Heat is added to a chemical system. Which energy will increase?


A-the activation energy of the system


B-the relative potential energy of the system


C-the kinetic energy of the reactant molecules


D-the potential energy of the products

In reference to the given data concerning the separation of the mixture, the percent by mass of salt in the mixture is 73.9%.

To find the percent by mass of salt in the mixture, we need to divide the mass of salt by the total mass of the mixture and multiply by 100.

First, we need to calculate the mass of sand in the mixture:

Mass of sand = Total mass of mixture - Mass of salt

Mass of sand = 2.18 g - 1.61 g = 0.57 g

Now we can calculate the percent by mass of salt in the mixture:

Percent by mass of salt = (Mass of salt / Total mass of mixture) x 100%

Percent by mass of salt = (1.61 g / 2.18 g) x 100%

The percent by mass of salt = 73.9%

Therefore, the percent by mass of salt in the mixture is 73.9%.

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The pH of the 0.400 M sodium formate solution is approximately 1.90, which is closest to option (A) 2.07.

The condition for the separation of formic corrosive (HCHO₂) is:

HCHO₂ + H₂O ↔ H₃O⁺ + CHO²⁻

The balance steady articulation for this response is:

Ka = [ H₃O⁺][CHO²⁻]/[HCHO₂]

From the given data, we realize that the Ka of formic corrosive is 1.8 x 10^-4. We likewise know that sodium formate (NaCHO₂) is a salt of formic corrosive and it will separate totally in water to shape Na+ and CHO²⁻particles. The CHO²⁻ particle will respond with water to frame HCHO₂ and Goodness particles.

NaCHO₂(s) ↔ Na+(aq) + CHO²⁻(aq)

CHO²⁻(aq) + H2O(l) ↔ HCHO₂(aq) + Gracious (aq)

Since NaCHO₂ totally separates in water, we can expect that [CHO²⁻] = [NaCHO₂] = 0.4 M.

Let x be the centralization of  H₃O⁺ particles shaped in the response. Then, [OH-] = \(1.0 x 10^-14/x\).

Utilizing the harmony consistent articulation, we can compose:

\(1.8 x 10^-4 = x^2/(0.4 - x)\)

Since x << 0.4, we can surmised (0.4 - x) to be 0.4.

\(1.8 x 10^-4 = x^2/0.4\)

\(x = sqrt(1.8 x 10^-4 x 0.4) = 0.0126 M\)

pH = - log[H3O+] = - log(0.0126) = 1.90

Consequently, the pH of the 0.400 M sodium formate arrangement is roughly 1.90, which is nearest to choice (A) 2.07.

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Milk of magnesia is typically absorbed in the stomach and small intestine. As an antacid, it neutralizes stomach acid, which can help to relieve symptoms of indigestion and heartburn.

Milk of magnesia is an oral suspension of hydrated magnesium carbonate in water. It is used as an antacid to neutralize stomach acid and relieve symptoms of indigestion and heartburn. It is typically taken by mouth and is absorbed in the stomach and small intestine. It is not absorbed into the bloodstream and does not have a systemic effect on the body. It can also be used as a laxative.

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Answer and Explanation:

Your answer is...

The stars appear to move together along a path because of Earth's rotation on its axis.

Answer:

C. Stars appear to move together along a path because of the earths rotation on its axis.

Explanation:

lol ik its right bc I got a 100 on my science test:)

The acid strength of a compound generally increases as you move down a group in the periodic table.

The case of the compounds you mentioned, the ranking from lowest to highest acid strength would be as follows:

1. \(H2O\) (water)

2.\(H2S\) (hydrogen sulfide)

3\(. H2Se\) (hydrogen selenide)

4.\(H2Te\) (hydrogen telluride)

Water (H2O) is a neutral compound and has very limited acidity. Hydrogen sulfide (H2S) is a weak acid compared to water. Hydrogen selenide (H2Se) is stronger in acidity than hydrogen sulfide. Finally, hydrogen telluride (H2Te) is the strongest acid among the compounds listed.

It's important to note that all of these compounds are relatively weak acids, and their acidity increases as you move down the group in the periodic table due to the larger size of the atoms and the weaker bond strength between hydrogen and the respective element.

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Answer:

core

Explanation:

Answer:

It is getting thicker and keeping the Earth warmer.

Answer:

it is getting thinner and keeping the earth warmer

When a car runs out of gas, pushing on the car's windshield from the inside will not move the vehicle forward. This is because the windshield is not connected to the car's propulsion system.

The engine of a car requires fuel (such as gasoline) to combust and generate power, which is then transmitted to the wheels to propel the car. Pushing on the windshield does not provide any additional fuel or mechanical force to move the car.

To move a car without fuel, physical force must be applied to the car's body, such as pushing it from the front or back. This relies on the principle of Newton's laws of motion, where an external force is required to change the motion of an object. However, pushing on the windshield alone would not exert sufficient force on the car's body to overcome friction and inertia.

Additionally, the windshield of a car is not designed to withstand the force of pushing from the inside. It is made of glass or a combination of glass and laminated plastic, primarily intended to protect occupants from wind, debris, and provide structural integrity to the car's cabin. Applying force to the windshield could result in damage or even shattering, posing a risk to the occupants.

In summary, when a car runs out of gas, pushing on the car's windshield from the inside will not move the vehicle forward due to the lack of fuel and the windshield's structural limitations.

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Answer:

200g or 40 teaspoons

Explanation:

An average human, weighing about 50 pounds, has about 200 g or 40 tps of NACl

Answer:

The angular alignment is 90 degrees

Explanation:

The neap tide is a type of tide which occurs around seven days after a spring tide. This type of tide happens twice every month.

The tide is usually moderate and it exists when the sun and moon are usually at right angles to each other when it occurs. A right angle is also known as 90 degrees which validates the tide occurring at an angle 90.

Answer: B) 10 ml

Explanation:

According to the dilution law,

\(M_1V_1=M_2V_2\)

where,  

\(M_1\) = molarity of  stock \(NaOH\) solution = 1.0 M

\(V_1\) = volume of stock \(NaOH\) solution = 2.0 ml  

\(M_1\) = molarity of dilute \(NaOH\)  solution = 0.20 M

\(V_1\) = volume of diluted \(NaOH\) solution = ?

Putting in the values we get:

\(1.0\times 2.0=0.20\times V_2\)

\(V_2=10ml\)

Therefore, final volume reading is 10 ml

0.026 moles is the right answer.

We have that for the Question "How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K?" it can be said that  moles of xenon gas is

n=0.22moles

From the question we are told

How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K?

Generally the equation for the ideal gas is mathematically given as

\(n=\frac{Pv}{RT}\\\\n=\frac{0.64*8.5}{0.08206*300}\)

n=0.22moles

Therefore

How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K is

n=0.22moles

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Answer:

Total pressure is the sum of all partial of all components

150mmHg + 350mmHg + 200mmHg = 700mmHg

700mmHg = 0.92atm

The following reactions of alkenes is not stereospecific is C. acid-catalyzed hydration reaction (H₂O/H₂SO₄)

Stereospecific reactions occur when the stereochemistry of the reactant is retained in the product. These types of reactions are distinguished by the use of double-headed arrows in reaction mechanisms to demonstrate the conservation of stereochemistry. The following reactions of alkenes stereospecific are hydrogenation (H₂/P₁), bromination (Br₂ in CH₂Cl₂), bromohydrin formation (Br₂/H₂O).

The acid-catalyzed hydration reaction (H₂O/H₂SO₄) of alkenes is not stereospecific because the H and OH atoms can be added to either face of the alkene's double bond. When the reaction occurs, an intermediate carbocation is formed, which is planar. This carbocation can either be attacked by the nucleophile from above or below, resulting in the formation of an equal amount of stereoisomers. Therefore, the correct answer is C. acid-catalyzed hydration reaction (H₂O/H₂SO₄) is not stereospecific.

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Answer:

Explanation:

Naming ionic compounds building a triangle so that each edge has the same answers facing each other

Answer:

phenolphthalein

Explanation:

In the titration of strong acid and strong base, phenolphthalein is used as suitable indicator.

The compound that will form the most intensely colored 0.01 M aqueous solution will depend on the specific compound and its ability to exhibit color in solution.

The compound that will form the most intensely colored 0.01 M aqueous solution will depend on the specific compound and its ability to exhibit color in solution. Without knowing the specific compounds being considered, it is difficult to provide a definitive answer. Different compounds can exhibit a wide range of colors based on their molecular structure and electronic transitions.

In general, compounds with highly conjugated systems or transition metal complexes tend to exhibit intense colors in solution. These compounds often have extended delocalized π-electron systems that allow for absorption of light in the visible range, resulting in the observed color.

To determine which compound would form the most intensely colored solution, it would be necessary to consider the specific compounds and their molecular structures, including the presence of conjugated systems or transition metal ions. Conducting experiments or consulting references specific to the compounds in question would provide more accurate information regarding their coloration in aqueous solution.

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To find the mass percent of oxygen in Mn3(PO4)2, calculate the molar mass of the compound, determine the mass of oxygen, and calculate the mass percent.

To find the mass percent of oxygen in the compound Mn3(PO4)2:

a. Calculate the molar mass of the entire compound:

  Mn: 3 atoms × atomic mass of Mn

  P: 2 atoms × atomic mass of P

  O: 8 atoms × atomic mass of O

b. Calculate the mass of the oxygen in the compound:

  Multiply the number of oxygen atoms by the molar mass of oxygen.

c. Divide the mass of the oxygen in the compound by the total molar mass and multiply by 100% to get the mass percent of oxygen.

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Before scientists publish their data and conclusions in scientific journals, they ask other experts in the same field to review the work and ensure that the results and conclusions are valid. This is known as Peer review.

Research project outcomes are evaluated by the scientific and medical communities after publication in peer-reviewed journals. It also offers guidelines so that additional researchers might carry out the experiment or expand on it to validate the findings.

Before a paper is published, its quality is evaluated through a process called peer review. To assist editors in deciding whether to publish a manuscript in their journal, independent researchers in the relevant field evaluate submitted manuscripts for originality, validity, and significance.

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To determine the order of the reaction with respect to the ligand and substrate, we can use the method of initial rates.

For the substrate, we keep the concentration of the ligand constant at 1.0 M and vary the substrate concentration to get the following initial rates:

[substrate] (M) | [ligand] (M) | rate (M/s)
--- | --- | ---
1.0 | 1.0 | 5
5.0 | 1.0 | 25
10.0 | 1.0 | 50

When we double the substrate concentration from 5.0 M to 10.0 M, we see that the rate of the reaction also doubles. This suggests that the reaction is first order with respect to the substrate.

For the ligand, we keep the concentration of the substrate constant at 5.0 M and vary the ligand concentration to get the following initial rates:

[substrate] (M) | [ligand] (M) | rate (M/s)
--- | --- | ---
5.0 | 1.0 | 25
5.0 | 5.0 | 125
5.0 | 25.0 | 625

When we increase the ligand concentration from 1.0 M to 5.0 M, we see that the rate of the reaction increases by a factor of 5. When we increase the ligand concentration from 5.0 M to 25.0 M, we see that the rate of the reaction increases by a factor of 5 again. This suggests that the reaction is second order with respect to the ligand.

Therefore, the rate equation for this reaction is:

Rate = k [substrate]^1 [ligand]^2

where k is the rate constant.

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The temperature of the equilibrium mixture should be increased. The given decomposition reaction of \(CaCO_3\) to CaO and \(CO_2\) is endothermic, which means that the reaction requires heat to proceed.

Increasing the temperature of the equilibrium mixture will favor the endothermic reaction, causing more \(CaCO_3\) to decompose into the CaO and the \(CO_2\). As a result, the production of carbon dioxide will increase. This is because the forward reaction (decomposition of \(CaCO_3\)) is favored at higher temperatures due to the heat being absorbed by the reaction. Therefore, to increase the production of carbon dioxide in this reaction, the temperature of the equilibrium mixture should be increased.

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The EPA's claim that sulfur dioxide levels have fallen by 85% between 1990 and 2016 is accurate based on the calculation of the percent decrease.

To determine whether the EPA's claim about the decrease in sulfur dioxide levels is accurate, we can calculate the percent decrease between 1990 and 2016.

Step 1: Find the difference between the initial and final values.
The initial value in 1990 is 100% (the entire amount of sulfur dioxide levels).
The final value in 2016 is 15% (85% decrease from the initial value).

Step 2: Calculate the percent decrease.
To find the percent decrease, we subtract the final value from the initial value and then divide the result by the initial value. Finally, we multiply by 100 to express the decrease as a percentage.

Percent decrease = [(Initial value - Final value) / Initial value] * 100
Percent decrease = [(100 - 15) / 100] * 100
Percent decrease = (85 / 100) * 100
Percent decrease = 85%

Therefore, the calculated percent decrease between 1990 and 2016 is 85%, which matches the EPA's claim. The claim is accurate as the percent decrease aligns with the EPA's statement that sulfur dioxide levels have fallen by 85% during this time period.

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Answer:

lewis structures :

Explanation:

4 electrons

6 electrons outer shell

3 outer shell

2 outer shell

7 outer shell

1 outer shell.

v

Answer: The heat required to raise the temperature of 179 g of acetic acid, is 21000 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(Q=m\times c\times \Delta T\)

Q = Heat absorbed  = ?

m = mass of acetic acid = 179 g

c = heat capacity of acetic acid = \(2.043J/g^0C\)

Initial temperature  = \(T_i\) = \(25^0C\)

Final temperature = \(T_f\)  = \(82.7^0C\)

Change in temperature ,\(\Delta T=T_f-T_i=(82.7-25)^0C=57.7^0C\)

Putting in the values, we get:

\(Q=179g\times 2.043J/g^0C\times 57.7^0C=21100J\)

Thus heat required to raise the temperature of 179 g of acetic acid, is 21000 Joules

Dates are collected carefully and with a lot of laborious work, much as how they are cultivated. After adding water and filtering the homogenized result with a cellulose filter aid, date fruits are removed using a wet grinding process.

The polysaccharide cellulose, an organic molecule with the formula n, is made up of a linear chain of several hundred to many thousands of D-glucose units that are covalently bonded.

Plant cell walls include the carbohydrate cellulose. The structure of the carbohydrate is polysaccharide. A lengthy chain of many sugar units joined by chemical bonding makes up a polysaccharide. Examples of polysaccharides include starch, chitin, glycogen, cellulose, and glycogen.

Use of a reach lift varies greatly depending on the size of the trees. This lift carries an employee up the trees to gather the date bunches. The filtering aid might be date pits. Before filtering, a fermentation may be performed.

Thus, Dates are collected carefully and with a lot of laborious work, much as how they are cultivated.

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The linear equation relationship between the time in hours and the temperature is y = (2.67x + 60) ⁰F .

The relationship between the amount of time that has passed in hours and the temperature can be defined using the linear equation. The linear equation should follow this rule

y = mx + c

where y is the effect parameter, m is the gradien, x is cause parameter and c is the initial state of effect parameter.

The gradien can be found by using this formula

m = Δy / Δx

From the question above, the given parameters are

y = temperature

x = time

Δy = 2 ⁰F

Δx = 45 min = 0.75 hour

c = 60 ⁰F

Find the gradien

m = Δy / Δx

m = 2 / 0.75

m = 2.67

The relationship between temperature and time should be

y = mx + c

y = (2.67x + 60) ⁰F

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Metallic behavior correlates with large atomic size and low ionization energy. This is true. In metallic behavior, a metal atom tends to lose electrons easily and form positive ions. When these atoms are packed together in a solid metal, they form a lattice that consists of positively charged ions and free electrons, which are free to move throughout the lattice.

When atoms have low ionization energies, it is easier for them to lose electrons and become positive ions. So, large atomic size and low ionization energy can lead to metallic behavior. A larger atomic size means that there is more distance between the nucleus and the outermost electrons. This means that the valence electrons are not as strongly attracted to the nucleus, and it is easier for them to be removed. Low ionization energy means that the energy required to remove an electron from an atom is low. So, when an atom with low ionization energy is in contact with another atom, it tends to lose electrons easily and become a positive ion. This positive ion then attracts the electrons from the other atom, forming a metallic bond. Thus, metallic behavior correlates with large atomic size and low ionization energy. This is because these properties make it easier for metal atoms to lose electrons and become positive ions, leading to metallic bonding.

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The correct statements are that a rock is considered an ore when it contains at least one metallic mineral in sufficient amounts to be extracted profitably and when it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

Step-by-step explanation:

When it occurs in sufficient amounts to be used to build roads and buildings: This statement is incorrect. Rocks that are used for construction purposes, such as limestone or sandstone, are not considered ores unless they also contain economically valuable minerals.

Only when it contains lead: This statement is incorrect. Ores are not limited to containing only lead. Ores can contain various metallic minerals, not just lead.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably: This statement is correct. Ores are rocks that contain valuable metallic minerals in concentrations that make extraction economically feasible. These minerals can include gold, silver, copper, aluminum, zinc, and many others.

Only when it contains iron: This statement is incorrect. While iron ores are commonly known and widely used, ores are not limited to containing only iron. There are numerous other metallic minerals that can be extracted profitably from rocks.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably: This statement is correct. Fluorite and sulfur are examples of non-metallic minerals that can be extracted profitably from rocks, and if a rock contains these minerals in sufficient quantities, it can be considered an ore.

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