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A Particale's position function is given by X= 3t3+5t²-6 with X in meter and t in second What is the average velocity between t1-2s and t2-6s 4 196m/s.a O 784 .b O 38m/s .c O 822m/s.d O

125Answer:

Explanation:uruhavdfh

Answer:

608

Explanation:

Trust me

Answer:

608

Explanation:

I only answer after making sure the answer is correct and I get the green tick, not the red cross (Acellus)

When a stone is tied to a 0.50 m string and whirled at a constant speed of 4.0 m/s in a vertical circle, the acceleration at the bottom of the circle is 32.0 m/s²

The acceleration at the bottom of the circle can be determined using the formula:
acceleration = (velocity²) / radius

Given that the stone is whirled at a constant speed of 4.0 m/s and is tied to a 0.50 m string, we can calculate the acceleration.

First, let's convert the speed from m/s to m²/s² by squaring it: (4.0 m/s)² = 16.0 m²/s².

Next, substitute the value of velocity^2 (16.0 m²/s²) and the radius (0.50 m) into the formula:

acceleration = (16.0 m²/s²) / (0.50 m) = 32.0 m/s².

Therefore, the acceleration at the bottom of the circle is 32.0 m/s².

In conclusion, when a stone is tied to a 0.50 m string and whirled at a constant speed of 4.0 m/s in a vertical circle, the acceleration at the bottom of the circle is 32.0 m/s².

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The displacement of the bicycle is 85.3125m

Displacement of the bicycle may be defined as the change in position of the bicycle. It is a vector quantity so that it has direction and magnitude.

We are given that,

The initial velocity of the bicycle = u = 5m/s

The acceleration of the bicycle is = a = 2.5 m/s²

The time taken by the bicycle = t = 6.5 seconds

Therefore, to get the value of displacement of the bicycle by the equation of motion which is written as,

S = ut + (1/2) at²

Where, S is displacement, u is initial velocity, a is acceleration and t is time taken by the bicycle.

Since , putting the values in above equation then we get,

S = {5m/s × 6.5sec} +{ (1/2) × 2.5m/s² × (6.5 sec)²}

S = 32.5 m + 52.8125m

S = 85.3125m

Therefore, the bicycle would be moves 85.3125m

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Answer:

1.5 m

Explanation:

a = v/t

a = 2/1,5 = 4/3

x = 1/2 a t² + vt + x

x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m

About \(1.795 x 10^-3\)  seconds

Answer:

To find the force with which the cue ball will strike the other ball, you will need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

You can calculate the force using the following formula:

Force = mass * acceleration

Plugging in the values from your question, we get:

Force = 0.350 kg * 5.21 m/s^2 = 1.82 N

To convert the distance the cue ball travels from centimeters to meters, divide the distance by 100. So 175 cm is equal to 1.75 m.

I hope this helps!

Calculate the buoyant force acting on the block, which is equal to the weight of water displaced, using Archimedes' principle. The block's weight less the buoyant force equals the tension in the string.

To calculate the buoyant force, we need to determine the volume of water displaced by the block. The volume of the block is equal to its mass divided by its density, so we have: Volume of block = mass / density = 653 g / 0.73 g/cm3 = 894.5 cm3 Since the block is completely submerged, the volume of water displaced is also 894.5 cm3. The weight of this volume of water is: Weight of water = density of water x volume of water x acceleration due to gravity

= 1 g/cm3 x 894.5 cm3 x 9.81 m/s2

= 8,756.75 g ,Thus, the buoyant force acting on the block is 8,756.75 g or 8.75675 N. Since the block is trying to float to the surface, the buoyant force acts upwards and the tension in the string acts downwards. Therefore, the tension in the string is: Tension in string = weight of block - buoyant force

= 653 g x 9.81 m/s2 - 8.75675 N

= 6,263.63 N - 8.75675 N

= 6,254.87 N , Therefore, the tension in the string is approximately.

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The speed of the joined cars after the collision is most likely less than the speed of car b before the collision.

This is due to the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the system is the two toy cars, and the collision is a closed system because no external forces are acting on the cars.

Before the collision, car b has a certain momentum, and car a has zero momentum since it is at rest. After the collision, the two cars stick together and move in the same direction as car b before the collision. The total momentum of the system remains constant, but now it is shared between the two cars. Since the total mass of the system has increased, the speed of the joined cars after the collision will be less than the speed of car b before the collision.

To calculate the exact speed of the joined cars after the collision, we would need to know the masses and initial velocities of the two cars. However, we can say with certainty that the speed will be less than the speed of car b before the collision due to the conservation of momentum.

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Answer:

0J

Explanation:

PE=mgh

PE=  1000kgx9.8m/s^2x0m

PE = 0J

The plane was flying at 39.6 m/s when the bottle was released .

\(h = ut + 1/2at^2\)

distance fallen h= 500m

Initial velocity u=0

a=98 m/s2

\(h = 1/2at^2\)

\(t^2 = 2h/a\)

\(t^2 = 1000/9.8 = 10.1s\)

\(d_h = 400, t = 10.1s\)

\(v = d_h/t\\v = 400/10.1\)

v = 39.6 m/s

Altitude or Height  (also known as depth) is a measurement of the distance between a reference point and a point or object, usually in a vertical or "upward" direction. The exact definition and reference value varies depending on the context (eg, aeronautics, geometry, geodesy, sports, or barometric pressure). Although the term height is often used to refer to the height of a place above sea level, in geography the term height is often preferred for this use.

The vertical measurement of distance in the "down" direction is usually called depth.

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Answer:

10 vibrations per second

Explanation:

Answer:

Kinetic Energy is 1.59x10^7 Newtons

Potential Energy cannot be determined since no height is given. An example calculation is provided that assumes 3000 meters.

Explanation:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: 

K.E. = 1/2 m v2.

If the mass is in kilograms and the velocity in meters per second, the kinetic energy has units of kilograms-meters per second squared, which is 1 Newton. (A newton is defined as 1 kg⋅m/s2. 1 Joule is defined as 1 N*m, or 1 kg⋅m2/s2

Data: 8500 kg airplane

220 km/h flight speed

We'll convert the speed from km/h to m/sec.

(220 km/h)*(1 h/3600 sec)*(1000m/1km) = 61.1 m/s

Kinetic Energy:

K.E. = 1/2 m v2

K.E. = 1/2 (8500 kg)*(61.1 m/s)^2

K.E. = 1/2 (8500 kg)*(3733 m^2/s^2)

K.E. = 1.59x10^7 kg*m^2/s^2

K.E. = 1.59x10^7 Newtons

Potential Energy

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

P.E. = mgh

P.E. = (8500kg)*(9.8 m/s^2)*(h)

I don't see a height given for the plane, so we can't calculate a potential energy. If it were at 3000 meters (1.86 miles), the calculation would be:

P.E. = (8500kg)*(9.8 m/s^2)*(3000 m)

P.E. = (2.5x10^8 kg*m/s^2) or 2.5x10^8 Newtons

Answer:

h=mv^2/mg

h=v^2/g

Explanation:

please make me as brainlest

Answer:

Answer is in attached photo.

Explanation:

The solution is in the attached photo, do take note for this question, we are making h the subject, and in equations, we can cancel like terms.

When the elevation of the sun above the horizon is at 90 degrees, the percentage of absorbed radiation is at its maximum.

At this angle, the sun's rays are perpendicular to the Earth's surface, resulting in the highest amount of solar radiation being absorbed. Therefore, the percentage of absorbed radiation is 100%.

When the elevation of the sun above the horizon is at 90 degrees, it means that the sun is directly overhead, which typically occurs at solar noon in most locations. At this position, the sun's rays are perpendicular to the Earth's surface.

However, without further information about the specific properties of the surface and the context in which the absorption is being measured, it is not possible to provide an exact percentage of absorbed radiation. The percentage would vary depending on factors such as the reflectivity (albedo) and material composition of the surface, as well as the presence of any intervening medium like air or water.

In general, when the sun is directly overhead (at 90 degrees elevation), a larger portion of the sunlight is likely to be absorbed by the surface compared to other angles, but the exact percentage would require more specific details.

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Answer:

E = 0.93 10⁻⁶ N/C, 24º NorthEast

Explanation:

The electric force is related to the electric field by the relation

          F = q E

where the bold letters indicate vectors and q is a scalar electric charge.

Using this equation the electric force is in the same direction as the electric field.

The magnitude of the field is

          E = F / q

the charge they give us is q = 8.7 C

let's calculate

          E = 8.1 10⁻⁶ / 8.7

          E = 0.93 10⁻⁶ N / C

In summary, the magnitude of the electric field is E = 0.93 10⁻⁶ N/C and its direction is 24º NorthEast

Answer:

B

Explanation:

i worked it out on a diffrent sheet so its hard to explain

The current, according to Ohm's law if, if The voltage between two points in a circuit is 5 V and the resistance between the points is 80 ohms, is 0.063 A so, option B is correct.

Electric currents can be created by the movement of any electric charge carriers, including ions (atoms that have gained or lost one or more electrons), holes, or subatomic charged particles (such electrons with a negative charge or protons with a positive charge) (electron deficiencies that may be thought of as positive particles).

Given:

The voltage between two points in a circuit is 5 V,

If the resistance between the points is 80 ohms,

Calculate the current using Ohm's law as shown below,

Current = The voltage between two points / the resistance between the points

Current = 5 / 80

Current = 0.0625

Current = 0.063 A,

Thus, the current according to Ohm's law is 0.063 A.

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Answer:

how to make a face mask with fabric ties with the new one is a block away from the new house in the new house

Explanation:

hope it help

Answer:

If a star is moving towards the earth, its light is shifted to higher frequencies on the color spectrum (towards the green/blue/violet/ultraviolet/x-ray/gamma-ray end of the spectrum). A higher frequency shift is called a "blue shift".

Explanation:

It just means that the entire spectrum is shifted up in frequency.

Answer:

amplitude, wavelength, frequency, and speed.

Explanation:

No matter whether you are talking about vibrations or waves, all of them can be characterized by the following four characteristics

♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

Answer:  Nothing will happen.

Explanation: A penny dropped from the top of the Empire State Building will not kill anyone. The penny will reach a terminal velocity of about 30 mph, which is not enough to cause serious injury.

The myth that a penny dropped from the Empire State Building can kill someone is a common one, but it is not true. The penny will not reach enough speed to cause serious injury. In fact, MythBusters tested this myth and found that a penny dropped from the Empire State Building could not even penetrate a layer of ballistics gel, which is designed to simulate human flesh.

So, if you're ever feeling tempted to drop a penny from the Empire State Building, don't do it. It's not worth the risk.

The penny's terminal velocity is 50 miles per hour (80 kilometers per hour), and air resistance prevents it from accelerating further, so it will only cause minor discomfort when dropped off the Empire State Building.

If you were to drop a penny off the Empire State Building, it would reach an incredibly high velocity due to the force of gravity. However, because of its small size and lightweight, it would not cause any damage to anything or anyone on the ground below. In fact, it is illegal to drop objects off of buildings, including the Empire State Building, due to the potential danger it could pose to people and property below. So, if you ever find yourself on the top of the Empire State Building, it's best to keep your pennies in your pocket!
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The (326-2) Type IGS cable is an excellent choice for high-voltage applications where flexibility and reliability are key factors. It is particularly well-suited for use in power transmission and distribution applications where it can help to improve system efficiency and reduce maintenance costs.

The (326-2) Type IGS cable is a factory assembly of one or more conductors, each individually insulated and enclosed in a loose fit nonmetallic flexible conduit. This type of cable is specifically designed as an integrated gas spacer cable and is rated for use up to 35,000 volts.

The nonmetallic conduit used in the IGS cable provides a high degree of flexibility and allows for ease of installation, particularly in challenging environments. Additionally, the integrated gas spacer technology provides enhanced electrical performance by minimizing electrical stress, reducing the risk of corona discharge, and improving the overall reliability of the cable.

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Ignore the fact that some of the values are negative numbers and instead consider their magnitude.

A)   Both are experience large force.

B)   Both are experience large impulse.

C)   Both are experience large momentum.

D)  Car experience large change velocity.

collision; collision To come together and have a strong or direct effect is an intransitive verb. The vehicle struck a tree. Hovercraft collision

Utilizing the rule of conservation of momentum, we can find a solution to this issue. If there are no outside forces, the truck-car system's total momentum must be preserved both before and after the collision.

Truck of mass m1 = 4000kg          

velocity of truck V1 = 10m/s

Car of mass m2 = 1000kg

let

velocity of car V2

principle of conservation of momentum use

m1V1=m2V2

4000×10=1000×V2

V2=40000/1000

V2=40m/s

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Answer: The correct option is A ( because the Earth is rotating, with the telescope attached to it).

Explanation:

A telescope is a device that is used mostly for viewing distant objects. It's an optical instruments as it's made up of lens and curved mirror depending on the type of telescope. The first telescope was invented by Hans Lippershey in 1608. It is used extensively in war,sea and astronomical discoveries.

Parts of a typical telescope includes:

--> the optical system: this is the most important part of a telescope. This determines the optical aperture of the telescope, how bright or how sharp the formed image would be. This can be a lens or a mirror.

--> Eyepiece: this magnifies the image formed.

--> Motorized drive system: these drive system are mounted with the telescope to aid in a quick and smooth movement while detecting, for example, celestial bodies. This part of the telescope is important as the telescope is mounted on the earth surface which rotates about its axis from west to east. Since the drive system is motorized, it can automatically move very smoothly from east to west at exactly the same rate that Earth is rotating from west to east, so it can continue to point at the object being observed.

The third point mass should be placed 64 cm away from 155 kg in between them.

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.

Given that: a 155 kg point mass is located 1.50 m from a 275 kg point mass.

Let a new point unit mass is placed  x m away from 155 kg in between them.

If the net gravitational force on the third point mass due to the original two masses is zero:

G* 155/x² = G * 275/(1.50  -x)²

(1.50 - x)² = (275/155)x²

1.50 - x = ±1.33 x

2.33 x = 1.50

x = 0.64 m = 64 cm.

Hence,  the third point mass should be placed 64 cm away from 155 kg in between them.

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Answer:

at rest because time is passing and speed is still at 0

Explanation:

1. The change in the kinetic energy of the system is given by the expression ΔKE = 1/2 * m * (vf^2 - 0^2) = 1/2 * m * vf^2, where m is the mass of the ball and vf is its final velocity. The change in potential energy of the system is given by the expression ΔPE = m * g * (hi - hf), where g is the acceleration due to gravity near the surface of the Earth (approximately 9.8 m/s^2).

The net external work by external forces on the system is zero, since the only force acting on the ball is the force of gravity, which is a conservative force and does not do any work on the ball.

Using the conservation of energy principle, we can write the equation ΔKE + ΔPE = 0, which implies that 1/2 * m * vf^2 + m * g * (hi - hf) = 0. Solving for vf, we get vf = √(2gh), where h = hi - hf is the height from which the ball falls. This is the final speed of the ball when it reaches height hf near the surface of the Earth, assuming no air resistance and negligible changes in kinetic energy of the Earth.

Let's write expressions for each quantity using the given terms and physical constants:

1. The change in kinetic energy of the system (the ball and the Earth):
ΔKE = ½mvf² - ½m(0)² = ½mvf²

2. The change in potential energy of the system:
ΔPE = mghf - mghi = mg(hf - hi)

3. The net external work by external forces on the system:
Since there is no air resistance and changes in Earth's kinetic energy are negligible, the net external work is zero.
W_ext = 0

4. Now, let's write an equation that relates the expressions above and use it to solve for the final speed of the ball. We'll use the work-energy theorem:
W_ext = ΔKE + ΔPE

Since W_ext = 0, we can rewrite the equation as:
0 = ½mvf² + mg(hf - hi)

To solve for vf, rearrange the equation:
½mvf² = -mg(hf - hi)
vf² = -2g(hf - hi)
vf = sqrt(-2g(hf - hi))

So, the final speed of the ball is given by the expression:
vf = sqrt(-2g(hf - hi))

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