Answers
ANSWER:
1.3 times faster
STEP-BY-STEP EXPLANATION:
Given:
Distance ostrich = 56 m
Time ostrich = 14.5 s
Initial velocity = 0 m/s
To calculate the final velocity of the ostrich we use the following formula:
\(\begin{gathered} d=0.5(v_f+v_i)\Delta t \\ \\ \text{ we solve for }v_f \\ \\ 56=0.5(0+v_f)14.5 \\ \\ 56=7.25v_f \\ \\ v_f=\frac{56}{7.25}=7.7\text{ m/s} \end{gathered}\)Now, we calculate the average velocity of the ostrich, like this:
\(\begin{gathered} v_o=\frac{v_i+v_f}{2}=\frac{0+7.7}{2} \\ \\ v_o=3.9\text{ m/s} \end{gathered}\)We calculate the time it would take the ostrich to travel 100 meters with the following formula:
\(\begin{gathered} d=0.5(v_{f}+v_{i})\Delta t \\ \\ \text{ we replacing} \\ \\ 100=0.5\left(0+7.7\right)\Delta t \\ \\ \Delta t=25.9\text{ sec} \end{gathered}\)now we calculate the time of the cheetah knowing that it takes 5.7 seconds less:
\(\begin{gathered} t_c=t_o-5.7 \\ \\ t_c=25.9-5.7=20.2\text{ sec} \end{gathered}\)Now, we can calculate the final velocty of the cheetah using the following formula:
\(\begin{gathered} d=0.5(v_{f}+v_{i})\Delta t \\ \\ \text{ we replacing} \\ \\ 100=0.5\left(v_f+0\right)20.2 \\ \\ v_f=\frac{100}{10.1} \\ \\ v_f=9.9\text{ m/s} \end{gathered}\)Now we calculate the average velocity, like this:
\(\begin{gathered} v_c=\frac{v_i+v_f}{2}=\frac{0+9.9}{2} \\ \\ v_c=4.95\text{ m/s} \end{gathered}\)we calculate the ratio between the two to know how many times the cheetah is faster:
\(r=\frac{4.95}{3.9}=1.3\)Therefore, the cheetah is 1.3 times faster than the ostrich.
Related Questions
the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
Answers
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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one deterrent to burglary is to leave your front porch light on all the time if your fixture contains the 23 watt compact fluorescent bulb at 120 volts and your local power utility cell's energy at ten cents per kilowatt-hour how much will it cost to leave the bulb on for the entire month
Answers
Answer:
Cost = 165.6 cents = $1.656
Explanation:
First, we will calculate the total energy consumed by the bulb in a month:
\(E=Pt\\\)
where,
E = Energy Consumed = ?
P = power = 23 W
t = time = (1 month)(30 days/1 month)(24 h/1 day) = 720 h
Therefore,
\(E = (23\ W)(720\ h)\\E = 16560\ Wh = 16.56\ Kilowatt-hour\)
Now, the cost will be:
\(Cost = P(Unit\ Cost)\\Cost = (16.56\ kilowatt-hour)(10\ cents/kilowatt-hour)\)
Cost = 165.6 cents = $1.656
Frequency= Wavelength = 502 km Speed= 100 m/s
Answers
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.
T/F if the electric field is zero everywher(e inside a region of space, the potential must also be zero in that region.
Answers
No. It just indicates that potential is a continuous. So because derivative of the a constant is 0 as well as the total if 0 is a constant, the only way to obtain 0 for field is for the potential to be constant.
What might be an illustration?Possibility: anything that could happen. The potential advantages of the new medicine have doctors quite enthused. Critics claim that the factory could endanger the environment. growth potential for the institution. He might run for president, according to some.
Is the possibility good?A positive charge is always surrounded by a positive potential. The potential decreases and approaches zero as you go further from the charge. As you move further away, it becomes less encouraging.
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A dog can provide sufficient power to pull a sled with a 60 N force at a steady 2.0 m/s. Suppose the dog is hitched to a different sled that requires 120 N to move at a constant speed. How fast can the dog pull this second sled?
Answers
Answer:
v = 1.0 m/s
Explanation:
Applying the definition of power (rate of change of energy with respect to time), and the definition of average speed, we can say that the power is the product of the net force applied, times the speed achieved by the force on the mass of the object, as follows:P = F* vIn this case, this power can be written as follows:P = 60 N * 2.0 m/s = 120 J/s = 120 WIf the power remains constant, but now it is required a force of 120 N to move the sled at a constant speed, it is clear that the maximum speed possible will be 1.0 m/s, due to 120 N* 1.0 m/s = 120 W, which is the maximum power available.
1. The drawing shows a skateboarder moving at 5.4 m/s along a horizontal section of a track that is
slanted upward by 48° above the horizontal at its end, which is 0.40 m above the ground. When she
leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air
resistance, find the maximum height H to which she rises above the end of the track.
Answers
Projectile motion is the curved path motion of a body launched into the air near the Earth's surface and having a horizontal velocity.
The maximum height to which the skateboarder rises, H, is approximately 0.6 meters above the end of the track.Reason:
Given parameter are;
Initial velocity of the skateboarder, v₁ = 5.4 m/s
Inclination of the track, above the horizontal, θ = 48°
Height of the end of the elevated track, h ≈ 0.40 m
Path of the skateboarder when she leaves the track = Path of a projectile
Required:
Maximum height H to which she rises above the end of the track.
Solution;
From v² = u² - 2·g·h, at the end of the track where;
h = 0.40 m
u = Initial velocity = 5.4
g = 9.81 m/s²
We have;
v₂² ≈ 5.4² - 2 × 9.81 × 0.40 = 21.312
The velocity at which she leaves the track, v₂ ≈ √(21.312 m²/s²).At the maximum height, H, we have;
\(\displaystyle v__y\) = 0
Therefore, from \(\displaystyle v__y\)² = \(\displaystyle u__y\)² - 2·g·H, where;
\(\displaystyle u__y\)² = 2·g·H
\(H = \dfrac{u_y^2}{2 \cdot g}\)Which gives;
\(H = \dfrac{21.312}{2 \times 9.81} \times sin^2(48^{\circ}) \approx 0.6\)Therefore;
The maximum height to which she rises above the end of the track, H ≈ 0.6 m.Learn more about projectile motion here:
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A test charge of 2 C is placed in a field where the E-field = 7 N/C. What is the force on the test charge? You must show your work to earn any credit.
Answers
The force on the test charge is 14 N.
When a test charge is placed in an electric field, it experiences a force. The strength of the electric field is measured in newtons per coulomb, and the magnitude of the force exerted on the test charge is proportional to the amount of charge on it. The formula to calculate the force is given by:
F = q*E
where F is the force, q is the amount of charge on the test charge, and E is the strength of the electric field. Given:
Test charge = 2 C CoulombsElectric field = 7 N/C
Using the formula above,
F = q*E = 2C * 7N/C = 14 N
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A battery has 2 cells .Each of the potential difference 1.2v.If the cells are connected in parallel and the total current flowing through is 4.0A.Draw a circuit diagram to show the circuit arrangement
Answers
The connection of the circuit is shown in the image attached here.
What is a parallel?
When we heat that a connection is done in parallel our minds would have to go to a connection that is made to common junction. The implication of this is that there are wires that would come out from each of the cells and that the wires would be joined at a common point.
Many different applications, including electric automobiles where many batteries may be connected in parallel to enhance the range and power output of the vehicle, can benefit from the parallel connection of cells.
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if one food calorie which equals 1000 "chemistry" calories equals 4184 J, then how far could you go on one cookie containing 50 calories ?
Answers
On one cookie containing 50 calories, you could potentially go approximately 298 meters
How to calculate the valueGiven that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:
50 food calories * 4184 J/calorie = 209,200 joules
Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).
Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)
Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)
Distance ≈ 298 meters
Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters
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the strength of the electric field at a certain distance from a point charge is represented by e. what is the strength of the electric field at twice the distance from the point charge? the strength of the electric field at a certain distance from a point charge is represented by e. what is the strength of the electric field at twice the distance from the point charge? at twice the distance, the strength of the field is 4e. at twice the distance, the strength of the field is e/2. at twice the distance, the strength of the field is 2e. at twice the distance, the strength of the field is e/4. at twice the distance, the strength of the field remains equal to e.
Answers
At twice the distance from a point charge, the strength of the electric field is 1/4 of its original value, so it is e/4.
The electric field is a fundamental concept in physics and is used to describe the force that a charged particle experiences in a given electric field. It is a vector quantity that represents the force per unit charge and is defined as the force that a charged particle would experience if placed at a given point in space. The electric field is created by a charged object and acts on other charged objects placed in its vicinity, causing them to experience a force. The strength of the electric field decreases with increasing distance from the charged object and its direction is defined as the direction in which a positive test charge would be pushed. The electric field is a crucial aspect of many areas of physics, including electromagnetism, circuits, and electronics.
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If a stone dropped into a well reaches the waters surface after 3.0 seconds how far did the stone drop before hitting the water
Answers
Stone travels at the distance of 44.1 meters far did the stone drop before hitting water.
What is the distance ?
Distance is a numerical and sometimes qualitative measure of how far apart an object or point is. In physics or everyday use, distance can refer to estimates based on physical length or other criteria.
How can distance used in real life?
I am using it in my navigation. Airplane pilots use distance formulas to calculate the distance between their plane and other planes. Find the coordinates of the plane and then apply the distance formula to get the distance.
What is the use of distance?
(i) indicate body position at any point in time; (ii) You can see a graph of the distance your body has moved in a certain period of time. (iii) The object's velocity can be determined at any point in time.
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What is the subject Physic about
Answers
Explanation:
Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.
Answer:
if you are very excited to know why ball doesn't go up
Which statement explains why a blue car does not appear to be red?
A. Blue light is absorbed by the car.
B. Red light is absorbed by the car.
C. Blue light is transmitted through the car.
D. Red light is transmitted through the car.
Answers
Answer: B. Red light is absorbed by the car.
Explanation:
The colour of the object is decided by the wavelength of light that it reflects.
Light with the longest wavelength appears red, and light with the shortest wavelength appears violet. The wavelengths of visible light that an object reflects or transmits determine the color that the object appears to the human eye.
The blue car appears blue as it absorbs red light and reflects blue colour.
A stone of mass 6.74kg is dropped from rest at a height of 6.02m. What impulse does gravity impart to this stone from the instant is dropped until it hits the ground, assuming negligible air resistance?
Answers
The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns
What is impulse?
This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
How to determine the timeInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 6.02 mTime (t) =?h = ½gt²
6.02 = ½ × 9.8 × t²
6.02 = 4.9 × t²
Divide both side by 4.9
t² = 6.02 / 4.9
Take the square root of both side
t = √(6.02 / 4.9)
t = 1.1 s
How to determine the impulseTime (t) = 1.1 sMass (m) = 6.74 kgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 6.74 × 9.8 = 66.052 NImpulse =?Impulse = Force × time
Impulse = 66.052 × 1.1
Impulse = 72.66 Ns
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8. A weight lifter lifts a set of weights a vertical distance of 2 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights? Please show full working out ( not in words)
Answers
Answer: Work = change in energy which can be calculated by force * displacement so taking this we can multiply 350n by *2m and we can come out with 700 joules
Explanation: I Hope This Helps I'm new at this.
1.How are elements arranged on the periodic table in terms of valence electrons?
2. Show some evidence using data tables
3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.
Answers
Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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explain the relationship between distance, time, mass, velocity, and momemtum.
Answers
The relationship between distance, time, mass, velocity, and momentum is p = m v = m d / t
p = m v
v = d / t
p = Momentum
m = Mass
v = Velocity
d = Distance
t = Time
p = m v
m v = m d / t
Momentum is the quantity of an object with mass in motion. It is directly proportional to mass and velocity. Velocity is the rate of change of distance with respect to time.
Therefore, the relationship between distance, time, mass, velocity, and momentum is p = m v = m d / t
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what is the value of Stephen's constant ?
thankyou ~
Answers
Convert 3.45inches into km
Answers
Answer:
can someone please answer this i need this for a mastery test aswell
Explanation:
it would be very appreciated
Answer:
3.45 inches = 8.763e-5 kilometers
18v 30 hms For 60 hms Calculate the Current I1 I2 and I3
Answers
For a 18V source and resistors of 30Ω and 60Ω, I1 is 0.6A, I2 is 0.3A, and I3 is 0.9A.
To calculate the currents (I1, I2, and I3), we can use Ohm's law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by the resistance of the conductor.
Voltage (V) = 18V
Resistance (R1) = 30Ω
Resistance (R2) = 60Ω
To find the current I1 flowing through the 30Ω resistor, we use Ohm's law:
I1 = V / R1
Substituting the values:
I1 = 18V / 30Ω
I1 = 0.6A
Therefore, the current I1 is 0.6A.
To find the current I2 flowing through the 60Ω resistor, we again use Ohm's law:
I2 = V / R2
Substituting the values:
I2 = 18V / 60Ω
I2 = 0.3A
Therefore, the current I2 is 0.3A.
To find the current I3, we need to consider the circuit configuration. Assuming the resistors are connected in series, the total resistance (\(R_t_o_t_a_l\)) can be calculated by summing the individual resistances:
\(R_t_o_t_a_l\) = R1 + R2
\(R_t_o_t_a_l\) = 30Ω + 60Ω
\(R_t_o_t_a_l\) = 90Ω
Now, we can find the current I3 using Ohm's law:
I3 is the total current flowing in the circuit, which can be calculated by adding the currents flowing through R1 and R2:
I3 = I1 + I2
I3 = 0.6A + 0.3A
I3 = 0.9A (Amperes)
In summary, with an 18V source and resistors of 30Ω and 60Ω, the currents can be summarized as follows: I1 = 0.6A, I2 = 0.3A, and I3 = 0.9A.
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Picture is question i need help as soon as possible
Answers
Answer:
32.7 m
Explanation:
If it is in the air for 5.16 s the highest point is at one-half of this time
= 5.16/2 = 2.58 s <====== at this point velocity = zero
vf = vi + at
0 = vi - 9.8 (2.58) shows vi = 25.3 m/s
d = vi t + 1/2 at^2
= 25.3 (2.58) - 1/2 (9.8) (2.58^2 ) = max height = 32.7 meters
An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?
Answers
Answer: Displacement = -2.39 m
Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:
Displacement = Final position - Initial position
Displacement = (-4.27 m) - (-1.88 m)
Displacement = -4.27 m + 1.88 m
Displacement = -2.39 m
Therefore, the displacement of the object is -2.39 m.
Please mark me brainliest if you understand now! Thank you
The mass of a material is a/an ___________.
Answers
Answer:
Extensive property
Explanation:
Answer:
Extensive property
Explanation:
Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
Answers
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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With a current shunt, the current is obtained by measuring _____ across the current shunt and calculating using Ohm's Law
Answers
With a current shunt, the current is obtained by measuring voltage across the current shunt and calculating using Ohm's Law.
A current shunt is a device that is used to measure electric current. It is a small resistor placed in parallel with the load (or the element being measured), that creates a known small voltage drop proportional to the current flowing through it.
By measuring this voltage drop and using Ohm's law, the current flowing through the shunt (and the load) can be calculated. Current shunts are commonly used in high-current applications, such as in power plants, electrical distribution systems, and electric vehicles.
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With a current shunt, the current is obtained by measuring the voltage drop across the current shunt and calculating using Ohm’s Law. A current shunt is a device that creates a low-resistance path for electric current, to allow it to pass around another point in the circuit. In current measuring, shunts allow the measurement of high current values by placing a resistor of low, known resistance in parallel with a voltmeter.
Identify the isotope that has atoms with 117
neutrons, 77 protons, and 77 electrons.
1. None of these
2. 194Ir
3. 77Pt
4. 117Hg
5. 117Os
6. 194Au
7. 77Ti
Answers
Explanation:
Since the atomic number is 77, this means that the element is iridium (Ir). The nucleide notation of this element is
\(^{194}_{\:\:77}\text{Ir}\)
Find distance between two object of radius 6 cm and 2 cm
Answers
The distance between two objects of radius 6 cm and 2 cm is zero
To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.
Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.
The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.
Substituting the values, we have d = 6 cm + 2 cm = 8 cm.
Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:
Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.
The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.
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what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k
Answers
The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.
To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:
C = A × B
Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.
Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:
C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)
Now, let's expand the cross product using the properties of vector products:
C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +
(3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +
(1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)
Now, let's calculate each of these cross products:
C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +
(3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +
(1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)
Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:
C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k
Combining like terms, we get:
C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)
Simplifying further:
C = 6.00i - 12.00j + k
Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.
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The vector product of A and B is -3i - 5j - 9k.
Explanation:The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.
In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.
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An electron with a velocity of 14.4 m/s in the positive y-direction enters a region where there is a uniform electric field of 201 N/C in the positive x-direction. The mass of the electron is 9.109 × 10−31 kg.
What is the y-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in μm?
What is the x-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in m?
Answers
1. The electron experiences acceleration and moves independently in the y-direction.
2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.
3. The x-component of displacement remains zero.
To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:
1. Acceleration of the Electron:
The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.
Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:
F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)
= -3.216 × \(10^-^1^7\) N
Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:
a = F / m
= (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)
= -3.530 × \(10^1^3 m/s^2\)
2. Displacement in the y-direction:
Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:
y = (1/2) * a *\(t^2\)
Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:
y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)
= -8.11 μm
Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.
3. Displacement in the x-direction:
Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.
Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.
Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.
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Hey Motors and lamps both use...
electricity that isn't moving
electric current
Both a and b
Answers
Answer:
both
Explanation: