given tan(x)=24/25 (in quadrant 1), find sin(2x)

a. The probability of selecting an orange ball is approximately 0.4500.

b. Therefore, the probability that the ball is from the second bucket given that it is orange is 1/3.

a. To find the probability that the ball selected is orange, we need to consider the probabilities of selecting each bucket and then selecting an orange ball from that bucket.

The probability of selecting the first bucket is 1/2, as there are two buckets and the selection is random. In the first bucket, there are 6 orange balls out of a total of 10 balls. Therefore, the probability of selecting an orange ball from the first bucket is 6/10.

The probability of selecting the second bucket is also 1/2. In the second bucket, there are 3 orange balls out of a total of 10 balls. Thus, the probability of selecting an orange ball from the second bucket is 3/10.

To calculate the overall probability of selecting an orange ball, we need to consider the probabilities of selecting each bucket and then selecting an orange ball from that bucket:

P(Orange ball) = P(First bucket) * P(Orange ball from first bucket) + P(Second bucket) * P(Orange ball from second bucket)

= (1/2) * (6/10) + (1/2) * (3/10)

= 3/10 + 3/20

= 9/20

≈ 0.4500

Therefore, the probability that the ball selected is orange is approximately 0.4500.

b. Given that the coach selects an orange ball, we need to find the probability that the ball is from the second bucket.

The probability of selecting the second bucket is still 1/2, as before.

Using Bayes' theorem, we can calculate the probability that the ball is from the second bucket given that it is orange:

P(Second bucket | Orange ball) = (P(Orange ball | Second bucket) * P(Second bucket)) / P(Orange ball)

P(Orange ball | Second bucket) = 3/10 (as there are 3 orange balls out of 10 in the second bucket)

P(Second bucket) = 1/2 (as the probability of selecting the second bucket is still 1/2)

P(Orange ball) = 9/20 (as calculated in part a)

P(Second bucket | Orange ball) = (3/10 * 1/2) / (9/20)

= 3/20 / 9/20

= 3/9

= 1/3

Therefore, the probability that the ball is from the second bucket given that it is orange is 1/3.

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Given data:

The first value of x is a=-16.

The first value of y is b=20.

The second value of x is c=-12.

The second value of y is d=15.

The expression for the rate change is,

x=(d-b)/(c-a)

Substitute the given values in thhe above expression.

x=(15-20)/(-12+16)

=-5/4

Thus, he constant rate of change is -5/4.

Responder:

$ 555,911.5

Explicación paso a paso:

Dado

Principal = $ 545,680

Interés = 2,25%

Tiempo = 10 meses = 10/12 años

Debemos buscar la cantidad después de 10 meses.

Monto = Principal + Intereses

Interés = PRT / 100

Interés = 545,680 * 2,25 * 10/1200

Intereses = 12,277,800 / 1200

Interés = 10.231,5

Cantidad = 545,680 + 10,231.5

Cantidad = 555,911.5

por lo tanto, la cantidad después de 10 meses es $ 555,911.5

Answer:

8*x+16-(8*x-16)=0

Step-by-step explanation:

Solve :    32   =  0

This equation has no solution.

A. a non-zero constant never equals zero.

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If the observed t-value exceeds the critical t-value, then the difference between the sample means is most likely statistically significant.

In other words, the difference between the sample means is unlikely to have occurred by chance and is likely due to a real difference in the population means. The direction and magnitude of the difference must be further examined using effect size measures and confidence intervals.

Therefore, the most suitable value to be fit in the blank space of the given incomplete statement is, statistically significant.

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the limit of the given expression as x approaches 2 is 1/5.

To find the limit of the expression:

lim(x→2) [(ln(x + 3) - ln(5))/(x - 2)]

We can simplify it using logarithmic properties. Recall that the logarithmic property states:

ln(a) - ln(b) = ln(a/b)

Applying this property to our expression, we have:

lim(x→2) [ln((x + 3)/5)/(x - 2)]

Now, let's evaluate the limit:

lim(x→2) [ln((x + 3)/5)/(x - 2)]

By direct substitution, we get an indeterminate form of 0/0. We can use L'Hôpital's Rule to find the limit.

Applying L'Hôpital's Rule, we take the derivative of the numerator and the derivative of the denominator:

lim(x→2) [(1/(x + 3))/1]

Simplifying further, we have:

lim(x→2) [1/(x + 3)]

Now, we can substitute x = 2 into the expression:

lim(x→2) [1/(2 + 3)]

= lim(x→2) [1/5]

= 1/5

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The number which the iterates approach if you use the cos button 20 or 30 times starting with is;

a) For x = 1;  0.7390851332

(b) For x = 2, the iterates = -0.7390851332.

(c) For x = 10, the iterates = 0.7390851332

From the information given, we have that;

The cosine function is expressed as;

f(x) = cos(x),

Range is between -1 and 1.

In using the cos button  repeatedly, the iterates approach a fixed point called a cycle or attractor.

Then, we have;

(a) For x = 1, if the cos button is pressed 20 times, the iterates will approach = 0.7390851332

(b) For x = 2, the iterates will approach approximately -0.7390851332.

(c) For x = 10, the iterates will approach approximately 0.7390851332

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Step-by-step explanation:

I would show if they were right but the check marks kind of get in the way, sorry if this is too late.

The  two-way table with the joint and marginal relative frequencies is as follows:

         | Left    | Right   | Total

Female    | 0.048   | 0.450   | 0.498

Male      | 0.104   | 0.398   | 0.502

Total     | 0.151   | 0.848   | 1.000

A two-way frequency table, also known as a contingency table, is a tabular representation of categorical data that shows the frequency or count of observations for each combination of two categorical variables.

As, the joint relative frequencies represent the proportion of individuals who fall into both categories (e.g., female and left-handed, male and right-handed),

while the marginal relative frequencies represent the proportion of individuals in each category independently (e.g., the proportion of females and the proportion of left-handed individuals).

Here is the two-way table showing the joint and marginal relative frequencies:

         | Left   | Right  | Total

Female    | 11     | 104    | 115

Male      | 24     | 92     | 116

Total     | 35     | 196    | 231

To calculate the joint relative frequencies,

To calculate the marginal relative frequencies, we divide the row and column totals by the total number of individuals (231):

Marginal relative frequency of left-handed individuals: 35/231 ≈ 0.151

Marginal relative frequency of right-handed individuals: 196/231 ≈ 0.848

Marginal relative frequency of females: 115/231 ≈ 0.498

Marginal relative frequency of males: 116/231 ≈ 0.502

Therefore, the two-way table with the joint and marginal relative frequencies is as follows:

         | Left    | Right   | Total

Female    | 0.048   | 0.450   | 0.498

Male      | 0.104   | 0.398   | 0.502

Total     | 0.151   | 0.848   | 1.000

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Answer:

49

Step-by-step explanation:

Add up all the numbers and divide by how many numbers there are.

Answer:

49

Step-by-step explanation:

the sum of all the numbers is 294

294÷6=49

Answer: These American flag measurements ratios are: (A) Height (hoist) of the flag = 1.0; (B) Width (fly) of the flag = 1.9; (C) Union height (Hoist of the canton) = 0.5385 (A × 7/13, spanning seven stripes);

Step-by-step explanation:

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Answer:

cut.ly/4Ivk

Step-by-step explanation:

This link should help cut.ly/4RIvk

Answer:

Length: 12, Width: 6

Step-by-step explanation:

The width, or w is 1/2 the length, so the length is 2w

So, we can set up the equation 2w+2w+w+w, or 6w=36

So, w=6, and you can plug into the length

QUESTION : 18 miles to 18 yards to a fraction do i divide it ?

Yes so 18 miles / 18 yards = 1760/1

I think !?

Answer:

31,680 to 31,6800/10. Though I am not sure if it's right.

Answer:

£330

Step-by-step explanation:

The total ratio between Paul and Malachy is 2 + 3 = 5.

The amount that Paul will receive is:

2/5 * 2750 = £1100

The second ratio is between Paul, his wife and their son in the ratio 5:4:1. The total ratio between Paul, his wife and their son is:

5 + 4 + 1 = 10

The amount that Paul's wife will receive is:

4/10 * 1100 = £440

The amount that their son will receive is:

1/10 * 1100 = £110

Therefore, the amount that the wife will receive over the son is:

440 - 110 = £330

Answer:

Kenny found 80% of the eggs.

Step-by-step explanation:

(4 ÷ 5) × 100 = x

0.8 × 100 = x

80% = x

Kenny found 80% of the eggs.

Answer:

Cause it is

Step-by-step explanation:

Answer:

let the number of meals = m

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The correct response is d. A primitive is associated with both data and methods, whereas an object merely holds data.

Information that has been transformed into a format suitable for transmission or processing is referred to as data in computing. Information that has been binary-digitally altered for use with contemporary computers and transmission methods is referred to as data. The topic data may be expressed in both the singular and plural forms. Data can take the shape of text, observations, figures, photographs, statistics, graphs, and symbols. Individual prices, weights, addresses, ages, names, temperatures, dates, or distances, for instance, might be included in the data. Data lacks significance and utility on its own because it is an unprocessed sort of knowledge. Basic data includes information like a person's name, last name, address, phone number, cell number, fax number, email address, and vehicle license plate.

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The probability of winning a certain lottery is p = 1/64,481. For a single play, the expected number of wins is E(X) = 1*p + 0*(1-p) = p.

The variance of the number of wins for a single play is\(Var(X) = p(1-p) = 1/64,481 * 64,480/64,481 = 64,480/64,481^2\).

For 669 plays, the expected number of wins is 669p and the variance of the number of wins is \(669Var(X) = 669(64,480/64,481^2) = 668.99/64,481\).

The standard deviation is the square root of the variance, so the answer is approximately sqrt(668.99/64,481) = 0.309.

Therefore, the closest answer choice is D) 0.3.

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In business calculus, the term "functions" refers to mathematical relationships that associate inputs (typically denoted as x) with corresponding outputs (typically denoted as y). Functions can represent various aspects of business operations, such as revenue, cost, profit, demand, and supply.

The concept of "limits" in calculus deals with the behavior of a function as the input approaches a particular value. It determines the value that the function approaches or tends to as the input gets arbitrarily close to a specified value. Limits are essential for analyzing the behavior of functions near certain points, understanding rates of change, and evaluating derivatives and integrals.

"Continuity" of a function refers to its smooth and unbroken nature, without any abrupt jumps, holes, or vertical asymptotes. A function is continuous if its graph can be drawn without lifting the pen from the paper. Continuity ensures that small changes in the input correspond to small changes in the output, which is crucial for reliable analysis and prediction.

For example, consider the function f(x) = 2x + 1. This linear function represents a business scenario where x represents the number of units sold, and f(x) represents the total revenue generated. The limit of f(x) as x approaches 2 is 5, indicating that as the number of units sold approaches 2, the total revenue approaches $5. Since f(x) = 2x + 1 is a linear function, it is continuous across its entire domain.

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The volume of the cylinder  V = πr²h. Therefore, we need to have more information about the cylinder's height in order to solve this problem.

To find the volume of the cylinder, we first need to know the height of the cylinder. However, the height is not given in the question. Therefore, we cannot determine the volume of the cylinder with the given information.

We can use the formula for the volume of a cylinder, which is V = πr²h, where V is the volume, r is the radius, and h is the height.

Since r = 11 units and x = 15 units, we can find the diameter of the base of the cylinder by multiplying r by 2, which gives us 22 units. However, we still do not know the height of the cylinder.
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Two angles whose sum is 180° are called supplementary angles. The correct option is C.

Two angles whose sum is 180° are called supplementary angles. If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line. Those two-two angles are two pairs of supplementary angles. That means, that if supplementary angles are aligned adjacent to each other, their exterior sides will make a straight line.

In the given Image, ∠a and ∠b are supplementary angles to each other. Therefore, the correct option is C.

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Each walkway is around 51 yards long.

Pythagoras Theorem is the way in which you can find the missing length of a right angled triangle.

The triangle has three sides, the hypotenuse (which is always the longest), Opposite (which doesn't touch the hypotenuse) and the adjacent (which is between the opposite and the hypotenuse).

Pythagoras is in the form of;

a²+b²=c²

However, it can also be written in the form of c²=a²+b²

In order to find the hypotenuse, you will have the length of two sides, for example, these could be 3 and 4.

As 'C' is always the hypotenuse, you have to work out the two other lengths, and you do this by squaring the numbers.

3²=9 and 4²=16.

As you're looking for C, you've got to add these together

9+16=25

As a²+b²=c², this means that the answer for C is the square root of 25.

√25= 5

Divide the square in half to make a right triangle. Now, use Pythagoras' theorem to solve for the hypotenuse.

a²+b²=c²

⇒ 36²+36²=c²

⇒ 1296+1296=c²

⇒ 2592=c²

∴ c =50.9116

Round to the nearest whole number, we get c = 51 yards.

Thus, each walkway is around 51 yards long.

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Answer:

32

Step-by-step explanation:

Answer:

Step-by-step explanation:

To graph the equation 3(x - 2) = 5(x + 1), we can first simplify it by expanding the brackets:

3x - 6 = 5x + 5

Next, we can isolate the variable on one side of the equation. We can do this by subtracting 3x from both sides and adding 6 to both sides:

-11 = 2x

x = -11/2

Now we have the x-coordinate of the point where the graph of the equation intersects the x-axis. To find the y-coordinate of this point, we can substitute x = -11/2 into one of the original equations and solve for y:

3(x - 2) = 5(x + 1)

3(-11/2 - 2) = 5(-11/2 + 1)

-33/2 - 6 = -55/2 + 5

-33/2 - 6 + 55/2 = 5

-33/2 + 44/2 = 5

11/2 = 5

Plot the coordinates on the graph to obtain the graph of the system of inequalities.

As Math World correctly notes, to solve a system of linear equations by graphing, we simply graph both equations in the same coordinate plane and locate the intersection of the two lines.

The visual technique actually just requires three easy actions to complete: Slope-Intercept Form should be applied to both equations.

Each linear equation's graph should be shown in the same coordinate plane. Identify the system's solution.

If the lines cross, the system's solution may be found by using the coordinates of the crossing point. The problem cannot be solved if the lines are parallel.

Let us suppose number of members =x.

Let us suppose the number of non members = y.

The system of equation for the following situation is:

5x + 10y ≤ 300

x ≥ 2y

Substitute different values of x to obtain different values of y.

Plot the coordinates on the graph to obtain the graph of the system of equations.

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Answer:

sample proportion of defective items

Step-by-step explanation:

The p-chart is a type of chart in which the sample is taken periodically from the production process, so as to determine if the population proportion of defective items in the sample falls within the control limits on the chart.

For a P-chart, as the sample size gets larger it turns more into a normal distribution making it possible to approximate the distribution of the proportion defective.

Answer:

116

Step-by-step explanation:

Answer: Heyaa! ^^

Your Answer when multiplied is.. 6x²−11x−10

Step-by-step explanation:

                    - FOIL EXPLANATION -

It stands for "First, Outer, Inner, Last"

· multiplying the First terms,

· multiplying the Outer terms,

· multiplying the Inner terms, and

· multiplying the Last terms

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