Help me and can you put the equation you used

Answer:

slope is -1/4

x int is 4

y int is-1

y=-1/4x-1

Step-by-step explanation:

Answer:

y= −1−x/4

Step-by-step explanation:

The altitude of Denali is 6074 ft higher than White Mountain Peak.

The distance above sea level is known as altitude, just like elevation. If an area extends at least 2,400 meters (8,000 feet) into the atmosphere, it is frequently referred to as being "high-altitude." Mount Everest, located in the Himalayan mountain range between Nepal and Tibet in China, is the highest point on Earth.

To know the difference we will Subtract the Altitudes.

Therefore 20,320ft - 14, 246 ft = 6074 ft.

Therefore, the altitude of Denali is 6074 ft higher than White Mountain Peak.

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When Tracey pours all the water from the smaller 5-inch cube container into the larger 7-inch cube container, the water will be approximately 7 inches deep in the larger container.

To find out how deep the water will be in the larger container, we need to consider the volume of water transferred from the smaller container. Since both containers are cube-shaped, the volume of each container is equal to the length of one side cubed.

The volume of the smaller container is 5 inches * 5 inches * 5 inches = 125 cubic inches.

When Tracey pours all the water from the smaller container into the larger container, the water completely fills the larger container. The volume of the larger container is 7 inches * 7 inches * 7 inches = 343 cubic inches.

Since the water fills the larger container completely, the depth of the water in the larger container will be equal to the height of the larger container. Since all sides of the larger container have the same length, the height of the larger container is 7 inches.

Therefore, the water will be approximately 7 inches deep in the larger container.

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The length of the rectangle's shorter side is 6cm and the of the rectangle's longer side is 12cm.

What is perimeter?

The total length of a shape's boundary, as used in geometry, is referred to as the shape's perimeter. Adding the lengths of all the sides and edges that surround a shape yields its perimeter. It is calculated using linear length units like centimeters, meters, inches, and feet.

Given:

A rectangle has a perimeter of 36 cm and an area of 72 cm^2.

Let the length of the rectangle's shorter side is 'a' and

the length of the rectangle's longer side 'b'.

As the perimeter is 36 cm.

⇒ Perimeter = 2(a + b)

               36 = 2(a + b)

                18 = a+ b

                 a = 18 - b

Now the area of rectangle is 72cm^2.

⇒                   Area = ab

                         72 = (18 - b)*b

                         72 = 18b - b^2

      b^2 - 18b + 72 = 0

b^2 - 12b - 6x + 72 = 0

b(b - 12) - 6(b - 12) = 0

         (b - 12)(b - 6) = 0

(b - 12) = 0,    (b - 6) = 0

b = 12,   b = 6

When  b = 12   ⇒  a = 18 - 12 = 6

When  b = 6   ⇒  a = 18 - 6 = 12

Hence, the length of the rectangle's shorter side is 6cm and the of the rectangle's longer side is 12cm.

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Answer: Probability of a student playing both basketball and baseball is 4/28 or 14.3%

Step-by-step explanation:

1) Students playing atleast one sport = 28 - 6 = 22

2) N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 9 + 17 - 22 = 4

3) Number of students playing both basketball and baseball = 4

Total number of students = 28

Probability of a student playing both basketball and baseball is 4/28

4/28= 0.1428571429 x 100%= 14.3%

Answer:4/28

Step-by-step explanation:4/28

Possible causal reasons for the correlation between time spent playing video games and aggression are:

1. Video games cause aggression: This suggests that playing violent video games leads to aggressive behavior. To study this causal hypothesis, one possible approach would be to randomly assign participants to play either a violent or non-violent video game for a certain amount of time and then measure their level of aggression using a standardized aggression scale. This could be repeated with different samples to increase the reliability of the results.

2. Aggressive individuals seek out violent video games: This suggests that individuals who are already predisposed to aggression are more likely to choose to play violent video games. To test this hypothesis, researchers could administer an aggression scale to participants before asking them to report how often they play video games, and what types of games they prefer. The correlation between aggression scores and the amount of time spent playing violent video games would then be calculated.

3. A third variable is responsible for the relationship: This suggests that there is a third variable that causes both increased video game play and aggression. For example, this third variable could be stress levels, which may increase the likelihood of both playing video games and displaying aggressive behavior. To study this hypothesis, researchers could measure stress levels in participants and then ask them to report how often they play video games and their level of aggression. The correlation between stress levels and both video game play and aggression could then be calculated.

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Because the general expression for a quadratic equation is

A. The y-intercept is at the point (0, 0).

B.  The zeros are x = 0 or x = ±√5

C.

A) The y-intercept of this graph is the point where x = 0.

When  x = 0, the value of y

= 0^4 - 5*0^2

= 0.

Therefore, the y-intercept is at the point (0, 0).

B) The x-intercepts/roots of the function are the values of x that make y = 0.

To find these values, we need to set y = 0 and solve for x:

x⁴ - 5x² = 0

x⁴ = 5x²

x² = x⁴/5

x = ±√(x⁴/5)

We can simplify this expression by factoring x² out of both sides:

x²(x² - 5) = 0

x² = 0 or x² - 5 = 0

x = 0 or x = ±√5

hence the x-intercepts are at x = 0 and x = ±√5.

C) The end behavior of this function refers to how the graph of the function approaches the x-axis as x approaches positive infinity and negative infinity.

x → ∞ f(x) → ∞

x → -∞ f(x) → -∞

D) The graph is attached

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Answer:

1. 9

2. 122cm squared

3. 189m

4. 30

5. b

Step-by-step explanation:

1. 27,36,45,54,63,72,81,90,99

2. 12x6=72 10x5=50 50+72=122

3. 21x9=189

4. 5x12=60 60/2=30

5  b because 150 divided by 4 doesn't give you a whole number.

Time taken by Matilda on each project is \(5\frac{7}{12}\) hours.

According to the question we have been given that,

Total time taken by Matilda to complete the consulting projects = \(16\frac{3}{4}\) hours

First we will convert it into simple fraction which is

         \(16\frac{3}{4} = \frac{67}{4} \\\) hours

Number of consulting projects = 3

And Matilda spends same amount of time to each of the project.

To find the time she spend on each project is by using unitary method

that is,            3 projects = \(\frac{67}{4}\) hours

                      1 project = \(\frac{67}{4} / 3\)

                                     = 67/12

                                     = \(5\frac{7}{12}\) hours

Hence time taken by Matilda on each project is \(5\frac{7}{12}\) hours.

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Answer:

x=22

Step-by-step explanation:

We would do the opposite so "six less" we would add 6 to 38. 6+38= 44 and "twice a number" we would divide by 2. 44 /2= 22. So the answer would be 22.

Hope this helps! :)

Answer:

Answer is 22

Step-by-step explanation:

38+6=44

44 ÷ 2= 22

:)

Answer:

Option B

Step-by-step explanation:

Average rate of change of a function between x = a and x = b will be,

Average rate of change = \(\frac{f(b)-f(a)}{b-a}\)

We have to calculate average rate of change of the given quadratic function between x = 0 and x = 2.

From the given graph,

f(2) = 6

f(0) = 10

Therefore, average rate of change = \(\frac{f(2)-f(0)}{2-0}\)

                                                          = \(\frac{10-6}{2-0}\)

                                                          = 2

Option B will be the answer.

These standardization methods are crucial in chromatography to ensure accurate quantification and comparability of results.

In chromatography, standardization methods are used to ensure accurate and reliable results by establishing reference points or calibration standards. Here are three common methods of standardization in chromatography: External Standardization: In this method, a set of known standard samples with known concentrations or properties is prepared separately from the sample being analyzed. These standards are then analyzed using the same chromatographic conditions as the sample. By comparing the response of the sample to that of the standards, the concentration or properties of the sample can be determined. Internal Standardization: This method involves the addition of a known compound (internal standard) to both the standard solutions and the sample. The internal standard should ideally have similar properties to the analyte of interest but be different enough to be easily distinguished. The response of the internal standard is used as a reference to correct for variations in sample preparation, injection volume, and instrumental response. Internal standardization helps improve the accuracy and precision of the analysis. Standard Addition: This method is useful when the matrix of the sample interferes with the analysis or when the analyte concentration is unknown. It involves adding known amounts of the analyte of interest to different aliquots of the sample. The response of the analyte is then measured, and the concentration is determined by comparing the response with that of the standards. The difference in response between the sample and the standards allows for the determination of the analyte concentration in the original sample.

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The concept of simplifying a Boolean expression involves reducing the expression to its most concise form by applying logical rules and simplification techniques. This helps in reducing complexity, improving readability, and optimizing logic circuits by eliminating redundant terms and literals.

The simplified expression consists of two terms with a total of 5 literals.

To simplify the expression:

xyz + xyz' + x'yz' + x'y'z

We can apply Boolean algebra rules to simplify the terms:

Combine terms with common literals:

xyz + xyz' = xy(z + z') = xy

Combine terms with common literals:

x'yz' + x'y'z = x'z(y + y') = x'z

Now we have simplified the expression to:

xy + x'z

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Answer:

D) 10.00 for a 36 pack

Step-by-step explanation:

(I'm going up by the smallest pack to the highest because I noticed they are all multiples of 6)

1.80 for a 6 pack (double it to become a 12 pack)

3.60 for a 12 pack but the other 12 pack is more expensive making a 6 pack cheaper. (add another 6 pack)

5.40 for a 18 pack (add another 6pack)

7.20 for a 24 pack so this means the 6pack is more expensive and a 24pack is cheaper (in gonna keep adding till we get to 36 pack)

9 for a 30 pack

10.80 for a 36 pack

The value of the test statistic is 6.51.

The test statistic for this problem can be calculated using the formula:

z = (p - P) / √(P * (1 - P) / n)

Where p is the sample proportion (0.67 in this case), P is the hypothesized population proportion (we don't know this value, so we assume it to be 0.5 for a two-tailed test), n is the sample size (380), and z is the standard normal distribution value corresponding to the level of significance.

Plugging in the values, we get:

z = (0.67 - 0.5) / √(0.5 * (1 - 0.5) / 380) = 6.51

So the value of the test statistic is 6.51.

The test statistic is a measure of how far the sample proportion deviates from the hypothesized population proportion under the null hypothesis. In this case, we assume that the population proportion is 0.5 (since we have no reason to believe otherwise), and we calculate the probability of observing a sample proportion of 0.67 or greater assuming this null hypothesis is true.

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To reduce the third-order ordinary differential equation y - y" - 4y + 4y = 0 into a companion system of linear equations, we introduce new variables u and v:

Let u = y,

v = y',

w = y".

Taking the derivatives of u, v, and w with respect to the independent variable (let's denote it as x), we have:

du/dx = y' = v,

dv/dx = y" = w,

dw/dx = y"'.

Now we can rewrite the given differential equation in terms of u, v, and w:

u - w - 4u + 4u = 0.

Simplifying the equation, we get:

-3u - w = 0.

This equation can be expressed as a system of first-order linear differential equations as follows:

du/dx = v,

dv/dx = w,

dw/dx = -3u - w.

Now we have a companion system of linear equations:

du/dx = v,

dv/dx = w,

dw/dx = -3u - w.

To solve this system completely, we need to find the solutions for u, v, and w. By solving the system of differential equations, we can obtain the solutions for u(x), v(x), and w(x), which will correspond to the solutions for y(x), y'(x), and y"(x), respectively.

The exact solutions for this system of differential equations depend on the initial conditions or boundary conditions that are given. By applying appropriate initial conditions, we can determine the specific solution to the system.

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Answer:

hey there, the answer is 8.9429 × 10^8

Answer:

8.9429 × 10^8

Step-by-step explanation:

ya the answer is 8.9429 × 10^8

Answer:

C

Step-by-step explanation:

It is the easiest to simplify

Answer: It’s D I but C but it was wrong.

We can conclude that they form a right triangle

So GF = FH

OF^2 = GF^2 + OG^2

OF^2 = 8.4^2 + 8^2

OF^2 = 70.56 + 64

OF^2 = 134.56

OF = 11.6

a. the sampling distribution is  \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. The probability that the sample proportion is within 0.03 of the population proportion is 0.4101.

c. The probability that the sample proportion is within 0.03 of the population proportion for a sample of 200 households is 0.7738.

a. The sampling distribution of the sample proportion, \(\bar p\), can be approximated by a normal distribution with mean equal to the population proportion, p, and standard deviation equal to the square root of \([(p \times (1-p)) / n]\),

where n is the sample size.

Given that p = 0.17 and assuming a large enough sample size, we can use the formula to calculate the standard deviation of the sampling distribution:

Standard deviation = \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. To find the probability that the sample proportion will be within a certain range of the population proportion, we need to calculate the z-score for the lower and upper bounds of that range and then find the area under the normal curve between those z-scores.

Let's say we want to find the probability that the sample proportion is within 0.03 of the population proportion. This means we want to find

P(\(\bar p\)- p ≤ 0.03) = P((\(\bar p\)-- p) / \(\sqrt{[(p \times (1-p)) / n]}\) ≤ 0.03 / \(\sqrt{[(p \times (1-p)) / n]\)

We can use the standard normal distribution and z-scores to find this probability:

\(z_1\) = (0.03 / \(\sqrt{(0.17 \times (1-0.17)/n}\))

\(z_2\) = (-0.03 / \(\sqrt{(0.17 \times (1-0.17))/n}\))

We can find the probability that the z-score is between \(z_1\) and \(z_2\):

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.541 ≤ Z ≤ 0.541) = 0.4101

c. To answer part (c), we need to specify the sample size. Let's say we are taking a sample of 200 households.

Using the formula for standard deviation of the sampling distribution from part (a), we get:

Standard deviation = \(\sqrt{(0.17 \times(1-0.17)) / 200}\) = 0.034

Now we can repeat the same steps as in part (b) with this standard deviation:

\(z_1\) = (0.03 / 0.034)

\(z_2\) = (-0.03 / 0.034)

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.882 ≤ Z ≤ 0.882) = 0.7738

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¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)

Proof:

1. ∃x(Fx & Gx) [Premise]

2. Fx & Gx [∃-Elimination, 1]

3. ∃xFx [∃-Introduction, 2]

4. ∃xGx [∃-Introduction, 2]

5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]

6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]

ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)

Proof:

1. ¬ 3x(Px v Qx) [Premise]

2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]

3. Vx ¬ Px [∀-Introduction, 2]

4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]

iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Proof:

1. ¬ Vx(Fx → Gx) v 3xFx [Premise]

2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]

3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]

4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]

5. Fx → Gx [Resolution, 3, 4]

6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

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Mike Sullivan recently retired as Professor of Mathematics at Chicago State University, having taught there for more than 30 years. He received his PhD in mathematics from Illinois Institute of Technology.

He is a native of Chicago’s South Side and currently resides in Oak Lawn, Illinois. Mike has 4 children; the 2 oldest have degrees in mathematics and assisted in proofing, checking examples and exercises, and writing solutions manuals for this project. His son Mike Sullivan, III co-authored the Sullivan Graphing with Data Analysis series as well as this series. Mike has authored or co-authored more than 10 books. He owns a travel agency and splits his time between a condo in Naples, Florida and a home in Oak Lawn, where he enjoys gardening.

Michael Sullivan, III has training in mathematics, statistics and economics, with a varied teaching background that includes 27 years of instruction in both high school and college-level mathematics. He is currently a full-time professor of mathematics at Joliet Junior College. Michael has numerous textbooks in publication, including an Introductory Statistics series and a Precalculus series which he writes with his father, Michael Sullivan.

Michael believes that his experiences writing texts for college-level math and statistics courses give him a unique perspective as to where students are headed once they leave the developmental mathematics tract. This experience is reflected in the philosophy and presentation of his developmental text series. When not in the classroom or writing, Michael enjoys spending time with his 3 children, Michael, Kevin and Marissa, and playing golf. Now that his 2 sons are getting older, he has the opportunity to do both at the same time!

Product details

Publisher ‏ : ‎ Pearson; 4th edition (8 January 2018)

Language ‏ : ‎ English

Hardcover ‏ : ‎ 1224 pages

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Answer:

634342

FACTOR:

2 x 317171

We will find the sum of 3+ 1 1/2 with help of a

Answer:

Hello, It isn't clear.

It looks blur to me

Answer:

7. C

8. A

To find slope, we need two points. Once we have them, we can put them into the formula:

\(\frac{y_2 - y_1}{x_2 - x_1}\)      ← this is rise/run

For 7, it's just a matter of comparing any two consecutive points.

For 8, you are given the two points.

The coordinates of point b' are (-4, 1) and the coordinates of point c' are (-6, 0).

To obtain the coordinates of points b' and c' after the same translation as point a', we need to apply the same translation vector to points b and c.

The translation vector can be found by calculating the differences between the x-coordinates and the y-coordinates of points a' and a.

Translation Vector = (x-coordinate of a' - x-coordinate of a, y-coordinate of a' - y-coordinate of a)

                   = (-2 - 3, -3 - (-4))

                   = (-5, 1)

Now, we can obtain the coordinates of points b' and c' by adding the translation vector to the respective coordinates of points b and c.

For point b':

Coordinates of b' = (x-coordinate of b + x-coordinate of translation vector, y-coordinate of b + y-coordinate of translation vector)

                 = (1 + (-5), 0 + 1)

                 = (-4, 1)

Therefore, the coordinates of point b' are (-4, 1).

For point c':

Coordinates of c' = (x-coordinate of c + x-coordinate of translation vector, y-coordinate of c + y-coordinate of translation vector)

                 = (-1 + (-5), -1 + 1)

                 = (-6, 0)

Therefore, the coordinates of point c' are (-6, 0).

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Answer:

Step-by-step explanation:

The zero of a function is also known as the x-intercept of a function. The x-intercept of a function exists where y = 0. So we will begin by setting each of those lines = 0:

4x - 20 = 0     and     -1/2x + k = 0 and then solve each for x:

4x = 20 so

x = 5 and

-1/2x = -k and

1/2x = k so

x = 2k. Now we set the 2 x expressions equal to each other and solve for k:

5 = 2k so

k = 5/2

The value of the K in the given equation is 5/2.

The zero of a function is also known as the x-intercept of a function.

The x-intercept of a function exists where y = 0. So we will begin by setting each of those lines = 0:

4x - 20 = 0     and  

-1/2x + k = 0 and then solve each for x:

The substitution method is the algebraic method to solve simultaneous linear equations. As the word says, in this method, the value of one variable from one equation is substituted in the other equation.

4x = 20 so

x = 5 and

-1/2x = -k and

1/2x = k so

x = 2k. Now we set the 2 x expressions equal to each other and solve for k

5 = 2k so

k = 5/2

Therefore the value of the K in the given equation is 5/2.

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Answer:c

Step-by-step explanation:

lowest 3

Highest 15

15-3=12