for the number a[15:0] = 0110110010001111, a[14:13] is ______ a[3:2]

Answer: iy had around 5000 R

Explanation:

Answer:

Explanation:

1) Thrust coefficient at sea level.

Cfsl = TSL / Pca

TSL = Mp * Vc  + ( Pc - Pa )Ac

Mp = mass flux = 43.75 kg/s

∴ Cfsl  = Mp Vc / Pca  + ( Pc - Pa )/Pc * ( Ac / A* )

           = 1.6 - 0.04923 = 1.55

2) Specific impulse at sea

Isp = Vc / g = 2549.75 / 9.81

                   = 260 N.s

3) Altitude at optimal expansion

H = 3370 m

4) thrust coefficient at optimal expansion

CF = 1.6

attached below is the detailed solution

5) Mass flux through the throat

Mass flux = P1 * At / Cc

                = ( 7*10^6 * 0.01 ) / 1600

                = 43.75 kg/s

Answer:

1) 4.41 * 10^-4 kw

2) 2.20 * 10^-4 kw

Explanation:

Given data:

Filter = 500 m^3/min

dust velocity = 3g/m^3

bag ; length = 3 m , diameter = 0.13 m

change in pressure = 1 kPa

efficiency = 60%

1) Calculate the Fan power

First :

Calculate the total dust loading = 3 * 500 = 1500 g

To determine the Fan power we will apply the relation

\(n_{o} = \frac{\frac{p}{eg*Q*h} }{1000}\)    = \(\frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3 } }{1000}\)

fan power ( \(n_{0}\) ) = 4.41 * 10^-4 kw

2) calculate power drawn

change in P = 6 atm = 6 * 10^5 pa

efficiency compressor = 50%

hence power drawn = 4.41 * 10^-4 kw  * 50% = 2.20 * 10^-4 kw

The resistance of a parallel branch affects the current flowing through it in an opposite manner.

The sum of the power used by each resistor makes up the total power used in a parallel circuit. The voltage drop across each bulb is 6.0 V when the light bulbs are linked in parallel, and they all glow as the current passing through them combines to generate the current flowing through the battery. Each component of a series circuit receives the same amount of current. The circuit would be open and no current would flow if it were to be interrupted at any point. Therefore, the remaining bulbs would not be able to shine if one of them burns out.

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The following should be done by the team member:

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Answer:

control loop unit

Explanation:

Edmentum/Plato

Cadastral surveying is the sub-field of cadastre and surveying that specialises in the establishment and re-establishment of real property boundaries. ... A cadastral surveyor must apply both the spatial-measurement principles of general surveying and legal principles such as respect of neighboring titles.

A solid line around a component indicates that the component is complete. A dashed line around the component indicates that the component is being shown is not complete.

Answer:

A

Explanation:

Answer:

the temperature of the aluminum at this time is 456.25° C

Explanation:

Given that:

width w of the aluminium slab = 0.05 m

the initial temperature \(T_1\) = 25° C

\(T{\infty} =600^0C\)

h = 100 W/m²

The properties of Aluminium at temperature of 600° C by considering the conditions for which the storage unit is charged; we have ;

density ρ = 2702 kg/m³

thermal conductivity k = 231 W/m.K

Specific heat c = 1033 J/Kg.K

Let's first find the Biot Number Bi which can be expressed by the equation:

\(Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{h \dfrac{w}{2}}{k}\)

\(Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{100 \times \dfrac{0.05}{2}}{231}\)

\(Bi = \dfrac{2.5}{231}\)

Bi = 0.0108

The time constant value \(\tau_t\) is :

\(\tau_t = \dfrac{pL_cc}{h} \\ \\ \tau_t = \dfrac{p \dfrac{w}{2}c}{h}\)

\(\tau_t = \dfrac{2702* \dfrac{0.05}{2}*1033}{100}\)

\(\tau_t = \dfrac{2702* 0.025*1033}{100}\)

\(\tau_t = 697.79\)

Considering Lumped capacitance analysis since value for Bi is less than 1

Then;

\(Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]\)

where;

\(Q = -\Delta E _{st}\) which correlates with the change in the internal energy of the solid.

So;

\(Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]= -\Delta E _{st}\)

The maximum value for the change in the internal energy of the solid  is :

\((pVc)\theta_1 = -\Delta E _{st}max\)

By equating the two previous equation together ; we have:

\(\dfrac{-\Delta E _{st}}{\Delta E _{st}{max}}= \dfrac{ (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]} { (pVc)\theta_1}\)

Similarly; we need to understand that the ratio of the energy storage to the maximum possible energy storage = 0.75

Thus;

\(0.75= [1-e^{\dfrac {-t}{ \tau_1}}]}\)

So;

\(0.75= [1-e^{\dfrac {-t}{ 697.79}}]}\)

\(1-0.75= [e^{\dfrac {-t}{ 697.79}}]}\)

\(0.25 = e^{\dfrac {-t}{ 697.79}}\)

\(In(0.25) = {\dfrac {-t}{ 697.79}}\)

\(-1.386294361= \dfrac{-t}{697.79}\)

t = 1.386294361 × 697.79

t = 967.34 s

Finally; the temperature of Aluminium is determined as follows;

\(\dfrac{T - T _{\infty}}{T_1-T_{\infty}}= e ^ {\dfrac{-t}{\tau_t}}\)

\(\dfrac{T - 600}{25-600}= e ^ {\dfrac{-967.34}{697.79}\)

\(\dfrac{T - 600}{25-600}= 0.25\)

\(\dfrac{T - 600}{-575}= 0.25\)

T - 600 = -575 × 0.25

T - 600 = -143.75

T = -143.75 + 600

T = 456.25° C

Hence; the temperature of the aluminum at this time is 456.25° C

A line drawn from the leading edge to the trailing edge of an airfoil and equidistant at all points from the upper and lower contours is called the mean camber line.

The mean camber line is a very important concept in aerodynamics as it defines the overall shape of an airfoil and plays a key role in determining its aerodynamic characteristics, such as lift and drag. It is used to calculate the maximum thickness, maximum camber, and location of the maximum camber of an airfoil.

The mean camber line is typically used as a reference line when designing airfoils, and different shapes can be created by modifying it with specific curves and angles.

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Actions violated:

Actions to be taken:

Edit: Use these to write your paragraph.

$255 per hour

Total number of employed people = 16

(i) 5 people earn $15 per hour

That means that the total amount earned by those 5 is;

5 x $15 = $75 per hour

(ii) 4 people earn $17 per hour

That means that the total amount earned by those 4 is;

4 x $17 = $68 per hour

(iii) The remaining people earn $16 per hour.

There are 7 people remaining. i.e

16 - 5 - 4 = 7

That means that the total amount earned by those remaining (7) is;

7 x $16 = $112 per hour

The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e

Total = $75 + $68 + $112

Total = $255

Therefore, the total hourly wage earned by all 16 people is $255

Answer:

approaching a lady or a man

Answer: B.Idle relearn

Explanation:

When replacing an intake manifold gasket due to a vacuum leak, using a scan tool for idle relearn is a crucial step to complete the job. The Option B.

The scan tool is used to reset the idle control system and allow the engine's computer to relearn the correct idle speed and air/fuel mixture. This is important because the replacement of the intake manifold gasket can affect the engine's idle characteristics.

By using the scan tool to perform an idle relearn procedure, the engine management system can recalibrate and optimize the idle control parameters, ensuring smooth and stable idle operation. This step helps to restore the engine's performance and maintain proper combustion efficiency after the intake manifold gasket replacement.

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Kwan owns his own business installing, sanding, and finishing beautiful hardwood floors. Kwan works in the construction pathway of the architecture and construction career cluster. The correct option is B.

Construction Business refers to any trade that installs, modifies, or repairs any commercial building element, component, material, or device.

Construction works include the construction, demolition, repair, or renovation of buildings, roads, bridges, or other structures, as well as the fabrication of steel structures and all other civil works.

Kwan runs his own company that installs, sands, and finishes beautiful hardwood floors. Kwan works in the architecture and construction career cluster's construction pathway.

Thus, the correct option is B.

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Your question seems incomplete, the missing options are:

A. Design/Pre-Construction

B. Construction

C. Maintenance/Operations

D. Production

Answer:

Construction

Explanation:

I took the test

The expanse saved is $5000 and the net present value is $6946.

Hydraulic press is defined as a press machine that produces compressive force with the help of a hydraulic cylinder. The Pascal's law, which states that when pressure is applied to a confined fluid, the pressure changes across the entire fluid, underlies the operation of a hydraulic press.

20 years make up the term.

Since the MARR is 10% after taxes, the discount rate already takes taxes into account.

The initial cost is $51,000 (installment cost of $65,000 minus $14,000 market value of the defender).

Salvage is worth $10,000.

The annual operational expense savings are 14,000 - 9,000, = $5,000.

Differences in depreciation are irrelevant because only cash flows are taken into account by net present value.

The net present value = 42,568 + 1,486 - 51,000 =-$6,946

The present value of the net is negative.

Thus, the expanse saved is $5000 and the net present value is $6946.

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Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

The program that takes in a line of text as input, and outputs that line of text in reverse is as follows:

list1 = []

x = input("input your text for it to be reverse: ")

while x != "done" and "d" and "Done":

    list1.append(x)

    x = input("input your text for it to be reverse: ")

for i in list1:

    print(i[::-1])

The code is written in python

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Answer:

I don't know the answer but you can download Ga u t h math to answer that

Explanation:

no spacing it is just can't lay aside

Answer:

Explanation:

B evaporator outlet: on the suction line between the evaporator and the compressor

The kinematics we can find the time to cross the Atlantic is 67 days.

The kinematics studies the movement of the body making relationships between the position, the speed and the acceleration of the same.

The average velocity is defined as the relation between the displacement between the time of the interval

           v = \(\frac{\Delta x}{t}\)

           Δt = \(\frac{\Delta x}{v}\)

Where v is the velocity, x the displacement t time

In this case they indicate the displacement is Δx = 3000 mi and the speed is v = 50 m / min

The system of units allow data to be exchanged with precision and safety, for this there is currently the international system of measurements (SI), where the unit of length is the meter and the unit of time is the second, let's reduce the magnitudes given to these units.

           Δx = 3000 mi (  ) = 4.828 10⁶ m

            v = 50 m / min ( ) = 0.833 m / s

Now we can calculate the time to cross the Atlantic

            Δt = 4.828 10⁶ / 0.833

            Δt = 5.796 10⁶ s

Let's reduce to days

            Δt = 5.796 10⁶ s (  ) (  )

            Δt = 67 days

In conclusion using kinematics we can find the result of the time to cross the Atlantic is 67 days.

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Answer:

Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.

Explanation:

For example, in our furniture assembly problem we may have the following action: "Attach Leg A to the top using two screws."

This action would have several preconditions, such as "Leg A and the top are in the correct position" and "There are two screws available." The action would also have an effect, namely, "Leg A is attached to the top." Additionally, the action might have a duration or time requirement, such as "It should take no more than 2 minutes to complete the action." Overall, actions in a planning problem need to be carefully designed to ensure that they have well-defined preconditions, effects, and time requirements, as well as being feasible and logically consistent. By defining actions in this way, planners can reason about how to achieve complex goals using a sequence of actions.

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The answer to your question is c. ListBox. A ListBox is a user interface element that displays a collection of items, or values, with one item per line. It is a common control in many user interface frameworks, including Windows Forms and WPF in Microsoft .NET.

A ListBox can be populated with items at design time or at runtime, and it can be data-bound to a data source to display dynamic data. The user can select one or more items in the ListBox, and the selected items can be retrieved programmatically.

In addition to displaying text items, a ListBox can display images, icons, or other user interface elements as items. The appearance and behavior of a ListBox can be customized by setting various properties, such as the font, color, selection mode, and sorting.

Overall, a ListBox is a versatile and useful control for displaying and selecting collections of items in a user-friendly way. It is a fundamental element of many user interfaces and can be easily implemented in various programming languages and platforms.

A ListBox object displays a collection of items, or values, with one item per line. This user interface element allows users to select one or multiple items from the provided list. ListBox is commonly used when there is a need to present multiple options for users to choose from, while keeping the layout organized and compact.

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a) Laminar flow occurs when a liquid or gas flows smoothly in a parallel direction with little disruption between the layers. Laminar flow occurs at slow speeds, low flow rates, and low velocities.

b) \(ρ = 0.9994 kg/m³v = 7.2 m³/mink = 0.02953 W/m\).\(°CA = 0.0225 m²q = vA = 7.2 x 0.0225 = 0.162 m³/min\) =\(2.7 x 10⁻⁶ m³/sµ = pv/k = 0.9994 x 2.097 x 10⁻⁵/0.02953 = 0.000703m = ρq = 0.9994 x 2.7 x 10⁻⁶ = 0.0027 kg/s Re = md/µ = 0.0027 x 12/0.000703 = 46.10\)

Therefore, the volume flow rate below which the flow will not be turbulent is approximately 0.66 m³/min.

c)\(XT = (0.05 Re Pr (D/2)) / (1 + 12.7 Pr^(2/3)(1 - (D/2L)^(2/3)))\)Where, D is the diameter of the duct and L is the length of the duct, and XT is the thermal entrance length.

\(XT = (0.05 × 46.1 × 0.7154 × 0.09) / (1 + 12.7 × 0.7154^(2/3) (1 - (0.09/12)^(2/3)))= 0.32 meters\)

Therefore, the length of the thermal entrance region in the duct is approximately 0.32 meters.

d)\(h = Nuk/kh = (Nu x k)/DNu = 0.023 (46.1)^(4/5) (0.7154)^0.4Nu = 40.5h = (40.5 x 0.02953) / 0.09= 13.3 W/m²K\)

Therefore, the coefficient of convection at the exit point of the duct is approximately 13.3 W/m²K.

e) \(Q = hA(Ts - Tm)Q = mCp (Tm2 - Tm1)\)

\(Tm2 = Tm1 + (Q/(mCp))Tm2 = 60 °C, Tm1 = 90 °C, Ts = 60 °C, Cp = 1008 J/kg°C, m = 0.0027 kg/s, A = 0.0225 m²Q = hA(Ts - Tm) = mCp(Tm2 - Tm1)13.3 × 0.0225 × (60 - Tm) = 0.0027 × 1008 × (60 - 90)Tm = 75.27 °C\)

Therefore, the temperature of air at the exit point of the duct under the constant surface temperature condition is approximately \(75.27 °C\).

f) An engineer suggests inserting a twisted metal plate in the square duct. A twisted tape is a passive heat transfer enhancer that can improve heat transfer rates in heat exchangers and other heat transfer applications. The twisted tape enhances heat transfer by increasing turbulence and promoting greater mixing between the fluid and the duct's walls.

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Answer:

The best chose will happen to be C

Answer:

They protect the entire hand from abrasion and punctures, and are a dependable, comfortable glove for a wide variety of jobs. Drivers' gloves are available in various types of leathers and can be unlined or lined for cold weather. Leather palm gloves provide maximum protection against abrasive and puncture hazards.

Gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

Abrasive is defined as a substance, sometimes a mineral, used to shape or polish a product by rubbing, which causes some of the workpiece to be removed due to friction. Abrasives are a particular kind of extremely hard material that are utilized in a variety of residential, industrial, and technological applications. A portion of the work piece is worn away when the abrasive is rubbed against it.

These leather gloves each offer particular levels of comfort, protection, and durability. Some of these leather gloves are suitable for use by those handling dangerous chemicals and sparks. Some can provide cut protection to an extreme degree. For workers who handle heat and water, certain types of leather gloves are recommended.

Thus, gloves with leather palms offer the best defense against abrasive and puncture risks. They have leather palms and fingers and are constructed of dependable cotton or canvas.

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