How did astronomers precisely determine the length of an Astronomical Unit in the 1960s?

Answer:

Approximately \(4.7\; {\rm s}\).

Explanation:

Acceleration is the rate of change in velocity.

The initial velocity of this vehicle was \(v_{0} = 24\; {\rm m\cdot s^{-1}}\). After stopping, the velocity will be \(v_{1} = 0\; {\rm m\cdot s^{-1}}\). Hence, the change in the velocity of this vehicle will be:

\(\begin{aligned}\Delta v &= v_{1} - v_{0} \\ &= 0\; {\rm m\cdot s^{-1}} - 24\; {\rm m\cdot s^{-1}} \\ &= (-24)\; {\rm m\cdot s^{-1}} \end{aligned}\).

It is given that the vehicle decelerates at a constant rate of \(5.1\; {\rm m\cdot s^{-2}}\). Thus, the rate of change in the velocity of this vehicle (acceleration) will be negative (velocity is decreasing) at \(a = (-5.1)\; {\rm m\cdot s^{-2}}\).

To find the time required for this change in velocity, divide the change by the rate of change:

\(\begin{aligned}(\text{time required}) &= \frac{(\text{change})}{(\text{rate of change})} \\ &= \frac{\Delta v}{a} \\ &= \frac{(-24)\; {\rm m\cdot s^{-1}}}{(-5.1)\; {\rm m\cdot s^{-2}}} \\ &\approx 4.7\; {\rm s}\end{aligned}\).

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Explanation:

Given that,

Length of gold wire, l = 4 m

Voltage of battery, V = 1.5 V

Current, I = 4 mA

The resistivity of gold, \(\rho=2.44\times 10^{-8}\ \Omega-m\)

Resistance in terms of resistivity is given by :

\(R=\dfrac{\rho l}{A}\)

Also, V = IR

So,

\(\dfrac{V}{I}=\dfrac{\rho l}{A}\)

A is area of wire,

\(\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}\), r is radius, r = d/2 (diameter=d)

\(\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m\)

Out of four option, near option is (C) 17 μm.

The diameter of the wire is 18μm and the closest answer is option C.

The resistance of a wire is proportional to its length and inversely proportional to its area.

Given that a  4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. Then,

R = (ρL)/A

where

ρ = resistivity = 2.44 × 10-8 Ω·m

L = length

A = Area = \(\pi ^{2}\)D/2

D = diameter of the wire

From Ohm's law, V = IR

make resistance R the subject of the formula

R = V/I

R = 1.5/4 x \(10^{-3}\)

R = 375 Ω

Substitute all the parameters into the formula

R = (ρL)/A

375 = (2.44 × \(10^{-8}\) x 4)/A

A = (9.76 × \(10^{-8}\))/ 375

A = 2.603 x \(10^{-10}\) \(m^{2}\)

but

A =  \(\pi (D/2)^{2}\)

2.603 x \(10^{-10}\) =  \(\pi (D/2)^{2}\)

\(\pi\)\(D^{2}\) /4 = 2.603 x \(10^{-10}\)

\(\pi\)\(D^{2}\) = 1.04 x \(10^{-9}\)

\(D^{2}\) = (1.04 x \(10^{-9}\))/ \(\pi\)

D = \(\sqrt{3.3 * 10^{-10} }\)

D = 1.8 x \(10^{-5}\) m

D = 18 μm

Therefore, the diameter of the wire is 18μm and the closest answer is option C.

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The external structure of a solid  refers to the overall structure of the solid due to the arrangement of its particles..

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

A solid is a substance which has a definite shape and volume.

Solids are one of the three states of matter.

The particles in a solid are arrange in regular repeating patterns due to the strong intermolecular forces of attraction between the particles in the solid.

The external structure of a solid refers to the overall structure of the solid due to the arrangement of its particles.

The external structure of a solid may be a crystal or amorphous in shape.

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

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The theory that has been proposed that would explain the neurology of memory are;

The neurophysiology of learning  can be described as the theory that cover the three main cognitive processes and this can be regarded as core value of the the information processing system.

It should be noted that the  information processing system usually make use of the  brains  which helps to remember information through attention, perception and all this are found in the functionality of the brain system in the human system.

Therefore, All of these are correct.

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The increase in the energy of an electromagnetic wave can be achieved only by decreasing the wavelength. Hence, option (d) is correct.

The given problem is based on the fundamentals of electromagnetic wave and the energy stored in an electromagnetic wave.

The mathematical expression for the energy carried out by the  electromagnetic waves is given as,

\(E = h \times \nu\\\\E = \dfrac{h \times c}{ \lambda}\)

Here,

h is the Planck's constant.

\(\nu\) is the frequency of the electromagnetic wave.

c is the speed of light.

\(\lambda\) is the wavelength of wave.

Clearly, the energy of electromagnetic waves is directly proportional to the frequency of wave and inversely proportional to wavelength. So, decreasing the wavelength, we can easily increase the energy of electromagnetic wave.

Thus, we can conclude that the increase in the energy of an electromagnetic wave can be achieved only by decreasing the wavelength. Hence, option (d) is correct.

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Answer:

it represents the physical changes.

Explanation:

I

a)  the average power of the elevator motor during this period is 0.1696 hp

b) The power during an upward trip with constant speed is 16.13 horsepower.

To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.

Given:

Mass of the elevator (m) = 682 kg

Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²

Time taken for acceleration (t) = 3.10 s

(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:

d = 0.5 * a * t^2

= 0.5 * 0.5806 m/s² * (3.10 s)^2

= 1.0153 m

Next, we can calculate the work done (W) by the elevator motor:

W = m * a * d

= 682 kg * 0.5806 m/s² * 1.0153 m

= 391.55 J

Now, to find the average power (P), we divide the work done by the time taken:

P = W / t

= 391.55 J / 3.10 s

= 126.36 W

To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.

Therefore, the average power of the elevator motor during this period is:

P = 126.36 W / 745.7

= 0.1696 hp

(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.

The force of gravity (Fg) can be calculated using:

Fg = m * g

= 682 kg * 9.8 m/s²

= 6683.6 N

The power (P) required is given by the formula:

P = Fg * v

= 6683.6 N * 1.80 m/s

= 12030.5 W

To convert the power to horsepower:

P = 12030.5 W / 745.7

= 16.13 hp

Therefore, the power during an upward trip with constant speed is 16.13 horsepower.

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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The average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.

The correct answer is option D.

In the given graph, we can deduce the following;

The average speed of the ant is calculated as;

\(average \ speed = \frac{total \ distance }{total \ time }\)

The total distance from the graph is calculated as follows;

The total distance = (6 + 2 + 2 + 7 + 7 + 3 + 2) cm = 29 cm

\(average \ speed = \frac{total \ distance }{total \ time } = \frac{29 \ cm}{105 \ s} = 0.276 \ cm/s\)

The average velocity is calculated as the change in displacement per change in time.

The displacement is the shortest distance between the start and end positions.

Notice, you have a right triangle, now calculate the length of  line P.

                                                ↓end

                                                ↓

                                                ↓ 6cm

                                                ↓

  start -------------13 cm------------

Use Pythagoras theorem to solve for P.

\(P^2 = 6^2 + 13^2\\\\P^2 = 36 + 169\\\\P^2 = 205\\\\P= \sqrt{205} \\\\P = 14.318 \ cm\)

The average velocity of the ant is calculated as;

\(average \ velocity= \frac{\Delta displacemnt }{total\ time }= \frac{14.318 \ cm}{105 \ s} = 0.136 \ cm/s \\\\\)

Thus, the average speed of the ant is 0.276 cm/s and the average velocity is 0.136 cm/s.

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a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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The amount left of a radioactive sample amount N0 if the decay constant is 0.00125 seconds and the time is 180 seconds is 0.7999 N.

The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.

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A) The work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.

B) The book is moving at 1.91 m/s at point C.

C) If +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.

(a) To find the work done on the book between points A and B, we need to use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy:

Net work done = change in kinetic energy

The change in kinetic energy can be found by subtracting the initial kinetic energy at point A from the final kinetic energy at point B:

change in kinetic energy = (1/2)mvB^2 - (1/2)mvA^2

where m is the mass of the book, vA is the velocity of the book at point A, and vB is the velocity of the book at point B.

Substituting the given values, we get:

change in kinetic energy = (1/2)(1.50 kg)(1.25 m/s)^2 - (1/2)(1.50 kg)(3.21 m/s)^2

= -5.32 J

Since the final velocity is less than the initial velocity, the change in kinetic energy is negative. Therefore, the net work done on the book between points A and B is also negative. The magnitude of the net work done is:

|net work done| = |-5.32 J| = 5.32 J

Therefore, the work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.

(b) Since -0.750 J of work is done on the book from point B to point C, we can use the work-energy principle again to find the final velocity at point C:

Net work done = change in kinetic energy

Substituting the given values, we get:

-0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)

Solving for vC, we get:

vC = 1.91 m/s

Therefore, the book is moving at 1.91 m/s at point C.

(c) If +0.750 J of work was done on the book from point B to point C, we would have:

0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)

Solving for vC, we get:

vC = 2.31 m/s

Therefore, if +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.

The given question is incomplete, the complete question is

A 1.50-kg book is sliding along a rough horizontal surface. at point a it is moving at 3.21 m>s, and at point b it has slowed to 1.25 m>s. (a) how much work was done on the book between a and b? (b) if -0.750 j of work is done on the book from b to c, how fast is it moving at point c? (c) how fast would it be moving at c if +0.750 j of work was done on it from b to c?

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Answer:

The first velocity is 0.19

The second velocity is 0.45

Explanation:

In order to answer the question of where the arrows of the magnetic domains point, one must consider the properties of the magnets' poles: A) The arrows line up and point upward.

Iron or cobalt is a common component of permanent magnets. An alloy composed of aluminum is called alnico. Involves a systematic process minerals are capable of making powerful electromagnets. They are widely utilized in industrial and consumer electronics applications.

The word "lithos magnes" from classical Greek is where the name first appeared. According to Pliny's explanation in his "Naturalis Historia," the term is derived from the myth of the Greek shepherd Magnes on Mount Ida, whose iron staff and the nails in his shoes were drawn to the magnetite stones.

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Answer:

POINTS LEFT

Explanation:

just did it

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Answer:

6 is Electrical

1 is Thermal

13 is Mass and Acceleration

3 is Force and Distance

2 is Work and Time

4 is Mechanical

Explanation:

NOTE: Sorry if I missed any and sorry if some aren't correct, but I think they are :)

Answer:

Therefore, the GPE of the fish from the given height is 26.19 J.

Explanation:

The gravitational potential energy (GPE) of an object at a height h is given by the formula:

GPE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

In this case, the mass of the fish is 0.3 kg, the height from which it was dropped is 9 meters, and the acceleration due to gravity on Earth is approximately 9.81 m/s². Thus, the GPE of the fish can be calculated as:

GPE = (0.3 kg) × (9.81 m/s²) × (9 m) = 26.19 J

Therefore, the GPE of the fish from the given height is 26.19 J.

I like puffins

To answer the question: "A student made a model of isostasy by placing a block of wood in a beaker of water how can a student demonstrate isostaic rebound using her model?" If she "Press the block down and let go

The state of gravitational equilibrium between the Earth's crust and mantle known as isostasy or isostatic equilibrium causes the crust to "float" at an elevation that is dependent on its thickness and density.

This idea is used to explain how various topographic heights can occur on the surface of the Earth.

Hence, to test the model she has, she should press the block down and let go

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A student made a model of isostasy by placing a block of wood in a beaker of water how can a student demonstarte isostaic rebound using her model

A. Blow vigorously on the block

B. Press the block down and let go

C. Add water until the beaker overflow

D. Pour out all the water

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

Option c.

Explanation:

Inverse of a statement is defined as the statement in which both hypothesis and conclusion are in negative form.

In the given sentence, "If today is Tuesday, then I have Geometry class", hypothesis is "If today is Tuesday" and the conclusion is "I have Geometry class.".

Inverse of the given statement is :

If today is not Tuesday, then I do not have Geometry class.

The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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The melting point of the substance in the heating curve is 20°C.

1) The melting point of the substance is the temperature at the point where, the substance is having a phase change from solid state to liquid. So, the temperature at point B, 20°C is its melting point.

2) The boiling point of the substance is the temperature at the point where, the substance is having a phase change from liquid state to gaseous state. So, the temperature at point D, 90°C is its boiling point.

3) The point A is where the substance is at solid state.

4) The substance is at liquid state at the point C.

5) The substance is at gaseous state at the point E.

6) At point B, solid state is changing to liquid state.

7) At point D, liquid state is changing to gaseous state.

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Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer:

A.Amorphous solid

Explanation:

There are two states used to describe solids in science; these are crystalline and amorphous (non-crystalline) solids.

Crystalline solids are solids whose constituent particles are properly arranged in a 3-dimensional structure in a crystal-like manner. They have a definite melting point and a defined shape and pattern. A common example of a crystalline solid is diamond.

Amorphous or non-crystalline solids are the opposite of the crystalline solids as there constituent particles are disorderly arranged. They do not have a defined melting point as they melt over a range of temperature.

From the above, it can be deduced that candle wax exhibits the properties of amorphous solids.  give me brainliest please

Explanation:

released By the organisms as carbon dioxide

hope it is helpful

mark me as brilliant

Carbon cycles through the Earth system. During photosynthesis, carbon is  converted by organisms from a gas to carbohydrates. Hence, option (C) is correct.

The exchange of carbon compounds between the earth's biosphere, geosphere, pedosphere, hydrosphere, and atmosphere is known as the carbon cycle.

The following are the key steps in the carbon cycle process:

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Answer:

Explanation:

CANT SEE ITS TOO PIXELATED

There are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

The current in the circuit is determined by applying Ohms law as shown below;

V = IR

where;

I = V/R

At a constant resistance of the circuit, the current in a circuit will increase when the emf of the circuit increases.

Thus, we can conclude that, there are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

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