Fully factorise 27t² + 15t​

Answer:

x< -12

Step-by-step explanation:

-1/2x>6
x-2.   x-2

x>-12

Since we multiply by we negative we flip the sign

x< -12

Hopes this helps

Answer: 7.62

Step-by-step explanation:

Answer:

Adamu have 25 cards.

hope this answer helps you dear....take care and may u have a great day ahead! if I have any doubt feel free to ask!

Adamu has 25 Cards

This involves basic arithmetic calculations and simultaneous equations.

Let the following letters represent the number of cards each has;

A: ADAMU

F: FUNKE

S: SHEHU

K: KWAME

T: TANKO

- From online research, the Total Number of cards is 134 and not 133. Thus;

A + F + K + S + T = 134  --- eq 5

Let's put A - 5 = T and A + 4 = K in eq 3 to get;

A + F = (A + 4) + (A - 5) + 13

A + F = 2A + 12

F = 2A - A + 12

F = A + 12

Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;

A + A + 12  + A + 4 + A - 2 + A - 5 = 134

Simplifying gives;

5A + 9 = 134

5A = 134 - 9

5A = 125

A = 125/5

A = 25

Adamu has 25 Cards

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Using the trigonometry ratio, he angle of elevation of the ramp to the nearest degree is 11°.

In the given question,

A ramp goes from a doorway of a building to the ground.

The end of the ramp connected to the doorway is 1 foot above the ground.

The distance along the ramp to the building is 5 feet.

We have to find the angle of elevation of the ramp to the nearest degree.

The distance is 5 feet.

The height is 1 foot.

To find the angle of elevation we used the trigonometry ratio.

According the trigonometry ratio, we know that tangent is the ratio between height and distance.

We can write it as

tan A=height/distance

Now putting the value

tan A=1/5

tan A=0.2

So A = arctan(0.2)

A = 11.30°

A ≈ 11°

Hence, the angle of elevation of the ramp to the nearest degree is 11°.

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The length of the arc defined by the central angle of 312 degrees is 26π cm.

The formula for the arc length of a circle is given by:

L = (θ/360) × 2πr

where L is the length of the arc, θ is the central angle in degrees, and r is the radius of the circle.

Substituting the given values, we get:

L = (312/360) × 2π(30)

L = (26/30) × π × 30

L = 26π cm

Therefore, the length of the arc defined by the central angle of 312 degrees is 26π cm.

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Answer:

7mph

Step-by-step explanation:

Given

Time Taken to go upstream Tup = 35 min

Time Taken to go downstream Tdown=21 min.

Let the absolute speed (i.e speed relative to the stationary riverbed) be :

Vup : going upstream

Vdown: going downstream.

We know that the distance traveled upstream = distance traveled downstream, hence we can equate both distances, i.e. :

Distance Traveled Upstream = Distance Traveled Downstream

Vup · Tup = Vdown · Tdown   (substituting the values for time above)

35Vup = 21Vdown

Vup = (21/35) Vdown ------------(eq 1)

We are also given that the motorboat can travel at V = 28 mph relative to the water.

Since going upstream, we are going AGAINST the current, relative to the riverbed, we expect to be travelling slower. In fact, the absolute difference between the speed relative to the water (i.e V = 28 mph) and the speed relative to the seabed (i.e Vup), is equal to the speed of the current.

The same can be said for going downstream WITH the current, that the absolute difference between V = 28mph and Vdown is also equal to the speed of the current.

Hence we can equate the two:

28 - Vup = Vdown - 28

Vup + Vdown = 2(28)

Vup + Vdown = 56 ---------------------(eq 2)

If we solve the system of equations (eq 1) and (eq2), we will get

Vup = 21 mph and Vdown = 35 mph

(sanity check tells us that this makes sense because we expect to be going slower upstream because we are going against the current)

Hence current speed

= 28-Vup

= 28 - 21

= 7 mph. (answer)

Sanity Check:

Current speed can also be written:

= Vdown-28

= 35 - 28

= 7 mph (same as what we found above, so this checks out)

The speed of the current motorboat = 7 mph

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Speed of boat in still water = 28 mph

Let the speed of stream = w

Here, The upstream time is 35 min = 35/60 h = 7/12 h

downstream time is 21 min = 21/60 h = 7/20 hours

Since, The distance (d = vt) traveled either way is the same, but at different speeds and times.

Hence, Set upstream and downstream distances (vt) equal and solve for w as;

⇒ (28 - w)(7/12) = (28 + w)(7/20)

⇒ 20 (28 - w) = 12 (28 + w)

⇒ 5(28 - w) = 3(28 + w)

⇒ 140 - 5w = 84 + 3w

⇒ 140 - 84 = 5w + 3w

⇒ 56 = 8w

⇒ w = 7

Thus, The speed of the current = 7 mph

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Answer:

122.30 cm²

Step-by-step explanation:

The figure is a triangular prism.

Formula for calculating surface area of a triangular prism = bh + L(S1 + S2 + S3)

Where,

b = 11 cm

h = 4.3 cm

S1 = 8 cm

S2 = 6 cm

S3 = 11 cm

L = 3 cm

Surface area = 11*4.3 + 3(8 + 6 + 11)

= 47.3 + 3(25)

= 122.3 cm²

Answer:

6

Step-by-step explanation:

because fish don't drown

The point in the solution set from the graph is (0, 0)

From the question, we have the following parameters that can be used in our computation:

y < -5/2x - 2

y ≥ -1/2x + 2

Next, we plot the graph of the system of the inequalities

The graph is given

From the graph, we have solution to the system to be the shaded region

The point in the solution set from the graph is (0, 0)

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Answer:

sec(thita)=√8/3 I think that

Answer:

No. It is an inverse variation.

Step-by-step explanation:

6= xy

Making y the subject of formula:

\(y = \frac{6}{x} \)

For a direct variation, the equation would be in the form of y=kx, where k is a constant.

However, the equation above is in the form of \(y = \frac{k}{x} \).

Thus, 6=xy does not show direct variation.

The statement, For every point on the graph of f(x), there is a point on the graph of F⁻¹(x) with reversed coordinates is false.

In relation to the original function f, the inverse function is denoted by the symbol f⁻¹, and both the original function's domain and its range are transformed into the inverse function's domain and range, respectively. Swapping (x, y) with (y, x) with reference to the line y = x yields the graph of the inverse function.

We know that inverse of function is NOT the reciprocal of f. The composition of the function f and the reciprocal function f inverse gives the domain value of x.

Hence, the statement, For every point on the graph of f(x), there is a point on the graph of F⁻¹(x) with reversed coordinates is false.

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Answer:

I can explain how to complete each of the steps you have provided.

1. Draw a point at (1, -2)

This is a simple step. Just mark a dot on your paper at the coordinates (1, -2).

2.

Draw an 8-unit long radius

Using your compass, set the radius to 8 units. Place the compass on the point you drew in step 1 and draw a circle around it, making sure that the radius is 8 units long.

3. Using a compass

Draw a circle with your point from step one as your center and the point from step two as the side: This step is already completed in step 2.

4. Using a protractor draw a 70 degree arc

Place your protractor on the center of the circle (the point you drew in step 1) and draw a 70 degree arc on the circle.

5. Draw a central angle which intercepts your arc

Use a straight edge to draw a line from the center of the circle to each endpoint of the arc you drew in step 4. This creates a central angle, which is an angle whose vertex is at the center of the circle and whose sides intercept the circle.

6. Draw an inscribed angle which intercepts a 40 degree arc

Use a straight edge to draw a line from one endpoint of the 70 degree arc to the other endpoint. Then, draw a perpendicular bisector of this line, which intersects the center of the circle. This creates a 40 degree arc on the circle. Draw a line from the center of the circle to one endpoint of the 40 degree arc, and draw a line from that endpoint to the other endpoint of the 40 degree arc. This creates an inscribed angle, which is an angle whose vertex is on the circle and whose sides intercept the circle.

7. Draw a tangent line

Choose a point on the circle that is not on the 70 degree arc. Draw a line from that point tangent to the circle.

8. Draw a secant line

Choose two points on the circle that are not on the 70 degree arc. Draw a line through those points, which intersects the circle at two points.

9. Equation of your circle

The equation of a circle with center (a,b) and radius r is (x-a)^2 + (y-b)^2 = r^2. Using the coordinates of the center from step 1 and the radius from step 2, the equation of the circle is (x-1)^2 + (y+2)^2 = 64.

Answer:

d

Step-by-step explanation:

because the unit rate is 11/12 m p m

Answer:B and E

Step-by-step explanation:

Divided and multiply

Let's start with the given arc and its angle.

The angle YWX is going to be half the arc length.

YWX = 1/2 (226) = 113

Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.

(15x - 8) + 113 = 180

15x + 105 = 180

15x = 75

x = 5

Hope this helps!

Answer: I assume this is a activity on edge

x≥ -2

-2≤x

were the correct options

Answer:3 and 4

Step-by-step explanation:trust

Calista's grade on her last assignment is 98.

To determine Calista's grade on her last assignment, we can calculate the average grade using the given information.

The sum of Calista's grades on the first five assignments is: 62 + 88 + 92 + 74 + 78 = 394.

Since the average grade is given as 82, we can find the total sum of all six assignments by multiplying the average grade by the number of assignments, which is 6: 82 * 6 = 492.

To find Calista's grade on her last assignment, we subtract the sum of her grades on the first five assignments from the total sum: 492 - 394 = 98.

To determine Calista's grade on her last assignment, we can calculate the average grade using the given information.

The sum of Calista's grades on the first five assignments is: 62 + 88 + 92 + 74 + 78 = 394.

Since the average grade is given as 82, we can find the total sum of all six assignments by multiplying the average grade by the number of assignments, which is 6: 82 * 6 = 492.

To find Calista's grade on her last assignment, we subtract the sum of her grades on the first five assignments from the total sum: 492 - 394 = 98.

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The probability that all three number cubes will land on an odd number is 1/8

From the question, we have the following parameters that can be used in our computation:

Number of cubes = 3

Sections on each cube = 6

Odd sections on each cube = 3

This means that

P(Odd) = Odd sections/Total sections

So, we have the following representation

P(Odd) = 3/6

Simplify

P(Odd) = 1/2

For the three cubes, we have

P(All odd) = P(Odd)^Number of cubes

Substitute the known values in the above equation, so, we have the following representation

P(All odd) = (1/2)³

Evaluate

P(All odd) = 1/8

Hence, the probability is 1/8

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Answer: 1/8

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 ; l       .

                        .

      /.         ;      

      .

Answer:

  13 square units

Step-by-step explanation:

The bounding rectangle is 4 units wide and 5 units high, so has an area of 4×5 = 20 square units. From that are subtracted the areas of 4 triangles. 2 of them are 3 wide and 1 high, so have a combined area of 3×1 = 3 square units. The other two are 1 wide and 4 high, so have a combined area of 1×4 = 4 square units.

Then the area of the parallelogram is ...

  20 -3 -4 = 13 . . . . square units

Step-by-step explanation:

The equation has infinite solution p=2 that's tour variable

5 = 60

6 = 150

7 = 30

if you have any more questions let me know

Answer:

42 units

Step-by-step explanation:

Area of a trapezoid is always 1/2(b1+b2)*h

so here base 1 is 4 units, and base 2 is 10 units. When we add these we get 14, divided by 2 which is 7, and multiplied by height of 6, which is 42

Explanation

to find the regular monthly payment amount we need to use the formula:

so

Step 1

find the principal,

if you make a 20% down , it means the rest is 80 %, so the Principal will be 80 % of the total

Step 2

now, find the regular monthly payments amount

a) let

b) replace

so, the answer is 9201.41

We are told that we want a polynomial f(x) with the given zeros.

Recall that if we know the zeros oa polynomial, we can write the polynomial by writing the factors (x - zero of the polynomial) and multiply them all together.

For example, if we want a polynomial of degree 2 with zeros at 2 and 3, then the polynomial would be

In this case, we have a polynomial f(x) of degree 4. So far, we know that 3 is a zero and that -i is a zero. So we write the following

where a,b,c and d are the zeros of f(x). We know that 3 is a zero and that -i is a zero. So we have

So to fully describe f(x) we need to find the values of b and d. We are told that 3 is a zero of multiplicity 2. This means that the factor (x -3) appears two times in the factorization of f(x). So we can say that b=3. So we have

Now, we need to find the value of d. Note that we are told that -i is a zero of the function. -i is a complex number, so one important property of polynomials is that if a complex number a+bi is a zero of the polynomial, then the number a-bi (which is called the complex conjugate) is also a zero. Note that the complex conjugate of a complex number is calculated by leaving the real part intact and multiplying the imaginary part by -1.

In our case we have the complex number -i. So we can write -i= 0 - 1i . Then, its complex conjugate is i.

So, we have that d=i.

Then our polynomial would look like this

Note that

So our polynomial ends up being

a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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The range of the function is (c) all real numbers greater than or equal to 11

The table of values is given as:

x    y

0     11

2     25

5    46

7    60

From the question, we understand that:

She eats 11 gram of protein from the chicken drumstick

This means that the minimum y value is 11

Also, we understand that:

x can take decimal numbers.

This means that y can take any decimal number above 11

Hence, the range of the function is (c) all real numbers greater than or equal to 11

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Answer:

56811

Step-by-step explanation:

This is the answer as when you do the math it checks out

Answer:

0.14 is the answer as it is out of 100

Step-by-step explanation:

14/100

/100 as a decimal= 0.00

14/100 = 0.14

Answer: 0.771 you are welcome