For the data in the table, how many data points are in each group for the median-median line? x y 2.5 6 6 7 7 1 7.5 8 9 11 12 2 11.5 9 15 11 16 15 20 20 21.5 24 22.5 25 21 28 a. left: 4, center: 8, right: 4 b. left 5, center: 5, right: 5 c. left: 5, center: 6, right: 5 d. left:7, center: 2, right: 7

Answer:

6.40$

Step-by-step explanation:

HOPE THIS HELPS

PLZZ MARK BRAINLEIST

Answer:

identify a property is the answer

Answer:

5280

Step-by-step explanation:

Take the amount of miles, multiply it by 1760, and you should get the approximate amount of yards.

Answer:

£ 170 .

Step by step explanation :

Given that the price of a computer was decreased by 20% to £136. And we need to find the Original price before the decrease. So , let the earlier price be x ,

Decrease in 20 % :-

⇒ Decreased price = 20% of x

⇒ Decreased price = 20/100 × x

⇒ Decreased price = x/5

New price :-

⇒ New price = x - x/5

⇒ New price = 5x - x/5

⇒ New price = 4x/5.

But its given £ 136 , So

⇒ 4x/5 = £ 136

⇒ x = £ 136 * 5/4

⇒ x = £ 170

Answer:

(2,1)

Step-by-step explanation:

Answer:

(2,1)

Step-by-step explanation:

Answer:

A: 113.04in^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2 where r is the radius

We know the diameter is 12 inches so the radius is 1/2 the diameter

r = 1/2 d =1/2(12) = 6inches

A = (3.14) (6)^2

A = 113.04 in ^2

Answer:

\(x + x = 2x \\ 5y + y = 6y \\ thank \: ou\)

Answer:

The area of the circle is 30.25π cm^2.

Step-by-step explanation:

The circumference of a circle is equal to the diameter of the circle times π. Therefore, if the circumference of the circle is 11π cm, the diameter must be 11 cm.

The formula for the area of a circle is A = πr^2, where r is the radius of the circle. The radius of the circle is half the diameter, so the radius is (1/2) * 11 cm = 5.5 cm.

Substituting this value for r into the formula for the area of a circle, we get:

A = π * (5.5 cm)^2

= π * 30.25 cm^2

= 30.25π cm^2

Therefore, the area of the circle is 30.25π cm^2.

a)The two way table is shown in figure,

b)The success rate of the three treatments in preventing cardiac arrests are 90.91% , 79.41% and 70%.

c)The expected cell count are as shown in the figure,

d)No. There is no difference among the treatments.

e) The brief summary is mentioned below.

Given,

The total number of people is 107.

33 people are enrolled in a stress management programme.

3 people had cardiac events as a result of the stress management programme.

34 people are in the exercise group.

The number of cardiac events in the exercise group was 7 people.

40 people receive routine care.

12 people had cardiac events while receiving standard care.  

a)

The two-way table for the given information is shown in the figure

b)

During the same time period, 7 of the 34 people in the exercise group and 12 of the 40 patients in usual care experienced such events.Success rate can be determined by,

\(Success=\frac{no.\ of\ people\ who\ did not\ suffered\ in\ group}{Total\ number\ of people\ in\ group}\)

For stress management:-

\(Success\ rate = \frac{30}{33}=0.9091=90.90\%\)

For exercise program:-

\(Success\ rate = \frac{27}{34}=0.7941=79.41\%\)

For usual care:-

\(Success\ rate = \frac{28}{40}=0.7=70\%\)

c)

Expected cell count can be calculated by formula,

\(Expected\ value=\frac{row\ total*column\ total}{table\ total}\)

then,

Expected value for the people who suffered cardiac arrest,

Under stress management:-

\(E= \frac{22*23}{107}=6.79\)

Under exercise group:-

\(E=\frac{22*34}{107}=6.99\)

Under usual care:-

\(E=\frac{22*40}{107}=8.22\)

Expected value for the people who did not suffered cardiac arrest :-

Under stress management:-

\(E=\frac{85*33}{107}=26.21\)

Under exercise group:-

\(E=\frac{85*34}{107}=27.01\)

Under usual care:-

\(E=\frac{85*40}{107}=31.78\)

The expected cell count is mentioned in the table

d)

The null and alternate hypothesis are

\(H_0\) :There is no difference in the actual success rates of the three treatments.

\(H_1\) :The three treatments differ in terms of actual success rates.

The test statistic can be calculated by

\(x^2=\sum \frac{(O-E)^2}{E}\)

Where,

O=observed value

E=Expected value

Under null hypothesis,

\(x^2=\frac{(3-.679)^2}{6.79}+\frac{(7-6.99)^2}{6.99}+\frac{(12-8.22)^2}{8.22}+\frac{(30-26.21)^2}{26.21}+\frac{(27-27.01)^2}{27.01}+\frac{(28-31.78)^2}{31.78}\\\\=4.8514\)

The p-value for the test is \(P(x_2 > 4.8514)=0.0884\)

There is no statistically significant difference in the success rates of the three treatments.

e)

Because the p-value is greater than 0.05 (at the 5% level of significance), there is insufficient evidence to reject the null hypothesis and conclude that there is no difference in the actual success rates for the treatments.

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The given set {60, 70, 80, ..., 100} is finite as it have countable elements in it.

The numbers "60, 70, 80,..., 100" make up a set that starts at 60 and goes up by 10 with each number after that. The ellipsis (...) is used to indicate that the pattern continues indefinitely.

However, despite the pattern appearing to continue indefinitely, the set itself is considered finite. This is so that we can count the elements in the set to get an exact count. The total elements in the set is hence 5. Since we have a clear starting point (60), a defined pattern of incrementing by 10, and a known ending point (100), we can confidently state that the set is finite.

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Describe the following set as either finite or infinite {60,70,80,....., 100} Choose the correct description below. Finite Infinite.

Answer:

Saturday.

Step-by-step explanation:

To answer the above question, we must recognise that Tuesday appears once every 7 days.

If today is Tuesday, 31 days ago will be obtained as follow:

31/7 = 4 remainder 3

Thus

31 = (7 × 4) + 3

31 = (28) + 3

Thus, the 28th day is Tuesday. If we count 3 days back from Tuesday, the day will be Saturday.

Therefore, the magician made his wife disappear on Saturday.

Answer:

C) 24

Step-by-step explanation:

8; 16 24 32 40 48

12; 24 36 48 69 72

They both have the common multiple of 24 and 48 in the intermediate multiplication since 24 is half of 48 and is the smallest multiple that is the answer.

Answer:

how would i know

Step-by-step explanation:

you did this to me, and its is sickining. get a life

Answer:

x = 31

So 2x-7 = 55

x + 4 = 35

Step-by-step explanation:

\(2x-7+x+4=90\\3x-3=90\\3x=93\\x=31\)

There are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.

There are 12 different outfits that can be put together using 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.

How to solve the problem:

To find out the number of different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes, we will simply multiply the number of options for each category together.

Number of options for pants = 3

Number of options for shirts = 2

Number of options for shoes = 2

Number of different outfits that can be put together

= 3 × 2 × 2

= 12

Therefore, there are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.

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The 4 steps to solve an equation:

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The recommended lot size is 167 textbooks, and the order should be placed once per year to minimize inventory costs.

We may utilize the economic order quantity (EOQ) calculation to predict the lot size and frequency of orders that would reduce inventory expenses. The following is the EOQ formula:

EOQ = √((2DS)/H),

where:

D = annual demand (number of calculus textbooks sold per year),

S = ordering cost per order, and

H = holding cost per unit per year.

In this case:

D = 120 calculus textbooks,

S = $9 (fixed cost) + $4 (cost per calculus textbook ordered),

H = $1.35 (cost to store one calculus textbook for one year).

Substituting,

EOQ = √((2 × 120 × (9 + 4)) / 1.35)

= √((2 × 120 × 13) / 1.35)

≈ √(37440 / 1.35)

≈ √27777.78

≈ 166.67 (rounded to the nearest whole number)

The computed EOQ, which corresponds to the ideal lot size for ordering calculus textbooks, is around 166.67. We would round it to the next whole number because we are unable to order fractional numbers, which would give us a lot size of 167 volumes.

If we split the yearly demand (120 textbooks) by the lot size, we get the frequency of orders each year:

Frequency of orders = 120 / 167

≈ 0.719 (rounded to the nearest whole number)

The order should be placed approximately 0.719 times per year. Since we cannot place fractional orders, we would round it to the nearest whole number, resulting in one order per year.

Therefore, the recommended lot size is 167 textbooks, and the order should be placed once per year to minimize inventory costs.

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The simplest way to perform a division is long division and synthetic division.

What is division?

Division in mathematics is the process of dividing an amount into equal parts. For instance, we may split a group of 20 people into four groups of 5, five groups of 4, and so on.

There are two methods to perform division:

Long division: The mathematical procedure for splitting big numbers into more manageable groups or sections is known as long division. A difficulty can be solved by breaking it down into manageable parts. Dividends, divisors, quotients, and remainders all exist in long divisions.

Synthetic division: In algebra, synthetic division is a technique for manually dividing polynomials according to Euclid, requiring less writing and calculation than long division. Although the approach can be applied to division by any polynomial, it is often taught for division by linear monic polynomials.

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Answer:

from my understanding of math, yes

Step-by-step explanation:

Answer:

Step-by-step explanation:

D. never

A parameter is a fixed value that represents a characteristic of a set population, such as the population mean or population proportion. It is a fixed value that is true for the entire population, it is calculated using all the data of the population. For example, the mean of the height of all adults in a country is a parameter. Since it is based on all the data, it is not an estimation, it is the true value of the population. Therefore, a parameter does not change, it is a fixed value for a set population.

The probability that a pupil uses neither pool nor gym is 11/70

Probability is the likelihood that an event will happen. This can range from an event being impossible to some likelihood to being absolutely certain. In math terms, probability is on a scale from 0 to 1. Zero means the event is impossible, like rolling a seven on a die that only has digits from 1 to 6.

Number of pupil that can use pool and gym = 28

Number of people that can use pool = 48

Number of people that can use gym = 39

Number of people that can use pool only = 48 - 28 which is 20

Number of people that can use gym only = 39 - 28 = 11

Total number of persons that can use either pool, gym or both = 20 + 11 + 28 which is 59

Number of people that cannot use either or both of the facilities = 70 - 59 which is 11.

Probability = required outcome / possible outcome

Required outcome = 11

possible outcome = 70

Probability = 11/70

In conclusion, the probability that a pupil uses neither swimming pool nor gym is 11/70

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In both the triangles,

three sides are congruent,

so,

the two triangles are related by side -side -side , so the triangles can be proven congruent .

The value of x in the given 45-45-90 triangle is 9.89.

The given triangle is a right-angled triangle which can be solved using the Pythagoras theorem. The Pythagoras theorem states that the square of the hypotenuse is equal to the sum of the square of the base and the square of the perpendicular. This theorem can be applied to all right-angled triangles.

In the given triangle, we have been told that the length of both legs is 7. Now, after applying the theorem -

= 7²+7² = H²

= 49 + 49 = H²

= 98 = H²

= √98 = H

= 9.89 = H

Hence, this is the value of x.

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Our initial assumption that the square root of n is rational must be false, and we can conclude that the square root of 18 is irrational.

To prove that the square root of 18 is irrational using strong induction, we first need to state and prove a lemma:

Lemma: If n is a composite integer, then n has a prime factor less than or equal to the square root of n.

Proof of Lemma: Let n be a composite integer, and let p be a prime divisor of n. If p is greater than the square root of n, then p*q > n for some integer q, which contradicts the assumption that p is a divisor of n. Therefore, p must be less than or equal to the square root of n.

Now we can prove that the square root of 18 is irrational:

Base Case: For n = 2, the square root of 18 is clearly irrational.

Inductive Hypothesis: Assume that for all k < n, the square root of k is irrational.

Inductive Step: We want to show that the square root of n is irrational. Suppose for the sake of contradiction that the square root of n is rational. Then we can write the square root of n as p/q, where p and q are integers with no common factors and q is not equal to 0. Squaring both sides, we get:

n = p^2 / q^2

Multiplying both sides by q^2, we get:

n*q^2 = p^2

This shows that n*q^2 is a perfect square, and since n is not a perfect square, q^2 must have a prime factorization that includes at least one prime factor raised to an odd power. Let r be the smallest prime factor of q. Then we can write:

q = r*m

where m is an integer. Substituting this into the previous equation, we get:

nr^2m^2 = p^2

Since r is a prime factor of q, it is also a prime factor of p^2. Therefore, r must be a prime factor of p. Let p = r*k, where k is an integer. Substituting this into the previous equation, we get:

nm^2r^2 = r^2*k^2

Dividing both sides by r^2, we get:

n*m^2 = k^2

This shows that k^2 is a multiple of n. By the lemma, n must have a prime factor less than or equal to the square root of n. Let s be this prime factor. Then s^2 is a factor of n, and since k^2 is a multiple of n, s^2 must also be a factor of k^2. This implies that s is also a factor of k, which contradicts the assumption that p and q have no common factors.

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The probability of including k specified members in a random sample of size n without replacement from a population of size N can be calculated using the hypergeometric distribution.

The hypergeometric probability mass function is given by:

\(\[P(X = k) = \frac{{\binom{K}{k} \cdot \binom{N-K}{n-k}}}{{\binom{N}{n}}}\]\)

where:

- K is the number of specified members in the population.

- n is the size of the sample.

- k is the number of specified members in the sample.

- N is the total population size.

In this case, we want to find the probability that k specified members are included in the sample, so the probability can be calculated using the hypergeometric distribution formula.

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Answer:

28/16071  as a decimal 0.00174226...

Step-by-step explanation:

Hope this helps!

Answer:

An acute triangle - interior angles are always less than 90 degrees with different side measures.

An obtuse triangle - one of the interior angles is more than 90 degrees. if one angle measures more than 90 degrees, then the sum of the remaining two angles is less than 90 degrees.

An right triangle -  a triangle with a right angle (90 degrees)

Equilateral triangle has three equal sides. Isosceles triangles has two equal side lengths. Scalene triangles has no equal side lengths

Answer:

1.39

Step-by-step explanation:

Creating a table:

X :___0 __ 1 __ 2 ___ 3 ____ 4 ___ 5 ___ 6

P(x):0.02_0.03_0.07, 0.12, 0.30_ 0.28_0.18.

The standard deviation = sqrt(Var(x))

Var(x) = Σx²*p(x) - E(x)²

E(x) = ΣX*p(x)

E(x) = (0*0.02) + (1*0.03) + (2*0.07) + (3*0.12) + (4*0.30) + (5*0.28) + (6*0.18) = 4.21

Var(X) :

((0^2*0.02) + (1^2*0.03) + (2^2*0.07) + (3^2*0.12) + (4^2*0.30) + (5^2*0.28) + (6^2*0.18)) - 4.21^2

19.67 - 17.7241

= 1.9459

Standard deviation = sqrt(Var(X))

Standard deviation = sqrt(1.9459)

Standard deviation = 1.3949551

= 1.39

x(4x+y)(16x^2-4xy + y^2)