Help please 20 points

Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.

Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.

First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.

Next, we can find the vertex using the formula:

Vertex = (-b/2a, f(-b/2a))

where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:

Vertex = (-b/2a, f(-b/2a))

= (-6/(2*-1), f(6/(2*-1)))

= (3, -14)

So the vertex of the parabola is at the point (3,-14).

Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.

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The expression is equal to in the given sentence 1/3x + 3/4 + 2/3x - 1/4 - 2/3x is 1/3x + 1/2

You must change a number by each variable and carry out the arithmetic operations in order to evaluate an algebraic statement. Since 6 + 6 equals 12, the variable x in the situation above is equal to 6. If we are aware of the values of our elements, we may substitute those values for the original variables before evaluating the expression.

An term that is equal to: must be found.

1/3x + 3/4 + 2/3x - 1/4 - 2/3x

Let's continue to solve it as follows:

If we separate similar phrases, we obtain,

1/3x + 2/3x - 2/3x + 3/4 - 1/4

Further calculation yields, thus,

1/3x + 1/2

Consequently, the phrase has the same meaning as

1/3x + 3/4 + 2/3x - 1/4 - 2/3x is 1/3x + 1/2

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Answer:

7/4a + 1/3

1 3/4a + 1/3

Hope this helped

Answer:

4 5/6 = n

Step-by-step explanation:

5 1/2 = n+ 2/3

Subtract 2/3 from each side

5 1/2 - 2/3 = n+ 2/3 -2/3

5 1/2 - 2/3 = n

Get a common denominator of 6

5 1/2 * 3/3 = 5 3/6

2/3 = 2/3 * 2/2 = 4/6

5 3/6 - 4/6 = n

We need to borrow 1 from the 5 in the form of 6/6

5 3/6 = 4 6/6+ 3/6 = 4 9/6

4 9/6 - 4/6 =n

4 5/6 = n

Answer:

-8, 13

-3, 8

6, -1

10, - 5

Step-by-step explanation:

Point A is located at (4, 4) in the coordinate plane.With these dimensions, we can determine that Point A is located at (4, 4) in the coordinate plane.

To find the coordinates of point A, we need to consider the properties of the shaded region. The shaded region consists of a rectangle and a triangle. We know that the area of the shaded region is 120 square units, and the height of the line segment above the horizontal axis is 4 units.

The rectangle's area is given by its length multiplied by its width. Since the height of the rectangle is 4 units, we can deduce that the length of the rectangle is also 4 units. Therefore, the width of the rectangle can be found by dividing the total area of the shaded region by the length of the rectangle.

Subtracting the width of the rectangle from the total width of the shaded region will give us the base of the triangle. Since the triangle is isosceles, the base length is equal to the height of the rectangle.

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       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Jo's sum is easy   = (100)(101)/2  =  50 * 101   =  5050

Given,

In the question:

Jo adds up all the positive integers from 1 to 100. Kate does a similar thing with the first 100 positive integers.

She first rounds every integer to its nearest multiple of 10 (rounding 5s up) and then adds the 100 values.

To find the what is the positive difference between jo's sum and Kate's sum?

Now, According to the question:

Kate  would first start with 5  [ since 1 - 4 ]  are rounded to 0

Starting with 5 thru 14  she will have ten 10s

15 - 24   she will have  ten 20s

25 - 34 she will have  ten 30s

.

.

.

.

.

85 - 94 she will have ten 90s

95 - 100   she will have six 100s

So.....her sum is

10  [10  + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90]  + 6 [100]

10  [ (10) (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9) ] + 6[100]  

10 (10)  [  sum of the first nine positive integers ] + 6 [ 100]

100  [  (9)(10) / 2 ]  + 6[100]  

100 [ 45]  + 6[100]

100 [ 45 + 6 ]  

100 [ 51 ]

5100

Hence, The positive difference is 5100 - 5050  =  50

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There are 840 ways to six letters of ALGORITHM be written in a row with first two letters OR.

Given in the question:

The word ALGORITHM has 9 letters. We want them to be written in a row, which means, order of the letters are important, so, we will use Permutation.

Formula for Permutation:

P(n,r) = n!/(n-r)!

we will use 7 letters out of 9 letters and 4 letters

n= 7 and r = 4

Now, we will put values in the formula:

P(7,4) = 7! / (7-4)!

P(7,4) = 7! / 3!

P(7,4) = 7 × 6 × 5 × 4

= 840.

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For all the n ≥ 5 conditions, the condition satisfies that an nth root is always a whole number.

The question states that;

Only rarely do you see the fourth or fifth root when studying roots; most of the time, you only see square and cube roots. It can be intriguing to think of additional root systems, though. to think about additional root systems.

Here, we have;

' n ' is a whole number.

' n ' is greater than five.

∴ n = n - 5

∴ The nth root of the above number is \(\sqrt[n]{n-5}\)

Here, n ∈ R where n ≥ 5

Let n = 5;

      ⇒ \(\sqrt[5]{5-5}\) = 0 ( whole number )

Let n = 6;

      ⇒ \(\sqrt[6]{6-5}\) = 1 ( Whole number )

Similarly, so on for all the n ≥ 5 conditions, the above condition satisfies.

Hence, for all the n ≥ 5 conditions, the condition satisfies that an nth root is always a whole number.

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Answer: Peter must invest $15,971.06 today to achieve his goal.

Explanation: We are given that Peter intends to retire in 4 years and he would like to receive $130 every month for 18 years. The first payment is to be received a month after his retirement. We need to determine how much he must invest today to achieve his goal. The present value of an annuity can be calculated by the following formula: PV = A * [(1 - (1 / (1+r)^n)) / r]where,  PV = present value of the annuity A = amount of the annuity payment r = interest rate per period n = number of periods For this problem, the amount of the annuity payment (A) is $130, the interest rate per period (r) is 3.8% p.a. compounded monthly, and the number of periods (n) is 18 years * 12 months/year = 216 months. The number of periods should be the same as the compounding frequency in order to use this formula. So, PV = $130 * [(1 - (1 / (1+0.038/12)^216)) / (0.038/12)] = $15,971.06. Therefore, Peter must invest $15,971.06 today to achieve his goal.

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The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated for different data sets, as specified in the given values.

The UCL and LCL are statistical control limits used in process control to determine if a process is in a stable and predictable state. These limits define the range within which data points should fall if the process is under control.

In each case provided (A, B, C, D, E), the UCL and LCL values are given. These values represent the calculated control limits for the respective data sets.

To calculate the control limits, a specific statistical method such as the ± 3σ (sigma) method may have been used. This method sets the UCL and LCL at three standard deviations above and below the mean.

The UCL represents the upper threshold or upper boundary, while the LCL represents the lower threshold or lower boundary. These limits help identify any potential deviations or out-of-control situations in the data.

By applying the given values, the corresponding UCL and LCL for each data set can be calculated. These limits are important for quality control and process monitoring, ensuring that the data falls within acceptable ranges.

To calculate the UCL and LCL using ±3σ limits, we use the following formulas:

UCL = Mean + 3σ
LCL = Mean - 3σ

Here, σ represents the standard deviation of the data set. The ±3σ limits provide a range that encompasses most of the data points in a normal distribution, with approximately 99.7% of the data falling within this range.
A) For data set A:
UCL = 7.437
LCL = -2.237

B) For data set B:
UCL = 7.82
LCL = 0

C) For data set C:
UCL = 8.382
LCL = 0

D) For data set D:
UCL = 7.82
LCL = -2.22

E) For data set E:
UCL = 9.112
LCL = 0

The ±3σ limits are derived from the standard deviation (σ) of the data set. Unfortunately, the standard deviation is not provided in the given information. If you have the standard deviation available, we can proceed to calculate the UCL and LCL using the formulas UCL = Mean + 3σ and LCL = Mean - 3σ.

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Question - What are the upper control limit (UCL) and lower control limit (LCL) using a ±3σ limit for the given data sets?

A) For data set A, the UCL is 7.437 and the LCL is -2.237.
B) For data set B, the UCL is 7.82 and the LCL is 0.
C) For data set C, the UCL is 8.382 and the LCL is 0.
D) For data set D, the UCL is 7.82 and the LCL is -2.22.
E) For data set E, the UCL is 9.112 and the LCL is 0.

Answer:

11 out of 22 marbles

Step-by-step explanation:

Just add up the red and green marbles to get the top # and then add up all the colored marbles to get the bottom #.

Hope this helps :) Please give brainliest!

Answer:

×=-7,×=-3

Step-by-step explanation:

plz don't mind my "×"

×^2+10×+21=0

×^2+7×+3×+21=0

rearrange

that is ; ×^2+3×+7×+21=0

(×^2+3×)+(7×+21)=0

×(×+3)+7 (×+3)=0

therefore

(×+7) (×+3)=0

×+7=0 ×+3=0

×= -7 ×=-3

Answer:

a : 2 , b : 1 , c : 0 , d : 0

Step-by-step explanation:

a: 2

b: 1

c: 0

d:0

Answer:

d .

Step-by-step explanation:

I went over it in class .

Answer:

D) 3/25

Step-by-step explanation:

Total number of tiles:

Number of tiles with "E" on it:

Probability of selecting a tile with "E" on it:

Answer choice: D) 3/25

The length of side MN is approximately 4.43 for the right triangle MNO.

In a right triangle MNO, with side NO equivalent to 4 and MO equivalent to 1.9, and with points MNO equivalent to 25 degrees and MON equivalent to 90 degrees, the length of side MN can be tracked down utilizing the Pythagorean hypothesis.

The Pythagorean hypothesis expresses that in a right triangle, the square of the length of the hypotenuse (the longest side) is equivalent to the number of squares of the other different sides. Thus, for this situation:

MN² = NO² + MO²

MN² = 4² + 1.9²

MN² = 16 + 3.61

MN² = 19.61

Taking the square root of both sides:

MN = √(19.61)

MN = 4.43

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The question is -

Consider the right triangle MNO below. Which expressions represent the length of the side MN?

The probability that you land on 8 twice is 1/64

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

We spin a spinner numbered 1-8 twice

The total sample space can be given by considering all the possible values

Hence the total number of spins are 8*8= 64 spins

The possibility that getting 8 twice is only once possible. As it will be only one pair in all the possible values.

Hence, The total probability is 1/64

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The statistical decision based on the reported results of the hypothesis test is that the null hypothesis was rejected at the α = .05 significance level.

The t-value reported is 2.38, and the degrees of freedom are 21. This suggests that the test was likely a t-test with an independent samples design, where the sample size was n = 22 (since df = n - 1).

The p-value reported is less than .05, which indicates that the probability of obtaining the observed results, or results more extreme, under the assumption that the null hypothesis is true, is less than .05. Therefore, the null hypothesis is rejected at the .05 significance level in favor of the alternative hypothesis.

In conclusion, the statistical decision is that there is sufficient evidence to suggest that the population means are not equal, and the sample size was 22. However, we do not have information about the direction of the effect (i.e., whether the difference was positive or negative).

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Answer:

5 hours

Step-by-step explanation:

To change minutes to hours you will have to divide the total minutes by 60 (because 60 minutes is in one hour), in this situation it would look like this:

180/60 = 3

So, Alexa babysat for 3 hours on Saturday.

Now, just add the 3 hours from Saturday and 2 hours from Sunday and you get a total of 5 hours!

I hope this helps!!

- Kay :)

Therefore, the formula W = Fd, where F is the force (weight) and d is the distance lifted. Plugging in our values, we get W = 48 lbs x 160 ft = 7,680 ft-lbs.

To find the work W done in pulling the rope to the top of the building, we need to calculate the weight of the rope and the distance it is being lifted. The weight of the rope is 0.8 lb/ft and the length is 60 ft, so the total weight is 48 lbs. The distance lifted is 160 ft.
The work W done in pulling the heavy rope, 60 ft long and weighing 0.8 lb/ft, to the top of a 160 ft high building can be found by calculating the weight of the rope and the distance it is being lifted. The weight of the rope is 48 lbs (0.8 lb/ft x 60 ft), and the distance lifted is 160 ft. Using the formula W = Fd, where F is the force (weight) and d is the distance lifted, we can plug in our values and find that W = 48 lbs x 160 ft = 7,680 ft-lbs.

Therefore, the formula W = Fd, where F is the force (weight) and d is the distance lifted. Plugging in our values, we get W = 48 lbs x 160 ft = 7,680 ft-lbs.

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Answer:

8

Step-by-step explanation:

1/5 / 40=?

or u could do 5 divided 40 or

5*_=40

so the answer is 8

Step-by-step explanation:

There are 84% out of 225. First find 10%. To do that divide the number by 10, so 225 ÷ 10 = 22.5 Next, do 22.5 x 8. Then you have 80%. Now, all that is need ed is the 4%. To get that, divide 225 by 100. Multiply the answer by 4 to get the 4%. Add the 80% and the 4% to get your answer. I really hope this helps. answers

Also, since I am just helping, I am un able to give you straight answers. I hope this also helps with work in the future.

if the second derivative is negative, then the first derivative is decreasing, Graphically, we see this as the curve. of the graph being concave down, that is, shaped like a parabola open downward.

The second derivative tells whether the curve is concave up or concave down at that point. If the second derivative is positive at a point, the graph is bending upwards at that point. Similarly if the second derivative is negative, the graph is concave down.

When second derivative is positive concavity?

If the second derivative is positive at a point, the graph is concave up at that point. If the second derivative is positive at a critical point, then the critical point is a local minimum. If the second derivative is negative at a point, the graph is concave down.

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The probability of selecting blue marble and green marble is 1/13.

A probability is a number that reflects the chance or likelihood that a particular event will occur. The certainty of an event is 1 which is equivalent to 100%.

Probability = sample space/total outcome

total outcome = 13

The probability of picking blue in the first pick = 6/13

since there is no replacement, the total outcome for the second pick = 12

The probability of picking green in the second pick = 2/12 = 1/6

Therefore the probability of selecting blue and green marble = 6/13 × 1/6

= 1/13

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The appropriate intervals to use when creating a histogram of the data are 0 – 35, 35 – 70, 70 – 105, and 105 – 140.

To create a histogram of the given data, we need to group the movie ticket sales into intervals. The intervals should be appropriate and cover the range of values in the data set.

Let's analyze each option and see if it satisfies the criteria:

A) 0 – 29, 30 – 59, 60 – 89, 90 – 119, 120 – 149: This option covers the entire range of the data and provides equal intervals of 30. However, it doesn't account for the maximum value in the data set (131).

B) 0 – 30, 30 – 55, 55 – 80, 80 – 105, 105 – 130: This option also covers the entire range of the data and provides narrower intervals. However, it doesn't account for the maximum value (131).

C) 0 – 24, 25 – 49, 50 – 74, 75 – 99, 100 – 125: This option doesn't cover the maximum value (131) and has intervals that are too narrow.

D) 0 – 35, 35 – 70, 70 – 105, 105 – 140: This option covers the entire range of the data and provides wider intervals. It includes the maximum value (131) and is the most appropriate choice for creating a histogram of the given data.

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Answer:

50 m

Step-by-step explanation: