HELP PLS. Choose the period with the highest grade, and provide and explanation based on the shape on the histograms.

Using the z-distribution, supposing a population standard deviation of 5, the minimum number of snapdragons you need for the new study is of 267.

The bounds of the confidence interval are presented as follows:

\(\overline{x} \pm z\frac{\sigma}{\sqrt{n}}\)

In which the parameters are described as follows:

The margin of error of the interval is:

\(M = z\frac{\sigma}{\sqrt{n}}\)

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of \(\frac{1+0.95}{2} = 0.975\), so the critical value of the interval is of z = 1.96.

The population standard deviation is given as follows:

\(\sigma = 5\)

The minimum number of dragons needed is n when M = 0.6, hence:

\(M = z\frac{\sigma}{\sqrt{n}}\)

\(0.6 = 1.96\frac{5}{\sqrt{n}}\)

\(0.6\sqrt{n} = 1.96 \times 5\)

\(\sqrt{n} = \frac{1.96 \times 5}{0.6}\)

\((\sqrt{n})^2 = \left(\frac{1.96 \times 5}{0.6}\right)^2\)

n = 266.8 = 267 (rounded up, as 266 would have a margin of error slightly above the desired).

The population standard deviation is missing, and we suppose that it is of 5.

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The substitution effect, denoted by ε*, measures the change in quantity demanded of q1 due to the relative price change, while the income effect, denoted by θξ, measures the change in quantity demanded of q1 due to the change in purchasing power. The total effect, denoted by ε, combines both the substitution and income effects.

To calculate the substitution effect, we need to evaluate the price elasticity of demand for q1, which measures the responsiveness of quantity demanded to a change in price. The income effect depends on the income elasticity of demand, which measures the responsiveness of quantity demanded to a change in income. These elasticities can be calculated using the given utility function, but specific price and income data are required.

Without the actual price and income data, it is not possible to provide the exact numerical values for the substitution, income, and total effects. The effects can only be determined with the necessary information and by performing the appropriate calculations using the utility function. The values of ε*, θξ, and ε will depend on the specific price and income changes that are considered.

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68.26% confident that the true Proportion of time spent mowing is between 0.4504 and 0.5496

The problem statement as

ks to determine the limits between which the manager of Lawn and Garden Services can be 68.26% confident that the true proportion of time spent mowing is.

What is the proportion of time spent mowing

We know that there are 400 observations of a typical worker. Out of this, the activity of mowing has been observed 200 times. The proportion of time spent mowing can be obtained as;`p = 200 / 400 = 0.5`T

hus, 50% of the worker’s time is spent mowing.What are the limits for a 68.26% confidence interval?We will use the formula for the 68.26% confidence interval as follows:`p ± z_(α/2) sqrt((p(1 - p))/n)` where's = 0.5``n = 400`At a 68.26% confidence interval, α = 1 - 0.6826 = 0.3174.

The value of `z_(α/2)` can be obtained from a standard normal distribution table as `1 - (0.3174 / 2) = 0.8413`Thus,`z_(α/2) = 0.8413`

Plugging in all the values, we get;`0.5 ± 0.8413 sqrt((0.5 * 0.5) / 400)`

Solving this, we get the limits as`(0.4504, 0.5496)`

Thus, we can be 68.26% confident that the true proportion of time spent mowing is between 0.4504 and 0.5496.

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Answer:

5/12 ounces

Step-by-step explanation:

If each tube holds 1/3 oz of paint, the you multiply 1/3 by the number of tubes that she used. 1/3oz/tube(1.25 tubes)= 5/12 ounces

Answer:

angle 4

its on the outside and it is alternate

Answer:

d

Step-by-step explanation:

The standard deviation the manufacturer must achieve to reduce the 36-month failure rate to only 10% is approximately 4 months, the correct option is (d) .

If manufacturer wants to reduce 36-month failure rate to only 10 percent , then

We need to find value of standard deviation that corresponds to a 36-month lifespan such that only 10% of machines fail before that time.

We can find this by finding the corresponding z-score that corresponds to a cumulative probability of 0.10.

We know , "z = (x - μ)/σ" ;

where:

⇒ x = 36 (desired lifespan)

⇒ μ = 42 (mean lifespan)

⇒ σ = standard deviation we want to find

⇒ z = z-score that corresponds to a cumulative probability of 0.10

Substituting the given values and solving for "σ", we get:

⇒ -1.28 = (36 - 42)/σ

⇒ σ = (42 - 36)/1.28

⇒ 4.69

So , the standard deviation is approximately 4 months.

Therefore, The correct option is (d) 4 months.

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The given question is incomplete , the complete question is

A manufacturer claims that lifespans for their copy maxhines (in months) can be described by a Normal model N(42,7).

The manufacturer wants to reduce the 36-month failure rate to only 10%. Assuming the mean lifespan will stay the same, what standard deviation must they achieve?

(a) 1 months

(b) 2 months

(c) 3 months

(d) 4 months.

Answer:

Step-by-step explanation:

\(area = \pi {r}^{2} \\ = 3.14 \times {7}^{2} \\ = 3.14 \times 49 \\ = 153.86 \: {km}^{2} \\ \)

Answer:

a

Step-by-step explanation:

The area of the shape is given as 24.52 cm2

We have two triangles and 1 rectangle

we have to find the area of the triangles first and then solve for the area of the rectangle.

The area of a triangle = 1/2bh

for first triangle

area = 1/2 * 2.7 * 3

= 4.05

for second triangle

height = 6.8 - 2.7

= 4.1

area = 1/2 * 3.4 * 4.1

= 6.97

For the rectangle

area = l * w

= 2.7 * 5 = 13.5

The area = 13. 5 + 6.97 + 4.05

= 24.52 cm2

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Using the triangle proportionality theorem, the missing lengths that are indicated are:

1. 35

2. 14

3. 28

4. 18

The triangle proportionality theorem states that when a line is drawn to be parallel to any side of a triangle that it intersects two of the side of the triangle at two different points, then the two sides are divided proportionally or in the same ratio.

Apply the triangle proportionality theorem to find all the missing length that are indicated. Let the missing side be represented as x.

Problem 1:

x/28 = 15/12

x = (28)(15)/12

x = 35

Problem 2:

x/28 = 6/(18 - 6)

x/28 = 6/12

x/28 = 1/2

x = 28/2

x = 14

Problem 3:

x/35 = 12/(12 + 3)

x/35 = 12/15

x/35 = 4/5

x = (35)(4)/5

x = 28

Problem 4:

x/54 = 8/24

x/54 = 1/3

x = 54/3

x = 18

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Answer:

The value is 4

Step-by-step explanation:

This is because the value of an absolute number is always positive so the absolute value of 4 would remain 4.

Answer: 4

Step-by-step explanation: The absolute value is how far a number is away from 0

Answer:

3.50 × 12 = 42

Therefore, she spent 42 dollars.

Answer:

height and the base your take height you square it then you square the base then you -

Answer:

If you are finding the equation using two points then the answer is

y = −2 x + 1

If this does not help, just ignore honestly.

Answer:

-1600

Step-by-step explanation:

−4^3(5^2)

5 × 5 = 25

-4 × -4 × -4

   -16 × -4

       -64

64 × 25 = -1600

The answer is -1600

Hope this helped.

Applying the segment addition postulate, the value of r is determined as: A. 10.

A perpendicular bisector is a line segment which divides another line segment into two equal parts, that is, the segments formed have equal lengths.

Since point G lies on the perpendicular bisector of segment DM, therefore:

DG = GM

Given the following:

DM = 25

GM = 4r - 28

DG = r + 3

Therefore:

DG + GM = DM [segment addition postulate]

Substitute

r + 3 + 4r - 28 = 25

Combine like terms

5r - 25 = 25

5r = 25 + 25

5r = 50

5r/5 = 50/5

r = 10

Thus, applying the segment addition postulate, the value of r is determined as: A. 10.

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Answer:

Step-by-step explanation:

Which ones have four sides?

A

B

D

Okay, here we have this:

Considering the provided system of equations, we are going to graph the system, so we obtain the following:

Graphing the system we have:

We can see that the two functions do not intersect at any time, therefore the system of equations has no solution in the set of real numbers.

A monomial is an algebraic expression that consists of a single term. A monomial can contain constants and/or variables, which are multiplied together.

The expression 3x²y is a monomial. It contains the constant 3, the variable x squared, and the variable y. The variables can be raised to an exponent, as in this example; however, the exponent must be a whole number.A monomial can also contain coefficients, which are the numbers that are multiplied with a variable. In the example above, the coefficient is 3. If there is no coefficient stated, then the coefficient is assumed to be 1. Therefore, the expression x²y is also a monomial, with the coefficient being 1.Additionally, a monomial can contain a product of numbers and variables, such as the expression 2xyz. This is also considered a single term, since all of the numbers and variables are multiplied together.

Monomials can be used to calculate polynomials, which are algebraic expressions consisting of multiple terms. By adding, subtracting, and multiplying monomials together, you can create a polynomial. For example, the expression (3x²y) + (2xyz) is a polynomial, since it consists of two terms. The first term is the monomial 3x²y, and the second term is the monomial 2xyz.

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The equation of a circel which has center is $a + b + c + r = 1 + 10 - 4 + \sqrt{11} = 7 + \sqrt{11}.$

The equation of a circle with center at (h, k) and radius r is given by: $(x - h)^2 + (y - k)^2 = r^2$
Since the circle has a center at (-5, 2), we can write the equation as: $(x + 5)^2 + (y - 2)^2 = r^2$
Expanding the equation, we get: $x^2 + 10x + 25 + y^2 - 4y + 4 = r^2$

Given the equation of the circle in the form $ax^2 + 2y^2 + bx + cy = 40,$ we can compare the coefficients: $x^2 + 10x + y^2 - 4y = 40 - 25 - 4 = 11$. So, $a = 1, b = 10,$ and $c = -4.$
To find r, we can use the fact that $40 = r^2 + 25 + 4.$ Thus, $r^2 = 11,$ and $r = \sqrt{11}.$

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Answer:

A. x=30

Step-by-step explanation:

1. first you subtract 5 from both side so you can get rid of it.

x/3 + 5 =15

       -5   -5

x/3=15

2. then multiply all terms by 3 to eliminate the fraction's denominator

x/3 ⋅ 3 = 10⋅3

3. lastly you simplify. cancel the 3 from the fraction and solve for x.

x=30

It will take approximately 15.61 years for $1,886 to grow to $8,156 with a 7.02 percent annual interest rate, compounded annually.

To determine the number of years it will take for $1,886 to grow to $8,156 with a 7.02 percent annual interest rate, we can use the compound interest formula:

A = P * (1 + r)^n,

where A is the future value, P is the principal amount, r is the interest rate per period, and n is the number of periods.

In this case, the principal amount is $1,886, the future value is $8,156, and the interest rate is 7.02 percent. We need to solve for n.

Dividing both sides of the equation by P:

(1 + r)^n = A / P,

Substituting the given values:

(1 + 0.0702)^n = 8,156 / 1,886.

Using logarithms to solve for n:

n = log(8,156 / 1,886) / log(1 + 0.0702).

Using a calculator, the approximate value of n is:

n ≈ 15.61.

Therefore, it will take approximately 15.61 years for $1,886 to grow to $8,156 with a 7.02 percent annual interest rate, compounded annually.

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Answer:

9 essay questions.

Step-by-step explanation:

We have been given that ada’s history teacher writes a test for the class with 26 questions. We can represent this information in an equation as:

x+y=26

We are also told that multiple choice worth 3 points each, so total number of points for x questions will be 3x.

As essays worth 8 points each, so total number of points for y questions will be 8y.

Since the test is worth 123 points, so we can represent this information in an equation as:

3x + 8y= 123

Now we will use substitution method to solve system of linear equations.

From equation (1) we will get,

x=26-y

Substituting this value in equation (2) we will get,

3×(26-y)+8y=123

78-3y+8y=123

78+5y=123

Let us subtract 78 from both sides of our equation.

78-78+5y=123-78

5y=45

Let us divide both sides of our equation by 5.

5y/5=45/5

y=9

According to the question we have  the 99% UCB on the mean time of the race is 223.

The formula for finding the upper confidence bound (UCB) is UCB = Mean + (Zα/2)(σ/√n), where Mean is the sample mean, Zα/2 is the z-score for the desired level of confidence, σ is the population standard deviation (which is not given, so we'll use the sample standard deviation instead), and n is the sample size.

We are given the sample of times as follows:137, 143, 153, 162, 168, 176, 190, 192, 196, 203, 218, 223, 236, 243, 252, 269, 271, 276, 283, 287.

We'll need to calculate the sample mean and standard deviation before we can find the UCB. Using a calculator, we get: mean ≈ 207.65s ≈ 48.41 Next, we'll use a table or calculator to find the z-score for a 99% confidence interval, which is Zα/2 = 2.576.

Now we can plug in the values we know to get the UCB:UCB = mean + (Zα/2)(σ/√n)UCB ≈ 207.65 + (2.576)(48.41/√20)UCB ≈ 223.02 .Therefore, the 99% UCB on the mean time of the race is 223.

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Let X be the number of people who experience mild side effects after taking the drug. X follows a binomial distribution with parameters n = 100 (the number of people taking the drug) and p = 0.75 (the probability of mild side effects).

To find the probability that more than 70 people will experience mild side effects, we need to calculate:

P(X > 70) = 1 - P(X ≤ 70)

Using the cumulative distribution function (CDF) of the binomial distribution, we can find:

P(X ≤ 70) = F(70) = ∑(i=0 to 70) [nCi * p^i * (1-p)^(n-i)]

where nCi is the binomial coefficient for choosing i items out of n.

We can use a software or calculator to calculate this sum, or use an approximation like the normal approximation to the binomial distribution.

Assuming normal approximation is appropriate, with mean μ = np = 75 and standard deviation σ = sqrt(np(1-p)) = 3.354, we can calculate the z-score:

z = (70.5 - μ) / σ = (70.5 - 75) / 3.354 = -1.33

Using a standard normal distribution table or a calculator with normal distribution functions, we can find the probability of z-score less than -1.33 is 0.0918, which is the probability of 70 or fewer people experiencing mild side effects.

Therefore, the probability of more than 70 people experiencing mild side effects is:

P(X > 70) = 1 - P(X ≤ 70) = 1 - 0.0918 = 0.9082

Using the binomial distribution, there is a probability of approximately 0.9082 that more than 70 people will experience mild side effects out of 100 people who take the drug.

The number of cases per batch that should be produced to minimize cost is: 300 units

The number of cases per batch that should be produced to minimize cost can be found by using the Economic Order Quantity.

The Economic Order Quantity (EOQ) is a calculation performed by a business that represents the ideal order size that allows the business to meet demand without overspending. The inventory manager calculates her EOQ to minimize storage costs and excess inventory.  

Thus:

Number of cases per batch = √((2 * Setup costs * annual demand)/ holding costs for the year)

Solving gives:

√((2 * 30 * 15000)/10)

= √90000

= 300 units

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Answer:

x = 5.5

EF = 14

Step-by-step explanation:

We can use ratios to solve

AG                  7

----------- =  -----------------

EG                   2x+3

We know that EG is 2 times AG since A is the midpoint

AG                  7

----------- =  -----------------

2 AG                   2x+3

Canceling like terms

1                  7

----------- =  -----------------

2                    2x+3

Using cross products

1 (2x+3) = 2*7

2x+3 = 14

Subtract 3 from each side

2x+3-3 = 14-3

2x =11

Divide by 2

x = 11/2

x = 5.5

EF = 2x+3 = 2*5.5+3 = 14

Answer:

\(2w - \frac{ 7}{4} \)

Step-by-step explanation:

\( \frac{1}{4} \times 8w = 2w \\ \frac{1}{4} \times ( - 7) = \frac{ - 7}{4} \)

Answer: 2w -7/4

Step-by-step explanation:

    1 /4(8w  − 7)  

Apply the distributive property.

    1 /4(8w  − 7)  + 1/4  ⋅  − 7

Cancel the common factor of 4.

Factor 4 out of 8w.

     2w + 1/4 ⋅ -7

Combine  1/4 and -7

    2w + ((-7)/4)

Move the negative in front of the fraction.

    2w − 7/4