Glycerin is poured into an open U-shaped tube until the height in both sides is 22 cm. Ethyl Alcohol is then poured into one arm until the height of the alcohol column is 18 cm. The two liquids do not mix. What is the difference in height between the top surface of glycerin and the top surface of alcohol?

Answers

Answer 1

The distinction in top among the pinnacle floor of glycerin and the pinnacle floor of ethyl alcohol is 0.0432 meter or 4.32 centimeter the difference in height between the top surface of glycerin and the top surface of alcohol is 4.32 centimeter.

Given the subsequent data:

Height of ethyl alcohol = 25cm to n = 0.25I mHydrostatic top = 20 cm to m = 0.2 m.Scientific data:Density of ethyl alcohol = 790 kg/m³Density of glycerin = 1260 kg / (m ^ 3)To calculate the distinction in top among the pinnacle floor of glycerin and the pinnacle floor of ethyl alcohol:The system for hydrostatic strain.Where:p is the density.g is the acceleration because of gravity.h is the top.At steady temperature, the strain on the pinnacle floor of glycerin withinside the open U-formed tube is identical to the strain on the pinnacle floor of ethyl alcohol:rho_*h_ = rho_*h_Substituting the given parameters into the system, we have;1260h_ = 790 * 0.251260h_ = 197.5h_ = 197.5/1260Height of glycerin = 0.1568 meters.Now, we are able to locate the distinction in top:Height of glycerin = 0.1568 meters.Now, we are able to locate the distinction in top:Difference = 0.2 - 0.1568Difference = 0.0432 meter or 4.32 centimeter.

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Related Questions

PLEASE HELP QUICKLY THANKS

PLEASE HELP QUICKLY THANKS

Answers

Answer: the answer is d

Explanation:

which of the following can cause skin cancer and which can't?

Campfire
Flashlight
Lamp
Sun
Tanning bed
fluorescent light bulbs

Answers

Sun
Tanning bed
Fluorescent light bulbs

A book is sitting on a desk. What best describes the normal force acting on the book?

the upward force the desk pushes on the book
the upward force the book pulls on the Earth
the downward force the book pushes on the desk
the downward force the Earth pulls on the book

Answers

A book is sitting on a desk is due to the Gravitational force of Earth Gravity so D. the downward force the Earth pulls on the book.

What is the gravitational force of an object?

The force of attraction between all masses that is objects in the universe, especially the attraction of the Earth's mass for bodies near its surface.

How gravity is formed?

Einstein said that the shape of spacetime is responsible for the rise of force that we experience as gravity. A concentration of mass, such as the Earth or sun, bends space around it like a rock bends the flow of a river.

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A solid block weighs 1.80 N in air. When fully submerged in water, it displaces a volume of 2.0 x 10
-^5m³. Density of water is 1000 kg/m³.
Determine
a) the average density of the block

b) the normal force the floor of the vessel exerts on the submerged body

Answers

a) The average density of the block can be calculated using the formula for density.Since the mass of the block is 1.80 N and the volume is 2.0 × 10∧5 \(m^{3}\), the average density is 0.9 kg/\(m^{3}\).

What is mass ?

Mass is a measure of the amount of matter contained in an object. It is a fundamental physical property that is commonly used to measure the size of objects. Mass is usually measured in grams (g) or kilograms (kg) but can also be measured in other units such as ounces, pounds and tons. Mass is different from weight, which is a measure of the force of gravity on an object.

b) The normal force the floor of the vessel exerts on the submerged body can be calculated using the formula for buoyancy. In this case, the normal force is equal to 1000 kg/\(m^{3}\) × 2.0 × 10∧5 \(m^{3}\)× 9.81 m/\(s^{3}\), which is equal to 1.962× 10∧8 N.

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A wave is moving at a velocity of 8 km/sec with a frequency of 10 Hz.
Use the equation you rearranged to determine the wavelength of the wave.

Answers

Explanation:

arn core concepts.

See Answer

1) For a P wave with velocity of 8 km/s (typical upper mantle speed) in a Poisson solid,compute the wavelength for waves with periods of:

a) 15 sec

b) 1 sec

c) 0.1 sec (100 Hz)

2) Repeat question 2 for an S wave in the same medium (Hint: you have to determine the S wave speed).

Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object.
a) 300N
b) 30N
c) 5N
d) 150N

An 5kg object is released from rest near the surface of a planet. The vertical position of the object

Answers

Answer:

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

\( y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} \)   (1)

Where:

\(y_{f}\): is the final vertical position (obtained from the graph)

\(y_{0}\): is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → \(t_{f}\) = 5 s

y₀ = 300 m → \(y_{f}\) = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

\( a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} \)

Finally, the weight of the object is:

\( W = ma = 5 kg*6 m/s^{2} = 30 N \)

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

What type of force is jumping a trampoline?

Answers

Answer:

Tension

Explanation:

An electric heating plate works for 3 hours at a voltage of U = 230V.
Now the voltage increases by 5%. By how much does the energy increase, which
is now converted into heat during 3 hours? Consider the heating plate as a resistor which is not temperature dependent.
how should I proceed to come to the solution ?

Answers

If the voltage supplied to the circuit increases by 5%, the electric energy will also increases by 5%.

What is the electric energy of a heating plate?

The electric energy of a heating plate is the rate at which energy is consumed or the rate at which electric energy is used up.

Mathematically, electric energy is given as;

E = Pt

where;

P is electric power t is time of energy use

E = IVt

where;

I is the current flowing in the circuitV is the voltage in the circuit

From the equation above, the electric energy used is directly proportional to the voltage supplied.

When the voltage increases by 5%, the electric energy also increases by 5%.

Thus, we can conclude that, to determine the increase in the electric energy, the equation for electric energy, relating voltage, current and time to electric energy must be applied as shown above.

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A current loop with radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T. Considering all possible orientations of the loop relative to the field, what is the largest potential energy difference (in Joules) you can find between two orientations

Answers

For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as

du=0.2512J

What is the largest potential energy difference (in Joules) you can find between two orientations?

Generally, the equation for the initial velocity  is mathematically given as

v0=-iAB

Therefore

-2*\pi(0.2)(0.5))

v0=-0.1256J

for  180

theta=0180=-iABcos180

V180=0.1256J

Therefore

du=v180-v0

0.1258-(-0.1256

du=0.2512J

In conclusion,  potential energy

du=0.2512J

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A cat that weighs 4 kilograms is moving at a velocity of 1 m/s. What is the kinetic energy?

Answers

The kinetic energy of the cat is 2 joules (J).

The kinetic energy of an object can be calculated using the formula KE = 1/2 * mass * velocity^2.

The kinetic energy of an object can be calculated using the formula:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

In this case, the mass of the cat is 4 kilograms, and its velocity is 1 m/s. Plugging these values into the formula:

KE = 0.5 * 4 kg * (1 m/s)^2

Simplifying the equation:

KE = 0.5 * 4 kg * 1 m^2/s^2

KE = 0.5 * 4 kg * 1

KE = 2 kg

Therefore, the kinetic energy of the cat is 2 joules (J).

Kinetic energy is the energy possessed by an object due to its motion. In this case, the cat's kinetic energy is determined by its mass and velocity. The formula for kinetic energy demonstrates that it is directly proportional to the mass and square of the velocity. As the mass increases, the kinetic energy also increases. Similarly, as the velocity increases, the kinetic energy increases exponentially.

In this example, the cat's kinetic energy is relatively low due to its mass and velocity values. If the cat were moving at a higher velocity or had a greater mass, the kinetic energy would be significantly higher. Kinetic energy is an important concept in understanding the energy associated with moving objects and is utilized in various fields such as physics, engineering, and sports science.

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A 45 Kg object is given a net force of 500 n what is its approximate acceleration

Answers

Acceleration = force / mass = 500/45 = 11.1 m/s^2

The acceleration of the object is 11.11 m/\(s^2\) (approximately).

What is acceleration?

The rate of change of velocity of a body with respect to time is known as acceleration. Due to having both magnitude and direction, it is a vector quantity having SI unit m/s^2.

Given parameter,

The mass of the object, m = 45 Kg.

Net force acting on the object, F = 500 N.

Acceleration of the object, a= ?

From Newton's 2nd law of motion,

Force = mass × acceleration

⇒ F = ma

⇒ a = F/m

= 500 N /45 Kg

= 11.11 m/s^2. (approximate)

Hence, the approximate value of acceleration of the object, a = 11.11 m/s^2.

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A metal ball bearing with mass 5.0 g falls out of a factory machine and drops to the concrete floor 3.0 m below. It bounces back up to its starting point. Find the changes in the bearing's potential and kinetic energies as it a) travels from the machine down to the floor, and b) travels up from the floor back to its starting point.

Answers

When an object is not moving, it contains potential energy (stored energy). Potential energy transforms into kinetic energy if a force is applied or it starts to move (energy of motion).

What is the equation for kinetic energy change?

The relationship between kinetic energy and an object's mass and square of the its velocity is given by K=12mv2. The kinetic energy is measured in kgs squared per indication of the number if the mass is measured in kilogram and the velocity is measured in metres per second.

What occurs as the objects move in relation to potential and kinetic energy?

You now understand that kinetic energy is motion-related and potential energy is position-related. Their capacity to change into one another is the main connection between them. To put it another way, potential energy changes into kinetic energy, which then changes back into potential energy.

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Which of the following is the best hypothesis?
A. The size of ice crystals in clouds depends on the air temperature.
B. It is fun to fly an airplane through large cumulus clouds.,
C. How big can ice crystals get inside a cloud?
D. Clouds are always found in the atmosphere.

Answers

A the size of ice crystals….

The net force on a box F as a function of the vertical position y is shown below.
What is the work done on the box from y=0 to 6.0m?

The net force on a box F as a function of the vertical position y is shown below.What is the work done

Answers

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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The average speed of a car that drives 140 kilometers in 2 hours

Answers

Answer:

240 kilometer

Explanation:

ur just mutipling the number by 2

Your average speed was 70.0 Kilometers per hour (km/h)

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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A 25 N block rests on an adjustable inclined plane; the maximum angle just before it slips is 37° with the horizontal. What the coefficient of static friction is between block and plane surfaces? (use sin 37 0 =0.6 and cos 37 0 =0.8)

Answers

The coefficient of static friction for the given inclined plane is 0.8

What is the coefficient of static friction?The friction that occurs when an object is placed on a surface is known as the coefficient of static friction. The movement of an object on a surface also causes kinetic friction.The coefficient of static friction, which is defined as the difference between the normal force and the frictional force, provides a good description of friction.This aids in the thing lying flat on a surface. A scalar value without dimensions is the coefficient of friction. It is a ratio between the pressure pushing two bodies together and the frictional force between them.The greatest frictional force (F) that can exist between two surfaces before the movement starts is divided by the normal force (N) to determine the coefficient of static friction.

coefficient of static friction = μ = F/N

μ = 25 cos 37 / 25

μ cos 37

μ = 0.8

Hence the coefficient of static friction for the given inclined plane is 0.8.

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In the diagram below, a 5 kg object is moving with a speed of 10 m/s, and a 10 kg object is moving with a speed of 5 m/s.

Which object in the diagram has more kinetic energy?

A. The 5 kg object has more kinetic energy.

B. The 10 kg object has more kinetic energy.

C. Both of the objects have the same amount of kinetic energy.

D. Neither object has any kinetic energy.​

In the diagram below, a 5 kg object is moving with a speed of 10 m/s, and a 10 kg object is moving with

Answers

Answer:

C.Both objects have the same amount of kinetic energy.

Explanation:

different masses can have the same kinetic energy

Hope it helps

If a 5 kg object is moving with a speed of 10 m/s, and a 10 kg object is moving with a speed of 5 m / s, then the 5 kg object has more kinetic energy, therefore the correct answer is option A.

What is mechanical energy?

The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.

The expression for total kinetic energy can be given as follows

KE = 1/2 mv²

As given in the problem, In the diagram below, a 5 kg object is moving at a speed of 10 m/s, and a 10 kg object is moving at a speed of 5 m/s.

Thus, the 5 kg object has more kinetic energy .

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A 200 kg Blue car is moving rightward at 2 m/s and collides inelastically with a 200 kg Red car.
What must the speed of the Red car be so that both cars come to a stop? (Adjust the Blue car mass to 200 kg and its velocity to +2 m/s. Set the bumper type to Locking. Adjust the mass of the Red car to 200 kg. Adjust the speed of the Red car so that, when they collide, both cars come to a stop.)

Answers

With the use of formula, the speed of the red car must be 2 m/s

COLLISION

There are two types of collision.

Elastic CollisionInelastic Collision

In Inelastic collision, the momentum is conserved while energy is not. Also, both mases will move with a common velocity after collision.

Given that a 200 kg Blue car is moving rightward at 2 m/s and collides inelastically with a 200 kg Red car. For both cars to come to a stop, the final velocity V will be equal to zero.

by using the formula

\(M_{1}U_{1} - M_{2}U_{2} = ( M_{1} + M_{2} ) V\)

Where V = 0

\(M_{1}U_{1} = M_{2}U_{2}\)

Substitute all the parameters into the equation

200 x 2 = 200\(U_{2}\)

\(U_{2}\) = 400 / 200

\(U_{2}\) = 2 m/s

Therefore, the speed of the red car must be 2 m/s

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The separation distance in B is_____ times greater than in A, the force of attraction is
than A.

Answers

The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

What is the force of attraction between two object?

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

k is Coulomb's constant
q₁ is magnitude of first chargeq₂ is the magnitude of the second charger is the distance between the charges

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using ____in art.

value

modeled forms

local color

linear perspective

Answers

Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using linear perspective in art.

One of the pioneers of modern art, Cezanne used a novel approach to painting at the time. In his still life paintings, Cezanne represented things utilizing a system of flattened planes and simplified forms rather than the conventional perspective techniques that provide the impression of depth and space.

Additionally, he played around with color, relying on color blocks rather than shading and modeling to convey a sense of volume and form.

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Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]
Y2 : 4.95sin[π(3.80x-1180t-0.250)]
Where x , y1 and y2 are in meters and t is in seconds

Answers

The wave function of the resultant wave, Y1 + Y2 is Y = 4.95sin[π(3.80x - 1180t - 0.206)].

The wave function Y1 describes a sinusoidal wave with an amplitude of 4.95 meters, a wavelength of λ = 2π/3.8 ≈ 1.65 meters, and a frequency of f = 1180/3.8 ≈ 310 Hz. The phase of the wave is such that the maximum displacement occurs at x = 0 and t = 0, and the wave is moving in the negative x direction.

The wave function Y2 also describes a sinusoidal wave with the same amplitude and wavelength as Y1, but with a phase difference of 0.25 seconds. This means that Y2 is shifted to the left (negative x direction) by a distance of Δx = λΔφ/2π = λ(0.25)/2π ≈ 0.206 meters. The frequency and speed of Y2 are the same as Y1.

To determine the resultant wave Y, we add the two wave functions: Y = Y1 + Y2. Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can simplify the expression for Y:

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t)cos(0.25) + cos(π/2)sin(0.25)]

Y = 4.95sin[π(3.80x - 1180t)] + 4.95sin[π(3.80x - 1180t + 0.25)]

Y = 4.95sin[π(3.80x - 1180t - 0.206)]

The resultant wave Y is a sinusoidal wave with the same amplitude and wavelength as Y1 and Y2, but with a phase shift and a different waveform due to interference. The frequency and speed of Y are also the same as Y1 and Y2.

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-- The given question is incomplete, the complete question is

"Two traveling sinusoidal waves are described by the wave functions

Y1 : 4.95sin[π(3.80x-1180t)]

Y2 : 4.95sin[π(3.80x-1180t-0.250)]

Where x , y1 and y2 are in meters and t is in seconds. Find the wave function of the resultant wave (Y1 + Y2)." --

This same experiment is performed on the international space station. What is the primary issue with performing this experiment in the absence of gravity

Answers

Answer:

Difference in experimental data.

Explanation:

There is difference of experimental value between the experiment that is performed on the earth and on the international space station because presence of gravity. The result of the experiment on the earth is different due to the presence of gravity that contributes in the result of the experiment as compared to international space station where no gravity is present so there is high difference of the numerical value of the result of both experiments of earth and international space station.

statics and strength of materials

statics and strength of materials

Answers

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

What is the force P?

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ is the area of segment ABA₂ is the area of segment BC

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Let the mass of object 1 be m and the mass of object 2 be 3m . If the collision is perfectly inelastic, what are the velocities of the two objects after the collision?

Answers

In a collision that is completely inelastic, the two objects cling together and continue to move as a single entity. As the two objects' ultimate velocities are equal, v′1=v′2=v′ (v 1 ′ = v 2/ ′ = v),

What does it mean for two things to collide precisely inelastically?

Let's move on to the second category of collisions. Kinetic energy is not maintained in an inelastic collision. When two things collide in a collision that is precisely inelastic, the max amount of mechanical energy is lost as the objects cling together again after impact.

What happens in a collision that is completely inelastic?

When some of the angular momentum of a colliding item or system is lost, a physics term known as an elastic collisions is used. In a completely inelastic collision, the interacting atoms stay together and the most kinetic energy is wasted. Such situations involve the use of wasted kinetic energy to bind the two items together.

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An object accelerates from rest. After accelerating for 12 s, it has traveled 240 m. What is its velocity at that time?​

An object accelerates from rest. After accelerating for 12 s, it has traveled 240 m. What is its velocity

Answers

The velocity of the object that accelerates from rest in 12 seconds and traveled 240m is 20m/s.

How to calculate velocity?

The velocity of a body is a vector quantity that denotes the rate of change of position with respect to time i.e. combining speed with a directional component.

Displacement is a vector quantity which denotes distance with a directional component.

The velocity of a body can be calculated by dividing the displacement by the time taken as follows:

∆v = ∆x ÷ ∆t

Where;

∆V = change in velocity (m/s)∆x = displacement (m)∆t = time (s)

∆V = 240m ÷ 12s

∆v = 20m/s

Therefore, the velocity of the object that accelerates from rest in 12 seconds and traveled 240m is 20m/s.

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State Newton’s Universal Law of Gravitation.

Answers

Answer:

This law states that every particle attract every other particle in the universe with a force that is directly proportional to the product of their mass and inversely proportional to the square of the distance between the center

Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds


a.
increases.



b.
remains constant.


c.
decreases.



d.
increases at first, but then stays constant.



e.
decreases at first, but then stays constant.

Answers

Answer: a

Explanation:

Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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