What is a group of millions to billions of stars, objects that orbit those stars, gases, and dust?
1.Galaxy
2.Planet
3.Solar system
4.Universe
Answer:
Galaxy
Explanation:
A group of millions to billions of stars objects that orbit those stars, gases, and dust is known as Galaxy. Thus, the correct option for this question is A.
What is a Galaxy?A galaxy may be defined as a huge collection of gas, dust, and billions of stars and their solar systems, all held together by gravity. It is an extremely large group of stars and planets that extends over many billions of light years.
A galaxy is any of the systems of stars and interstellar matter that make up the universe. Many such assemblages are so enormous that they contain hundreds of billions of stars. Galaxies usually exist in clusters, some of which measure hundreds of millions of light-years across.
A Planet is a celestial body that surrounds around the sun. All planets including the sun form the solar system. While the universe is the collection of all of space and everything in it including stars, planets, galaxies, etc.
Therefore, a group of millions to billions of stars objects that orbit those stars, gases, and dust is known as Galaxy. Thus, the correct option for this question is A.
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The reaction R of the body to a dose M of medication is often represented by the general function R(M)=M^2(C/2−M/3where C is a constant. If the reaction is a change in blood pressure, R is measured in millimeters of mercury (mmHg). If the reaction is a change in temperature, Ris measured in degrees Fahrenheit ("F). The rate of change dR/dM is defined to
be the body's sensitivity to the medication. Find a formula for the sensitivity dR/dM=
A formula for the sensitivity dR/dM represents the sensitivity of the body's reaction to the medication. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.
To find a formula for the sensitivity, dR/dM, let's differentiate the given function R(M) with respect to M.
Step 1: Start with the function \(R(M) = M^2(C/2 - M/3).\)
Step 2: Apply the power rule of differentiation to differentiate M^2. The power rule states that if
\(f(x) = x^n, then f'(x) = n*x^(n-1). \\\)
n this case, n = 2.
\(dR/dM = 2M^(2-1)*(C/2 - M/3).\)
Simplifying, we have:
\(dR/dM = 2M*(C/2 - M/3).\)
Step 3: Distribute the 2M to each term inside the parentheses:
\(dR/dM = M*C - (2M^2)/3.\)
This formula represents the sensitivity of the body's reaction to the medication, dR/dM. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.
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the formula for the sensitivity, or the rate of change of the reaction R with respect to the dose M, is
dR/dM = MC - M\(^2^/^3\)
How do we calculate?We calculate the derivative of the reaction function R(M) with respect to M.
the reaction function: R(M) = M²(C/2 - M/3)
We will apply the power rule and the constant multiple rule of differentiation,
dR/dM = d/dM [M²(C/2 - M/3)]
= 2M(C/2 - M/3) + M²(0 - (-1/3))
= 2M(C/2 - M/3) + M\(^2^/^3\)
dR/dM =\(MC - 2M^2^/^3 + M^2^/^3\)
= \(MC - M^2^/^3\)
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describe how to identify the smell of gas in the laboratory
Answer:
When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.
Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.
Complete the second row in the table by filling in the missing information about a system at equilibrium. C: Q < Keq Q > Keq Q = Keq
The second row of the table, which deals with the equilibrium of a system, can be completed by filling in the missing information.C: Q < KeqWhen Q < Keq, the reaction will proceed in the forward direction. It means that the concentration of reactants will be higher than the concentration of products.
The forward reaction is thus favored When the forward reaction is favored, the equilibrium constant Keq is greater than the reaction quotient Q. As a result, there is an increase in the concentration of products to reactants until the Keq and Q values become equal. As a result, the reaction proceeds in the forward direction to achieve equilibrium. This case is also referred to as the reaction proceeding spontaneously in the forward direction
When Q > Keq, the concentration of the reactants is higher than the concentration of products, and the reaction is in the reverse direction. The reverse reaction is favored in this case. The reaction proceeds in the reverse direction to establish equilibrium when the concentration of products increases to that of reactants, and the Keq and Q values become equal. This case is referred to as the reaction proceeding spontaneously in the reverse direction.When Q = Keq, the reaction is at equilibrium, which means that the rate of the forward reaction is equal to the rate of the reverse reaction. As a result, the concentration of products and reactants remain constant.
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if the equilibrium constant for a b c is 0.208, then the equilibrium constant for 2c 2a 2b is a.4.81 b.0.416 c.23.1 d.0.584 e.0.208
The equilibrium constant for 2c 2a 2b is 4.81
Equilibrium constant calculation explained.
The equilibrium constant expression for the reaction:
A + B + C ⇌ 2C + 2A + 2B
can be written as:
K = ([C]^2 [A]^2 [B]^2) / ([A][B][C])^2
which simplifies to:
K = [C]^2 [A]^2 [B]^2 / [A]^2 [B]^2 [C]^2
K = [C]^2 / [A]^2 [B]^2
Since the reaction is the reverse of the original reaction A + B + C ⇌ 2C + 2A + 2B, we can use the principle of microscopic reversibility to relate the equilibrium constants for the forward and reverse reactions:
K_reverse = 1 / K_forward
Therefore, the equilibrium constant for the reverse reaction 2C + 2A + 2B ⇌ A + B + C can be calculated as:
K_reverse = 1 / 0.208 = 4.81
Therefore, the equilibrium constant for the reaction 2C + 2A + 2B ⇌ A + B + C is approximately 4.81.
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whats the difference between the two models of the atom
Answer:
We need the two models in question...
Explanation:
Can't explain the difference between two things without knowing what the two things are.
Suppose you scrape your knee falling off your bike. What may happen if mitosis doesn't start around the open wound? Explain.
If the cells do not multiply by mitosis then the wound will not heal.
What is mitosis?There are two kinds of cell division and these are mitosis and meiosis. We have to note that mitosis occurs at the body cells and the exact number of chromosomes in the parent cell is transferred to the daughter cells.
Meiosis occurs in the gamete cells and each of the parent cells would only contribute half of the maximum number of the chromosomes that they contain.
We know that when we have a cut, the cells around the area of the cut would begin to multiply by the process of mitosis helping the wound to heal.
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The correct coefficients needed to balance the following reaction are:
___ PbI2 + ___ ZnS → ___ PbS + ___ZnI2
a) 1, 2, 2, 1
b) 1, 1, 1, 1
c) 1, 1, 2, 2
d) 2, 1, 1, 2
explain the characteristics of particles of matter
have a a great day
so the atp synthase f1 subunit will run in the direction where the free energy difference between products and reactants (δg) is
So the ATP synthase F1 subunit will run in the direction where the free energy difference between products and reactants (ΔG) is negative.
In oxidative phosphorylation, ATP Synthase (F₁F₀-ATPase) is mainly composed of two subunits. They are: Proton conducting unit (F₀) and Catalytic unit (F₁). Isolated F₁ subunits of ATP synthase catalyzes the hydrolysis of ATP . There is no coupling to the c-ring (Fo) in the isolated F1 subunit . The F₀ contains the proton channel. So, the ATP synthase subunit (F₁) will run in the direction where the difference in free energy between products and reactants (ΔG) is negative.
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Fluorine gas reacts with zinc (II) chloride →
Answer:
Zinc Chloride + Difluorine -----> Zinc Fluoride + Dichlorine
Explanation:
ZnCl2 + F2 → ZnF2 + Cl2
when pressure is kept constant then the temperature varies with volume
a. directly
b. inversely
c. none of these
d. both a and b.
Answer:
A
Explanation:
I need help on this!!
A covalent bond will be formed when two atoms are each trying to take each others electrons. Option A
What is a covalent bond?A covalent bond is a type of chemical bond that involves the sharing of electrons between atoms. In a covalent bond, two or more atoms share one or more pairs of electrons to achieve a more stable electron configuration.
The strength of a covalent bond depends on a variety of factors, including the number of shared electrons, the distance between the atoms, and the electronegativity of the atoms involved. Covalent bonds are very strong, and they play a crucial role in the formation of molecules and compounds in chemistry.
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If the work function of tin (Sn) is 281 nm, what equation could you use to determine the amount of energy required to eject a photoelectron from a sample of tin?
Answer:
See explanation
Explanation:
The work function is given by;
Wo = hc/λ
where;
h = 6.6 * 10^-34 Js
c = 3 * 10^8 ms-1
λ = 281 nm or 281 * 10^-9 m
Wo = 6.6 * 10^-34 * 3 * 10^8 / 281 * 10^-9
Wo = 7.0 * 10^-19 J or 4.375 eV
Note that the work function is the minimum energy required to eject an electron from a sample of tin.
write a balanced chemical equation based on the following description: the reaction of solid iron(iii) sulfide with aqueous hydrochloric acid to form aqueous iron(iii) chloride and hydrogen sulfide gas.
The final balanced Equation is, Fe₂S₃ (s) + 6HCl (aq) → 2Fecl₃ (aq) + 3H₂S(g)
Reaction of Solid iron (III) Sulfide with aqueous hydrochloric acid.
What is the meaning of balanced Equation?
An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction.
Unbalanced Reaction
Fe₂S₃ (s) + HCl (aq) → Fecl₃ (aq) + H₂S(g)
Now, this equation has equation has 2 Fe atom on reactant side and one in product side. To balance that add 2 as coefficients with Fecl₃.
Fe₂S₃ (s) + HCl (aq) → 2Fecl₃ (aq) + H₂S(g)
Now, balance S atoms by adding 3 as coefficient in front of H₂S(g).
Fe₂S₃ (s) + HCl (aq) → 2Fecl₃ (aq) + 3H₂S(g)
Now, Products have 6 Cl and 6H atoms. Balance them by adding 6 in front of на HCl (aq) as coefficient.
Therefore, the final balanced Equation is,
Fe₂S₃ (s) + 6HCl (aq) → 2Fecl₃ (aq) + 3H₂S(g)
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If 0.36 g of NaC is dissolved in water and the resulting solution 1 point weighs12.80 g, what is the Mass \% ofNaClin the solution? Make certain your answer has the correct number of significant figures.
a. 2.813%
b. 4.995%
c. 5.0%
d. 2.8%
The mass % of Nac is 2.8%. Therefore, option (d) 2.8% is the correct answer to this question.
In a solution, the mass percentage of any component is the proportion of the mass of that component to the mass of the entire solution multiplied by 100 percent. The mass percentage of NaC in the solution can be calculated using the given values as follows: The mass percentage of NaC = (mass of NaC/mass of solution) × 100 percent. Let's solve the given problem using this formula. Mass of NaC = 0.36 g
The mass of the solution = 12.80 hence, the mass percentage of NaC in the solution is,
Mass percentage of
NaC = (0.36 g/12.80 g) × 100 percent mass percentage of
NaC = 2.8125 % ≈ 2.8 %
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A student has a container of sand and sugar. What characteristic could be used to separate the mixture?
Answer:
Sugar will dissolve, so water.
Explanation:
Sugar is a bicubacle food source you could say, sand will not evaporate or dissolve in the water since it is not a 3c2e source. Using water will seperate them.
Answer: Heat
Explanation:
Because is you put water and sand in a container you can separated by boiling the water and all the water would evaporate and the sand would stay.
Calculate the molality of a solution in water that is 3.48 M of a compound (H2CO). The density of the solution is 0.881 g/mL.
Molality is defined as the number of moles of solute per 1000 g of solvent (mol/kg). Here's how to calculate molality:
Step 1: Determine the moles of solute (H2CO) present in the solution. Number of moles of solute (n) = Molarity of solution × Volume of solution (in L) = 3.48 mol/L × 1 L = 3.48 moles of solute (H2CO).
Step 2: Calculate the mass of the solvent (water) in kg using the density of the solution. Density of solution = Mass of solution / Volume of solution .
Mass of solution = Density of solution × Volume of solution Mass of solution = 0.881 g/mL × 1000 mL Mass of solution = 881 g or 0.881 kg.
Step 3: Calculate the molality of the solution. Molality of the solution = Moles of solute / Mass of solvent (in kg) Molality of the solution = 3.48 moles / 0.881 kg = 3.96 mol/kg
Molality is one of the most useful concepts used in chemistry. It describes the relationship between the number of moles of solute and the mass of the solvent in a solution. Molality is defined as the number of moles of solute per 1000 g of solvent (mol/kg).To calculate molality, you must first determine the number of moles of solute in the solution. In this case, the solution contains 3.48 moles of H2CO. After that, you must determine the mass of the solvent (water) in kg, which can be done by using the density of the solution. The density of the solution is 0.881 g/mL, which means that 1000 mL of solution weighs 881 g. Therefore, the mass of the solution is 881 g or 0.881 kg.Once you have the number of moles of solute and the mass of the solvent in kg, you can calculate the molality of the solution. In this case, the molality of the solution is 3.96 mol/kg.
Therefore, the molality of the solution in water that is 3.48 M of H2CO is 3.96 mol/kg.
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When the temperature of substance
decreases, what happens to the
substances thermal energy?
Explanation:
When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.
When the temperature of a substance is increased, i.e., if you double the Kelvin temperature of a substance, you double the average kinetic energy of its molecules. When the average kinetic energy of the molecules goes up (a rise in temperature), the average speed of the molecules increases.
select the components of a fatty acid. multiple select question. long helical chains of monosaccharides a long hydrocarbon chain a carboxyl group many amino acids
The components of a fatty acid include a long hydrocarbon chain and a carboxyl group. A fatty acid is a type of molecule that consists of a long chain of carbon atoms with hydrogen atoms attached, hence the term "hydrocarbon chain."
This chain is nonpolar and hydrophobic, meaning it repels water. At one end of the hydrocarbon chain, there is a carboxyl group, which is composed of a carbon atom double-bonded to an oxygen atom and single-bonded to a hydroxyl group (-OH). The carboxyl group is polar and hydrophilic, meaning it has an affinity for water. It is the carboxyl group that gives fatty acids their acidic properties. The term "long helical chains of monosaccharides" is not applicable to fatty acids. Monosaccharides are simple sugars and are not found in fatty acids. Additionally, fatty acids do not contain amino acids. To summarize, the components of a fatty acid are a long hydrocarbon chain and a carboxyl group.
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A fatty acid consists of a long hydrocarbon chain and a carboxyl group. These fatty acids can be saturated, with maximum hydrogen atoms and single bonds, or unsaturated, with one or more double bonds and fewer hydrogen atoms.
Explanation:The components of a
fatty acid
include a
long hydrocarbon chain
and a
carboxyl group
.
Fatty acids are lipids that contain long-chain hydrocarbons terminated with a carboxylic acid functional group. The long hydrocarbon chain gives fatty acids their hydrophobic or water-fearing properties. Fatty acids can be saturated, having the maximum number of hydrogen atoms and only single bonds between carbon atoms, or unsaturated, having one or more double bonds and less hydrogen.
The number of carbons in the fatty acid may range from 4 to 36; most common are those containing 12–18 carbons. The fatty acids in a fat molecule are attached to each of the three carbons of the glycerol molecule with an ester bond through an oxygen atom. This is another key characteristic of fatty acids.
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Draw the structure of the major organic product formed in the reaction of 1?methylcyclohexene with diborane in diglyme, followed by basic hydrogen peroxide.
The major organic product formed in the reaction of 1-methylcyclohexene with diborane in diglyme, followed by basic hydrogen peroxide is 1-methylcyclohexanol.
This reaction is an example of hydroboration-oxidation, which is a common method for the conversion of an alkene into an alcohol. Hydroboration is the addition of borane (BH3) to an alkene to form a trialkylborane.The reaction between 1-methylcyclohexene and diborane (BH3) in diglyme produces trialkylborane as an intermediate product as shown below.
On further reaction with basic hydrogen peroxide (H2O2) as an oxidant, the trialkylborane converts into alcohol as shown below:Thus, the final product obtained after the reaction of 1-methylcyclohexene with diborane in diglyme followed by basic hydrogen peroxide is 1-methylcyclohexanol, which is the major organic product.1-methylcyclohexanol is an organic compound with the molecular formula C7H14O. It is a secondary alcohol with a branched chain. This reaction is widely used in the production of various types of alcohols.
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Write equations that show the following processes.
Express your answer as a chemical equation separated by a comma. Identify all of the phases in your answer.
The first two ionization energies of nickel
The fourth ionization energy of zirconium.
The first two ionization energies of nickel:
Ni(g) → Ni+(g) + e^− (1st ionization energy)
Ni+(g) → Ni2+(g) + e^− (2nd ionization energy)
The fourth ionization energy of zirconium:
Zr3+(g) → Zr4+(g) + e^−
What are the chemical equations for the first two ionization energies of nickel and the fourth ionization energy of zirconium?The first two ionization energies of nickel can be represented by the following equations:
Ni(g) → Ni+(g) + e- (first ionization energy)
Ni+(g) → Ni2+(g) + e- (second ionization energy)
The fourth ionization energy of zirconium can be represented by the following equation:
Zr3+(g) → Zr4+(g) + e-
In all equations, the state of the element or ion is indicated in parentheses, with (g) representing a gaseous state. The symbol e- represents an electron, and the arrow indicates the direction of the reaction.
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which of the molecular orbital diagrams is correctly filled for the diatomic molecule r2? (each atom of r has six valence electrons in ns and np orbitals.)
Atomic orbitals are the areas to the left and right of the dashed lines. The possible molecular orbitals that they can form are indicated by the dashed lines.
Normally, in diatomic molecular orbitals, the atomic orbitals with the closest energy level can overlap with each other and form molecular orbitals. Therefore, the atomic orbitals generally tend to overlap one by one from the lowest potential energy to the highest potential energy. For example, in a homonuclear diatomic molecule, which means that both atoms are the same element, the same orbitals will overlap together and form molecular orbitals.
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You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100M benzoic acid (pK
a
=4.20) and 0.240M sodium benzoatc. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid:
Previous question
To prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.The ratio of benzoic acid to sodium benzoate in the buffer solution using the Henderson-Hasselbalch equation.
To prepare a pH 4.00 buffer solution using benzoic acid and sodium benzoate, we need to calculate the appropriate volumes of the 0.100 M benzoic acid and 0.240 M sodium benzoate solutions.
First, we need to determine the ratio of benzoic acid to sodium benzoate in the buffer solution. The Henderson-Hasselbalch equation can help us with this calculation:
pH = pKa + log([A-]/[HA])
Given that the pH is 4.00 and pKa is 4.20, we can rearrange the equation:
log([A-]/[HA]) = pH - pKa
log([A-]/[HA]) = 4.00 - 4.20
log([A-]/[HA]) = -0.20
Next, we take the antilog of -0.20 to find the ratio of [A-] to [HA]:
[A-]/[HA] = antilog(-0.20)
[A-]/[HA] = 0.63
The ratio of [A-] to [HA] is 0.63.
Now, let's calculate the volumes of each solution needed. Let's assume x represents the volume (in mL) of the 0.100 M benzoic acid solution and y represents the volume (in mL) of the 0.240 M sodium benzoate solution.
Since the total volume is 100.0 mL, we have the equation: x + y = 100
Considering the ratio of [A-] to [HA] as 0.63, we can write the equation: y/x = 0.63
Solving these two equations simultaneously will give us the volumes of each solution:
x + y = 100
y/x = 0.63
By substituting y = 0.63x from the second equation into the first equation, we get:
x + 0.63x = 100
1.63x = 100
x = 61.35 mL (rounded to two decimal places)
Substituting this value back into the equation x + y = 100, we find:
61.35 + y = 100
y = 38.65 mL (rounded to two decimal places)
Therefore, to prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.
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what may happen to the electron when it loses its energy?
When electrons loses energy they jump between shells as they are rotating around the nucleus.
materials that are eroded from one location are always ?
what will be the result of the reaction
(CH3COO)2+redP +Cl2
Answer:
(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl
Explanation:
This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.
Help I Will Mark Brainlist !! (ATTACHED IMAGE BELOW) Which of the diagrams below would be the FASTEST? _____ Why? Which of the diagrams below would be the SLOWEST? ____ Why?
Answer:
Fastest C. Reaction time is faster
Slowest A. Reaction time is slower and it takes longer to finish
Explanation:
question is below! please tell me more than the equation.
To convert the astronomical units (AU) into miles, we can use the conversion factor of 1 AU = 93,000,000 miles.
The distances in miles for the given planets and asteroid belt are:
Mercury: 36,015,000 miles (0.387 x 93,000,000)
Venus: 67,146,000 miles (0.722 x 93,000,000)
Earth: 93,000,000 miles (1 x 93,000,000)
Mars: 141,960,000 miles (1.52 x 93,000,000)
Asteroid Belt: 241,800,000 miles (2.6 x 93,000,000)
Jupiter: 484,560,000 miles (5.2 x 93,000,000)
Saturn: 893,940,000 miles (9.58 x 93,000,000)
Uranus: 1,789,440,000 miles (19.2 x 93,000,000)
Neptune: 2,796,300,000 miles (30.1 x 93,000,000)
Pluto: 3,679,250,000 miles (39.5 x 93,000,000)
Therefore, the distances in miles for the given planets and asteroid belt are as above.
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A 2.00 g sample of ammonia is mixed with 4.00 g of oxygen. Which is the
limiting reactant and how much excess reactant remains after the reaction
has stopped?
Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Given data:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Excess reactant's amount left = ?
Solution:
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol