Graph the equation 4x+8y=16 (pls show ur work)

Answer:

quadrant 1 - (2,4)

quadrant 2 - (-3,4)

quadrant 3 - (-1, -5)

quadrant 4 - (6, -1)

Step-by-step explanation:

quadrant one consists of both x and y being positive.

quadrant two being the x is negative but the y is negative.

quadrant 3 has its x and y both negative.

finally, quadrant 4 has its x positive, but y is negative.

By calculation, your grade in the class now is 78.7

From the question, we have the following parameters that can be used in our computation:

Score of 47.2 in 60

Represent the score in 100% with x

So, we have the following equation

47.2/60 = x/100

Multiply both sides of the equation by 100

So, we have

100 * 47.2/60 = x/100 * 100

This gives

100 * 47.2/60 = x

So, we have

x = 100 * 47.2/60

Evaluate

x = 78.7

Hence, your grade in the class now is 78.7

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steal it

Step-by-step explanation:

Answer:

sorry i think a

Step-by-step explanation:

Step-by-step explanation:

1) x^2-5x+x-5

=x(x-5)+1 (x-5)

=(x+1)(x-5)

3) a^2-25

= a^2-(5)^2

= (a+5)(a-5)

The original piece of sheet metal was a square with side length 21 cm.

Let's denote the side length of the square piece of sheet metal as x. When we remove a square of side 6 cm from each corner, the length of each side of the remaining square becomes x-2(6) = x-12. Thus, the base of the box has dimensions (x-12) by (x-12) and the height of the box is 6 cm.

The volume of the box is given by

Volume = Base area x height

Volume = (x-12)² × 6

We are given that the volume is 486 cubic centimeters, so we can set up the equation

486 = (x-12)² × 6

Simplifying and solving for x, we get

81 = (x-12)²

9 = x-12

x = 21 cm

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Answer:

I think it might be 124 feet

When parking downhill next to a curb, you should turn your front wheels into the curb.

This means you should steer the wheels towards the curb or to the right if you are in a country where vehicles drive on the right side of the road.

By turning the wheels into the curb, it provides an extra measure of safety in case the vehicle rolls downhill. If the brakes fail, the curb will act as a barrier, preventing the car from rolling into traffic.

Turning the wheels away from the curb leaves the vehicle vulnerable to rolling freely downhill and potentially causing an accident.

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Answer:

x=74

Step-by-step explanation:

We know this triangle is an isosceles, because there are two angles that are congruent and one angle that isn't, because x=x.

All angles in a triangle add up to 180, so to find the value of x, we can use this equation: 180=32+x+x

We can simplify by combining the x's:

180=32+2x

Then subtract 32 to isolate the variable

148=2x

And divide by 2

The answer would be 74.

Answer:

0.7 for one letter. 1.5 for flat fee...

Step-by-step explanation:

Answer:  \(y=\frac{3}{4} x\)

Step-by-step explanation:

        We will create a point-slope equation to solve.

        First, we need to find the slope.

\(\displaystyle \frac{y_2-y_1}{x_2-x_1}= \frac{6--3}{8--4} =\frac{9}{12} =\frac{3}{4}\)

        Next, we will create our point-slope equation.

\(\displaystyle y-y_1=m(x-x_1)\)

\(\displaystyle y--3=\frac{3}{4} (x--4)\)

 \(\displaystyle y+3=\frac{3}{4} (x+4)\)

 \(\displaystyle y=\frac{3}{4} x+3 -3\)

 \(\displaystyle y=\frac{3}{4} x\)

Answer:

300ft^2

Step-by-step explanation:

The point of diminishing returns is (20.98, 21247.3).

The point of diminishing returns occurs when the marginal cost of producing an extra unit of output exceeds the marginal revenue generated from selling that unit. Mathematically, it is the point at which the derivative of the production function equals zero and the second derivative is negative.

Given the polynomial function N(x) of degree 3, we can find the point of diminishing returns by finding the critical points where the first derivative equals zero and evaluating the second derivative at those points.

The derivative of N(x) is N'(x) = -18x² + 360x + 2250. To find the critical points, we set N'(x) = 0:

0 = -18x² + 360x + 2250

Dividing by -18 simplifies the equation:

0 = x² - 20x - 125

Using the quadratic formula, we find the solutions to the equation:

x₁,₂ = (20 ± √(20² - 4(1)(-125))) / 2(1)

x₁,₂ = 10 ± 5√5

Thus, the two critical points of N(x) are at x = 10 - 5√5 and x = 10 + 5√5.

To determine the point of diminishing returns, we evaluate the second derivative N''(x) = -36x + 360 at these critical points:

N''(10 - 5√5) = -36(10 - 5√5) + 360 ≈ -264.8

N''(10 + 5√5) = -36(10 + 5√5) + 360 ≈ 144.8

From the evaluations, we find that N''(10 + 5√5) is negative while N''(10 - 5√5) is positive. Therefore, the point of diminishing returns corresponds to x = 10 + 5√5.

To find the corresponding y-coordinate (N(10 + 5√5)), we can substitute the value of x into the original function N(x).

Hence, the point of diminishing returns is approximately (20.98, 21247.3).

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A 13ft ladder is leaning against a wall. If the top of the ladder slips down the wall at a rate of 2 ft/s, then the foot of the ladder will be moving away from the wall at a rate of 4 ft/s when the top is 5 ft above the ground.

This can be determined using the formula Rate = Distance/Time. Since we know that the top of the ladder is slipping down at a rate of 2 ft/s, we can calculate the rate at which the foot of the ladder is moving away from the wall. The distance between the top of the ladder and the foot of the ladder is 8 ft (13 ft - 5 ft). Since the top of the ladder is moving down 2 ft/s, the foot of the ladder must be moving away from the wall at a rate of 4 ft/s.

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a. The standard form of the given linear programming model is as follows:

Objective function: Min Z = 8X1 + 6X2 + 0S1 + 0S2

Subject to:

2X1 + 4X2 - S1 = 8

3X1 + 2X2 - S2 = 6

X1, X2, S1, S2 ≥ 0

b. Using the linear programming simplex method to solve the standard form:

Initial tableau:

```

     BV   |   X1   X2   S1   S2   RHS

-------------------------------------

  Z   |   8     6    0    0    0

-------------------------------------

 S1   |   2     4   -1    0    8

-------------------------------------

 S2   |   3     2    0   -1    6

```

Entering variable: X1 (column with the most negative coefficient in the Z row).

Leaving variable: S1 (minimum ratio of the RHS to the coefficient in the X1 column).

Pivot operation: Divide the S1 row by 2.

```

     BV   |   X1   X2   S1   S2   RHS

-------------------------------------

  Z   |   2     6    0    0    16

-------------------------------------

  S1  |   1     2   -0.5  0    4

-------------------------------------

  S2  |   1.5   2    0.5 -1    2

```

Entering variable: X2 (column with the most negative coefficient in the Z row).

Leaving variable: S2 (minimum ratio of the RHS to the coefficient in the X2 column).

Pivot operation: Divide the S2 row by 2.

```

     BV   |   X1   X2   S1   S2   RHS

-------------------------------------

  Z   |   0     5    1    0    18

-------------------------------------

  S1  |   1     0   -1    1    2

-------------------------------------

  X2  |   0.75  1    0.25 -0.5  1

```

No more negative coefficients in the Z row. Optimal solution found.Solution: X1 = 2, X2 = 0.75, Z = 18. The optimal solution for the given linear programming model is X1 = 2, X2 = 0.75, with the minimum objective value Z = 18.

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As per the BMI, the dependent variable is outcome

In this study, the researcher wants to compare the effectiveness of two different exercise programs in reducing BMI in individuals with diabetes. The participants will be randomly assigned to either the aerobic dancing group or the walking group, and their BMI will be measured before and after the six-month exercise program.

The changes in BMI between the two groups will be compared to determine which exercise program is more effective in reducing BMI in this population. The dependent variable in this study is the change in BMI, as it is the outcome that is being measured and compared between the two groups.

Overall, this study will provide valuable insights into the effectiveness of different exercise programs in reducing BMI in older adults with diabetes, which can have important implications for their overall health and wellbeing.

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After six​ months, the​ subjects' symptoms are studied and compared. Answer parts​ are given below.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

Given:

A pharmaceutical company wants to test the effectiveness of a new allergy drug.

The company identifies 250 females​ 30–35 years old who suffer from severe allergies.

The subjects are randomly assigned into two groups.

One group is given the new allergy drug and the other is given a placebo that looks exactly like the new allergy drug.

After six​ months, the​ subjects' symptoms are studied and compared.

Here, 30-35 year-old girls are used to test the new allergy medication's effects.

(a)

Females between the ages of 30 and 35 who are the test subjects are the experimental units.

The new allergy medication, whose results are being studied, is the remedy.

It's best to choose C.

(b)

A bias may develop if a researcher or patient knows whether subjects received a medication or a placebo.

In this case, choice B is preferable.

(c)

If neither the researcher nor the subject knew whether they were receiving a medicine or a placebo, the study would be considered double-blind.

In this case, choice A is preferable.

Therefore, all the correct choices are given above.

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The complete question is given in the image.

The probability that less than 2 of the tested bottles are contaminated is 20/27.

The probability that less than 2 of the tested bottles are contaminated,  to consider two cases when 0 bottles are contaminated and when 1 bottle is contaminated.

Case 1: 0 bottles contaminated

The probability of a bottle being contaminated is given by the ratio of contaminated bottles to the total number of bottles: 6/18 = 1/3.

The probability of 0 out of 3 bottles being contaminated calculated using the binomial probability formula: P(X=k) = (nCk) ×p²k ×(1-p)²(n-k).

k = 0, n = 3, and p = 1/3.

P(X=0) = (3C0) × (1/3)²0 × (2/3)²(3-0) = 1 × 1 × (8/27) = 8/27.

Case 2: 1 bottle contaminated

Similar to Case 1, the probability of 1 out of 3 bottles being contaminated  be calculated.

P(X=1) = (3C1) × (1/3)²1 × (2/3)²(3-1) = 3 ×(1/3) × (4/9) = 4/9.

To find the total probability of less than 2 bottles being contaminated, sum the probabilities of the two cases:

P(X<2) = P(X=0) + P(X=1) = 8/27 + 4/9 = (8+12)/27 = 20/27.

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The equation of the polynomial is P(x) = (x - 8)(x - 1)(x + 2)

The given parameters are

The sum of multiplicities of the polynomial equation must be equal to the degree.

This means that the multiplicity of the zeros 8, 1 and -2 is 1

The equation of the polynomial is then calculated as

P(x) = (x - zero)^ multiplicity

So, we have

P(x) = (x - 8) * (x - 1) * (x + 2)

This gives

P(x) = (x - 8)(x - 1)(x + 2)

Hence, the equation is P(x) = (x - 8)(x - 1)(x + 2)

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(1) Using the Black/Scholes Option Pricing Model, the value of the call option is $7.70.

(2) The intrinsic value of the call is the difference between the stock price and the strike price of the option. Therefore, it is $4.

(3) The stock price required to break-even is the sum of the strike price and the option premium. Therefore, it is $74.

(4) If volatility were to decrease, the value of the call would decrease.

(5) If the exercise price would increase, the value of the call would decrease.

(6) If the time to maturity were 3-months, the value of the call would decrease.

(7) If the stock price were $62, the value of the call would be zero.

(8) The maximum value that a call option can take is unlimited.

In the Black/Scholes option pricing model, the value of a call option can be calculated using the formula:

C = S*N(d1) - X*e^(-rT)*N(d2)

where S is the stock price, X is the exercise price, r is the risk-free rate, T is the time to maturity, and σ2 is the variance of the stock's return.

Using the given values, we can calculate d1 and d2:

d1 = [ln(S/X) + (r + σ2/2)T]/(σ2T^(1/2))

   = [ln(74/70) + (0.10 + 0.50/2)*0.5]/(0.50*0.5^(1/2))

   = 0.9827

d2 = d1 - σ2T^(1/2) = 0.7327

Using these values, we can calculate the value of the call option:

C = S*N(d1) - X*e^(-rT)*N(d2)

= 74*N(0.9827) - 70*e^(-0.10*0.5)*N(0.7327)

= $7.70

The intrinsic value of the call is the difference between the stock price and the strike price of the option. Therefore, it is $4.

The stock price required to break-even is the sum of the strike price and the option premium. Therefore, it is $74.If volatility were to decrease, the value of the call would decrease. This is because the option's value is directly proportional to the volatility of the stock.

If the exercise price would increase, the value of the call would decrease. This is because the option's value is inversely proportional to the exercise price of the option.

If the time to maturity were 3-months, the value of the call would decrease. This is because the option's value is inversely proportional to the time to maturity of the option.If the stock price were $62, the value of the call would be zero. This is because the intrinsic value of the call is zero when the stock price is less than the strike price.

The maximum value that a call option can take is unlimited. This is because the value of a call option is directly proportional to the stock price. As the stock price increases, the value of the call option also increases.

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The interest cost and the total amount due on a six month loan is  $1500 and total amount due is $1599

SI is equal to 100. r = 10% T=6 months, or 6/12 years.

Idea employed: SI = Prt/100. Interest rate in principle.

Calculation: P = (100 100 12)/(10 6) 100

= (P 10 6)/(12 100)

P = 2000.

For instance, if your current APR is 17.99% and you currently owe $500 on your credit card over the course of the month, you can get your monthly interest rate by dividing 17.99% by 12, which is roughly 1.49%. Then multiply $500 by 0.0149 to get a monthly payment of $7.45.

annual interest = $1,599

 full amount due = ($1,500 + $99).

= $1599

Hence we get the required  answers.

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We are given that

In right triangle ABC, if angle A is 90 degrees, angle C is 34 degrees, and AC is 71.4, find BC.

Solution

We will first draw a diagram to illustrate the information

Above we want to find x

The method to use is SOHCAH

From the right angle triangle above we have above, we have the adjacent side and we want to find the hypotenus, so we use cosine

i.e

We need to solve for x here

Thus, |BC| = 86.1 (to the nearest tenth

Step-by-step explanation:

A. x^2-9x+18

B. x^2-8x+16

C. 2x^2-5x-12

D. 12x^2-31x+7

The way that the sample size would have to change to decrease the length of the confidence interval is to increase from 400 to 1600.

The confidence interval's length is directly proportional to the sample size. The specific relationship between these two factors follows an inverse proportion that correlates to the square root of the sample size.

One could represent this correlation through a proportionality statement: the larger the sample size, the smaller the confidence interval's length becomes.

Given that L1 = 0. 06 and n1 = 400, we want to find n2 such that L 2 = 0. 03:

L1 / L2 = √(n 2 / n 1)

The values would then be:

L1 / L2 = √ ( n2 / n1 )

0.06 / 0.03 = √ ( n2 / 400)

2 = √ (n2 / 400)

2² = ( √ (n2 / 400))²

4 = n2 / 400

n2 = 4 x 400

n2 = 1600

In conclusion, the sample size needs to increase to 1, 600.

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When comparing data sets, it is important to consider different measures such as means, MADs (mean absolute deviations), medians, and IQRs (interquartile ranges).

We need to determine which measures are better for comparing the data sets. The mean is a measure of central tendency that represents the average of the data set, while the MAD measures the average distance between each data point and the mean. Comparing the means can give an overall idea of the average values in the data sets, but the MAD provides information about the spread or variability of the data. On the other hand, the median is another measure of central tendency that represents the middle value in a data set when the data is arranged in ascending or descending order. The IQR is a measure of the spread of the middle 50% of the data. Comparing the medians can give insights into the central values, while the IQR provides information about the spread of the bulk of the data. Which measures are better for comparing the data sets depends on the specific characteristics of the data and the purpose of the comparison. If the data sets have outliers or extreme values that can significantly affect the mean, comparing the medians and IQRs might be more appropriate. However, if the data sets are normally distributed and without outliers, comparing the means and MADs can provide a comprehensive understanding of the average values and variability. It is essential to consider the context, characteristics, and goals of the analysis when choosing the appropriate measures for comparison.

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Answer:

A≈50.27

Step-by-step explanation:

:P

Once we have a sketch of the region ω, we can determine the limits of integration for each variable by looking at the boundaries of the region. We can then change the order of integration by switching the order in which we integrate the variables.

Step 1: Sketch the region ω
To do this, we need the information about the limits of the repeated integral. However, since no specific integral is provided, let's use a general example to illustrate the process. The region ω is typically defined by a set of inequalities that describe the boundaries of the region. These boundaries can be plotted on a graph to give us a visual representation of the region.

Example:
Let's consider a double integral:
∬ ω f(x,y) dy dx, with the limits of integration for y as (g₁(x) ≤ y ≤ g₂(x)), and for x as (a ≤ x ≤ b).

To sketch region ω, we need to plot the bounding curves y = g₁(x), y = g₂(x), x = a, and x = b on a coordinate plane.

Step 2: Change the order of integration
To change the order of integration, we need to express the limits of integration in terms of x.

1. Find the inverse functions of g₁(x) and g₂(x), which are h₁(y) and h₂(y) respectively.
2. Determine the range of y, which will be the new limits of integration for the outer integral.
3. Rewrite the double integral with the new order of integration:
∬ ω f(x,y) dx dy, with the limits of integration for variable x as (h₁(y) ≤ x ≤ h₂(y)), and for y as (c ≤ y ≤ d).

Now, we have successfully sketched the region ω and changed the order of integration for the repeated integral.

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Answer:

x-6=5x+10

x-6-5x=10

-4x-6=10

-4x=10+6

-4x=16

-4x÷-4=16÷-4

x=-4