Answer:
this is a right angle triangle with a 45 degree angle so ew has to be the same length as qe so 7 and then a square + b squared= c squared gets you the hypotenuse 9.89 with proper sig figs you get 10
Step-by-step explanation:
Rectangular prism surface area
Answer:
Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.
Find fourconsecutive integers with the sum of 54
Answer:
They are 12, 13, 14 and 15.
Step-by-step explanation:
If the least integer is x, then:
x + x + 1 + x + 2 + x + 3 = 54
4x + 6 = 54
4x = 48
x = 12.
What is the slope of the following points? (11,9) and (12,9)
the equation to find the slope between 2 points is
\(m=\frac{y2-y1}{x2-x1}\)name the points
1=(11,9)
2=(12,9)
apply the formula
\(\begin{gathered} m=\frac{9-9}{12-11} \\ m=\frac{0}{1} \\ m=0 \end{gathered}\)the slope between the points is 0.
What are the MRSs? Determine if there is a diminishing MRS
a. U(x,y)=3x+y
b. U(x,y)=x.y
c. U(x,y)=x⋅y
d. U(x,y)=x2−y2
e. U(x,y)=x+yx.y 3.
Consider each of a. U(x,y)=x0.1y0.4 b. U(x,y)=min(αx,βy) c. U(x,y)=αx+βy calculate the following i. Demand curves for x and y ii. Indirect utility function iii. (Indirect) expenditure function iv. Show that the demand curve is homogeneous in degree zero in terms of income and prices
a. The MRS is constant (not diminishing) at 1/3.
U(x,y) = 3x + y
The MRS for this utility function can be found by taking the partial derivative of x concerning y:
MRS = ∂U/∂y / ∂U/∂x = 1 / 3
The MRS is constant (not diminishing) at 1/3.
b. The MRS is diminishing because as y increases, the MRS decreases.
U(x,y) = x * y
The MRS for this utility function can be found by taking the partial derivative of x concerning y:
MRS = ∂U/∂y / ∂U/∂x = 1 / y
The MRS is diminishing because as y increases, the MRS decreases.
c. The MRS is diminishing because as y increases, the MRS decreases.
U(x,y) = x * y
The MRS for this utility function can be found by taking the partial derivative of x concerning y:
MRS = ∂U/∂y / ∂U/∂x = 1 / y
Similar to the previous case, the MRS is diminishing because as y increases, the MRS decreases.
d. The MRS depends on the ratio of y to x and can vary.
U(x,y) = x^2 - y^2
The MRS for this utility function can be found by taking the partial derivative of x concerning y:
MRS = ∂U/∂y / ∂U/∂x = -2y / 2x = -y / x
The MRS depends on the ratio of y to x and can vary. It is not necessarily diminishing.
e. The MRS depends on the values of x and y and can vary.
U(x,y) = x + y / (x * y)
The MRS for this utility function can be found by taking the partial derivative of x concerning y:
MRS = ∂U/∂y / ∂U/∂x = -1 / (y^2) + 1 / (x^2 * y)
The MRS depends on the values of x and y and can vary. It is not necessarily diminishing.
Now let's move on to the second part of the question:
For parts a, b, and c, we need more specific information about the utility functions, such as the values of α and β, to calculate the demand curves for x and y, the indirect utility function, and the expenditure function.
To show that the demand curve is homogeneous in degree zero in terms of income and prices, we need the specific functional form of the utility functions and information about the prices of x and y. Please provide the necessary details for parts A, b, and c to continue the analysis.
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A video store changes a monthly membership fee of $7.50 but the charge to rent each movie is only $1.00 per movie another store has no membership fee but it cost $2.50 to rent each movie how many movies need to be ready each month for the total fees to be the same from either company
Answer:
5 movies
Step-by-step explanation:
Let x denotes number of movies that need to be ready each month for the total fees to be the same from either company.
Monthly membership fee charged by a video store = $7.50
Amount charged to rent each movie = $1.00
So,
total amount charged by the first store = \(7.50+(1)x=7.50+x\)
Monthly membership fee charged by another video store = $0
Amount charged to rent each movie = $2.50
So,
total amount charged by another store = \(0+2.50(x)=2.50x\)
To find number of movies that need to be ready each month for the total fees to be the same from either company,
solve \(7.50+x=2.50x\)
\(7.50+x=2.50x\\7.50=2.50x-x\\7.50=1.50x\\x=\frac{7.50}{1.50}\\ =5\)
What is the best way to describe -22
А
С
3
2
1
0
1
2
3
the opposite of 2
the distance between A and C
point A
the distance between A and D
Answer:
point A
Step-by-step explanation:
on the number line, point A represent -2
What is the size of x when the opposite is 4.9 the hypotenuse is 7.2 i need to work out x which is where it meets with the hypotenuse and adjacent?
Answer:
Step-by-step explanation:
10
Which is the following functions is graphed below?
Answer:
A.y=|x|+7
Step-by-step explanation:
algebra 2-2
solve \(\sqrt{x}+3=-6\)
√x+3=-6
The solution of equation is x=-3
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
Given
The equation;√x+3=-6
Now,
√x=-6-3
√x=-9
x=-3
Therefore the answer of the given equation will be -3
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Consider this expression
When hanging a 2 7/8 ft long wall hanging in the middle of a wall that is 11 ft long, approximately how far from each end of the wall should it be hung to be in the center of the wall?
It should be hung 4 1/16 feet (Measurement unit) from each side of the wall.
what are measurement units(e.g. feet)?
Finding a number that represents the amount of something is what measurement is all about. A measuring unit is a unit of measurement that is used to express a physical quantity.
There are 7 measurement SI-units and these are following
Length - meter (m)Time - second (s)Amount of substance - mole (mole)Electric current - ampere (A)Temperature - kelvin (K)Luminous intensity - candela (cd)Mass - kilogram (kg)Let, the wall hanging should be hung d feet from each end of wall
therefore,
Length of wall hanging=2 7/8 feet
Length of wall= 11 feet
length left after hanging the wall hanging=11 - 2 7/8
=8 1/8 feet
hence d=(8 1/8)/2
d=4 1/16 feet (distance from each end of wall)
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Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes, and one vertex in the plane.
The volume of the largest rectangular box in the first octant with three faces in the coordinate planes, and one vertex in the plane is V = xyz, where x, y, and z are the lengths of the sides of the rectangular box.
To find the largest volume, we need to maximize x, y, and z. Since we have three faces in the coordinate planes, one vertex will be at the origin (0, 0, 0). The other two vertices will lie on the coordinate axes.
Let's assume the vertex on the x-axis is (x, 0, 0), and the vertex on the y-axis is (0, y, 0). The third vertex on the z-axis will be (0, 0, z). Since the box is in the first octant, all the coordinates must be positive.
To maximize the volume, we need to find the maximum values for x, y, and z within the constraints. The maximum values occur when the box touches the coordinate planes. Therefore, the maximum values are x = y = z.
Substituting these values into the volume formula, we get V = xyz = x³. Therefore, the volume of the largest rectangular box is V = x³.
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What is the maximum volume of a rectangular box situated in the first octant, with three of its faces lying on the coordinate planes, and one of its vertices located in the plane?
Let V be the set containing all sequences in the form of a=(a1,a2,…) where ai∈R for all i∈N and define the map ∥⋅∥2:V→R by ∥a∥2=(∑n=1[infinity]∣an∣2)1/2 In this problem we will investigate properties of the space ℓ2:={a∈V:∥a∥2<+[infinity]}. Show that 1. (ℓ2,∥⋅∥2) is a normed vectorspace over R under addition a+b=(a1+b1,a2+b2,…). 2. Show that (ℓ2,∥⋅∥2) is complete. 3. Show that the closed unit ball B(0,1):={a∈ℓ2:∥a∥2≤1} is not compact.
1. (ℓ2, ∥⋅∥2) is a normed vector space over R. 2. (ℓ2, ∥⋅∥2) is complete. 3. The closed unit ball B(0,1) is not compact.
To show that (ℓ2, ∥⋅∥2) is a normed vector space over R, we need to verify the following properties:
a) Non-negativity: \(||a||_2 \geq 0\) for all a ∈ ℓ2.
b) Definiteness: \(||a||_2 = 0\) if and only if a = 0.
c) Homogeneity: \(||c. a||_2 = |c| . ||a||_2\) for all c ∈ R and a ∈ ℓ2.
d) Triangle inequality: \(||a+b||_2 \leq ||a||_2 + ||b||_2\) for all a, b ∈ ℓ2.
These properties can be easily verified using the definition of the norm \(|| \,||_2\) as the square root of the sum of the squares of the elements in the sequence.
To show that (ℓ2, ∥⋅∥2) is complete, we need to demonstrate that every Cauchy sequence in ℓ2 converges to a limit that is also in ℓ2. Let {an} be a Cauchy sequence in ℓ2, meaning that for any ε > 0, there exists N such that for all m, n ≥ N, we have \(||a_m - a_n||_2 < \epsilon\).
To show completeness, we need to find a limit point a ∈ ℓ2 such that \(\lim_{n \to \infty} ||an - a||_2\). We can construct this limit point by taking the limit of each component of the sequence. Since each component is a real number and the real numbers are complete, the limit exists for each component. Thus, the limit point a will also be in ℓ2, satisfying the completeness property.
To show that the closed unit ball B(0,1) = {a ∈ ℓ2 : ∥a∥2 ≤ 1} is not compact, we need to demonstrate that there exists an open cover of B(0,1) that does not have a finite sub-cover.
Consider the sequence {en}, where en is the sequence with a 1 in the nth position and 0s elsewhere. Each en is in B(0,1) since ∥en∥2 = 1. Now, for each n, consider the open ball B(en, 1/2). It can be shown that the intersection of any two of these open balls is empty, and hence, no finite sub-cover can cover B(0,1).
Therefore, B(0,1) is not compact.
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A company is designing a new cylindrical water bottle. The volume of the bottle will be 99 cm³. The height of the water bottle is 7.8 cm what is the radius of the water bottle. Use 3.14 for
Answer:
2.08
Step-by-step explanation:
99/7.8=13.56
13.56/3.14=4.32
the square root of 4.32 is 2.08
Hi everyone, i'm stuck on question 3c part i. i know the answer is 8 years and 4 months but unsure how to get to that point. please show all working out thank you so much!
(i) It will take Evelyne approximately 63 months (or 5 years and 3 months) to repay the loan after increasing her repayments to $3000 per month. (ii) Interest saved = $642,064.
Describe Interest?Interest can be simple or compound. Simple interest is calculated based only on the principal amount borrowed or invested. Compound interest, on the other hand, is calculated based on both the principal and the accumulated interest. In other words, the interest earned is reinvested back into the principal, which then earns additional interest. Compound interest results in a higher return compared to simple interest, as the interest earned is compounded over time.
Interest is an important concept in personal finance, business, and economics. It plays a key role in determining the cost of borrowing money and the return on investment, and affects the overall economy through its impact on consumption, investment, and savings.
c. After 10 years, Evelyne is able to increase her repayments to $3000 per month.
i. To determine how long it will take Evelyne to repay the loan after increasing her repayments to $3000 per month, we need to first calculate the remaining loan balance at that time. Since Evelyne has been repaying the loan for 10 years, the number of monthly payments remaining is:
20 years x 12 months/year - 10 years x 12 months/year = 120 months
Using the formula for the present value of an annuity, we can calculate the remaining loan balance after 120 months of monthly payments of $X:
\(PV=X*[1-\frac{(1+\frac{r}{12} )^{n} }{\frac{r}{12} } ]\)
where PV is the present value of the annuity (i.e., the remaining loan balance), X is the monthly payment, r is the monthly interest rate, and n is the number of months.
Substituting the given values, we get:
PV = $350,000 * [(0.0054167 - (1 + 0.0054167)⁻¹²⁰)/(0.0054167)] = $178,432.76
Therefore, the remaining loan balance after 10 years of repayments is $178,432.76.
To determine how long it will take Evelyne to repay the loan after increasing her repayments to $3000 per month, we can use the formula for the present value of a lump sum:
PV = FV / (1 + r/12)ⁿ
where FV is the future value (i.e., the remaining loan balance), r is the monthly interest rate, and n is the number of months.
Substituting the values, we get:
$178,432.76 = FV / (1 + 0.065/12)ⁿ
Solving for n, we get:
n = ln(\(\frac{FV}{PV}\)) / ln(1 + \(\frac{r}{12}\)) = ln( \(\frac{178432.76}{0}\)) / ln(1 + \(\frac{0.065}{12}\)) = 62.45
Therefore, it will take Evelyne approximately 63 months (or 5 years and 3 months) to repay the loan after increasing her repayments to $3000 per month.
ii. To calculate the interest that Evelyne will save by increasing her repayments to $3000 per month, we need to first calculate the total interest that she would have paid if she had continued with her original repayment schedule. Using the formula for the future value of an annuity, we can calculate the total amount that Evelyne would have paid over 20 years:
\(FV=X*[\frac{(1+\frac{r}{12} )^{n-1} }{\frac{r}{12} } ]\)
where FV is the future value of the annuity (i.e., the total amount paid), X is the monthly payment, r is the monthly interest rate, and n is the number of months.
Substituting the given values, we get:
FV = $1,176.42 * \([\frac{(1 + 0.0054167)^{240}-1 }{0.0054167} ]\) = $842,064.88
Therefore, the total amount that Evelyne would have paid over 20 years is $842,064.88.
To calculate the interest that Evelyne will save by increasing her repayments to $3000 per month, we can subtract the total amount that she will pay with the increased repayments from the total amount that she would have paid with her original repayment schedule:
Interest saved = $842,064.88 - ($3000 * 63) = $642,064.
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what is the x-intercept of the line 5x-2y=10
a.5
b.0
c.2
d.-10
in a year group of 113 student 60 liked hockey 45 liked rugby and 18 liked neither. calculate the number of students who liked both rugby and hockey
Answer: 10
Step-by-step explanation:
Total number of students = 113
we require to find the number of students who like both hockey and rugby.
number of students who like game = total number of students - students who doesn't like either one
= 113 - 18 = 95 = A ∪ B
So equation become
A ∪ B = A + B - A ∩ B
95 = 60 + 45 - A ∩ B
A ∩ B = 105-95 = 10.
Kiran cuts out a square piece of paper with side length 6 inches. Mai cuts out a paper sector of a circle with radius 6 inches, and calculates the arc length to be inches. Whose paper is larger? Explain or show your reasoning.
A circle is a curve sketched out by a point moving in a plane. The area of the circular paper is more than the area of the square.
What is a circle?A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.
The arc length of radius 6 inches is equal to,
Length of the Arc of a quarter = 2πr×(1/4) = 2×π×6×0.25 =0.9448 inches
The area of the circular paper = πr² = π×6×6 = 113.097²
The area of the square with a side of 6 inches = 36 in²
Therefore, the area of the circular paper is more than the area of the square.
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Hello! Please help me solve this problem.
Make sure to show your work so I know your answer is correct and I could also give you points for it!
Answer:
96/120 = 4/5
4/5 × 425 = 340 students
The ratio of oxygen atoms to sulfur
atoms in sulfur dioxide is always the same.
The table shows the numbers of atoms
in different quantities of sulfur dioxide.
Complete the table. (Explore Activity 1)
The complete table is
Sulfur atoms 6 9 12 27
Oxygen atoms 12 18 24 54
What are Ratios:
A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other.
A ratio can be compared by the division of two numbers. For example, the ratio of a and b can be represented as a: b and read as a is to b. Here a: b can be written as a/b
Here we have
The ratio of oxygen atoms to sulfur atoms in sulfur dioxide is always the same. The table shows the number of atoms in different quantities of sulfur dioxide.
The given table is
Sulfur atoms 6 9 12 ___
Oxygen atoms 12 __ ___ 54
Let x, y, and z be the missing values in the table
Given that ratio of oxygen atoms to sulfur atoms in sulfur dioxide is always the same.
=> 12/6 = x/9 = y/12 = 54/z
Now the x, y, and z values can be calculated as follows
Take 12/6 = x/9
=> 2 = x/9
=> x = 18
Take 12/6 = y/12
=> 2 = y/12
=> y = 24
Take 12/6 = 54/z
=> 2 = 54/z
=> z = 54/2
=> z = 27
Therefore,
The complete table is
Sulfur atoms 6 9 12 27
Oxygen atoms 12 18 24 54
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The complete Question is given in the picture
Solve the simultaneous equation.
The value of a = -2 and b = 3.
What is a system of equations?
A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.
Here, we have
Given: 3a - 5b = -26, a + 2b = 6
We have to solve this equation.
3a - 5b = -26...(1)
a + 2b = 6...(2)
Now we multiply equation (1) by 2 and equation (2) by 5 and we get
6a - 10b = -52....(3)
5a + 10b = 30....(4)
After solving equations (3) and (4), we get
11a = -22
a = -2
Now we put the value of 'a' in equation(3) and we get
6(-2) - 10b = -52
-10b = -52 + 12
-10b = -30
b = 3
Hence, the value of a = -2 and b = 3.
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an eraser is 2 and a half inches long how long are 10 erasers placed end to end
We may infer after addressing the stated question that As a result, ten expressions erasers set end to end would measure 25 inches in length.
What is expression?You can add, subtract, divide, and multiply. This is how an expression is put together: Expression, number, and mathematical operator Numbers, variables, and operations (such as addition, subtraction, multiplication, and division, etc.) are all components of a mathematical expression. Expressions and phrases can be contrasted. Any mathematical statement with variables, integers, and an arithmetic operation between them is referred to as an expression or algebraic expression. For instance, the phrases 4m and 5 as well as the variable m from the given statement are all separated by the arithmetic symbol + in the phrase 4m + 5.
If an eraser is 2.5 inches long, then 10 erasers placed end to end equal:
25 inches = 10 erasers x 2.5 inches/eraser
As a result, ten erasers set end to end would measure 25 inches in length.
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Complete question:
Date Name Unit 4.7 LS² Day 3 Homework An Eraser Is 2(1)/(2) Inches Long. How Long Are 10 Erasers Placed End To End?
Will mark brainliest
question-
jack jogs and rides his bike for a total of 75 minutes every day. he rides his bike 15 minutes more than he jogs.
part a: write a pair of linear equations to show the relationship between the number of minutes jack jogs (x) and the number of minutes he rides his bike (y) every day.
part b: how much time does jack spend jogging every day?
part c: is it possible for jack to have spent 60 minutes riding his bike every day? explain your reasoning.
The answers have been shown below.
To find the answers:Questions regarding the time spent by Jack jogging and bike riding are needed to be answered.
(A) The equations are \(x+y=75, y=15+x\)
Time spent jogging is 30 minutes
The total time would be \(45+60=105\) minutes which is not equal to 75 minutes.
(B) Let \(x\) be the time spent jogging.
\(y\) be the time spent bike riding.
\(x+y=75\\y=15+x\\x+15+x=75\\2x+15=75\\x=\frac{75-15}{2} =30\)
Time spent jogging is 30 minutes.
\(y=60\\x+y=75\)
(C) If he rides his bike 15 minutes longer than he jogs then he would have to jog \(60-15 = 45\) minutes.
Therefore, the total time would be \(45+60=105\) minutes which is not equal to 75 minutes.
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pam is 17 years old and her sister is 9. her two brothers are 11 and 7 years old. what is the mean of their ages
Answer:
11
Step-by-step explanation:
17+9+11+7 divided by 4
because the mean= sum of the terms divided by the number of terms
the sum= 17+9+11+7=44
the number of terms= 4
44 divided by 4= 11
Answer:
(17+9+11+7) / 4 mean is an average
it is equal to the sum of the elements divided by the number of elements
the sum is 44
the number of elements is 4
the mean is the average= 44/4=11
Step-by-step explanation: i dont know why they would ask that
I need help with this. Plspslpsss help me
Step-by-step explanation:
1. k = 32
k + 19 = 51
32 + 19 = 51
51 = 51
correct, so, k=32 is a valid solution.
2. x = 43
16 = x - 27
16 = 43 - 27
16 = 16
correct, so, x = 43 is a valid solution.
3. m = 9
28 - m = 17
28 - 9 = 17
19 = 17
wrong. so, m = 9 is NOT a valid solution.
4. y = 8
y + 19 = 27
8 + 19 = 27
27 = 27
correct, so, y = 8 is a valid solution.
5. p = 22
19 = p + 3
19 = 22 + 3
19 = 25
wrong. so, p = 22 is NOT a valid solution.
6. r = 11
4 + r = 15
4 + 11 = 15
15 = 15
correct, so, r = 11 is a valid solution.
7.
a - 8 = 9 adding 8 to both sides
a = 17
8.
v + 13 = 15 subtracting 13 from both sides
v = 2
9.
16 = n - 24 adding 24 to both sides
40 = n or n = 40, of course
10.
c - 9 = 16 adding 9 to both sides
c = 25
11.
11 + k = 18 subtracting 11 from both sides
k = 7
12.
15 = w - 7 adding 7 to both sides
22 = w or w = 22, of course
Plss help me out!!!!!!
Answer:
its D because they all match the sides
(L2) A circle that contains a polygon so that it passes through each vertex of the polygon is a(n) _____ circle.
(L2) An inscribed circle is one that encompasses a polygon so that it passes by each of the polygon's vertices.
A circumcircle, not an inscribed circle, is a circle that encircles a polygon at each vertex. A circle that is enclosed within a polygon and intersects each side of the polygon exactly once is said to be inscribed. A circumcircle, on the other hand, is a circle that goes through every vertex of the polygon, with its center located at the point where the perpendicular bisectors of the polygon's sides converge. The greatest circle that can be drawn within a polygon is the circumcircle, while the largest circle that can be drawn inside a triangle is the inscribed circle.
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La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
Answer:
Falso.
Step-by-step explanation:
Sea \(d = \frac{a}{b}\) un número racional, donde \(a, b \in \mathbb{R}\) y \(b \neq 0\), su opuesto es un número real \(c = -\left(\frac{a}{b} \right)\). En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:
(a) El exponente es cero.
(b) El exponente es un negativo impar.
(c) El exponente es un negativo par.
(d) El exponente es un positivo impar.
(e) El exponente es un positivo par.
(a) El exponente es cero:
Toda potencia elevada a la cero es igual a uno. En consecuencia, \(c = d = 1\). La proposición es verdadera.
(b) El exponente es un negativo impar:
Considérese las siguientes expresiones:
\(d' = d^{-n}\) y \(c' = c^{-n}\)
Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:
\(d' = \left(\frac{a}{b} \right)^{-n}\) y \(c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}\)
\(d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}\) y \(c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}\)
\(d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}\)y \(c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}\)
\(d' = \left(\frac{b}{a} \right)^{n}\) y \(c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}\)
\(d' = \left(\frac{b}{a} \right)^{n}\) y \(c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}\)
\(d' = \left(\frac{b}{a} \right)^{n}\) y \(c' = \left[-\left(\frac{b}{a} \right)\right]^{n}\)
Si \(n\) es impar, entonces:
\(d' = \left(\frac{b}{a} \right)^{n}\) y \(c' = - \left(\frac{b}{a} \right)^{n}\)
Puesto que \(d' \neq c'\), la proposición es falsa.
(c) El exponente es un negativo par.
Si \(n\) es par, entonces:
\(d' = \left(\frac{b}{a} \right)^{n}\) y \(c' = \left(\frac{b}{a} \right)^{n}\)
Puesto que \(d' = c'\), la proposición es verdadera.
(d) El exponente es un positivo impar.
Considérese las siguientes expresiones:
\(d' = d^{n}\) y \(c' = c^{n}\)
\(d' = \left(\frac{a}{b}\right)^{n}\) y \(c' = \left[-\left(\frac{a}{b} \right)\right]^{n}\)
\(d' = \left(\frac{a}{b} \right)^{n}\) y \(c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}\)
\(d' = \left(\frac{a}{b} \right)^{n}\) y \(c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}\)
Si \(n\) es impar, entonces:
\(d' = \left(\frac{a}{b} \right)^{n}\) y \(c' = - \left(\frac{a}{b} \right)^{n}\)
(e) El exponente es un positivo par.
Considérese las siguientes expresiones:
\(d' = \left(\frac{a}{b} \right)^{n}\) y \(c' = \left(\frac{a}{b} \right)^{n}\)
Si \(n\) es par, entonces \(d' = c'\) y la proposición es verdadera.
Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.
If x and b are the roots of ax^2 - bx + c then calculate x + b
Answer:
Step-by-step explanation:
Wyatt does 29 push-ups in the morning and 36 more push-ups in the evening. If he does the same number of push-ups every day of the week for 4 weeks, about how many push-ups will he do in all?
Answer: 1,820 Pushups
Step-by-step explanation: 29+36=65
65 x 7 (days in a week)=455
455 x 4(as in the 4 weeks)=1,820 Pushups total
I hope this helped! let me know if you need more help! :)