Good policy and practice dictate that each firewall device, whether a filtering router, bastion host, or other firewall implementation, must have its own set of configuration rules that regulate its actions. This ensures proper security measures are in place for each device, and helps maintain a robust and secure network environment.
A. True. Good policy and practice dictate that each firewall device should have its own set of configuration rules that regulate its actions. This is important to ensure that the firewall is providing the appropriate level of protection for the network and that any changes to the firewall do not impact other devices on the network.
A. True
Good policy and practice dictate that each firewall device, whether a filtering router, bastion host, or other firewall implementation, must have its own set of configuration rules that regulate its actions. This ensures proper security measures are in place for each device and helps maintain a robust and secure network environment.
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The statement "Good policy and practice dictate that each firewall device, whether a filtering router, bastion host, or other firewall implementation, must have its own set of configuration rules that regulate its actions" is True.
Good policy and practice dictate that each firewall device must have its own set of configuration rules to ensure that its actions are regulated and controlled. This helps to ensure that the firewall operates effectively and efficiently, and that any potential security threats are properly identified and addressed.
Without proper configuration rules, a firewall may not be able to effectively block unwanted traffic or prevent unauthorized access to a network, which could lead to serious security breaches and data loss. Therefore, it is essential to implement individualized configuration rules for each firewall device in order to maintain a high level of security and protection for a network.
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Use JAVA and create a class called Airport with the following fields:
Identifier.
Coordinates which consist of Latitude and Longitude. Latitude is positive to indicate is North of the Equator and negative when it's located in the southern hemisphere. Longitude is negative to indicate is West and positive to indicate it's East of the Greenwich median.
A magnetic variation which also is indicated negative for West and positive for East. It is OK to have no magnetic variation.
Elevation above sea level in feet.
For example San Diego airport has the values ID: SAN, Lat: 32.7335556, Long: -117.1896667, Var: 14, Elev: 16.8' (http://www.airnav.com/airport/SAN)
The class should have an accessor and mutator methods for each field.
When the Longitude is negative it is understood it’s on the West side of the Greenwich Meridian and when the Latitude is negative is understood it’s South of the Ecuador.
The "Airport" class in Java is designed to represent an airport with fields such as identifiers, coordinates (latitude and longitude), magnetic variation, and elevation above sea level.
The class includes accessor and mutator methods for each field to retrieve and modify their values. The convention is that negative longitude indicates the airport is located west of the Greenwich Meridian, and negative latitude indicates it is south of the equator.
The "Airport" class in Java encapsulates the essential information related to an airport. It includes fields such as the identifier (e.g., airport code), coordinates (latitude and longitude), magnetic variation (indicating the magnetic deviation from true north), and elevation above sea level. The class provides accessor methods, also known as getter methods, to retrieve the values of these fields, and mutator methods, also known as setter methods, to modify the field values.
In this specific implementation, when the longitude value is negative, it signifies that the airport is located west of the Greenwich Meridian. Similarly, a negative latitude value indicates that the airport is situated south of the equator. By following this convention, it becomes easier to determine the location of an airport based on its coordinates.
Using the "Airport" class, one can create instances representing different airports by setting values for their respective fields. These instances can then be utilized in various applications related to airport management, navigation systems, or geographical data analysis. The accessor and mutator methods provide a means to access and modify the airport information, ensuring encapsulation and data integrity within the class.
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Why is it nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source
Answer:
Because the shunt winding consist of a large number of turns,
Explanation:
It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly
In a tension test of steel, the ultimate load was 13,100 lb and the elongation was 0.52 in. The original diameter of the specimen was 0.50 in. and the gage length was 2.00 in. Calculate (a) the ultimate tensile stress (b) the ductility of the material in terms of percent elongation
Answer:
a) the ultimate tensile stress is 66717.8 psi
b) the ductility of the material in terms of percent elongation is 26%
Explanation:
Given the data in the question;
ultimate load P = 13,100 lb
elongation δl = 0.52 in
diameter of specimen d = 0.50 in
gage length l = 2.00 inch
First we determine the cross-sectional area of the specimen
A = \(\frac{\pi }{4}\) × d²
we substitute
A = \(\frac{\pi }{4}\) × ( 0.50 )²
A = 0.1963495 in²
a) the ultimate tensile stress σ\(_u\)
tensile stress σ\(_u\) = P / A
we substitute
tensile stress σ\(_u\) = 13,100 / 0.1963495
tensile stress σ\(_u\) = 66717.766 ≈ 66717.8 psi
Therefore, the ultimate tensile stress is 66717.8 psi
b) ductility of the material in terms of percent elongation;
percentage elongation of specimen = [change in length / original length]100
% = [ δl / l ]100
we substitute
% = [ 0.52 in / 2.00 in ]100
= [ 0.26 ]100
= 26
Therefore, the ductility of the material in terms of percent elongation is 26%
Create a PLCfiddle program that emulates a washing machine with
the following characteristics
1. The machine will NOT RUN if the DOOR LID is open
2. The machine will not run until the START button has been pressed the FILL VALVE opens and water begins to fill the machine.'
4. When the FILL LEVEL float switch detects that the machine is full, the AGITATOR MOTOR starts and the FILL VALVE is closed
5. After a certain amount of time passes, an EMPTY signal is generated and the EMPTY VALVE opens, allowing water to drain. The AGITATOR MOTOR stops.
6. When the FILL LEVEL float switch detects that the machine is empty, the EMPTY VALVE is closed and the FILL VALVE opens to refill the machine.
7. When the FILL LEVEL float switch detects that the machine is full, the SPIN MOTOR starts and the FILL VALVE is closed. This will be the Rinse cycle
8. After a certain amount of time passes, an EMPTY signal is generated and the EMPTY VALVE opens, allowing water to drain. The SPIN MOTOR stops.
9. When the FILL Level float switch detects that the machine is empty the EMPTY VALVE is closed and the DONE BUZZER sounds.
10. A RESET switch must be available to reset the machine state at any time.
11.There must be an indicator light for each machine state.
The PLCfiddle program that emulates a washing machine with the above characteristics is given below
What is the PLCfiddle programladder
NETWORK 1, 1, 1, 1, 1
TITLE Washing Machine PLC Program
// Inputs
I:1/0 DOOR_LID // Door Lid Sensor
I:1/1 START_BUTTON // Start Button
I:1/2 FILL_LEVEL // Fill Level Float Switch
I:1/3 EMPTY_SIGNAL // Empty Signal
I:1/4 RESET_BUTTON // Reset Button
// Outputs
O:2/0 FILL_VALVE // Fill Valve
O:2/1 AGITATOR_MOTOR // Agitator Motor
O:2/2 EMPTY_VALVE // Empty Valve
O:2/3 SPIN_MOTOR // Spin Motor
O:2/4 DONE_BUZZER // Done Buzzer
// Internal Variables
B3:1/P FILL_STARTED // Fill Started Flag
B3:1/P AGITATION_STARTED // Agitation Started Flag
B3:1/P RINSE_STARTED // Rinse Started Flag
B3:1/P SPIN_STARTED // Spin Started Flag
// Network 1: Main Control Logic
LD NOT I:1/0 // Check if DOOR_LID is closed
ANL I:1/1 O:2/0 // Check if START_BUTTON is pressed and set FILL_VALVE
ANL O:2/0 B3:1/0 // Check if FILL_VALVE is open and set FILL_STARTED flag
ANL O:2/0 O:2/1 // Check if FILL_VALVE is open and set AGITATOR_MOTOR
ANL I:1/3 O:2/2 // Check if EMPTY_SIGNAL is received and set EMPTY_VALVE
ANL O:2/1 B3:1/1 // Check if AGITATOR_MOTOR is running and set AGITATION_STARTED flag
ANL I:1/2 O:2/0 // Check if FILL_LEVEL is reached and set FILL_VALVE
ANL I:1/3 O:2/2 // Check if EMPTY_SIGNAL is received and set EMPTY_VALVE
ANL O:2/2 B3:1/1 // Check if EMPTY_VALVE is open and set AGITATION_STARTED flag
ANL O:2/2 O:2/3 // Check if EMPTY_VALVE is open and set SPIN_MOTOR
ANL I:1/2 O:2/0 // Check if FILL_LEVEL is reached and set FILL_VALVE
ANL I:1/3 O:2/2 // Check if EMPTY_SIGNAL is received and set EMPTY_VALVE
ANL O:2/3 B3:1/2 // Check if SPIN_MOTOR is running and set RINSE_STARTED flag
ANL I:1/2 O:2/0 // Check if FILL_LEVEL is reached and set FILL_VALVE
ANL I:1/3 O:2/2 // Check if EMPTY_SIGNAL is received and set EMPTY_VALVE
ANL O:2/2 B3:1/2 // Check if EMPTY_VALVE is open and set RINSE_STARTED flag
ANL O:2/2 O:2/4 // Check if EMPTY_VALVE is open and set DONE_BUZZER
ANL I:1/4 SET B3:1/0 // Check if RESET_BUTTON is pressed and set FILL_STARTED flag
RST B3:1/1 B3:1/2 B3:1/3 // Reset AGITATION_STARTED, RINSE_STARTED, and SP
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Which of the following may occur during an annealing heat treatment? a. Stress may relieved. b. Ductility may increase. c. Toughness may increase. d. A specific microstructure may be produced. e. All of the above.
Stress relief, increased ductility, increased toughness, and the production of a specific microstructure can all occur during an annealing heat treatment.Therefore, option e. "All of the above" is the correct answer.
What changes may occur during an annealing heat treatment?During an annealing heat treatment, all of the options mentioned may occur.
a. Stress may be relieved as the material is heated and allowed to slowly cool, reducing internal stresses.
b. Ductility may increase as the heat treatment promotes the rearrangement of atoms, leading to improved plasticity.
c. Toughness may increase as the annealing process refines the microstructure, reducing defects and increasing resistance to fracture.
d. A specific microstructure may be produced through controlled heating and cooling, resulting in desired properties such as improved grain size and distribution.
Therefore, option e. "All of the above" is the correct answer.
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what acronym is helpful for remembering the behaviors that indicate potential violence?
The acronym STAMP can be used to describe these components and be regarded as a viable paradigm for assessing nursing violence. Voice volume and tone, trembling, anxiety, and pacing.
A paradeigma is a device used in classical (Greek-based) rhetoric to show an audience an example of a related event. This example is used to lead the audience to a conclusion without actually leading them there. A personal accountant would serve as an example of how a paradeigma is designed to guide an audience. The role of a personal accountant is to assist in guiding a client as to how money should be spent based on the customer's financial goals, not to tell What to buy (and what not to buy) for a customer Paradeigma was defined by Anaximenes as "past events that are comparable to, or the reverse of, those that we are discussing."
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For the beam loaded as shown in Fig Q2a. perform the following task:
Calculate the support reactions at A and E;
(i)
Draw the shear force diagram for the beam showing all important
values;
>
(iii)
Draw the bending moment diagram for the beam showing all
important values.
6 kN
10 KN
2 kN/m
B
D
1 m
1 m
1 m
1 m
Answer:
a
Explanation:
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Which method can be used to create an output object for file temp.txt?
a. new PrintWriter(new File("temp.txt"))
b. new PrintWriter("temp.txt")
c. new Scanner(new File("temp.txt"))
d. New Scanner(temp.txt)
Option (b) new PrintWriter("temp.txt") can be used to create an output object for file temp.txt.
The method that can be used to create an output object for file temp.txt is new PrintWriter("temp.txt").
The PrintWriter class in Java is used to write data to text files.
We can use the following syntax to create a PrintWriter object:
PrintWriter out = new PrintWriter("temp.txt");
The above code will create a PrintWriter object called out that can be used to write data to a file called temp.txt.
This method will create a new file if the specified file does not exist. If the file already exists, its contents will be overwritten.
If we want to append data to an existing file, we can create the PrintWriter object in append mode by passing a second argument to the constructor.
For example:
PrintWriter out = new PrintWriter(new FileWriter("temp.txt", true));
This will create a PrintWriter object called out that appends data to the file temp.txt.
If the file does not exist, it will be created.
The second argument true specifies that we want to append data to the file instead of overwriting it.
Therefore, option (b) new PrintWriter("temp.txt") can be used to create an output object for file temp.txt.
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derive an expression for the electric field a distance z above a circular ring carrying a constant line charge. you must show all the steps to receive full credit
The expression for the electric field at a distance z above a circular ring carrying a constant line charge is E = λ / (2ε₀(R² + z²)), where λ is the charge density (charge per unit length), R is the radius of the ring, ε₀ is the vacuum permittivity, and z is the distance above the center of the ring.
To derive an expression for the electric field a distance z above a circular ring carrying a constant line charge, we can use the principle of superposition and consider the electric field contribution from each infinitesimal charge element on the ring.
Let's consider a circular ring of radius R and charge density λ (charge per unit length) uniformly distributed along the ring. We will find the electric field at a point P located a distance z above the center of the ring.
Start by considering an infinitesimal charge element on the ring at an angle θ with respect to the vertical axis passing through the center of the ring. The charge element has a length dθ and carries a charge dq = λdθ.
Divide the charge element dq into small segments and find the electric field contribution from each segment at point P. The electric field due to a small segment of charge is given by Coulomb's Law:
dE = k * dq / r²,
where k is the electrostatic constant (k = 1 / (4πε₀), where ε₀ is the vacuum permittivity), dq is the charge element, and r is the distance between the charge element and point P.
Express the distance r in terms of z and R using trigonometry. We can consider a right triangle formed by the line segment connecting the charge element to point P, the radius R, and the vertical distance z. By applying the Pythagorean theorem, we have r = √(R² + z²).
Substitute dq and r into the expression for the electric field:
dE = k * dq / r² = k * λdθ / (R² + z²).
Integrate the electric field contribution over the entire ring by summing up the contributions from all the infinitesimal charge elements. The integration limits will be from 0 to 2π, representing a complete loop around the ring:
E = ∫[0, 2π] k * λdθ / (R² + z²).
Simplify the integral:
E = k * λ / (R² + z²) ∫[0, 2π] dθ.
The integral of dθ over the range [0, 2π] is simply 2π.
Substitute the value of the integral and simplify further:
E = (2πkλ) / (R² + z²).
Finally, substitute the value of k (1 / (4πε₀)) to obtain the final expression for the electric field:
E = λ / (2ε₀(R² + z²)).
Therefore, the expression for the electric field at a distance z above a circular ring carrying a constant line charge is E = λ / (2ε₀(R² + z²)), where λ is the charge density (charge per unit length), R is the radius of the ring, ε₀ is the vacuum permittivity, and z is the distance above the center of the ring.
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Explain any three ways research can facilitate the work of building technicians
According to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.
What are building technicians?They are experts in construction projects, supporting the design of plans, estimating costs, planning work methods, etc.
Research can facilitate the work of building technicians in the following ways:
Conception, design and planning of the project.Selection of materials for floor, wall and ceiling systems.Carry out the programming of works, budgets and analysis of unit prices.Therefore, we can conclude that according to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.
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a current amplifier supplies i rna to a load resistance of i k.o. when the load resistance is increased to 12 kn, the output current decreases to 0.5 ma. what are the values of the short-circuit output current and the output resistance of the amplifier?
We can use the voltage divider rule to calculate the output current from the amplifier:
\(Vout = iRNA * RL/(RA + RL)\)
When RL is i kΩ,
\(Vout = iRNA * i kΩ/(RA + i kΩ)\)
When RL is 12 kΩ,
\(Vout = 0.5 mA * 12 kΩ/(RA + 12 kΩ)\)
Since the voltage gain of the amplifier is infinite, the output voltage is equal to the input voltage.
we can equate the two values of Vout as follows:
\(iRNA * i kΩ/(RA + i kΩ)\)
\(= 0.5 mA * 12 kΩ/(RA + 12 kΩ)\)
Simplifying this equation and solving for RA, we get:
RA = 4 kΩ
The short-circuit output current is the current flowing through RA and is given by:
ISC = Vinput/RA
Where Vinput is the voltage applied to the input of the amplifier.
Vinput = iRNA * RA
ISC = iRNA/RA
\(= iRNA/4 kΩ\)
\(= (iRNA/1000) / 4 A\)
\(= 0.25 iRNA mA\)
The short-circuit output current is 0.25 iRNA mA. the output resistance of the amplifier is 4 kΩ and the short-circuit output current is 0.25 iRNA mA.
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7.6 (A) One axis of the worktable in a CNC positioning system is driven by a ball screw with a 7.5-mm pitch. The screw is powered by a stepper motor which has 120 step angles using a 5) 1.8 2:1 gear reduction (two turns of the motor for each turn of the ball screw). The worktable is programmed to move a distance of 350 mm from its present position at a travel speed of 1,000 0 mm/min.(a) How many pulses are required to move the table the specified distance? (b) What is the required motor rotational speed and (c) pulse rate to achieve the desired table speed?
The required motor rotational speed to achieve the desired table speed is approximately 0.148 rotations/sec, and the pulse rate is approximately 0.444 pulses/sec.
To determine the number of pulses required to move the table the specified distance, we can use the following formula:
Number of pulses = (Distance / Pitch) * (Motor Step Angle / Gear Reduction)
(a) Calculating the number of pulses:
Distance = 350 mm
Pitch = 7.5 mm
Motor Step Angle = 120 degrees
Gear Reduction = 5:1 (two turns of the motor for each turn of the ball screw)
Number of pulses = (350 / 7.5) * (120 / 5)
Number of pulses = 1866.67
Therefore, approximately 1867 pulses are required to move the table the specified distance.
(b) To calculate the required motor rotational speed, we can use the formula:
Motor rotational speed = (Pulse rate * Motor Step Angle) / 360
Given that the travel speed is 1000 mm/min, we need to convert it to mm/sec:
Travel speed = 1000 mm/min = 1000 / 60 mm/sec ≈ 16.67 mm/sec
(c) Calculating the pulse rate:
Pulse rate = Travel speed / Distance per pulse
Distance per pulse = Pitch * Gear Reduction
Distance per pulse = 7.5 mm * 5
Distance per pulse = 37.5 mm
Pulse rate = 16.67 mm/sec / 37.5 mm
Pulse rate ≈ 0.444 pulses/sec
Using the pulse rate, we can calculate the required motor rotational speed:
Motor rotational speed = (0.444 * 120) / 360
Motor rotational speed ≈ 0.148 rotations/sec
Therefore, the required motor rotational speed to achieve the desired table speed is approximately 0.148 rotations/sec, and the pulse rate is approximately 0.444 pulses/sec.
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Which of the following are true statements regarding the development of the break-even point formula? (Check all that apply.)
1 point
a.Fixed costs are reflected in the equation on a per-unit basis.
b.Profit is assumed to be zero.
c.Contribution margin is reflected in the equation as a total.
d.Revenues and variable costs are reflected in the equation on a per-unit basis.
The following statements are true regarding the development of the break-even point formula:Fixed costs are reflected in the equation on a per-unit basis.Profit is assumed to be zero.Contribution margin is reflected in the equation as a total.
Revenues and variable costs are reflected in the equation on a per-unit basis.100 word answer:The break-even point formula is a tool for business owners to help them determine when their business will break even. It's an important calculation for small business owners, especially those who are just starting out. The development of the break-even point formula involves the following true statements: Fixed costs are reflected in the equation on a per-unit basis. Profit is assumed to be zero. Contribution margin is reflected in the equation as a total. Revenues and variable costs are reflected in the equation on a per-unit basis. By analyzing these factors, a business owner can calculate the point at which their business will break even and adjust their pricing or costs accordingly.
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A transformer whose nameplate reads 2300/230 V, 25 kVA| operates with primary and secondary voltages of 2300 V and 230 V rms, respectively, and can supply 25 kVA from its secondary winding. If this transformer is supplied with 2300 V rms and is connected to secondary loads requiring 8 kW at unity PF and 15 kVA at 0.8 PF lagging,
(a) what is the primary current?
(b) How many kilowatts can the transformer still supply to a load operating at 0.95 PF lagging?
(c) Verify your answers with PSpice
(a) The primary current is approximately 10.87 A. (b) The transformer can still supply approximately 17.36 kW to a load operating at 0.95 PF lagging.To solve the given problem, we can use the power relationships in a transformer:
(a) The primary current can be calculated using the formula I_primary = S_secondary / (V_primary * sqrt(3)), where S_secondary is the apparent power on the secondary side and V_primary is the primary voltage. Here, S_secondary is given as 15 kVA at 0.8 PF lagging, which can be converted to real power as P_secondary = S_secondary * PF = 15 kW. Therefore, I_primary = 15 kW / (2300 V * sqrt(3)) ≈ 10.87 A. (b) To calculate the remaining power that the transformer can supply at 0.95 PF lagging, we first determine the apparent power on the secondary side as S_secondary = P_secondary / PF = 15 kW / 0.8 = 18.75 kVA. Then, using the formula P_primary = S_primary * PF, we find P_primary = 18.75 kVA * 0.95 ≈ 17.36 kW. (c) PSpice is a circuit simulation tool, and its usage may involve creating and simulating transformer circuits. To verify the answers with PSpice, you would need to set up the transformer circuit with the given specifications and analyze the primary current and power supply capability at different power factors. The simulation results can be compared to the calculated values to validate the accuracy of the answers.
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All of these are true about GMA (MIG) welding EXCEPT that:
O both the base metal and electrode are melted.
O shielding gas protects the well, tiom contamination.
O heat is produced using a short electric arc.
the welding gun liner regulates the shielding gas.
Answer:
the welding gun liner regulates the shielding gas.
Explanation:
The purpose of the welding gun liner is to properly position the welding wire from the wire feeder till it gets to the nozzle or contact tip of the gun. Regulation of the shielding gas depends on factors such as the speed, current, and type of gas being used. In gas metal arc welding, an electric arc is used to generate heat which melts both the electrode and the workpiece or base metal.
The electric arc produced is shielded from contamination by the shielding gas. The heat generated by the short electric arc is low.
There is an AC series circuit that is constructed of a 150.0-ohm resistor along with 300.0 ohm inductive reactance and 200.0 ohm capacitive reactance. What is the difference in phase between the current and resistor voltage of the circuit
Answer:
0°
Explanation:
The resistor voltage has the same phase as the circuit current. There is no phase difference.
Answer:
0° (zero degree)Explanation:
the difference in pjase between the current and resistor voltage of the given 150.0 ohm, 300.0 ohm and 200.0 ohma w18 3 119 is used as a compression member with one end fixed and the other end pinned. the length is 12 feet. what is the available compressive strength if a992 steel is used?
If a W18x119 steel section is used as a compression member with one end fixed and the other end pinned, and the length of the member is 12 feet, the available compressive strength can be determined for A992 steel.
To calculate the available compressive strength, we need to consider the buckling behavior of the member. In this case, the buckling mode is Euler buckling, which occurs when the critical stress of the member is reached.
The critical stress for Euler buckling can be calculated using the formula:
σc = (π^2 * E) / (K * L / r)^2
Where:
σc is the critical stress
E is the modulus of elasticity of the material (for A992 steel, it is approximately 29,000 ksi)
K is the effective length factor (for a pin-ended compression member, K is 1.0)
L is the length of the member (12 feet in this case, which is 144 inches)
r is the radius of gyration of the W18x119 section, which can be obtained from steel section tables or calculated using geometric properties of the section.
Once the critical stress is determined, the available compressive strength is typically taken as a fraction of the critical stress, depending on the design safety factor specified by the applicable design code. The design safety factor varies depending on the specific design requirements and standards being used.
By plugging in the values and performing the calculations, the available compressive strength for the given W18x119 section made of A992 steel can be determined.
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Two planes leave the metropolis airport at the same time. One flies due north at 400 mph, the other flies at 300 mph on a course 120 degrees clockwise from due north. To the nearest mile, how far apart are the planes after four hours?
The distance between the planes after four hours is 2000 miles.
How to estimate the distance between the two planes?We shall use vector addition to find the distance between the two planes after four hours,
Distance for the plane flying due north at 400 mph = 400 mph × 4 hours = 1600 miles.
Distance for the plane flying at 120 degrees clockwise from due north = 300 mph × 4 hours = 1200 miles in that direction.
Next, let's assume these distances as vectors.
The northbound plane's vector is 1600 miles directly up and the second plane's vector is 1200 miles at an angle of 120 degrees clockwise from north.
To use vector addition for the two vectors:
We shall use the Pythagorean theorem to find the magnitude of the resultant vector since the vectors are at right angles to each other:
Magnitude = √((1600²) + (1200²))
= √(2,560,000 + 1,440,000)
= √4,000,000
= 2,000 miles
Therefore, after four hours, the planes are 2000 miles apart.
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Under the right conditions, it is possible, due to surface tension,to have metal objects float on water. Consider placing a shortlength of a small diameter steel ( γ = 490 lb/ft3)rod on a surface of water. What is the maximum diameter that therod can have before it will sink? Assume that the surface tensionforces act vertically upward. Note: A standard paper cliphas a diameter of 0.036 in. Partially unfold a paper clip and seeif you can get it to float on water. Do the results of thisexperiment support your analysis?
Answer:
A) 0.0614 inches
b) The standard steel paper clip should float on water
Explanation:
The maximum diameter that the rod can have before it will sink
we can calculate this using this formula :
D = \((\frac{8\alpha }{\pi y } )^{\frac{1}{2} }\) ----- 1
∝ = value of surface tension of water at 60⁰f = 5.03×10^−3 lb/ft
y = 490 Ib/ft^3
input the given values into equation 1 above
D = \((\frac{8*(5.3*10^{-3}) }{\pi *490 } )^{\frac{1}{2} }\)
= 5.11 * 10^-3 ft convert to inches
= 5.11 *10^-3 ( 12 in/ 1 ft ) = 0.0614 inches
B) The diameter of a standard paper Cliphas = 0.036 inches
and the diameter of the rod = 0.0614. Hence the standard steel paper clip should float on water
29 10 1 point According to Gate Theory, which of the following factors can make you more sensitive to pain? Placebo effects Competing signals, like rubbing your elbow Chronic stress High levels of arousal 30 1 point Patients who are allowed to self-administer morphine use less than when they receive injections from healthcare providers. True False 31 1 point What happens when people lose their sense of smell (olfaction)? They often become manic. 32 Not much. Olfaction is not a very important sense for humans. They compensate by developing an increased sensitivity to taste (gustation). They often become depressed. 1 point The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them. True False
The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.
Gate Theory states that competing signals such as rubbing your elbow can make you more sensitive to pain. This theory suggests that physical signals such as massage, pressure, heat, or cold can block the transmission of pain messages through the spinal cord and prevent them from reaching the brain. Therefore, when people rub their elbows or apply pressure to the area, this stimulates the non-painful touch fibers and decreases the transmission of the painful stimuli.
As per the statement, patients who are allowed to self-administer morphine use less than when they receive injections from healthcare providers is True. Olfaction is a very important sense for humans, and they often become depressed when they lose their sense of smell (olfaction). The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.
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How to execute the executable file 'abc' mandatorily in the current directory KARIA19 A ../abc B./abc C..\abc D \abc
An executable file is a type of computer file that is used to perform different actions or execute a command or program on a computer. The name executable file comes from the fact that it is a file that is designed to be executed or run on a computer.
The file extension of an executable file is .exe.
In order to execute the executable file 'abc' mandatorily in the current directory, the correct option is B./abc. Here is how to do it:
1. Open the Command Prompt or Terminal.
2. Navigate to the current directory where the 'abc' file is located using the command "cd" followed by the file path.
3. Once you are in the current directory where the 'abc' file is located, type in the command "./abc" (without quotes) and press Enter.
4. This will execute the 'abc' file in the current directory and perform the action it is programmed to do.
It is important to note that in some cases, the executable file may not be able to run due to various reasons such as file permissions, file corruption, or compatibility issues.
In such cases, it is recommended to seek help from a professional or the software developer.
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The throttling valve is replaced by an isentropic turbine in the ideal vapor-compression refrigeration cycle to make the ideal vapor-compression refrigeration cycle more closely approximate the actual cycle.
A. True
B. False
Answer:
False
Explanation:
The given statement is False. In real scenario the throttling valve not replaced by an isentropic turbine in the ideal vapor-compression refrigeration cycle. It is done so that the ideal vapor-compression refrigeration cycle to make the ideal vapor-compression refrigeration cycle more closely approximate the actual cycle.
how do you make coke for steel?
There are seven steps in the engineering design process. Why is it important that the engineer not skip a step?
It is illegal to skip a step.
Not skipping steps ensures that the best possible design is chosen and developed.
Without completing all the steps, nothing would ever be approved by the government.
Since there is a team of employees, a skipped step can mean that someone will not be compensated for his or her role in the pre
TUID
Answer:
Not skipping steps ensures that the best possible design is chosen and developed.
Explanation:
Engineers should not skip any step to ensure the best possible design is chosen and developed.
Answer:
Not skipping steps ensures that the best possible design is chosen and developed.
Explanation:
A_____is any material that poses an unreasonable risk of damage or injury to persons, property, or
the environment if not properly controlled during handling.
Select one:
a. Hazardous material
b. Safety data sheet (SDS)
c. Both A and B
d. None of the above
Answer:
A, Hazardous Material
Explanation: Because that defines a hazardous material. A Safety Data Sheet isn't a material, so it can cause harm.
69.48 / 7.2 = 965 use number sense
Answer: See explanation
Explanation:
69.48 / 7.2 = 965 as written in the question isn't correct. The correct answer should have been:
69.48 / 7.2 = 9.65
It should be noted that when we divide, the answer that one gets cannot be more than the two numbers that were used for the division. Hence, there's no way that 965 would be more than 69.48 and 7.2.
The 150 mm thick wall of a gas fired furnace is constructed of fireclay brick (k=1.5 W/m.K) , tho=2600 kg/m3, and cp=1000 J/kg.K ) and is well insulated at its outer surface. The wall is at a uniform initial temperature of 20 degree C, when the burners are fired and inner surface is exposed to products of combustion for which T infinity=950 degree C and h=100 W/ m2.K.
(A) How long does it take for the outer surface of the wall to reach a temperature of 750 degree C?
(B) plot the temperature distribution in the wall at the foregoing time.
Answer:
I am thick but I dont know the anwser
The time that it will take for the outer surface of the wall to reach a temperature of 750 degree C will be 33800 seconds.
How to calculate the time?Using the approximation methods, Fo will be;
= In(0.215/1.262)/(1.4289)²
= 0.867
Then, the time taken will be:
= 0.867(0.15)²/(1.5/2600 × 1000)
= 33800 seconds.
In conclusion, the time taken is 33800 seconds.
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What is 90 to the power of 46
Answer:Just multiply 90 by itself 46 times
Explanation:
do it
how to calculate flow rate through a pipe when the velocity is not known
Calculating the flow rate through a pipe can be done using the pipe's cross-sectional area and the pressure difference between the two ends of the pipe. The first step is to determine the pipe's cross-sectional area, which can be calculated using the pipe's diameter.
Once the area is determined, the pressure difference between the two ends of the pipe is measured using a pressure gauge. By using Bernoulli's equation, the flow rate can then be calculated. Bernoulli's equation states that the pressure difference is equal to the fluid's density times the velocity squared times one-half of the cross-sectional area. If the velocity is not known, it can be calculated using the mass flow rate and the density of the fluid. Therefore, by knowing the cross-sectional area, pressure difference, density, and mass flow rate, the flow rate through a pipe can be calculated.
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Give me source code of Simple openGL project. ( without 3D or Animation) simple just.
Answer:
Use GitHub or stackoverflow for this answer
Explanation:
It helps with programming a lot