Answer:
It would take her 10 track practices to get up to 40 miles.
Step-by-step explanation:
find the particular solution of the differential equation that satisfies the initial condition.
f''x=5/x2, f'(1)=3, x>0
The given differential equation is `f''x = 5/x^2`.We need to find the particular solution of the differential equation that satisfies the initial condition `f'(1)=3`.
The given differential equation can be written as `f''x = d/dx(dx/dt) = d/dt(5/x^2) = -10/x^3`.Thus, `f''x = -10/x^3`.Let us integrate the above equation to get `f'(x) = 10/x^2 + C1`.Here `C1` is the constant of integration.Let us again integrate the above equation to get `f(x) = -5/x + C1x + C2`.Here `C2` is the constant of integration.As `f'(1)=3`, we have `C1 = 5 - 3 = 2`.Thus, `f(x) = -5/x + 2x + C2`.Now, we need to use the initial condition to find the value of `C2`.As `f'(1)=3`, we have `f'(x) = 5/x^2 + 2` and `f'(1) = 5 + 2 = 7`.Thus, `C2` is given by `C2 = f(1) + 5 - 2 = f(1) + 3`.Therefore, the particular solution of the differential equation that satisfies the initial condition is given by `f(x) = -5/x + 2x + f(1) + 3`.Given differential equation `f''x = 5/x^2`We need to find the particular solution of the differential equation that satisfies the initial condition `f'(1) = 3` by solving the differential equation using integration.So, we have `f''x = d/dx(dx/dt) = d/dt(5/x^2) = -10/x^3`.Thus, `f''x = -10/x^3`.Integrating the above equation, we get `f'(x) = 10/x^2 + C1`, where `C1` is the constant of integration.Integrating the above equation again, we get `f(x) = -5/x + C1x + C2`, where `C2` is the constant of integration.Using the initial condition `f'(1) = 3`, we get `C1 = 5 - 3 = 2`.Substituting `C1` in the above equation, we get `f(x) = -5/x + 2x + C2`.Now, we need to use the initial condition to find the value of `C2`.So, `f'(x) = 5/x^2 + 2` and `f'(1) = 5 + 2 = 7`.Thus, `C2` is given by `C2 = f(1) + 5 - 2 = f(1) + 3`.Therefore, the particular solution of the differential equation that satisfies the initial condition is given by `f(x) = -5/x + 2x + f(1) + 3`.The particular solution of the given differential equation `f''x = 5/x^2` that satisfies the initial condition `f'(1) = 3` is `f(x) = -5/x + 2x + f(1) + 3`.
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explain what the symbols and sd represent.
The symbols d and sd represent:
The differences in the mean of the paired data entries in the dependent samples.
What is the standard deviation?
A measure of a set of values' variance or dispersion is called the standard deviation.
Here,
d: the difference between paired data in the dependent samples.
sd: standard deviation.
The dependent samples' dependent samples' standard deviation for the variance between the means of the paired data items.
Hence, the differences in the mean of the paired data entries in the dependent samples.
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Please help!
I genuinely don't know how to do this, a step-by-step would do great. Thank you.
Answer:
x = 10
Step-by-step explanation:
Because the triangles are similar, the following equations must be solved in order to find out how much bigger or smaller the triangle is.
10 * y = 15
16 * y = 24
You'll find that
y = 1.5
Then, you are able to insert y into the following equation and solve for x
(x - 4) * y = 9
(x - 4) * 1.5 = 9
1.5x - 6 = 9
1.5x = 15
x = 10
We can plug x back into the previous equation in order to check if it is correct
(x - 4) * 1.5 = 9
(10 - 4) * 1.5 = 9
6 * 1.5 = 9
9 = 9
The decimal -2.97 is the solution to which subtraction problem?
-6.1 - 3.13
-6.1 - (-31.3)
-0.61 - (-3.13)
-6.1 - (-3.13
Answer:-6.1-(-3.13
Step-by-step explanation:
After you change the two negatives in the middle to a positive, the equation would simplify to -6.1+3.13.
5/8−(14)2 what would be the correct answer for this problem
-27.375
Hope this helps.
Paul is running Tennis shop. He sells balls and rackets. Rackets (R) cost $1.20 each and Balls (B) cost $2:0 each. At the end of a month, Paul made a total of $70 and sold a total of 90 Rackets and Balls combined. Which system of equations represents this situation?
A. 2R + 1.20B = 90, B - R = 160.
B. 1.20R + 2B = 90, R - B = 90
C. 1.20R + 2B = 70, and R + B = 90
D. 1.20B + 2R = 90 and 2B + R = 70
The system of equations that represent the situation are 1.20R + 2B = 70, and R + B = 90.
What are the system of equations?
The system of equations are sets of equations that have to be solved simultaneously in order to determine their required values. They are often referred to as simultaneous equations.
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Kayla rented a limousine for prom. There was a one-time charge of $100, plus
an hourly rate of $45. Her total cost for the night was $347.50. How many
hours did Kayla rent the limo? please helppp
Answer:
5.5 hours
Step-by-step explanation:
347.50 - 100 = 247.50
247.50 ÷ 45 = 5.5
Answer:
5.5 hours
Step-by-step explanation:
if the one-time charge was 100 then subtract 100 from 347.50 and you would get 247.50 then divide that by 45 and you get 5.5.
Three charges (-25 nC, 79.1nC, and −55.9nC) are placed at three of the four corners of a square with sides of length 22.2 cm. What must be the value of the electric potential (in V) at the empty comer if the positive charge is placed in the opposite comer?
Given that three charges (-25 nC, 79.1nC, and −55.9nC) are placed at three of the four corners of a square with sides of length 22.2 cm. We need to determine the value of the electric potential (in V) at the empty comer if the positive charge is placed in the opposite corner.
The formula for the electric potential at a point in space is given by;V = k [ (q1 / r1) + (q2 / r2) + (q3 / r3) + ….. ]where;k = Coulomb's constant (8.99 × 10^9 Nm²/C²)q1, q2, q3,…. are the charges at the cornersr1, r2, r3,…. are the distances from the corner to the point whose potential is being calculated Now we can calculate the electric potential at the empty corner as follows;The three charges can be represented as shown below:Charges at corners of a square
The distance from any corner to the opposite corner (where the positive charge is placed) is given by d = √[ (22.2 cm)² + (22.2 cm)² ] = 31.4 cmTherefore, the electric potential at the empty corner is given by;V = k [ (q1 / r1) + (q2 / r2) + (q3 / r3) ]Here, q1 = -25 nC, q2 = -55.9 nC, q3 = 79.1 nC, r1 = r2 = r3 = d = 31.4 cm = 0.314 mPlugging in the values we get;V = 8.99 × 10^9 [ (-25 × 10^-9 / 0.314) + (-55.9 × 10^-9 / 0.314) + (79.1 × 10^-9 / 0.314) ]= 8.99 × 10^9 [ -0.0795 - 0.1783 + 0.252 ]= 8.99 × 10^9 × 0.0052= 46.8 VTherefore, the value of the electric potential at the empty comer if the positive charge is placed in the opposite comer is 46.8 V.
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.............................
...................... ......
Answer:
a = 20
b = 10
Or if in coordinate format, (20,10)
Step-by-step explanation:
\(\left \{ {{4a-3b=50} \atop {5a-2b=80}} \right.\)
Solve the system using elimination:
In elimination, you want to eliminate a term. I want to eliminate b, so what I would do is to get it the same coefficient (LCM)
\(\left \{ {4a - 3b=50} \atop {5a-2b=80}} \right.\)\(\left \{ {{8a-6b=100} \atop {15a-6b=240}} \right.\) <= Multiply the equations by 3 to find LCM\(-7a = -140\\\) Remember, if the terms you want to eliminate have the same sign in front of them ( - or +), subtract the top equation from the bottom. If they are different signs, add the two equations. \(a=20\)Now, plug in 20 for an into any of the original equations
4a - 3b = 504(20) - 3b = 5080 - 3b = 50-3b = -30b = 10The solution of the system is written as a coordinate, in alphabetical order. Since the variables are a and b, you write it as (a,b).
The solution is \(\boxed{(20,10)}\)
-Chetan K
Anthony writes a numerical expression 2+10x3-2 and says that the expression has a value of 34. Is Anthony correct? Explain your answer.
Answer:
he is incorrect
Step-by-step explanation:
He is incorrect because 10 times 3 is 30, plus-minus 2 which is 30. So instead of 34, it is 30. or you can say Anthony is wrong. Following the order of operations, you would do the 10*3 first. Then, you would take the 30, and finish the equation from left to right. So you would add 2 to make it 32 and then subtract 2 to make it 30 again. So your final answer is 30, not 34. So Anthony is wrong.
find an equation of the tangent line to the graph of the function at the given point. y = arcsec 18x, 2 18 , 4
The equation of the tangent line to the graph of y = arcsec(18x) at the point (2, 18) is y = (√3 / 6)x + (18 - √3 / 3).
How to find tangent line equation?To find the equation of the tangent line to the graph of the function y = arcsec(18x) at the point (2, 18), we need to determine the slope of the tangent line at that point.
The derivative of the arcsec(x) function is given by:
d/dx [arcsec(x)] = 1 / (|x| * sqrt(x^2 - 1))
Using this derivative, we can find the slope of the tangent line at x = 2:
m = 1 / (|2| * sqrt(2^2 - 1))
= 1 / (2 * sqrt(3))
= 1 / (2 * √3)
= √3 / 6
Now that we have the slope (m) and the point (2, 18), we can use the point-slope form of a linear equation to find the equation of the tangent line:
y - y₁ = m(x - x₁)
where (x₁, y₁) is the given point (2, 18) and m is the slope (√3 / 6).
Plugging in the values:
y - 18 = (√3 / 6)(x - 2)
Simplifying further:
y - 18 = (√3 / 6)x - (√3 / 6)(2)
y - 18 = (√3 / 6)x - √3 / 3
Finally, rearranging the equation to the standard form:
y = (√3 / 6)x + (18 - √3 / 3)
So, the equation of the tangent line to the graph of y = arcsec(18x) at the point (2, 18) is y = (√3 / 6)x + (18 - √3 / 3).
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how many inches are in a feet
Answer:
1 foot = 12 inches
Step-by-step explanation:
Your car holds 50 litres
of gas. If the price is 116.8 ($1.168) how much
money will you spend on gas?
l will spend $58.40 on gas.
What is Multiplication?
Multiplication is an arithmetic operation that involves combining two or more numbers to produce a third number called the product. The symbol for multiplication is "×" or "*".
For example, if you have 3 apples and want to know how many apples you would have if you tripled the amount, you can multiply 3 by 3 to get the answer: 3 × 3 = 9. So, if you tripled the amount of apples you had, you would have 9 apples in total.
Multiplication can be thought of as repeated addition. For instance, 3 × 4 is the same as 3 + 3 + 3 + 3, which equals 12. In this example, 3 is added to itself four times.
Here given, a car holds 50 litres of gas and the price is 116.8 ($1.168) per litre.
We want to calculate the total cost of the gas.
We can find it by multiplying the number of litres by the price per litre
Total cost = \(50 \times 1.168\)
Total cost = $58.40
Therefore, l will spend $58.40 on gas.
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Correct question is "Your car holds 50 litres
of gas. If the price is 116.8 ($1.168) per litre then how much money will you spend on gas?"
Is this statement true or false? You calculate a finance charge by subtracting the cost of the purchase from the total payment,
Answer:
True
Step-by-step explanation:
Brainliest?
Answer:
I Believe the answer is True
Step-by-step explanation:
Find the sale price of the item. Round to two decimal places if necessary.
Original price: $80.00
Markdown: 32%
Answer:
sale price is $54.40
Step-by-step explanation:
original Price - discount = sale Price
80 - 80(0.32) = $54.40
Answer: $54.40
Step-by-step explanation:
100 - 32 / 100 = 0.6880 * 0.68 = 54.40Write the equation in standard form. 4y−5x=3(4x−2y+1)
Answer:
-17x+10y=3
Step-by-step explanation:
Standard form is:
Ax+By=C
Let's start by simplifying the equation:
4y-5x=3(4x-2y+1)
Distribute the 3:
4y-5x=3(4x)+3(-2y)+3(1)
4y-5x=12x-6y+3
Subtract 12x from both sides
4y-17x=-6y+3
Add 6y to both sides
10y-17x=3
-17x+10y=3
Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)
Component 3 must be started on day 197 to meet the delivery date of day 200.
To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.
(a) Backward schedule:
Operation | Work Center | Time (hours) | Start Day
--------------------------------------------------------
Final Assembly | Work Center 1 | 1 | 200
Sub-assembly 1 | Work Center 2 | 2 | 199
Component 4 | Work Center 3 | 3 | 197
Component 2 | Work Center 4 | 4 | 196
Component 3 | Work Center 5 | 3 | ????
(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.
From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.
Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.
Hence, component 3 must be started on day 197 to meet the delivery date of day 200.
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Calculate the value of x
\(2x + 2x + 1 = 13 + x\)
4
2x +2x +1 =13 + x
4x - x = 13 - 1
3x = 12
x=12/3
x=4
Checking, 2*4+2*4+1 =17
13+4=17
Answer:
Step-by-step explanation:
2x + 2x + 1 = 13 + x
To find the value of x, isolate 'x'
Step1: Subtract x from both sides
2x + 2x - x + 1 = 13
Step 2: Subtract 1 from both sides
2x + 2x - x = 13 - 1
Step3: Combine like terms
3x = 12
Step 3: Divide both sides by 3
x = 12/3
x = 4
Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis. α = 0.01 for a left-tailed test (H1:µ <µ0).
The critical z value for a left-tailed test with α = 0.01 is -2.33.
To find the critical z value for a left-tailed test with α = 0.01, we need to look up the corresponding z-score in the standard normal distribution table.
Since the null hypothesis is H0: µ = µ0, we need to find the z-score that corresponds to the area to the left of the critical value, which is 0.01.
From the standard normal distribution table, we can see that the z-score corresponding to an area of 0.01 to the left is -2.33.
Therefore, the critical z value for a left-tailed test with α = 0.01 is -2.33.
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Chuck and 7 friends went to a Rodeo in Calgary. The cost of admission was $6 per person. The friends also went
to a concert for an addition charge. In total the cost of the admission and concert was $264. Which algebraic
expression would best model solving for the cost of a concert ticket?
Three concert tickets cost `\$45`. At this same rate, how much do `12` tickets cost?
The cost of 12 tickets is $180.
Given that, three concert tickets cost $45.
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Here, the cost of one ticket
= 45/3
= $15
So, the cost of 12 tickets = 12×15
= $180
Therefore, the cost of 12 tickets is $180.
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The distance AB =
(-3,1) (1,-1)
Round to the nearest tenth
The measure of the arc CE would be -
m. arc{CE} = 141°
What is distance formula?The distance formula is given by -
(d)² = (x₂ - x₁)² + (y₂ - y₁)²
Given are the coordinate points as -
(- 3,1) & (1,- 1)
The given coordinate points are -
(d)² = (- 1 - 1)² + (1 + 3)²
(d)² = (-2)² + (4)²
(d)² = 4 + 16
(d)² = 20
d = √20
Therefore, the distance AB is equivalent to √20 units.
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Sketch the curve y = \sqrt{x+3} .
Find the area bounded by the curve, X-axis and Y-axis.
I get the first part but not the second part.
The area bounded by the curve, x-axis and y-axis of the function y = √(x + 3) is 2√3
How to determine the area bounded by the curve, x-axis and y-axis?The curve is given as:
y = √(x + 3)
The area bounded by the curve, x-axis and y-axis is when x = 0 and y = 0
When y = 0, we have:
0 = √(x + 3)
This gives
x = -3
So, we set up the following integral
A = ∫ f(x) d(x) (Interval a to b)
This gives
A = ∫ √(x + 3) d(x) (Interval -3 to 0)
When the above is integrated, we have:
A = 1/3 * [2(x + 3)^(3/2)] (Interval -3 to 0)
Expand
A = 1/3 * [2(0 + 3)^3/2 - 2(-3 + 3)^3/2]
This gives
A = 1/3 * 2(3)^3/2
Apply the law of indices
A = 2(3)^1/2
Rewrite as:
A = 2√3 or 3.46
Hence, the area bounded by the curve, x-axis and y-axis of the function y = √(x + 3) is 2√3
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Use the scatter plot to answer the question. The points in the scatter plot generally increase upward to the right. © 2018 StrongMind. Created using GeoGebra.
Which type of linear correlation is present in the scatter plot?
positive
neutral
negative
strong
The positive linear correlation is present in the scatter plot option first “positive” is correct.
What is the line of best fit?A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.
\(\rm m = \dfrac{n\sum xy-\sum x \sum y}{n\sum x^2 - (\sum x)^2}\\\)
\(\rm c = \dfrac{\sum y -m \sum x}{n}\)
We have given a scatter plot in the picture.
As we can see in the scatter plot the dots are not so close that the correlation between x and y will be weak.
If we draw a line of best fit the slope of the line will be positive, the correlation will be positive.
Thus, the positive linear correlation is present in the scatter plot option first “positive” is correct.
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Dale mixed 5.9 grams of salt into a pot of soup he was cooking. Before he served the soup, Dale added 0.31 grams of salt. How much salt did Dale put into the soup in all? EXPLAIN what you need to do, and solve it. QUIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIICKKKKKKKKKKKKKKKKKKKKK
Answer:
Dale put 6.21 grams of salt into the soup in all
Step-by-step explanation:
Arithmetic
There are situations where different mathematic operations must be done in order to find the required results. Four operations are known as basics in arithmetic: addition, subtraction, multiplication, and division.
The question describes how Dale added 5.0 grams of salt into a pot of soup and then he added 0.31 grams of salt more. This means the total amount of salt added by Dale into the soup is the sum of both quantities:
Total salt added = 5.9 grams + 0.31 grams = 6.21 grams.
Dale put 6.21 grams of salt into the soup in all
Can someone answer all these questions
If the perimeter is 16' the sum of the length and width must be 8'. Assuming that area is non 0 possible dimensions are:
1x7 2x6 3x5 4x4 5x3 6x2 7x1
what is the exact value of the expression? tan(π6) sin(5π3)⋅cos(−3π4)
The exact value of the expression tan(π/6) sin(5π/3)⋅cos(-3π/4) is -√3/2.
We have tan(π/6). The angle π/6 is equivalent to 30 degrees. The tangent of 30 degrees is √3/3.
We have sin(5π/3). The angle 5π/3 is equivalent to 300 degrees. In the unit circle, the sine value at 300 degrees is -√3/2.
Finally, we have cos(-3π/4). The angle -3π/4 is equivalent to -135 degrees. In the unit circle, the cosine value at -135 degrees is -√2/2.
Multiplying these values together, we have (√3/3) * (-√3/2) * (-√2/2). Simplifying, we get (√3 * √3 * √2) / (3 * 2 * 2) = (√3 * √2) / 12.
Taking the negative sign into account, the final value is -√3/2, which is approximately -0.866.
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Which of the following figures are not similar?
Answer:
The second diagram on the first page
Step-by-step explanation:
Every other diagram is a multiplication, for example in the first picture its multiplied by 3 on the top and bottom and then on the sides its both by 4. But in diagram 2 its most likely to be an addition, which dose not work in the ones that were already shown.
if we are given a right-tail probability (or area) a and want a measurement m, which function in excel should we use? assume that the mean of the distribution is mu and the standard deviation is sigma.
The function in Excel that we should use to find a measurement M given a right-tail probability (or area) A is = NORM.INV(1-A, mu, sigma)
In order to find a measurement M given a right-tail probability A in Excel, we can use the NORM.INV function. The NORM.INV function in Excel returns the inverse of the normal cumulative distribution for a given probability.
The formula for NORM.INV function is:
= NORM.INV(1-A, mu, sigma)
where:
A is the right-tail probability (or area)
mu is the mean of the distribution
sigma is the standard deviation
The function returns the measurement M such that the right-tail area from M to infinity under the normal curve is equal to A.
Note - In some versions of Excel, the function may be called NORM.INV.RT instead of NORM.INV.
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a scale model of a building is 3 inches tall. if the building is 90 feet tall, find the scale of the model. a. 1in: 20ft c. 1:25 b. 1ft: 20in d. 1 in: 30ft
The scale of the model is 1 inch : 30 feet (option d).
To determine the scale of the model, we need to compare the height of the model to the actual height of the building. Given that the height of the model is 3 inches and the height of the building is 90 feet, we can set up a ratio to find the scale.
Let's denote the scale as "1 inch : X feet". Setting up the ratio, we have:
1 inch / X feet = 3 inches / 90 feet.
To solve for X, we can cross-multiply:
3 inches * X feet = 1 inch * 90 feet.
Simplifying the equation:
3X = 90.
Dividing both sides by 3, we find:
X = 30.
Therefore, the scale of the model is 1 inch : 30 feet (option d). This means that each inch on the model represents 30 feet in the actual building. So, for every 1 inch of the model's height, the real building's height corresponds to 30 feet.
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