halp please and thank you??????????​

Answer:6/3÷2/4=4

Step-by-step explanation: i hope its the rght

answer

The value of expression after divide is,

⇒ 4

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

The expression is,

⇒ 6/3 divided by 2/4

Now, We can divide the numbers as;

⇒ 6/3 divided by 2/4

⇒ 6/3 ÷ 2/4

⇒ 2 ÷ 1/2

⇒ 2 × 2

⇒ 4

Hence, The value of expression after divide is,

⇒ 4

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Answer:

Step-by-step explanation:

\(Slope = \dfrac{1-0}{0-[-7]}=\dfrac{1}{0+7}=\dfrac{1}{7}\)

Answer:

-57.6 degrees

Step-by-step explanation:

0 is a point between 53.6 degrees and -4 degrees.

The change from 53.6 to 0 was -53.6 degrees, and that from 0 to -4 degrees was -4 degrees.  

Thus, the total change (drop) in temperature was -53.6 degrees less 4 degrees, or -57.6 degrees.

Answer:

x=5

Step-by-step explanation:

3x-1.5=13.5

+1.5 +1.5

3x=15

÷3 ÷3

x=5

Theorem 4.3.9 can be proved using either the 0 characterisation of continuity or the sequential characterisation of continuity. Both characterisations are important and useful in different situations.

Theorem 4.3.9: Suppose f: X → Y. TFAE:(i) f is continuous on X(ii) For every open subset V of Y, the inverse image f^-1 (V) is open in X(iii) For every convergent sequence x_n→x, we have f(x_n)→f(x).

A proof for Theorem 4.3.9 using the 0 characterisation of continuity is given below:

Suppose f: X → Y is continuous on X. Let V be open in Y. Let a∈f^-1 (V). Then f(a)∈V, so there exists an ɛ > 0 such that B(f(a), ɛ) ⊆ V.

Since f is continuous at a, there exists a δ > 0 such that x ∈ X and d(x, a) < δ implies d(f(x), f(a)) < ɛ. That is, f(B(a, δ)) ⊆ B(f(a), ɛ) ⊆ V.

This implies B(a, δ) ⊆ f^-1 (V). Thus f^-1 (V) is open in X.For the other direction, suppose for every open subset V of Y, the inverse image f^-1 (V) is open in X. Let a ∈ X. Let ɛ > 0. Set V = B(f(a), ɛ). Then V is open in Y, so f^-1 (V) is open in X.

Since a ∈ f^-1 (V), there exists a δ > 0 such that B(a, δ) ⊆ f^-1 (V). Then f(B(a, δ)) ⊆ V. That is, d(f(x), f(a)) < ɛ whenever d(x, a) < δ. Thus f is continuous at a.This gives us a proof of Theorem 4.3.9 using the 0 characterisation of continuity.

A proof for Theorem 4.3.9 using the sequential characterisation of continuity is given below:Suppose f: X → Y. Suppose (x_n) is a sequence in X converging to x. Then (x_n) is a net in X. By Theorem 4.3.2(iii), if f is continuous at x, then f(x_n) converges to f(x).Now suppose that for every convergent sequence (x_n) in X that converges to x, we have f(x_n) converges to f(x).

Let V be open in Y. Let a∈f^-1 (V). Suppose that f is not continuous at a. Then there exists an ɛ > 0 such that for every δ > 0, there exists an x ∈ B(a, δ) such that d(f(x), f(a)) ≥ ɛ. Let δ_n = 1/n. Then for each n, there exists x_n ∈ B(a, δ_n) such that d(f(x_n), f(a)) ≥ ɛ. Then (x_n) converges to a, but (f(x_n)) does not converge to f(a). This contradicts our assumption.

Thus f is continuous at a.Hence we have a proof for Theorem 4.3.9 using the sequential characterisation of continuity.

We first showed the proof of Theorem 4.3.9 using the 0 characterisation of continuity.

We then showed the proof of Theorem 4.3.9 using the sequential characterisation of continuity.We used the 0 characterisation of continuity to show that f is continuous on X if and only if for every open subset V of Y, the inverse image f^-1 (V) is open in X. This result follows from the definitions of continuity and openness.

We used this characterisation to prove Theorem 4.3.9. We showed that f is continuous on X if and only if for every convergent sequence x_n→x, we have f(x_n)→f(x).

This characterisation is important because it allows us to prove continuity of a function using the open sets of the codomain. We do not need to use sequences or nets to prove continuity.

This is useful in some cases where we cannot use sequences or nets, for example, in metric spaces that are not first-countable.We then used the sequential characterisation of continuity to show that f is continuous on X if and only if for every convergent sequence x_n→x, we have f(x_n)→f(x).

This characterisation follows from the definition of continuity and the sequential characterisation of convergence. We used this characterisation to prove Theorem 4.3.9. We showed that f is continuous on X if and only if for every open subset V of Y, the inverse image f^-1 (V) is open in X.

This characterisation is important because it allows us to prove continuity of a function using sequences.

This is useful in many cases, for example, in metric spaces that are first-countable. It also allows us to prove that some spaces are not first-countable by finding a function that is not continuous using sequences.

Therefore, Theorem 4.3.9 can be proved using either the 0 characterisation of continuity or the sequential characterisation of continuity. Both characterisations are important and useful in different situations.

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the slope would be 2/4

Answer:

8

Step-by-step explanation:

4/9 of 18 is 8

Answer:

None of these

Step-by-step explanation:

\(\frac{x^{2}}{2} +\frac{y^{2}}{3} =\frac{4sin^{2}t}{2} +\frac{9sin^{2}t}{3} =5\times sin^{2}t\)

\(x^{2}+y^{2}=13\sin^{2} t\)

\(3x^{2}+2y^{2}=30\sin^{2} t\)

Answer:

n = 65; p = 0.8

Step-by-step explanation:

The sample size (n) and sample proportion () can a normal curve be

used to approximate the sampling distribution is n = 65, p = 0.8.

The correct option is D.

According to the Central Limit Theorem, the shape of sample distribution of sample proportions with a population proportion, 'p' is normal

If n·p ≥ 10 and n·(1 - p) ≥ 10.

n = 65, p = 0.8

∴ n·p = 65 x 0.8 = 52 > 10

n·(1 - p) = 65 × (1 - 0.8) = 13 > 10

For n = 90, p = 0.9, n·(1 - p) = 18 > 10, a normal distribution can be used to approximate the sampling distribution.

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Answer:

George had $725 in savings

Step-by-step explanation:

Let's assume that George had x dollars in savings before he bought the camera.

According to the problem, George spent 80% of his savings to buy the camera, which means he had 20% of his savings left after the purchase. We can write this as:

0.20x = amount of savings left after buying the camera

We also know that the camera cost $580. We can set up an equation to relate the cost of the camera to the amount of savings that George had before buying the camera:

0.80x = $580

Solving for x, we get:

x = $580 / 0.80

x = $725

Therefore, George had $725 in savings before he bought the camera.

Answer: These two polygons are congruent. YX corresponds to CD. The correct option among all the options that are given in the question is the first option or option "A". 

"MP" is the one angle or side among the following choices given in the question that is common to TRIANGLE NPW and TRIANGLE OMP . The correct option among all the options that are given in the question is the second option or option "B".

Step-by-step explanation:

Answer:

It's AB

Step-by-step explanation:

To determine the house's value one year later, we multiply the house's value by 1.07.

a. The value of the house at any given moment during the first five years is 107% of the value of the house exactly one year earlier. This is because the value increased by 7% each year.

b. To determine the house's value one year later, we multiply the house's value by 1.07. This is because the value increased by 7%.

c. The function that determines the value of the house in thousands of dollars in terms of the number of years since Brayen purchased the house is:
f(t) = 190(1.07)^t
where t is the number of years since Brayen purchased the house and f(t) is the value of the house in thousands of dollars.

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Answer:

18.3824%

Step-by-step explanation:

Sorry, this may be wrong. I am using an old skill, so it may be wrong.

The Proportional relationship y = 10x is a good fit for the data.

What is a proportional relationship?

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality,

i.e., y = kx

In which k is the constant of proportionality.

For this problem, foe each value of x, the output is 10 times that, hence the constant is k = 10 and the proportional relationship y = 10x is a good fit for the data.

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Answer:

The Proportional relationship y = 10x is a good fit for the data.

You sent 19 text messages. Let's start by using variables to represent the unknown quantities in the problem. Let t be the number of text messages sent, and let p be the number of pictures sent.

We know that it costs $0.07 to send a text message and $0.12 to send a picture, and we also know that the total amount spent was $3.38. So we can write two equations based on this information:

0.07t + 0.12p = 3.38 (equation 1)

t = 2p (equation 2)

We can use equation 2 to substitute for t in equation 1:

0.07(2p) + 0.12p = 3.38

Simplifying this equation gives:

0.26p = 3.38

p = 13

So you sent 13 pictures. Now we can use equation 2 to find the number of text messages sent:

t = 2p = 2(13) = 26

So you sent 26 text messages. However, we should check if this answer is consistent with the total amount spent:

0.07(26) + 0.12(13) = 1.82 + 1.56 = 3.38

This checks out, so the final answer is that you sent 26 text messages and 13 pictures.

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Answer:

D) 7.7

Step-by-step explanation:

√60= 7.7459 and so on

and 7 2/3 in a decimal form= 7.66666

The only number between those two is 7.7

The dog's running speed of 5 km/hr can be converted to approximately 3.125 mi/hr by multiplying it by the conversion factor of 1 mi/1.6 km. Rounding to the nearest thousandth, the dog can run at about 3.125 mi/hr.

To convert the dog's running speed from kilometers per hour (km/hr) to miles per hour (mi/hr), we need to use the conversion factor of 1.6 km = 1 mi.First, we can convert the dog's speed from km/hr to mi/hr by multiplying it by the conversion factor: 5 km/hr * (1 mi/1.6 km) = 3.125 mi/hr.

However, we need to round the answer to the nearest thousandth (three decimal places). Since the digit after the thousandth place is 5, we round up the thousandth place to obtain the final answer.

Therefore, the dog can run at approximately 3.125 mi/hr.

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An equal tangent vertical curve with an initial grade of 2.0% and a final grade of -1.0% has the value of A as 333.33 ft (130 words).An equal tangent vertical curve refers to a vertical curve consisting of two straight grades, with equal tangents at the vertex of the curve. The value of A is the length of the curve.

The formula for finding the length of an equal tangent vertical curve is given as follows:

\($$L=\frac {100A}{R} $$\)

Where, L is the length of the curve in feet,R is the radius of the curve in feetA is the algebraic difference in grades multiplied by 100Hence, the value of A for an equal tangent vertical curve that has an initial grade of 2.0% and a final grade of -1.0% can be calculated as follows:

\($$A= \frac {Final grade - Initial grade}{2}= \frac {-1-2}{2} = -\frac {3}{2} $$\)

Therefore, the length of the curve can be found as follows:

\($$L= \frac {100(-3/2)}{R}$$$$L= -50\frac {ft}{R} $$\)

The radius of the curve will be infinite if both grades are equal.

Therefore, the formula for an infinite radius is used to find A as follows:

\($$A= 2\Bigl(\frac {L}{3}\Bigr)$$\)

Substituting the value of L, we get:

\($$A= 2\Bigl(\frac {-50}{3}\Bigr)$$\)

\($$A= -\frac {100}{3} ft$$\)

However, since A is a length, it cannot be negative.

Therefore, taking the absolute value of A gives us the length of the equal tangent vertical curve, which is:

\($$A= \frac {100}{3} = 33\frac {1}{3} ft $$\)

Rounding up to the nearest whole number, the value of A is approximately 333.33 ft.

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The Blu-ray movie will cost approximately $36.42 in 5 years with an inflation rate of 12% and continuous compounding.

To calculate the future cost of the Blu-ray movie in 5 years with an inflation rate of 12% and continuous compounding, we can use the formula for continuous compound interest:

A = P * e^(rt)

Where:

A = Future value

P = Present value

e = Euler's number (approximately 2.71828)

r = Annual interest rate (in decimal form)

t = Time period in years

In this case, the present value (P) is $19.99, the inflation rate (r) is 12% or 0.12, and the time period (t) is 5 years. Substituting these values into the formula, we get:

A = 19.99 * e^(0.12 * 5)

Calculating the exponent first:

0.12 * 5 = 0.6

Then:

e^0.6 ≈ 1.82212

Finally:

A = 19.99 * 1.82212 ≈ 36.42

Using the formula for continuous compound interest, we calculated that a Blu-ray movie that costs $19.99 today will cost approximately $36.42 in 5 years, assuming an inflation rate of 12% and continuous compounding.

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Answer:

8

Step-by-step explanation:

16-8=8

\(\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+4}x\stackrel{\stackrel{c}{\downarrow }}{+6} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 4}{2(1)}~~~~ ,~~~~ 6-\cfrac{ (4)^2}{4(1)}\right) \implies \left( - \cfrac{ 4 }{ 2 }~~,~~6 - \cfrac{ 16 }{ 4 } \right) \\\\\\ \left( -2 ~~~~ ,~~~~ 6 -4 \right)\implies (-2~~,~~2)\)

The probability of selecting a bird would be = 2/15

Probability is defined as the ability of an outcome to occur by chance or not.

The formula that can be used to calculate the outcome of an event= P(E) = number of favorable outcomes/Total number of outcomes

Where, P(E) is the probability of any event.

Let E be an event of selecting an insect.

According to the given question

We have

Total number of insects = 10

Total number of trees = 8

Total number of flowers = 8

Total number of birds = 4

Now, the total number of outcomes = 10 + 8 + 8 + 4 = 30

Total number of favorable outcomes(birds) = 4

Therefore,

The probability of selecting a bird = 4/30 = 2/15

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Complete question:

A stack of 30 science flashcards includes a review card for each of the

following: 10 insects, 8 trees, 8 flowers, and 4 birds.

What is the probability of randomly selecting a bird.

The gravitational potential energy change during the climb is approximately 4974.6 Joules.

The gravitational potential energy change can be calculated using the formula:

ΔPE = mgh

Where ΔPE is the change in gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the change in height.

First, we need to calculate the change in height. Since the road has a slope of 4.3 degrees, we can use trigonometry to find the vertical component of the climb:

h = l * sin(θ)

Where l is the length of the road and θ is the slope angle in radians. Converting 4.3 degrees to radians, we have:

θ = 4.3 * (π/180) ≈ 0.0749 radians

Substituting the values, we get:

h = 1200 * sin(0.0749) ≈ 91.32 meters

Next, we can calculate the gravitational potential energy change:

ΔPE = (72 kg) * (9.8 m/s²) * (91.32 m) ≈ 4974.6 Joules

Therefore, the gravitational potential energy change during the climb is approximately 4974.6 Joules.

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Answer:

$230

Step-by-step explanation:

Hes paid 200 for his wages but if he works overtime by 12 hours he gets half of the 5 dollars he earns per hour which is 2.5 which then is 2.5 times 12 which is then 30 plus the 200 he earned for the 40 hours.

Answer:

D

Step-by-step explanation:

16m-(5+8m)

this expression change like

16m-5-8m

1.644 gml⁻¹ is is the new volume of the water .

What is density, ?

density = mass/volume

     ρ  = 12.5/7.6

      ρ = 1.644 gml⁻¹

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The right answer is -2/3

please see the attached picture for full solution

Hope it helps..

Good luck on your assignment..

Answer:

-2/3

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

(10-12)/(5-2) = -2/3

Answer:

Step-by-step explanation:

I understand

A solution in mathematics is any value of a variable that makes the specified equation true.

On, the other hand, a solution set is the set of all variables that makes the equation true.

For example;

the solution set of 2y + 6 = 14 is 4 because 2(4) + 6 = 14.

In summary, 4 is the solution set in the above example because it makes the equation true.

Also, when an equation has two variables, the set of ordered pairs that are the solution to the equation are called the solution set to the equation.

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