Given f(t)=t2 -t and h(x) = 3x+2 evaluate h(f(2))

Answer:

9/10

1/2+2/5

Since these fractions have different denominators, we need to find the least common multiple of the denominators.The least common multiple of 2 and 5 is 10, so we need to multiply to make each of the denominators = 10

1/2 ∗ 5/5 = 5/10

5/2∗ 2/2= 4/10

Since these fractions have the same denominator, we can just add the numerators

5/10+ 4/10 = 9/10

Answer:

1/10

Step-by-step explanation:

Begin by writing the given phrase as an equation. The sum of two-fifths and f can be written 2/5+f, and that term is equal to one-half, written 1/2. Written together,

2/5+f=1/2.

Begin by subtracting 25 from each side,

2/5+f−2/5=1/2−2/5.

Simplify and rewrite with a common denominator,

f=1/2⋅5/5−2/5⋅2/2

and simplify again,

f=5−4/10,

and solve for f,

f=110.

Rick would need to have at least 100 cars on hand to immediately be able to deliver any car (model, option package, color).

To immediately deliver any car, Rick Rich's dealership must have all possible combinations of Mercedes models, option packages, and colors in stock.

With five models, four option packages, and five colors, there are 5 x 4 x 5 = 100 possible combinations.

Therefore, Rick would need to have at least 100 cars on hand, each representing a unique combination of model, option package, and color. It's worth noting that having exactly 100 cars on hand would only allow Rick to deliver one of each possible combination, so it may be prudent to have additional inventory on hand to meet demand for more popular combinations.

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Answer:ok

Step-by-step explanation:

ol

Answer:

x<1/2

Step-by-step explanation:

Answer:

the answer is D

Step-by-step explanation:

Q1) The angle A in the given triangle is: 29.93°

Q2) The length of the ladder to the nearest whole number is: 131 ft

Pythagoras Theorem is defined as the way in which you can find the missing length of a right angled triangle.

The triangle has three sides, the hypotenuse (which is always the longest), Opposite (which doesn't touch the hypotenuse) and the adjacent (which is between the opposite and the hypotenuse).

Pythagoras is in the form of; a² + b² = c²

Q1) Thus:

BC = √(15² - 13²)

BC = 7.4833

Thus:

7.4833/sin A = 15/sin 90

(7.4833 * sin 90)/15 = sin A

0.4989 = sin A

A = sin⁻¹0.4989

A = 29.93°

Q2) Using Trigonometric ratio, the height of the ladder is:

100/x = cos 40

x = 100/0.766

x = 131 ft

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Answer:

127

Step-by-step explanation:

PR is straight line with the measure of 180 degrees

to find PQT we need to subtract 53 from 180

180 - 53 = 127

The first equation is incorrect.

The second equation is correct.

The third equation is correct.

Let's go through each equation and determine whether it is correct or incorrect:

(b²+7b-9)+(4b-6b²) = -8b² + 14b-9

To determine if this equation is correct, we need to simplify both sides and check if they are equal.

On the left side:

(b²+7b-9)+(4b-6b²) = b² - 6b² + 7b + 4b - 9 = -5b² + 11b - 9

On the right side:

-8b² + 14b - 9

Comparing both sides, we can see that -5b² + 11b - 9 is not equal to -8b² + 14b - 9. Therefore, the equation is incorrect.

(4a+6)-(3a²-9a+1)=-3a²+ 13a +5

Again, we need to simplify both sides of the equation and check if they are equal.

On the left side:

(4a+6)-(3a²-9a+1) = 4a + 6 - 3a² + 9a - 1 = -3a² + 13a + 5

On the right side:

-3a² + 13a + 5

Comparing both sides, we can see that -3a² + 13a + 5 is equal to -3a² + 13a + 5. Therefore, the equation is correct.

(12c-8c²)+(5c²- 10c) = -3c²+2c

Again, let's simplify both sides and compare them.

On the left side:

(12c-8c²)+(5c²- 10c) = 12c - 8c² + 5c² - 10c = -3c² + 2c

On the right side:

-3c² + 2c

Comparing both sides, we can see that -3c² + 2c is equal to -3c² + 2c. Therefore, the equation is correct.

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Answer:

I think 8 is the geometric

Answer:

1)  C

2) F

3) A

Step-by-step explanation:

Given that :  X = number of Wildlife raft Trips to be scheduled.

while Y = number of Group Sailing Lessons to be scheduled.

1) Constraint (1) : 120x + 160y ≥ 1800

Represents the Minimum revenue requirement

2) Constraint (4) : 6x ≥ 30

Represents The demand of raft trips that must be satisfied.

3) Constraint (6) : x + y ≤ 12

Represents The maximum number of captions who can be deployed.

weight of bag :

The slope and the y-intercept of the line y = 4x + 5 are given as follows:

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

The coefficients m and b represent the slope and the intercept, respectively, and are explained as follows:

The function for this problem is given as follows:

y = 4x + 5.

Hence the slope and the intercept are given as follows:

The problem asks for the slope and the intercept of y = 4x + 5.

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The volume of the described solid is V = 16r³/3

Given,

A solid line S should be drawn between z=a and z=b. If S has a cross-sectional area of Px through x and is perpendicular to the x-axis, then A (x)

Volume of S = limₙ→∝ ∑i=₁ⁿ A(xi) Δx = \(\int\limits^b_a {A(x)} \, dx\)

The equation of circle x² + y² = r² where r is the radius of the circle.

Equation of upper semicircle yu= √(r²-x²)  and

Equation of lower semicircle yl = -√(r²-x²)

Area of cross-section A(x) = (yu² - yl²)

Substitute yu and yl values

A(x) = [√(r²-x²) - (-√(r²-x²) )]² = 4(r² -x²)        (1)

The limit for volume v varies from -r to r

Thus Volume v = ₋\(\int\limits^r_r {A(x)} \, dx\)

Substitute A(x) from (1)

V = ₋\(\int\limits^r_r {4(r^{2}-x^{2} ) } \, dx\)

⇒V = 4[r²x - x³/3 ]

⇒V = 4(r³ - r³/3) - 4(-r³ + r³/3) = 4[2 (r³ - r³/3)] = 16r³/3

The volume of the described solid S where the base is a circular disk or radius r and parallel cross sections perpendicular to the base are squares is V = 16r³/3

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The length of the square in centimetres in algebraic expression is 25m

The perimeter of a square is m meters.

The length of the each side of the square in centimetres can be represented in an algebraic expression as follows:

Therefore,

perimeter of a square = 4l

where

Therefore,

m = 4l

where

l = m / 4 meters.

Therefore, the side length of the square in centimetres is as follows:

1 meters = 100 cm

m / 4 meters  = ?

cross multiply

length of the square in meters = m / 4 × 100

length of the square in meters = 100m / 4

length of the square in meters = 25m

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9514 1404 393

Answer:

Step-by-step explanation:

For there to be no solution, the lines represented by the left-side and right-side expressions must be parallel. That is, the coefficients of x must be identical,

  a = c

and the y-intercepts must be different:

  b ≠ d.

Answer:

82

Step-by-step explanation:

\(4^3 + \frac{96}{8} \cdot 5 - 42 = 64 + 12\cdot 5 - 42 = 64 + 60 - 42 = 82\)

Answer:

82

Step-by-step explanation:

PEMDAS

\(4^{3}\) + [(96 ÷ 8) x 5] - 42

\(4^{3}\) + [(12) x 5] - 42

4^3 + (60) - 42

64 + 60 - 42

124 - 42

82

hope this helps :)

Answer:

6:5

18:15

Step-by-step explanation:

Answer:

a and b

Step-by-step explanation:

Step-by-step explanation:

1. 9

2. 105

3. 8

4.0

Mark me branliest

The function \(f(x) = -\sqrt{(x + 11 - 3)}\), evaluated at x = -7 has a real output, which is -1.

Given is a function \(f(x) = -\sqrt{(x + 11 - 3)}\), we need to check if x = -7, gives a real output or not,

Let's evaluate the function f(x) = -√(x + 11 - 3) at x = -7 and determine if it has a real output.

Plugging in x = -7 into the function, we get:

\(f(-7) = -\sqrt{(-7 + 11 - 3)}\)

Simplifying further:

f(-7) = -√(1)

The square root of 1 is 1, so:

f(-7) = -1

Therefore, the function \(f(x) = -\sqrt{(x + 11 - 3)}\), evaluated at x = -7 has a real output, which is -1.

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Answer:

638.45

Step-by-step explanation:

The interest on the couch will be:

0.13 * $565 = $73.45

So the total amount Sharon paid for the couch with interest is:

$565 + $73.45 = $638.45

Answer:

y = 9

Step-by-step explanation:

 from both sides of the equation

−2+6=−12

-2y+6=-12−2y+6=−12

−2+6−6=−12−6

-2y+6

−2y+6−6=−12−6

2

Simplify

Subtract the numbers

Subtract the numbers

−2=−18

-2y=-18−2y=−18

3

Divide both sides of the equation by the same term

−2=−18

-2y=-18−2y=−18

−2−2=−18−2

-2−2−2y=−2−18

4

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=9

Answer:

\( x = - 1\)

\(x + 1 = 0\)

\( {(x + 1)}^{2} = {x}^{2} + 2x + 1 = 0\)

So m = 2 and n = 1, meaning m + n = 3.

Answer:

Given that the vertices of quadrilateral PQRS are P(6,3), Q(4,2), R(2,4) and S(4,5) and the quadrilateral is dilated with a scale factor of 2, about the origin.

Now, let's find the new vertices of the dilated image:

Vertex P is dilated by a scale factor of 2, its new coordinates will be (2 × 6, 2 × 3) = (12, 6). Therefore, the new vertex P' is at (12, 6).

Vertex Q is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 2) = (8, 4). Therefore, the new vertex Q' is at (8, 4).

Vertex R is dilated by a scale factor of 2, its new coordinates will be (2 × 2, 2 × 4) = (4, 8). Therefore, the new vertex R' is at (4, 8).

Vertex S is dilated by a scale factor of 2, its new coordinates will be (2 × 4, 2 × 5) = (8, 10). Therefore, the new vertex S' is at (8, 10).

Therefore, the coordinates of the vertices of the final image are P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).So, the correct option is D. P’(12, 6), Q’(8, 4), R’(4, 8), and S’(8, 10).

Step-by-step explanation:

Hope this helps you!! Have a good day/night!!

first off, let's notice that "x" and "y" are encapsulating a function in terms of time or namely "t", and that dy/dt is decreasing at a rate of 3 cm/s, since the rate is decreasing, that makes the rate negative, thus is changing at -3 cm/s.

\(xy=12\implies \stackrel{product~rule}{\cfrac{dx}{dt}y~~ + ~~ x\cfrac{dy}{dt}}~~ = ~~0\implies \cfrac{dx}{dt}y~~ + ~~x(-3)~~ = ~~0 \\\\\\ \cfrac{dx}{dt}y=3x\implies \left. \cfrac{dx}{dt}=\cfrac{3x}{y} \right|_{(\stackrel{x}{4},\stackrel{y}{3})}\implies \cfrac{3(4)}{3}\implies 4\)

Answer:

the ordered pair is (-2,11)

Answer:

See below ~

Step-by-step explanation:

Equating the system of equations :

When x = -1 :

When x = -2 :

Answer:

x=21 not sure if this is the answer

Answer:

1728

Step-by-step explanation: