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To completely simplify the expression tan(x) - tan(x) 1-sec(x) 1 + sec(x),

one has to use the fundamental identities in algebra and follow several techniques such as common denominator.

The fundamental identities are as follows:

Sin θ = 1/csc θCos θ = 1/sec θTan θ = sin θ/cos θCot θ = cos θ/sin θSec θ = 1/cos θcsc θ = 1/sin θ

The expression to be simplified is as shown below.

tan(x) - tan(x) 1-sec(x) 1 + sec(x)

Using the identity tan(x) = sin(x) / cos(x),

the expression becomes;

sin(x) / cos(x) - sin(x) / cos(x) (1 - 1 / cos(x)) / (1 + 1 / cos(x))

Simplify the expression in the brackets in order to have a common denominator;

cos(x) / cos(x) - 1 / cos(x) / (cos(x) + 1)

Simplify further using the common denominator;

cos(x) - 1 / cos(x) (cos(x) - 1) / (cos(x) + 1)

Thus, the completely simplified expression is

(cos(x) - 1) / (cos(x) + 1).

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The following are the zeros for the function h (x) = x2 + 3x - 8: - x= -4 and x=2.

Given a collection of inputs X (domain) and a set of potential outputs Y (codomain), a function is more technically defined as a set of ordered pairings (x,y) where xX and yY with the caveat that there can only be one ordered pair with the same value of x. The function notation f:XY can be used to express that f is a function from X to Y.

The function's zero is a value of x that makes it equal to zero. In other words, the equation f(x) = 0 leads to a zero.

By putting h(x) equal to zero and figuring out x, we may determine the zeroes for the function h(x) = x2 + 3x - 8.

h(x) = x² + 3x - 8 = 0

We may factor the left side of the equation to find x:

x² + 3x - 8 = (x-2)(x+4) = 0

We set each factor to zero and solve for x to discover the zeroes:

x-2 = 0 or x+4 = 0

x = 2 or x = -4

Consequently, the function's zeros are x = 2 and x = -4.

So, A is the right response. x = -4 and x = 2

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The complete question is

What are the zeros of the function h (x) = x² + 3x - 8?

A. x = -4 and x = -2

B. x= -8 and x = 2

C. x = -2 and x = 8

D. x = 2 and x = 8

Answer:

1760 yards

1 mile = 1760 yards. The symbol is "mi".

Step-by-step explanation:

As given, the amount of copper is 0.9009. You have used 95% of the copper, then the amount of copper used is 0.9009 * 0.95 = 0.855855.

To find the cross-sectional area of the wire, we will use the formula for resistance
\(R = ρ(L/A)\),

To calculate the cross-sectional area of the wire, we can re-arrange the above formula,\(A = ρL / R = (1.72 * 10^-8 m) (1 m) / (0.673 Ω) = 2.56 * 10^-8 m²\)

To find the diameter of the wire, we will use the formula for the area of a circle,
\(A = πr²\), where r is the radius of the wire. Substituting the value of A in the above formula, we get
\(,πr² = 2.56 * 10^-8 m²T\)
r = \(√(2.56 * 10^-8 m² / π) = 8.063 * 10^-5 m\)

The diameter of the wire is
\(,D = 2r = 2 * 8.063 * 10^-5 m = 1.61 * 10^-4 m\)

The diameter of the wire is \(1.61 * 10^-4\) m.

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Answer:

1 cm

Step-by-step explanation: WOOOO  brainiest pls

Answer:

0.07 - 2.69 = x = -2.62

Step-by-step explanation:

x - -2.69 can be rewritten as x + 2.69

So, x + 2.69 = 0.07

Now subtract 2.69 from both sides to isolate x:

0.07 - 2.69 = x, so x = -2.62

Hey ! there

Answer:

Step-by-step explanation:

In this question we are given that the product of two integers is -160 and one of them is 8 . And we are asked to find the other integer .

For finding the other integer we are assuming ,

And now we can find other Integer by making equation and solving it .

SOLUTION : -

Equation is :

\( \quad \dashrightarrow \qquad \: 8 \times x = - 160\)

or ,

\( \quad \dashrightarrow \qquad \: 8x = - 160\)

To isolate the variable x , We are dividing both sides by 8 :

\( \quad \dashrightarrow \qquad \: \dfrac{ \cancel{8}x}{ \cancel{8}} = \cancel{ \dfrac{ - 160}{8} }\)

On simplifying it , We get :

\( \quad \dashrightarrow \qquad \: \red{\underline{\boxed{\frak{x = - 20}}}} \quad \bigstar\)

Verifying : -

Now we are verifying whether our answer is wrong or right by substituting value of x in the equation . So ,

Substituting value of x :

Multiplying 8 with - 20 :

Therefore , of answer is correct .

Answer:

\( \: \)

Step-by-step explanation:

\( \: \)

Given,

\( \: \)

To Find,

\( \: \)

Solution,

\( \: \)

So, The equation will be :

\( \\ \longrightarrow \qquad{ \ {{ { \sf{x \times 8= - 160}}}}} \\ \: \: \)

\( \longrightarrow \qquad{ \ {{ { \sf{8x= - 160}}}}} \\ \: \: \)

Now, Let us divide both sides by 8 :

\( \\ \longrightarrow \qquad{ \ {{ { \sf{ \frac{8x}{8} = \frac{ - 160}{8} }}}}} \\ \: \: \)

\( \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{x= - 20}}}}} \: \: \bigstar \: \\ \)

Therefore,

Answer:

Explanation:

Here, we want to plot the graph of z1 plus z2

Firstly,let us identify the coordinates of z1 and z2

We can get this from the graph provided

z1 is (8,-4)

z2 is (-2,-3)

The sum of these two will be : (6,-7)

To plot this, we draw dotted vertical line at the point x = 6 and dotted horizontal line at the point y = -7

Wherever these two dotted lines meet is the point z

Answer:

x = 2.6

Step-by-step explanation:

2.5(x + 5) = 7.5x - 0.5

1 can only be divided by one other integer except1, hence it is not a prime number.

Any natural number higher than 1 that is not the sum of two smaller natural numbers is referred to be a prime number. A composite number is a natural number greater than one that is not prime.

Given this definition, 1 is not a prime number because it can only be divided by one other integer, which is 1 itself.

Based on the explanation above, we can then conclude that 1 is not a prime number.

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Answer:

Step-by-step explanation:

Hope this helps u!!

The parabola appears wider when |a| >1, the parabola appears thinner

When a is positive, the parabola opens upwards, but when a is negative parabola opens downwards

Step-by-step explanation:

brainliest?

We can simplify the numerical expression to get:

(2/5)*(14 - 27) + (2⁵/16) = -16/5

Here we have the expression:

(2/5)*(14 - 27) + (2⁵/16)

Let's simplify the term in the right first, we know that:

2⁵ = 2*2*2*2*2 = 4*4*2 = 16*2 = 32

Replacing that we get:

(2⁵/16) = 32/16 = 2

Then we get:

(2/5)*(14 - 27) + (2⁵/16) = (2/5)*(14 - 27) + 2

Now we can simplify the term in the left:

(2/5)*(14 - 27) = (2/5)*(-13) = -26/5

Replacing that we get:

(2/5)*(14 - 27) + 2 = -26/5 + 2 = -26/5 + 10/5 = -16/5

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The polynomial 250x³ - 42x² + 112x is a trinomial of degree 3.

A polynomial is a mathematical equation that solely uses the operations addition, subtraction, multiplication, and non-negative integer exponentiation of variables. Variables are sometimes known as indeterminate in mathematics. Majorly used polynomials are binomial and trinomial.

The given polynomial is 250x³ - 42x² + 112x.

To classify this polynomial by the number of terms, we count the number of terms it has, which is three. Therefore, we can classify it as a "trinomial".

To identify the degree of this polynomial, we look at the highest power of x in the polynomial. In this case, the highest power of x is 3, which is the coefficient of the x³ term. Therefore, the degree of this polynomial is 3.

So, the polynomial 250x³ - 42x² + 112x is a trinomial of degree 3.

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x, x+1, x+2, x+3

5(x+3)-2(x+1) = 20

5x + 15 -2x -2 = 20

3x + 13 = 20

x = 11

answer : 11, 12, 13, 14

Answer:

dc/a-b-d

Step-by-step explanation:

ax – bx = d

x + c

Multiply both sides by x + c

ax – bx

(x + c) = d(x + c)

x + c

Simplify

ax – bx

(x+c): ax – bx

x + c

ax – bx = d(x+c)

Expand d(x+c): dx + cd

ax — bx = dx + cd

Subtract dx from both sides

ax – bx – dx = dx + cd – dx

Simplify

ax – bx – dx = cd

Factor ax – bx – dx: x(a – b – d)

x(a - b- d) = cd

Divide both sides by a – b – d; a + b + d

x(a – b - d) cd

a + b + d

a - b - d

a – b-d

Simplify

X =dc/a-b-d

The value of 'x' in the algebraic equation is  \(\rm x= \frac{dc}{a-b-d} \\\)  where \(\rm a\neq b+d\)

It is given that the algebraic equation  \(\rm \frac{ax-bx}{x+c}= d\)

It is required to solve the algebraic (polynomial) equation if \(\rm a\neq b+d\)

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have an algebraic equation:

\(\rm \frac{ax-bx}{x+c}= d\)

\(\rm \frac{ax-bx}{x+c}= d\\\\\rm ax-bx=d(x+c)\\\rm ax-bx=dx+dc\\\rm ax-bx-dx=dc\\\rm (a-b-d)x=dc\\\\\rm x= \frac{dc}{a-b-d} \\\)

Thus, the value of 'x' in the algebraic equation is  \(\rm x= \frac{dc}{a-b-d} \\\) where \(\rm a\neq b+d\)

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b. r(t) = (cos(t), sin(t)), for 0 <= t <= pi. c. Sphere of radius 1 centered at the origin: r(u, v) = (cos(u) * sin(v), sin(u) * sin(v), cos(v)), for 0 <= u <= 2pi and 0 <= v <= pi.

b) Here are the parameterizations for a line segment connecting two points of your choice and half of a circle centered at the origin:

Line segment from (0, 0) to (1, 2): r(t) = (1 - t) * (0, 0) + t * (1, 2) = (t, 2t), for 0 <= t <= 1.

Half of a circle of radius 1 centered at the origin: r(t) = (cos(t), sin(t)), for 0 <= t <= pi.

c) Here are the parameterizations for a plane and a sphere:

Plane passing through (1, 0, 0), (0, 1, 0), and (0, 0, 1): r(u, v) = u * (1, 0, 0) + v * (0, 1, 0) + (1 - u - v) * (0, 0, 1), for 0 <= u <= 1 and 0 <= v <= 1.

Sphere of radius 1 centered at the origin: r(u, v) = (cos(u) * sin(v), sin(u) * sin(v), cos(v)), for 0 <= u <= 2pi and 0 <= v <= pi.

Note that for the plane parameterization, we used the fact that a plane passing through three non-collinear points can be parameterized by a linear combination of the points, with the coefficients summing to 1. For the sphere parameterization, we used spherical coordinates to express the position of each point on the sphere in terms of two angles, u and v.

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Answer:

11x - 3y

Step-by-step explanation:

6x + 5x + 2y - 5y

11x - 3y

Hope this helps

Answer:

\(m = \frac{14 - 7}{2 - 0} = \frac{7}{2} \)

\(14 = \frac{7}{2} (2) + b\)

\(14 = 7 + b\)

\(b = 7\)

\(y = \frac{7}{2} x + 7\)

Answer:

Let us begin by simplifying the expression (-18x^3 + 17 +6) / (3x + 2):

- Combine the constants (17+6) to get 23.

- We now have (-18x^3 + 23) / (3x+2).

- Factor out -3 from the numerator to get -3(6x^3 -23)/ (3x+2).

- We can now cancel out the (3x+2) in both the numerator and denominator to get:

-3(6x^2 - 4x + 3)

Therefore, the answer is (C) -6x^2 + 4x - 3.

Answer:

x=4.4

Step-by-step explanation:

9x+2 = 4x+ 24

5x+2 = 24

5x = 22

5x/5 = 22/5

x=4.4

i got one solution scream at me if im wrong

Answer:

answer

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

The equivalent expression is (5x^2 - 7x + 18)/[(x - 4)(x + 6)].

To simplify the given expression, we need to combine the terms with a common denominator. The given expression is:

(x + 3)/(x - 4) + (4x)/(x + 6)

To combine these fractions, we need to find the common denominator, which is (x - 4)(x + 6). We can rewrite the expression using the common denominator:

[(x + 3)(x + 6)]/[(x - 4)(x + 6)] + [(4x)(x - 4)]/[(x - 4)(x + 6)]

Now we can add the fractions:

[(x^2 + 9x + 18) + (4x^2 - 16x)]/[(x - 4)(x + 6)]

Combining like terms in the numerator:

(5x^2 - 7x + 18)/[(x - 4)(x + 6)]

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Answer:

-3√5

Step-by-step explanation:

3√5-2√45

3√5-2•√9×√5

3√5-2•3√5

3√5-6√5

-3√5

Answer:

c. \( - 3 \sqrt{5} \)

Step-by-step explanation:

\(3 \sqrt{5} - 2 \sqrt{45} \)

\( - 2 \times 3 \sqrt{5} = - 6 \sqrt{5} \)

\(3 \sqrt{5} - 6 \sqrt{5} \)

\((3 - 6) \sqrt{5} = - 3 \sqrt{5} \)

\( \boxed{\green{= - 3 \sqrt{5} }}\)

The average value of the function  \(\( f(x)=3\cos x \) on \( \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \)\),      is \(\[\text{Average value }=\frac{6}{\pi} \]\)

To find the average value of the function \(\( f(x)=3\cos x \) on \( \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \),\)

We use the following formula:

\(\[\text{Average value }=\frac{1}{b-a}\int_{a}^{b}f(x)dx\]\)

where a is the lower limit of the interval, b is the upper limit of the interval, and f(x) is the given function.

Thus,\(\[\text{Average value }=\frac{1}{\frac{\pi}{2}-(-\frac{\pi}{2})}\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}3\cos x dx\]\)

Using integration by substitution, we can evaluate the integral as follows:

\(\[\int\cos x dx = \sin x + C\]\)where C is the constant of integration.

Thus,\(\[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}3\cos x dx\)

=\(3\sin x \bigg|_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\)

= \(3(\sin \frac{\pi}{2} - \sin -\frac{\pi}{2})\)

=\(6\]\)

Substituting this back into the formula, we get\(\[\text{Average value }=\frac{1}{\frac{\pi}{2}-(-\frac{\pi}{2})}\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}3\cos x dx = \frac{6}{\pi}\]\)

Therefore, the average value of the function \(\( f(x)=3\cos x \) on \( \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \) is \( \frac{6}{\pi} \).\) The required answer is:

\(\[\text{Average value }=\frac{6}{\pi} \]\)

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Answer:

9.6

Step-by-step explanation:

Answer:

the answer is 9.6

Step-by-step explanation:

your welcome