helpppppp pl.ssssssssssss IIIINEeeDDD THISS DONE TODAY!!!!!!

Lets call the above set of points \(L\).

The domain is between minimum and maximum of the x-coords points specified,

\(\mathrm{min}(L;x)=0\)

\(\mathrm{max}(L;x)=7\)

So domain is \(D_L=[\mathrm{min}(L;x),\mathrm{max}(L;x)]=[0,7]\).

The range is the same story but you look at y values,

\(\mathrm{min}(L;y)=-8\)

\(\mathrm{max}(L;y)=8\)

So range is \(R_L=[\mathrm{min}(L;y),\mathrm{max}(L;y)]=[-8,8]\).

Hope this helps :)

Answer:

160 meters

Step-by-step explanation:

Before I begin, note that distance = rate * time (or d = r * t)

To solve this problem, we need to find what point these two people have the same distance. (so Janiyah covers the same distance as Connor)

So, let's set the time that Janiyah takes as x (in seconds). So, he covers

d = r * t, or 8x meters

Then, Connor's equation would be

d = r * t

d = 5x + 60 (because he got a 60 meter headstart)

Because d is the same in both equations, to solve for the amount of time they run:

8x = 5x + 60

Subtract 5x from both sides.

3x = 60

x = 20

Then, to find Janiyah's distance (you can also use Connors because the two distances are equal), put x = 20 into 8x

8x = 8 * 20 = 160

So, Janiyah ran 160 meters.

Just in case, let's check if this is correct. Connor's distance equals Janiyah's, so

5x + 60 = 160

5 * 20 + 60 = 160

100 + 60 = 160

160 = 160

True.

So, the answers are correct.

I hope this helps! Feel free to ask any questions!

Answer: 160 meters

Step-by-step explanation:

Answer: 5541 pages

Step-by-step explanation:

2489+3052= 5541 pgs

Answer:

$6.96 more was the book than the lunch

Step-by-step explanation:

do cost of the book subtract the cost of the lunch forget the decimals and just subtract like normally. then at the end bring down the decimals, hope this helps

Using substitution, the determination of equivalent expressions are is as follows:

Equivalent:

-6x+7-2x-3 and 4(-2x + 1)

10x-4(x-6)-3 and 11+ 2(x + 5) + 4x

Not Equivalent:

-3(x+1)-12 and -3(x-15).

Equivalent expressions are algebraic expressions that have the same value when the same value is used to substitute the variable.

To determine whether two expressions are equivalent, we can use 1 or 0:

1) -6x+7-2x-3 and 4(-2x + 1)

When x = 0

-6(0)+7-2(0)-3 = 7-3 = 4

When x = 0, 4(-2x + 1) becomes:

4(-2(0) + 1) = 4(1)  = 4

Thus, -6x+7-2x-3  and 4(-2x + 1) are equivalent expressions.

2) -3(x+1)-12 and -3(x-15)

When x = 0, -3(x+1)-12 becomes:

-3(0+1)-12 = -3-12 = -15

When x = 0, -3(x-15) becomes:

-3(0-15) = -3(-15)  = 45

Since -3(x+1)-12 and -3(x-15) give different results when x = 0, they are not equivalent expressions.

3) 10x-4(x-6)-3 and 11+ 2(x + 5) + 4x

When x = 0, 10x-4(x-6)-3 becomes:

10(0)-4(0-6)-3 = 24-3 = 21

When x = 0, 11+ 2(x + 5) + 4x becomes:

11+ 2(0 + 5) + 4(0) = 11+10  = 21

Since  10x-4(x-6)-3 and 11+ 2(x + 5) + 4x give the same result when x = 0, they are equivalent expressions.

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Answer:

=

−

8

Step-by-step explanation:

The statements that are true are B and D.

Given are some statements we need to check which is true.

Let's analyze each statement:

A. 4 is a perfect cube.

False. 4 is not a perfect cube because there is no integer that can be cubed to give 4.

B. 16 is a perfect square.

True. 16 is a perfect square because it can be expressed as 4^2, where 4 is an integer.

C. 2,197 is both a perfect square and a perfect cube.

False. 2,197 is not a perfect square because there is no integer that can be squared to give 2,197.

However, it is a perfect cube because 13³ equals 2,197.

D. 8 is a perfect cube.

True. 8 is a perfect cube because it can be expressed as 2³, where 2 is an integer.

E. 18 is neither a perfect square nor a perfect cube.

True. 18 is neither a perfect square nor a perfect cube because there is no integer that can be squared or cubed to give 18.

Therefore, the statements that are true are B and D.

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Answer:

if each box equal with 1/2 cm, so

length × width × height

= 5/2 × 1 × 3/2

= 15/4 cm³

= 3 3/4 cm³

Hope it helps!

Answer:

51

Step-by-step explanation:

(-3)^4-5(5)+6(5)÷(-3)(2)

81-25+30÷-6

81-25-5

81-30

51

(Remember order of operations-PEMDAS)

suppose they are independent of a geometric random variable with parameter p. Let M = max(x1,....,xN) (a) Find P{M<} by conditioning on N is  nλe^(-nλx)

Given fx (x) = λe^λx

Fx (x) = 1 – e^-λx      x…0

To find distribution of Min (X1,….Xn)

By applying the equation

fx1 (x) = [n! / (n – j)! (j – 1)!][F(x)]^j-1[1-F(x)]^n-j f(x)

For minimum j = 1

[Min (X1,…Xn)] = [n!/(n-1)!0!][F(x)]^0[1-(1-e^-λx)]^n-1λe^-λx

= ne^[(n-1) λx] λe^(λx)

= nλe^(-λx[1+n-1])

= nλe^(-nλx)

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Using the graph, it is found that the correct option is:

In this problem:

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The interval of the graph at which Susan is running fastest is from point A ( 0 , 0 ) to B ( 10 , 3 )

Given data ,

Susan is running a 5k race. The graph of distance vs. time is shown

So , the slope of the first line is m₁

And , the slope of the second line is m₂

where the points are A ( 0 , 0 ) , B ( 10 , 3 ) , C ( 20 , 4 )

Now , slope of AB is

m₁ = ( 3/10 ) = 0.3

And , m₁ = 0.3 kilometers per minute

And , slope of BC is

m₂ = ( 4 - 3 ) / ( 20 - 10 )

m₂ = 1/10

m₂ = 0.1 kilometers per minute

Therefore , the interval is fastest at second line from B ( 10 , 3 ) , C ( 20 , 4 )

Hence , Susan is running fastest is from point A ( 0 , 0 ) to B ( 10 , 3 )

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No, Savannah is incorrect. Doubling the length, width, and height of a right rectangular prism will not double its surface area.

Surface area is the total area of an object's exposed faces, including any external surface area. It is a measure of the size of a surface and is usually expressed in square units such as square meters or square centimeters. Surface area is a two-dimensional measurement, since it only takes into account the area of a surface, and not its thickness or volume.

The surface area of a right rectangular prism is calculated by multiplying the length by the width and then multiplying that number by two and adding the two products together.

For example, the surface area of a right rectangular prism with a length of 15 cm, a width of 10 cm, and a height of 5 cm is calculated as follows:

Surface area = (15 cm * 10 cm) + (15 cm * 5 cm) = 150 cm2 + 75 cm2 = 225 cm2

Doubling the length, width, and height of this right rectangular prism would give us a prism with a length of 30 cm, a width of 20 cm, and a height of 10 cm. The surface area of this new prism would be calculated as follows:

Surface area = (30 cm * 20 cm) + (30 cm * 10 cm) = 600 cm2 + 300 cm2 = 900 cm2

As you can see, doubling the length, width, and height of the right rectangular prism does not double its surface area - the surface area has increased by four times (900 cm2/225 cm2 = 4).

In conclusion, doubling the length, width, and height of a right rectangular prism does not double its surface area; rather, it increases the surface area by a factor of four.

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No, Savannah is incorrect. Doubling the length, width, and height of a right rectangular prism will not double its surface area.

Surface area is the total area of an object's exposed faces, including any external surface area. It is a measure of the size of a surface and is usually expressed in square units such as square meters or square centimeters. Surface area is a two-dimensional measurement, since it only takes into account the area of a surface, and not its thickness or volume.

The surface area of a right rectangular prism is calculated by multiplying the length by the width and then multiplying that number by two and adding the two products together.

For example, the surface area of a right rectangular prism with a length of 15 cm, a width of 10 cm, and a height of 5 cm is calculated as follows:

Surface area = (15 cm * 10 cm) + (15 cm * 5 cm) = 150 cm2 + 75 cm2 = 225 cm2

Doubling the length, width, and height of this right rectangular prism would give us a prism with a length of 30 cm, a width of 20 cm, and a height of 10 cm. The surface area of this new prism would be calculated as follows:

Surface area = (30 cm * 20 cm) + (30 cm * 10 cm) = 600 cm2 + 300 cm2 = 900 cm2

As you can see, doubling the length, width, and height of the right rectangular prism does not double its surface area - the surface area has increased by four times (900 cm2/225 cm2 = 4).

In conclusion, doubling the length, width, and height of a right rectangular prism does not double its surface area; rather, it increases the surface area by a factor of four.

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Answer:

The company charged $500 for its services,and Mia gives the movers a 16% tip. Now, we can add the tip amount to the cost of the service to find the total amount Mia paid: Total amount = Cost of service + Tip amount = $500 + $80 = $580

Step-by-step explanation:

Answer:

commutative property

Step-by-step explanation:

an example is 3.4 = 4.3

Answer:

Commutative property. :)

Answer:

x = 11

Step-by-step explanation:

The two angles measuring (7x + 14)° and (9x - 8)° are corresponding angles, which are always congruent to each other and thus equal to each other.  

Step 1:  Thus, we can find the value of x by setting the two angles equal to each other:

7x + 14 = 9x - 8

7x + 22 = 9x

22 = 2x

11 = x

Optional Step 2:  We can check that we've found the correct answer by plugging in 11 for x in both (7x + 14) and (9x - 8) and checking that we get the same number:

7(11) + 14 = 9(11) - 8

77 + 14 = 99 - 8

91 = 91

Answer:

The answer is C

Step-by-step explanation:

I say this because you have to simplify and  plug in the numbers to get answer choice c

An investment of $6,400 to increase to $14,000 if it is invested at 5% per year compounded continuously is ≈15.6

Define compound interest?

Given that :

P = $ 6,400

Q = $ 14,000

r = 5%

Let P be the initial investment

r be the rate of interest

t be the time

Q be the increase amount

Q = P \(e^{rt} }\)

14,000 = 6,400 (\(e^{0.05t}\))

\(e^{0.05t}\) = \(\frac{14000}{6400}\)

\(e^{0.05t}\)  = 2.187

Taking log on both sides , we get

0.05t = ln (2.187)

0.05t = 0.78

       t = \(\frac{0.78}{0.05}\)

       t ≈ 15.6

An investment of $6,400 to increase to $14,000 if it is invested at 5% per year compounded continuously is ≈ 15.6

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Answer:

4

Step-by-step explanation:

{sec(θ) - tan(θ) = 1/4, sec(θ) + tan(θ)} = tan(θ) + sec(θ) = 4

use subsitution

Answer:

c

Step-by-step explanation:

assume base 10

-logy = x

\( \frac{1}{ log(y) } = x\)

log base x y = 5 turns into the format x^ 5 = y

implement that to get c

i)

Factor using completing square method

\(\dashrightarrow \sf y = -x^2+16x-64\)

\(\dashrightarrow \sf y = -(x^2-16x+64)\)

\(\dashrightarrow \sf y = -(x^2-8x-8x+64)\)

\(\dashrightarrow \sf y = -(x(x-8)-8(x-8))\)

\(\dashrightarrow \sf y = -((x-8)(x-8))\)

ii)

Find zeros of a function, f(x) = 0

\(\dashrightarrow \sf -((x-8)(x-8))=0\)

\(\dashrightarrow \sf (x-8)=0, \ (x-8)=0\)

\(\dashrightarrow \sf x = 8\)

iii)

In order to find vertex use the formulae : x =  -b/2a

\(\dashrightarrow \sf x = \dfrac{-(16)}{2(-1)}\)

\(\dashrightarrow \sf x = 8\)

Then find y:

\(\dashrightarrow \sf y = -(8)^2+16(8)-64\)

\(\dashrightarrow \sf y = 0\)

coordinates: (8, 0)

iv) Sketched Below:

#1

#2

Zeros are the x intercepts

Here they are

#3

Vertex form of parabola:-y=a(x-h)²+k

#4

Attached

Answer:

2000

Step-by-step explanation:

3x450=1350

1350+650=2000

=2000

Answer:

BODMAS

3 x 450 = 1350

1350 + 650 = 2000

Answer:

she would have to run 3 mines south then 6 miles east meaning she is 9 mines away from the start.

Step-by-step explanation:

6.71 miles is the distance runner has to jogfrom her starting point if she plans to run straight back

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given,

If a runner jogs 6 miles west

Let the path will be AB =6miles

Then jogs 3 miles north,

BC=3 miles

We need to find  how far is the runner from her starting point if she plans to run straight back

Which means we need to find AC

Pythagoras' theorem is a fundamental relation in Euclidean geometry between the three sides of a right triangle.

AC²=AB²+BC²

AC²=6²+3²

AC²=36+9

AC²=45

Take square root on both sides

AC=√45

AC=6.71

Hence, 6.71 miles is the distance runner has to run from her starting point if she plans to run straight back

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Answer:

I am here........

nice to meet you

Answer:

\(23y(2 + 4) = 23y(6) = 138y\)

The distance between Bloemfontein and Upington is a distance of 582 kilometers. The distance between two cities may vary depending on the route taken, traffic, and other factors. The distance between these two cities is measured in a straight line, which may not be the actual road distance.

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Answer: To find the distance of a chord from the center of a circle, we need to use the following formula:

Distance from center = sqrt(r^2 - (c/2)^2)

Where r is the radius of the circle and c is the length of the chord.

In this case, the radius of the circle is 3.7cm and the length of the chord is 7cm.

So, substituting these values in the formula, we get:

Distance from center = sqrt(3.7^2 - (7/2)^2)

= sqrt(13.69 - 12.25)

= sqrt(1.44)

= 1.2 cm

Therefore, the distance of the chord from the center of the circle is 1.2 cm.

Step-by-step explanation:

Answer:

26.31 units

Step-by-step explanation:

Given: Points \((-10,12),(-6,-14)\)

To find: Distance between the given points

Solution:

Let \((x_1,y_1)=(-10,12)\,,\,(x_2,y_2)=(-6,-14)\)

The distance formula is used to find the distance between two points \((x_1,y_1),(x_2,y_2)\)

According to distance formula,

Distance = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

\(\sqrt{(-6+10)^2+(-14-12)^2}\\ =\sqrt{16+676}\\ =\sqrt{692}\\ =26.31\)

So, distance between the given points is 26.31 units