HELP PLEASE!!!
Running at 3.0 m/s, Burce, the 50.0 kg quarterback, collides with Max, the 100.0 kg tackle, who is traveling at 6.0 m/s in the other direction. Upon collision, Max continues to travel forward at 2.0 m/s.If the collision between the players lasted for 0.04 s, determine the impact force on either during the collision

Answer:

Yes

Explanation:

Yes. The momentum is the same when the speed of the tennis ball is 18 times greater than the speed of the basketball and the velocities of both objects are in the same direction.

Answer:

Explanation:

F = GMm/d²

F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²

F = 5.5019685...x 10⁻¹⁰ N

round as appropriate, probably no more than 3 significant figures.

Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹

According to Newton's Second Law of Motion, the acceleration a of an object with mass m that experiences a net force F is:

Replace F=6.60*10^5N and m=1.30*10^7kg to find the acceleration of the train:

The time t that it takes for an object with acceleration a to reach a speed v starting from rest is:

Replace v=74.0km/h, a=5.077*10^-2m/s^2 and convert the speed to m/s to find the time that it takes for the train to reach that speed. Convert the final answer to minutes:

Therefore, the time that it takes for the train to reach a speed of 74.0km/h is approximately 6.75 min.

Answer:

In my physics class, something that helps connect better with kids is keeping connected with them always make sure to ask if they understand what you're teaching if they are following because sometimes most kids are to afraid to admit that they are lost, another way to connect with kids is maybe posting surveys to be able to check in with each student especially during this hard times :)

Explanation:

1. start with fun activities.

2. Encourage single-tasking.

3. Designate a learning playing field.

In fluid dynamics, the terms "lines of flow" and "streamlines" are used to describe the path followed by individual fluid particles as they move within a flow. While both terms are closely related, they have slightly different meanings.

Lines of flow refer to the imaginary lines that are drawn in a fluid flow field to represent the direction in which the fluid particles move. These lines can be fluid dynamics,as the path that a fluid particle would trace out over time. Lines of flow can provide information about the overall flow pattern and direction in a fluid system.

On the other hand, streamlines are the actual curves or lines that are tangent to the velocity vector at every point in the flow field.

These streamlines are defined as the locus of points through which a fluid particle passes at a given instant. Streamlines are a mathematical representation of the flow pattern and can be determined through computational fluid dynamics (CFD) or experimental methods.

In laminar flow, where the fluid flows smoothly in layers with minimal turbulence, the lines of flow and streamlines coincide with each other. This means that the lines of flow and streamlines are identical, and fluid particles move along these lines without crossing each other.

The streamlines do not intersect or cross paths in laminar flow, indicating that the flow is well-ordered and predictable.

In summary, lines of flow and streamlines both describe the path followed by fluid particles in a flow field, with the key difference being that lines of flow are conceptually drawn paths, while streamlines are the actual curves tangent to the velocity vector at each point. In laminar flow, the lines of flow and streamlines coincide, reflecting the organized and smooth nature of the flow.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

True

Explanation:

Answer:

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Explanation:

We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:

\(W\) - Weight of the airplane, measured in newtons.

\(F\) - Lift, measured in newtons.

\(\theta\) - Banking angle, measured in sexagesimal degrees.

The equations of equilibrium associated with the airplane are, respectively:

\(\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}\) (Eq. 1)

\(\Sigma F_{z} = F\cdot \cos \theta - W = 0\) (Eq. 2)

From (Eq. 2):

\(F = \frac{W}{\cos \theta}\)

In (Eq. 1):

\(W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}\)

By using the definition of weight, we eliminate the mass of the airplane:

\(g\cdot \tan \theta = \frac{v^{2}}{R}\)

Where:

\(g\) - Gravitational acceleration, measured in meters per square second.

\(v\) - Speed, measured in meters per second.

\(R\) - Radius of curvature, measured in meters.

Lastly, we clear the radius of curvature with the expression:

\(R = \frac{v^{2}}{g\cdot \tan \theta}\)

If we know that \(v = 250\,\frac{m}{s}\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(\theta = 15^{\circ}\), the radius of curvature is:

\(R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}\)

\(R = 23784.356\,m\)

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

The techniques that scientists can use to determine the characteristics of Earth's layers include:

Waves were used by scientists to study the layers of the Earth. This was done through the use of seismic waves. These are the waves that are generated by nuclear test explosions.

Also, another technique to determine the characteristics of Earth's layers is the use X-rays to obtain a view of Earth's interior layers.

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Answer:

study how seismic waves travel through different layers

use X-rays to obtain a view of Earth's interior layers

:)

Explanation:

The velocity of the bullet if the impact causes the block to swing 10cm above its initial level is 281m/s.

The law of conservation of momentum determines that the momentum of a system remains conserved after a collision. The initial momentum of a system of two bodies is equal to the final momentum of the system.

After collision, initial K.E. (Kinetic energy) of combined mass = 3 × 10 × 0.1 = 3J

1/2 × 3 × v² = 3

v = √2m/s

Conservation of momentum,

15 × v = 3000 × √2

v = 281m/s

Therefore, the velocity of the bullet is 281m/s.

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1) Berenice, Chadwick, and Edouard have poor vision (near-sightedness)

The near point, or the shortest distance at which an item can be seen well by a human eye, is 25cm.

The far point is the farthest distance at which an item may be viewed clearly with the bare eye.

Diverging lenses, which produce virtual pictures at the individual's far point when confronted with objects at infinity, can be used to treat nearsightedness.

2) Bernice and Edouard have a near point larger than 25cm and a far point less than infinity, resulting in nearsightedness and hyperopia.

Because of the reasons stated above, the folks listed will need bifocals to correct their vision.

Converging lenses, which produce virtual pictures at the patient's near point when shown with things at 25 cm, can cure farsightedness. To compensate for both farsightedness and nearsightedness, bifocals have both converging and diverging lenses.

3) The near point, or the shortest distance within which an item can be seen well by a human eye, is 25cm.

The far point is the farthest distance at which an item may be viewed clearly with the bare eye.

A hyperopic eye can see far away objects clearly, but its near point grows, thus it is higher than 25cm for that eye.

According to the table, Avishka and Francesca have farsightedness, hence their near point is more than 25cm, hence can be corrected using Converging lenses.

Nearsightedness often runs in families. Objects in the distance seem hazy. The illness can progress slowly or quickly. Treatment options include glasses, contact lenses, and LASIK surgery.

Nearsightedness is frequently caused by an eye that is excessively long or oval-shaped rather than spherical. It might also be caused by a too-steep corneal curvature. As a result of these alterations, light beams collide in front of the retina. The messages transferred from the retina to the brain are distorted.

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Answer:

2.25 N

Explanation:

The formula for mechanical advantage is:

\(Mechanical \ Advantage = \frac{F_o}{F_i}\)

\(F_o\) stands for output force and \(F_i\) stands for input force.

We can plug in the given forces into the equation:

\(Mechanical \ Advantage = \frac{450\ N}{200\ N}=2.25 \ N\)

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer:

E. None of the above

Answer:

An object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Forces are "pushes" or "pulls" on the object, and forces, like velocity and acceleration are vector quantities.

Answer:

It bends.

Explanation:

Water is denser than water. This causes light that is passing from air to water to appear to bend towards the normal line near the water's surface.

Answer:

Option A. 39.2 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 4 s

Final velocity (v) =?

v = u + gt

Since the initial velocity (u) is 0, the above equation becomes:

v = gt

Thus, inputting the value of g and t, we can obtain the value of v as shown below:

v = 9.8 × 4

v = 39.2 m/s

Therefore, the velocity of the ball at 4 s is 39.2 m/s.

Answer:

19.6 m/s

Explanation:

I took the quiz and got it right!

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

(a) The minimum force required to get the block moving can be calculated using the formula F = μ * m * g, where μ is the coefficient of static friction, m is the mass of the block, and g is the acceleration due to gravity. Plugging in the values given in the problem, we get F = 0.1 * 59.0 kg * 9.8 m/s² = 57.9 N. So the minimum force required to get the block moving is 57.9 N.

(b) Once the block starts to move, its acceleration can be calculated using the formula a = (F - f_k) / m, where F is the applied force, f_k is the force of kinetic friction, and m is the mass of the block. The force of kinetic friction can be calculated using the formula f_k = μ_k * m * g, where μ_k is the coefficient of kinetic friction. Plugging in the values given in the problem, we get f_k = 0.03 * 59.0 kg * 9.8 m/s² = 17.4 N. So if the applied force of 57.9 N is maintained, then the acceleration of the block would be a = (57.9 N - 17.4 N) / 59.0 kg = 0.69 m/s².

(a) The minimum force required to get the block moving can be calculated using the formula F = μ * m * g, where μ is the coefficient of static friction, m is the mass of the block, and g is the acceleration due to gravity. Plugging in the values given in the problem, we get F = 0.1 * 59.0 kg * 9.8 m/s² = 57.9 N. So the minimum force required to get the block moving is 57.9 N.

(b) Once the block starts to move, its acceleration can be calculated using the formula a = (F - f_k) / m, where F is the applied force, f_k is the force of kinetic friction, and m is the mass of the block. The force of kinetic friction can be calculated using the formula f_k = μ_k * m * g, where μ_k is the coefficient of kinetic friction. Plugging in the values given in the problem, we get f_k = 0.03 * 59.0 kg * 9.8 m/s² = 17.4 N. So if the applied force of 57.9 N is maintained, then the acceleration of the block would be a = (57.9 N - 17.4 N) / 59.0 kg = 0.69 m/s².

Answer:

d

Explanation:

because when an object stand in front of light, light bends around the other and doesn't go through it

The value of the spring constant is 8704 N/m.

The spring constant (k) can be found using Hooke's law, which states that the force required to stretch or compress a spring is proportional to the distance it is stretched or compressed.

Mathematically, it can be expressed as:

F = -kx

where F is the force applied to the spring,

k is the spring constant, and

x is the distance the spring is stretched or compressed.

Since the force applied to the spring is equal to the weight of the book, we can write:

F = mg = -kx

where m is the mass of the book and

g is the acceleration due to gravity.

Substituting the given values, we get:

560 g * 9.8 m/s^2 = -k * 0.25 m

Dividing both sides by -0.25 m and solving for k,

we will get it as:

k = (560 g * 9.8 m/s^2) / 0.25 m

k= 8704 N/m

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Answer:

C

Explanation:

if you plug the coordinates to each line, you'll see which one best fits the answer to your question.

u = 5.83

Explanation:

The magnitude of a vector \(\vec{u}\) is

\(|\vec{u}| = \sqrt{u_z^2 + u_y^2} = \sqrt{(-5)^2 + (3)^2}\)

\(\:\:\:\:\:\:\:= \sqrt{34} = 5.83\)

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Angle of 5.61° should  be banked so that car running at 50 Km/hr be safe to go round the circular turn of 200 m radius.

The process of raising outer edge of the road over its inner edge through certain angle θ is called as banking of road. Banking of road is nothing but the process of making the angle between the surface of road to horizontal surface of the road. The angle made by this two surfaces is called as angle of banking. Banking of road is done for safe turn at high speed.

Angle of banking is given by the formula,

tanθ = v²÷Rg

Where θ = angle of banking

           R = Radius of circular turn

           g = acceleration due to gravity

Given,

velocity of the car v = 50km/hr = 13.88 m/s

Radius of the circular orbit = 200 m

From formula,

tanθ = 13.88² ÷ (200×9.8)

tanθ = 0.09829

θ = tan⁻¹(0.09829)

θ = 5.61°

Hence angle must be backed at 5.61° to have safe turn.

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Answer:

match what lol ?

Answer: Match what?

I love your profile pic.

Explanation:

It will decrease the capacitance. this effect will be produced on a capacitor if the separation between the plates is increased. Hence option D is correct.

The capacity of a capacitor to store electric charge is determined by its capacitance. It is inversely proportional to the gap or distance between the capacitor plates and directly proportional to the area of the capacitor plates.

The capacitance of a capacitor reduces when the distance between the plates is increased. Because of the weaker electric field and decreased capacity to store charge caused by the increased gap between the plates, this happens. The capacitor's capacitance therefore drops.

As stated in option D, a capacitor's capacitance will decrease as the distance between its plates increases.

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Answer:

-2

Explanation: