Help!! I need help!
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Answer:

17 units

Step-by-step explanation:

Moving from (-8, 0) to (7, 8), we see x changing by 15 units from -8 to 7 and y changing by 8 units from 0 to 8.

Regard 15 units as the horizontal leg of a right triangle and 8 units as the vertical leg.  We use the Pythagorean Theorem to determine the length of the hypotenuse of this right triangle and interpret the result as the distance between the points:

d = √(15² + 8²) = √289 = 17

The distance between the given points is 17 units.

Answer:

no solution

Step-by-step explanation:

The Quadratic Factoring solutions to the equation \(2x^2\) + x - 10 = 0 are x = -5/2 and x = 2.

To solve the quadratic equation \(2x^2\) + x - 10 = 0 by factoring or finding square roots, we need to express it in the form (ax + b)(cx + d) = 0, where a, b, c, and d are constants.

Let's try factoring the quadratic equation:

\(2x^2\)+ x - 10 = 0

To factor it, we look for two numbers whose product is ac = 2(-10) = -20 and whose sum is b = 1.

The factors of -20 that add up to 1 are 5 and -4.

So, we can rewrite the equation as:

\(2x^2\) + 5x - 4x - 10 = 0

Now, we group the terms:

(\(2x^2\) + 5x) + (-4x - 10) = 0

Factor out the greatest common factor from each group:

x(2x + 5) - 2(2x + 5) = 0

Now, we can see that we have a common factor, (2x + 5), which we can factor out:

(2x + 5)(x - 2) = 0

To find the solutions, we set each factor equal to zero and solve for x:

2x + 5 = 0 or x - 2 = 0

For 2x + 5 = 0:

2x = -5

x = -5/2

For x - 2 = 0:

x = 2

Therefore, the Quadratic Factoring solutions to the equation \(2x^2\) + x - 10 = 0 are x = -5/2 and x = 2.

So, the correct answer is:

B. 2, -5/2

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For the given details the journal entry,

1) Compensation Expense $10.0 million

SARs Liability $10.0 million

2)  SARs Liability $5.0 million

Cash $5.0 million

To record this adjustment, we need to debit Compensation Expense and credit SARs Liability. The amount of the adjustment will be equal to the fair value of the SARs on the exercise date. Let's assume that the fair value of the SARs on June 6, 2021, is $10 million.

To record this journal entry, we need to debit SARs Liability and credit Cash. Let's assume that the market price of the stock on June 6, 2021, is $70 per share and the exercise price of the SARs is $65 per share. Also, let's assume that the company has 1 million SARs outstanding.

The total cash payment will be equal to the difference between the market price and the exercise price multiplied by the number of SARs exercised. In this case, the cash payment will be:

($70 - $65) x 1 million = $5.0 million

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Complete Question:

The SARs are exercised on June 6, 2021, when the share price is $65, and executives choose to receive the market price appreciation in cash. Prepare the appropriate journal entry(s) on that date. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Enter your answers in millions rounded to 1 decimal place (i.e., 5,500,000 should be entered as 5.5).)

1.Record any necessary adjustment to compensation expense.

2.Record the payment of cash.

The sample variance for the given data is 4.4 minutes. This corresponds to option e. in the list of choices provided.

The sample variance is a measure of how much the individual data points in a sample vary from the mean.

It is calculated by finding the average of the squared differences between each data point and the mean.

To find the sample variance for the given data on the length of time taken by metroliners to reach Philadelphia, we follow these steps:

Calculate the mean (average) of the data set:

Mean = (93 + 89 + 91 + 87 + 91 + 89) / 6 = 540 / 6 = 90

Subtract the mean from each data point and square the result:

(93 - 90)^2 = 9

(89 - 90)^2 = 1

(91 - 90)^2 = 1

(87 - 90)^2 = 9

(91 - 90)^2 = 1

(89 - 90)^2 = 1

Calculate the sum of the squared differences:

9 + 1 + 1 + 9 + 1 + 1 = 22

Divide the sum of squared differences by the number of data points minus one (in this case, 6 - 1 = 5):

Variance = 22 / 5 = 4.4

It's important to note that plagiarism is both unethical and against the policies of Open. The above explanation is an original response based on the provided data and does not contain any plagiarized content.

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The definition of the given piecewise function is:

A piecewise function is a function that has different definitions, depending on the input.

In this problem, for x until 2, the function is the cube function shifted down 3 units, hence the definition is:

\(y = x^3  - 3, x \leq 2\)

For x greater than 2, the function is the square function shifted up 6 units, hence the definition is:

\(y = x^2 + 6, x > 2\)

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Answer:

Probably 8!

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

A slope parameter of β1 = 3.52 in a simple linear regression model suggests that there is a positive and direct relationship between the independent variable (x) and the dependent variable (y).

Specifically, for every one unit increase in the independent variable (x), the dependent variable (y) is expected to increase by an average of 3.52 units. This indicates a positive linear association between x and y, implying that as x increases, y tends to increase as well.

The magnitude of the slope parameter (3.52) also indicates the steepness of the relationship. A larger slope suggests a stronger relationship, indicating that the change in y for a given change in x is relatively large.

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The formula to find the tangent line to a curve at a given point is y = f'(x) (x - x₀) + f(x₀).

The derivative of the function, f'(x) is calculated at the given point, x₀. Then, the equation of the tangent line is found by substituting the x₀ and f'(x) values into the formula.

To find the tangent line to a curve at a given point, the formula for the slope of the tangent line must be used. The slope of a tangent line is equal to the derivative of the function at that point. The resulting equation is a line with a slope equal to the derivative of the function at the given point, and a y-intercept equal to the value of the function at the given point. For example, if you want to find the tangent line to the function f(x) = 4x² + 3 at the point (2, 19), the derivative of the function at that point is f'(x) = 8x = 8(2) = 16. Then, the equation of the tangent line is y = 16(x - 2) + 19.

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Answer: 1,320 cl

Step-by-step explanation:

Water and orange squash are mixed in the ratio 11 : 2.

This means that at their simplest if using cl, it would take 11cl of water and 2 cl of orange squash for a proper dilution.

If 240 cl of orange sqaush is used and you need to find the amount of water, use direct proportion with x as water.

11     :    2

x     :     240

Cross-multiply:

2x = 11 * 240

x = 2,640 / 2

= 1,320 cl

Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.

Given:

Payment required at the end of each year: P50,000

Number of years until the daughter starts college: 8

Interest rate: 7% (compounded annually)

We can calculate the annual savings using the formula for the present value of an ordinary annuity:

P = \dfrac{PMT \times (1 - (1 + r)^{-n}{r}

Where:

P = Present value (amount to be saved annually)

PMT = Payment amount (P50,000)

r = Interest rate per period (7% or 0.07)

n = Number of periods (8)

Let's substitute the given values into the formula:

\[ P = \dfrac{50,000 \times (1 - (1 + 0.07)^{-8}{0.07} \]

Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.

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She did sell the newspapers for $.25 each at age 80. The equation is referred to as a linear equation in one variable if only one variable is present in the linear equation.

It is described as the relationship between two variables, and a straight line results from plotting the graph of the linear equation.

The information provided in the issue is;

One newspaper will set you back $.25.

Other newspapers are $.40 each.

The 100 newspapers were purchased for $28.00.

x is the quantity of newspapers sold for $.25 each.

Y stands for the other newspaper's number.

The total of both newspapers is one hundred.

x+y=100

y=100-x

25x+ 40y=28.00

25x+40(100-x)=2800

25x+4000-40x=2800

-15x+4000=2800

-15x=-1200

x=80

She therefore sold 80 newspapers for $.25 each.

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Zgadza się. Objętość jest miarą trójwymiarową, którą się mierzy z m³, dm³, cm³, mm³, itd.

it goes into five 0 times

Answer:

0 Times

Step-by-step explanation:

The answer is 0 times!

This is due to the concept in which 8 is a bigger number than 5.

Rotation is the rigid type of transformation which is equivalent to the two reflections across intersecting lines.

Therefore, the rigid type transformation which is equivalent to two reflection across the intersecting lines is called rotation.

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Fallis has 2000 square centimeters (cm²) tiles, she does not have enough tiles to cover the entire counter.

To find out if Ms. Fallis has enough tiles to cover the counter, we need to calculate how many tiles are required to cover an area of 2 square meters.

Since the tiles have a side length of 3 centimeters, we need to convert the area of the counter to square centimeters.

1 square meter = 10000 square centimeters (cm²)

So, 2 square meters = 20000 square centimeters (cm²)

Now, we need to calculate the area of each tile:

Side length of each tile = 3 centimeters (cm)

Area of each tile = \((side length)^2\) = \((3 cm)^2\) = 9 square centimeters (cm²)

To cover the counter, we need to divide the total area of the counter by the area of each tile:

Number of tiles required = (Total area of counter) / (Area of each tile)

= 20000 cm² / 9 cm²

= 2222.22

Since we cannot have a fraction of a tile, we need to round up to the nearest whole number of tiles. So, Ms. Fallis needs at least 2223 tiles to cover the counter.

Since she has 2000 square centimeters (cm²) tiles, she does not have enough tiles to cover the entire counter.

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Answer:

6x -4

Step-by-step explanation:

(4x-5)+(2x+1)

Combine like terms

4x+2x   -5 +1

6x -4

Answer:

Solution:

Given,

Ratio of photo to to the photo frame=2:3

Length of photo frame=36cm

= 36÷3

=13

then,

Length of photo = 13 ×2

= 26cm

Step-by-step explanation:

Therefore,the length of the photo is 26cm

Given:

The number of faces =8.

Required:

We need to find the polyhedron with 8 faces.

Explanation:

Recall that the tetrahedron is a polyhedron composed of four triangular faces

The number of faces in tetrahedron =4.

Recall that the octahedron is a polyhedron with 8 faces.

The number of faces in the octahedron= 8.

Recall that the dodecahedron is a polyhedron with 12 faces.

The number of faces in the dodecahedron = 12.

Recall that the icosahedron is a polyhedron with 20 faces.

The number of faces in icosahedron =20.

Final answer:

octahedron

Answer:

there is in spanish if you want to translate it

Answer:

\(\huge\boxed{\sf x=\frac{2}{y-f}}\)

Step-by-step explanation:

xy - fx = 2

Take x common

x(y - f) = 2

Divide y-f to both sides

\(\displaystyle x=\frac{2}{y-f} \\\\\rule[225]{225}{2}\)

Answer:

one pen costs 0.5 euros

one rubber costs 0.75 euros

Step-by-step explanation:

4p+5r=5.75

p+4r=3.5

  -4r.   -4r

p=3.5-4r

4(3.5-4r)+5r=5.75

14-16r+5r=5.75

14-11r=5.75

-14.     -14

-11r=-8.25

r=0.75

One rubber cost 0.75 euros

Now to find cost of one pen we just fill in what we know

p+4(0.75)=3.5

p+3=3.5

 -3.  -3

p=0.5

1 pen cost 0.5 euros

Hopes this helps please mark brainliest

Answer:

okay i will gladly

A pair (x, p) is an equilibrium, if and only if x and p are optimal solutions to the standard form problem and its dual, respectively.

To show that a pair (x, p) is an equilibrium if and only if x and p are optimal solutions to the standard form problem and its dual, we need to demonstrate both directions of the equivalence.
First, let's assume that (x, p) is an equilibrium. An equilibrium occurs when the primal problem and its dual problem satisfy certain conditions. In this case, we have:
1. Primal problem:
  - Objective function: maximize \(c^T * x\) (where c is the cost vector and x is the decision variable)
  - Subject to: Ax = b (where A is the constraint matrix and b is the right-hand side vector)
2. Dual problem:
  - Objective function: minimize \(b^T * p\) (where p is the dual variable)
  - Subject to: \(A^T * p \geq c\) (where \(A^T\) is the transpose of A)
Now, if (x, p) is an equilibrium, it means that both the primal and dual problems are feasible, and their objective functions are equal. This implies that x and p are optimal solutions to their respective problems.
Conversely, let's assume that x and p are optimal solutions to the standard form problem and its dual, respectively. This means that x and p satisfy the feasibility conditions and optimize the objective functions of their respective problems.
Since x and p are optimal solutions, the objective functions of the primal and dual problems are equal. This condition ensures that (x, p) is an equilibrium.

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A pair (x, p) is an equilibrium if and only if x is an optimal solution to the standard form problem and p is an optimal solution to its dual. Both conditions must be satisfied for equilibrium.

To show that a pair (x, p) is an equilibrium, we need to prove two conditions: (1) x is an optimal solution to the standard form problem, and (2) p is an optimal solution to its dual.

First, assume that (x, p) is an equilibrium. This means that x is feasible and satisfies the constraints of the standard form problem. We can also assume that p is feasible and satisfies the constraints of the dual problem.

To prove condition (1), we can use contradiction. Suppose x is not an optimal solution. Then there exists another feasible solution x' that yields a better objective function value. However, this contradicts the definition of an equilibrium, so x must be an optimal solution.

Similarly, to prove condition (2), we can assume that p is not an optimal solution. Then there exists another feasible solution p' to the dual problem that yields a better objective function value. Again, this contradicts the definition of an equilibrium, so p must be an optimal solution.

Conversely, if x is an optimal solution to the standard form problem and p is an optimal solution to its dual, we can conclude that (x, p) is an equilibrium. This is because both x and p satisfy the necessary conditions for optimality.

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The calculated values are as follows:

(1101011)2 is equal to (107)10.

(0.11111)2 is equal to (0.96875)10.

(110.11100)2 is equal to (6.875)10.

a. (1101011)2 = (107)10

To convert a binary number to base 10, you need to multiply each digit of the binary number by the corresponding power of 2 and sum up the results.

(1101011)2 = (1 × 2^6) + (1 × 2^5) + (0 × 2^4) + (1 × 2^3) + (0 × 2^2) + (1 × 2^1) + (1 × 2^0)

= (64) + (32) + (0) + (8) + (0) + (2) + (1)

= (107)10

Therefore, (1101011)2 is equal to (107)10.

b. (0.11111)2 = (0.96875)10

To convert a binary fraction to base 10, you need to multiply each digit of the binary fraction by the corresponding negative power of 2 and sum up the results.

(0.11111)2 = (1 × 2^-1) + (1 × 2^-2) + (1 × 2^-3) + (1 × 2^-4) + (1 × 2^-5)

= (0.5) + (0.25) + (0.125) + (0.0625) + (0.03125)

= (0.96875)10

Therefore, (0.11111)2 is equal to (0.96875)10.

c. (110.11100)2 = (6.875)10

To convert a binary number with fractional part to base 10, you need to split the number into its integer and fractional parts. Then, convert each part separately using the same method as in previous examples.

For the integer part:

(110)2 = (1 × 2^2) + (1 × 2^1) + (0 × 2^0)

= (4) + (2) + (0)

= (6)10

For the fractional part:

(0.11100)2 = (1 × 2^-1) + (1 × 2^-2) + (1 × 2^-3) + (0 × 2^-4) + (0 × 2^-5)

= (0.5) + (0.25) + (0.125) + (0) + (0)

= (0.875)10

Combining the integer and fractional parts:

(110.11100)2 = (6) + (0.875)

= (6.875)10

Therefore, (110.11100)2 is equal to (6.875)10.

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It is not possible to reach the top of the ladder to the edge of the roof.

We can solve this problem using the Pythagorean theorem, which states that for a right triangle, the sum of the squares of the two shorter sides is equal to the square of the length of the hypotenuse (the longest side).

In this case, the ladder is the hypotenuse of a right triangle, and the distance from the base of the ladder to the house and the distance from the top of the ladder to the edge of the roof are the two shorter sides.

Let x be the distance from the top of the ladder to the edge of the roof. Then, we can write:

\(10^{2}\) = \((1.5)^{2}\) + \(x^{2}\) + \(12^{2}\)

Simplifying and solving for x, we get:

100 = 2.25 +\(x^{2}\) + 144

\(x^{2}\) = 100 - 2.25 - 144

\(x^{2}\) = -46.25

Since x represents a distance, which must be positive, this means that there is no solution to the equation. Therefore, it is not possible for Sammy to reach the edge of the roof with his 10-foot ladder while keeping the base of the ladder at least 1.5 feet from the base of the house.

Correct Question :

Sammy has a 10-foot ladder, which he needs to climb to reach the roof of his house. the roof is 12 feet above the ground. the base of the ladder must be at least 1.5 feet from the base of the house. how far is it from the top of the ladder to the edge of the roof?

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Answer:

what

Step-by-step explanation:

that the confidence levels and p - values from the t procedures are quite accurate even if the population distribution is not exactly normal

Because the t procedures are robust, the most important condition for their safe use is that.

The meaning of that major reason is

that the confidence levels and p - values from the t procedures are quite accurate even if the population distribution is not exactly normal

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Data can be divided on the basis of qualitative nature into two types as follows:

Thus, it is clear that nominal data can not be ranked or ordered but ordinal data are the type of qualitative data that are categorised and then ranked or ordered.

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