for the nucleophile of this reaction, dialkyl phosphonates (diesters of phosphonic acids) are . . .
electron withdrawing by resonance and inductive effect
electron withdrawing by inductive effect.
electron donating by resonance and inductive effect
electron donating groups by resonance
electron withdrawing by resonance effect

Answer:

A) B has more electron shells then A

Explanation:

Element A is flourine

Element B is chlorine

Chlorine has three electron shells and flourine only has 2 electron shells (on Bohr model)

Chlorine's outer shell has 7 electrons and so does flourines outer shell(on bohr model)

Sense Answer A is correct and Answer B is wrong, common snese will tell you that D is wrong sense B is wrong, and sense D is wrong that means only one is right and sense A is correct it makes C wrong

Explanation :

The compound pairs that would give a precipitate when their aqueous solutions are mixed are those that produce an insoluble compound when two solutions are mixed.

The correct answer for the question is option

A) CuBr2 and K2CO3.

What is a precipitate?

A solid product that is separated from a liquid reaction mixture is referred to as a precipitate.

During a chemical reaction in a solution, a precipitate may form when two aqueous solutions are mixed together.

The following pairs of compounds do not form a precipitate when their aqueous solutions are mixed:HNO3 and NH4INa2CO3 and H2SO4KCl and KNO3

What is an aqueous solution?

A liquid solvent, generally water, is used to dissolve one or more solutes in a solution, creating an aqueous solution. An aqueous solution is a solution in which the solvent is water. An aqueous solution is a water-based solution with a pH of 7 or greater.

Therefore, the compound pairs that would give a precipitate when their aqueous solutions are mixed are CuBr2 and K2CO3.

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Answer:

C

Explanation:

It was the first to show that the atom had no net charge.

Answer:

Factors Affecting the Preferential Discharge of Ions in Electrolysis

Answer: Handwashing. It is estimated that washing hands with soap and water could reduce diarrheal disease-associated deaths by up to 50% 1. Researchers in London estimate that if everyone routinely washed their hands, a million deaths a year could be prevented 2.

Explanation:

Answer: sugar

Explanation:

The reaction with S_N₂mechanism is likely to be faster than the reaction with S_N₂ mechanism. This is because the carbocation intermediate formed in S_N₁ mechanism is more stable.

The pair of reactions given below is:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH₃OH + NaI

The type of substitution mechanism:

The first reaction involves S_N₁ mechanism (unimolecular nucleophilic substitution). The second reaction involves S_N₂ mechanism (bimolecular nucleophilic substitution).

Prediction of the reaction that will occur at a faster rate:

The reaction with S_N₁ mechanism is likely to be faster. The rate of this reaction mainly depends on the stability of the carbocation intermediate formed after the initial step. In this case,CH₃Cl reacts to form a tertiary carbocation which is more stable than the primary carbocation formed in CH₃I.

Drawing the correct organic product:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH_3OH + NaI

CH₃C reacts with NaOHin an S_N₁ mechanism to produceCH₃OH and NaCl.


CH₃ reacts withNaOH in an S_N₂mechanism to produce CH₃OH and NaCI.


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• The depression in freezing point is given by ΔTF = KF · b · i,

where i depend upon the number of ions produced by the solute in a solution.

• The higher the value of i obtained, the higher the depression freezing point .

• CaCl2 (aq) → Ca2+ (aq) + 2Cl– (aq).....(3 ions)

• and NaCl Na+ and Cl– ions →...............(2 ions )

• Sugar/sucrose doesnt dissociate

• Thus CaCl2 will have similar freezing point as water . Option B

•

Answer:

Hi numu !

How are you .

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Hope you have nice time

A germinating seed is one from which a plant has started to grow. A non-germinating seed is usually dry, and a new plant has not yet emerged. The germinating corn seed consumed more oxygen than the non-germinating corn seed. This statement is true.  Therefore, option A is correct.

A dry seed starts to absorb water through its seed coat when it comes into touch with damp soil or growing medium. The seed swells and the seed coat splits open as it absorbs more water. Small shoots and roots make up the embryo inside the seed. First to appear from the seed is the root.

The prerequisites for seed germination include oxygen, water, temperature, and, only for particular seeds, light. The sprouting of seeds is impacted when one or more of these are missing. Similar internal elements that impact this process include seed viability, dormancy, and embryonic maturity.

Thus, option A is correct.

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Answer:

b

Explanation:

the angular distance of a place east or west of the meridian at Greenwich, England, or west of the standard meridian of a celestial object, usually expressed in degrees and minutes

We have that  the time that will have elapsed when 25.00 grams remains is

T=72hours

From the question we are told

100.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How much time will have elapsed when 25.00 grams remains?

Generally the equation for the Half life  is mathematically given as

Where

\(X=\frac{25}{100}\\\\X=0.25\\\\Therefore\\\\\frac{1}{2}^n=0.25\\\\n=2 half lives\)

Therefore

T=2*36

T=72 hours

Hence

 the time that will have elapsed when 25.00 grams remains is

T=72hours

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Answer: Ketone

Explanation:

Answer:

Commensalism

Explanation:

Commensalism is an association between two organisms in which one benefits and the other derives neither benefit nor harm. The Spanish moss benefits and the oak tree neither benefits nor is harmed.

Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

Answer:

You right!

Explanation:

Answer: Yes your right

Vanadium(V) oxide is the inorganic compound with the formula V₂O₅. Commonly known as vanadium pentoxide, it is a brown/yellow solid, although when freshly precipitated from aqueous solution, its colour is deep orange. Because of its high oxidation state, it is both an amphoteric oxide and an oxidizing agent.

formula:V2O5

pls mark as brainliest

Answer:

is it vanadium v oxide or just vanadium oxide

Explanation:

Answer:

\(V_2=1099.35mL\)

Explanation:

Hello there!

In this case, according to the given information, it is possible to infer that as both the amount of the gas and the pressure remains the same, we can solve this problem via the Charles' law a directly proportional relationship between the volume and temperature:

\(\frac{V_2}{T_2} =\frac{V_1}{T_1}\)

Thus, by solving for the final volume, V2, we obtain:

\(V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{886mL*371K}{299K}\\\\V_2=1099.35mL\)

Best regards!

The equilibrium partial pressure of HI when 0.200 moles of HI are added is 4.69 atm

To answer this question, we will need to use the equilibrium constant expression for the reaction:

H2(g) + I2(g) ⇌ 2HI(g)

At equilibrium, the concentrations of the three gases will be related by the equilibrium constant, Kc:

Kc = [HI]^2 / ([H2] * [I2])

We can use the given initial concentrations to calculate Kc:

Kc = (0.775 mol/L)^2 / ((0.112 mol/L) * (0.112 mol/L)) = 49.3 L/mol

Now we can use the change in moles of HI to calculate the new concentration and partial pressure of HI. Since 0.200 moles of HI are added, the new concentration of HI will be:

[HI] = (0.775 + 0.200) mol / 5.00 L = 0.195 mol/L

Using the equilibrium constant expression, we can solve for the new equilibrium partial pressure of HI:

Kc = [HI]^2 / ([H2] * [I2])
49.3 L/mol = (0.195 mol/L)^2 / ((0.112 mol/L) * (0.112 mol/L)) * P(HI)
P(HI) = 49.3 L/mol / (0.195 mol/L)^2 * (0.112 mol/L) * (0.112 mol/L)
P(HI) = 4.69 atm

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The element that is shown by the quantum number is zirconium.

The quantum number is a kind of a description of the address of the electron that is present in the compound. This stems from the wave mechanical model of the atom that was put forward by Schrodinger.

In this case, we have the quantum number of the element as 4,2,-1,-1/2. This is going to correspond to an electron that can be found in the 4d orbital of the atom. This corresponds to a member of the transition series.

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Answer:

Metallic bonds occur among metal atoms.

The main two requirements to compare the energy for 2 compounds are the balanced chemical formula and the temperature of the compounds.

Gibb's free energy change of any reaction will be calculated by using the below equation as:

ΔG = ΔH - TΔS, where

ΔH = change in enthalpy

T = temperature

ΔS = change in entropy

Before calculating the free energy of any reaction you should first balance the given chemical reaction to check the involved moles of substance and also the value of temperature before & after the completion of reaction to check the nature of the reaction.

Hence balancing the equation and checking the temperature are the two requirements.

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Answer:

b

Explanation:

The statement that is true about what can occur in a chemical change is b. Elements may combine to form compounds.

A chemical change can be described as the change which do take place when the substance's composition is been altered which could bring about the formation of another substance.

It should be noted that in the chimical change there is uaually a formation of a new product after one or more substance must have reacted together which implies that in this kind of change there is usuall a new substance that will be formed in the process.

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Hbr(aq) h2o(l)→h3o (aq) (aq) br−(aq) Write your responses in chemical terms. Enter your responses using commas to separate them in the question's sequence. Compound acid - H3O+, Composite base - Br-, Bronsted-lowry acid - HBr, and Brønsted - lowry bases - H2O.

Any material with a different compositions is a chemical. To put it another way, every chemical always consists with same "stuff." There are some substances in nature, like water. Other chemicals, including chlorine, are produced Covalent compounds hold together molecules, ionic compounds hold together ions, metallic bonds keep together intermetallic compounds, and coordinate covalent bonds hold coordination complexes together.

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Answer:

4.194 atm

Explanation:

We will be using a modified version of the Ideal Gas Equation, known as the Combined Gas Law to solve this question.

The Combined Gas Law states that

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

where,

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now, we modify the values given in the question to standard units.

P₁ = Unknown

V₁ = 29L

T₁ = 70 C = 273.15 + 70 = 343K

P₂ = 3.0 atm

V₂ = 37L

T₂ = 40 C = 273.15 + 40 = 313K

Now substituting the values in our equation, we get

P₁ * 29 L / (343K) = 3.0 atm * 37 L / (313K)

Taking all unknowns to one side,

P₁ = (3.0  * 37  * 343) / (29  * 313)

P₁ = 4.194 atm

Therefore, the original pressure of the gas was 4.194 atm

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Answer:140 grams of N2 are made.

Explanation:

15 mol CuO x (1 mol N2 / 3 mol CuO) = 5 moles of N2.

5 mol N2 x (28 g N2 / 1 mol N2) = 140 grams of N2.

The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer: 72.58 km/hr

Explanation:

\(\frac{45 miles}{1 hour}\)×\(\frac{1 km}{0.62 miles}\) = 72.58 km/hr

Answer:

it is 72.9 km/h

Explanation:

just multiply 45 * 1.62 = ~72.9