Given the following formula, solve for t.
v u + at O
A. t = OB. t = O C. t = OD. t = UU a a (v + u) a (v - u) v+u a picture included​

Answer:

60y+48

Step-by-step explanation:

Answer: 18: 18, 36, 54, 72, 90
20: 20, 40, 60, 80, 100
16: 16, 32, 48, 64, 80

32: 32, 64, 96, 128, 160

Step-by-step explanation:

multiply each number by 1 2 3 4 5 respectivly to get the answer.

The bifurcations occur at \(\(\mu = -1\)\), \(\(\mu = 0\)\), and \(\(\mu = 1\)\), where the stability of the equilibrium points changes. For \(\(\mu > 1\)\), both equilibrium points \(\(x = -1 + \sqrt{\mu}\)\) and \(\(x = -1 - \sqrt{\mu}\)\) become unstable.

To investigate the bifurcations of the system represented by the equation \(\(x'' = [(x + 1)^2 - \mu + x'][(x - 1)^2 + \mu + x'] - \dots\)\), we need to analyze the equilibrium points and their stability as the parameter \(\(\mu\)\)varies.

First, let's find the equilibrium points by setting \(\(x'' = 0\) and \(x' = 0\)\). Simplifying the equation, we have:

\(\[(x + 1)^2 - \mu + x' = 0 \quad \text{and} \quad (x - 1)^2 + \mu + x' = 0\]\)

Solving these equations simultaneously, we get:

\(\[(x + 1)^2 - \mu = 0 \quad \text{and} \quad (x - 1)^2 + \mu = 0\]\)

From the first equation, we have two possible cases:

1. If \(\(\mu > -1\), then \((x + 1)^2 - \mu = 0\)\) implies \(\(x = -1 \pm \sqrt{\mu}\)\).

2. If \(\(\mu \leq -1\)\), then \(\((x + 1)^2 - \mu = 0\)\) has no real solutions.

From the second equation, we have:

\(\((x - 1)^2 + \mu = 0\) implies \(x = 1 \pm \sqrt{-\mu}\).\)

Now let's analyze the stability of these equilibrium points by considering small perturbations around each point.

If \(\(\mu > 0\)\), the point is stable.

If \(\(0 < \mu < 1\)\), the point is a saddle point.

If \(\(\mu > 1\)\), the point is unstable.

If \(\(\mu > 0\)\), the point is stable.

If \(\(0 < \mu < 1\)\), the point is a saddle point.

If \(\(\mu > 1\)\), the point is unstable.

All values of \(\(\mu\)\) lead to an unstable point.

All values of \(\(\mu\)\) lead to an unstable point.

So, the bifurcations occur at \(\(\mu = -1\)\), \(\(\mu = 0\)\), and \(\(\mu = 1\)\), where the stability of the equilibrium points changes. For \(\(\mu > 1\)\), both equilibrium points \(\(x = -1 + \sqrt{\mu}\)\) and \(\(x = -1 - \sqrt{\mu}\)\) become unstable. For \(\(-1 < \mu < 0\)\), the equilibrium points \(\(x = -1 + \sqrt{\mu}\)\) and \(\(x = -1 - \sqrt{\mu}\)\) are stable. And for \(\(\mu < -1\) and \(\mu = 0\)\), there are no real equilibrium points.

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Answer:

h = 3 cm

Step-by-step explanation:

The volume (V) of a rectangular prism is calculated as

V = Ah ( A is the area of the base and h the height )

Here V = 36 and A = 6 × 2 = 12 cm² , then

12h = 36 ( divide both sides by 12 )

h = 3

Answer: 3 cm

Step-by-step explanation:

The formula to solve the volume of a rectangular prism is V = l x w x h

Where V is volume, l is length, w is width, and h is height

Givens are, Volume = 36 cm3

length = 6 cm

width = 2 cm

Now, we will plug in the numbers to the formula

36 cm3 = 6cm x 2cm x h

36 cm3 = 12 cm2 x h

divide 12cm2 on both sides

36cm3/12cm3 = h

h = 3cm

Answer:

look at explanation k=3

Step-by-step explanation:

5×3=15 15-5=10 10+6=16

Answer:

Tuesday or Monday not sure

Step-by-step explanation:

But mostly Tuesday.

Answer:

Tuesday i think

Step-by-step explanation:

Answer: 13,36,-2,-2,pi

Step-by-step explanation:

You do exactly what it says for the rule to -6 to get your answer.

Answer:

7 - 2m can be translated to "7 minus two times m" or "the difference between 7 and twice m".

3(m + 2) = 15 can be translated to "three times the sum of m and 2 is equal to 15" or "the product of 3 and the sum of m and 2 is 15".

To solve the equation, we can start by distributing the 3 on the left side:

3(m + 2) = 15

3m + 6 = 15

Then, we can subtract 6 from both sides:

3m + 6 - 6 = 15 - 6

3m = 9

Finally, we can divide both sides by 3:

3m/3 = 9/3

m = 3

Therefore, the solution to the equation 3(m + 2) = 15 is m = 3.

5m - m(2 - m) can be translated to "5m minus the product of m and the difference between 2 and m" or "the difference between 5m and m times the quantity 2 minus m".

To simplify the expression, we can use the distributive property to expand the second term:

5m - m(2 - m) = 5m - 2m + m^2 = m^2 + 3m

Therefore, the simplified expression is m^2 + 3m.

The solution set for this linear-quadratic system of equations is {(-3, 0), (5, 8)}.

The solution set for this linear-quadratic system of equations is {(-3, 0), (4, 0)}.

The solution set for this linear-quadratic system of equations is {(-3, 0), (4, 0)}.

We can find the value of y in terms of x using the second equation and substitute it in the first equation.

Here's the process:

We solve the second equation, y - x - 3 = 0, for y, and we get y = x + 3.

Then, we substitute this value of y into the first equation, y = x2 - x - 12, and we get x2 - x - 12 = x + 3.

We solve for x by bringing all the terms to one side and simplifying, which gives x2 - 2x - 15 = 0.

This is a quadratic equation that can be factored into (x - 5)(x + 3) = 0.

Therefore, the solutions for x are x = -3 or x = 5.

We substitute these values of x in the equation y = x + 3 to find the corresponding values of y.

The solutions are (-3, 0) and (5, 8).
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Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= \(\frac{x^2+9x+18}{x+3}\) factorise the numerator

= \(\frac{(x+3)(x+6)}{x+3}\) ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

For the given breadth and area, the length of the rectangle is 8 m.

We know that the formula for the area of a rectangle is the product of length and breadth, mathematically represented as:

Area = Length * Breadth......(i)

In this case, we are given;

Area, a = 64 sqm

Breadth, b = 8 m

So, let the length be L.

Putting values in the formula mentioned under equation (i),

64 = 8*L

L = 64 / 8

L = 8 m

Therefore, the length of the given rectangle will be 8 m.

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8m is the length of the rectangle whose area is 64sq m and breath is eight m.

We know, a rectangle is a quadrilateral and to find the area of a rectangle we need to multiply the length and breadth of the rectangle. In a rectangle the opposite sides are equal and parallel to each other and all the angles bisect each other at 90°. The sum of interior angles is 360°. The diagonals bisect each other at different angles.

here, area= 64m² and breadth= 8m (given) length=?

length × breadth= area

⇒length × 8= 64

⇒length= 64÷8

⇒length= 8

Therefore, the length of the rectangle is 8m.

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Answer:

There is no mode for the following data.

Step-by-step explanation:

This is because the mode is the  value which occurs most frequently in a data set. yet there is not a piece of data that appears the most frequently.  

The mode of this data set is the Independents.

The mode is a statistical term that refers to the value that appears most frequently in a data set. In this case, you have provided data on the number of Republicans, Democrats, and Independents. There are 47 Republicans, 49 Democrats, and 52 Independents.

To determine the mode, we simply look for the highest count among the three groups. In this case, we can see that the group with the highest count is the Independents with a count of 52.

Therefore, the mode of this data set is the Independents. This tells us that Independents are the most frequent group in this particular data set. Remember, the mode is just one way to describe the central tendency of data and should be considered alongside other measures like the mean and median for a more comprehensive understanding of the data distribution.

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the correct choice is {0, 18}. These elements are unique to set C and do not appear in set A.

To find the set difference C - A, we need to remove all elements from A that are also present in C. Let's examine the sets:

C = {0, 6, 12, 18}

A = {2, 4, 6, 8, 10, 12}

We compare each element of A with the elements of C. If an element from A is found in C, we exclude it from the result. After the comparison, we find that the elements 2, 4, 8, 10 are not present in C.

Thus, the set difference C - A is {0, 18}, as these are the elements that remain in C after removing the common elements with A.

Therefore, the correct choice is {0, 18}. These elements are unique to set C and do not appear in set A.

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The given information is as follows:A random sample of 150 teachers in an​ inner-city school district found that​ 72% of them had volunteered time to a local charitable cause within the past 12 months.

The formula for calculating the standard error of sample proportion is given as:$$Standard\(\ error=\frac{\sqrt{pq}}{n}$$\)where:p = proportion of success in the sampleq = proportion of failure in the samplen = sample sizeGiven:Sample proportion, p = 72% or 0.72Sample size, n = 150

The proportion of failure in the sample can be calculated as:q = 1 - p= 1 - 0.72= 0.28Substituting the known values in the above formula, we get:\($$Standard \ error=\frac{\sqrt{pq}}{n}$$$$=\frac{\sqrt{0.72(0.28)}}{150}$$$$=0.0372$$\)Rounding off to the nearest thousandth, we get the standard error of sample proportion as 0.037

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A. To determine if the above data provide evidence that more than 10% of nickel plates are not suitable for use in the test, we can conduct a hypothesis test.

The null hypothesis (H0) states that the proportion of unfit nickel plates is equal to or less than 10% (p ≤ 0.10). The alternative hypothesis (Ha) states that the proportion is greater than 10% (p > 0.10).

We can use a one-sample proportion test to assess the evidence against the null hypothesis. In this case, we compare the observed proportion of unfit plates (14/100 = 0.14) to the hypothesized proportion of 10% (0.10).

With an importance level (significance level) of 0.05, we can calculate the test statistic and p-value to make our decision.

B. To calculate the probability that the null hypothesis in part (a) will be accepted when the true proportion is 15% and a sample size of 100 is used, we need to consider the type II error rate or the probability of failing to reject the null hypothesis when it is false.

Given that the true proportion is 15% (p = 0.15), we would like to find the probability of accepting the null hypothesis (p ≤ 0.10) with an importance level of 0.05.

To calculate this probability, we need additional information, specifically the critical value or the rejection region for the hypothesis test. Without this information, we cannot directly determine the probability of accepting the null hypothesis.

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The probability the friend finds no one in the first spot is 60%.

Probability is the chance or likelihood that an expected event occurs when there are many possible outcomes or events.

For instance, the probability that when the counting friend goes to the hiding spot, they can or cannot find a friend there.

The two friends can only hide in 2 spots, leaving 3 spots with nobody.

The number of hiding spots = 5

The number of friends hiding = 2

The number of counting friends = 1

The number of spots they can hide = 2 out of 5

The probability of finding a person in a hiding spot = 2/5 or 40%

The probability of not finding a person in a hiding spot = 3/5 (1 - 2/5) or 60% (1 - 40%).

The chances that your friend finds anyone in the first spot are 60%.

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Completely factorize the polynomial using any methods that are appropriate, then look for shared factors and the polynomial's roots. Next, double-check your work to confirm accuracy.

Follow these steps to determine a polynomial's factorization:

Completely factor the polynomial using any relevant techniques, including grouping, utilizing the difference of squares or cubes, or using the quadratic formula.

By multiplying them all together, you can verify that each factor is accurate. The final figure must match the initial polynomial.

Look for shared factors among the polynomial factors. If the polynomial has common components, remove them from the equation and rewrite it as the product of the common factors and the other factors.

The polynomial's roots can be verified by setting each factor to zero and calculating the variable. The roots ought to correspond to the original polynomial.

Verify your work a second time to make sure all relevant elements have been identified and taken into consideration.

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The amount you could save per month would be 25% of your discretionary money.

Discretionary income is the money you have left over after paying taxes and necessary cost-of-living expenses.

The formula for discretionary money is: Discretionary money = Realized income - Fixed expenses. Inputting data, we have: Discretionary money = $3,543.22 - Fixed expenses

Amount to be saved = 25% of discretionary money

Amount to be saved = 0.25 * (Realized income - Fixed expenses)

Therefore, the amount savable is calculated as 0.25 times the difference between your realized income and fixed expenses.

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The probability that the diameter of a selected bearing is greater than 46 millimeters is 0.8413.

To solve this problem, we need to use the standard normal distribution and standardize the diameter values to find the corresponding z-score. The formula for standardizing a value is:

z = (x - μ) / σ

Where:

x = the value we want to standardize (in this case, 46 millimeters)

μ = the mean diameter of the ball bearings (51 millimeters)

σ = the standard deviation (which is the square root of the variance, so σ = sqrt(25) = 5)

Substituting the values we have:

z = (46 - 51) / 5 = -1

Now, we need to find the probability that a selected bearing has a diameter greater than 46 millimeters, which is equivalent to finding the area to the right of z = -1 on the standard normal distribution curve. This can be done using a table or calculator.

Using a calculator or software, we can find that the area to the right of z = -1 is 0.8413 (rounded to four decimal places). Therefore, the probability that the diameter of a selected bearing is greater than 46 millimeters is 0.8413.

Answer: 0.8413 (rounded to four decimal places).

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Answer:

\(B=\frac{143}{19}\)

Step-by-step explanation:

The explanation is attached below.

The derivative of the function using the definition of the derivative f(x) is  mathematically given as

Derivative f(x)=k

Doman of \(f'(x)=\mathrm{R}\)

Given that \(f(x)=k \pi+d \ldots(1)\)

To find the derivative of f(x) by using the limit definition.

\(\begin{aligned}f^{\prime}(x) &=\lim _{z \rightarrow 0} \frac{f(x+h)-f(x)}{h} \\&=\lim _{k \rightarrow 0} \frac{k(x+h)+d-(k x+d)}{h} \\&=\lim _{h \rightarrow 0} \frac{h h}{h} \\&=\lim _{k \rightarrow 0} k \\&=k\end{aligned}\)

Hence f'(x)=k

To find the domain of f(x)=k+d

\(f(\pi) \in \mathbb{R} \Leftrightarrow k \pi+d \in \mathbb{R}\\\\\Leftrightarrow x \in \mathbb{R}\)

Hence Domain of \(f(x)=\mathbb{R}\)

To find the domain of f'(x)=k

\(\begin{aligned}f^{\prime}(x) \in \mathbb{R}^{\prime} & \Leftrightarrow k \in \mathbb{R} \\& \Leftrightarrow x \in \mathbb{R}\end{aligned}\)

Hence Doman of \(f'(x)=\mathrm{R}\)

In conclusion, the angular coefficient of this function corresponds to the derivative of a linear function.

The domain of every linear function or any integer is represented by the set R(all numbers), which may be written as (-∞, +∞).

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Answer:

27 vertical posts and 36 horizontal rails

Step-by-step explanation:

If Max builds 1style of fence with each section having 3vertical posts and 6horizontal rails, to calculate the number of posts and rails that he need for a fence that will be 9 sections long, we will use the following equality;

For Posts:

1section = 3 vertical posts

9 sections = x

Cross multiply

x × 1 = 9× 3

x = 27

Hence Max will need 27vertical posts for a fence that is 9sections long

For the rail:

1 section = 6 horizontal rails

6 sections = y

Cross multiply

y× 1 = 6 × 6

y = 36

Hence Max will need 36 horizontal rails for a fence that is 9sections long.

In total Max will need 27 vertical posts and 36 horizontal rails for a fence that is 9sections long

Answer:

2,1

Step-by-step explanation:

a) Straight Line: The Excel function used for the straight-line method is "SLN." b) Double Declining Balance: The Excel function used for the double declining balance method is "DDB." c) Sum of Years Digits: The Excel function used for the sum of years digits method is a combination of "SYD" and other mathematical functions. d) Variable Declining Balance: The Excel function used for the variable declining balance method may vary depending on the specific calculation required.

a) Straight Line: The straight-line method calculates depreciation by dividing the asset's cost by its useful life. In Excel, the "SLN" function is used, which takes three arguments: cost, salvage value, and useful life. The formula is "=SLN(cost, salvage, life)."

b) Double Declining Balance: The double declining balance method applies a constant depreciation rate to the asset's book value. In Excel, the "DDB" function is used, which takes five arguments: cost, salvage value, useful life, period, and factor. The formula is "=DDB(cost, salvage, life, period, [factor])."

c) Sum of Years Digits: The sum of years digits method calculates depreciation by assigning weights to each year based on the asset's useful life. In Excel, the "SYD" function is used, which takes four arguments: cost, salvage value, useful life, and period. The formula is "=SYD(cost, salvage, life, period)."

d) Variable Declining Balance: The variable declining balance method calculates depreciation using a varying depreciation rate based on the asset's expected usage or production levels. The Excel function to be used may depend on the specific calculation or formula required for the variable declining balance method.

Conclusion:

Excel provides specific functions to facilitate the calculations for different depreciation methods. The "SLN" function is used for straight-line depreciation, "DDB" function for double declining balance, and "SYD" function for sum of years digits method. These functions simplify the calculations by taking relevant arguments and producing accurate results. However, for the variable declining balance method, the specific Excel function may vary depending on the formula or calculation required. By utilizing the appropriate Excel functions, depreciation calculations can be performed efficiently and accurately within the chosen depreciation method.

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Step-by-step explanation:

Using Cosine rule, we have:

q² = r² + s² - 2(r)(s)(cosQ)

= 380² + 390² - 2(380)(390)(cos48°)

= 98169.688cm²

Hence q = 313cm. (nearest centimeter)

The required value of side q is 313 cm for the triangle ΔQRS.

A triangle is a geometric figure with three edges, three angles and three vertices. It is a basic figure in geometry.

The sum of the angles of a triangle is always 180°

Given that,

In triangle QRS side r = 380 cm, side s = 390 cm and angle Q = 48°.

To find the length of the side q,

Use cosine rule,

\(cos Q = \frac{(r^2 + s^2 - q^2)}{(2\times r \times s)}\)

Substitute the values here,

\(cos 48 = \frac{(380)^2 + (390)^2- q^2}{2\times380 \times390} \\\)

\(0.67 = \frac{144400 + 152100 - q^2}{296400}\)

198,588 = 296500 - q²

q² = 97912

q = 312.90

q = 313 cm

The value of side q is 313 cm.

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Answer:

7.5 hours

Step-by-step explanation:

distance = rate * time (d=rt)

First we find her average rate, or speed:

Now we take that rate and use our second distance to find the time:

d = rt

t = d/r = 350 miles / 46.6666 miles/hour = 7.5 hours

B is the y- intercept of the equation B = 28 - 7t, where B is the percentage of the battery.

What is a linear graph?

Linear graphs are straight line graphs to represent the relationship between two quantities. This graph helps in depicting a result in single straight lines. There is no use of curves, dots, bars, etc., and a straight line is denoted by the term linear. Let's represent the given example in the form of a data table.

Given equation,

B = 28 - 7t

B represents the battery percentage of the phone.

t represents time,

According to the equation, with passing of time the percentage of the battery drops.

28 is the highest amount of battery present at 0 time hours.

With passage of time the battery decreases.

So, in t = 1 hr,

battery, B = 28 - 7*1 = 28 -7 = 21%

similarly, t = 4 hrs,

B = 28 -7*4 = 28 -28 = 0%

The battery completely drains and becomes 0%

Therefore, B is the y- intercept of the equation B = 28 - 7t, where B is the percentage of the battery.

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The range of the dataset obtained from the difference between the maximum and minimum value is 5.

The range of a distribution or dataset is obtained by subtracting the maximum and minimum values in the distribution.

Range = Maximum - Minimum

From the dataset :

Maximum number of messages sent = 15

Minimum number of messages sent = 10

Range = 15 - 10 = 5

The value of the range in the dataset is 5

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The range of the set {10, 11, 11, 11, 13, 15, 15} is R = 5.

For a set of numbers {x₁, x₂, ..., xₙ}

The range is defined as the difference between the largest value and the smallest value.

In this case, we have the set:

{10, 11, 11, 11, 13, 15, 15}

The largest value is 15, and the smallest value is 10, then the range of this set will be:

Range = 15 - 10

Range = 5

The range of the set is 5 units.

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