundaries- volcanic activity, shallow earthquakes, new sea floor.
convergent boundaries- earthquakes, volcanoes, formation of mountains.
transform boundaries- earthquakes, crustal deformation
Explanation:
(hope this helped!!)
Which phrase gives two processes scientists think move the Earth's lithospheric plates?
A.)gravity acting on the edges of plates and convection in the mantle
B.)convection in the mantle and pressure of magma on the edge of the plate
C.)friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
C.)gravity acting on the edges of plates and friction between the plate and the asthenosphere
The reason i ask this question is bc i wanted to give u guys the right answeralso the correct answer is "A"
Group A elements are considered representative elements. True False
Answer:
This is True
Explanation:
If you look at the elemetnts and use notes, you can see it is a represetaive element. have a nice day! good luck!
Formic acid has a Ka of 1.77*10-4. To 55.0 mL of 0.25 M solution 75.0 of 0.12 M NaOH is added . What is the resulting pH.
Answer:
To solve this problem, we first need to write the balanced chemical equation for the reaction between formic acid (HCOOH) and sodium hydroxide (NaOH): HCOOH + NaOH → NaCOOH + H2O From the equation, we can see that 1 mole of HCOOH reacts with 1 mole of NaOH to produce 1 mole of NaCOOH and 1 mole of H2O. Therefore, the number of moles of NaOH added can be calculated as follows: moles of NaOH = concentration × volume = 0.12 M × 0.075 L = 0.009 mol Since the reaction is a neutralization reaction, the number of moles of HCOOH initially present can be calculated as follows: moles of HCOOH = concentration × volume = 0.25 M ×
Answer:
4.88
Explanation:
Formic acid is a weak acid and its dissociation can be represented by the equation: HCOOH ⇌ H+ + HCOO-. The acid dissociation constant (Ka) for this reaction is 1.77*10^-4. When NaOH is added to the solution, it will react with the formic acid to produce its conjugate base (formate ion) and water. This reaction can be represented by the equation: HCOOH + OH- → HCOO- + H2O.
To calculate the resulting pH, we need to determine the number of moles of formic acid and NaOH present in the solution. The number of moles of formic acid can be calculated by multiplying its molarity by its volume in liters: 0.25 M * 0.055 L = 0.01375 moles. Similarly, the number of moles of NaOH can be calculated as: 0.12 M * 0.075 L = 0.009 moles.
Since NaOH is a strong base, it will react completely with formic acid to produce formate ions and water. This means that 0.009 moles of formic acid will react with 0.009 moles of NaOH to produce 0.009 moles of formate ions and water.
After the reaction, there will be 0.01375 - 0.009 = 0.00475 moles of formic acid left in the solution and 0.009 moles of formate ion produced.
The total volume of the solution after adding NaOH is 55 mL + 75 mL = 130 mL or 0.13 L.
We can now use an ICE table to calculate the equilibrium concentrations of all species present in the solution:
(ICE table Picture attached below)
Substituting these values into the expression for Ka and solving for x gives us:
Ka = [H+][HCOO-]/[HCOOH] = x(0.009/0.13 + x)/(0.00475/0.13 - x) = 1.77*10^-4
Solving this quadratic equation gives us x = [H+] = 1.33*10^-5 M.
The pH of the solution can now be calculated as pH = -log[H+] = -log(1.33*10^-5) = 4.88.
So, the resulting pH after adding NaOH to the formic acid solution is 4.88.
If the student’s estimate of the balloon’s volume was incorrect and the actual volume was 620 ml, would the amount of glucose that actually reacted be more than or less than the amount calculated in part (c)? Explain your response.
( C answer ) only 1.9 g of glucose reacted and only .0211 mol of co2 was formed.
The number of moles of CO2 produced is 0.021 moles
If the estimated volume of the balloon is wrong then the amount of glucose reacted must be more than is stated.
What is respiration equation?The respiration equation represents the chemical process of aerobic cellular respiration, which occurs in the mitochondria of cells and is the primary way in which cells generate energy in the form of ATP (adenosine triphosphate).
The equation of the reaction is;
C6H12O6 + 6O2 → 6CO2 + 6H2O + ATP
We know that;
Number of moles of glucose = 10 g/180 g/mol
= 0.056 moles
PV = nRT
n = PV/RT
n = 1 * 0.55/318 * 0.082
n = 0.021
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La fórmula CH3-CH=CH-CH2-CH2-CH2-CH3 ,se le debe llamar de la siguiente manera.
A) Hepteno
B) 1 Hepteno
C) 2 Hepteno
D) Heptinol
ayuden plis
what is point group of allene?
Allene (1,2-propadiene) has point group D2d, itself is achiral because it has two planes of symmetry. ... An allene with substituents on one terminal carbon atom are unlike and substituent on other terminal carbon atoms are same, allene will be achiral. It will have one symmetry plane.
Hope this helped :)
conclusion of solution and filteration of organic compounds method
Filtration is the process of passing a liquid containing contaminants through a filter to get a cleaner liquid.
What can you conclude after learning about filtration of solutions of organic compounds?After filtration impurities are left on the filter when the liquid goes through it, resulting in a cleaner combination. The procedure of separating one ingredient from another in a compound is used in the purification of chemical compounds or any materials. A mixed sample is turned into fresh samples, each of which contains a single ingredient.Separation procedures are then utilised to separate these compounds. These techniques alter the relative proportions of components in a combination.The type of the compounds and the impurities in them influence the purification of organic chemicals and compounds.
Purification of compounds can be done in other methods as well such as distillation, chromatography, sublimation and crystallisation.
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Full question:
What can you conclude after learning about filtration of solutions of organic compounds? Name other methods of purification of compounds.
Choose the mole ratio below that is INCORRECT based on the given balanced equation:
2 C2H5OH + 7 O2 --> 4 CO2 + 6 H2O
O 2 moles C2H5OH = 4 moles CO2
O 7 moles O2 = 2 moles C2H5OH
O 4 moles CO2 = 4 moles O2
O 6 moles H2O = 7 moles O2
Answer:
4 moles CO₂ = 4 moles O₂
Explanation:
The incorrect mole ratio is 4 moles CO₂ = 4 moles O₂.
Let us write the reaction equation:
2C₂H₅OH + 7O₂ → 4CO₂ + 6H₂O
To write mole ratios in a chemical reaction, we must ensure the equation is balanced.
Since the given expression is balanced,
Then 4 moles CO₂ = 4 moles O₂ is not correct;
Rather;
4 moles CO₂ = 7 moles O₂ is the right expression
Which period 2 element would the 4th ionization energy be much larger than the 3rd ionization energy?
Period 2 element would the 4th ionization energy be much larger than the 3rd ionization energy is Boron.
Boron belongs to period second. atomic no. of boron is 5 and the electronic configuration is given as :
B₅ = 1s² 2s² 3p₁
The 1st ionization energy = 800.6
the 2nd ionization energy = 2427.1
the 3rd ionization energy = 3659.7
the 4th ionization energy = 25025.8
So. we can see that the 3rd ionization energy is much lower than 4th ionization energy because after removing the 3rd electron from 2s boron will attain the stable electronic configuration of helium. now to remove electron from filled orbital it will require much larger energy the 3rd ionization energy.
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I need help with this
The theoretical yield of water formed from the reaction of 46.8g of octane and 287g of oxygen gas is 58.58 g.
What is a balanced chemical equation?A balanced chemical equation is a representation of a chemical reaction using chemical formulas and symbols. It shows the reactants and products of the reaction, and the coefficients in front of the formulas ensure that the number of atoms of each element is the same on both sides of the equation.
The balanced chemical equation for the reaction between octane and oxygen gas is:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
According to the stoichiometry of the balanced equation, 2 moles of octane react with 25 moles of oxygen gas to produce 18 moles of water. Therefore, the molar ratio of octane to water is 2:18 or 1:9.
First, we need to determine which reactant is limiting, i.e., which reactant will be completely consumed in the reaction. To do this, we can calculate the amount of water that would be produced if each reactant were to react completely and then compare the results.
The molar mass of octane (C8H18) is 114.23 g/mol, so 46.8 g of octane is equal to:
46.8 g / 114.23 g/mol = 0.41 mol
The molar mass of oxygen gas (O2) is 32.00 g/mol, so 287 g of oxygen gas is equal to:
287 g / 32.00 g/mol = 8.97 mol
Now, we can calculate the theoretical yield of water based on the amount of each reactant:
Octane: 0.41 mol octane × 9 mol H2O/1 mol octane = 3.69 mol H2O
Oxygen gas: 8.97 mol oxygen gas × 9 mol H2O/25 mol O2 = 3.25 mol H2O
Since the stoichiometry of the reaction indicates that the amount of water produced should be proportional to the amount of octane used, and the calculation shows that less water would be produced if we used all of the oxygen gas, we conclude that oxygen is the limiting reactant.
Therefore, the theoretical yield of water formed is 3.25 mol H2O × 18.02 g/mol = 58.58 g H2O.
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Name two indicators used in quantitative analysis.
At constant current is passed through an electrolytic cell containing molten MgCl2 for 18 hr. if 4.8 x 105 g of Cl2
are obtained. Calculate the current in Amperes.
The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.
To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.
Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:
Q = nF
Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.
In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.
First, we need to calculate the number of moles of Cl2 produced:
Molar mass of Cl2 = 35.45 g/mol
Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol
Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:
Q = nF
Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)
Q ≈ 1.308 x 10^9 C
The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.
Given that the time is 18 hours, we convert it to seconds:
Time = 18 hours * 60 minutes/hour * 60 seconds/minute
Time = 6.48 x 10^4 seconds
Finally, we can calculate the current:
Current (I) = Q / Time
I = (1.308 x 10^9 C) / (6.48 x 10^4 s)
I ≈ 2.02 x 10^4 Amperes
Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.
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Contrast the combustion of glucose in a flame to harvesting the energy from glucose in a biological cell. What key differences are there?
• Glucose (sugar ) is made out of ,carbon, hydrogen an oxygen., When exposed through a fire (combustion) , the heat results in those atoms combining with the oxygen in the air and, turn into liquid, and releases CO2. (exothermic reactio)
• On the contrary; ,the energy can be harvested from glucose in a biological cell through, cellular respiration. ,whereby, ,glucose is reduced to provide energy in the form of ATP and heat,. (endorthermic reaction )
) Calculating Heat from Thermochemical Equations
The thermochemical equation for the combustion of methane gas is:
Calculate much heat is released when 3.5 moles of methane gas undergo a combustion reaction.
A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.
What is a combustion reaction?A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:
CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol
The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.
So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol
Therefore, -3115 kJ/mol of heat is released.
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HELP ASAP ILL MARK BRAINLIEST
what is the number of molecules in 2.25 mol. of carbon dioxide molecules (CO2)
Answer:
1.36 x 10^24 molecules
Explanation:
1 mole of CO2 has 6.022 x 10^23 moles
=> 2.25 x 6.022 x 10^23 = 1.35495 x 10^24 or 1.36 x 10^24