g the complete bipartite graphs kn,n and kn,n 1 have the maximum possible number of edges among al

The values of the angles given are: 0,90,180,240,270,360,420,480,540,600,630,660,720 and

he sine of an angle is the trigonometric ratio of the opposite side to the hypotenuse of a right triangle containing that angle.  It is defined as the length of the opposite side divided by the length of the hypotenuse

The given angles are: 0,30,45,90,120,135,180,210,225,240,270,300,315,330,360

2∅  2*∅ = 0, 90,180,240,270,360,420,480,540,600,630,660,720

sin 2∅ = sin0 = 0; Sin90=1;  sin180=0; sin240= -0.8660; sin270 = -1;

Each angle is multiplied by sine sine360 =1; sin420 = 0.8660; sin480= 0.9848; sin540=1; sin600=-0.8660; sin630=-1; sin660=0.8660; sin720= 0.9397

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Answer:

He used 5 47 cent stamps and 8 7 cent stamps

subtract 0.47 from 2.91 until you get 0.56 then you begin to subtract 0.07 to get 0.

The value of x = ±5.

What is Quadratic Equation?

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where ‘a’ is called the leading coefficient and ‘c’ is called the absolute term of f (x).

Method 1 :

⇒ 16x² - 400 = 0

⇒ 16x² = 400

⇒ x² = 400/16

⇒ x² = 25

⇒ x = ±5

Method 2 :

⇒ 16x² - 400 = 0

⇒ 16(x² - 25) = 0

⇒ x² - 25 = 0

⇒ x² = 25

⇒ x = ±5

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Answer:

\(\frac{1}{7}\)

Step-by-step explanation:

6 weeks is 42 days.

6 days/42 days = 1/7

Answer:

2x

Step-by-step explanation:

5, 10, 20, 40, 80

each step is multiplying by 2, therefore the sequence is 2x

Answer:

Step-by-step explanation:

You want a graph and the x-intercept of the line through (-3, 4) with y-intercept 1.

The slope formula gives you the slope you can use with the slope-intercept equation.

  m = (y2 -y1)/(x2 -x1)

One point is given as (-3, 4). The y-intercept is (0, 1), so the slope is ...

  m = (1 -4)/(0 -(-3)) = -3/3 = -1

Then the equation for the line is ...

  y = mx +b

  y = -1x +1

  y = -x +1 . . . . simplify

The x-intercept is the point that has y-coordinate 0:

  0 = -x +1

  x = 1 . . . . . . add x

The line crosses the x-axis at x

The equation of the line passing through the two points (4,2) and (-3,1) is 7y-x-10=0

Equation of a line is an algebraic form of showing the set of points, which together forms a line in a coordinate system.

Given the line passes through the points (4,2) and (-3,1)

Here, x1=4, y1=2, x2=-3, y2=1

So, the slope of the line (m)= \(\frac{y2-y1}{x2-x1}\\\)=\(\frac{1-2}{-3-4}\\\)=\(\frac{1}{7}\)

Now we know, the equation of the line is given as,

y-y1=m(x-x1)

Putting the value of y1 and x1 in the equation we get,

y-2=\(\frac{1}{7}\)(x-4)

7y-14=x-4

7y-x-10=0

Hence the equation of the line that passes through the two points (4,2) and (-3,1) is 7y-x-10=0.

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Answer:

Coordinates of G = \((2,0)\)

Step-by-step explanation:

Given: Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3).

To find: coordinates of G

Solution:

Midpoints of a side joining points \((a,b),\,(c,d)\) are given by \((\frac{a+c}{2},\frac{b+d}{2})\)

Diagonals of a parallelogram bisect each other.

So,

Midpoint of DF = Midpoint of EG

Midpoint of DF = \((\frac{-4+3}{2},\frac{-2+3}{2})=(\frac{-1}{2},\frac{1}{2})\)

Midpoint of EG = \((\frac{-3+x}{2},\frac{1+y}{2})\)

Let coordinates of G be \((x,y)\)

Therefore,

\((\frac{-1}{2},\frac{1}{2}) =(\frac{-3+x}{2},\frac{1+y}{2})\\\\\frac{-1}{2}=\frac{-3+x}{2},\,\frac{1}{2}=\frac{1+y}{2}\\\\-1=-3+x,\,1=1+y\\\\x=-1+3,\,y=1-1\\x=2,\,y=0\)

So,

Coordinates of G = \((2,0)\)

Answer:

9.16 × 10-6

Step-by-step explanation:

Answer:

6.97

Step-by-step explanation:

Answer: There are 9 mangoes left in the basket.

Step-by-step explanation:

(2/5) * 15 = 6.

15 - 6 = 9.

Answer:-1/6

Step-by-step explanation:

Draw a line out in the 2nd quadrant.

Your y=\(\sqrt{35}\)    hypotenuse=6  use pythagorean theorem to solve for x

6² = 35 + x²

x=1

so

cosΘ = -1/6

Answer:

314.00

Step-by-step explanation:

Answer:

15.70

Step-by-step explanation:

A=r^2

Answer:

A: the probability that a 1 is received is 0.56.

B:  the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).

Step-by-step explanation:

To solve this problem, we can use conditional probabilities and the concept of Bayes' theorem.

a. To find the probability that a 1 is received, we need to consider the two possibilities: either a 1 was sent and remained unchanged, or a 0 was sent and got flipped to a 1 by the random error.

Let's denote:

P(1 sent) = 0.6 (probability a 1 is sent)

P(0→1) = 0.2 (probability a 0 is flipped to 1)

P(1 received) = ?

P(1 received) = P(1 sent and unchanged) + P(0 sent and flipped to 1)

= P(1 sent) * (1 - P(0→1)) + P(0 sent) * P(0→1)

= 0.6 * (1 - 0.2) + 0.4 * 0.2

= 0.6 * 0.8 + 0.4 * 0.2

= 0.48 + 0.08

= 0.56

Therefore, the probability that a 1 is received is 0.56.

b. If a 1 is received, we want to find the probability that a 0 was sent. We can use Bayes' theorem to calculate this.

Let's denote:

P(0 sent) = ?

P(1 received) = 0.56

We know that P(0 sent) + P(1 sent) = 1 (since either a 0 or a 1 is sent).

Using Bayes' theorem:

P(0 sent | 1 received) = (P(1 received | 0 sent) * P(0 sent)) / P(1 received)

P(1 received | 0 sent) = P(0 sent and flipped to 1) = 0.4 * 0.2 = 0.08

P(0 sent | 1 received) = (0.08 * P(0 sent)) / 0.56

Since P(0 sent) + P(1 sent) = 1, we can substitute 1 - P(0 sent) for P(1 sent):

P(0 sent | 1 received) = (0.08 * (1 - P(0 sent))) / 0.56

Simplifying:

P(0 sent | 1 received) = 0.08 * (1 - P(0 sent)) / 0.56

= 0.08 * (1 - P(0 sent)) * (1 / 0.56)

= 0.08 * (1 - P(0 sent)) * (25/14)

= (2/25) * (1 - P(0 sent))

Therefore, the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).

A message is coded into the binary symbols 0 and 1 and the message is sent over a communication channel. The probability a 0 is sent is 0.4 and the probability a 1 is sent is 0.6. The channel, however, has a random error that changes a 1 to a 0 with probability 0.2 and changes a 0 to a 1 with probability 0.1. (a) What is the probability a 0 is received? (b) If a 1 is received, what is the probability a 0 was sent?

the total time is ,

3/4 + 1/2 + 1/4 =

so the total time is

9/4 hrs = 2.25 hours

Quotient :  2x⁴ - 4x³ - 7x² + 5x + 1 

Remainder :  10 

Answer:

-10

Step-by-step explanation:

Answer:

7x3=21

467 divided by 21 = 22

22 is your length

Step-by-step explanation:

Answer:

\(y - 4 = - 3(x - 2)\)

Answer:

Definitely not "feels"!

Step-by-step explanation:

I would go with " Always" aka "A"

Answer:

I think C, never irrational

Step-by-step explanation:

I feel you, link scams are horrible.

If this answer helped, please give brainliest! It would help a lot if you gave it :D

Total area = 104+24 = 128 sq.in ,  Option C is the right answer.

The missing figure is attached with the answer.

The space occupied by a two dimensional figure is called Area.

The figure given in the question can be divided into two figure

A rectangle of 8 * 13 inch

and a triangle of 8 * 6 inch

The area of a rectangle is given by

Length * Breadth

8 * 13

= 104 sq.inch

The area of the triangle is given by

(1/2) * base * height

= (1/2) * 8 * 6

= 24 sq.inch

Total area = 104+24 = 128 sq.in

Therefore Option C is the right answer.

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Answer:

Answer: 71 cups

Step-by-step explanation:

71 x 1.5 = 106.5 - 5.25 = 101.25

Plz mark me brainliest

Answer:

100=1.50x-5.25

105.25=1.50x

x=70.167

so to get at least $100 a day she'd have to sell 71 cups

Answer:

-178 = u

Step-by-step explanation:

227 = 49-u

Subtract 49from each side

227-49 = 49-49-u

178 = -u

Multiply each side by -1

-178 = u

Answer:

C

Step-by-step explanation:

well if you multiply each of tjem you would only sabe money on c the other choices would cause you to lose money so its c

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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The probability of tossing 10 tails in a row is  \(\frac{1}{1024}\)

A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1, and they can also be expressed as percentages ranging from 0% to 100%.

Given that,

When a fair coin is tossed 10 times, the sample size (n) is:

n = \(2^{10}\)

This is so because a fair coin has 2 sides.

So, we have:

n = 1024

There is only one occurrence of having 10 tails in a row in the 1024 possible outcomes.

So, the probability is:

P = \(\frac{1}{1024}\)

Therefore,

The probability of tossing 10 tails in a row is  \(\frac{1}{1024}\)

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Answer:

x is 60⁰ because 180 - 40 is 120 divide it by 2 because the bottem angles are equal and u get 60

Answer;

Explanation;

Here, we want to get the solution a pair of linear equation which we are to solve simultaneously by the graphical method

We need to plot the graphs of these two lines; The point at which the lines meet will represent the solution to the system of linear equations

The general equation of a straight line is;

where m is the slope and b is the y-intercept

To plot the lines, we need the x-intercepts and the y-intercepts

This refer to the point at which the line touches the x and y axes respectively

Let us take the lines one after the other;

The y-intercept here is -4; so the point is (0,-4)

To get the x-intercept value, we simply set y to zero and get the value of x

So the x-intercept is (-4/3,0)

To plot the line; we simply join (0,-4) and (-4/3,0)

For the second line;

We have the y-intercept as -2

So the point is (0,-2)

To get the x-intercept, we simply set y to 0 and solve for x

So, the x-intercept point is (-2,0)

We can now join (0,-2) and (-2,0) to represent the second line

Proceeding, we get the lines on the cartesian grid

This is shown in the attachment below;

As we can see from the plot, the lines touch at the point (-1,-1) and that represents the solution to the equation

suppose they are independent of a geometric random variable with parameter p. Let M = max(x1,....,xN) (a) Find P{M<} by conditioning on N is  nλe^(-nλx)

Given fx (x) = λe^λx

Fx (x) = 1 – e^-λx      x…0

To find distribution of Min (X1,….Xn)

By applying the equation

fx1 (x) = [n! / (n – j)! (j – 1)!][F(x)]^j-1[1-F(x)]^n-j f(x)

For minimum j = 1

[Min (X1,…Xn)] = [n!/(n-1)!0!][F(x)]^0[1-(1-e^-λx)]^n-1λe^-λx

= ne^[(n-1) λx] λe^(λx)

= nλe^(-λx[1+n-1])

= nλe^(-nλx)

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