Hello, I needed help with a physics assignment. It is fill-in-the-blanks; however, there aren't any word choices.

Answer:

\(Va-Vb=168KV\)

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\(\sqrt{0.3^2+0.4^2} =0.5\)

at  opposite sides

Mathematically Va can represented as

\(Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(0.00001333333-0.000004} )\)

\(Va =84000V\)

\(Va =84KV\)

Mathematically Vb is  represented as

\(Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )\)

\(Va =9*10^9(-0.00001333333+0.000004} )\)

\(Va =-84000V\)

\(Va =-84KV\)

Therefore

\(Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV\)

Answer:

n × t_1/2

Exmplanation:

The age of meteorite is calculated by multiplying it's quantity n with the half life . This means that the formula is for age of this meteorite is;

Age of meteorite= n × t_1/2

where;

n = quantity of the meteorite

t_/2 = half life of the meteorite

Thus:

The correct formula is; n × t_1/2

Explanation:

answer is 6.0Kg •m/s because

momentum= mass • velocity

that is 5 • 1.2 = 6

When a typical comet in the Oort cloud is only 1 km in diameter, then the mass of the Oort cloud is changes to  4.18×10⁹ kg.

The mass of each comet int he Oort cloud is,

mass = density × Volume

volume of sphere = 4/3(π×r²) where, r = radius of the sphere

From the given,

diameter = 1 km

radius = Diameter / 2 = 1/2(D)

Volume of the comet = 4/3 (π×r²) = 4/3 (π× (1/2 (10)³)²)

                                   = 4/3×(π) ×(1/8×10⁶)

Mass = density  × volume, where density = 1000 kg/m³

         = 1000  × 4/3×(π) ×(1/8×10⁶)

        = 4.18 ×10⁹ kg

When the typical comet in the Oort cloud is only 12 km in diameter the mass of Oort cloud is 4.18×10⁹ kg.

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Answer:

D. Iron is more easily magnetized than steel but steel is more easily demagnetized than iron.

Answer:

Newton's second law of motion

Answer:

Speed

Explanation:

Ii is given that, "A teenager received a ticket for driving 80 miles per hour.". It doesn't give any information about the direction of motion. It means it represents the speed of teenager. Speed is a scalar quantity. It doesn't have direction.

Hence, the given information describes the teenager's speed.

Answer:

Speed! :)

Explanation:

There is no reference to the direction, which cancels out velocity and direction. In addition, they don't mention the initial speed and the time, so acceleration is out, leaving your answer... SPEED:)

Hope this helps, have a marvelous day!

Answer:

A) 1.76U×10⁻³N

B) 2.716×10⁻³N

C) 264.5⁰

Explanation:

See detailed workings for (a), (b), (c) attached.

When the liquid cools down, it loses heat energy.

As the liquid cools, it loses heat energy. As a result, its particles slow down in movement and come closer to one another. Attractive forces begin to hold particles and the crystals of a solid form.

If water is cooled, it can change into ice. If ice is warmed, it can change into a liquid state. Heating a substance makes the molecules move very fast whereas cooling a substance makes the molecules move very slowly.

Heating a liquid increases the speed of the molecules present in it. An increase in the molecule's speed competes with the attraction between molecules and results in the molecules moving apart whereas Cooling a liquid decreases the movement of the molecules.

So we can conclude that the liquid cools down when it loses heat energy.

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ANSWER:

STEP-BY-STEP EXPLANATION:

We know that the force is equal to the following:

We know that the force is equal to the following:

Answer:

The correct response will be "13.755 kN".

Explanation:

According to the question,

The given values are:

a = 300 mm

i.e.,

  = 0.3 cm

b = 200 mm

i.e.,

  = 0.2 dm

Internal pressure,

\(P_{in}=100\)

Now,

The area of the elliptical shape window will be:

⇒  \(A = \pi ab\)

On substituting the values, we get

⇒      \(=3.14\times 0.300\times 0.200\)

⇒      \(=0.1885 \ m^2\)

By using the table,

At 10 km, the atmospheric pressure will be

⇒  \(p_o=27.03 \ kPa\)

Now,

The outward force will be:

⇒  \(F_{net}=p_{in}A-p_{0}A\)

⇒          \(=(p_{in}-p_{0})A\)

⇒          \(=(100-27.03)\times (0.1885)\)

⇒          \(=13.755 \ kN\)

Answer:

Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work

Answer:

Explanation:

Walrus' kinetic energy = 2.05 x \(10^6\) J.

To calculate the walrus' kinetic energy,

we need to use the formula KE = 0.5\(mv^2\), where m is the mass of the walrus and v is its velocity.

We know the mass of the walrus is 907 kg and its velocity is 23 m/s.

Substituting these values in the formula, we get KE = 0.5 x 907 x \((23)^2\) = 2.05 x\(10^6\) J.

Therefore, the walrus' kinetic energy is 2.05 x \(10^6\) J.

It is important to note that kinetic energy is the energy an object possesses due to its motion, and is directly proportional to both its mass and velocity.

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Answer:

force needed for the bus to go round the corner is 50,000 N.

Explanation:

To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:

F = (mv^2)/r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.

Plugging in the values given in the problem, we get:

F = (2500 kg)(5 m/s)^2 / 50 m

= 50,000 N

So the force needed for the bus to go round the corner is 50,000 N.

The speed of the ball have in falling 3.6 s is 35.5 m/s.

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.

Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.

Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.

Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.

Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.

Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.

Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.

Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.

Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.

Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.

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The average acceleration of snowboarder's is 0.19 m/s² and distance travel by snowboarder is 6.70 metres.

We have given that snowboarder start moving from rest means

Initial speed (u) = 0 m/s

Final speed (v) = 1.6 m/s

time taken (t) = 8.4 s

Applying first equation of motion

v = u + at

1.6 = 0 + a×8.4

1.6 = 8.4a

a = 1.6/8.4 m/s²

a = 0.19 m/s²

So average acceleration is 0.19 m/s².

Now Applying second equation of motion

s = ut + 1/2at²

s = (0) × (8.4) + (1/2)(0.19)(8.4)² metre

s = (1/2)(0.19)(8.4)²  metre

s = 6.70 metre

So that distance covered by snowboarder is 6.70 metre.

So we find out the average acceleration by using first equation of motion and the average acceleration came out to be 0.19 m/s² and to find out the distance covered by snowboarder we use second equation of motion and the distance came out to be 6.70 metre.

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A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)

Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.

Using the formula Force = Pressure × Area

given Pressure = 50 N/\(m^{2}\)

area = 0.25 \(m^{2}\)

Substituting the values ,

Force = 12.5 Newton

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Answer:

56

Explanation:

I just want the points to be completely honest with you.  

Explanation:

\(\boxed{\sf{K.E = \dfrac{1}{2} \times m \times v^2}}\)

Let's Do!

\(\boxed{\sf{14 = \dfrac{1}{2} \times 17 \times v^2}}\)

\(\boxed{\sf{\dfrac{14 \times 2}{17} = v^2}}\)

\(\boxed{\sf{ \sqrt{\dfrac{14 \times 2}{17}}= v}}\)

So, 1.283 m/s is the required answer.

Answer:

Behind the retina is a layer of shiny, blue-green stuff called the tapetum. This layer assists night vision by reflecting light back through the retina.

Explanation:

Pls mark me as brainliest plss

Answer:

c

Explanation:

Answer:

Resistivity and conductivity are reciprocal quantities.

Doubling one will cause the other to be reduced to one half.

Answer:

Displacement = 167.63 m  

Explanation:

Distance refers to the total ground covered by an object while in motion while displacement refers to how far an object is from it's original position.

Now, we are told that the helicopter flies 160m horizontally and then flies 50m downwards.

This means that it's displacement will be the distance from its final position to the initial position.

This can be represented with a triangle attached.

From the triangle, the displacement d will be gotten from pythagoras theorem.

Thus;

d² = 160² + 50²

d² = 25600 + 2500

d² = 28100

d = √28100

d ≈ 167.63 m

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The work exerted on the car by the engine is 250 Joules.

What is Work?

Work is a physical quantity that is defined as the force applied to an object over a distance. It is a scalar quantity and is measured in units of joules (J) in the International System of Units (SI). The formula for work is W = F x d, where F is the force applied and d is the distance over which the force is applied.

The work exerted on the car by the engine can be calculated using the formula:

Work = Power x Time

Since the car is moving at a constant velocity, we can calculate the time it takes for the engine to exert the given power by using the formula:

Velocity = Work / Time

So, we can find time by using:

Time = Work / Velocity

Substituting the given values, we have:

Time = (750 watts) / (3m/s)

Therefore, the work exerted on the car by the engine is:

Work = Power x Time

Work = 750 watts x (750 watts / 3m/s)

Work = 750 * 250 Joules

So, the work exerted on the car by the engine is 250 Joules.

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Answer:

0J

Explanation:

No work is being done on the wall by the man pushing on it.

 Given parameters:

Mass of man  = 75kg

Mass of wall  = 500000kg

Time  = 250s

Unknown:

Work done  = ?

Solution:

Work done is the force applied on a body that moves it along a particular path.

For work to be done, distance must be move or displacement must occur.

Since the wall is not moving the distance is 0;

    Work done  = Force x distance

Since distance is 0m, work done is 0J

The work done on the wall by the man is 0 J.

To calculate the amount of work done by the man, we use the formula below.

Formula:

Where:

from the question,

Given:

Substitute these values into equation 1

Hence, the work done on the wall by the man is 0 J.

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Answer: