Henry is saving up to buy a new jacket. He already has $95 and can save an additional $5 per week using money from his after school job. How much total money would Henry have after 10 weeks of saving? Also, write an expression that represents the amount of money Henry would have saved in w weeks

Answer:

y ≤ -1/5x +1

Step-by-step explanation:

The line had an incline of -1/5 and the intersect with the y-axis is 1, so the line is given by

y = -1/5x +1

The indicated area in graph is below the line, so now you have enough to get the right inequality:

y ≤ -1/5x +1

v

Step-by-step explanation:

jejejejeeirii5ueuruururueurururr

Thus, the integral of xe^yds on the circle from (2,0) to (5,4) is equal to 207/8 e^4 - 23/8.

To solve this problem, we will use the line integral formula:
∫(P dx + Q dy) = ∫(P(x,y) dx + Q(x,y) dy)

where P and Q are the x and y components of the vector field F(x,y) = (xe^y, 0).

First, we need to parameterize the given circle. We can do this by using the parametric equations:

x = 2 + 3t
y = 4t

where 0 ≤ t ≤ 1.

Next, we can compute the differential ds:

ds = √(dx^2 + dy^2) = √(9 + 16) dt = 5 dt

Now, we can substitute the parametric equations and ds into the line integral formula:

∫(P dx + Q dy) = ∫(xe^y dx) = ∫(xe^y dx/dt dt) = ∫((2+3t)e^(4t) 3 dt)

Evaluating the integral gives:

∫(xe^yds) = ∫((2+3t)e^(4t) 3 dt) = 207/8 e^4 - 23/8

Therefore, the integral of xe^yds on the circle from (2,0) to (5,4) is equal to 207/8 e^4 - 23/8.

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Answer:

y = 5x - 6

Step-by-step explanation:

We are given a line, which is parallel to the line y=5x+3.

We also know that this line passes through the point (3,9).

We want to find the equation of this line.
Parallel lines have the same slopes, yet different y intercepts.
So, let's find the slope of the line y=5x+3.

The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y intercept.

As 5 is in the place of where the slope (m) is, 5 is the slope of the line.

It is also the slope of the line parallel to it (which is the line we are trying to find).

We can write the equation of this new line in slope-intercept form as well, which is also the format your system wants.

Before we write the equation of the line in slope-intercept form, we can write it in point-slope form, then convert it into slope-intercept form.

Point-slope form is \(y-y_1=m(x-x_1)\), where m is the slope and \((x_1, y_1)\) is a point.

As we have already found the slope (5), we can immediately plug it into the formula.

\(y-y_1=5(x-x_1)\)

Now, remember that we were also given a point, that passes through the line. This point is (3,9).

We can use its values in the formula.

Substitute 3 as \(x_1\) and 9 as \(y_1\).

y - 9 = 5(x-3)

Now, we have written the line in point-slope form.

However, we're not done yet; remember that we want it in slope-intercept form.

We can solve the equation for y to get slope-intercept form.

So, on the right, open up the parentheses and distribute 5 to both x and -3.

y - 9 = 5x - 15

Now add 9 to both sides.

y = 5x - 6

Answer:

138.23cm^2

Step-by-step explanation:

I took an assessment with the same question

I used a calculator for this, and got the answer of C. 138.2cm^2

Answer:

I feel you bro

Step-by-step explanation:

In this case, the frequency of Maggie spending 9 hours in the office is 2, and the total frequency is the sum of all the frequencies, which is 3 + 1 + 4 + 2 = 10.

Therefore, the experimental probability is 2/10, which simplifies to 1/5.

To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.

Looking at the histograms described:

The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.

The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.

The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.

The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.

Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.

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Answer:

1/4

Step-by-step explanation:

The slope of a graph is always the rate of change for every value of x, in this case, days. Since she is adding 1/4 of a mile to her run each day, this means that the slope of this linear relationship is 1/4.

She increases a full mile in 4 days, just a little note.

The vectors [-5 4 5], [2 -1 5], and [-17 16 45] are linearly dependent with scalars (1, 3, 1) as an example of a non-zero solution.

To determine if the vectors [-5 4 5], [2 -1 5], and [-17 16 45] are linearly independent, we need to find the scalars a, b, and c that satisfy the equation:

a * [-5 4 5] + b * [2 -1 5] + c * [-17 16 45] = [0 0 0]

If the only solution is a = b = c = 0, the vectors are linearly independent. If there are other solutions where a, b, and c are not all zero, the vectors are linearly dependent.

Let's form a matrix with these vectors as columns:

|-5  2 -17|
| 4 -1  16|
| 5  5  45|

Now, we can row reduce this matrix to its reduced row echelon form (RREF):

| 1 -2  5|
| 0  1 -3|
| 0  0  0|

From the RREF, we can write the system of linear equations:

x - 2y + 5z = 0
y - 3z = 0

Solving this system, we get:

y = 3z
x = 2y - 5z = 6z - 5z = z

Since z can be any scalar, we have infinitely many solutions where not all of a, b, and c are zero. For example, when z = 1, we get x = 1 and y = 3. So, the scalars (1, 3, 1) make the equation true.

Thus, the vectors [-5 4 5], [2 -1 5], and [-17 16 45] are linearly dependent with scalars (1, 3, 1) as an example of a non-zero solution.

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Answer:

Here’s the answer! Best of luck.

Step-by-step explanation:

Answer:

85

Step-by-step explanation:

5×9=45

8×5=40

add it

85

Answer:

Step-by-step explanation:

To find the value of x, solve the equation. Do this by rearranging the equation to make x the subject.

Answer:

x=32761 /4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4x+7=32768

Step 2: Subtract 7 from both sides.

4x+7−7=32768−7

4x=32761

Step 3: Divide both sides by 4.

Answer:

non

Step-by-step explanation:

Answer:

probably 2.5/d

Step-by-step explanation:

my mathematical teacher

The correct answer is option O: 5 V.

To determine the average voltage (Vavg) given a peak-to-peak voltage (Vpp) of 10 V, we need to consider the relationship between Vavg and Vpp in an alternating current (AC) waveform.

The average voltage of an AC waveform is related to its peak-to-peak voltage by the formula: Vavg = 0.5 * Vpp.

Applying this formula to the given Vpp of 10 V, we can calculate the Vavg as follows: Vavg = 0.5 * 10 V = 5 V.

The average voltage is equal to half of the peak-to-peak voltage, resulting in an average voltage of 5 V for a Vpp of 10 V.

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Answer:

Corresponding angels:

a,f

h,b

e,d

c,g

y = 80  Vertical angles are congruent

x = 50 Sum of the interior angles of a triangle is 180

180 - 80 -50 = 50

Step-by-step explanation:

y = 0.1029x + 99.7514

The estimated regression model for predicting annual maintenance expense (y) for a given number of hours of weekly usage (x) is y = 0.1029x + 99.7514. To calculate this regression equation, you can use the least-squares method to minimize the sum of the squared errors between the predicted values and the actual values. The regression equation can be used to calculate the estimated maintenance expense (in hundreds of dollars) for any given number of hours of weekly usage.

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Answer:

Logan's solution and reasoning for solving an equation are shown below:

Given

Step 1: x-10-50 Reason 1: Given

Step 2

x-10+10=50+10 Reason 2 Addition Property of Equality

Step 3

60

Reason 3 Simplity

Step 4:

<= 60

Reason 4: Division Property of Equality

Step 5.

x = 40

Reason 5: Simplity

Choose which reason is incorrect.

O Reason 2

O Reason 3

O Reason 4

Step-by-step explanation:

Answer: Y= -9 + 3x/2

Step-by-step explanation: Down below Have a brilliant day-Lily ^_^

Step-by-step explanation:

Let's solve your inequality step-by-step.

2

w

+3>

29

w

3w+2

w

>

29

w

Let's find the critical points of the inequality.

3w+2

w

=

29

w

3w+2=29(Multiply both sides by w)

3w2+2w=29w(Multiply both sides by w)

3w2+2w−29w=29w−29w(Subtract 29w from both sides)3w2−27w=0

3w(w−9)=0(Factor left side of equation)

3w=0 or w−9=0(Set factors equal to 0)

w=0 or w=9

Check possible critical points.

w=0(Doesn't work in original equation)

w=9(Works in original equation)Answer:

w<0 or w>9

Answer:

Step-by-step explanation:

by using formula (a+b)^2=a^2+2ab+b^2

in these two we have to just open the formula

(3x+2y)^2

=(3x)^2+2(3x)(2y)+(2y)^2

=9x^2+12xy+4y^2

(3y+2x)^2

=(3y)^2+2(3y)(2x)+(2x)^2

=9y^2+12xy+4x^2

The probability that I'll get a telemarketing call during the next two hours is 0.5e^(-2) ≈ 0.0677, or about 6.77%.

Let X be the time until the next telemarketer call. Then X has an exponential distribution with parameter λ. Let A be the event that I get a telemarketing call in the next hour, and B be the event that I get a telemarketing call in the next two hours. We want to find P(B | A).

We know that P(A) = 0.5, so λ = -ln(0.5) = ln(2). Then the probability density function of X is f(x) = λe^(-λx) = 2e^(-2x) for x > 0.

Using the definition of conditional probability, we have:

P(B | A) = P(A ∩ B) / P(A)

We can compute P(A ∩ B) as follows:

P(A ∩ B) = P(B | A) * P(A)

P(B | A) is the probability that I get a telemarketing call in the second hour, given that I already got a call in the first hour. This is the same as the probability that X > 1, given that X > 0. Using the memoryless property of the exponential distribution, we have:

P(X > 1 | X > 0) = P(X > 1)

So P(B | A) = P(X > 1) = ∫1∞ 2e^(-2x) dx = e^(-2).

Therefore, we have:

P(B | A) = P(A ∩ B) / P(A)

e^(-2) = P(A ∩ B) / 0.5

Solving for P(A ∩ B), we get:

P(A ∩ B) = e^(-2) * 0.5 = 0.5e^(-2)

So the probability that I'll get a telemarketing call during the next two hours is 0.5e^(-2) ≈ 0.0677, or about 6.77%.

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Answer:

238

Step-by-step explanation:

First, you have to figure out the area for each of the boxes, and then you add all of the areas together

Answer:

D) 269.3

Step-by-step explanation:

Rectangular prism volume:

V = whl

V = (12.1)(5.3)(4.2)

V = 269.346

Answer:

B) 24

Step-by-step explanation:

The area of the rectangle is 48 units (8 x 6).

The base of the is 6 units and the height is 8 units. The formula for the are of a triangle is A = \(\frac{1}{2}\)bh.

b = base

h = height

A = \(\frac{1}{2}\)(6)(8)

A = 24

Answer:

\(24\)

Step-by-step explanation:

If the area of a rectangle is bh, and the area of a triangle is bh/2, then a triangle's area is half a rectangle's area. Hence, if the area of the rectangle is 48, the area of the triangle is half of 48, or 24.

Answer:

Part A: one solution:

Part B: x = 3, y = 4.

1) Part A: how many solutions does the pair of equations for lines A and B have?

The solution of a system of equations in a graph is given by the intersetion of the curves that represent the equations.

In this case, there are two straight lines, which intersect in one and only one point.

Hence, the system has one solution.

2) Part B: what is the solution to the equations of lines A and B?

The solution is the pair of coordinates of the intersection point. It is (3, 4).

Therefore, the solution is x = 3, y = 4.

Step-by-step explanation:

MRK ME BRAINLIEST PPLLZZZZZZZZZZZZZZZZZZZ

The inverse of the matrix is A⁻¹ = 1/(ab) [0 1/b] assuming that a and b are both non-zero.

A matrix is a rectangular array of numbers, symbols, or expressions arranged in rows and columns. Matrices are used in mathematics, science, engineering, computer graphics, and many other fields to represent and manipulate sets of numbers or other data. A matrix is usually denoted by a capital letter, such as A, and its entries or elements are denoted by lowercase letters with subscripts, such as aij, where i denotes the row number and j denotes the column number.

Here,

To find the inverse of the matrix [a 0; 0 b], where a and b are non-zero, we can use the formula for the inverse of a 2x2 matrix:

               [d  -b]

1/det(A) * [-c a]

where A is the matrix we want to invert, det(A) is the determinant of A, and a, b, c, and d are the elements of A.

[a 0]

A = [0 b]

det(A) = (a * b) - (0 * 0)

= ab

So the inverse of A is:

[d  -b]

A⁻¹= 1/det(A)[-c a]

where d = 1/a and a = 1/b:

          [1/a  0]

A⁻¹ = 1/(ab) [0 1/b]

Thus, the inverse of the matrix [a 0; 0 b] is:

         [1/a  0]

A⁻¹ = 1/(ab) [0 1/b]

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To provide Logical Proofs with line-by-line justifications for the following arguments,

Let's use the first 4 rules of inference.

Given below is the justification for each step of the proof with the applicable rule of Inference.

E > M1. A > (E > ~F) Premise2. H v (~F > M) Premise3. A Premise4. ~H  Premise5. A > E > ~F 1, Hypothetical syllogism6.

E > ~F 5,3 Modus Ponens 7 .

~F > M 2,3 Disjunctive Syllogism 8.

E > M 6,7 Hypothetical SyllogismIf

A is true, then E must be true because A > E > ~F.

Also, if ~H is true, then ~F must be true because H v (~F > M). And if ~F is true,

Then M must be true because ~F > M. Therefore, E > M is a valid  based on the given premises using the first four rules of inference.

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The inverse of a function in vertex form can be determined by substituting the function in the standard form of a quadratic function

The various steps to find the inverse of a function in vertex form can be noted as -

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