9514 1404 393
Answer:
(-∞, -4) ∪ [-2, ∞)
Step-by-step explanation:
The solution to the first inequality is ...
-9x +3 > 39
-9x > 36 . . . . . subtract 3 from both sides
x < -4 . . . . . . . divide both sides by -9; reverse > to < because -9 is negative
__
The solution to the second inequality is ...
-5x +6 ≤ 16
-5x ≤ 10 . . . . . . . subtract 6 from both sides
x ≥ -2 . . . . . . divide both sides by -2; reverse ≤ to ≥ because -2 is negative
__
These solution sets are disjoint. The solution of the OR of these inequalities is the union of the solution sets. The graph is shown below. In interval notation, it is described by ...
(-∞, -4) ∪ [-2, ∞)
The -2 has a square bracket because it is included in the set. The curved bracket at -4 indicates it is not included.
-x=5 what the answer
Answer:
x= -5
explanation:
-x=5
-x-5=0
-5=x
Need help question #1. Show steps please
Answer:
C
Step-by-step explanation:
We want to integrate:
\(\displaystyle \int\frac{4x^4+3}{4x^5+15x+2}\,dx\)
Notice that the expression in the denominator is quite similar to the expression in the numerator. So, we can try performing u-substitution. Let u be the function in the denominator. So:
\(u=4x^5+15x+2\)
By differentiating both sides with respect to x:
\(\displaystyle \frac{du}{dx}=20x^4+15\)
We can "multiply" both sides by dx:
\(du=20x^4+15\,dx\)
And divide both sides by 5:
\(\displaystyle \frac{1}{5}\, du=4x^4+3\,dx\)
Rewriting our original integral yields:
\(\displaystyle \int \frac{1}{4x^5+15x+2}(4x^4+3\, dx)\)
Substitute:
\(\displaystyle =\int \frac{1}{u}\Big(\frac{1}{5} \, du\Big)\)
Simplify:
\(\displaystyle =\frac{1}{5}\int \frac{1}{u}\, du\)
This is a common integral:
\(\displaystyle =\frac{1}{5}\ln|u|\)
Back-substitute. Of course, we need the constant of integration:
\(\displaystyle =\frac{1}{5}\ln|4x^5+15x+2|+C\)
Our answer is C.
PLESSS SOMEONE KNOW THIS
Answer:
D.
Step-by-step explanation:
Order of operation states that in order for the addition to be done first, it must be in a set of parenthesis. Then, 4 multiplied by the sum would mean the addition has to be done first. so, yeah.
Don't know if that helps. I hope it does. Have a great day
What is an equation of the line that passes through the point (1,-7)(1,−7) and is parallel to the line 3x+y=33x+y=3?
Explanation:
Anything parallel to Ax+By = C is of the form Ax+By = D, where C and D are different values.
The given equation is 3x+y = 3. Anything parallel to this is 3x+y = D
Plug (x,y) = (1,-7) into that second equation to compute D
3x+y = D
D = 3x+y
D = 3(1)+(-7)
D = 3-7
D = -4
Therefore, our answer is 3x+y = -4
If you wanted to solve for y, then you'd get y = -3x-4. Both parallel lines have a slope of -3 but different y intercepts.
2³(3÷4+x)+12=2 iuybki[ojiouhnkluibkjb
Answer:
what?
Step-by-step explanation:
hansnskekkwkwnw
Answer:
X=-2
Step-by-step explanation:
1. Open up the brackets
You then get
6+8x+12=2
2. Send the whole numbers to the other sides
8x= 2-6-12
8x = - 16
3. Divide both sides by 8 to leave x alone
X=-2
What is 45018 times 5248
Answer:
236,254,464
Hope you got it
Question provided in attachment.
We can be 99% confident that the true mean healing rate of newts falls within the interval of 22.919 to 30.415 micrometers per hour.
How to calculate the valueSample Mean: = (29 + 27 + 34 + 40 + 22 + 28 + 14 + 35 + 26 + 35 + 12 + 30 + 23 + 18 + 11 + 22 + 23 + 33) / 18
= 480 / 18
≈ 26.667
Sample Standard Deviation (s):
= ✓((Σ(29 - 26.667)² + (27 - 26.667)² + ... + (33 - 26.667)²) / (18 - 1))
≈ ✓(319.778 / 17)
≈ ✓(18.81)
≈ 4.336
Confidence level = 99%
Sample Size (n) = 18
Sample Mean = 26.667
Sample Standard Deviation (s) = 4.336
Degrees of Freedom (df) = n - 1 = 18 - 1 = 17
Using a t-table or statistical software, we find that the critical value for a 99% confidence level with 17 degrees of freedom is approximately 2.898.
Margin of Error (E) = 2.898 * (4.336 / ✓18))
≈ 3.748
Confidence Interval = (26.667 - 3.748, 26.667 + 3.748)
= (22.919, 30.415)
We can be 99% confident that the true mean healing rate of newts falls within the interval of 22.919 to 30.415 micrometers per hour. This means that if we were to repeat the study multiple times and construct confidence intervals, approximately 99% of those intervals would contain the true mean healing rate of the population.
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Imagine you were a dairy products processor planning for production in 2001. Describe how you would allocate the milk you buy, in terms of bottling whole milk and 0–1% fat milk.
With the full question now given (see attached image), I would allocate equal resources to Whole Milk and 0-1% fat milk. This exercise is about the Allocation of Resources in a free economy with the help of market trends. See further explanation below.
What is the Allocation of Resources?The allocation of available resources to diverse purposes is referred to as resource allocation in economics. In the framework of a whole economy, resources can be distributed through a variety of mechanisms, including markets and planning.
Note that in the attached graph, the demand for Whole Milk has been falling while the demand for 0-1% fat is dropping. While the reasons for this trend is beyond the scope of this exercise, suffice it to say that it is reasonably expected that the consumption data in 2001 will most likely be equal to each other.
1980 to 1985 the movement in 0-1% fat milk was negligible but it shot up the next 5 year period.
It is logical to expect that this pattern will reoccur since the demeand has been stable for the last 10 years (hence a reoccurring pattern).
On the other hand, every 5 years, the demand (consumption) for Whole Milk has consistently dropped. Hence the reason for the decision.
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write a rule for the nth term of the arithmetic sequence a8=-15 a17=-78
Answer:
Find the 40th term for the arithmetic sequence in which
a8=60 and a12=48 .
Substitute 60 for a8 and 48 for a12 in the formula
an=a1+(n−1)d to obtain a system of linear equations in terms of a1 and d .
a8=a1+(8−1)d→60=a1+7da12=a1+(12−1)d→48=a1+11d
Subtract the second equation from the first equation and solve for d .
12=−4d−3=d
Then 60=a1+7(−3) . Solve for a .
60=a1−2181=a1
Now use the formula to find a40 .
a40=81+39(−3)=81−117=−36 .
Step-by-step explanation:
The rule for the nth term of the given arithmetic sequence is given by aₙ = 41-7n
What is arithmetic sequence?An arithmetic sequence is a list of numbers with a definite pattern.
Given is the 8th and 17th term of an arithmetic sequence, which are -15 and -78
We know that, nth term of an arithmetic sequence, is given by =
aₙ = a₁ + (n-1)d
Where n is the number of terms and d is the common difference,
Therefore,
a₈ = a₁ + (8-1)d
-15 = a₁+7d
a₁ = -7d-15...(i)
a₁₇ = a₁ + (17-1)d
-78 = a₁+16d
a₁ = -78-16d...(ii)
Solving equations 1 and 2,
-78-16d = -7d-15
9d = -63
d = -7
a₁ = = -78-16(-7)
a₁ = 34
Therefore, nth term =
aₙ = a₁ + (n-1)d
aₙ = 34+(n-1)(-7)
aₙ = 34-7n+7
aₙ = 41-7n
Hence, the rule for the nth term of the given arithmetic sequence is given by aₙ = 41-7n
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Need help haven’t been able to get this question right for while
Explanation
Absolute value basically measures how far the number is from zero,for example
\(\lvert x\rvert\)as we can see
\(\lvert x\rvert=\lvert-x\rvert\)hence,
Step 1
\(\lvert x\rvert=0\)so, we need to find a number such the distance from zero to that number be zero,
therefore , that number is zero
hence
\(\begin{gathered} x_1=0 \\ x_2=0 \end{gathered}\)Step 2
\(\lvert x\rvert=2\)now, weed to find a value such distance from zero is 2, so those values are +2 and -2
\(\begin{gathered} x_1=2 \\ x_2=-2 \end{gathered}\)Step 3
c)
\(\lvert x\rvert=-6\)the solution of a absolute value function is always positive, remeber we are talking about a distance, so, there is not solutioni
\(\begin{gathered} c) \\ x_1=DNE \\ x_2=\text{DNE} \end{gathered}\)I hope this helps you
What is the meaning of "\( \varphi (x,y)\) be \( y\wedge \phi (x)\) "?
The given passage provides a proof that the Separation Axioms follow from the Replacement Schema.
The proof involves introducing a set F and showing that {a: e X : O(x)} is equal to F (X) for every X. Therefore, the conclusion is that the Separation Axioms can be derived from the Replacement Schema.In the given passage, the author presents a proof that demonstrates a relationship between the Separation Axioms and the Replacement Schema.
The proof involves the introduction of a set F and establishes that the set {a: e X : O(x)} is equivalent to F (X) for any given set X. This implies that the conditions of the Separation Axioms can be satisfied by applying the Replacement Schema. Essentially, the author is showing that the Replacement Schema can be used to derive or prove the Separation Axioms. By providing this proof, the passage establishes a connection between these two concepts in set theory.
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HELP PLEASEEEEEEE
15 - 4x = 2(3x + 1)
Answer:
x = 1.3
Step-by-step explanation:
15 - 4x = 2(3x + 1)
15 - 4x = 6x + 2
-2 -2
--------------------------
13 - 4x = 6x
+4x +4x
--------------------------
13 = 10x
/10 /10
---------------------------
1.3 = x
Answer:
13/10
Step-by-step explanation:
Hope this helps!!!
1) Convert 2-7i to trigonometric form
2) Use the n-th roots theorem to find the requested roots of the given complex number.
Find the cube roots of 125
Answer:
1) \(\sqrt{53}(\cos286^\circ+i\sin286^\circ)\)
2) \(\displaystyle 5,-\frac{5}{2}+\frac{5\sqrt{3}}{2}i,-\frac{5}{2}-\frac{5\sqrt{3}}{2}i\)
Step-by-step explanation:
Problem 1
\(z=2-7i\\\\r=\sqrt{a^2+b^2}=\sqrt{2^2+(-7)^2}=\sqrt{4+49}=\sqrt{53}\\\\\theta=\tan^{-1}(\frac{y}{x})=\tan^{-1}(\frac{-7}{2})\approx-74^\circ=360^\circ-74^\circ=286^\circ\\\\z=r\,(\cos\theta+i\sin\theta)=\sqrt{53}(\cos286^\circ+i\sin 286^\circ)\)
Problem 2
\(\displaystyle z^\frac{1}{n}=r^\frac{1}{n}\biggr[\text{cis}\biggr(\frac{\theta+2k\pi}{n}\biggr)\biggr]\,\,\,\,\,\,\,k=0,1,2,3,\,...\,,n-1\\\\z^\frac{1}{3}=125^\frac{1}{3}\biggr[\text{cis}\biggr(\frac{0+2(2)\pi}{3}\biggr)\biggr]=5\,\text{cis}\biggr(\frac{4\pi}{3}\biggr)=5\biggr(-\frac{1}{2}-\frac{\sqrt{3}}{2}i\biggr)=-\frac{5}{2}-\frac{5\sqrt{3}}{2}i\)
\(\displaystyle z^\frac{1}{3}=125^\frac{1}{3}\biggr[\text{cis}\biggr(\frac{0+2(1)\pi}{3}\biggr)\biggr]=5\,\text{cis}\biggr(\frac{2\pi}{3}\biggr)=5\biggr(-\frac{1}{2}+\frac{\sqrt{3}}{2}i\biggr)=-\frac{5}{2}+\frac{5\sqrt{3}}{2}i\)
\(\displaystyle z^\frac{1}{3}=125^\frac{1}{3}\biggr[\text{cis}\biggr(\frac{0+2(0)\pi}{3}\biggr)\biggr]=5\,\text{cis}(0)=5(1+0i)=5\)
Note that \(\text{cis}\,\theta=\cos\theta+i\sin\theta\) and \(125=125(\cos0^\circ+i\sin0^\circ)\)
If you are surveying people about whether they like to swim, where are you more likely to get a random sample?
A) at a local supermarket
B) at a local beach
C) at a swimsuit store
D) outside a local swimming pool
Answer:
B) a local beach.
At a local beach, you might find quiet a few different perspective from people who like or don't like swimming, whether going to a swimsuit store, you most likely will find people buying the swimsuit because they enjoy it, and plan on swimming in it.
Step-by-step explanation:
Hope it helps! =D
In a field of wildflowers, the number of flowers is decaying exponentially. One year there are 1,200 flowers, and the next year there are 900 flowers.
The percent of decrease is 33 25 30 20 and the decay factor is 0.75 1.25 0.67 0.70
Find the amount of decay:
1200 - 900 = 300
Divide amount of decay by original amount:
300/1200 = 0.25
The percent of decay is 25 %
The decay factor is 1.00 a 0.25 = 0.75
Find inverse of the following f(x)=x^3+9
as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.
\(\stackrel{f(x)}{y}~~ = ~~x^3+9\hspace{5em}\stackrel{\textit{quick switcheroo}}{x~~ = ~~y^3+9} \\\\\\ x-9=y^3\implies \sqrt[3]{x-9}=y=f^{-1}(x)\)
PLEASE HELP!!!!! 30 POINTS
Answer: C (3)
Step-by-step explanation:
The digit in the hundredths place of 8.731 is 3. This is because the hundredths place is the third decimal place from the right, and it holds the value of 0.03. Therefore, the digit in the hundredths place is 3.
Find the resistance in a 1238 watt circuit with 120 volt electricity passing through it.
The resistance in the circuit is 11.63 ohms
What is resistance?Resistance is the opposite of the flow of current. It can also be defined as the ratio of square of voltage to the power of a circuit. It is measured in ohms.
The factors that affects the resistance of a conductor are;
1. temperature
2. length of the wire
3. Area of the wire
4. Nature of the wire
power = V²/R
R = V²/P
P = 1238 W
v = 120
R = 120²/1238
R = 14400/1238
R = 11.63 ohms
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Do these pairs of values (x and y) represent twoquantities that are proportional?x y253 661510 20A. No, because not all of the pairs represent the same ratio.B. No, because the y-values are not increasing at aconstant rate.C. Yes, because the ratios and are equal.O D. Yes, because the ratios are all positive.SUBMIT
Given:
Required:
We need to find that these are in proportional
Explanation:
\(\begin{gathered} \frac{2}{5} \\ \\ \frac{3}{6}=\frac{1}{2} \\ \\ \frac{6}{15}=\frac{2}{5} \\ \\ \frac{10}{20}=\frac{1}{2} \end{gathered}\)
Final answer:
No, because not all the pairs are in the same ratio
A triangle has an angle that measures 68º.
Which of these can be the measures of the
other two angles?
A. 112° and 90°
B. 84° and 42°
C. 54° and 58°
D. 28° and 152°
Answer: B
Step-by-step explanation:
Dont trust me
Classify the polynomial by degree and by number of terms. 4x^3 The polynomial is ______ _______
Given
Polynomial =
\(4x^3\)Find
Classify the polynomial by degree and by nymber of terms
Explanation
By Degree
It is cubic polynomial because the expression is of degree three.
By number of terms
It has only one term so it is monomial.
Final Answer
By degree = Cubic
By number of terms = Monomial
A medium soft serve costs $0.56 per ounce.
If a medium is 6.5 ounces, how much does it cost?
Help quick
Using the unitary method, we found out that the cost of 6.5 ounces of a medium soft serve is $3.64.
What is meant by the unitary method?
The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, and then multiplying that value to determine the required value. This method allows us to calculate both the value of many units from the value of one unit and the value of one unit from the value of many units. In the unitary technique, the value of a unit or one quantity is always counted first, and the values of additional or fewer quantities are then determined. This method is known as the unitary method for this reason.
Given,
The cost of an ounce of medium soft serve = $0.56
The amount of soft serve in a medium size = 6.5 ounces
We are asked to find the cost of the total amount of soft serve in a medium size.
This can be done using the unitary method.
If 1 ounce = $0.56
Then for 6.5 ounces, the cost is = 6.5 * 0.56 = $3.64
Therefore using the unitary method, we found out that the cost of 6.5 ounces of a medium soft serve is $3.64.
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At the supermarket you can fill your own honey bear container. A customer buys 12 oz of honey for $5.40.
How much honey can you buy per dollar?\
Solve the following equation
3x²+x-12
= 1
b
Od
x=-12 x=11
x=4 x=-3
x=12 x=-1
x=3 x=-4
The solution to the equation 3x² + x - 12 = 1 is x = -1/4; and x = 4
What is an equation?An equation is an expression that shows the relationship between numbers and variables using mathematical operators.
The polynomial is classified based on degree as linear, quadratic, cubic and so on.
Given the equation:
3x² + x - 12 = 1
subtracting 1 from both sides:
3x² - 11x - 4 = 0
3x² - 12x + x - 4 = 0
3x(x - 4) + 1(x - 4) = 0
(3x + 1)(x - 4) = 0
3x + 1 = 0; and x - 4 = 0
x = -1/4; and x = 4
The solution to the equation is x = -1/4; and x = 4
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A ladder leans against the side of a house. The angle of elevation of the ladder is 61°, and the top of the ladder is 14 ftabove the ground. Find the distance from the bottom of the ladder to the side of the house. Round your answer to thenearest tenth.
A ladder leans against the side of a house. The angle of elevation of the ladder is 61°, and the top of the ladder is 14 ft above the ground.
In the above diagram, AB is the ladder and AC is the house.
\(\begin{gathered} \angle\text{ABC}=61^o \\ AC=14\text{ ft} \end{gathered}\)In th etriangle ABC,
\(\begin{gathered} \frac{AC}{BC}=\tan 61 \\ \frac{14}{BC}=\tan 61 \\ BC=\frac{14}{\tan 61} \\ =7.76 \end{gathered}\)So, the distance from the bottom of the ladder to the side of the house is approximately 7.76 ft
Find the slope of each of the following functions at the given points. f(x)=x²; (-3,9)
Answer:
the eqn given by the function is y=9---(1)
given point is(-3,9)=(X,y)
we know,
y=mx
mx=9 [from 1]
or,m(-3)=9 [from point]
or,m=9/-3
:.m=-3
hence, slope=-3
ANSWER ALL WITH THE NUMBER LABELED:))
The length of the arc intercepted by a central angle of 5 radians in a circle of radius
73 is
The length of the arc intercepted by a central angle of 86" in a circle of radius 15 is
Answer:
The length of the arc intercepted by a central angle of 3 radians in a circle of radius 76 is 228 and the length of the arc intercepted by a central angle of 2 radians in a circle of radius 15 is 30.
Explain:
The following formula determines the length of an arc that a circle's central angle intercepts:
Arc length is equal to (central angle / 2) 2r r r
where r denotes the circle's radius. We can determine the length of the two arcs using the following formula:
For the first circle, with a radius of 76 and a center angle of 3 radians:
Arc length = 3 x 76 = 228
Therefore, in a circle with a radius of 76, the length of the arc that is intercepted by a central angle of 3 radians is 228.
For the second circle, whose radius is 15, and whose center angle is 2 radians:
Arc length = 2 x 15 = 30
As a result, the length of the arc in a circle with a radius of 15 is 30 when it is intercepted by a central angle of 2 radians.
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Please help!
i do not understand my homework!
Answer:
I believe the answer is A.
Answer:
the answer is D I believe
For what values of theta do maximum r-values occur on the graph the polar equation r = 2 cos4 theta? Note that the maximum r-value occurs at a point that is the maximum distance from the pole
Answer:r=2 cos^4(theta)
Step-by-step explanation:To find the values of theta where the maximum r-values occur on the graph of the polar equation r = 2 cos^4(theta), we need to find where the derivative of r with respect to theta is equal to zero, since the maximum r-values occur at these points.
First, we can simplify the equation by using the identity cos(2theta) = 2cos^2(theta) - 1 and substituting cos^2(theta) = (1 + cos(2theta))/2. This gives:
r = 2 cos^4(theta) = 2(1/2 + 1/2 cos(2theta))^2 = 1 + cos(2theta) + cos^2(2theta)/2.
Next, we can take the derivative of r with respect to theta, using the chain rule:
dr/dtheta = -sin(2theta) - 2cos(2theta)sin(2theta).
Setting this equal to zero and factoring out sin(2theta), we get:
sin(2theta)(-1 - 2cos(2theta)) = 0.
This equation is satisfied when sin(2theta) = 0 or cos(2theta) = -1/2.
When sin(2theta) = 0, we have 2theta = k*pi for some integer k. Therefore, theta = k*pi/2.
When cos(2theta) = -1/2, we have 2theta = 2*pi/3 + 2*k*pi or 2theta = 4*pi/3 + 2*k*pi for some integer k. Therefore, theta = pi/3 + k*pi or theta = 2*pi/3 + k*pi.
These are the values of theta where the maximum r-values occur on the graph of the polar equation r = 2 cos^4(theta).