Please may you enlarge the image, I can't read it.
PLEASE HELP FAST!!! IT IS URGENT!!!
Answer:
Step-by-step explanation:
No 10% of condition are not met :)
Quinn deposit $3000 into a savings account her freshman year of college. She will earn simple interest on the account at 2.56%. If she makes no contributions or withdrawals, what will the accrued value of the account be when she graduates four years later 
\(~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3000\\ r=rate\to 2.56\%\to \frac{2.56}{100}\dotfill &0.0256\\ t=years\dotfill &4 \end{cases} \\\\\\ A = 3000[1+(0.0256)(4)] \implies A=3000(1.1024)\implies A = 3307.2\)
1. Quinn's test scores are 95, 90, and 83. What must she score on the next test to have an average
score of 90 on the four tests?
Answer:
92
Step-by-step explanation:
Add 95, 90, and 83 all together
add 92 to that total
divide by 4
Determine the turning points and distinguish between them when necessary y=x³ - 3x - 9x + 4
The turning points of the function y = x³ - 3x² - 9x + 4 are (3, -23) and (-1, 9).
To determine the turning points of the given function y = x³ - 3x² - 9x + 4, we need to find the critical points where the derivative of the function is equal to zero.
1. Find the derivative of the function:
y' = 3x² - 6x - 9
2. Set the derivative equal to zero and solve for x:
3x² - 6x - 9 = 0
3. Factorize the quadratic equation:
3(x² - 2x - 3) = 0
4. Solve the quadratic equation by factoring or using the quadratic formula:
(x - 3)(x + 1) = 0
This gives us two possible values for x: x = 3 and x = -1.
5. Substitute these critical points back into the original function to find the corresponding y-values:
For x = 3:
y = (3)³ - 3(3)² - 9(3) + 4
= 27 - 27 - 27 + 4
= -23
For x = -1:
y = (-1)³ - 3(-1)² - 9(-1) + 4
= -1 - 3 + 9 + 4
= 9
6. Therefore, the turning points are (3, -23) and (-1, 9).
Note: It appears that there was a typo in the original equation, where the term "-9x" should have been "-3x²". The above solution assumes the corrected equation.
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Young Sally went Trick or Treating last Halloween, In her treat bag were 15 pieces of gum, 7 lollipops, 8 tootsie rolls, 6 candy bars, and an apple.
a) Candy bars are her favorite. What percent of her treats are candy bars?
b) She really does not like gum or apples, What percent of the treats things she does not like?
Answer:
A: 16.2% (if you need it rounded, it is 16%)
B: 43.2% (if you need it rounded it is 43%)
Step-by-step explanation:
We need to find the candy bar percentage rate so we divide the amount of candy bars, by the total about of treats collected.
15 + 7 + 8 + 6 + 1 = 37
Now we divide the cady bars by the total amount:
6/37 = 16.2%
Now we do the same thing again but this time with the apples and gum:
16/37 = 43.2%
You did it!
Have a great day!!
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Find the measure of the indicated angle.
99⁰
96⁰
98⁰
92°
L
120°
K
N
M
64
Answer:
? = 92°
Step-by-step explanation:
the chord- chord angle ? is half the sum of the measures of the arcs intercepted by the angle and its vertical angle, that is
? = \(\frac{1}{2}\) (LM + AK) = \(\frac{1}{2}\) (120 + 64)° = \(\frac{1}{2}\) × 184° = 92°
Every quadratic function has one or more x-intercepts.
True or False
Answer:
False
Explanation:
Quadratic functions can sometimes even have only one or NO x-intercepts.
So the answer is false.
Hope this is correct, have a great day!
What degree is required to factor a quadratic?
Ex: x^2+3x+6
The degree required to factor a quadratic equation is 2, i.e degree 2.
An equation is said to be quadratic if and only if its degree is not greater than 2, and not lesser than two. So that any equation with degree 2 is a quadratic equation.
A degree of an expression is the highest power of the variable in it. For example, 5x + 2 is to one degree, 3x^2 + 2x - 1 is to degree 2, 10x^4 + 3x^3 - x^2 + 4x - 6 is to degree 4 etc.
The methods required in solving a given quadratic equation are either by factorization, completing the square, graph, or by algebraic formula.
Therefore in the given question, the degree required is 2, i.e degree 2.
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It is suspected that calcium in blood platelets may be related to blood pressure. As part of a study of this relationship, researchers recruited 30 subjects whose blood pressure was normal (i.e., not abnormally elevated). For each subject two measurements were made: pressure (average of systolic and diastolic measurements) and calcium concentration in the blood platelets. The sample size is n = 30, and the sample correlation is r = 0.4. Is there evidence that blood pressure and platelet calcium are linearly related? State the hypothesis and test it at 5% level of significance. What is your conclusion?
Answer:
Step-by-step explanation:
The null and the alternative hypothesis are:
\(\mathbf{ H_o: \rho = 0} \\ \\ \mathbf{H_1: \rho \ne 0}\)
The test statistics is as follows:
\(t = \dfrac{r\sqrt{n-2} }{\sqrt{1-r^2}}\)
\(t = \dfrac{0.4 \sqrt{30-2} }{\sqrt{1-0.4^2}}\)
\(t = \dfrac{0.4 \sqrt{28} }{\sqrt{0.84}}\)
t = 2.3094
The critical value
\(t_{\alpha/df} = t_\ \{0.05/2 \ , \ 30-2 \} } \\ \\ = t_{0.025,28} = \pm 2.048 ( from \ the \ t-tables)\)
Decision rule:
To reject \(H_o\) if t > \(t_{\alpha/df}\).
So since t > \(t_{\alpha/df}\). we reject \(H_o\) at ∝ = 0.05
Conclusion: There is sufficient evidence to conclude that blood pressure and patient calcium are linearly related.
Find the volume of the solid of revolution formed by revolving the region bounded by
y = (1/2)x cosh x
x = 1
x = 2
y = 0
about the y-axis
The volume of the solid of revolution is approximately 2.470 cubic unit.
What is formula of volume ?To find the volume of the solid of revolution, we need to use the formula:
V = π∫[a,b] \(y^2\) dx
where y is the distance between the function that is being rotated and the axis of revolution, which in this case is the y-axis.
To begin, we must determine the y-equation for the curve that defines the boundary of the region.
y = (1/2)x cosh x
Solving for x in terms of y, we get:
x = \(cosh^{-1}\)(2y/y)
We only need to find the volume for the region where y is not negative and then multiply the result by 2 because the curve is symmetric with respect to the y-axis.
The limits of integration for x are x = 1 and x = 2, which correspond to y-values of y = (1/2) cosh(1) and y = (1/2) cosh(2), respectively.
So, we can write the integral for the volume as:
V = 2π∫[\(0,(1/2)cosh(2)] [(cosh^{-1}(2y/y))^2] dy\)
We can simplify this by using the identity \(cosh^{-1}(x) = ln(x + \sqrt{x^2 - 1}),\) which gives:
V = 2π∫[\(0,(1/2)cosh(2)] [(ln(2y/y +\sqrt{((2y/y)^2 - 1)))^2}] dy\)
This integral can be evaluated using integration by parts or numerical methods. Using numerical methods, we get:
V ≈ 2.470 cubic units (rounded to three decimal places)
Therefore, the volume of the solid of revolution is approximately 2.470 cubic unit.
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At store A, 3 pounds of apples cost $12. At store B, the cost is given by y = 2 x where y is the cost in dollars and x is the number of pounds of apples. The cost of apples at store C is shown in the graph.
Answer the questions to find out which store's apples are the least expensive.
1. What is the unit price of apples at store A? Explain how you found this unit price.
2. What is the unit price of apples at store B? How did you use the equation to fi nd the unit price?
3. What is the unit price of apples at store C? How did you use the graph to fi nd the unit price?
4. Which store has the lowest unit price for apples?
Answer:
The unit price is the cost per unit of an item or the cost/price for each item.
1) 4$ per pound. By simplifying the proportion (constant ratio) between the cost, and the pounds of apples. 3 pounds of apples cost 12$ → 3/3 pounds of apples cost 12/3$ → 4 dollars for every pound.
2) 2$ per pound. By evaluating the rate of change (change in the y over x or dependent variable over independent) in the equation: y = 2x. y is the cost in dollars, and x is the pounds of apples. So there are 2 pounds (weight) of apples for every dollar.
3) 3$ per pound. Given a graph with a y scaled by 3, and an x scaled by 1 with a graph y = x or 1 unit up for every unit right. This must be equivalent to y = 3x. Where y is labeled as the cost in dollars, and x as the weight in pounds. So there are 3 dollars for every pound of apples.
4) Store B. Because 2 is less than 3 which is less than 4.
Hope it helps, stay safe and tell me if me wrong! :D
Given Triangle DEF is isosceles and angle D is the vertex angle, Find x, DE, DF, EF
Answer:
x=2;DE,EF=9,DF=5
Step-by-step explanation:
Since DEF is isoceles, you can set the equations
x+7 and 2x+5 equal to each other
x+7=2x+5, now solve for x
-x=-2,
x=2, now plug in for each side
DE,EF=9
DF=3(2)-1=5
Angle ADB and CD are straight lines. angle ADC = 5 x angle CDB Work out the size of angle ADC.
Answer:
Step-by-step explanation:
Please answer this HELLLPPPP!!!!!
Answer:
x = 10
Step-by-step explanation:
Diagonals of a rhombus bisect each other at a 90° angle, but most importantly (for this problem), they bisect the opposite angles of the rhombus equally.
This means that the two angles, given by the expressions (6x + 12) and (8x - 8), are equal to each other.
Set them equal to each other in an equation and solve for x.
6x + 12 = 8x - 8Subtract 6x from both sides.
12 = 2x - 8Add 8 to both sides.
20 = 2xDivide both sides by 2.
x = 10The value of 10 for x will make the given parallelogram a rhombus.
Assumptions: Tax depreciation is straight-line over three years. Pre-tax salvage value is 25 in Year 3 and 50 if the asset is scrapped in Year 2. Tax on salvage value is 40% of the difference between salvage value and book value of the investment. The cost of capital is 20%.
Based on the given assumptions and calculations, the net present value (NPV) of the investment in the new piece of equipment is -$27,045.76, indicating that the investment is not favorable.
To calculate the after-tax cash flows for each year and evaluate the investment decision, let's use the following information:
Assumptions:
Tax depreciation is straight-line over five years.
Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4.
Tax on salvage value is 30% of the difference between salvage value and book value of the investment.
The cost of capital is 12%.
Given:
Initial investment cost = $50,000
Useful life of the equipment = 5 years
To calculate the depreciation expense each year, we divide the initial investment by the useful life:
Depreciation expense per year = Initial investment / Useful life
Depreciation expense per year = $50,000 / 5 = $10,000
Now, let's calculate the book value at the end of each year:
Year 1:
Book value = Initial investment - Depreciation expense per year
Book value \(= $50,000 - $10,000 = $40,000\)
Year 2:
Book value = Initial investment - (2 \(\times\) Depreciation expense per year)
Book value \(= $50,000 - (2 \times$10,000) = $30,000\)
Year 3:
Book value = Initial investment - (3 \(\times\) Depreciation expense per year)
Book value = $50,000 - (3 \(\times\) $10,000) = $20,000
Year 4:
Book value = Initial investment - (4 \(\times\) Depreciation expense per year)
Book value \(= $50,000 - (4 \times $10,000) = $10,000\)
Year 5:
Book value = Initial investment - (5 \(\times\) Depreciation expense per year)
Book value \(= $50,000 - (5 \times $10,000) = $0\)
Based on the assumptions, the salvage value is $10,000 in Year 5.
If the asset is scrapped in Year 4, the salvage value is $15,000.
To calculate the tax on salvage value, we need to find the difference between the salvage value and the book value and then multiply it by the tax rate:
Tax on salvage value = Tax rate \(\times\) (Salvage value - Book value)
For Year 5:
Tax on salvage value\(= 0.30 \times ($10,000 - $0) = $3,000\)
For Year 4 (if scrapped):
Tax on salvage value\(= 0.30 \times ($15,000 - $10,000) = $1,500\)
Now, let's calculate the after-tax cash flows for each year:
Year 1:
After-tax cash flow = Depreciation expense per year - Tax on salvage value
After-tax cash flow = $10,000 - $0 = $10,000
Year 2:
After-tax cash flow = Salvage value - Tax on salvage value
After-tax cash flow = $0 - $0 = $0
Year 3:
After-tax cash flow = Salvage value - Tax on salvage value
After-tax cash flow = $0 - $0 = $0
Year 4 (if scrapped):
After-tax cash flow = Salvage value - Tax on salvage value
After-tax cash flow = $15,000 - $1,500 = $13,500
Year 5:
After-tax cash flow = Salvage value - Tax on salvage value
After-tax cash flow = $10,000 - $3,000 = $7,000
Now, let's calculate the net present value (NPV) using the cost of capital of 12%.
We will discount each year's after-tax cash flow to its present value using the formula:
\(PV = CF / (1 + r)^t\)
Where:
PV = Present value
CF = Cash flow
r = Discount rate (cost of capital)
t = Time period (year)
NPV = PV Year 1 + PV Year 2 + PV Year 3 + PV Year 4 + PV Year 5 - Initial investment
Let's calculate the NPV:
PV Year 1 \(= $10,000 / (1 + 0.12)^1 = $8,928.57\)
PV Year 2 \(= $0 / (1 + 0.12)^2 = $0\)
PV Year 3 \(= $0 / (1 + 0.12)^3 = $0\)
PV Year 4 \(= $13,500 / (1 + 0.12)^4 = $9,551.28\)
PV Year 5 \(= $7,000 / (1 + 0.12)^5 = $4,474.39\)
NPV = $8,928.57 + $0 + $0 + $9,551.28 + $4,474.39 - $50,000
NPV = $22,954.24 - $50,000
NPV = -$27,045.76
The NPV is negative, which means that based on the given assumptions and cost of capital, the investment in the new piece of equipment would result in a net loss.
Therefore, the investment may not be favorable.
Please note that the calculations above are based on the given assumptions, and additional factors or considerations specific to the business should also be taken into account when making investment decisions.
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The complete question may be like :
Assumptions: Tax depreciation is straight-line over five years. Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4. Tax on salvage value is 30% of the difference between salvage value and book value of the investment. The cost of capital is 12%.
You are evaluating an investment in a new piece of equipment for your business. The initial investment cost is $50,000. The equipment is expected to have a useful life of five years.
Using the given assumptions, calculate the after-tax cash flows for each year and evaluate the investment decision by calculating the net present value (NPV) using the cost of capital of 12%.
Which series tests can be used to show that a series converges absolutely? (Select all that apply) Alternating Series Test Ratio Test Limit Comparison Test Test for Divergence Root Test
The following are the series test to show series are absolute convergence ,Ratio Test ,Limit Comparison Test, Root Test.
The following series tests can be used to show that a series converges absolutely,
Ratio Test
Root Test
Limit Comparison Test
The Alternating Series Test cannot be used to show absolute convergence, as it only applies to alternating series.
The Test for Divergence is used to show that a series diverges, but not whether it converges absolutely.
The Alternating Series Test and Test for Divergence do not test for absolute convergence, but rather conditional convergence.
They cannot be used to show that a series converges absolutely.
Therefore, series used to show absolute convergence are given by
Ratio Test
Limit Comparison Test
Root Test
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If a race averages 125 miles per hour for 4 hours, how far does the car travel? Use the number line to help you find the answer.
If the speed is 125 miles per hour and the amount of time is 4 hours, in order to find the distance traveled, we just need to multiply the speed and the time:
\(\begin{gathered} \text{distance}=\text{speed}\cdot\text{time} \\ \text{distance}=125\cdot4 \\ \text{distance}=500\text{ miles} \end{gathered}\)Using the number line, we have:
b) A man sold two books at $375 each. On the first book, he gains 25%and
the other, he loses 25%. How much does he gain or lose in the whole
transaction? Also, find the gain or loss percent in the whole transaction
Find the numbers with the following property three times the sum of four and a number is less than seven times the same number
Let's represent the number with the variable "x". According to the given property, we can write the following equation:
3(x + 4) < 7x
Now, let's solve this inequality to find the range of numbers that satisfy the property.
3x + 12 < 7x
Subtract 3x from both sides:
12 < 4x
Divide both sides by 4 (since the coefficient of x is 4):
3 < x
So, the range of numbers that satisfy the given property is x > 3.
Therefore, any number greater than 3 will satisfy the condition. For example, 4, 5, 6, 7, 8, etc.Step-by-step explanation:
If the basic measuring unit in base-7 is 49 circles, what does the measuring unit of size .001seven look like
The measuring unit is the standard unit of a quantity
The measuring unit of size 0.001 is represented by one millionth circle
How to determine the unit of base 0.001The basic measuring unit in base 7 is given as:
49 circles
The above can be represented as:
Base 7 = 49 circles
Represent the base with n.
So, we have the following rule
\(Circle = n^2\)
For measuring unit 0.001, we have:
\(Circle = 0.001^2\)
Evaluate the square
\(Circle = 0.000001\)
This means that,
The measuring unit of size 0.001 is represented by one millionth circle
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I need so much help please somebody help me
Answer:
$448
Step-by-step explanation:
You need to find 2% of 400.00, so you would do this: 0.02 · 400 = 8
That means $8 is 2% of 400, so all you need to do is multiply 8 by 6 to get 48. Add that number to the original $400, and you get $448.
Hope this answers your question!
HELLO CAN SOMEONE PLEASE ANSWER THIS I WILL MARK YOU THE BRAINLIEST !!!
Answer:
88
Step-by-step explanation:
180 = (56+36)+x
180 - 92 = x
x = 88
Answer: 88
Step-by-step explanation:
56 + 36 + ? = 180
? + 92 = 180
180 - 92 = 88
If, 56 + 36 + 88 = 180
Then ? = 88
Determine whether the following represents a linear relationship or a nonlinear relationship.
Answer:
the answer to this is
A) nonlinear
Step-by-step explanation:
this is not linear because the line is not a line that goes in 1 direction. It has points of an increase and decrease so it is non linear
Answer:
it is not linear
Step-by-step explanation:
It is not a linear line because it is not going straight
335.71 divided by 1000
Solve using substitution.
y = –6
–8x − 7y = –6
Okay so you put -6 in where y is then solve and youll get your answer
-8x-7(-6)=-6
A jar of peanut butter contains 50 tablespoons of peanut butter.
How many sandwiches can you make from the jar of peanut butter, assuming you have plenty of bread and jelly?
A. 25 sandwiches
B. 9 sandwiches
C. 10 sandwiches
D. 50 sandwiches
Answer:
the correct answer is A. 25 sandwiches.
Step-by-step explanation:
Assuming you have plenty of bread and jelly, you can make 25 sandwiches from the jar of peanut butter.
Each sandwich typically requires 2 tablespoons of peanut butter, one slice of bread with peanut butter and one slice of bread with jelly.
So, if you have 50 tablespoons of peanut butter, you can make 25 sandwiches with it, because 50 / 2 = 25.
Therefore, the correct answer is A. 25 sandwiches.
Answer: 25
Step-by-step explanation:
We have 50 tablespoons of peanut butter and we know that it requires 2 tablespoons to make a single sandwich. In order to find how many sandwiches we can make with our 50 tablespoons, we would have to do 50 divided by 2.
2+2...=50
Sketch a graph of f(x)={- 5 if x < -2 2x-1 if-2 < x≤ 2 0 if x>2. (piecewise)
A graph of the given piecewise-defined function is shown in the image below.
What is a piecewise-defined function?In Mathematics and Geometry, a piecewise-defined function simply refers to a type of function that is defined by two (2) or more mathematical expressions over a specific domain.
Generally speaking, the domain of any piecewise-defined function simply refers to the union of all of its sub-domains. By critically observing the graph of this piecewise-defined function, we can reasonably infer and logically deduce that it is constant over several intervals or domains such as x > 2 and x < -2.
In conclusion, this piecewise-defined function has a removable discontinuity.
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just need the answer.
in degrees thanks;)
1. QR = 36 ; PR = 45 ; PQ = 21, Sin _?. = 21 / 45
2. QR = 16 ; PR = 2 ; PQ = 8, tan _?_ = 8/16
3. QR = 15; PR = 28 ; PQ = 15, Cos _?_= 15 / 28
4. OR = 47 ; PR = 64 ; PQ = 38, tan_?_= 38 / 47
5. OR = 4 ; PR = 17; PQ = 12, Sin _?_1 = 12 / 17
6. OR = 36 ; PR = 59 ; PO = 20, Cos __?_= 36 / 59
7. OR = 82 ; PR = 63 ; PQ = 29, tan __?_= 29 / 82
8. QR = 10 ; PR = 28 ; PQ = 8, Sin _ ? 11 = 8 / 28
9. QR = 51 ; PR = 42 ; PQ = 9, tan _?__ = 9 / 51
10. OR = 16 ; PR = 20 ; PQ = 17, Cos __?_|| = 16 / 20
11. QR = 12 ; PR = 84 ; PQ = 60, Sin? = 60 / 84
12. OR = 19 ; PR = 32 ; PQ = 45, Cos _ ? = 19 / 32
13. QR = 76 ; PR = 27 ; PQ = 64, tan __?_= 64 / 76
14. OR = 26; PR = 48 ; PQ = 37, Cos __?_= 37 / 48
15. OR = 19 ; PR = 66 ; PO = 23, Cos_?_= 23 / 66
need help with this one please
The ratio of the number of boys to the number of
girls in choir is 6 to 5. There are 70 girls in the choir.
How many boys are in the choir?
Answer:
48 boys
Step-by-step explanation: