given the equation 9x+3Y=7 which equation is perpendicular to an equation with a y intercept of 12

Answer:

294

Step-by-step explanation:

Answer:

3.15 cents

Step-by-step explanation:

So, lets go over all the information we know.

First off, we know that the cost of the item is 70 dollars.

Secondly, we know that the fee is 4.5% of 70 dollars.

Now, what is 4.5%?

Well, we know that 100% is qual to 1.

So lets divide 4.5 by 100, which is just moving the decimal point back by 2:

0.045

Now, the last thing to do is multiply 0.045 by 70.

0.045x70

=

3.15

So now we know the fee for a 70 dollar item is 3.15 dollars!

Hope this helps ;)

He is  2√19 miles far way from starting point.

Suppose Billy starts at point A, turns at point B, and ends at point D, as shown below.

If Billy turns 60◦ northward and walks six miles, then we can draw a 30 − 60 − 90 triangle whose hypotenuse is 6 miles

It follows that Billy traveled 6/2 = 3 miles eastward during these 6 miles, and that he traveled 3√3 miles northward during these 6 miles. In total, Billy traveled 4 + 3 = 7 miles  eastward and 3√ 3 miles northward.

By the Pythagorean Theorem, the distance from his starting point is q:

(7)2 + (3√3)2

=√49 + 27

= √76

= 2√19 .

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Answer:

y=-1/2m+4

Step-by-step explanation:

in photo :)

Answer:

9 marbles

Step-by-step explanation:

He got 47 marbles, after keeping 2 of his marbles, he got 47-2 = 45 marbles left

To divide equally between his 5 friends, each of his friend should get 45 :5 = 9 marbles each

Enjoy your prize :D

Answer:

The pattern is of +4

You can also take a look on the given picture to understand more

1+4=5

2+4=6

5+4=9

Hope it's helpful!

The line integral of the vector field F = <21 + y, 27> along the line segment between the points (5, 0) and (11, 0) is 126.

The given vector field is F = <21 + y, 27>. The line integral of the vector field F along a curve C is given by the formula:int_C F · dr = ∫C F · T dswhere T is the unit tangent vector to the curve C and ds is an element of arc length along the curve C.So, first we need to find the equation of the line segment between the points (5, 0) and (11, 0). This line segment lies on the x-axis and has equation y = 0.So, let's take C to be the line segment between the points (5, 0) and (11, 0), and let's parameterize C by x. Then C can be represented by the vector-valued function:r(x) = for 5 ≤ x ≤ 11.The unit tangent vector T is given by:T = r'(x) / ||r'(x)||= <1, 0> / ||<1, 0>||= <1, 0>.Thus, the line integral of F along C is:int_C F · dr = ∫C F · T ds= ∫5^11 F(x, 0) · <1, 0> dx= ∫5^11 <21 + 0, 27> · <1, 0> dx= ∫5^11 21 dx= 21(x)|5^11= 21(11 - 5)= 21(6)= 126Therefore, the line integral of the vector field F = <21 + y, 27> along the line between the points (5,0) and (11,0) is 126.

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Answer: I think it's A. But correct me if I'm wrong. I don't really do a lot of this math.

Answer:

Step-by-step explanation:

I think its D I'm not Shure I hope it helps, I would wait and see if I'm not the only one who says its D because I may be wrong.

Answer: \(12x^{2} -18x-12\)

Step-by-step explanation:

(6x-12)(2x+1)

Foil method

6x*2x

6x*1

-12*2x

-12*1

add them up

\(12x^{2} -18x-12\)

Answer:

  1.75%

Step-by-step explanation:

The monthly interest rate is the interest amount divided by the base on which it is computed, expressed as a percentage.

  $4.96/$283.15 × 100% ≈ 1.75172% ≈ 1.75%

Answer:

The perimeter of the shape is (7x²+10x+81) inches.

Step-by-step explanation:

When finding the perimeter of a shape, you have to add up all the side lengths :

\(p = 31 + (4 {x}^{2} + 8x) + (3 {x}^{2} - 5x + 20) + (7x + 30)\)

\(p = 31 + 4 {x}^{2} + 8x + 3 {x}^{2} - 5x + 20 + 7x + 30 \)

\(p =( 7 {x}^{2} + 10x + 81) \: inches\)

Answer:

total no. of butterflies=11000

no.of butterflies=679

percentage of butterflies=?

Percentage of butterflies= (11000/679) percent..

= 16.20 percentage

therefore 16.20 percentage butterflies are in US

Answer: A

Step-by-step explanation:

Each gallon costs 3 dollars.

8(gallons) times $3(for each gallon) = 24(dollars).

The probability that at least one child would draw the nickel too small is: P(X ≥ 1) = 1 - P(X = 0).

b) To find the probability that exactly 4 children would draw the nickel too small, we can use the binomial probability formula. The formula is: P(X = k) = (nCk) * (p^k) * (q^(n-k)), where n is the number of trials, k is the number of successes, p is the probability of success, and q is the probability of failure.

In this case, n = 8 (as 8 children are chosen), k = 4 (as exactly 4 children drawing the nickel too small), p = 0.15 (as the probability of a child drawing the nickel too small), and q = 1 - p = 1 - 0.15 = 0.85.

So, the probability that exactly 4 children would draw the nickel too small is: P(X = 4) = (8C4) * (0.15^4) * (0.85^(8-4)).

c) To find the probability that at least one child would draw the nickel too small, we can use the complement rule. The probability of at least one success is equal to 1 minus the probability of no success.

The probability of no success (all children drawing the nickel of the right size) is given by: P(X = 0) = (8C0) * (0.15^0) * (0.85^8).

Therefore, the probability that at least one child would draw the nickel too small is: P(X ≥ 1) = 1 - P(X = 0).

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Answer:

Not sure if this will help but that looks like a bisection of angles BAC and TSR.

Answer:  9=6x

Step-by-step explanation:

add 4x to both sides to isolate the variable term

Answer:

0.45

Step-by-step explanation:

You divided 2.25 by 5

Answer:

\(k = -\frac{7}{3}\)

Step-by-step explanation:

Given :

p(x) = 2x² − 3kx + 5

Since, -1 is a zero for p then :

p(-1) = 0

Solving the equation p(-1) = 0 for k :

p(-1) = 0

⇔ 2(-1)² − 3k(-1) + 5 = 0

⇔ 2 + 3k + 5 = 0

⇔ 3k = -5 - 2

⇔ 3k = -7

⇔ k = -7/3

NOTE :

If -1 is a zero of p

\(\Longrightarrow k = -\frac{7}{3}\)

\(\Longrightarrow p(x) = 2x^2 - 3(\frac{-7}{3}) x + 5\\\Longrightarrow p(x) = 2x^2+ 7x + 5\)

(a) Using the chain rule, dtdz at time t = 0 is equal to 22.

(b) The tangent plane T(x, y) of f(x, y) at the point (3, 2, 31) is given by the equation 20x - 10y + 11.

(c) Using the chain rule, dtdT at time t = 0 is equal to 20.

(d) The results in part (a) and part (c) are the same because the chain rule guarantees that the derivative of the composite function is the same regardless of the order in which the derivatives are taken.

(a) To find dtdz, we need to use the chain rule. Let's compute it:

dz/dt = (∂z/∂x)(dx/dt) + (∂z/∂y)(dy/dt)

Given z = 3x^2 + 2xy - y^3, x(t) = 3 + sin(t), and y(t) = 2 + t^2, we can differentiate x(t) and y(t) to get:

dx/dt = cos(t)

dy/dt = 2t

Now, let's find the partial derivatives of z with respect to x and y:

∂z/∂x = 6x + 2y

∂z/∂y = 2x - 3y^2

Substituting the values into the chain rule formula, we have:

dz/dt = (6x + 2y)(cos(t)) + (2x - 3y^2)(2t)

At t = 0, x = 3 and y = 2, so we can substitute these values:

dz/dt = (6(3) + 2(2))(cos(0)) + (2(3) - 3(2)^2)(2(0))

= 22

Therefore, dtdz at time t = 0 is equal to 22.

(b) To find the tangent plane T(x, y) of f(x, y) at the point (3, 2, 31), we need to compute the partial derivatives of f(x, y) with respect to x and y:

∂f/∂x = 6x + 2y

∂f/∂y = 2x - 3y^2

Evaluate these derivatives at (x, y) = (3, 2):

∂f/∂x = 6(3) + 2(2) = 20

∂f/∂y = 2(3) - 3(2)^2 = -10

The tangent plane at the point (3, 2, 31) can be written as:

T(x, y) = f(3, 2) + (∂f/∂x)(x - 3) + (∂f/∂y)(y - 2)

Substituting the values, we have:

T(x, y) = 31 + 20(x - 3) - 10(y - 2)

= 20x - 10y + 11

Therefore, the equation of the tangent plane T(x, y) is 20x - 10y + 11.

(c) Now, let's use the chain rule to find dtdT at time t = 0, where T(x, y) is the tangent plane from part (b) and x(t) = 3 + sin(t), and y(t) = 2 + t^2.

We need to find the partial derivatives of T(x, y) with respect to x and y:

∂T/∂x = 20

∂T/∂y = -10

Now, let's differentiate x(t) and y(t) with respect to t:

dx/dt = cos(t)

dy/dt = 2t

Using the chain rule, we have:

dtdT = (∂T/∂x)(dx/dt) + (∂T/∂y)(dy/dt)

= 20(cos(0)) + (-10)(2(0))

= 20

Therefore, dtdT at time t = 0 is equal to 20.

(d) The results from part (a) and part (c) are the same because the chain rule guarantees that the derivative of the composite function is the same regardless of the order in which the derivatives are taken. In both cases, we are finding the derivative of z with respect to t, either directly (part a) or by finding the derivative of T with respect to t and using the chain rule (part c).

In particular, the calculation in part (c) follows the formula for the chain rule: dtdT = (∂T/∂x)(dx/dt) + (∂T/∂y)(dy/dt), where (∂T/∂x) and (∂T/∂y) are the partial derivatives of T with respect to x and y, and dx/dt and dy/dt are the derivatives of x(t) and y(t) with respect to t, respectively.

Therefore, the results in part (a) and part (c) are the same due to the application of the chain rule.

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Disproved: n^8 is not equal to O(9^n).

To disprove the statement, we need to show that n^8 grows faster than 9^n as n approaches infinity.

We can compare the growth rates by taking the limit of the ratio n^8 / 9^n as n approaches infinity. If the limit is not zero, it means that n^8 grows faster than 9^n.

Taking the limit, we have:

lim(n→∞) (n^8 / 9^n)

Using L'Hôpital's rule, we can differentiate the numerator and denominator eight times:

lim(n→∞) (8! / (ln(9))^8)

Since the factorial term (8!) is a constant, and ln(9) is also a constant, the limit evaluates to a nonzero value. Therefore, n^8 grows faster than 9^n, and we can conclude that n^8 is not equal to O(9^n).

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If we want to provide a 99% confidence interval for the mean of a population, the confidence coefficient will be 0.99. This means that there is a 99% probability that the true population mean falls within the calculated interval.

The confidence coefficient for a confidence interval represents the level of confidence we have in our estimate.

In the case of a 99% confidence interval, the confidence coefficient is 0.99. This means that we are 99% confident that the true population mean falls within the calculated interval. The confidence coefficient is derived from the desired level of confidence, which is typically expressed as a percentage.

A higher confidence level corresponds to a larger confidence coefficient. In practical terms, a 99% confidence interval indicates that if we were to repeat the sampling process multiple times and construct 99% confidence intervals, approximately 99% of those intervals would contain the true population mean.

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The values for numbers #21 through #26 are as follows:

#21: 2.33% or 0.0233. #22: $56.4842. #23: 1.85% or 0.0185. #24: $56.4148. #25: 3.64% or 0.0364. #26: $57.4397

#21: 2.33% (arithmetic mean as a fraction: 0.0233)

#22: $56.4842 (result of the calculation)

#23: 1.85% (geometric mean as a fraction: 0.0185)

#24: $56.4148 (result of the calculation)

#25: 3.64% (continuous mean as a fraction: 0.0364)

#26: $57.4397 (result of the calculation)

To fill out numbers #21 through #26, we need to calculate the values for each term using the given information and convert the percentages to fractions.

#21: The arithmetic mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #21 = 2.33% = 0.0233.

#22: Multiply the starting price ($53.07) by the compound factor (1 + arithmetic mean)^3. Substitute the value of #21 into the calculation. Therefore, #22 = $53.07 x (1 + 0.0233)^3 = $56.4842.

#23: The geometric mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #23 = 1.85% = 0.0185.

#24: Multiply the starting price ($53.07) by the compound factor (1 + geometric mean)^3. Substitute the value of #23 into the calculation. Therefore, #24 = $53.07 x (1 + 0.0185)^3 = $56.4148.

#25: The continuous mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #25 = 3.64% = 0.0364.

#26: Multiply the starting price ($53.07) by the continuous factor e^(continuous mean x 3). Substitute the value of #25 into the calculation. Therefore, #26 = $53.07 x e^(0.0364 x 3) = $57.4397.

Hence, the values for numbers #21 through #26 are as calculated above.

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Answer:

Step-by-step explanation:

hi Is that you on your pic

Answer:

hlo buddy

are u free now.. nhjm....

Answer:

put x=-1, and the rest will be easy

If x + 1 divides f(x), this means x = -1 is a root of f(x), i.e. f(-1) = 0. Plugging in x = -1 gives

f(-1) = 2 (-1)³ + k (-1) - 1 = -3 - k = 0

Solve for k; you end up with k = -3.

FMECA is a bottom-up hardware approach to risk assessment. It is an inductive, or data-driven, linking elements of a failure chain as follows: Effect of Failure, Failure Mode, and Causes/Mechanisms. To estimate the reliability of software, most software prediction models use the probability density function to predict "Mean Time To Failure."

FMECA is a systematic and structured analytical methodology used to identify potential failures in a system, equipment, process, or product, and to assess the effect and probability of those failures. FMECA stands for Failure Modes, Effects, and Criticality Analysis. FMECA is similar to FMEA (Failure Modes and Effects Analysis) in that it is used to identify failure modes and assess their risk.

However, FMECA goes beyond FMEA by analyzing the criticality of each failure mode. This makes it an effective tool for identifying the most significant failure modes and prioritizing them for corrective action. A Probability Density Function (PDF) is a function that describes the likelihood of a random variable taking on a particular value.

PDF is used in software prediction models to estimate the reliability of software by predicting "Mean Time To Failure" (MTTF). MTTF is the average time between failures of a system, equipment, process, or product.

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The correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are given below.Option A. V = -(0.25)x - 4 Option B. V = − (0.25)x+4

A function can be defined as a special relation where each input has exactly one output. The set of values that a function takes as input is known as the domain of the function. The set of all output values that are obtained by evaluating a function is known as the range of the function.

From the given options, only option A and option B are the functions that satisfy the condition.Both of the options are linear equations and graph of linear equation is always a straight line. By solving both of the given options, we will get the range as (-∞, 4) and domain as (-∞, 0).Hence, the correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are option A and option B.

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