Hello could you please help me with this problem? Write an equation in standard form for the line that has an undefined slope and passes through (-6,4).

Answer:

SI derived units

Other quantities, called derived quantities, are defined in terms of the seven base quantities via a system of quantity equations. The SI derived units for these derived quantities are obtained from these equations and the seven SI base units.

Explanation:

Hope this helps :D

We are given:

Mass of the Crate(m) = 71 kg

Applied force(F) = 577 N

Resolving the applied force:

To solve this problem, we will first make a free-body diagram (attached)

The Applied force has been resolved into 2 components denoted by a thinner line and 'g' is the acceleration due to gravity

We found the values by using basic trigonometry

Finding the Normal Force:

Normal force is equal and opposite to the net force applied on the ground. So, we will subtract the vertical component of the applied force from the weight of the crate.

Normal force = mg - F*Sin(27°)

Normal force = [(71)*(9.8)] - [ (577)(0.454) ]                           [g = 9.8 m/s²]

Normal Force = 433.84 N

Answer:

3.03°

Explanation:

Given that

Height of the tree branch, h = 4.5 m

Distance of the veterinarian away, d = 85.5 m

The vet is to aim at the monkey at a particular angle. If we consider the force of gravity that will be acting on the dart. Then the angle that will be needed will be calculated as this.

So the angle is

Tan θ = opposite / adjacent

Tan θ = 4.5 m/ 85.5 m

Tan θ = 0.053, then

θ = Tan^-1 (0.053)

θ = 3.03°

Therefore, the angle needed is 3.03°

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)

GPE = 15,998.95 J (joules)

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Answer:

vt3bryhtevy4g24vu5hy4

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Simple Answer. Mass cannot change.

Force=Acceleration

Based on the mass and luminosity of the Sun, the time required to convert of its original hydrogen into helium is 7.505 × 10^10 years.

Nuclear fusion is the process whereby nucleus of lighter atoms are fused together to produce heavier atoms with the release of large amounts of energy.

Nuclear fusion occurs at the core of the sun where four hydrogen atoms are fused to form one helium atom with the release considerable energy, and this is known as hydrogen fusion.

The mass of the Sun = 2.0 × 10^30 kg

The Sun’s hydrogen mass is 0.71 × 2.0 × 10^30 kg = 1.42 × 10^30 kg.

The Sun converts 6 × 10^11 kg of hydrogen into helium per second.

Time required to convert all of the Sun's hydrogen to helium = 1.42 × 10^30 kg/6 × 10^11 kg/s

Time required = 2.367 × 10^18 seconds

Converting to years:

3.154 × 10^7 seconds = 1 year

2.367 × 10^18 seconds = 2.367 × 10^18 seconds * 1 year/3.154 × 10^7 seconds

Time required = 7.505 × 10^8 years

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The potassium atom has a 19 atomic number. Potassium contains 19 protons total. Potassium contains 20 neutrons in total. The mass number for potassium is calculated using the formula: 19+20 = 39.

The first step in calculating the number or atoms is to determine the number in moles. To get the amount of moles in an element or compound, divide the supplied mass by the element or compound's molar mass. The amount of atoms in One mole of a given substance is N A, or 6. 023 10 23 atoms.

The quantity of substance that composes an element's atom is known as its atomic mass. One among the mass of the a carbon-12 atom, with an assigned atomic mass of 12 units, is expressed in a fraction or 1.992646547 1023 grams, or 1.992646547 g. One atom's mass unit is equal to 1.660539040 1024 gram on this scale (amu).

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Answer:

Ok

Explanation:

Answer:

1. cell membrane

2. golgi body

3. mitochondrion

4. cytoplasm

5. nucleolus

6. nucleus

Explanation:

The correct answer to this question is Option A; 6.

Why?

In a plant cell, the nucleus surrounds the nucleolous, which would be number 5. Therefore, number 6 would be your correct answer.

~Thank you~

Answer:

projectile motion

total time of flight= 2V° Sintheta / g

answer is 3second

Hope This would help you!

Answer:

chinese

Explanation:

Answer:

B chinese

hope this helps you

Answer:

They are isotopes of each other

Explanation:

Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons.

For atom A and atom B, their number of protons is the same (10)

But their number of neutrons is different (12) and (10)

When a wave is in phase, the frequencies and periods are the same, meaning they pass the same points at the same times.

Incorrect answers:

Have different frequencies

Pass given points at different times

Weaken one another; when two waves are in phase, their crests, or high points, line up with each other and amplify each other because when added, the sum is a total of the two wave values.

Correct answer: Strengthen one another

The required coefficient of kinetic friction between the box and the floor is calculated to be 0.14.

We should draw the free-body diagram of the box.

Weight of the box is given as 78 N.

W = m g = 78 N

Kinetic friction f k = μk N

where,

μk is coefficient of kinetic friction

N is the normal force

Newton's second law mathematically states,

F = m a

where,

F is force

m is mass

a is acceleration

The horizontal component of F is given as Fx = 21 N

The vertical component of F is given as Fy = 27 N

From the free-body diagram, we can write the equations,

Fx - f k = m a ---(1)

N - Fy - W = 0 ---(2)

N = Fy + W = 27 + 78 = 105 N

Putting known values in (1),

Fx - f k = m a

f k = Fx - m a = 21 - (78/9.8) a

The acceleration of the box is given as 0.84 m/s².

f k = 21 - (78/9.8) (0.84) = 21 - 6.69 = 14.31 N

f k = μk N

14.31 = μk (105)

μk = 0.14

Thus, the coefficient of kinetic friction is calculated to be 0.14.

The given question is incomplete. 'Calculate the coefficient of kinetic friction between the box and the floor.'

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The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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Answer:

60 kilometers per hr

Explanation:

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.

The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.

So, the mass of the block of lead is approximately 1.63 metric tons.

Answer:

electromagnetic waves only

Explanation:

I just took the test, Hope it helps!

Answer:

A: Electromagnetic waves only

Explanation:

Answer:

C. Constant

Explanation:

The total energy of the cannonball remains constant as it travels through the air.

Answer:

Explanation:

hi my name is Ava

Answer:

\(\boxed {\boxed {\sf 2.2 \ m/s^2}}\)

Explanation:

We are asked to solve for the magnitude of the car's acceleration.

We are given the initial speed, final speed, and distance, so we will use the following kinematic equation.

\({v_f}^2={v_i}^2+2ad\)

The car is initially traveling at 15.0 meters per second and accelerates to 20.0 meters per second over a distance of 40.0 meters. Therefore,

Substitute the values into the formula.

\((20.0 \ m/s)^2= (15.0 \ m/s)^2 + 2 a (40.0 \ m)\)

Solve the exponents.

\(400.0 \ m^2/s^2 = 225.0 \ m^2/s^2 + 2 a(40.0 \ m)\)

Subtract 225.0 m²/s² from both sides of the equation.

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 225.0 \ m^2/s^2 -225 \ m^2/s^2 +2a(40.0 \ m)\)

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 2a(40.0 \ m)\)

\(175 \ m^2/s^2 = 2a(40.0 \ m)\)

Multiply on the right side of the equation.

\(175 \ m^2/s^2 =80.0 \ m *a\)

Divide both sides by 80.0 meters to isolate the variable a.

\(\frac {175 \ m^2/s^2}{80.0 \ m}= \frac{80.0 \ m *a}{80.0 \ m}\)

\(\frac {175 \ m^2/s^2}{80.0 \ m}=a\)

\(2.1875 \ m/s^2 =a\)

Round to the tenths place. The 8 in the hundredth place tells us to round the 1 up to a 2.

\(2.2 \ m/s^2=a\)

The magnitude of the car's acceleration is 2.2 meters per second squared.

Answer:

The final pressure inside the container is 107.7 atm

Explanation:

Given;

volume of the closed container =  7.20 L

mass of liquid helium in the container = 10.9 g

initial temperature of the container = 3.00 K

initial pressure of the container = 1.00 atm.

final temperature of the container = 293 K

Number of moles of He in the container = 10.9 / 4 = 2.725 moles

At 273˚K and 1 atm pressure (STP), the volume of 1 mole of a gas = 22.4 L

Volume of 2.725 moles of He at STP = 2.725 x  22.4 = 61.04 L

Volume of 2.725 moles of He at 3 K and 1 atm = (3/273) x 61.04 = 0.671 L

Thus, volume of He = 0.671 L

Volume of air in the container = 7.2 L – 0.671 L = 6.529 L

Since, the liquid helium evaporated, we only have air left in the container,

thus, final volume of the container, V₂ =  6.529 L

Initial volume of the container, V₁ = 7.20 L

Initial pressure of the in the container, P₁ = 1 atm

initial temperature of the container, T₁ = 3 K

Final temperature of the container, T₂ = 293 K

Final pressure of the container, P₂ = ?

Apply general gas law, in order to estimate P₂

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\\\P_2 = \frac{P_1V_1T_2}{T_1V_2} \\\\P_2 = \frac{1*7.2*293}{3* 6.529}\\\\P_2 = 107.7 \ atm\)

Therefore, the final pressure inside the container is 107.7 atm

Explanation:

K.E =1/2 mv^2

=1/2(156789)(45.6)^2

=78,394.5 × 2,079.36

=163,010,387.52 kg m/s

This should be your answer.

A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.

The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

The Brundtland Commission was set up with the intention to achieve sustainable development. The tenure of the commission lasted from 1984 to 1987.

The commission identified the pillars of sustainable growth as economic growth, environmental protection, and social equality. The committee opined that environmental problem emanates from poverty in the southern region and reckless consumption of resources in the northern region.

The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.

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The current is 1.13* 10^{-4}A

Given that r = radius of the coil = 4 cm = 0.04 m

Area of coil is given as

A = πr²

A = (3.14) (0.04)² = 0.005024 m²

N = Number of turns = 500

R = Resistance = 600 Ω

B = magnetic field = (0.0120)t + (3 x 10⁻⁵) t⁴

Taking derivative at both the side

\( \frac{dB}{dt} = (0.120 + (12 \times 10^-5)t^3)\)

Induced current is given as

\(i= (\frac{NA}{R} )( \frac{db}{dt} )\)

\(i \: = (\frac{NA}{R})(12 \times 10 ^{-5} )t^3\)

substituting the value t = 5

\(i = ( \frac{(500)(0.005024)}{600}) (12 \times 10 ^{-5} )5^3\)

\(i = 1.13 \times 10 ^{ - 4} A\)

Hence the current is

\(1.13 \times 10^-4A\)

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The Electric current is 1.11* 10^{-4}A


Given that the coil's radius is 3.55 cm (0.35 m),

The formula for the coil's area is A = r2 A = (3.14) (0.35)2 = 0.005024 m2.

R = Resistance = 600 N = Number of spins = 500 B = Magnetic field = (0.0120)

t + (3 x 10⁻⁵) t⁴

The number t = 5 is substituted for taking the derivative at both the induced current and the electric current.

The Electric current is therefore 1.11* 10^{-4}A
Electric current - The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure. These electrons can be held loosely or securely depending on the situation.

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